Help please !!!!!! Please

The acid dissociation constant (Ka) for the acid is calculated to be 2.9 × 10^-6 M if the pH of the resulting solution is 2.73

The acid dissociation constant (Ka) is used to differentiate between weak and strong acids and in this case, can be calculated as follows;

Considering the chemical reaction:

HA ⇄ H⁺ + A⁻

Here HA is the acid that disassociates into the conjugate base of the acid (A⁻) and a hydrogen ion represented as H⁺

As the molarity of monoprotic acid is 1.16 M and the pH of the solution is 2.73, therefore;

[A⁻] = [H⁺] = 10^(-2.73)

[A⁻] = [H⁺] = 0.00186 M; equilibrium concentration

[HA] = 1.16 M - 0.00186 M

[HA] = 1.15814 M

Ka =  [A⁻][H⁺] / [HA]

Ka = (0.00186)² / 1.15814 M

Ka = 2.9 × 10^-6 M

Therefore the Ka for the acid is calculated to be 2.9 × 10^-6.

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The spontaneity of a reaction is determined by the Gibbs free energy change (∆G), which is a measure of the system's ability to do work.

The equation that links ∆G, ∆H, and ∆S is: ∆G = ∆H - T∆S, where T is the temperature in Kelvin and ∆H and ∆S are the enthalpy and entropy changes, respectively. The signs of ∆H and ∆S determine whether the reaction is exothermic or endothermic and whether it is entropy-driven or enthalpy-driven, respectively.

If ∆G is negative, the reaction is spontaneous, meaning it occurs without the input of energy.The given reaction has a ∆H of 23.25 kJ and a ∆S of 161.26 J/mol∙K.

First, we need to convert the units of ∆S from J/mol∙K to kJ/mol∙K by dividing by 1000.∆S = 161.26 J/mol∙K ÷ 1000 = 0.16126 kJ/mol∙K Substitute the values into the equation to determine the spontaneity of the reaction:

∆G = ∆H - T∆S∆G = (23.25 kJ) - (298 K) x (0.16126 kJ/mol∙K)∆G = 23.25 kJ - 48.02 kJ∆G = -24.77 kJ Since ∆G is negative, the reaction is spontaneous.

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Answer:

The main difference between isopropyl alcohol and rubbing alcohol is the concentration. The concentration of isopropyl alcohol is 100%, while the concentration of rubbing alcohol is less because of the addition of water. Otherwise, the two liquids have similar properties.

Explanation:

Hope this helps

Simultaneous causality can cause the endogeneity problem. This statement is true and it can be stated as follows:

To address this problem, researchers often use instrumental variable techniques or conduct a suitable econometric analysis that accounts for endogeneity.

Endogeneity refers to the situation where the relationship between two variables is affected by a third variable that is not accounted for in the analysis.

Simultaneous causality occurs when two or more variables simultaneously influence each other. In this case, the relationship between the variables is not one-directional, making it difficult to establish a clear cause-and-effect relationship.

This can lead to endogeneity because the presence of simultaneous causality violates the assumption of exogeneity, which assumes that the explanatory variables are not affected by the error term in the regression model.

As a result, the estimated coefficients may be biased and inconsistent.

To address this problem, researchers often use instrumental variable techniques or conduct a suitable econometric analysis that accounts for endogeneity.

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Answer:

Molarity = 2.4 M

Explanation:

Given data:

Mass of silver fluoride = 12.7 g

Volume of water = 125 mL (125 mL× 1 L /1000 mL = 0.125 L)

Molarity of solution = ?

Solution:

Number of moles of silver fluoride:

Number of moles = mass/molar mass

Number of moles = 12.7 g/ 41.98 g/mol

Number of moles = 0.30 mol

Molarity:

Molarity = number of moles of solute / volume in L

Molarity = 0.30 mol / 0.125 L

Molarity = 2.4 M

1. ₉¹⁹F

2. Mg(OH)₂

3. 2H₂ + O₂ ⇒ 2H₂O

1. Fluorine, atomic number : 9 , mass number = 19

Symbol : ₉¹⁹F

protons=electrons=atomic number = 9

neutrons = mass number - atomic mass

\(\tt n=19-9=10\)

Configuration : [He] 2s² 2p⁵

2. Magnesium hydroxide is an ionic compound and is a strong base consisting of 2 ions:

Positive ion: Magnesium: Mg²⁺

negative ion: Hydroxide: OH⁻

The charges of the two are crossed, so that the compound becomes:

Mg(OH)₂

3. Reaction :

H₂ + O₂ --------> H₂O

give coefficient :

aH₂ + bO₂ --------> H₂O

H, left = 2a, right 2⇒2a=2⇒a=1

O, left = 2b, right 1⇒2b=1⇒b=0.5

Reaction becomes :

H₂ + 0.5O₂ --------> H₂O x 2

2H₂ + O₂ --------> 2H₂O

The volume of calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point is 87.5 mL.

In the given case, we have to calculate the volume of 0.530 M calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point.

The chemical equation for the reaction of phosphoric acid with calcium hydroxide is given below:

H₃PO₄ + Ca(OH)₂ → Ca(H₂PO₄)₂ + 2H₂O

Molar mass of H₃PO₄ = 3(1.008) + 1(30.974) + 4(15.999)

                                    = 98.0 g/mol

Molar mass of Ca(OH)₂ = 1(40.078) + 2(15.999)

                                         = 74.1 g/mol

Number of moles of H₃PO₄ in 35.0 mL of 0.440 M

phosphoric acid= Molarity × Volume(in liters)

= 0.440 × (35.0/1000)

= 0.0154 mol

Number of moles of Ca(OH)₂ required to react completely with 0.0154 mol of H₃PO₄= 0.0154 mol

Number of moles of Ca(OH)₂ present in the solution

= Molarity × Volume(in liters)

= 0.530 × Volume

Calcium hydroxide will react with phosphoric acid until the third equivalence point is reached.

Ca(OH)₂ + 2H₃PO₄ → Ca(H₂PO₄)₂ + 2H₂O(moles)

0.0154         0.031                0.0464

(Molarity) 0.53              0.53              0.53

(Volume)    V₁                   V₂                         V₃

Equivalence point is the point where the number of moles of two reactants is equal to each other.The number of moles of H₃PO₄ is equal to the number of moles of Ca(OH)₂ at the third equivalence point,

So, 0.0464 mol of Ca(OH)₂ is required to react completely with 0.0154 mol of H₃PO₄  .

Volume of 0.530 M calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point

= (0.0464 mol)/(0.530 mol/L)

= 0.0875

L= 87.5 mL (rounded to three significant figures)

Therefore, the volume of 0.530 M calcium hydroxide solution required to titrate 35.0 mL of 0.440 M phosphoric acid to the third equivalence point is 87.5 mL.

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Answer:

1) it takes 13 second

2) 2100 miles

3) 40 miles / hours

4) 730 meters

The formula for a compound made from x2 and y- can be predicted using the crisscross method.

X2 has a charge of 2+ while y- has a charge of 1-. To form a neutral compound, the charges must balance each other.

To do this, the charge of x2 will become the subscript of y, and the charge of y- will become the subscript of x2.

Thus, the formula for the compound will be written as X2Y.

This indicates that two atoms of x combine with one atom of y to form the compound.

The compound may have different properties and characteristics depending on the identity of the elements X and Y.

Overall, the crisscross method is an effective way to predict the formula of an ionic compound.

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Answer:

I think option B is the correct answer.

I think it will help you.

Answer:

OB. The government provides soil and freshwater resources to all American citizens

Explanation:

have a great day ahead" :)

The law of conservation states that the mass of the element remains the same during the course of the reaction.

The law of reaction conformed by the following:-

According to the question, the amount of carbon is 15g in the reactant and the amount will remain same at the end of reaction, which is product that is 15g.

Hence, the amount remain same in the reaction that is 15g.

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None of the available choices have as many molecules as 1 L of STP-produced C2H4 gas.

At STP (Standard Temperature and Pressure), which is defined as a temperature of 273.15 K and a pressure of 1 atmosphere, the volume of a gas is directly proportional to the number of molecules present. This means that if we have two gases at STP with the same volume, they must contain the same number of molecules.

For a gas with a given volume, the number of molecules present can be calculated using the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

To determine which gas has the same number of molecules as 1 L of C2H4 gas, we need to calculate the number of moles of C2H4 present in 1 L of C2H4 gas. The molar volume of any gas at STP is 22.4 L/mol.

The molar mass of C2H4 is 28.05 g/mol, so 1 L of C2H4 gas at STP contains:

n = m/M = 1000 g / 28.05 g/mol = 35.6 mol

Therefore, 1 L of C2H4 gas contains 35.6 moles of C2H4.

(a) For 0.5 L of H2 gas, the number of moles present is:

n = PV/RT = (1 atm x 0.5 L) / (0.0821 L atm/mol K x 273.15 K) = 0.0207 mol

Since 0.0207 mol is less than 35.6 mol, 0.5 L of H2 gas has fewer molecules than 1 L of C2H4 gas.

(b) For 1 L of Ne gas, the number of moles present is:

n = PV/RT = (1 atm x 1 L) / (0.0821 L atm/mol K x 273.15 K) = 0.0409 mol

Since 0.0409 mol is less than 35.6 mol, 1 L of Ne gas has fewer molecules than 1 L of C2H4 gas.

(c) For 2 L of H2O gas, the number of moles present is:

n = PV/RT = (1 atm x 2 L) / (0.0821 L atm/mol K x 273.15 K) = 0.082 mol

Since 0.082 mol is less than 35.6 mol, 2 L of H2O gas has fewer molecules than 1 L of C2H4 gas.

(d) For 3 L of Cl2 gas, the number of moles present is:

n = PV/RT = (1 atm x 3 L) / (0.0821 L atm/mol K x 273.15 K) = 0.123 mol

Since 0.123 mol is less than 35.6 mol, 3 L of Cl2 gas has fewer molecules than 1 L of C2H4 gas.

Therefore, none of the given options have the same number of molecules as 1 L of C2H4 gas at STP.

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Answer:

Explanation:

0.750 tsp of baking soda in grams would be  4.49 grams.

From the available information:

If, 1 tsp of baking soda = 0.211 oz, then 0.750 tsp of baking soda would be:

 0.750 x 0.211 = 0.15825 oz

Thus, 0.750 tsp of baking soda is equivalent to 0.15825 oz of baking soda.

If 1 oz = 28.35 grams, then 0.15825 oz of baking soda will be:

28.35 x 0.15825 = 4.49 grams

In other words, 0.750 tsp of baking soda would be worth 4.49 grams of baking soda going by the available conversion factors.

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Add a trace of acidic acid to the eluting solvent mixture.

TLC is the acronym for thin layer chromatography. This type of chromatography occurs when we have an eluting solvent and a stationary phase such as a thick adsorbent paper on a support.

In a chromatography, there is a stationary phase and a mobile phase. The stationary phase here is the sold support while the mobile phase is the eluting solvent which carried the mixture to be separated.

This stationary phase is spotted with the mixture to be eluted and the chromatogram is observed on the stationary phase. We know that an acid would be eluted by a polar solvent.

If the chromatogram is a stretched circle that appears rounder as you move a little farther then you have to add a trace of acidic acid to the eluting solvent mixture.

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Missing parts;

You are running a reaction to make a carboxylic acid, but what appears to be the product spot is too low on the tlc plate and is elongated, i.e., it isn't a nice circle but is stretched out a lot. To make this spot rounder and move a little farther, which of the following is most likely to work?

Using a more polar eluting solvent mixture.

Adding a trace of ammonium hydroxide to the eluting solvent mixture.

Adding a trace of water to the eluting solvent mixture.

Adding a trace of methanol to the eluting solvent mixture.

Adding a trace of acidic acid to the eluting solvent mixture.

The purpose of using cobalt glass was to filter out yellow light emitted by sodium, allowing the observer to see the violet flame color of potassium.

When a sample containing both sodium and potassium is heated in a flame, they emit different colors of light. However, both elements emit some yellow light, which can make it difficult to distinguish between them. Cobalt glass filters out the yellow light, allowing the observer to see the distinct violet color of potassium flame. This is because the cobalt glass absorbs the yellow light and transmits the rest of the visible spectrum. Using cobalt glass is a common technique in flame tests to improve the accuracy of identifying the elements present in a sample.

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The value of Δrxn for nitrous acid when [NO−2]=[H3O+]=3.18×10−5 M and [HNO2]=1.457 M is -214.96 kJ/mol.

Given:

HNO2(aq) + H2O(l) ⇌ H3O+(aq) + NO−2(aq)

Ka = 5.6 x 10^-4 M

Δ∘rxn at 25.0 ∘C for nitrous acid is to be calculated when [NO−2]=[H3O+]=[HNO2]=1.00 M.

Using the Ka expression:

Ka = [H3O+][NO−2] / [HNO2]

5.6 x 10^-4 = [1.00]^2 / [1.00]

Therefore,

[H3O+] = [NO−2] = 0.02365 M

To calculate Δ∘rxn:

Δ∘rxn = -2.303RT log Ka

At 25°C, R = 8.314 J/mol K and T = 298 K.

Δ∘rxn = -2.303 x 8.314 x 298 x log (5.6 x 10^-4) kJ/mol

= -21.1 kJ/mol

The value of Δ∘rxn is -21.1 kJ/mol.

Since Δ∘rxn is negative, the acid will spontaneously dissociate under these conditions because the reaction is exothermic and Δ∘rxn is negative, indicating that the reaction is spontaneous.

Now, let's calculate the value of Δrxn for nitrous acid when [NO−2]=[H3O+]=3.18×10−5 M and [HNO2]=1.457 M.

Using the formula:

Δrxn = ΔfH°(H3O+(aq)) + ΔfH°(NO2−(aq)) - ΔfH°(HNO2(aq))

Given values:

ΔfH°(HNO2(aq)) = -56.06 kJ/mol

ΔfH°(H3O+(aq)) = -237.13 kJ/mol

ΔfH°(NO2−(aq)) = 33.89 kJ/mol

Δrxn = -237.13 + 33.89 - (-56.06) kJ/mol

= -214.96 kJ/mol

Therefore, the value of Δrxn for nitrous acid when [NO−2]=[H3O+]=3.18×10−5 M and [HNO2]=1.457 M is -214.96 kJ/mol.

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Answer:

d on edge my guys.

Explanation:

Answer:

violet

Explanation:

i think it is D i hope this helps yall

Answer:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

Explanation:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

Explanation:

3.Apply the ideal gas law: PV = nRT solving for n. Here you can use the pressure given in atm, but you must choose the 0.0821 atm L/mole K gas constant. Or you can change 4.5 atm to 3420 mm Hg and use the 62.4 mmHg L/mole K gas constant. You must change 500 ml to 0.5 L because both gas constants have units in L, and so the volume must be in liters so it can cancel out. And of course, you must change the temperature to Kelvin.

a. n = (4.5atm)(0.5L)

moliK)(298K) = 0.092 mole (0.0821 atmiL

b. 0.092mol 32g

⎛⎝⎜ ⎞⎠⎟ = 2.9 g

1mol

c. Remember that D = mass

vol so D = 2.9g

0.5L = 5.9 g/L

When a student accidentally adds 2.0g of Mg metal instead of Zn to react with 5.0g of \(CuSO_4\), the copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate reacted to form Cu. Therefore, option C is the correct answer

\(CuSO_4 + Mg \rightarrow Cu + MgSO_4\)

Copper (II) sulfate reacts with magnesium to form copper and magnesium sulfate, and the reaction is exothermic. As a result, the temperature of the solution increases.

When magnesium is added to a copper (II) sulfate solution, the magnesium displaces copper from copper (II) sulfate, forming magnesium sulfate and copper.

The addition of magnesium instead of zinc means that the copper (II) sulfate solution would react with magnesium rather than zinc. Magnesium has a lower reactivity than zinc, which means that it will displace copper from copper (II) sulfate instead of zinc.

However, not all the copper (II) sulfate will be reacted to form copper, since only a portion of the copper (II) sulfate is consumed by the reaction with magnesium.

Therefore correct option is c " the copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate was reacted to form Cu."

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The ability of microbes to utilize N2 as a nitrogen source is called Nitrogen fixation.

Nitrogen fixation refers to the process by which certain microorganisms convert inert atmospheric nitrogen (N2) into biologically useful forms of nitrogen. Nitrogen is a crucial component of amino acids, which are building blocks of proteins and nucleic acids (DNA and RNA) essential for life.Nitrogen fixation is classified into two categories: atmospheric and industrial. Nitrogen fixation by industrial processes includes Haber-Bosch and Ostwald processes while biological nitrogen fixation is a natural process. Biological nitrogen fixation is carried out by some free-living soil bacteria, symbiotic bacteria present in the root nodules of leguminous plants, and some other groups of bacteria that live in symbiotic associations with various types of plants.

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The Ka of an acid that has a pH of 4. 67 and a concentration of 0. 448 M. is \(4. 6 \times 10^{-7}\)

pH is a measure of acidity or alkalinity of a solution on a scale of 0 to 14. A solution with a pH of 7 is neutral. Solutions with a pH below 7 are acidic and solutions with a pH above 7 are alkaline. The pH value of a solution is important for many chemical reactions and biological processes. pH is an indicator of the concentration of hydrogen ions in a solution, which can affect the behavior of other molecules and ions. pH is also used to measure the acidity of soils and other environmental variables.

D) \(4. 6 \times 10^{-7\).The Ka of an acid can be calculated using the following equation: \(Ka = 10^{(-pH)/[H_3O^+]}\). In this case, the pH = 4.67 and the concentration of the acid = 0.448 M.
Thus, Ka = \(10^{(-4.67)/(0.448)} = 4.6 \times 10^{-7.\)

Therefore the correct option is D.

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Answer:

The temp is 176k

Explanation: