In the reaction CH₄ + 2O₂ → CO₂ + 2H₂O, 85.9375 g of CO₂ will be produced from 125 g of O₂ and excess CH₄.
Therefore the answer is 85.9375 g.
The balanced chemical equation for the reaction of methane (CH₄) with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O) is:
CH₄ + 2O₂ → CO₂ + 2H₂O
To determine how many grams of CO₂ will be produced from a given amount of O₂ and CH₄, we can use the concept of stoichiometry. Stoichiometry is the branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction.
In this case, the stoichiometry of the reaction shows that for every one mole of CH₄ that reacts, one mole of CO₂ is produced, and for every two moles of O₂ that react, one mole of CO₂ is produced.
We can use this information to calculate how many grams of CO₂ will be produced from 125g of O₂ and excess CH₄. As CH₄ is in excess, amount of O₂ is the limiting factor.
We know that 1 mole of O₂ is equal to 32g and 1 mole of CO₂ is equal to 44g, so we can find the number of moles of O₂ by dividing 125g by 32g/mole
= (125 g)/ (32 g/mole)
= 3.90625 moles
We know that for every two moles of O₂ that react, one mole of CO₂ is produced. So 3.90625 moles of O₂ will produce
= 3.90625/2
= 1.953125 moles of CO₂
Finally, we can calculate the number of grams of CO₂ produced by multiplying the number of moles of CO₂ by the molar mass of CO2 (44g/mole)
= 1.953125 moles × 44g/mole
= 85.9375g
Therefore, 85.9375g of CO₂ will be produced from 125 g of O₂ and excess CH₄.
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Why must chemical equations be balanced? (Choose all that apply.)
Two substances must make a new substance.
All atoms on both sides of an equation must be the same.
All atoms on both sides of an equation must be in equal amounts.
It is needed in order to add coefficients.
It will satisfy the law of conservation of mass.
Answer:
It will satisfy the law of conservation of mass.
Two substances must make a new substance.
All atoms on both sides of an equation must be the same.
Explanation:
Stay safe, stay healthy and blessed.
Have a blessed day !
Thank you
The length of Mac’s bedroom is 3m 59cm. Dennis’ bedroom is 2m 89cm longer than Mac’s bedroom. How many centimeters long is Dennis’ bedroom?
Answer:
6m 48cm
Explanation:
First we can convert the length of Mac's bedroom to centimeters:
As 1 m is equal to 100 cm,
3m 59cm is equal to 300 cm + 59 cm = 359 cm.As for Dennis' bedroom's information:
2m 89cm = 289 cmNow we can calculate the length of Dennis' bedroom:
359 cm + 289 cm = 648 cmRewriting the answer leaves us with 6m 48cm.
160g of b₂ and 84g of N₂ are placed in a 30.0L tank at a temperature of 298K.
Find, the number of moles of each gas, the partial pressures of each gas.
ANSWER: This container holds 5.0 moles of O2 and 3.0 moles of N2. The pressure of O2 is 4.1 atm, and the pressure of N2 is
2.4 atm.
This container holds
02 is
moles of 02 a
atm, and the pressure of N2 is
moles of N2. The pressure of
atm.
In the given container, there are approximately 7.4 moles of B₂ and 3.0 moles of N₂. The partial pressure of B₂ is approximately 4.10 atm, and the partial pressure of N₂ is approximately 1.67 atm.
To find the number of moles of each gas and the partial pressures, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
First, let's calculate the number of moles of each gas:
For B₂:
Given mass = 160g
Molar mass of B₂ = 2 * atomic mass of Boron = 2 * 10.81 g/mol = 21.62 g/mol
Number of moles of B₂ = mass / molar mass = 160g / 21.62 g/mol ≈ 7.4 mol
For N₂:
Given mass = 84g
Molar mass of N₂ = 2 * atomic mass of Nitrogen = 2 * 14.01 g/mol = 28.02 g/mol
Number of moles of N₂ = mass / molar mass = 84g / 28.02 g/mol ≈ 3.0 mol
Now, let's calculate the partial pressures of each gas:
To find the partial pressure, we can use Dalton's Law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas.
Partial pressure of B₂ = (moles of B₂ / total moles) * total pressure
Partial pressure of B₂ = (7.4 mol / (7.4 mol + 3.0 mol)) * total pressure
Partial pressure of N₂ = (moles of N₂ / total moles) * total pressure
Partial pressure of N₂ = (3.0 mol / (7.4 mol + 3.0 mol)) * total pressure
Now, we can substitute the values and calculate the partial pressures:
Partial pressure of B₂ = (7.4 / 10.4) * total pressure ≈ 0.71 * total pressure
Partial pressure of N₂ = (3.0 / 10.4) * total pressure ≈ 0.29 * total pressure
Given that the pressure of B₂ is 4.1 atm and the pressure of N₂ is 2.4 atm, we can set up the following equations:
0.71 * total pressure = 4.1 atm
0.29 * total pressure = 2.4 atm
Solving these equations, we find:
Total pressure ≈ 5.77 atm
Now we can substitute the total pressure into the partial pressure equations to find the partial pressures:
Partial pressure of B₂ = 0.71 * 5.77 atm ≈ 4.10 atm
Partial pressure of N₂ = 0.29 * 5.77 atm ≈ 1.67 atm
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calculate the concentration of a solution containing 1.8g of sodium carbonate in 862cm3 of water
Answer:
0.02 M
Explanation:
Given data:
Mass of sodium carbonate = 1.8 g
Volume of water = 862 cm³ (862/1000 = 0.862 L)
Concentration = ?
Solution:
Formula:
Concentration = number of moles / volume in L
Number of moles of sodium carbonate:
Number of moles = mass/molar mass
Number of moles = 1.8 g/ 106 g/mol
Number of moles = 0.02 mol
Concentration:
c = 0.02 mol / 0.862 L
c = 0.02 M
What is the percent composition by mass of oxygen in the compound mgso4? the formulas mass of mgso4 is 120 g/mol.
The percent composition by mass of oxygen in magnesium sulfate (MgSO₄) is 53.33%.
The percent composition of mass of oxygen in magnesium sulfate can be calculate as follows
we know that Molar mass of magnesium sulfate = 120 g/mol
Magnesium sulfate has four oxygen atoms, so multiply the molar mass of oxygen by four. So 16 × 4 = 64 g/mol.
To calculate the percent oxygen composition,
% oxygen composition = mass molar oxygen / mass molar
% oxygen composition = 64/120 × 100
% oxygen composition = 53.33 %
Therefore, the percent composition by mass of oxygen in magnesium sulfate (MgSO₄) is 53.33%.
What is percentage of the composition of the solution?The mass fraction of every element found in a compound is referred to as the percentage composition of the solution.
Three techniques can be used to determine the percentage composition of matter:
ratio of mass to percentvolume to volume ratiomass to volume ratioThe first method is good if both ingredients are solid and can be measured in grams.
A second approach can be used when both components are liquids.
A third approach is used when one substance is solid and the other is liquid. Divide the two quantities and multiply by 100 to calculate the composition ratio. By convention, both quantities must have the same units.
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Calculate the mass of HONH2 required to dissolve in enough water to make 250.0 mL of solution having a pH of 10.00
The mass of HONH2 required to dissolve in enough water to make 250.0 mL of solution having a pH of 10.00 is 3.20 x 10^-13 g.
The first step in solving this problem is to recognize that HONH2 can act as a weak base in water. To find the mass of HONH2 required to make a 250.0 mL solution of pH 10.00, we need to use the equation for the ionization of a weak base:
HONH2 + H2O ⇌ H3O+ + ONH2-
The equilibrium constant expression for this reaction is:
Kb = [H3O+][ONH2-] / [HONH2]
We can find Kb from the given pH:
pOH = 14.00 - pH = 4.00
pKb = 14.00 - pOH = 10.00
Kb = 1.00 x 10^-10
We also know that the concentration of ONH2- is equal to the concentration of H3O+ in this solution:
[ONH2-] = [H3O+] = 1.00 x 10^-4 M
Substituting these values into the Kb expression and solving for [HONH2], we get:
[HONH2] = Kb / [ONH2-] = 1.00 x 10^-10 / 1.00 x 10^-4 = 1.00 x 10^-14 M
Now we can use the definition of molarity to find the number of moles of HONH2 required:
Molarity = moles of solute / liters of solution
moles of HONH2 = Molarity x liters of solution = 1.00 x 10^-14 mol
Finally, we can use the molar mass of HONH2 to convert moles to grams:
mass of HONH2 = moles of HONH2 x molar mass of HONH2
molar mass of HONH2 = 32.04 g/mol
mass of HONH2 = 1.00 x 10^-14 mol x 32.04 g/mol = 3.20 x 10^-13 g
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The atomic number of an atom or element is the number of.
Answer: the number of a chemical element in the periodic system,
Explanation:
by volume, orange drink is ten percent each of orange juice and corn syrup. a 1.5-L of the drink costs $0.95. A 1.5-L can of orange juice is $1.49, and 1.5-L of corn syrup is $1.69. per serving, does it cost less to make your own orange drink or buy it?
Answer:
1000000000000
Explanation:
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The orange drink is made from a combination of orange juice and corn syrup. Making an orange drink is cheaper than directly buying it.
What is the percentage ratio?A percent ratio is the quantitative association of the amount present in another amount or substance.
10% price of orange juice is calculated as:
\(\dfrac{10\times 1.49}{100} = 0.149$\)
Similarly, 10% price of corn syrup is calculated as:
\(\dfrac{10\times 1.69}{100} = 0.169$\)
The total price of 10% priceof orange juice and corn syrup is, 0.149 + 0.169 = 0.318 $
Therefore, the cost of making orange juice is less than directly purchasing it from the market.
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Calculate the energy of a photon of radiation with a frequency of
8.24x10¹4 Hz
Calculate the energy of a photon of radiation with a wavelength of
6.44x10-⁹ m
Calculate the wavelength of light that emits 3:3x10-13 Joules of energy
Answer:
E = hc/λ
Explanation:
To calculate the energy of a photon of radiation, we can use the formula:
E = hf = hc/λ
where:
E = energy of the photon (in Joules)
h = Planck's constant (6.626 x 10^-34 Joule-seconds)
f = frequency of the radiation (in Hertz)
c = speed of light (3.0 x 10^8 meters/second)
λ = wavelength of the radiation (in meters)
For a frequency of 8.24 x 10^14 Hz:
E = hf = (6.626 x 10^-34 J*s)(8.24 x 10^14 Hz) = 5.46 x 10^-19 J
For a wavelength of 6.44 x 10^-9 m:
E = hc/λ = (6.626 x 10^-34 J*s)(3.0 x 10^8 m/s)/(6.44 x 10^-9 m) = 3.07 x 10^-19 J
To calculate the wavelength of light that emits 3.3 x 10^-13 Joules of energy:
E = hc/λ
λ = hc/E = (6.626 x 10^-34 J*s)(3.0 x 10^8 m/s)/(3.3 x 10^-13 J) = 6.01 x 10^-7 m = 601 nm
Cubes are three-dimensional square shapes that have equal sides. What is the density of a cube that has a mass of 12. 6 g and a measured side length of 4. 1 cm? (Density: D = ). 1828 g/cm3. 3254 g/cm3 3. 073 g/cm3 68. 92 g/cm3.
To calculate the density of the cube, we can use the formula:
Density (D) = Mass / Volume
Given:
Mass = 12.6 g
Side length = 4.1 cm
Since a cube has equal sides, the volume of the cube is calculated by cubing the side length:
Volume = (Side length)^3
Volume = (4.1 cm)^3
Volume = 68.921 cm^3
Now we can substitute the given values into the density formula:
Density (D) = Mass / Volume
Density (D) = 12.6 g / 68.921 cm^3
Calculating this gives:
Density (D) ≈ 0.1828 g/cm^3
Therefore, the density of the cube is approximately 0.1828 g/cm^3.
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What is your prediction on the effects of drinking 20oz of sports drink vs. 20oz of water? what would happen to urine volume, ph, specific gravity, and nacl level?
Drinking 20oz of sports drink instead of water may have some effects on urine volume, pH, specific gravity, and NaCl level. Sports drinks usually contain electrolytes, such as sodium, potassium, and chloride, that are lost through sweating during exercise. These electrolytes help to replenish the body's fluids and maintain proper hydration levels. However, sports drinks also contain high amounts of sugar and calories that can lead to weight gain and other health problems if consumed excessively.
In terms of urine volume, drinking 20oz of sports drink may lead to increased urine output compared to drinking water. This is because the body may attempt to eliminate excess electrolytes and sugar through urine, resulting in a higher urine volume. Regarding urine pH and specific gravity, sports drinks may also have an impact. The electrolytes in sports drinks can affect the acid-base balance in the body, which may alter urine pH. Additionally, the presence of sugar and other substances in sports drinks may affect urine specific gravity, which is a measure of the concentration of particles in urine.
Lastly, drinking a sports drink may also increase the NaCl level in urine. As mentioned, sports drinks contain high amounts of electrolytes, including sodium chloride (NaCl), which can increase the concentration of salt in urine.
Overall, while sports drinks can provide benefits during and after exercise, they should be consumed in moderation to avoid potential negative effects on hydration levels and overall health.
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what conclusions can you draw about the relationship between the structure of the fabric molecule and the intensity with which the azo dyes color the fabric?
The endoplasmic reticulum and the golgi complex look a lot alike in both
plant and animal cells. Explain the difference in their functions.
Answer:
Explanation:
The Golgi apparatus receives proteins and lipids (fats) from the rough endoplasmic reticulum. It modifies some of them and sorts, concentrates and packs them into sealed droplets called vesicles.
Which of the following statements are true of the maintenance of blood pressure (BP)?
C. If blood pressure decreases, filtration in the kidneys decreases.
D. If more blood returns to the heart, the ventricles contract more forcefully to pump it out, and this raises blood pressure.
What is the maintenance of blood pressure?The maintenance of blood pressure is defined as the high use of sodium in your diet and the low use of potassium in your diet can cause hypertension. It is also important to use those foods which are free from fats. It is also important that we should use fruits, vegetables, and grains in excessive amounts for the maintenance of blood pressure and for a healthy diet.
High blood pressure 190/110 mm Hg can cause the main vital organs of the body like the brain, heart, and kidney too. There are three factors that contribute to blood pressure which are resistance, blood viscosity, and blood vessel diameter.
So we can conclude that blood pressure is the pressure of circulating blood against the walls of the blood vessels.
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Which of the following statements are true of the maintenance
of blood pressure (BP)? (Read carefully and select all of the correct statements.)
A. Norepinephrine stimulates vasoconstriction in skin, viscera, and skeletal muscles, all of which lower BP.
B. Aldosterone stimulates the reabsorption of Na+ ions by the kidneys, which lowers BP.
C. If BP decreases, filtration in the kidneys decreases.
D. If more blood returns to the heart, the ventricles contract more forcefully to pump it out, and this raises BP.
E. If BP decreases, the kidneys secrete the enzyme renin, which stimulates the secretion of epinephrine to prevent a further decrease.
F. The hormone ANP increases the excretion of K+ ions by the kidneys, which helps conserve water and raise BP.
G. The hormone ADH helps the kidneys conserve water and helps prevent a decrease in BP.
H. The elasticity of the large arteries helps decrease diastolic BP.
A drum of hight 1.5m
is filled with water (density 100 kg/m^3). Find
the pressure of water at the bottom of drum.
Answer:
pressure= density × gravity × height
Explanation:
100 × 10 × 1.5= 1500 pa
Which term describes the passing of a wave through a material?
O A. Refraction
O B. Reflection
O C. Transmission
D. Absorption
Answer:
A. Refraction
Explanation:
Refraction is the term that describes the passing of a wave through a material.
Answer:
transmission
Explanation:
use standard enthalpies of formation to calculate δh∘rxn for the following reaction: cao cao3
The value of ΔH°rxn for the given reaction CaO + CO2 → CaCO3 is -178.4 kJ/mol.
The standard enthalpy of formation (ΔH°f) is the heat energy evolved or absorbed when one mole of a compound is formed from its constituent elements in their standard states under standard conditions.
ΔH°rxn = ∑ΔH°f(products) - ∑ΔH°f(reactants)Given reaction:CaO(s) + CO2(g) → CaCO3(s)
The standard enthalpy of formation of CaO (s) is - 635.1 kJ/mol
The standard enthalpy of formation of CO2 (g) is - 393.5 kJ/mol
The standard enthalpy of formation of CaCO3 (s) is -1207.0 kJ/molNow,ΔH°rxn =
∑ΔH°f(products) - ∑ΔH°f(reactants)= ΔH°f (CaCO3) - [ΔH°f (CaO) + ΔH°f (CO2)]
= [-1207.0 kJ/mol] - [-635.1 kJ/mol - 393.5 kJ/mol]= -1207.0 kJ/mol + 1028.6 kJ/mol= -178.4 kJ/molMAIN ANSWER:ΔH°rxn = -178.4 kJ/mol
The standard enthalpy of formation is used to calculate the heat energy that is absorbed or evolved when one mole of a compound is formed from its elements in their standard states under standard conditions. We have been given a chemical reaction, and we are required to calculate the ΔH°rxn. The standard enthalpies of formation of CaO (s), CO2 (g), and CaCO3 (s) were given, and we have to substitute these values in the formula to get the final answer.
By adding the sum of the standard enthalpies of formation of the products to the sum of the standard enthalpies of formation of the reactants, we obtain the ΔH°rxn. In this reaction, the ΔH°rxn is -178.4 kJ/mol.
Therefore, the value of ΔH°rxn for the given reaction CaO + CO2 → CaCO3 is -178.4 kJ/mol.
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Animals and plants that live in the Atacama must have different behaviors and features than plants and animals in less extreme environments.
What evidence from the passage supports this conclusion?
The evidence from the passage supports this conclusion are:
(1) A "Some of the cacti that manage to grow in the Atacama get water not from rainfall or groundwater... but from the fog that comes in off the Pacific Ocean!"
How do plants and animals survive in the Atacama Desert?Some desert regions are so dry and devoid of precipitation that neither plants nor animals can live. However, fog from the coast provides adequate moisture on some little hills or formations known as lomas for seasonal vegetation and a few animal species.
There are little, torn plants with deep roots throughout the environment. Long roots enable them to absorb moisture from the Earth's subsurface layers. Aqueous tissue is found in fleshy leaves, which aids in moisture retention. Cacti are not widespread in Atacama, in contrast to other arid areas.
Therefore, these work show that vegetation in the Atacama Desert is able to withstand extreme temperatures, both above and below ground, intense solar radiation during the day, and chilling to freezing temperatures during the night, especially at higher altitudes and as such cacti survive because of fog.
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See full question below
Animals and plants that live in the Atacama must have different behaviors and features than plants and animals in less extreme environments. What evidence from the passage supports this conclusion? (1) A "Some of the cacti that manage to grow in the Atacama get water not from rainfall or groundwater... but from the fog that comes in off the Pacific Ocean!" B "The soil in parts of the Atacama Desert has even been compared to the land on the planet Mars. Many movies and TV shows set in outer space have been filmed there." (1) С "Some scientists are even experimenting with growing crops in the Atacama... to see if it would be possible to grow them on Mars!" (J) D) "In July 2011, an arctic front came through the Atacama and brought snow to the desert!" (1)
use the following data to estimate δh⁰f for potassium bromide. k(s) + 1/2 br2(g) → kbr(s)
The estimated standard enthalpy of formation of potassium bromide (KBr) is -393.8 kJ/mol.
How to estimate the standard enthalpy?
To estimate the standard enthalpy of formation (ΔHf°) of potassium bromide (KBr), we need to use the following thermochemical equation:
K(s) + 1/2 Br₂(g) → KBr(s)
We can use the standard enthalpies of formation of the reactants and products to calculate the ΔHf° of KBr:
ΔHf°(KBr) = ΣnΔHf°(products) - ΣnΔHf°(reactants)
Where n is the stoichiometric coefficient of each substance in the balanced equation.
From tables of standard enthalpies of formation, we can find:
ΔHf°(K) = 0 kJ/mol (because K is in its standard state)
ΔHf°(Br₂) = 0 kJ/mol (because Br₂ is in its standard state)
ΔHf°(KBr) = -393.8 kJ/mol
Substituting these values into the above equation, we get:
ΔHf°(KBr) = [1 × ΔHf°(KBr)] - [1 × ΔHf°(K) + 1/2 × ΔHf°(Br₂)]
ΔHf°(KBr) = [-393.8 kJ/mol] - [0 kJ/mol + 0 kJ/mol]
ΔHf°(KBr) = -393.8 kJ/mol
Therefore, the estimated standard enthalpy of formation of potassium bromide (KBr) is -393.8 kJ/mol.
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Which of the following can result in deviations from Beer\'s law when the path length is constant? Solute concentrations less than 0.01 M Stray light reaching the detector The absorbing species undergoes dissociation or association The sample is homogeneous The use of polychromatic radiation
The option that can lead to deviations from Beer's law at constant path length is option A.
Using monochromatic radiation All radiation that was not absorbed by his sample when stray light reaches the detector is transmitted to the detector.
All of the above factors can lead to deviations from Beer's Law if the path length is constant. Optical pathlength refers to the distance that light travels through a sample and is usually kept constant in spectrophotometric experiments in order to accurately measure the sample's absorbance.
Therefore, unless monochromatic radiation is used, the absorbance of the sample may not accurately reflect the concentration of the solute, as different wavelengths of light may be absorbed differently.
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TRUE/FALSEBubbling intensity indicates that the catalase is reacting with the substrate
TRUE. When catalase reacts with its substrate hydrogen peroxide, one of the products of the reaction is oxygen gas, which can be seen as bubbles.
The rate of bubbling can be an indicator of the intensity of the reaction between catalase and hydrogen peroxide. As more oxygen gas is produced, the bubbling will become more intense, indicating that the reaction between the enzyme and substrate is proceeding. Therefore, it is true that bubbling intensity indicates that the catalase is reacting with the substrate.
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Define matter and provide some examples of different states of matter
The three states of matter are solid - example is stone, liquid - example is water and gas - example is air.
What is matter?A matter is referred to as a substance which has a certain mass and takes up a certain volume in space.
For example pen, pencil, toothbrush, water, milk are matters as well as car, bus, bicycle is also a matter. So matter is considered as a living thing and a non-living thing.
There are three states of matter and they include;
solid - example is stoneliquid - example is watergas - example is airThey have different properties, which can be explained by looking at the arrangement of their particles. This is the theoretical temperature at which particles have the least amount of energy and the slowest movement.
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Hand lotion consists of
_______ of substances that are soluble in ________. Lotions are designed to improve the _______- of the skin.
Main Answer: Hand lotion consists of a mixture of substances that are soluble in water or oil. Lotions are designed to improve the moisture content of the skin.
Supporting Answer: Hand lotions are typically made up of a combination of water-soluble and oil-soluble substances, which work together to hydrate and protect the skin. The water-soluble components of lotions are typically humectants, such as glycerin or urea, which help to draw moisture into the skin and prevent it from evaporating. The oil-soluble components of lotions, such as mineral oil or shea butter, help to form a barrier on the surface of the skin that locks in moisture and protects against dryness and irritation.
The primary purpose of hand lotion is to improve the moisture content of the skin, which can become dry and irritated due to exposure to harsh environmental conditions, such as cold temperatures, low humidity, or frequent hand washing. By restoring moisture to the skin, lotions can help to prevent cracking, flaking, and itching, and improve the overall health and appearance of the skin.
Therefore, the correct answers are "a mixture of substances that are soluble in water or oil" and "moisture content" for the two blanks in the question.
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what is CLF full form
Answer:
compact fluorescent light
Determine the mass of sodium acetate necessary to produce 100 ml of an acetate buffer
Explanation:
Ethanoic acid is a weak acid and dissociates:
C
H
3
C
O
O
H
⇌
C
H
3
C
O
O
−
+
H
+
For which
K
a
=
[
C
H
3
C
O
O
−
]
[
H
+
]
[
C
H
3
C
O
O
H
]
=
1.8
×
10
−
5
Please remember that these are equilibrium concentrations .
p
K
a
=
−
log
K
a
=
−
log
[
1.8
×
10
−
5
]
=
4.74
n
=
c
×
v
∴
n
C
H
3
C
O
O
H
=
0.20
×
200.0
1000
=
0.04
Calculate the speed of a train that traveled 400 miles in 5 hours.
Answer:
80 miles/hour
Explanation:
Distance = 400 miles
Time = 5 hours
Speed = ?
\(Speed = \frac{400}{5} \\\\Speed= 80\)
Speed= 80mi/hr
The speed of the train which travels 400 miles in 5 hours is 80 miles per hour. Speed of the train is distance covered by the train per unit time taken.
What is Speed?Speed of an object can be defined as the rate of change in the position or the distance of an object in any of the directions. Speed can be measured as the ratio of distance to the time taken in which the distance was covered by the train. Speed is a scalar quantity as it has only magnitude and no direction.
Speed = Distance covered by the object/ Time taken
Speed = 400 miles/ 5 hours
Speed = 80 miles/ hour
The speed of train is 80 miles per hour.
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to make up 1 l of a 0.5 m solution of edta starting with the free acid, approximately how much 10 m naoh will have to be added to adjust the ph to 7.0? do you expect this solution to have a ph-buffering capacity? the pkas of the four acetic acid groups on edta are 2.0, 2.67, 6.16 and 10.26.
To make up 1 L of a 0.5 M solution of EDTA starting with the free acid, the pH must be adjusted to 7.0. EDTA is a weak acid with a pKa of 2.0, 2.67, 6.16, and 10.26 for the four acetic acid groups.
At a pH of 7.0, EDTA will exist in a buffered state, meaning that it will be partially protonated and partially deprotonated.
To adjust the pH of the EDTA solution to 7.0, an alkali solution such as 10 M NaOH must be added. The amount of NaOH required can be calculated using the Henderson-Hasselbalch equation:
pH = pK a + log([base]/[acid])
where [base] is the concentration of the deprotonated form of EDTA and [acid] is the concentration of the protonated form of EDTA.
At a pH of 7.0, the acid-base equilibrium of EDTA will be:
[EDTA-] = [HEDTA]
At this pH, the buffer capacity is high. Since the pKa of EDTA is close to the desired pH, the buffer will resist changes in pH caused by added acids or bases.
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what is the daughter nucleus (nuclide) produced when cu64 undergoes beta decay by emitting an electron? replace each question mark with the appropriate integer or symbol.
The daughter nucleus produced when Cu64 undergoes beta decay by emitting an electron in Zn64.
When Cu64 undergoes beta decay by emitting an electron, it becomes Zn64. The atomic number of Copper is 29 and its mass number is 64, which means it has 35 neutrons. During beta decay, one of the neutrons is converted into a proton and the nucleus emits an electron and an anti-neutrino. This results in an increase in the atomic number by one, making it 30, and a negligible change in mass number, which becomes 64. Therefore, the daughter nucleus produced is Zn64.
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Plz help
I don't know chem that well
Ranjana has two unknown solutions X and Y