The cubic polynomial can be computed using the following formula if the zeros of a cubic polynomial's product and sum are known: (x - sum of zeros) (x² + product of zeros) is a cubic polynomial.
A three-degree polynomial is referred to as a cubic polynomial. The cubic polynomial can be computed using the following formula if the zeros of a cubic polynomial's product and sum are known:
cubic function = (x - sum of zeros)
(x² + zero product)
For instance, the cubic polynomial is (x + 1)(x2 - 4) if the product of the zeros is 4 and the total of the zeros is -1.
The cubic polynomial is illustrative of:
ax³ + bx² + cx + d = 0
In the general case, where a, b, c, and d are constants.
The product of the zeros is given by: d/a ,
The zeros' sum is given by : - b/a.
These numbers are substituted into the cubic polynomial's general equation to produce the following result:
ax³ + bx² + cx + d = a(x³ + (-b/a)x² + (d/a)x)
= a(x³ - bx + d)
Therefore, if the product and sum of the zeros are known, the cubic polynomial may be obtained.
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Using the 100/50/20 Rule for daily fluid requirements (DFR). Calculate the following questions, do not round the patient's weight but round all final answers to a whole number. 1-10 kg = 100ml/kg/day 11-20 kg = 50ml/kg/day (+ 1000 mL/day for 1* 10kg) Over 20kg = 20mL/kg/day (1500 mL/day for 1s 20kg) 18. An infant weighs 11 pounds. What is the required amount of fluid per day in ml? I 19. A child weighs 31 lbs and 8 ozs. What is the required amount of fluid per day in ml? If no oral fluids are consumed, what is the hourly IV flow rate to maintain proper hydration?
18. An infant weighs 11 pounds which is equivalent to 4.98 kg. Using the 100/50/20 Rule, the required amount of fluid per day for an infant between 11-20 kg is 50 ml/kg/day. So, the required amount of fluid per day in ml is 4.98 kg x 50 ml/kg/day = 249 ml/day.
19. A child weighs 31lbs and 8 ozs which is equivalent to 14.21 kg. Using the 100/50/24 Rule, the required amount of fluid per day for a child over 20 kg is 20 ml/kg/day. So, the required amount of fluid per day in ml is 14.21 kg x 20 ml/kg/day = 284.2 ml/day.
If no oral fluids are consumed, the hourly IV flow rate to maintain proper hydration would be: 284.2 ml/day / 24 hours/day = 11.8 ml/hour.
Daily Fluid Requirements (DFR)The question is about fluid requirements for infants and children, and it is using the 100/50/20 Rule for Daily Fluid Requirements (DFR) to calculate the required amount of fluid per day for different weight ranges. The 100/50/20 Rule is a guideline used to determine the appropriate amount of fluid that infants and children should receive on a daily basis based on their weight. The rule states that for infants and children up to 10 kg, the recommended fluid intake is 100 ml/kg/day, for those between 11-20 kg it is 50 ml/kg/day, and for those over 20 kg it is 20 ml/kg/day.
The question also asking about the hourly IV flow rate to maintain proper hydration if no oral fluids are consumed.
This subject is part of pediatrics, more specifically in the field of fluid and electrolyte balance and management.
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If A and B are any two events defined on a sample space S of an experiment, then p(A ∩ B) = p(A).p(B)
True or False
The statement is True only for independent events and False otherwise. The statement "p (A ∩ B) = p(A). p(B)" is not always true for any two events A and B defined on a sample space S of an experiment.
This equation only holds true if A and B are independent events, meaning that the occurrence of one event does not affect the probability of the other event happening. In other words, p(A|B) = p(A) and p(B|A) = p(B).
If A and B are dependent events, meaning that the occurrence of one event affects the probability of the other event happening, then the equation does not hold true. In this case, the probability of A and B occurring together (p(A ∩ B)) would be less than the product of the probabilities of A and B occurring separately (p(A).p(B)).
Therefore, the statement is not always true and depends on whether A and B are independent or dependent events.
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For the rotation -442°, find the coterminal angle from 0° < Theta < 360°, the quadrant, and the reference angle.
Step-by-step explanation:
To find the coterminal angle with -442° we can add or subtract any integer multiple of 360°.
-442° + 360° = -82°
So one coterminal angle with -442° is -82°.
To determine the quadrant, we need to consider the sign of the angles in each quadrant. Since -442° is negative, it lies in the clockwise direction, which means it falls in the fourth quadrant.
To find the reference angle, we need to find the acute angle between the terminal side of the angle and the x-axis. We can do that by subtracting the nearest multiple of 360°.
-442° + 360° = -82° (the smallest positive coterminal angle)
Reference angle = 82°
Therefore, the coterminal angle with -442° between 0° and 360° is 318°, it lies in the fourth quadrant and the reference angle is 82°.
In both the Vendor Compliance at Geoffrey Ryans (A) and
Operational Execution at Arrows Electronics there are problems and
challenges. Integrate the problems and challenges from both
cases.
In both the Vendor Compliance at Geoffrey Ryans (A) and Operational Execution at Arrows Electronics cases, there are common problems and challenges. These include issues related to vendor management.
One of the key problems faced by both companies is vendor compliance. This refers to the ability of vendors to meet the requirements and standards set by the company. Both cases highlight instances where vendors fail to meet compliance standards, leading to disruptions in the supply chain and operational inefficiencies. This problem affects the overall performance and profitability of the companies.
Another challenge faced by both companies is operational execution. This encompasses various aspects of operations, including inventory management, order fulfillment, and delivery. In both cases, there are instances where operational execution falls short, leading to delays, errors, and customer dissatisfaction. This challenge requires the companies to streamline their processes, improve communication and coordination, and enhance overall operational efficiency.
Overall, the problems and challenges in both cases revolve around effective vendor management, supply chain optimization, and operational excellence. Addressing these issues is crucial for both companies to improve their performance, meet customer demands, and maintain a competitive edge in the market.
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i don't know how to solve this please help.
Answer:
equation: 17 +3m = 28.7m = 3.9Step-by-step explanation:
You want an equation and its solution to help you find the number of miles Carter must ride his bicycle each day (m) to total 28.7 miles after 3 more days, given he has already ridden 17 miles this week.
RelationThe total number of miles for the week will be 28.7. That will consist of the sum of miles already ridden (17) and the number each day multiplied by the remaining number of days.
The miles ridden each day is defined in the problem statement as "m". The number of remaining days is 3, so the total number of miles ridden on those days will be 3m.
Carter wants the sum to be ...
17 +3m = 28.7
This is the equation being asked for.
SolutionThis 2-step equation is solved in the usual way:
3m = 11.7 . . . . . . . . subtract 17 from both sides
m = 3.9 . . . . . . . . . divide both sides by 3
Carter would have to ride an average of 3.9 miles each day to reach his goal.
__
Additional comment
Your life experience should tell you how things add up. A total is the sum of its parts. Total miles = (miles already done) + (miles to go), for example.
Multiple things that are the same value can be "added" using multiplication: m + m + m = 3m, for example.
Question 1 of 10
Which function results after applying the sequence of transformations to
f(x) = x5?
• shift left 1 unit
• vertically compress by
3
• reflect over the y-axis
Answer: B) \(f\left(x\right)=\frac{1}{3}\left(-x-1\right)^{5}\)
Step-by-step explanation:
When graphing x5 the parent function and plugging in the equation for B the only equation that fits the criteria of
*shifting left 1 unit
*vertically compressed by 1/3
*reflect over the y-axis
So the answer is B
The function after the transformation is f ( x ) = ( 1/3 ) ( -x + 1 )⁵
How does the transformation of a function happen?The transformation of a function may involve any change.
Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs), etc.
If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:
Horizontal shift (also called phase shift):
Left shift by c units: y=f(x+c) (same output, but c units earlier)
Right shift by c units: y=f(x-c)(same output, but c units late)
Vertical shift:
Up by d units: y = f(x) + d
Down by d units: y = f(x) - d
Stretching:
Vertical stretch by a factor k: y = k × f(x)
Horizontal stretch by a factor k: y = f(x/k)
Given data ,
Let the function be represented as f ( x )
Now , the value of f ( x ) is
f ( x ) = x⁵
On reflecting over the y axis , we get
f ( x ) = ( -x )⁵
On vertically compressing by a factor of ( 1/3 ) , we get
f ( x ) = ( 1/3 ) ( -x )⁵
And , shifting 1 unit to the left , we get
f ( x ) = ( 1/3 ) ( -x + 1 )⁵
Hence , the transformed function is f ( x ) = ( 1/3 ) ( -x + 1 )⁵
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A piece of property has the shape of a right triangle. the longer leg is 10m shorter than twice the length of the shorter leg and the hypotenuse is 20m longer than the length of the longer leg. find the length of the sides of the triangle
Answer: 80 m, 150 m, 170 m
Step-by-step explanation:
Find the sum
(4 - n) + 2(-5n + 3)
Answer:
−11n + 10
Step-by-step explanation:
(4-n) + 2 (-5n+3)
4 - n + -10n + 6
-11n+4+6
The answer:-11n+10
Charlotte is saving money for a new phone, and she wants to have at least $545 saved before she goes to buy one. So far, she has saved $225. She plans to save $40 each week going forward. In how many weeks will Charlotte have saved enough to buy a phone?
Answer:
8 weeks. 545-225=320. 320÷40= 8
We can turn this into an equation:
545 is the y, 225 is the constant, and 40x is the amount per week.
So lets plug this in:
545 = 40x + 225
Subtract 225 from both sides
320 = 40x
Divide by 40
8 = x
This means that it will take 8 weeks to save enough money.
I hope this helps! :)
pls help meeh everything is on the image
Answer:
Your slope is -1 and you y is 2 and the equation is -1y+ 0x
Step-by-step explanation:
The density of glycerin is 20 g/cm3 at 20 0c. find the density of glycerin at 60 0c. the volume coefficient of glycerin is 5.1 x 10-4 0c-1.
The density of glycerin at 60°C is approximately 19.9592 g/cm³.
To find the density of glycerin at 60°C, we can use the volume expansion coefficient and the given density at 20°C.
The formula for volume expansion is:
ΔV = β * V₀ * ΔT
where:
ΔV is the change in volume,
β is the volume expansion coefficient,
V₀ is the initial volume, and
ΔT is the change in temperature.
In this case, we want to find the change in density, so we can rewrite the formula as:
Δρ = -β * ρ₀ * ΔT
where:
Δρ is the change in density,
β is the volume expansion coefficient,
ρ₀ is the initial density, and
ΔT is the change in temperature.
Given:
ρ₀ = 20 g/cm³ (density at 20°C)
β = 5.1 x 10⁻⁴ °C⁻¹ (volume expansion coefficient)
ΔT = 60°C - 20°C = 40°C (change in temperature)
Substituting the values into the formula, we have:
Δρ = - (5.1 x 10⁻⁴ °C⁻¹) * (20 g/cm³) * (40°C)
Calculating the expression:
Δρ = - (5.1 x 10⁻⁴) * (20) * (40) g/cm³
≈ - 0.0408 g/cm³
To find the density at 60°C, we add the change in density to the initial density:
ρ = ρ₀ + Δρ
= 20 g/cm³ + (-0.0408 g/cm³)
≈ 19.9592 g/cm³
Therefore, the density of glycerin at 60°C is approximately 19.9592 g/cm³.
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PLEASEEEE SOMEONE HELP I GIVE AS MUCH POINTS :’( Thank you!
The approximate area of the trapezoid is determined as 13.95 unit².
What is the approximate area of the trapezoid?The approximate area of the trapezoid is calculated as follows;
Area = ¹/₂(b₁ + b₂)h
Where;
b₁ and b₂ are the lengths of the parallel sidesh is the heightThe y-coordinates of the points on the curve at x=3/2 and x=4 is calculated as follows;
y(3/2) = - (3/2)²/2 + 3/2 + 5
y(3/2) = -9/8 + 3/2 + 5
y(3/2) = 5.375
y(4) = -4²/2 + 4 + 5
y(4) = -8 + 9
y(4) = 1
h = 5.375 - 1 = 4.375
The approximate area of the trapezoid is calculated as;
Area = ¹/₂(5.375 + 1) x 4.375
Area = 13.95 unit²
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The make African elephant at the city zoo has a mass of 5450 kg. What is its mass in scientific notation
The mass in scientific notation is \(5.45 * 10^3 kg\), this means that the mass of the African elephant is 5.45 multiplied by 1000,
To write the mass of the African elephant in scientific notation, we need to express it as a number between 1 and 10, multiplied by a power of 10. To do this, we can start by moving the decimal point in 5450 kg to the left until we have a number between 1 and 10. This gives us 5.45 kg.
Next, we need to determine the power of 10 that we multiplied by to get this number. To do this, we count the number of places we moved the decimal point, which is three places to the left. Therefore, the mass of the African elephant in scientific notation is:
\(5.45 * 10^3 kg\)
This means that the mass of the African elephant is 5.45 multiplied by 1000, which is the same as 5450 kg in standard notation. Writing the mass in scientific notation makes it easier to work with very large or small numbers, as it simplifies the representation of the number and makes it more manageable.
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40 POINTS
The table shows the distance, y, a greyhound dog can travel (in feet) in x seconds.
Time, x (seconds) Distance, y (feet)
0 0
5 220
10 440
15 660
Based on the information in the table, which equation can be used to represent the relationship between time and the distance a greyhound dog can travel?
The equation that can be used to represent the proportional relationship between time and the distance a greyhound dog can travel is:
y = 44x.
What is a direct proportional relationship?A direct proportional relationship is a function in which the output variable is found with the multiplication of the input variable and the constant of proportionality, as follows:
y = kx.
In which k is the constant of proportionality, also representing the rate between the output and the input for any pair of (input, output) except (0,0).
From the table of distances and time given in this problem, the constant is found as follows:
k = 220/5 = 440/10 = 660/15 = 44.
Hence the constant is of 44 and the relation is given by:
y = 44x.
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-3/8(-4y+z) what is the answer to this? By simplifying.
Answer:
3y/2 - 3z/8 is the answer
Answer:
Step-by-step explanation:
Element X is a radioactive isotope such that every 26 years, its mass decreases by half. Given that the initial mass of a sample of Element X is 680 grams, how much of the element would remain after 19 years, to the nearest whole number?
Answer:
410 g
Step-by-step explanation:
Radioactive decay can be modeled by an exponential equation. The amount remaining (y) after a time period (t) can be expressed in terms of the initial amount (a) and the half-life (h).
y = a(1/2)^(t/h)
__
We can use this equation with the given values to find the amount remaining.
y = (680 g)(1/2)^((19 yrs)/(26 yrs)) ≈ (680 g)(0.602583)
y ≈ 410 g
About 410 grams of element X will remain after 19 years.
HELPPPPPPPP PLEASE HELP ME EEEEEE
Answer: The correct answer is b
Step-by-step explanation:
25% off $30 is 22.50 and then when you add 7%ax it turns out to be 24.08
Simplify the expression 2(3+d-1)=
Answer:
4+2d
Step-by-step explanation:
2(3+d-1)
6+2d-2=6+(-2)+2d
=4+2d
If x²+y²=106 and xy=24, find the value of 2(x+y)²
(×+y)^2 = x^2 + y^2+ 2xy
= 106+ 2×24
=106+48
=154
2×154 = 308
A farmstand sells avocados. The population of avocados is normally distributed with a mean of 6 oz and standard deviation of 1 oz.
the mean of the sampling distribution for the avocados will also be 6 oz.
The mean of the sampling distribution for this population can be determined by the same mean as the population mean. In this case, the mean of the population of avocados is given as 6 oz. The sampling distribution refers to the distribution of sample means taken from the population.
According to the central limit theorem, when sampling from a population, regardless of its underlying distribution, the sampling distribution of the sample means will be approximately normally distributed, centered around the population mean. Thus, the mean of the sampling distribution will be equal to the population mean.
Therefore, in this scenario, the mean of the sampling distribution for the avocados will also be 6 oz. This implies that, on average, the mean weight of the samples drawn from the population will be 6 oz, reflecting the central tendency of the population.
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Complete question is below
A farmstand sells avocados. The population of avocados is normally distributed with a mean of 6 oz and standard deviation of 1 oz. What is the mean of the sampling distribution for this population?
Suppose GRE Analytical Writing scores are normally distributed with a mean of 3.8 and a standard deviation of 0.8. A university plans to admit students whose scores are in the top 40%. What is the minimum score required for admission
The minimum score required for admission to the university is 3.6.
To find the minimum score required for admission to the university, we need to determine the GRE score that corresponds to the 40th percentile of the distribution.
First, we need to find the z-score that corresponds to the 40th percentile. We can use a standard normal distribution table or a calculator to find this value.
Using a standard normal distribution table, we can look up the z-score that corresponds to a cumulative area of 0.40, which is approximately 0.25.
The z-score corresponding to a cumulative area of 0.25 is -0.25.
Next, we can use the formula for transforming a z-score to a raw score:
z = (x - mu) / sigma
where:
z is the z-score (-0.25 in this case)
x is the raw score we want to find
mu is the mean of the distribution (3.8 in this case)
sigma is the standard deviation of the distribution (0.8 in this case)
Solving for x, we get:
\(x = z\times sigma + \mu\)
\(x = (-0.25)\times 0.8 + 3.8\)
x = 3.6.
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Taylor makes $8 an hour at the pizza place and she is scheduled to work six hours this afternoon. However, Brandon called and wanted to know if she could go out to the movies. Assuming the movies will cost Taylor $10, what is her opportunity cost of going out to the movies?
Answer:
58
Step-by-step explanation:
im pretty sure its saying like what she is losing by not going to work and how much she is paying for the movie so 8x6 then add the 10
what is the answer to
3n=n-2
Answer:
- 1
Step-by-step explanation:
Step 1:
3n = n - 2
Step 2:
2n = - 2
Answer:
n = - 1
Hope This Helps :)
3x -y= -1 + -3x + 3y= 27
Answer:
Answer:
y = 13
Explanation:
You want to add the like variables:
(3x - y) = -1
+(-3x +3y) = 27
The x's cancel out:
2y = 26
Divide by 2 on both sides to get the y by itself and solve for y
y = 13
Step-by-step explanation:
a towing vessel 35 meters in length, with a tow 100 meters astern, must show a minimum of how many masthead lights?
The minimum number of masthead lights for the given vessel is 2.
What is the Ratio?The ratio can be defined as the proportion of the fraction of one quantity towards others. e.g.- water in milk.
Here,
A towing vessel 35 meters in length, with a tow 100 meters astern,
Masthead lights = total length of the tow / total length of the vessel
= 100 / 35 = 2.85
So, the Number of Masthead lights for the given vessel is 2 ≤ x ≤ 3.
And a minimum number of masthead lights is 2.
Thus, the minimum number of masthead lights for the given vessel is 2.
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Evaluate the following expression if c = 8 and d = -5
3 * (c+d
Hi,
if c = 8 and d = -5:
3*(c + d) <=> 3*(8 + (-5))
= 3*(8 - 5)
= 3*3
= 9
✅^_^
Variability between groups is due to ______. Group of answer choices the level of the dependent variable the F ratio the grouping factor chance Flag question: Question 4
Variability between groups is due to the grouping factor.
The F ratio is a measure of the variability between groups relative to the variability within groups, but it is not the cause of the variability between groups.
In an experimental design, researchers often manipulate an independent variable to observe its effects on a dependent variable.
The independent variable is often a grouping factor, which means that participants are assigned to different groups based on some characteristic or condition.
Participants may be assigned to a treatment group or a control group, or they may be grouped based on age, gender, or some other factor.
The experiment is conducted, the dependent variable is measured in each group, and the researcher is interested in whether there are significant differences between the groups.
Variability between groups refers to the differences in the mean scores of the dependent variable between the different groups.
The grouping factor is the reason for the variability between groups.
This is because the different groups are defined by the levels of the grouping factor, and the participants within each group are assumed to be similar with respect to the dependent variable.
Any differences between the groups must be due to the effect of the grouping factor.
The F ratio, which is calculated by dividing the variability between groups by the variability within groups, is used to test whether the differences between the groups are statistically significant.
The F ratio is a measure of the extent to which the grouping factor explains the variability in the dependent variable, and a significant F ratio indicates that there are significant differences between the groups.
Variability between groups is due to the grouping factor, and the F ratio is used to test whether the differences between the groups are statistically significant.
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Let a > 0 be real. Consider the complex function f(z) 1 + cos az 02 22 - Identify the order of all the poles of f(z) on the finite complex plane. Evaluate the residue of f(z) at these poles.
Hi! To answer your question, let's analyze the complex function f(z) given by f(z) = 1 + cos(az)/(z^2).
First, we need to identify the poles of the function. A pole occurs when the denominator of the function is zero. In this case, the poles are at z = 0. However, the order of the pole is determined by the number of times the denominator vanishes, which is given by the exponent of z in the denominator. Here, the exponent is 2, so the order of the pole is 2.
Now, let's find the residue of complex function f(z) at the pole z = 0. To do this, we can apply the residue formula for a second-order pole:
Res[f(z), z = 0] = lim (z -> 0) [(z^2 * (1 + cos(az)))/(z^2)]'
where ' denotes the first derivative with respect to z.
First, let's find the derivative:
d(1 + cos(az))/dz = -a * sin(az)
Now, substitute this back into the residue formula:
Res[f(z), z = 0] = lim (z -> 0) [z^2 * (-a * sin(az))]
Since sin(0) = 0, the limit evaluates to 0. Therefore, the residue of f(z) at the pole z = 0 is 0.
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A juice factory begins production at 8:00 a.m. A worker is asked to check the total number of bottles capped before going to lunch. At 12:00 p.m., 1600 bottles of juice had been capped. He checks the number of bottles capped a second time halfway between the beginning of his lunch break and the end of his day. In total, 3600 bottles of juice were capped by the time the factory closed at 5:00 p.m.
• What time did the worker check the second time?
• How many bottles had been capped at that time?
The production start time = 8:00am (8 hours of the day)
Lunch time = 12:00pm ( 12 hours of the day)
Factory closing time = 5:00pm ( 17 hours of the day)
The difference between the lunch time and closing time= 17 - 12
= 5 hours.
He checks the number of bottles capped a second time halfway between the beginning of his lunch break and the end of his day =12 + \(\frac{5}{2}\)
= 12 + 2.5 hours
= 14.5 hours
= 2: 30pm
From production start time to lunch time = 12 - 8
= 4 hours
Therefore, in 4 hours 1600 bottels were capped
1 hour = \(\frac{1600}{4}\)
= 400 bottles
Therefore the number of bottles that would be capped when the worker checked the second time should be = start time to lunch time + halfway between the beginning of his lunch break and the end of his day × 400 bottles.
= (4 + 2.5) × 400
= 1600 + 1000
=2600 bottles
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The diagram shows a circle, centre
O
.
Points
A
,
B
,
C
and
D
lie on the circumference of the circle.
E
D
F
is a tangent to the circle.
Angle
A
B
C
=
82
∘
and angle
O
D
C
=
57
∘
.
The value of x as shown in the circle with center O is 66°
Circle
Circle is the locus of a point such that all points on the plane is equidistant from a fixed point known as the center.
Using the image attached:
Triangle ODC is an isosceles triangle because OC = OD (radius), hence:
∠ODC = ∠OCD = 57° (isosceles triangle)
∠OCD + ∠ODC + ∠DOC = 180° (sum of angles in a triangle)
57 + 57 + x = 180
x = 66°
The value of x as shown in the circle with center O is 66°
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