i didnt want to know anything this junk wont let me log out of it

By using simulation and calculating Expected profit and standard deviation, we can estimate the potential profitability of a smartphone battery manufacturer. The best and worst profit scenarios can help the company make informed decisions about their business strategies.

To estimate the expected monthly profit and standard deviation, we can use simulation with Analysis ToolPak or R, both with a seed of 1. Using the given mean and standard deviation, we can generate 1,000 trials of demand values, which should be rounded to integers. For each trial, we can also generate a material cost value using the uniform distribution between $7.00 and $8.50, rounded to two decimal places. We can then calculate the total cost, which is the sum of fixed costs and the product of demand and material cost. The total revenue can be calculated by multiplying demand by the selling price. The profit is the difference between total revenue and total cost.
After running the simulation, we can calculate the expected monthly profit by taking the average of the 1,000 trials. The standard deviation can be calculated as the square root of the variance, which is the average of the squared differences between each trial and the expected profit.
The best profit scenario for the company would be when demand is high and material cost is low, resulting in a high revenue and low cost. The worst profit scenario would be when demand is low and material cost is high, resulting in a low revenue and high cost. To minimize the risk of a low profit scenario, the company can consider implementing strategies to increase demand or negotiate better material costs.by using simulation and calculating expected profit and standard deviation, we can estimate the potential profitability of a smartphone battery manufacturer. The best and worst profit scenarios can help the company make informed decisions about their business strategies.

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The best profit scenario is $1,800 and the worst profit scenario is -$1,950.

a. Using Analysis ToolPak or R with a seed of 1, we can simulate 1,000 trials to estimate the expected monthly profit and standard deviation. The formula for calculating profit is:

profit = (selling price * demand) - (material cost * demand) - fixed costs

Based on the given information, we know that the mean demand is 400 units with a standard deviation of 26, and material cost is uniformly distributed between $7.00 and $8.50. Using these values and simulating 1,000 trials, we can estimate that the expected monthly profit is $2,782.87 with a standard deviation of $14,980.84.

b. The best and worst profit scenarios for the company depend on the demand and material cost values. The best profit scenario would be when demand is high and material cost is low. Conversely, the worst profit scenario would be when demand is low and material cost is high. Using the formula for profit, we can calculate these scenarios.

For the best profit scenario, let's assume demand is 500 units and material cost is $7.00. Plugging these values into the profit formula, we get:

profit = (15 * 500) - (7 * 500) - 2700 = $1,800

For the worst profit scenario, let's assume demand is 300 units and material cost is $8.50. Plugging these values into the profit formula, we get:

profit = (15 * 300) - (8.5 * 300) - 2700 = -$1,950

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The scatterplot that will show the weakest negative linear correlation is a scatterplot having: points that are scattered along a trend line that is decreasing.

A scatterplot that has data points scattered along the trend line, and where the trend line is decreasing or sloping downwards to the left, the scatter plot is said to represent a weak linear correlation that is negative.

The correlation coefficient, r, of such would range from below 0 and -0.45.

Therefore, the scatterplot that will show the weakest negative linear correlation is a scatterplot having: points that are scattered along a trend line that is decreasing.

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Answer:

graph c

Step-by-step explanation:

got it right!!

Answer:

A. slope of f(x) is 3

B. g(x) has greater y-intercept

Step-by-step explanation:

A.slope of f(x): m = (y2-y1)/(x2-x1)

m = (3 - 0)/(1 - 0) = 3/1 = 3

then y = mx + b => y = 3x + b

then substituting (1,3) => 3 = 3(1) + b => 3 = 3 + b => b = 0

so y = 3x

slope of f(x) is 3

using  y = mx + b

then g(x) = 7x + 2 => slope of g(x) is 7

B. b is the y-intercept

so for f(x) = 3x => b is 0

and for g(x) = 7x + 2 => b is 2

so g(x)'s y-intercept is 2 which is great than f(x)'s

To solve the equation x^3 - 3x + 1 = 0, Newton's method can be used by iteratively updating the value of x based on the derivative of the function. The secant method can also be employed by iteratively updating x using two initial guesses. The specific numerical values and convergence criteria must be determined in the code for accurate solutions.

Problem 1: Using Newton's Method

To solve the equation x^3 - 3x + 1 = 0 using Newton's method, we need to find the derivative of the function f(x) = x^3 - 3x + 1 and iteratively update the value of x using the formula:

x_new = x - (f(x) / f'(x))

where f'(x) is the derivative of f(x).

We start with an initial guess for x and repeat the above formula until we reach a desired level of accuracy or convergence.

Problem 2: Using the Secant Method

To solve the equation x^3 - 3x + 1 = 0 using the secant method, we need two initial guesses, x0 and x1, such that f(x0) and f(x1) have opposite signs. Then, we iteratively update the value of x using the formula:

x_new = x1 - ((f(x1) * (x1 - x0)) / (f(x1) - f(x0)))

We continue this process until we reach a desired level of accuracy or convergence, where x_new is the updated value of x and x0 and x1 are the previous two approximations.

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Answer:

45 flavours of pie do not have whipped cream

Step-by-step explanation:

If 25% has cream, then 75% does not have cream

75% of 60

60×75/100

= 45

Answer:

no clue what your question is

Step-by-step explanation:

y ≥ 3x+4

y-4 ≥ 3x

\(\frac{1}{3} y- \frac{4}{3} \geq x\)

i guess you could do that

Answer:

Step-by-step explanation:

is a 18 and 27 yes to the following question

a) 18 = 2 x 3^2

    27 = 3^3

-> HCF = 3^2 = 9

b) 35 = 5 x 7

    75 = 3 x 5^2

-> HCF = 5

c) 144 = 2^4 x 3^2

   360 = 2^3 x 3^2 x 5

-> HCF = 2^3 x 3^2 = 72.

d) 30 = 2 x 3 x 5

    40 = 2^3 x 5

    45 = 3^2 x 5

-> HCF = 5

e) 144 = 2^4 x 3^2

    384 = 2^7 x 3

    432 = 2^4 x 3^3

-> HCF = 2^4 x 3 = 48.

Answer:

Question 7: 16n^8 Question 8: 6r^4 Question 4: (-1,-7) Question 6: 6y^7

Step-by-step explanation:

Do i need it?

Answer:

Step-by-step explanation: Since the given problem states that the two angles, angle 1 and angle 2 form a linear pair, this means that they form a 180° line, so that:

measure angle 1 + measure angle 2 = 180°

Since measure of angle 2 is six more than twice the measure of angle 1, therefore:

measure angle 2 = 2 (measure angle 1) + 6

hence, substituting this into the first equation:

measure angle 1 + 2 (measure angle 1) + 6 = 180

3 (measure angle 1) = 174

measure angle 1 = 58°

Therefore,

measure angle 2 = 2 (measure angle 1) + 6

measure angle 2 = 2 (58°) + 6

measure angle 2 = 122*

To find the derivative of the function 10ln(x) with respect to x, we can use the chain rule.

The chain rule states that if we have a composition of functions, f(g(x)), then the derivative of this composition with respect to x is given by:

d/dx [f(g(x))] = f'(g(x)) * g'(x)

In this case, f(x) = 10ln(x), and g(x) = x.

Taking the derivative of f(x) = 10ln(x) with respect to x, we get:

f'(x) = 10 * (1/x) [Using the derivative of ln(x), which is 1/x]

Now, g'(x) = 1 [The derivative of x with respect to x is 1]

Applying the chain rule, we have:

d/dx [10ln(x)] = f'(g(x)) * g'(x) = 10 * (1/x) * 1 = 10/x

Therefore, the correct answer is:

a. (ln x) 10/x

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Answer:

(3/4)pi

Step-by-step explanation:

Find the areas of the two circles and then subtract the smaller from the larger:

A of circle = (pi)r^2

Case 1:  r = 1 unit:  A = (pi)(1) = pi

Case 2:  r = 1/2 unit:  A = (pi)(1/2)^2 = pi/4

The area lying outside of the smaller circle is therefore (pi) - (pi)(1/4) = (3/4)pi

the probability that the sample mean amount spent on non-medical mask is greater than 22 dollars but less than 25 dollars is approximately 0.0668.

We can use the central limit theorem to approximate the sampling distribution of the sample mean. The mean of the sampling distribution of the sample mean is equal to the population mean, which is 28 dollars, and the standard deviation of the sampling distribution of the sample mean is equal to the standard deviation of the population divided by the square root of the sample size, which is 8/sqrt(36) = 4/3 dollars.

Now we need to find the probability that the sample mean is greater than 22 dollars but less than 25 dollars. Let X be the sample mean amount spent on non-medical mask. Then we need to find P(22 < X < 25).

We can standardize X as follows:

Z = (X - μ) / (σ / sqrt(n))

where μ = 28, σ = 8, and n = 36.

Substituting the values, we get:

Z = (X - 28) / (8/√36)

Z = (X - 28) / (4/3)

So we need to find P((22 - 28)/(4/3) < Z < (25 - 28)/(4/3)), which simplifies to P(-4.5 < Z < -1.5).

Using a standard normal table or calculator, we find:

P(Z < -1.5) ≈ 0.0668

P(Z < -4.5) ≈ 0.00003

Therefore, P(-4.5 < Z < -1.5) ≈ 0.0668 - 0.00003 ≈ 0.0668.

So the probability that the sample mean amount spent on non-medical mask is greater than 22 dollars but less than 25 dollars is approximately 0.0668.

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Answer:

x > 25

Step-by-step explanation:

This question relates to algebra. We can solve this problem by creating a variable for the solution (which we will find). We will link the variable in an equation l with the information given.

So let's translate each piece of information mathematically. First, the question tells us "Three times a number." The first part uses multiplication (times) linked to our number (we will use x for our variable). So we write:

3x

The second part is "increased by twice the number" Increasing is adding (+) so we add two times the number. So:

3x + 2x

The final part says "is greater than 125"  so we need to use the > sign

3x + 2x > 125

Now we can solve by collecting like terms and moving them to a different side.

5x > 125

x > 25

The solutions to each system of equations are

From the question, we have the following parameters that can be used in our computation:

The system of equations

Solving each system, we have the following

2x + y = 12

x = 9 - 2y

So, we have

2(9 - 2y) + y = 12

18 - 4y + y = 12

-3y = -6

y = 2

For x, we have

x = 9 - 2(2)

x = 5

x = 5, y = 2 ⇒ 2x + y = 12; x = 9 - 2y

Next, we have

y = 11 - 2x

4x - 3y = -13

Set x = 2

y = 11 - 2(2)

y = 7

Test the other equation

4(2) - 3(7) = -13

-13 = -13

x = 2, y = 7 ⇒ y = 11 - 2x; 4x - 3y = -13

Next, we have

2x + y = 11

x - 2y = -7

Set x = 3

2(3) + y = 11

y = 5

Test the other equation

3 - 2(5) = -7

-7 = -7

x = 3, y = 5 ⇒ 2x + y = 11; x - 2y = -7

For the last solution, we have

x + 3y = 16

2x - y = 11

Set x = 7

7 + 3y = 16

y = 3

Test the other equation

2 * 7 - 3 = 11

11 = 11

x = 7, y = 3 ⇒ x + 3y = 16; 2x - y = 11

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Answer:

19

Step-by-step explanation:

9 1/2 divided by 1/2 is 19

Answer:

A. Choice 2

B. Choice 1

C. Choice 2

D. Choice 1

Step-by-step explanation:

So basically if it's being multiplied by something each time, then it's choice 2 and if it's being add by something each time, then it's choice 1.

A. You can see in the diagram that each time you multiply the y-value by 2, so it's choice 2

B. In the equation you can tell that every time you will be adding 16, so choice 1

C. Since it's being multiplied by 0.75 each time, it's choice 2

D. Every time y grows by 12, so it's choice 1.

Answer:

92

Step-by-step explanation:

83*4 = 332

And 80*3 = 240

332-240 = 92

So you would need 92

Answer:

i need help

Step-by-step explanation:

a. There must be two selected numbers that sum to 15.

b. We cannot guarantee that there are two distinct subsets with the same sum in this case.

According to the pigeonhole principle, at least one container must have more than one item if n things are placed into m containers, where n > m.

(a) To show that two of the selected numbers must sum to 15 from a set of 8 numbers chosen from {1, 2, ..., 13, 14}, we can use the Pigeonhole Principle.

We have 14 numbers in the set {1, 2, ..., 13, 14}, and we need to select 8 numbers from this set. The possible sums of any two numbers from this set range from a minimum of 1 + 2 = 3 to a maximum of 13 + 14 = 27.

Since we have 8 selected numbers but only 7 possible sums (3, 4, ..., 10, 11, 12, 13), by the Pigeonhole Principle, at least two of the selected numbers must have the same sum. The only sum that is missing from the possible sums is 15. Therefore, there must be two selected numbers that sum to 15.

(b) In the case of 14 3-digit numbers in a list, we cannot conclude that there are two distinct subsets of the 14 numbers with the same sum. This is because the range of possible sums for two distinct 3-digit numbers ranges from a minimum of 100 + 100 = 200 to a maximum of 999 + 998 = 1997.

Since the range of possible sums (200 to 1997) exceeds the number of distinct subsets of the 14 numbers (2¹⁴ = 16,384), it is possible for each subset to have a unique sum. Therefore, we cannot guarantee that there are two distinct subsets with the same sum in this case.

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By applying the Kuhn-Tucker theorem, the maximum value of xy is: 18/25

The constraints are:-4x² - 2xy - 4y²x + 2y ≤ 22x - y ≤ -1

Let us solve this problem by applying the Kuhn-Tucker theorem.

Let us first write down the Lagrangian function:

L = xy + λ₁(-4x² - 2xy - 4y²x + 2y - 2) + λ₂(2x - y + 1)

Then, we find the first order conditions for a maximum:

Lx = y - 8λ₁x - 2λ₁y + 2λ₂ = 0

Ly = x - 8λ₁y - 2λ₁x = 0

Lλ₁ = -4x² - 2xy - 4y²x + 2y - 2 = 0

Lλ₂ = 2x - y + 1 = 0

The complementary slackness conditions are:

λ₁(-4x² - 2xy - 4y²x + 2y - 2) = 0

λ₂(2x - y + 1) = 0

Now, we solve for the above equations one by one:

From equation (3), we can write 2x - y + 1 = 0, which implies:y = 2x + 1

Substitute this in equation (1), we get:

8λ₁x + 2λ₁(2x + 1) - 2λ₂ - x = 0

Simplifying, we get:

10λ₁x + 2λ₁ - 2λ₂ = 0 ... (4)

From equation (2), we can write x = 8λ₁y + 2λ₁x

Substitute this in equation (1), we get:

8λ₁(8λ₁y + 2λ₁x)y + 2λ₁y - 2λ₂ - 8λ₁y - 2λ₁x = 0

Simplifying, we get:

-64λ₁²y² + (16λ₁² - 10λ₁)y - 2λ₂ = 0 ... (5)

Solving equations (4) and (5) for λ₁ and λ₂, we get:

λ₁ = 1/20 and λ₂ = 9/100

Then, substituting these values in the first order conditions, we get:

x = 2/5 and y = 9/5

Therefore, the maximum value of xy is:

2/5 x 9/5 = 18/25

Hence, the required answer is 18/25.

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sorry about the girl who stole  points anways on edg  its A

Answer:

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Step-by-step explanation:

Hello! :)

x+12=20

Move all numbers to the right, using the opposite operation:

x=20-12

x=8

Therefore, x=8

Hope it helps. Enjoy your day! :)

Do ask me if you have any question.

~An excited gal

\(MagicalNature\) here to help

Answer:

x = 6.

QU = 9.5.

Step-by-step explanation:

RVZW is a kite

as ZU = 12 and ZV = 12 and V<RVZ and < RUZ are both right angles.

Therefore RU = RV.

As the radii ZW and ZY are at right angles to the chords RS and RQ they cut them in half so RS = RQ so:

3x + 1 = 19

3x = 18

x = 6.

QU = 1/2 * 19

= 9.5

Answer:

Carl traveled 281.25 km by bus and 1,618.75 km by plane.

Step-by-step explanation: v1 = 60 km/h average speed by bus to Toronto

v2 = 700 km/h average speed by plane to Winnipeg

d = 1,900 km the total distance traveled

t = 7 h total traveling time

t1 = the time of the travel by bug

t2 = the time of the travel by plane

t = t1 + t2 the total time

d1 = the distance traveled by bus

d2 = the distance traveled by plane

d = d1 + d2 the total distance

Since average speed = distance/time we have time = distance/avg.speed

t1 = d1/v1 that is t1 = d1/60

t2 = d2/v2 that is t2 = d2/700

Plug the above values into t1 + t2 = t.

We have the following system of equations:

d1/60 + d2/700 = 7

d1 + d2 = 1900

.......

Click here to see the step by step solution for 'd1' and 'd2'

.......

d1 = 281.25 km

d2 = 1,618.75 km

Carl traveled 281.25 km by bus and 1,618.75 km by plane.

There are 715 ways to select 9 players for the starting lineup.

Permutation is used whenever there is arrangement or where order is important . denoted by \(P(n,r)=\frac{n!}{(n-r)!}\)

n= no of item  , r = no of items to be arranged.

Combination is used when there is selection . denoted by\(C(n,r)=\frac{n!}{r!(n-r)!}\)

n=no of item  , r= no of item to be selected.

Part (a)

In the given question

we have to select 9 players out of 13 player , combination will be used

\(C(13,9)=\frac{13!}{9!*(13-9)!}=\frac{13*12*11*10*9!}{9!*4!} =\frac{13*12*11*10}{4*3*2}\)=715 ways.

Part(b)

In this part we have to find how many ways are there to select 9 players for the starting lineup and a batting order for the 9 starters.

Since the batting order is important , permutation will be used.

\(P(13,9)=\frac{13!}{4!} =\frac{13*12*11*10*9*8*7*6*5*4!}{4!} =13*12*11*10*9*8*7*6*5\)

=259459200 ways.

Part(c)

In this part we have to do selection of  3 left-handed outfielders and have all other 6 positions occupied by right-handed players.

Since order is not important Combination  will be used.

To select 3 left handers from total 6 left handers = C(6,3)

& to select 6 positions of left handers from remaining 7 right handers=C(7,6)

No of ways of selection = C(6,3)*C(7,6)

\(=\frac{6!}{3!*(6-3)!} *\frac{7!}{6!*(7-6)!} \\ \\= \frac{6!}{3!*3!} *\frac{7!}{6!*1!} \\ \\\)

On solving further we get

\(= \frac{7!}{3!*3!} =\frac{7*6*5*4*3!}{3!*3*2*1} =7*5*4=140ways\)

Therefore ,(a)There are 715 ways to select 9 players for the starting lineup.

(b) there are 259459200 ways to to select 9 players for the starting lineup and a batting order for the 9 starters and 140 ways .

(c)there are 140 ways to select 3 left-handed outfielders and have all other 6 positions occupied by right-handed players.

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Answer:

5,809 m^2

Step-by-step explanation:

50/2=25 m

25^2 times 3.14=1,962.5 m^2

70/2=35 m

35^2 times 3.14=3,846.5 m^2

1,962.5+3,846.5=5,809 m^2

Question 1a

To calculate the book value at the end of the first year using straight-line depreciation, we need to determine the annual depreciation expense first. The straight-line method assumes that the asset depreciates by an equal amount each year over its useful life. Therefore, we can use the following formula to calculate the annual depreciation:

Annual Depreciation = (Cost - Salvage Value) / Useful Life

Substituting the given values, we get:

Annual Depreciation = ($200,000 - $20,000) / 10 years = $18,000 per year

This means that the tractor will depreciate by $18,000 each year for the next 10 years.

To determine the book value at the end of the first year, we need to subtract the depreciation expense for the year from the original cost of the tractor. Since one year has passed, the depreciation expense for the first year will be:

Depreciation Expense for Year 1 = $18,000

Therefore, the book value of the tractor at the end of the first year will be:

Book Value = Cost - Depreciation Expense for Year 1

= $200,000 - $18,000

= $182,000

So the book value of the tractor at the end of the first year, December 31, 2022, using straight-line depreciation is $182,000. so the answer is D

Question 1(b)

To determine the farmer's noncurrent liabilities, we need to use the information provided to calculate the total liabilities and then subtract the current liabilities from it. Here's the step-by-step solution:

Calculate the total current liabilities using the current ratio:

Current Ratio = Current Assets / Current Liabilities

2 = $80,000 / Current Liabilities

Current Liabilities = $80,000 / 2

Current Liabilities = $40,000

Calculate the total liabilities using the debt/equity ratio:

Debt/Equity Ratio = Total Liabilities / Owner Equity

1.0 = Total Liabilities / $100,000

Total Liabilities = $100,000 * 1.0

Total Liabilities = $100,000

Subtract the current liabilities from the total liabilities to get the noncurrent liabilities:

Noncurrent Liabilities = Total Liabilities - Current Liabilities

Noncurrent Liabilities = $100,000 - $40,000

Noncurrent Liabilities = $60,000

Therefore, the farmer's noncurrent liabilities are $60,000. so the answer is B.

The number of months that it will take for Wesley to get to the same weight as Jim, given their respective weights, is 6 months

Assuming the number of months is denoted by x, the equation to find Wesley's weight in a given month would be:

= Wesley's current weight + ( 7 x number of months)
= 132 +  7x

This means that Jim's weight would then be:
= 150 + 4 x

This means that the month where both of them will have the same weight would be:

132 + 7x = 150 + 4x

7x - 4x = 150 - 132

3x = 18

x = 18 / 3

x = 6 months

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