I accidentally clicked one, can you please tell me if it's correct or not.
if you don't know, please don't answer I need a 100 on this.

Thank you :)​

Answer:

0.989

Step-by-step explanation:

The formula for Margin of Error is:

z × Standard deviation/√n

Where

z = z score for 99% confidence Interval

= 2.576

n = 61 people

Standard deviation = $3

Hence,

Margin of Error

= 2.576 × 3/√61

= 0.989

The required length of the side AC in the triangle ACD with the  given  measurements is equals to  11.4 cm (correct to 3 significant figures).

In triangle ACD,

Measure of angle ADC = 42 degrees

AD = 17 cm

CD = 13 cm

The length of AC, use the Law of Cosines, which states that,

c^2 = a^2 + b^2 - 2ab cos(C)

Where c is the length of the side opposite the angle C,

And a and b are the lengths of the other two sides.

The length of AC, which is opposite the angle ADC.

AC^2 = AD^2 + CD^2 - 2AD CD cos(ADC)

Substituting the given values, we get,

⇒ AC^2 = 17^2 + 13^2 - 2(17)(13)cos(42)

⇒ AC^2 = 289 + 169 - 442 × 0.7431

⇒ AC^2 = 289 + 169 -328.4502

⇒ AC^2 = 129.5498

⇒ AC = 11.38

⇒ AC = 11.4 cm (correct to 3 significant figures).

Therefore, the length of AC in triangle ACD is equal to 11.4cm.

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The above question is incomplete, the complete question is:

In triangle ACD , measure of angle ADC = 42 degrees , AD = 17cm and CD = 13cm then Show that AC = 11. 4cm, correct to 3 significant figures.

Answer:

125%

Sorry for no explaination ;-;

Answer:

5/9

Step-by-step explanation:

we add all of the values and divide by the total number in this case 9, all of them add to make 5 so we do 5÷9 to get 5/9

Answer:

yes you did right answer

Answer:

91 pizzas

Step-by-step explanation:

Answer:

150

Step-by-step explanation: dont give away 50 points

Answer:

8.39 seconds

Step-by-step explanation:

Given the equation which models the height of a rocket:

y=-16x^2+263x+92

Time taken to reach maximum height ; = total total time of flight / 2

Total time of flight is obtained at h = 0

Hence +,

y=-16x^2+263x+92 ; y = 0

-16x^2+263x+92 = 0

Using the Quadratic equation solver :

X = 16.78 or x = -0.3466

Time can't be negative

Hence, total time of flight= 16.78

Therefore, time taken to reach maximum height :

Total time of flight / 2

= 16.78 / 2

= 8.39 seconds

The given system of equations do not have a solution since their related line equations have the same slope.

The given system of equations is:

-x + 5y = 3   .......... (1)

2x - 10y = 4   ........(2)

In Equation (1), add both sides by (-5y)

-x + 5y + (-5y) = 3 + (-5y)

-x = -3 - 5y

Multiply by (-1)

x = 3 + 5y

Substitute x = 3 + 5y into equation (2)

2x - 10y = 4

2.(3 + 5y) - 10y = 4

6 + 10y - 10y = 4

6 = 4 (False)

Since the last equation is false, we might suspect that the given system of solution does not have solutions.

We need to check the slope of both equations:

-x + 5y = 3

⇒ 5y = x + 3

⇒ y = 1/5 x + 3/5

2x - 10y = 4

⇒ -10 y = -2x + 4

⇒ y = (2/10) x - 4/10

⇒ y = 1/5 x - 2/5

We can see that both equations have the same slope, i.e. 1/5.

Hence, they do not have solutions since the lines are parallel to each other.

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The area and perimeter of the figure be 562.08 m² and 123.68 m.

The figure referred to is made out of a parallelogram and a crescent. The area of the parallelogram can be determined by utilizing the equation base x level, bringing about an area of 336 m².

The area of the crescent is determined utilizing the formula (π x r²)/2, calculating an area of 226.08 m². Thus, the complete area of the figure is 562.08 m².

The perimeter of the parallelogram is 86 m, while the border of the half circle is 37.68 m, giving an all-out perimeter of 123.68 m.

The area of the figure is 562.08 m², while the perimeter is 123.68 m.

This can be additionally separated into the area and perimeter of the parallelogram and half circle, which are 336 m² and 226.08 m² for the area, and 86 m and 37.68 m for the border, individually.

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The inequality can be simplified to:

-7 < x < 3

And the graph can be seen in the image at the end.

Here we have the inequality:

|x + 2| + 1 > 6

To solve this, we need to isolate the variable x, so if we first subtract 1 we get:

|x + 2| +1 - 1 > 6 - 1

|x + 2| > 5

The absolute value part can be decomposed into two.

-5 < x + 2 < 5

Now we can subtract 2 in all the inequality, so we get:

-5 - 2 < x + 2 - 2 < 5 - 2

-7 < x < 3

The graph of this can be seen below

The equation of g(x) is 24 (3)ˣ when the graph is stretched vertically by a factor of 3 to form the graph g(x).

What is function?

For the parent function f(x) and a constant k >0,

then, the function given by  

g(x) = kf(x) can be sketched by vertically stretching f(x) by a factor of k if k>1 (or)

if 0 < k < 1 , then it is vertically shrinking f(x) by a factor of k

As per the given statement that the graph of f(x) is stretched vertically by a factor of 3 i.e

k = 3 >1

so, by definition

g(x) = 3 f(x) = 3 . 8(3)ˣ

= 8(3)ˣ⁺¹

= 24 (3)ˣ

Hence, the equation of g(x) is 24 (3)ˣ when the graph is stretched vertically by a factor of 3 to form the graph g(x).

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The population median commute time of the employees of Asons is 40 minutes.

The median is a measure of central tendency that represents the middle value in a dataset when the data is arranged in ascending or descending order. In this case, the commute times provided are 47.4, 45, 35, and 40 minutes.

To determine the median, we arrange the commute times in ascending order: 35, 40, 45, 47.4. Since there are four values in the dataset, the middle value is the average of the two central values, which are 40 and 45. Taking the average of these two values gives us the median of 40 minutes.

Therefore, the population median commute time of the employees of Asons is 40 minutes, indicating that half of the employees have a commute time of 40 minutes or less, while the other half have a commute time of 40 minutes or more.

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Is this the question below if it is the answer is..

Answer/Step-by-step explanation:

line E prime F prime passes through the center of dilation.

there are two values of x in the interval where the instantaneous rate of change of is equal to the average rate of change of over the interval.

To find the average rate of change of over the interval , we need to calculate the slope of the line passing through the two endpoints of the interval.

The slope of the line passing through the points and is given by:

( - )/( - ) = ( -3 - 3)/(1 - (-1)) = -6/2 = -3

Therefore, the average rate of change of over the interval is -3.

To find how many values of in the interval have instantaneous rate of change equal to the average rate of change, we need to find the derivative of :

f'(x) = 3x^2 - 3x - 3

Setting f'(x) equal to the average rate of change, we get:

3x^2 - 3x - 3 = -3

Simplifying the equation, we get:

3x^2 - 3x = 0

Factoring out 3x, we get:

3x(x - 1) = 0

Therefore, the solutions are x = 0 and x = 1.

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Answer:

96 cm^2

Step-by-step explanation:

Volume of a cube =(side)^3=64 cm^3.

(side)^3= (4 cm.)^3

or side =4 cm.

Surface area =6×(side)^2..

=6×4×4 cm^2=

96 cm^2. , Answer

Answer:

Step-by-step explanation:

Volume of cube = 64 m³

Side³ = 64

Side = ∛64 = ∛2*2*2*2*2*2

Side = 2*2 = 4 m

Surface area = 6side² = 6* 4² = 6*4*4

                     = 96 m²

Answer:

Start with equation,

         y''(x) = f(x) = 6y/(10x-x²)               about point x₀ = 5

Then,

       y(x) = a₀ + a₁(x-5) + a₂(x-5)²+ a₃(x-5)³ + a₄(x-5)⁴...….

by inspection,

           y(5) = a₀      and       y'(5) = a₁

then,

y''(5) = 6a₀/(50-25) = 6a₀/25              

y'''(x) = 6y'/(10x-x2) - 6y(10-2x)/(10x-x2)2

then,                      

                              y'''(5) = 6a₁/25 - 0 = 6a₁/25                

y''''(x) = 6y''/(10x-x2) -12y'(10-2x)/(10x-x2)² + 12y/(10x-x2)² + 12y(10-2x)2/(10x-x2)³

then,

    y''''(5) = (6/25)(6a₀/25) + 0 + 12a₀/625 + 0

              = 48a₀/625

So,

y(x) = f(x) = f(5) + f'(5)(x-5) + f''(5)(x-5)2/2! + f'''(5)(x-5)3/3! + f''''(5)(x-5)4/4! …

                                                       or

y(x) = f(x) = a₀ + a₁(x-5) + (6ao/25)(x-5)2/2! + (6a1/25)(x-5)3/3! + (48a₀/625)(x-5)4/4!...

                                                         or

y(x) = f(x) = a₀ + a₁(x-5) + (3a₀/25)(x-5)²+ (a₁/25)(x-5)³+ (2a₀/625)(x-5)⁴.....

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The number  300 can be written as 300/1 as a quotient of integers to show that it is rational.

A rational number is a number of the form p/q, where q not equal to 0 and p  and q must be co-primes.

To write a number in the form of quotient of integer, we write it as , where p/q.

Here,  300 can be written as  300/1 or 600/2 .

But we should also take care that p and q must be co-primes.

Co-primes are the pairs of numbers that have only one common factor which is 1.

So, 300 can be written as 300/1

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Given: Rectangle PQRS, SP = 7 and PR = 25We need to find PQ.Let us first draw the diagram:Now, we know that opposite sides of a rectangle are equal.So, QR = PSAlso, PQ || SR and QR || PSIn right triangle SPQ, applying Pythagoras theorem.

\(We get: SQ² = SP² + PQ²7² = 25² + PQ²49 = 625 + PQ²PQ² = 49 - 625PQ² = -576As\) PQ cannot be negative, hence the answer is not possible. Thus, there is no possible answer available for the given problem.

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The number of ways to buy 20 bagels with at least one bagel of each kind from a bagel store that sells 6 different types of bagels is 3060.

To calculate the number of ways to buy 20 bagels with at least one bagel of each kind from a bagel store that sells 6 different types of bagels, we can use the concept of stars and bars.

First, we need to ensure that we have at least one of each type of bagel. So, we take one bagel of each type, which leaves us with 14 bagels to buy.

Now, we can use stars and bars to distribute the remaining 14 bagels among the 6 types of bagels. We represent the 14 bagels as stars and the 5 possible locations between the types of bagels as bars.

Using this method, we need to distribute 14 stars among 5 bars, which can be done in

(14+5-1) choose (5-1) = 18 choose 4 = 3060 ways.

Therefore, the number of ways to buy 20 bagels with at least one bagel of each kind from a bagel store that sells 6 different types of bagels is 3060.

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The optimal values of x and y that minimize the objective-function x + y, subject to the given constraints, are x = 4 and y = 0.

We can find the corner points of the feasible region and evaluate the objective function at those points to determine the optimal solution.

Graph the constraints:

Start by graphing the inequalities:

x + y ≥ 7

5x + 2y ≥ 20

x ≥ 0

y ≥ 0

Plot the lines x + y = 7 and 5x + 2y = 20. To graph x + y = 7, plot two points that satisfy the equation, such as (0, 7) and (7, 0), and draw a line through them. To graph 5x + 2y = 20, plot two points such as (0, 10) and (4, 0), and draw a line through them.

Shade the region that satisfies the inequalities x ≥ 0 and y ≥ 0.

The feasible region will be the shaded region.

Identify the feasible region:

The feasible region is the shaded region where all the constraints are satisfied. In this case, the feasible region will be a polygon bounded by the lines x + y = 7, 5x + 2y = 20, x = 0, and y = 0.

Find the corner points:

Locate the intersection points of the lines and the axes within the feasible region. These are the corner points. In this case, we have the following corner points:

Intersection of x + y = 7 and x = 0: (0, 7)

Intersection of x + y = 7 and y = 0: (7, 0)

Intersection of 5x + 2y = 20 and x = 0: (0, 10)

Intersection of 5x + 2y = 20 and y = 0: (4, 0)

Evaluate the objective function:

Evaluate the objective function, which is x + y, at each corner point:

(0, 7): x + y = 0 + 7 = 7

(7, 0): x + y = 7 + 0 = 7

(0, 10): x + y = 0 + 10 = 10

(4, 0): x + y = 4 + 0 = 4

Determine the optimal solution:

The optimal solution is the corner point that minimizes the objective function (x + y). In this case, the optimal solution is (4, 0) because it has the smallest objective function value of 4.

Therefore, the optimal values of x and y that minimize the objective function x + y, subject to the given constraints, are x = 4 and y = 0.

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Answer:

-6

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

   = ( -8- -14)/( 8 -9)

  = ( -8+14)/( 8 -9)

  6/-1

  -6

Answer:

\(\boxed {\tt m= -6}\)

Step-by-step explanation:

The slope formula is:

\(m=\frac{y_2-y_1}{x_2-x_1}\)

where (x₁, y₁) and (x₂, y₂) are the points given.

The points are (9, -14) and (8,-8). Therefore,

x₁=9

y₁= -14

x₂= 8

y₂= -8

Substitute the values into the formula.

\(m=\frac{-8 - -14}{8-9}\)

\(m=\frac{-8 +14}{8-9}\)

Solve the numerator.

\(m=\frac{6}{8-9}\)

Solve the denominator.

\(m=\frac{6}{-1}\)

Divide 6 by -1.

\(m= -6\)

The slope is equal to -6

Answer:

SOLUTION: Explain why the square root of 25 belongs to 4 subsets of the real numbers , but the square root of 5 only belongs to 1 . tell which subsets each belong to and why .

Step-by-step explanation:

The square root of 25 is 5, which  

1. A rational number, since 5 is the ratio of the two integers 5 and 1.

2. An integer since 5 is an element of {...,-3,-2,-1,0,1,2,3,.}  

3. A whole number, since 5 is an element of {0,1,2,3.}

4. A counting number, since 5 is an element of {1,2,3,}

The square root of 5 is only  

1. An irrational number, since it is not the ratio of any two integers.

[It can only be approximated by

this nonrepeating infinite decimal, it goes on forever:

2.2360679774997896964091736687312762354406183596115257...]

Answer:

x = 25

y = 6

Step-by-step explanation:

< B = < M

2x - 20 = 30

2x = 50

x = 25

AB = LM

7y - 8 = 2y + 22

5y = 30

y = 6

To find the break-even point, we need to find the point where the cost function and revenue function intersect, since at that point the profit will be zero.

So, we set the cost function equal to the revenue function:

180x + 8400 = 210x

Simplifying:

30x = 8400

x = 280

Therefore, the break-even point is at x = 280. To find the coordinates, we need to plug this value into either the cost or revenue function:

c(280) = 180(280) + 8400 = 50400

r(280) = 210(280) = 58800

So the break-even point is (280, 50400).
To find the coordinates of the break-even point, we need to determine the value of x when the cost of production (c(x)) is equal to the revenue (r(x)). In other words, we need to solve the equation c(x) = r(x).

Step 1: Set c(x) equal to r(x)
180x + 8400 = 210x

Step 2: Rearrange the equation to solve for x
210x - 180x = 8400
30x = 8400

Step 3: Divide both sides by 30 to find x
x = 8400 / 30
x = 280

Step 4: Find the break-even revenue by plugging x into either the cost or revenue function (we'll use r(x))
r(280) = 210 * 280 = 58800

So, the coordinates of the break-even point are (280, 58800), where 280 represents the number of cell phones produced and 58800 is the revenue generated.

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The range of the function g(x) = |x - 12| - 2 is {y | y > -2}, indicating that the function can take any value greater than -2.

To find the range of the function g(x) = |x - 12| - 2, we need to determine the set of all possible values that the function can take.

The absolute value function |x - 12| represents the distance between x and 12 on the number line. Since the absolute value always results in a non-negative value, the expression |x - 12| will always be greater than or equal to 0.

By subtracting 2 from |x - 12|, we shift the entire range downward by 2 units. This means that the minimum value of g(x) will be -2.

Therefore, the range of g(x) can be written as {y | y > -2}, which means that the function can take any value greater than -2. In other words, the range includes all real numbers greater than -2.

Visually, if we were to plot the graph of g(x), it would be a V-shaped graph with the vertex at (12, -2) and the arms extending upward infinitely. The function will never be less than -2 since we are subtracting 2 from the absolute value.

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The function f is twice differentiable on the interval [a, b], conditions provide some information about the behavior of the function f on the given interval.

Based on the given conditions, we can conclude the following:
1. The function f is defined on a non-degenerate closed interval [a, b] in the real numbers.
2. The function f is twice differentiable, meaning its derivative exists and is also differentiable.
3. The value of f(a) is negative, indicating that the function takes a negative value at the left endpoint of the interval.
4. The value of f(b) is positive, indicating that the function takes a positive value at the right endpoint of the interval.
5. The derivative of f, denoted as f'(x), is greater than or equal to a positive constant c for all x in the interval (a, b). This implies that the function is increasing or non-decreasing throughout the interval.
6. The second derivative of f, denoted as f''(x), is greater than or equal to 0 and less than or equal to a constant m for all x in the interval (a, b). This implies that the function is concave up or non-concave down throughout the interval.
These conditions provide information about the behavior of the function f within the interval [a, b].

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Answer:

The like terms: 3x and 2x

Step-by-step explanation:

3x+2x+6y+3

5x+6y+3

Hope this helps

Answer:

Original price of ticket = $12.5

Step-by-step explanation:

Given:

8% amount = $1

Find:

Original price of ticket

Computation:

Original price of ticket = 1(100/8)

Original price of ticket = $12.5