Answers
Answer:
d) 0.3 microns or smaller
Related Questions
I. An atom is the smallest unit of an element and a molecule is made up of two or more atoms chemically bonded together.
II. An atom is indivisible and a molecule can be broken down into atoms.
III. An atom is the smallest unit bonded together and a molecule is made up of elements.
IV. An element is the smallest unit of an atom and a molecule is made up of two or more metal and non-metal atoms chemically bonded together.
Which conclusion(s) best elaborate on the difference(s) between an atom and a molecule?
A) I & II
B) II & III
C) III & IV
D) IV & I
Answers
Answer:
I think it's the first and the second ... but I'm not sure
Krusty the clown was told that a certain itching powder, called Itch-Might is the newest thing on the market. It claims to last 50% longer than other itching powders. Krusty buys the new powder and compares it to his usually itching powder, Scratch-A-lot. then krusty designs an experiment. Group A is given the Itch-Might powder and Group B is given the Scratch-A-Lot powder. Group A reported
itching for 25 minutes and group B reported itching for 35 minutes.
Which group was the control?
1.Group A
2.Group B
Answers
Answer:
group a
Explanation:
Google said
Answer:
17 was The type of itch powder
Explanation:
Helps
Please !!!!!!!
Answers
Answer:
parts of x-ray
Explanation:
this is part of x ray of x ray I want to know if you are interested to show some idea because my brain gonna blow
Choose the reason(s) why plants need fertilizer. (There may be more than one answer.)
To provide oxygen
To provide nitrogen for proteins
To provide carbon dioxide
To provide various minerals
To provide protein for plant growth
Answers
Answer:
Explanation:Fertilizers are food for plants.Plants get carbondioxide from air and release oxygen.They are added to the soil to make up the deficiency of essential elements like nitrogen,phosphorus and potassium required for the proper growth of plants.
What global climatic change gave gymnosperms an advantage over ferns?
A) Increased fluctuations in global climate
B) the climate becoming hotter and wetter
C) the climate becoming cooler and drier
D) the climate becoming hotter and drier
Answers
Answer:
it is D
What global climatic change gave gymnosperms an advantage over ferns?
A) Increased fluctuations in global climate
B) the climate becoming hotter and wetter
C) the climate becoming cooler and drier
D) the climate becoming hotter and drier
The climate becoming hotter and drier which is the global climatic change gave gymnosperms an advantage over ferns. So, the correct option is D.
What are Gymnosperms?In contrast to angiosperms, or blooming plants, whose seeds are enclosed by fully developed ovaries, or fruits, gymnosperms are described as any vascular plant that reproduces by an exposed seed, or ovule. Many gymnosperms bear their seeds in cones, which are known as "uncovered seeds" because they are not visible until they are fully developed.
Pinophyta, Cycadophyta, Ginkgophyta, and Gnetophyta are the four classes of gymnospermous plants, having 88 genera and more than 1,000 species among them. Gymnosperms have an advantage over ferns as a result of the temperature growing hotter and drier as a result of global climate change.
Therefore, the correct option is D.
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Be sure to answer all parts.
Find the pH and the volume (mL) of 0.407 M HNO3 needed to reach the equivalence point in the titration of 2.65 L of 0.0750 M pyridine (C5H5N, Kb = 1.7 × 10−9).
Volume = mL HNO3
pH =
Answers
Answer:
pH = 3.215
Explanation:
From the given information;
Using the equation for the dilution of a stock solution:
Since moles of C5H5N = moles of HNO3
Then:
\(M_{C_5H_5N}\times V_{C_5H_5N}= M_{HNO_3}\times V_{HNO_3}\)
\(0.0750 M \times 2.65 L = 0.407 M \times V_{HNO_3}\)
\(V_{HNO_3}= \dfrac{0.0750 M \times 2.65 L}{0.407 M}\)
\(V_{HNO_3}=488.33 \ mL\)
The reaction between C5H5NH and H2O is as follows:
\(C_5H_5N^+H + H_2O\) ⇄ \(C_5H_5N + H_3O^+\)
\(Molarity \ of \ C_5H_5N^+H = \dfrac{moles}{addition \ of\ the\ total\ volume}\)
\(Molarity \ of \ C_5H_5N^+H = \dfrac{0.0750 \ M \times 2.65 \ L}{2.65 \ L + 0.48833 \ L}\)
\(Molarity \ of \ C_5H_5N^+H = \dfrac{0.19875 \ ML}{3.13833 L }\)
\(= \ 0.06333\ M\)
Now, the next step is to draw out the I.C.E table.
\(C_5H_5N^+H + H_2O\) ⇄ \(C_5H_5N + H_3O^+\)
I 0.06333 0 0
C - x x x
E 0.06333 -x x x
\(K_a = \dfrac{10^{-14}}{1.7 \times 10^{-19}} \\ \\ K_a = 5.8824 \times 10^{-6}\)
\(K_a = \dfrac{[C_5H_5N][H_3O^+] }{[C_5H_5N^+H] } \\ \\ 5.8824 \times 10^{-6} = \dfrac{x^2}{0.06333 - x}\)
Assuming x < 0.06333
\(x^2 = 5.8824 \times 10^{-6} \times 0.06333\)
Then
\(x^2 = 3.72532392 \times 10^{-7} \\ \\ x= \sqrt{3.72532392 \times 10^{-7}} \\ \\ x = 6.1035 \times 10^{-4} \ M\)
\([H_3O^+] = x = 6.1035 \times 10^{-4} \ M \\ \\ pH = -log (6.1035 \times 10^{-4}) \\ \\ \mathbf{\\ pH = 3.215}\)
The pH for HNO3 needed to reach the equivalence point in the titration of 2.65 L of 0.0750 M pyridine (C5H5N, Kb = 1.7 × 10−9) is
HNO3 + C5H5N→CSH5NH + + NO3
Moles of C5H5N = volume x concentration
=2.65 x 0.0750
=0.1987 mol
Moles of HNO3 needed = moles of C5H5N = 0.19875 mol Volume of HNO3 eeded = moles / con
=0.19875/0.54
=0.363L
=363 mL
At the equivalence point, most effective C5H5NH + a NO3-are Moles of C5H5NH+ = moles of C5H5N = 0.19875 mol
Total extent of answer n = 2.65 + 0.363 =3.013 L
Initial concentration [ C5H5NH + ] o = moles/ volume =0.19875/3.013 =0.06596 M
Kb of C5H5N = 1.7 x 10 ^ 9
By fixing the equation,
H + = 6.199 * 10 ^ 4 M
pH=-log[H+]
=3.207
=3.21 pH
What is pH ?The pH is the degree of ways acidic or simple a substance is. In humans, pH stability performs a position in preserving the frame functioning optimally. The best pH of the frame is barely alkaline, which helps sure biochemical reactions like oxygenating the blood.
Thus it is clear above.
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Strong sugar solution A Pin holding potato .Potato Pure water -Beaker 1.4.1 State TWO differences between the process investigated in the diagram above and diffusion. 1.4.2 Give ONE planning step that should be considered prior to this Investigation. 1.4.3 Explain the importance of the potato in this investigation.
Answers
1.4.1 Two differences between the process investigated in the diagram above and diffusion:
In the diagram, the process being investigated involves osmosis, not diffusion. Diffusion refers to the movement of particles from an area of higher concentration to an area of lower concentration, while osmosis specifically refers to the movement of water molecules across a semi-permeable membrane.In osmosis, the movement of water molecules occurs in response to the concentration gradient of solute particles, whereas in diffusion, the movement of particles is driven solely by the concentration gradient of the particles themselves.1.4.2 One planning step that should be considered prior to this investigation:
It is important to establish a clear and measurable objective for the investigation. This could involve defining the specific research question or hypothesis that the investigation aims to address. Having a well-defined objective will help guide the experimental design and ensure that relevant data is collected.1.4.3 The importance of the potato in this investigation:
The potato is important in this investigation because it serves as the object of study or the sample material through which osmosis is observed. The potato, being a plant tissue, contains cells with semi-permeable membranes that allow the passage of water molecules but restrict the movement of solute particles. By placing the potato in the strong sugar solution and observing the changes in its weight or texture, one can study the process of osmosis and the effects of water movement across the potato cells. The potato serves as a model system to understand the principles and mechanisms of osmosis in biological systems.for similar questions on sugar solution.
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What is the BEST definition of deciduous?
becoming inactive during the winter or other unfavorable times
shedding leaves on a yearly cycle
moving to an area that is warmer
taking moisture directly from the air
Answers
Answer:
shedding leaves on a yearly cycle
Answer:
shedding leaves on a yearly cycle
Fill in the blanks
a. In general, ____________ moisture levels are associated with lower microbial diversity.
b. Bacteria in the small intestine thrive in _____________ pH than stomach bacteria.
c. The likelihood Of colonization by skin pathogens is ____________ when normal microbiota are present.
d. The occurrence of opportunistic infections ___________ in immunocompromised patients.
1. Higher
2. Lower
Answers
Answer:
a. lower
b.higher
c.lower
1.Higher
Explanation
Moisture is a great environment for bacteria to grow, the moister the environment is the more the bacteria will thrive, thinking about this lower moisture levels will result in lower microbial diversity.
The small intestine has higher ph than the stomach, this means that the bacteria there thrive in higher ph than the stomach bacteria.
Normal microbia in the skin usually acts as the first barrier against pathogens, while we have normal microbia it will protect us and will be less likely to get skin pathogens.
Immunocompromised patients are people that have received treatment to reduce their immunological system capacity, this means that even though this is done to battle a disease, another opportunistic infection can appear and take advantage of the fact that the defenses are low.
What are the processes that are occurring during interphase of the cell cycle.
Answers
Answer:
The cell is replicating its organelles and DNA. It's basically growing to prepare for mitosis.
Explanation:
How is zoology related to biology?
Answers
Answer:
Zoology (also known as animal science) is the branch of biology devoted to study of animal life.
Explanation:
It covers areas ranging from the structure of organisms to the subcellular unit of life.
Which hypothesis proposes the correct explanation for the variety of traits in a species?
A. Cloning creates variety because offspring receive genetic material that is different from that of their parent.
B. Budding creates variety because offspring receive genetic material that is different from that of their parent.
C. Sexual reproduction creates variety because offspring have a different combination of genetic material than either parent.
D. Fragmentation and regeneration create variety because offspring receive genetic material that is different from that of their parent.
Answers
Answer:
A. Cloning creates variety because offspring receive genetic material that is different from that of their parent.
Explanation:
Which two tissues in the leaf transports substances around the plant
Answers
Answer:
i think this is the answer
Explanation:
Plant transport tissues - xylem and phloem Plants have two transport systems - xylem and phloem. Xylem transports water and minerals. Phloem transports sugars and amino acids dissolved in water.
Describe the general body morphology of a sponge. Then discuss some of a sponge's specialized cells, their function, and where they can be found. Using your best grammar, write 4-6 sentences
Answers
A sponge is an aquatic invertebrate animal with a diverse body structure, sponges are composed of specialized cells such as collar cells or choanocytes, and are found in the inner choanocyte layer.
The general body morphology of a sponge involves the presence of small pores or holes (ostia) on the body surface, which allow water to flow into the sponge. The water is then circulated inside the body of the sponge, which allows it to trap tiny organisms or organic particles for food consumption. They have a flagellum and collar-like structure that help to capture food.
Additionally, sponges contain amebocytes, which are mobile cells responsible for food uptake and waste disposal, and spicules, which provide support and protection for the sponge. These specialized cells are found in the inner layer of the sponge body.. Another specialized cell type is the amebocytes, located in the mesohyl, which play a role in digestion, nutrient transport, and structural support.
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“Fortunately, the V-2 came too late in the war to help the Germans win.” How did the United State's rocketry program, NASA, etc. benefit from this?
Answers
The way that United State's rocketry program, NASA, etc. benefit from the issue with e V-2 was that While the Space Race frequently fueled Cold War rivalry and anxiety, it also had significant positive effects on human society. Telecommunications, microtechnology, and other fields all experienced significant advancements as a result of space exploration.
What advantages does the NASA space program offer?The singular goal of NASA offers advantages both large and small. Spending in space exploration boosts the economy, creates jobs, and kickstarts businesses. Our inventions enhance day-to-day living, promote medical knowledge, aid in disaster relief efforts, and more.
Therefore, The Space Race was crucial because it revealed which nation had the best economy, science, and technology in the globe. Both the United States and the Soviet Union knew after World War II how crucial rocket research would be for the military.
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whut is a biofultproduc
Answers
I don’t know if this is what you were asking, but I will put it here just in case.
How would the South America boa constrictor which eats amphibians be categorized in this ecosystem
Answers
HELP ASAP PLEASE DUE LAST WEEK BRAINLIEST
Answers
In camellia plants, flower color is controlled by a single gene with codominant alleles. A camellia plants with red flowers (R) is crossed with a camellia plant with white flowers (WW). What are the expected phenotypes of the offspring of this cross?
O A. All will have both red and white flowers.
• B. All will have red flowers.
O c. Half will have red flowers and half will have white flowers.
• D. All will have pink flowers.
Answers
Half will have red flowers and half will have white flowers (option c).
In camellia plants, flower color is controlled by a single gene with codominant alleles. In this case, one parent plant has red flowers (R), while the other parent plant has white flowers (WW).
When two organisms with codominant alleles are crossed, both alleles are expressed equally in the offspring. Therefore, in this cross, the offspring will inherit one allele for red flowers (R) from the red-flowered parent and one allele for white flowers (W) from the white-flowered parent.
The possible combinations of alleles that the offspring can inherit are RW and RW.
When the alleles RW and RW combine, the resulting genotypes are RR (red-flowered) and RW (pink-flowered). However, since the allele for white flowers (W) is recessive to the allele for red flowers (R), the plants with the RW genotype will exhibit the dominant red flower phenotype.
Therefore, half of the offspring will have the RR genotype and display red flowers, while the other half will have the RW genotype and also display red flowers. None of the offspring will have the WW genotype, so there won't be any white flowers.
Hence, the expected phenotypes of the offspring of this cross are that half will have red flowers and half will have white flowers. Thus, the correct option is c.
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Explain the structure of Brazil’s government and describe Brazil’s unusual voting requirements
Answers
Brazil's main government structure is a federal republic. The peculiar voting requirements in Brazil are compulsory voting.
The term "federal republic" refers to the division of powers between the government and individual subdivisions. The central government controls major authorities like as defense, security, and monetary policy, while states manage infrastructure, local choices, education policy, and maintenance.
It is divided into three distinct branches: executive, legislative, and judicial. The President exercises executive power with the guidance of the cabinet. Legislative power is held by Congress, whereas judicial power is held by the judiciary, which is supported by the Supreme and regional Courts.
Voting is made compulsory for literates aged 18 to 70, including citizens living abroad, and not required for those aged 16 to 17, over 70, or illiterates of any age.
A justification form must be provided if you do not vote at an electoral center or post office. The dramatic growth in invalid balloting in Brazil elections highlights the requirement and relevance of institutional reforms in order to create a democratic democracy, with serious consequences.
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In which irrigation system wastage of water is the less?
A) Raised bed irrigation method
B) Sprinkle irrigation method
C) Drop irrigation method
D) Drain irrigation method
Answers
Answer: C) Drop irrigation method
Brainliest pls if correct!i begging you please help me
Theme . Anatomical and functional features of
TMJ at children depending of age. Clinical examination of patient with TMJ pathology, classification of diseases. Diseases of TMJ in children, clinical symptoms of acute and chronic diseases. Differential diagnostics, principles of treatment, prevention of diseases.
1. The clinical signs of MPD are following except:
A. teeth frequently have wear facets
B. daytime clenching or nocturnal bruxism.
C. range of mandibular movement may be decreased.
D. diffuse, poorly localized, preauricular pain..
E. crepitus, located directly over the TMG.
2. Radiographic appearance of DJD:
A. decreased joint space, surface erosions, osteophytes, and flattening of the condylar head.
B. radiographs of the tmjs are usually normal.
C. MRI images usually demonstrate anterior displacement of the disk.
D. erosive changes in the anterior and posterior aspects of the condylar heads.
E. irregular articular surfaces of the condyle and fossa, with varying degrees of calcified connection between these articulating surfaces.
3. Synovial fluid is a:
A. liquid of lymphatic systems
B. serous exudate from articular cavitas.
C. oral liquid which mixed blood lubricant.
D. filtrate of plasma that passes through fenestrations in the subendothelial capillaries.
E. secret of epithelial lining which covered articular surfaces.
4. Click occurring during the opening movement. It’s sign of:
A. disk displacement disorders.
B. mpd.
C. djd.
D. ankylosis.
E. acute infectious arthritis.
5. When the mandibular condyle translates anteriorly in front of the articular eminence and dislocations can’t be reduced may be necessary:
A. limitation of motion.
B. anesthesia of the auricular temporal nerve and the muscles of mastication.
C. using of stronger analgesics.
D. emg biofeedback and relaxation training, ultrasound, spray and stretch, and pressure massage.
E. occlusal splints.
6. Tricyclic antidepressants are administered in patient with:
A. systemic arthritic conditions.
B. acute arthritis.
C. anterior disk displacement without reduction.
D. degenerative joint disease.
E. mpd causing bruxism
7. The articular disc receives nutrition from:
A. intercellular space.
B. true vessels.
C. vessels of fibrous cartilage.
D. sinovial fluid. E. oral liquid.
8. By MPD the pain is a result of:
A. damage of articular disk
B. increased pressure in joint space.
C. abnormal muscular function or hyperactivity.
D. accumulate exudate in joint space.
E. articular surface flattening, erosions.
9. The pain syndrome in infectious arthritis of TMJ is result of:
A. increased pressure in joint space.
B. abnormal muscular function or hyperactivity.
C. damage of articular disk.
D. accumulate exudate in joint space.
E. articular surface flattening, erosions.
10. Etiologic factors suggested as contributing to the development of TMD are following except:
A. trauma.
B. immaturity of connective tissue structures.
C. occlusal factors.
D. parafunctional habits. E. posture.
11. Malocclusion associated with TMD is following:
A. all of above listed.
B. skeletal anterior open bite.
C. overjet greater than 6 to 7 mm.
D. retrocuspal position (centric relation) to intercuspal position (centric occlusion) slides greater than 4 mm.
E. unilateral lingual cross bite.
12. The muscles should be palpated for the presence of following features except:
A.spasm.
B. tenderness.
C. fasciculations.
D. fiber disruption
E. trigger points.
13. Normal range of movement of an adult's mandible is about:
A. 45 mm vertically (i.e., interincisally) and 10 mm protrusively and laterally.
B. 35 mm vertically (i.e., interincisally) and 15 mm protrusively and laterally.
C. 25 mm vertically (i.e.,
interincisally) and 10 mm protrusively and laterally.
D. 15 mm vertically (i.e., interincisally) and 15 mm protrusively and laterally.
E. 55 mm vertically (i.e., interincisally) and 20 mm protrusively and laterally.
Answers
Explanation:
I have provided the answers to the questions based on the given text below:
1. E. crepitus, located directly over the TMG.
2. A. decreased joint space, surface erosions, osteophytes, and flattening of the condylar head.
3. B. serous exudate from articular cavitas.
4. A. disk displacement disorders.
5. E. occlusal splints.
6. E. mpd causing bruxism
7. C. vessels of fibrous cartilage.
8. C. abnormal muscular function or hyperactivity.
9. D. accumulate exudate in joint space.
10. B. immaturity of connective tissue structures.
11. A. all of above listed.
12. D. fiber disruption. 13. A. 45 mm vertically (i.e., interincisally) and 10 mm protrusively and laterally.
Explain very simply how the X-ray diffraction process aids in solving structures of biological molecules.
Answers
Because x-rays and covalent bonds have a similar wavelength, x-ray crystallography currently offers the finest depiction of protein structure because it can show the accurate three-dimensional positions of the majority of atoms in a protein molecule.
What is X-ray diffraction?X-ray crystallography is an experimental science that determines the atomic and molecular structure of a crystal. In this experiment, the crystalline structure of the crystal causes a beam of incident X-rays to diffract into many specific directions, which allows the scientist to determine the atomic and molecular structure of the crystal.
Because x-rays and covalent bonds have a similar wavelength, x-ray crystallography is currently the method that provides the best visualization of protein structure. This is because it can reveal the precise three-dimensional positions of most of the atoms that are contained within a protein molecule.
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What new knowledge was gained from Frederick Griffiths work with pneumococci bacteria
Answers
Answer:The new knowledge gained from Frederick Griffith's work with pneumococci bacteria is that bacteria contain a physical substance that can change the structure of other bacteria. Therefore, option 3 is the correct answer.
Explanation:
What 2 molecules can be used to determine blood type?
Answers
Red blood cell antigens determine your blood group
Answer: The antigens expressed on the red blood cell determine an individual's blood group. The main two blood groups are called ABO (with blood types A, B, AB, and O) and Rh (with Rh D-positive or Rh D-negative blood types).
By looking at calendars, you can observe cycles, such as the cycle of the school year and summer vacation. On the lines below, write about cycles in your life
Answers
Answer:
what are the options for the answer
Explanation:
how does the latitude of a region affect its climate
Answers
byun walked 15 blocks in 25 minutes what was his average speed
Answers
Answer:
\(\frac{3}{5}\)blocks/minutes
Explanation:
Given parameters:
Number of blocks walked = 15blocks
Time taken for the walk = 25minutes
Unknown:
Average speed = ?
Solution:
In this scenario, the average speed is the rate of walking the blocks per unit of time;
Average speed = \(\frac{number of blocks}{time}\)
Input the parameters and solve;
Average speed = \(\frac{15}{25}\)blocks/minutes
Average speed = \(\frac{3}{5}\)blocks/minutes
How does the style of a tulip play a role in reproduction
Answers
Hello!
The Answer Is : This stigma embraces pollen deposited on the tip where it flies down to the ovaries of the tulip to pollinate unfertilized seeds within, known as ovules. In the reproduction of the plant, the sections of a tulip flower play a part.Thank you for asking this question!
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what would happen to the smooth er if the rough er was broken