How to find heat capacity of calorimeter with hot and cold water?

Answer:

D, the weight

Explanation:

Normal force is mass times gravity

gravity help determines weight

Also a,b and c are all vectors and D is a scaler

Answer:

the ancer is c I know it because I had the same test or it might have been different but it looks familiar to me

Answer:12

Explanation:Average speed=Total Distance divided by Total Time.

Answer: m/s north

explanation

Transmittance varies exponentially with absorptivity, path length, and concentration (see appendix b). Transmittance is the degree to which a substance allows light or other electromagnetic radiation to pass through it.

In other words, Transmittance is a measure of how transparent a substance is to a particular kind of radiation. It's expressed as a percentage or decimal fraction. The absorptivity is the ability of a material to absorb a particular type of electromagnetic radiation or light. It is defined as the ratio of the radiant energy absorbed by the material to the total energy incident on the material. The path length is the distance through which the electromagnetic radiation passes through a substance or medium. Concentration refers to the amount of a particular substance in a given volume or mass of a mixture or solution.To summarize, transmittance varies exponentially with absorptivity, path length, and concentration.

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Answer:

x=48.12 m

Vf=23.544 m/s

Explanation:

a=g

t=2.4

Vf=?

Vø=0

Vf=Vø+at

Vf=0+(9.81)(2.4)=23.544

x=Xø+Vøt+1/2at^2

x=1/2at^2

x=(1/2)(9.81)^2=48.11805

To find the volume of a three-dimensional symmetrical shape using integration, we can use the method of cylindrical shells. This method involves dividing the shape into thin cylindrical shells and then integrating their volumes.

Let's say we have designed a symmetrical solid in the shape of a sphere with a cylindrical cavity running through its center. We will place the flat side (R) of the sphere against the x-y plane. The sphere will be revolving around the z-axis since it is symmetrical about that axis.

To find the volume, we first need to determine the equations for the sphere and the cavity.

The equation for a sphere centered at the origin with radius R is:

x^2 + y^2 + z^2 = R^2

The equation for the cylindrical cavity with radius r and height h is:

x^2 + y^2 = r^2,  -h/2 ≤ z ≤ h/2

The volume of the solid can be found by subtracting the volume of the cavity from the volume of the sphere. Using the method of cylindrical shells, the volume of each shell can be calculated as follows:

dV = 2πrh * dr

where r is the distance from the axis of rotation (the z-axis), and h is the height of the shell.

Integrating this expression over the appropriate range of r gives the total volume:

V = ∫[r1, r2] 2πrh * dr

where r1 and r2 are the radii of the cavity and the sphere, respectively.

Substituting the expressions for r and h, we get:

V = ∫[-h/2, h/2] 2π(R^2 - z^2) dz - ∫[-h/2, h/2] 2π(r^2 - z^2) dz

Simplifying and evaluating the integrals, we get:

V = π(R^2h - (1/3)h^3) - π(r^2h - (1/3)h^3)

V =  πh( R^2 - r^2 ) - (1/3)πh^3

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Answer:

79%

Explanation:

Energy expelled / Energy absorbed = 415/525 = 0.79 = 79%

In one cycle, an engine burning a mixture of air and methanol absorbs 525 J and expels 415 J , then the efficiency of engine would be 20.95 %

The efficiency of an Indian can be defined as the ratio of the total useful work done by the engine to the total heat absorbed by the engine
It can be represented in the form of percentage or in terms of fraction as well.

In general the efficiency of an engine represented by the greek symbol η.

The mathematical expression for the efficiency of an Indian can be presented as follows

Efficiency = useful work done /total heat absorbed

Total useful work = total heat absorbed - total heat rejected

For the given problem,An engine burning a mixture of air and methanol absorbs 525 Jules and expel 415 Jules

The total useful work done by the engine = 525 J - 415 J
                                                                       =110 J

η = 110 / 525

  =0.2095

For getting the percentage we have to multiply the fraction with 100.

Thus ,efficiency of the engine comes out to be 20.95%.

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Answer:-00=;op

Explanation:poop

Answer:

450 hz X 4 = 1800

Explanation: Speed =

Wavelength (4) X frequency (450)

Im not 100% sure though

Answer:

Climbing stairs and lifting objects is work in both the scientific and everyday sense—it is work done against the gravitational force. When there is work, there is a transformation of energy. The work done against the gravitational force goes into an important form of stored energy that we will explore in this section.



Figure 1. (a) The work done to lift the weight is stored in the mass-Earth system as gravitational potential energy. (b) As the weight moves downward, this gravitational potential energy is transferred to the cuckoo clock.

Let us calculate the work done in lifting an object of mass m through a height h, such as in Figure 1. If the object is lifted straight up at constant speed, then the force needed to lift it is equal to its weight mg. The work done on the mass is then W = Fd = mgh. We define this to be the gravitational potential energy (PEg) put into (or gained by) the object-Earth system. This energy is associated with the state of separation between two objects that attract each other by the gravitational force. For convenience, we refer to this as the PEg gained by the object, recognizing that this is energy stored in the gravitational field of Earth. Why do we use the word “system”? Potential energy is a property of a system rather than of a single object—due to its physical position. An object’s gravitational potential is due to its position relative to the surroundings within the Earth-object system. The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0. We usually choose this point to be Earth’s surface, but this point is arbitrary; what is important is the difference in gravitational potential energy, because this difference is what relates to the work done. The difference in gravitational potential energy of an object (in the Earth-object system) between two rungs of a ladder will be the same for the first two rungs as for the last two rungs.

Converting Between Potential Energy and Kinetic Energy

Gravitational potential energy may be converted to other forms of energy, such as kinetic energy. If we release the mass, gravitational force will do an amount of work equal to mgh on it, thereby increasing its kinetic energy by that same amount (by the work-energy theorem). We will find it more useful to consider just the conversion of PEg to KE without explicitly considering the intermediate step of work. (See Example 2.) This shortcut makes it is easier to solve problems using energy (if possible) rather than explicitly using forces.

More precisely, we define the change in gravitational potential energy ΔPEg to be ΔPEg = mgh, where, for simplicity, we denote the change in height by h rather than the usual Δh. Note that h is positive when the final height is greater than the initial height, and vice versa. For example, if a 0.500-kg mass hung from a cuckoo clock is raised 1.00 m, then its change in gravitational potential energy is

mgh=(0.500 kg)(9.80 m/s2)(1.00 m) =4.90 kg⋅m2/s2=4.90 Jmgh=(0.500 kg)(9.80 m/s2)(1.00 m) =4.90 kg⋅m2/s2=4.90 J

Note that the units of gravitational potential energy turn out to be joules, the same as for work and other forms of energy. As the clock runs, the mass is lowered. We can think of the mass as gradually giving up its 4.90 J of gravitational potential energy, without directly considering the force of gravity that does the

The force of gravity, between the earth and a 70 kg human standing on the surface is 688N.

The force that pulls items toward the center of a planet or even other body is known as gravity. Each of the planet are kept in orbit about the sun by gravity. But in a wider sense, gravity is a force because it represents the interaction that happens when two masses are in close proximity to one another. Fundamentally, the stretching of space and the movement of items through the stretched spacetime are what produce gravitational effects. However, the outcome appears to be the result of applying force.

the force of gravity ⇒ Fg = G Mm/ R²

Fg=gravitational force

G=gravitational constant

M=mass of Earth

m=mass of object

R=distance from earth's centre to object's centre

Fg = (6.67 × \(10^{-11}\)× 5.98\(10^{24}\)×70)/ (6.37×\(10^{6}\))×(6.37×\(10^{6}\))

⇒ Fg ≅ 688N.

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Answer:

a solution

Explanation: A solution is a homogeneous mixture consisting of a solute dissolved into a solvent .

Answer:

Proxima Centauri

Explanation:

U 2 can help me by marking as brainliest........

The question does not have enough information to find out the power gain.

The value of the power gain in dB for the circuit can be found using the formula:

Power Gain (dB) = 10 log (Output Power/Input Power)

Here, the output power is given as 20 W and the input voltage is given as 2 V. Since power is directly proportional to the square of the voltage, we can calculate the input power using the formula:

Input Power = (Input Voltage)^2/R, where R is the input resistance of the amplifier.

Without information about the input resistance, we cannot calculate the exact value of the power gain in dB. Therefore, the answer is "not enough information given".

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Answer: H2CO3

Explanation:

1. An example of a flow driven by a horizontal pressure gradient that isn't caused by buoyancy differences is the wind.

2. An example of a large-scale flow in the ocean that is density-driven is the thermohaline circulation, also known as the global conveyor belt.

3. Density-driven or baroclinic flows refer to smaller-scale flows that arise from density differences within a fluid.

1. An example of a flow driven by a horizontal pressure gradient that isn't caused by buoyancy differences is the wind. Wind is the movement of air driven by differences in atmospheric pressure. The horizontal pressure gradient force acts to balance pressure differences, causing air to flow from areas of higher pressure to areas of lower pressure. This movement is not directly related to buoyancy differences but rather the pressure variations in the atmosphere.

2. An example of a large-scale flow in the ocean that is density-driven is the thermohaline circulation, also known as the global conveyor belt. This circulation is driven by differences in water density due to temperature and salinity variations. Cold, dense water sinks in certain regions (such as the North Atlantic), initiating a slow, deep current that transports water masses across vast distances and depths. This circulation plays a crucial role in global heat distribution and nutrient transport.

3. The difference between the density-driven flow in the ocean (such as thermohaline circulation) and a density-driven or baroclinic flow lies in their scales and driving mechanisms. Density-driven flows like thermohaline circulation operate on large scales and are driven by differences in water density due to temperature and salinity variations. These flows involve slow, deep currents that transport water masses over long distances and depths.

On the other hand, density-driven or baroclinic flows refer to smaller-scale flows that arise from density differences within a fluid. These flows typically occur in regions where there are gradients in density, temperature, or salinity. They often involve vertical motions and can be found in various oceanic and atmospheric phenomena, such as coastal upwelling, frontal systems, and eddies. Unlike the large-scale thermohaline circulation, these flows are more localized and occur in specific regions where density gradients exist.

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If the Earth's sideways velocity becomes zero the Earth would still continue to orbit as before.

Sideways velocity of the earth is the rotational speed of the earth in terms of linear velocity. That is 1100 miles an hour approximately. If the sideways velocity of the earth becomes zero, objects on the earth will start flying eastward. This is due to the momentum possesses by the object on the surface of the earth. Flying of the rocks and oceans would cause the earthquakes and tsunamis. But there will not be any effect on the orbital velocity of the earth as it is governed by the gravitational force between the earth and the sun. Which ultimately depends on the masses of the sun and the earth and the distance between them.

So the correct option will be that the earth would continue to orbit as before.

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Answer:

3.the distance away from the sun where it to hot or too cold for life to exist

Answer: The pressure that the brick exerts on the surface is approximately 781.8 Pa

Explanation:

Pressure is defined as the force exerted per unit area. In this case, the force exerted by the brick is its weight, which is the mass multiplied by acceleration due to gravity.

The formula to calculate pressure is:

P = F/A

where:

- P is the pressure

- F is the force

- A is the area

First, we need to calculate the weight of the brick. The weight (F) can be calculated using the equation F = m*g, where m is the mass of the brick and g is the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 m/s².

F = m*g

F = 1.8 kg * 9.8 m/s²

F = 17.64 N (rounded to two decimal places)

Next, we need to calculate the area of the cross section of the brick. The area (A) is calculated by multiplying the length by the width.

A = length * width

A = 21.5 cm * 10.5 cm

Before we can do this calculation, we need to convert the measurements from centimeters to meters, because the standard unit of measurement for area in physics is square meters (m²). 1 cm = 0.01 m, so:

A = 0.215 m * 0.105 m

A = 0.022575 m²

Finally, we can calculate the pressure using the formula P = F/A:

P = 17.64 N / 0.022575 m²

P = 781.8 Pa (rounded to one decimal place)

So, the pressure that the brick exerts on the surface is approximately 781.8 Pa (Pascals).

The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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Given:

The initial height of the ball, h=1.6 m

The initial speed of the ball, u=14 m/s

To find:

a) The time of flight of the ball.

b) The range of the ball.

Explanation:

As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.

Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.

The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.

a)

From the equation of motion,

Where g is the acceleration due to gravity and t is the time of flight of the ball.

On substituting the known values,

b)

The range of the ball is given by,

On substituting the known values,

Final answer:

a) The time of flight of the ball is 0.57 s

b) The range of the ball is 7.98 m

Answer:

D) when they build up landforms.

Explanation:

Natural processes such as deposition, volcanic activity, and plate tectonics can create new landforms and build up the Earth's surface. For example, volcanic eruptions can create new islands or add layers of rock and ash to existing landforms, while sediment deposition can build up river deltas and beaches. However, natural processes such as weathering, erosion, and mass wasting can also act as destructive forces, wearing down and reshaping landforms over time.

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Explanation:

SO2 is the best answer

please give brainliest and helpful

Answer: SO2

Explanation:

Answer:

The linear speed of the 0.0800 kg sphere as it passes through its lowest point is 0.989 m/s.

Explanation:

To solve this problem, we can use the principle of conservation of energy, which states that the initial potential energy of the system is equal to the final kinetic energy of the system, assuming no energy is lost to friction or other non-conservative forces.

Initially, the system has only potential energy due to the height of the spheres above their lowest point. At the lowest point, all of this potential energy is converted to kinetic energy, which is shared between the two spheres. We can set the initial potential energy equal to the final kinetic energy and solve for the final speed of the 0.0800 kg sphere.

The initial potential energy of the system is given by:

U_i = mgh = (0.0200 kg)(9.81 m/s^2)(40.0 cm) + (0.0800 kg)(9.81 m/s^2)(40.0 cm) = 0.0782 J

where h is the height of the spheres above their lowest point, which is half the length of the rod.

The final kinetic energy of the system is given by:

K_f = (1/2)mv^2

where m is the mass of the 0.0800 kg sphere and v is its final speed.

Setting the initial potential energy equal to the final kinetic energy and solving for v, we get:

0.0782 J = (1/2)(0.0800 kg)v^2

v^2 = 0.97875 m^2/s^2

v = 0.989 m/s (to three significant figures)

The pitch of the sound increases as the frequency of the sound increases while the loudness remains the same.

The main observations that can be made between a frequency of 500 Hz and one that is above 700 Hz, keeping the amplitude fixed are as follows:As the frequency increases, the pitch becomes higher.

The pitch, loudness, and quality of the sound will change,The higher the frequency, the higher the pitch of the sound. For example, high pitched sounds such as sirens, birds chirping, and whistling sounds have a frequency that is above 700 Hz.On the other hand, sounds that have a frequency of less than 500 Hz are typically lower pitched sounds such as bass instruments, bass guitars, and the sound of a bass drum.

                                          These sounds are perceived to be lower in pitch as compared to sounds with a frequency above 700 Hz.Moreover, there will be no noticeable change in the amplitude of the sound wave since it is held constant. The amplitude of the sound wave is related to the loudness of the sound, and not the pitch of the sound.

Therefore, the pitch of the sound increases as the frequency of the sound increases while the loudness remains the same..

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The acceleration of this car is equal to 9 meters per seconds square (m/s²).

An acceleration can be defined as the rate of change of the velocity of a physical object or body with respect to time.

In Science, the acceleration of a physical object (car) or body can be calculated by using this formula:

a = (V - U)/t

Where:  

Substituting the given parameters into the formula, we have;

a = (80 - 50)/30

a = 30/30

Acceleration, a = 1 m/s²

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The potential energy lost during the formation of product (B) is gained by the surroundings.

Exothermic reactions is a type of chemical reaction in which heat is lots to the surroundings.

From the given diagram, the energy of the reactants are more when compared to the products, so the reaction is exothermic and heat is released to surroundings.

Thus, the potential energy lost during the formation of product (B) is gained by the surroundings.

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The wavelength of the light is 5.3 x 10^-7 meters. So option C is correct.

It can be determined by the distance between the interference bands on the screen.

The formula for this relationship is: d = a * λ / L, where d is the distance between the bands, a is the distance between the slits, λ is the wavelength of the light, and L is the distance from the slits to the screen.

By plugging in the given values,

d = 4.2 x 10^-4 m, a = 5.0 x 10^-3 m, and L = 4.0 m, we can calculate λ. Solving for λ, we get λ = \(5.3 * 10^{-7\) m.

Hence, the wavelength of the green light is \(5.3 * 10^{-7\) meters.

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