how many degrees of crankshaft rotation are required for a piston to move from tdc to bdc and return to tdc

Answer:

For Figure Below, if the elevation of the benchmark A is 25.00 m above MSL:

1. Using the Rise and Fall Method, find the reduced level for all points. (Construct the Table)

2. Using HPC Method, find the reduced level for all points. ( Construct the Table).

3. Show all required Arithmetic checks for your work. For Item 1 and 2.

4. What is the difference in height between points H and D?

5. What is the gradient of the line connecting A and J, knowing that horizontal distance = 200

m.

Answer:

D. Fire clay bricks

Explanation:

Just like in the steel mills with the big furnaces that's what causes all the smoke to come out of the stacks

Answer:

d is correct

Explanation:

Answer:

Reflection

Explanation:

The specific behavior of light that will be essential to ensure the success of your design is "Reflection". This is because light maze makes use of a mirror and it's the light that is reflected that we see with our eyes. Also, the manner in which light is reflected off objects will affect the colors that are reflected as well.

Using the Inverse Square Law, the SPL at 150 ft under hard surface condition is 58.57 dB, at 500 ft under soft surface condition is 61.98 dB, and at 1500 ft under soft surface condition is 51.02 dB.

Given:

Distance of the highway (r) = 250 ft

Sound Pressure Level (SPL) at distance r (L1) = 64 dB

Sound Pressure Level follows the Inverse Square Law. According to this law, the SPL decreases by 6 dB when the distance is doubled, and it increases by 6 dB when the distance is halved.

Mathematically, it can be written as,L1/L2 = (r2/r1)² Where,

Substituting the given values and solving, we get the following:

For A) 150 ft under hard surface condition: L2 = L1 - 20 log(r2/r1) dB where

For B) 500 ft under soft surface condition: L2 = L1 - 20 log(r2/r1) dB where

For c) 1500 ft under soft surface condition: L2 = L1 - 20 log(r2/r1) dB where

Hence, the SPL at distances 150 ft under hard surface condition, 500 ft under soft surface condition, and 1500 ft under soft surface condition are 58.57 dB, 61.98 dB, and 51.02 dB, respectively.

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Answer:

The answer would most likely be c

Graphical forecasts for aviation are weather charts that are specifically designed to assist pilots and other aviation professionals in making informed decisions regarding their flights. These forecasts provide a visual representation of current and predicted weather conditions in a specific region, allowing pilots to plan their routes and make adjustments as necessary.

Graphical forecasts are particularly useful because they provide a clear and concise representation of weather patterns that may impact flight operations. By using these charts, pilots can quickly identify areas of potential turbulence, icing, or other weather-related hazards, allowing them to adjust their flight paths or altitude accordingly. Additionally, graphical forecasts are updated frequently, providing pilots with the most up-to-date information available. As a result, pilots can make informed decisions that prioritize safety and ensure a successful flight.

In conclusion, graphical forecasts for aviation are an essential tool that can help pilots navigate complex weather conditions and ensure a safe flight. By providing clear and concise information, these forecasts allow pilots to make informed decisions that prioritize safety and efficiency. As a result, they are an integral part of any flight planning process and should be used by all aviation professionals to ensure a successful flight.

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During gait the body of a living organism is gaining speed: a. during terminal stance.

Physical fitness can be defined as a measure of both the physical and mental soundness (wellness) or ability of an individual to engage in physical exercises, sports, work and other day-to-day activities.

For instance, one of the ways in which an individual can model good physical fitness to other individuals in their neighborhood is by:

Gait can be defined as the way and manner in which an animal or individual walks or runs, thereby affecting and altering the shape of the body.

In this context, we can infer and logically deduce that during gait the body of a living organism is gaining speed, especially during terminal stance.

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Answer:

A) For a double drainage system the time taken for total settlement will differ from that of a single drainage system, because in a double drainage case clay water escapes from both sides unlike in a single drainage case. hence water and air will be be expulsed faster for a double drainage making it attain  total settlement faster.

B) for only single = 12 years

Explanation:

Given data :

ultimate clay settlement = 32 cm

settlement of clay in 3 years = 7.5 cm

Cv ( coefficient of consolidation ) =  1.5 x 10^-4 cm^2 /s

A) For a double drainage system the time taken for total settlement will differ from that of a single drainage system, because in a double drainage case clay water escapes from both sides unlike in a single drainage case. hence water and air will be be expulsed faster for a double drainage making it attain  total settlement faster.

note : Total settlement is the same in both drainage system.

B) Determine how long it will take for 7.5 cm of settlement to occur if there is only single

applying the relation  below

Tv = Cv t / H^2

where Tv = time factor , d = thickness of layer , H = drainage path

Given that Tv and Cv are constant in both cases

t ∝ H^2   hence

\(\frac{t1}{t2} = \frac{H^21}{H^22}\)  ------ ( 1 )

t1 = time for single drainage for d meters , t2 = time for double drainage  for d meters

equation 1 can be rewritten as

t1/t2 = d^2 / (d/2)^2

∴ t1 = 4t2

given that t2 = 3 years ( value gotten from question )

t1 = 4 * 3 = 12 years

The values of h at the two internal boundaries are :

Given data :

Z₁ = Z₂ = Z₃ = 25 m

h top = 120 m

h bottom = 100 m

K₁ = 0.0001 m/s

K₂ = 0.0005 m/s

K₃ = 0.0010 m/s

we will apply the formula below since flow is perpendicular to the bedding plane

Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\)  ----- ( 1 )

Insert values given above into equation 1

Therefore ; Keq = 2.307 * 10⁻⁴ m/s

Hydraulic gradient ( Ieq ) = head loss / length

                                          = ( 120 - 100 ) / 3 * 25

                                   Ieq  = 0.266

Given that the flow is perpendicular to bedding plane

q1 = q2 = q3

V₁ = V₂ = V₃ = V

K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq

Hence :

V = Keq* Ieq

   = 2.307 * 10⁻⁴ * 0.266

   = 6.15 * 10⁻⁵ m/s .

Also;

K₁i₁ =  Keq * ieq = K₂i₂ = K₃i₃

therefore :

  i₁ = 0.615

  i₂ =  0.123

  i₃ = 0.0615

Pressure at point 1 ( i.e. pressure between first two formations )

h₁ = h top - i₁L₁

   = 120 - 0.615 * 25

   = 104.625 m

Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )

h₂ = h₁ - i₂L₂

    = 104.625 - 0.123 * 25

    = 101.55 m

Therefore we can conclude that The values of h at the two internal boundaries are :  h₁ = 104.625 m , h₂ = 101.55 m

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Contrast, Balance, Emphasis, Movement, White Space, Proportion, Hierarchy, Repetition, Rhythm, Pattern, Unity, and Variety are some of the aspects or guiding principles of visual design.

There is much disagreement on the number of design principles that exist (and even their exact nature), although 12 are frequently mentioned. Contrast, balance, emphasis, proportion, hierarchy, repetition, rhythm, pattern, white space, movement, diversity, and unity are among the 12 concepts described in the infographic below (there are also some additional Gestalt principles of design).

These ideas are frequently discussed individually, but in reality, they function together to produce designs that are both aesthetically pleasing and intuitive for the user. Professional designers are aware of how the principles interact to produce the intended impact. They can support, reinforce, or even oppose one another.

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Answer:

Completed load manifest, dispatch release and flight plan

Answer: A sample of the representative outcomes or sequences of events for all possible consequences of a model is called a scenario.

A successful bit-flipping attack requires knowledge of the exact contents of the ciphertext and a stream cipher.

A bit-flipping attack is a type of cryptographic attack where an attacker tries to change certain bits of the ciphertext to change the corresponding bits of the plaintext. To successfully perform this attack, the attacker needs to know the exact contents of the ciphertext, as they need to know which bits to flip.

Additionally, a stream cipher is required as it allows the attacker to modify specific bits of the ciphertext without affecting the rest of the message. A Caesar cipher, on the other hand, is a simple substitution cipher and not suitable for a bit-flipping attack. Therefore, options A and D are not correct. While knowledge of the exact contents of the plaintext would be helpful, it is not necessary for a successful bit-flipping attack. Hence, option C is also not correct.

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The critical value of the angular velocity obtained just before the slipping starts is the answer to this question and it is \(\bold{\omega = \sqrt{\frac{\mu.g}{r}}}\).

                                         \(\begin{aligned}\\\\F &= ma\\\\f_{max} &\geq ma\\\\ \mu_s.mg &\geq m.r\omega^2\\\\\omega &\leq \sqrt{\frac{\mu_sg}{r}}\\\\\omega_{critical} &= \sqrt{\frac{\mu_sg}{r}}\end{aligned}\)

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Answer:

Explanation:

Both a  and B

In these two statements by Technician A and Technician B, C. Both A and B are correct.

OEM means Original Equipment Manufacturer, while TCMC means Toyota Complete Maintenance Care. OEM brake pad kits come with new shims as TCMC brake pad kits.

Traditional part numbers bear 10-digits, but TCMC products bear 12-digit part numbers.

Thus, we can conclude from the statements by Technician A and Technician B that C. Both Technician A and Technician B are correct.

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The solution to the differential equation is

y (k)= (-1/3  ) * 1\(^{k}\) +(1/3) * 2\(^{k}\)  

= (  -1/3) +(2/3) * 2\(^{k}\)

To solve the   given differential equation Y(k+2) - 3y (k+1) +2y(k) = 0 with the initial conditions y(0) = 0 and y(1) = 1, we can use the method of characteristic roots.

Let's assume the solution has the form y(k)=   r\(^{k}\). Substituting this into the differential equation, we get   -

\(r^k+2\) -  + \(2r^k\) = 0

Dividing through by \(r^k\), we have

r² - 3r + 2 = 0

This    is a quadratic equation,which can be factored as

(r - 1  ) (r - 2) =0

So, we have two characteristic roots  

r1 = 1 and r2= 2.

The general solution is given by   -

y(k) = A   * \(r1^k\) +B * \(r2^k\)

Applying the initial conditions, we have -

y(0) = A * 1⁰ + B* 2⁰ =   A + B

= 0 → A = -B

y(1) =A * 1¹ + B * 2¹

=    A + 2B = 1

Solving these equations    simultaneously,we find A = -1/3 and B = 1/3.

Therefore, the solution to the differential equation Y(k+2) - 3y(k+1) + 2y(k) = 0 with the initial conditions y(0) = 0 and y(1) = 1 is  -

y(k )   = (-1/3) * 1\(^{k}\) +(1/3) * 2\(^{k}\)

= (-1/3) +   (2/3) * 2\(^{k}\)

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A PFAS anchorage point for a 6-foot lanyard must be able to hold a minimum static load of 5,000 pounds.

PFAS stands for Personal Fall Arrest System, which is a type of fall protection equipment that is designed to protect workers from falls.
The 5,000-pound minimum static load requirement is based on the assumption that the PFAS will experience a shock load of 2,500 pounds in the event of a fall.

This shock load is due to the force of the fall and the weight of the worker, and it puts a significant amount of stress on the anchorage point. The 5,000-pound minimum static load ensures that the anchorage point can withstand this shock load without failing.
It's important to note that the 5,000-pound minimum static load requirement is a general guideline, and the actual load capacity of the anchorage point will depend on a variety of factors, including the type of anchorage point, the material it's made from, and the conditions of use.

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The logical techniques to repair the logical damage caused to a file system is consistency checking are Zero-knowledge analysis: In this process, scan the drive of the affected computer, noting all file system structures and possible file boundaries. Then match the results to the specifications of a working file system. Then, consistency checking: involves scanning a disk's logical structure and ensuring that it is consistent with its specification. Option a and b is correct.

Zero-knowledge analysis and consistency checking are logical techniques because they involve analyzing the logical structure of the file system to identify and repair logical errors.

In zero-knowledge analysis, the affected drive is scanned, and the file system structures and possible file boundaries are noted. Then, the results are matched to the specifications of a working file system so that any inconsistencies can be identified and repaired.

Consistency checking involves scanning the logical structure of the disk and ensuring that it is consistent with its specification. This technique helps identify any inconsistencies or errors in the file system that may have occurred due to software or other logical issues.

On the other hand, removing hard disk platters and replacing PCBs or read/write head assemblies are physical techniques as they involve physically manipulating the components of the hard drive.

Therefore, a and b is correct.

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The monthly output of a certain product can be given by the function

\(`Q(x) = 2500x^(5/2)`\)

where x is the capital investment in millions of dollars.

differentiate the function Q(x) with respect to x.

\(dQ/dx = d/dx(2500x^(5/2))\)

Using the power rule of differentiation, we have:

\(dQ/dx = (5/2) * 2500 * x^(5/2 - 1)dQ/dx

= 6250x^(3/2) `dQ/dx

= 6250x^(3/2)`\)

which gives us the effect on the output if an additional capital investment of $1 million is made.

Note: To estimate the effect on the output if an additional capital investment of $1 million is made, we substitute x with x+1 in the expression for `dQ/dx`. This gives us the new output and the increase in output due to the additional investment.

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Answer:

Following are the description on the chain surveying:

Explanation:

The checking which is also called a beginning of the test is indeed a line uniting the summit of a triangular with other fixed locations from both sides of a triangle. To verify the overall precision of a framework, the check-line is measured. When assessed mostly on the ground, every length of an examination line should match its height. It also is called a proof line that connects the top of the triangle with any fixed location in the contrary direction. It is utilized for verifying the preciseness of a work.

Answer:

Solid to liquid ratio of thickeners is roughly 12 times the throughput of conventional machines of similar size

Explanation:

Thickening is a process where a slurry or solid-liquid mixture is separated to a dense slurry containing most of the solids and an overflow of essentially clear water

ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

In regards to auto repair information tools, the solution that is known to be made available is the use of ShopKey® Pro with 1Search.

This is know  to be a kind of an exclusive auto repair software that helps to streamlines the search acts to bring closer a special  combination of OEM data as well as experience-based Real Fixes.

Therefore, based on the above, one can say that ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

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Answer:

you know you could use like quora or yahoo answers

When thrust faults occur, the region undergoing stress is subject to compression stress.

Compressive stress is a force that causes a substance to deform in order to take up less space.

When thrust faults occur, the region undergoing stress is subject to compression stress. A substance is said to be under compression when it is subjected to compressive stress.

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The modifications of superheating and reheat for a vapor power plant are specifically better for the operation which of the following components b.Boiler.

There are 5 steam strength cycles: The Carnot cycle, the easy Rankine cycle, the Rankine superheat cycle, the Rankine reheat cycle and the regenerative cycle.

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Answer:

15 000 000 Ohms

Explanation:

1 Mega Ohm = 1 000 000 Ohms

So,

15 Mega ohms =15 000 000 Ohms

Answer:

A cost is something you have to give up or sacrifice and a benefit is something that is gained or is helpful.

Explanation:

In a cost-benefit analysis of a system, an engineer is to simply look at the requirements for the system and determine the costs to build the system, both in financial value and energy value.  Additionally, the engineer needs to determine the benefits that would come from choosing a particular path of cost.  If the benefits outweigh the cost for the project, then the solution is accepted.  Else, the cost outweighs the benefit and the solution is rejected.

Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.

Explanation:

Mass is the matter that makes up objects