HELPPPP!
I get confused :\

Answer:

okkkkk

Step-by-step explanation:

Step-by-step explanation:

please mark me as brainlest

Answer:

x = 51

Step-by-step explanation:

If the mean = 11.5, then that means all numbers added together divided by four = 11.5. Let's write this algebraically:

\(\frac{12.5+(-10)+(-7.5)+x}{4}=11.5\)

Now, let's solve for x:

\(12.5-10-7.5+x=11.5(4)\)

\(-5+x=46\)

\(x=51\)

I hope this helps!

Answer:

(x+12)(x+4)

(x-8)(x+5)

(m-7)(m-9)

Step-by-step explanation:

Helping in the name of Jesus.

The questions for grade 7 math worksheets are typically prepared by math teachers, curriculum specialists, and educational publishers.

These professionals use their knowledge of math concepts and pedagogy to create questions that are appropriate for the grade level and aligned with educational standards.

Additionally, they may use feedback from students and other teachers to refine the questions and ensure they are effective for teaching and learning. It is important for the questions to be clear, accurate, and challenging in order to help students develop their math skills and prepare for more advanced concepts.

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The CLV for transactors is $37.5, for revolvers it is $208.33, and for dormants, it is $2,000,000.

Customer Lifetime Value (CLV) is a financial analysis of the total revenue an organization can reasonably anticipate from a single customer over the course of their relationship. It is the net present value of the cash flows attributed to the relationship with a customer.

This metric is widely used in business to determine how valuable a customer is to the company.

The formula for CLV is:

CLV = (Average Value of a Sale) X (Number of Repeat Transactions) X (Average Retention Time in Months or Years)

There are three sub-segments of the credit card product: transactors, revolvers, and dormants.

The transactors are customers who pay off their credit card balance every month.

Revolvers are customers who carry a balance from month to month.

Dormants are customers who no longer use their credit card.

Each sub-segment will have a different CLV.

Here is how to calculate CLV for each sub-segment:

Transactors:

CLV = (Annual Fee) X (1/Churn Rate)

CLV = (450) X (1/12)

CLV = 37.5 dollars

Revolvers:

CLV = (Annual Interest Paid) X (Average Customer Lifespan)

CLV = (5000) X (1/24)

CLV = 208.33 dollars

Dormants:

CLV = (Number of Dormant Customers) X (Average Annual Spend per Customer) X (Profit Margin)

CLV = (10,000) X (1000) X (0.2)

CLV = 2,000,000 dollars

Therefore, the CLV for transactors is $37.5, for revolvers it is $208.33, and for dormants, it is $2,000,000.

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The house's value Increase in dollars by $37,760.

The current value of the house is $509, 760.

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. Using the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Given:

A house on the market was valued at $472,000.

After several years, the value increased by 8%.

Then, the value of house increased

= 472000 x 8/100

= $37,760

So, the current value of house

= 472000 + 37760

= $509, 760

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Answer:

When x = -2, y = 3

When x = -1, y = 0

When x = 0, y = -3

When x = 1, y = -6

Step-by-step explanation:

Given:

y = -3x - 3

Fill in the table using the following value for x

When x = -2

y = -3x - 3

y = -3(-2) - 3

y = 6 - 3

y = 3

When x = -2, y = 3

When x = -1

y = -3x - 3

y = -3(-1) - 3

y = 3 - 3

y = 0

When x = -1, y = 0

When x = 0

y = -3x - 3

y = -3(0) - 3

y = 0 - 3

y = -3

When x = 0, y = -3

When x = 1

y = -3x - 3

y = -3(1) - 3

y = -3 - 3

y = -6

When x = 1, y = -6

Answer:

18. 28 cm*2

19. 24 m

Step-by-step explanation:

18. length × l = 16

l*2= 16

l = 4

RQ = 4 cm

PR =7cm

Area of parallelogram = b×h

= 7×4

=28cm*2

19. 8 +8 + (6-2) +( 6- 2)

=24 m

The area of the raised garden is 504 square feet.

The formula for the area of a trapezoid is:

A = (b₁ + b₂) x h / 2

where b₁ and b₂ are the lengths of the two parallel bases, and h is the height of the trapezoid.

In this case, we have b₁ = 24 feet, b₂ = 32 feet, and h = 18 feet. So, plugging these values into the formula, we get:

A = (24 + 32) x 18 / 2

A = 28 x 18

A = 504 square feet

Therefore, the area of the raised garden is 504 square feet.

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Answer:

132in²

Step-by-step explanation:

Answer:

4 in

Step-by-step explanation:

reasoning: half of a circle is the diameter the radius is half of a diameter

pls give brainliest

btw if you ever need help  talk to me

btw sorry for the explanation

it wouldn't let me explain

If half of the circle is 16 inches the radios is 4 because the radios is straight line from the center to the circumference of a circle or sphere.

Answer: 4

Hope this helps~

Step-by-step explanation:

Please mark me as the brainliest answer

Answer:

x^3 - 7x^2 + 72

Step-by-step explanation:

you just subtract both equations

Answer:

the first 2

Step-by-step explanation:

5(6x + 3) + 4x = (6x + 3)5 + 4x due to the commutative rule of the multiplication (a×b = b×a).

and when you simplify the expression we get

5(6x + 3) + 4x = 30x + 15 + 4x = 34x + 15

so, the first two answer options are correct

Answer:

f(x)=x + 8

g(x)=x-5

fog=x-5+8

     =x+3

gof=x+8-5

     =x+3

gog=x-5-5

     =x-10

Answer:

Converse: If the air temperature is 32°F or less, then freezing rain is falling.

Inverse: If freezing rain is not falling, then the air temperature is not 32°F or less.

Contrapositive: If the air temperature is not 32°F or less, then freezing rain is not falling.

Explanation:

Statement: If p, then q.

Converse: If q, then p.

Inverse: If not p, then not q.

Contrapositive: If not q, then not p.

The amount of chemical in the tank after 15 minutes is 154.14 grams.

To determine the amount of chemical in the tank after 15 minutes, we need to use the formula for the concentration of a solution:

C = m/V

Where C is the concentration of the solution, m is the mass of the chemical, and V is the volume of the solution.

Initially, the tank contains 12 litres of water and 24 grams of chemical A, so the initial concentration of the solution is:

C0 = 24/12 = 2 grams per litre

The solution flows into the tank at a rate of 4 grams per litre and 4 litres per minute, so the amount of chemical flowing into the tank per minute is:

4 grams per litre × 4 litres per minute = 16 grams per minute

The well-stirred mixture flows out of the tank at a rate of 2 litres per minute, so the amount of chemical flowing out of the tank per minute is:

C × 2 litres per minute = 2C grams per minute

The net change in the amount of chemical in the tank per minute is:

16 grams per minute - 2C grams per minute = 16 - 2C grams per minute

After 15 minutes, the net change in the amount of chemical in the tank is:

(16 - 2C) grams per minute × 15 minutes = 240 - 30C grams

The final amount of chemical in the tank is:

m = 24 + 240 - 30C = 264 - 30C grams

The final volume of the solution in the tank is:

V = 12 + 4 litres per minute × 15 minutes - 2 litres per minute × 15 minutes = 42 litres

The final concentration of the solution in the tank is:

C = m/V = (264 - 30C)/42

Solving for C, we get:

42C = 264 - 30C

72C = 264

C = 264/72 = 3.67 grams per litre

The final amount of chemical in the tank is:

m = C × V = 3.67 grams per litre × 42 litres = 154.14 grams

Therefore, the amount of chemical in the tank after 15 minutes is 154.14 grams.

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Answer: Anything larger than the fraction 21/127

21/127 = 0.16535 approximately

=========================================================

Explanation:

Let's solve each inequality for x

We'll start with the first inequality

\(3(a-5x) < 1+x\\\\3a-15x < 1+x\\\\3a-1 < x+15x\\\\3a-1 < 16x\\\\16x > 3a-1\\\\x > \frac{3a-1}{16}\)

The variable x is larger than (3a-1)/16. If we knew what the value of 'a' was, then we could nail down the range of values for x more concretely.

Do the same for the second inequality

\(2 - \frac{x}{2} > 3 + 5(x-a)\\\\2 - \frac{1}{2}x > 3 + 5(x-a)\\\\2 - 0.5x > 3 + 5(x-a)\\\\2 - 0.5x > 3 + 5x-5a\\\\2 + 5a-3 > 5x+0.5x\\\\5a-1 > 5.5x\\\\5.5x < 5a-1\\\\x < \frac{5a-1}{5.5}\\\\\)

The variable x is also less than (5a-1)/(5.5)

--------------------------------------

At this point, we have found that

\(x > \frac{3a-1}{16}\) and \(x < \frac{5a-1}{5.5}\)

This means x is between those endpoints, excluding each endpoint

So we can form this compound inequality

\(\frac{3a-1}{16} < x < \frac{5a-1}{5.5}\)

This tells us the range of where x spans from.

---------------------------------------

If the endpoints are equal, aka the same value, then there's no way to have x have any solutions

So let's equate the endpoints and see what happens

\(\frac{3a-1}{16} = \frac{5a-1}{5.5}\\\\5.5(3a-1) = 16(5a-1)\\\\16.5a - 5.5 = 80a - 16\\\\-5.5 + 16 = 80a - 16.5a\\\\10.5 = 63.5a\\\\63.5a = 10.5\\\\a = \frac{10.5}{63.5}\\\\a = \frac{105}{635}\\\\a = \frac{21*5}{127*5}\\\\a = \frac{21}{127}\\\\a \approx 0.16535\\\\\)

If 'a' is equal to that value, then the two endpoints of that compound inequality are completely identical; therefore, in that situation, we wouldn't have any solutions for x.

---------------------------------------

The question is: what happens if 'a' is some number smaller than 21/127?

Let's say a = 0

So we see that -0.0625 < x < -0.1818; however, upon closer inspection, you should find that such an interval makes no sense. Why not? Because -0.0625 is not smaller than -0.1818. It should be the other way around. No number exists that is between -0.0625 and -0.1818 (I recommend using a number line to help see why this is the case).

Therefore, anything smaller than a = 21/127 will result in having no solutions for x in the original system of inequalities.

--------------------------------------

Now let's try something larger than a = 21/127

Let's say we picked a = 1

We end up with 0.125 < x < 0.7273 which is now valid because 0.125 is indeed smaller than 0.7273

Therefore, if a > 21/127, then we'll have those original system of inequalities lead to more than one solution for x.

The equation y = 5x/2 represents a proportional relationship with a constant of 5/2.

A proportional relationship is a type of relationship between two quantities in which they maintain a constant ratio to each other.

The equation that defines the proportional relationship is given as follows:

y = kx.

In which k is the constant of proportionality, representing the increase in the output variable y when the constant variable x is increased by one.

The equation for this problem is given as follows:

y = 5x/2.

Which is a proportional relationship, as it has an intercept of zero, along with a constant of k = 5/2.

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¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)

Proof:

1. ∃x(Fx & Gx) [Premise]

2. Fx & Gx [∃-Elimination, 1]

3. ∃xFx [∃-Introduction, 2]

4. ∃xGx [∃-Introduction, 2]

5. ∃xFx & ∃xGx [Conjunction Introduction, 3 and 4]

6. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx [1-5, Modus Ponens]

ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks)

Proof:

1. ¬ 3x(Px v Qx) [Premise]

2. ¬ Px v ¬ Qx [DeMorgan’s Law, 1]

3. Vx ¬ Px [∀-Introduction, 2]

4. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px [1-3, Modus Ponens]

iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)

Proof:

1. ¬ Vx(Fx → Gx) v 3xFx [Premise]

2. (¬ Vx(Fx → Gx) v 3xFx) → (¬ Vx(Fx → Gx) v Fx) [Implication Introduction]

3. ¬ Vx(Fx → Gx) v Fx [Resolution, 1, 2]

4. (¬ Vx(Fx → Gx) v Fx) → (Fx → Gx) [Implication Introduction]

5. Fx → Gx [Resolution, 3, 4]

6. ¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

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Answer:

82°

Step-by-step explanation:

 The exterior angle of triangle equals the sum of opposite interior angles.

 ∠C + ∠B = 143°

  61+ ∠B  = 143

         ∠B  = 143 - 61

         ∠B = 82°

The property which guarantees that a twice-differentiable function has a relative minimum at x =c is the statement that f(c) = 0 and f''(c) > 0. Hence, option B is the correct answer.

Explanation:According to the second derivative test, if f''(c) > 0 and f(c) = 0, then the function f has a relative minimum at x = c. We're given that f is a function with two continuous derivatives. If f(c) = 0 and f(c) is less than zero, it is still possible for f to have a relative minimum, but only if the second derivative is negative and changes to positive at x = c.If f(0) = 0 and f(c) is less than zero, then we cannot conclude that f has a relative minimum at x = c since the second derivative is not guaranteed to be greater than zero at x = c. We can rule out f(x) > 0 for x since this is not a property that has anything to do with relative minima.

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The population of an island in 1950 was 2 million. The population grew exponentially for 63 years and reached 6.5 million in 2013. The carrying capacity of the island is estimated to be 10 million.

If the population growth rate in the future is similar to the last 50 years, what will the population be in 2050

The population is given to be increasing exponentially, which means it will follow the equation:

\($P(t) = P_0 e^{rt}$\)Here,\($P(t)$\) is the population after a period of time \($t$, $P_0$\) is the initial population, $r$ is the annual growth rate (which we are given is the same as the growth rate of the last 50 years), and \($t$\) is the time.

We can find the annual growth rate $r$ using the formula:\($$r = \frac{\ln{\frac{P(t)}{P_0}}}{t}$$\)
We know\($P_0 = 2$ million, $P(t) = 6.5$ million, and $t = 63$\) years. Substituting these values, we get:

\($r = \frac{\ln{\frac{6.5}{2}}}{63} = 0.032$\) (rounded to 3 decimal places)

Since the carrying capacity of the island is 10 million, we know that the population will not exceed this limit.

Therefore, we can use the logistic model to find the population growth over time. The logistic growth model is:

\($$\frac{dP}{dt} = r P \left(1 - \frac{P}{K}\right)$$\)

where $K$ is the carrying capacity of the environment. This can be solved to give:\($P(t) = \frac{K}{1 + A e^{-rt}}$\)

where \($A = \frac{K-P_0}{P_0}$. We know $K = 10$ million, $P_0 = 2$ million, and $r = 0.032$\). Substituting these values, we get:\($A = \frac{10-2}{2} = 4$\)

Therefore, the equation for the population of the island is:\($P(t) = \frac{10}{1 + 4 e^{-0.032t}}$\)

To find the population in 2050, we substitute\($t = 100$\) (since 63 years have already passed and we want to find the population in 2050, which is 100 years after 1950):

\($P(100) = \frac{10}{1 + 4 e^{-0.032 \times 100}} \approx \boxed{8.76}$ million\)
Therefore, the estimated population of the island in 2050, assuming constant carrying capacity and consumption per capita, is approximately 8.76 million.

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To obtain the complete IPR curve, we can calculate the flow rates for a range of well shut-in static pressures and plot them on a graph.

Fetkovich's method is used to plot the Inflow Performance Relationship (IPR) curve for a well. The IPR curve represents the relationship between the flow rate of a well and the corresponding pressure drawdown.

To plot the IPR curve using Fetkovich's method, we need the following parameters:

pi: Initial reservoir pressure (psia)

Jo': Productivity index (stb/day-psia^2)

The equation for the IPR curve using Fetkovich's method is:

q = (pi - pwf) / (Bo * Jo')

Where:

q: Flow rate (STB/day)

pwf: Well shut-in static pressure (psia)

Bo: Oil formation volume factor (reservoir volume / stock tank volume)

To predict the IPRs of the well at different well shut-in static pressures (2500psia, 2000psia, 1500psia, and 1000psia), we can substitute the values of pwf into the IPR equation and solve for the corresponding flow rates (q).

Assuming we have the necessary data, let's calculate the IPRs for the given well:

pi = 3000 psia

Jo' = 4 × 10^-4 stb/day-psia^2

We'll also assume a constant oil formation volume factor (Bo) for simplicity.

Now, let's calculate the flow rates (q) at the specified well shut-in static pressures:

For pwf = 2500 psia:

q = (pi - pwf) / (Bo * Jo')

q = (3000 - 2500) / (Bo * 4 × 10^-4)

For pwf = 2000 psia:

q = (pi - pwf) / (Bo * Jo')

q = (3000 - 2000) / (Bo * 4 × 10^-4)

For pwf = 1500 psia:

q = (pi - pwf) / (Bo * Jo')

q = (3000 - 1500) / (Bo * 4 × 10^-4)

For pwf = 1000 psia:

q = (pi - pwf) / (Bo * Jo')

q = (3000 - 1000) / (Bo * 4 × 10^-4)

To obtain the complete IPR curve, we can calculate the flow rates for a range of well shut-in static pressures and plot them on a graph.

Please provide the value of the oil formation volume factor (Bo) to proceed with the calculation and plotting.

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The possible values of ∠G range from approximately 3.8° to 16°, to the nearest tenth of a degree.

To find the possible values of ∠G in triangle ΔEFG, we can use the fact that the sum of the angles in a triangle is always 180 degrees.

Given:

∠F = 32°

To find ∠G, we can use the equation:

∠G = 180° - ∠E - ∠F

Since we don't have information about ∠E, we can use the triangle inequality theorem to determine a range of possible values for ∠E.

According to the triangle inequality theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

In this case, we have:

EF + FG > EG

6.1 + 9.9 > EG

16 > EG

Also,

EF + EG > FG

6.1 + EG > 9.9

EG > 3.8

Combining these inequalities, we have:

3.8 < EG < 16

Now, let's find the range of possible values for ∠G by substituting the range of possible values for EG into the equation:

180° - ∠E - 32° = ∠G

Subtracting 32° from both sides, we have:

148° - ∠E = ∠G

Now, substituting the range of possible values for EG, we get:

148° - ∠E = ∠G

148° - ∠E = 3.8° to 16°

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The exact value of sin(u-v) is -77/85. This can be answered by the concept of Trigonometry.

Given the information, we can find the exact value of sin(u-v).

We know that sin(u) = -3/5 and cos(v) = 15/17. Since 3/2 < u < 2, u is in the fourth quadrant where sin is negative, and 0 < v < π/2, v is in the first quadrant where cos is positive.

We can use the trigonometric identity for sin(u-v): sin(u-v) = sin(u)cos(v) - cos(u)sin(v).

First, we need to find cos(u) and sin(v). We can use the Pythagorean identities: sin²(u) + cos²(u) = 1 and sin²(v) + cos²(v) = 1.

For u:
sin²(u) = (-3/5)² = 9/25
cos²(u) = 1 - sin²(u) = 1 - 9/25 = 16/25
cos(u) = √(16/25) = 4/5 (cos is positive in the fourth quadrant)

For v:
cos²(v) = (15/17)² = 225/289
sin²(v) = 1 - cos²(v) = 1 - 225/289 = 64/289
sin(v) = √(64/289) = 8/17 (sin is positive in the first quadrant)

Now we can use the identity sin(u-v) = sin(u)cos(v) - cos(u)sin(v):
sin(u-v) = (-3/5)(15/17) - (4/5)(8/17) = -45/85 - 32/85 = -77/85

So, the exact value of sin(u-v) is -77/85.

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The optimal solution for the amount of cash to withdraw each time to minimize transportation costs and maximize interest earnings is determined by calculating the Economic Order Quantity (EOQ) using the formula Q = √((2 * C * T) / r), and rounding the result to a convenient amount.

The Economic Order Quantity (EOQ) model is typically used for inventory management, not for optimizing cash withdrawals. However, if we assume that the question is seeking an optimal withdrawal strategy to minimize transportation costs and maximize interest earnings, we can approach it as follows:

Let's denote:

C = Annual cash need ($5,000)

T = Transportation cost per visit ($5)

r = Annual interest rate (5%)

To find the optimal solution for the amount of cash to withdraw each time, we can consider the trade-off between transportation costs and interest earnings. The objective is to minimize the total cost.

Calculate the optimal order quantity (Q) using the EOQ formula:

Q = √((2 * C * T) / r)

Round the calculated Q to the nearest convenient amount, such as multiples of $100 or $500.

The optimal solution would be to withdraw the rounded Q amount each time to minimize transportation costs while still meeting the annual cash need.

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Answer:

Olivia spent 129 minutes or 2:15 doing all the homework

Step-by-step explanation:

Answer: 47.4 or -42.6/negative

Step-by-step explanation: i tried my best