How many solutions?

This is a graph of a system of linear equations. Determine how many solutions there are for this system of equations.

Answer:

A

Step-by-step explanation:

Answer: 5400

Step-by-step explanation: image attached

Answer:

5400

Step-by-step explanation:

we need to calculate the area of big box (prism).

volume = 4 1/2 X 5 X 3 3/4

= 84.375 in³.

volume of small cube = 1/4 X 1/4 X 1/4

= 0.015625 in³.

now we need to find how many of the small ones go into the big one.

84.375/0.015625

= 5400.

Answer:

hey _ second answer is right _ ok

I CANNOT SEE THAT MY GUY

Answer:

...

Step-by-step explanation:

I can't really see well there

Answer:

x=2  y=11

Step-by-step explanation:

Answer:

The equation represents: A relation and a function

Step-by-step explanation:

A function is said to be a relation; however, the relation does not have to function. For a relation to result in a function, then every input gives an important output. Thus; the given information x² + y - 15 = 0 can be re-written as:

y = - x² + 15

Similarly, the equation typically illustrates a relation as well. Consequently, suppose we replace any x-value for x, then the one possible output will be for y. Hence, that is also a function.

Answer:

x = 128

Step-by-step explanation:

The angles are across form each other, meaning that they are the same angle. I hope this explains it enough, if not I can add more.

Answer:224

Step-by-step explanation:

Okay as you can see, the figure is divided into 3 shapes. 2 rectangles and a right trapezoid.

You can solve the area of the rectangle on the far right by doing 9x6 leaving you with 54.

For the other rectangles you can do 11x12 equaling 132. I got 11 because you know the top is 17 and as you see at the bottom that length you used for the first rectangle is 6, so you do 17-6. You get 12 from adding 9+3.  

For the right trapezoid the formula is A = ( a + b ) x h/2. So you can plug it in and say A=(12+7) x 4/2= 38.

You then add all the areas together (54+132+38= 224) leaving you with the answer of 224.

Answer:

\(-\frac{7}{20}k-3\) (or negative seven over twenty times k plus negative 3)

Step-by-step explanation:

Step 1:  Write out into numeral form

\(-\frac{3}{5}k-9+6+\frac{1}{4} k\)

Step 2: Factor out the common term

\(k(-\frac{3}{5} + \frac{1}{4})-9+6\)

Step 3: Find a common denominator

\(k(-\frac{12}{20}+\frac{5}{20} )-9+6\)

Step 4: Add and Distribute

\(-\frac{7}{20}k-9+6\)

Step 5: Simplify

\(-\frac{7}{20}k-3\)

Hope this helped!

Answer: 4, 4, 4

Step-by-step explanation:

Answer:

top one (3, 2) middle is (5, -15) and bottom is (-3, 6)

Answer: The statement "The probability of landing on blue is greater than the probability of landing on purple." is true.

Answer:

I think "The probability of landing on blue is greater than the probability of landing on purple."

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Explanation:

Answer:

Explanation:

Answer:

Explanation:

Answer:

Explanation:

Answer: YOUR MOM

Step-by-step explanation:

Answer:

Step-by-step explanation:

The set {1,2,3,4,5,6} has a total of 6! permutations

a. Of those 6! permutations, 5!=120 begin with 1. So first 120 numbers would contain 1 as the unit digit.

b. The next 120, including the 124th, would begin with  '2'  

 c. Then of the 5! numbers beginning with 2, there are 4!=24 including the 124th number, which have the second digit =1

d. Of these 4! permutations beginning with 21, there are 3!=6 including the 124th permutation which have third digit 3

e. Among these 3! permutations beginning with 213, there are 2 numbers with the fourth digit =4 (121th & 122th), 2 with fourth digit 5 (numbers 123 & 124) and 2 with fourth digit 6 (numbers 125 and 126).

Lastly, of the 2! permutations beginning with 2135, there is one with 5th digit 4 (number 123) and one with 5 digit 6 (number 124).

∴   The 124th number is 213564

Similarly reversing the above procedure we can determine the position of 321546 to be 267th on the list.

Part A: To calculate the measures of center, we can find the median and the mean for each school.

For Bay Side School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 25, so the median class size is 25.

To find the mean class size for Bay Side School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 12 + 12 + 12 + 14 + 15 + 15 + 16 + 16 + 18 + 18 + 20 + 20 + 23 + 25 + 25 = 243. There are 15 classes, so the mean class size is 243/15 ≈ 16.2.

For Seaside School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 15, so the median class size is 15.

To find the mean class size for Seaside School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 10 + 10 + 10 + 11 + 12 + 15 + 15 + 16 + 17 + 17Part A (continued):

18 + 18 + 20 + 20 + 25 = 222. There are 14 classes, so the mean class size is 222/14 ≈ 15.9.

Therefore, the measures of center for Bay Side School are: median = 25, mean ≈ 16.2.

The measures of center for Seaside School are: median = 15, mean ≈ 15.9.

Part B: To calculate the measures of variability, we can find the range and the interquartile range (IQR) for each school.

For Bay Side School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 12, so the range is 25 - 12 = 13.

To find the IQR for Bay Side School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 15 and Q3 is 20. Therefore, the IQR is 20 - 15 = 5.

For Seaside School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 10, so the range is 25 - 10 = 15.

To find the IQRPart B (continued): for Seaside School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 12 and Q3 is 18. Therefore, the IQR is 18 - 12 = 6.

Therefore, the measures of variability for Bay Side School are: range = 13, IQR = 5.

The measures of variability for Seaside School are: range = 15, IQR = 6.

Part C: If you are interested in a smaller class size, Seaside School is a better choice because its measures of center are lower than those of Bay Side School, indicating that its class sizes tend to be smaller on average. Additionally, Seaside School has a smaller range and IQR, indicating less variability in class size. Therefore, there is less chance of encountering very large classes at Seaside School compared to Bay Side School.

Answer: 49.2 yd 2

Step-by-step explanation:

You must know the formula for surface area. The surface area would be A=2(wl+hl+hw), Plug in the numbers, and then solve. You will get 49.2.

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length of the rectangle

w is the width

From the question

length of a rectangular picture is 5 inches more than three times the width is written as

l = 5 + 3w

Now substitute this into the above equation

Perimeter = 74 inches

74 = 2(5 + 3w) + 2w

74 = 10 + 6w + 2w

8w = 74 - 10

8w = 64

Divide both sides by 8

w = 8 inches

Substitute w = 8 into l = 5 + 3w

That's

l = 5 + 3(8)

l = 5 + 24

l = 29 inches

Hope this helps you

To estimate the volume using the Midpoint Rule with \(\displaystyle n=5\), we need to divide the interval \(\displaystyle 0\leq x\leq 1\) into \(\displaystyle n\) subintervals of equal width. Since \(\displaystyle n=5\), each subinterval will have a width of \(\displaystyle \Delta x=\frac{1-0}{5}=\frac{1}{5}\).

Now, let's calculate the volume using the Midpoint Rule. The formula for the volume obtained by rotating about the y-axis is:

\(\displaystyle V\approx 2\pi \sum _{i=1}^{n}y_{i}\Delta x\)

where \(\displaystyle y_{i}\) represents the value of the function \(\displaystyle y=\sqrt{1+x^{3}}\) evaluated at the midpoint of each subinterval.

First, let's find the midpoints of the subintervals. Since the width of each subinterval is \(\displaystyle \Delta x=\frac{1}{5}\), the midpoint of the \(\displaystyle i\)-th subinterval is given by:

\(\displaystyle x_{i}=\frac{\Delta x}{2}+\left( i-\frac{1}{2}\right) \Delta x=\frac{1}{10}+\left( i-\frac{1}{2}\right) \frac{1}{5}\)

Substituting \(\displaystyle x_{i}\) into the function \(\displaystyle y=\sqrt{1+x^{3}}\), we obtain:

\(\displaystyle y_{i}=\sqrt{1+\left( \frac{1}{10}+\left( i-\frac{1}{2}\right) \frac{1}{5}\right) ^{3}}\)

Now, we can calculate the approximate volume using the Midpoint Rule:

\(\displaystyle V\approx 2\pi \sum _{i=1}^{5}y_{i}\Delta x\)

Substituting the values of \(\displaystyle y_{i}\) and \(\displaystyle \Delta x\) into the formula, we can evaluate the sum and compute the estimated volume.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:the sale of a product increases at first then decreases.

Step-by-step explanation:

Answer:

All of them but not the 3rd and last one !

( Can yall go help me with my question!!!! )

Answer:

C, 235.5 cm^2

Step-by-step explanation:

Formula for area of circle:

A = πr^2

Where π represents pi(3.14 or 22/7) and r represents the radius.

Plug in given value (10):

A = πr^2

A = 3.14(10)^2

A = 3.14(100)

A = 314

Now they say a quarter of this circle is cut out, which means we have to first find out what a quarter of this area is:

314/4

= 78.5

A quarter of this circle is 78.5, so let's subtract this from the total area (314):

314 - 78.5

= 235.5 cm^2

The area is 235.5 centimeters squared.

Here are the pairs matched with their products:

- (-5)(4.2) matches with -21

- (-7)(-3) matches with 21

- (2.5)(-9) matches with -22.5

Pairs (4) and (5) do not have corresponding products in the given options.

Answer:

6 Faces

12 Edges

8 vertices

Step-by-step explanation:

The faces are all the flat surfaces

The Edges are the thick black lines

The Vertices are the extreme points where edges meet

Answer: hope this helps ♡

Answer:

Step-by-step explanation:Yikes. Just so we’re all clear—this is not a real SAT question.

So far, Adam’s record is 6 wins/30 games. If he plays x more games, his record will be:

image

You find the minimum x such that the fraction is greater than ½, which would mean he won more than ½ of his games.

Let’s do some math!

image

So if he plays 54 more games, and wins 2/3 of them, he’ll have the same number of wins as losses. Check on that to make sure: He’ll have played 30 + 54 = 84 games, and won 6 + (2/3)54 = 42 of them. Yep, that works.

Now here is where it gets tricky (and why this question is not SAT-caliber). Remember that he’s losing 1/3 of his games. If his 52nd, 53rd, and 54th additional games were win, win, loss, then he would have had, very briefly, a winning record after his 53rd additional game.

His 55th additional game is another chance at a winning record. If he loses that game, then he’ll win the next two, and have a winning record for sure by the 57th additional game. From there, if he continues winning 2/3 of his games, he’ll have a winning record forever.

Answer:

b

Step-by-step explanation:

how it works with life

Answer:

25.685 square feet.

Step-by-step explanation:

Circumference = 2 * π * radius

From this, we can derive the formula for the radius:

radius = Circumference / (2 * π)

Let's substitute the value of the circumference and calculate the approximate radius:

radius = 18 / (2 * π)

radius ≈ 18 / (2 * 3.14159)

radius ≈ 2.865 feet

Now that we have the approximate radius, we can calculate the area:

Area ≈ π * radius²

Area ≈ 3.14159 * (2.865)²

Area ≈ 3.14159 * 8.193225

Area ≈ 25.685 square feet

Therefore, the approximate area inside the circular park is approximately 25.685 square feet.

In a box plot, also known as a box-and-whisker plot, the data is dispersed and represented visually to provide a summary of the distribution and key characteristics of the dataset. Let's describe how the data is dispersed in the box plot for the given data set: 25, 36, 21, 30, 20, 32, 38, 19, 36, 31, 26, 33, 27, 18, 24.

By observing the box plot, we can see that the data is moderately dispersed, with the majority of values concentrated around the median. The range of the data is approximately 20 to 38, with some variability within the dataset.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:4/25

Step-by-step explanation: add the frequency together making it 50 then put the frequency u want (8) and divide by the total (50) making it 16 covert it into fraction it 4/25. ( i hope I got it right but tell me if I'm wrong ill try again)