y³√45x⁷y⁵ in its simplest form is 3√5y⁵x³√x√y
What is Expression?An expression is combination of variables, numbers and operators.
The given expression is y³√45x⁷y⁵
y³√9×5 x⁷y⁵
In the given expression x and y are the variables.
=y³3√5x³.√x. y²√y.
=y⁵.3√5x³√y√x
=3√5y⁵x³√x√y
Hence,y³√45x⁷y⁵ in its simplest form is 3√5y⁵x³√x√y
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find x when y is 90 rule y=12x + 54
Answer: x= 3
Step-by-step explanation:
Answer:
x=3
Step-by-step explanation:
So the equation is 90=12x+54. You get x by itself. To do that you subtract 54 from 90. You get 36. Then you divide.
when running a half marathon (13.1 miles), it took noah 8 minutes to run from mile marker 1 to mile marker 2, and 19 minutes to run from mile marker 2 to mile marker 4. how long did it take noah to run from mile marker 1 to mile marker 4?
Answer:
27
Step-by-step explanation:
Solve for problem 13! Please! The answer could be 58,11, or 15. If u get sum different let me know!
Answer:
15
Step-by-step explanation:
Volume of a cylinder = area of the base x height.
v = [(pi)(r)^2] x height
188.4 = [(3.14)(2)(2)] x h
188.4 = 12.56h
h = 15
Please let me know if you have questions
The point (-3, 1) is onlthe terminal side of angle O, in standard position. What are
the values of sine, cosine, and tangent of O? Make sure to show all work.
Answer:
cos(θ) = -3/√10
sin(θ) = 1/√10
tan(θ) = -1/3
Step-by-step explanation:
When we have a point (x, y), the angle generated between the positive x-axis and a ray that connects the origin and the point, is defined by:
cos(θ) = x/(√(x^2 + y^2))
sin(θ) = y/(√(x^2 + y^2))
tan(θ) = y/x
Now we have the point (-3, 1), then we have:
x = -3
y = 1
√(x^2 + y^2) = √((-3)^2 + 1^2) = √10
Then we just need to replace these values in the given formulas:
cos(θ) = x/(√(x^2 + y^2)) = -3/√10
sin(θ) = y/(√(x^2 + y^2)) = 1/√10
tan(θ) = y/x = 1/-3 = -1/3
SOMEONE PLEASE HELP ANSWER CORRECTLY !!!!! WILL MARK BRIANLIEST !!! HELPPPPPP MEEEEEEE !!!!!
Answer:
(-2,-3)
Step-by-step explanation:
A=(8,-5)
M=(3,-4)
The difference between them is that m is 5 to the left and 1 up. We need to do the same thing to find B.
B=(-2,-3)
Which of the following describes a square root of 41 ?
A Between 20 and 21
B Between 40 and 42
C Between 6 and 7
D Between 5 and 6
Answer
C
Step-by-step explanation:
What is the simplified form of the following expression? 7 (RootIndex 3 StartRoot 2 x EndRoot) minus 3 (RootIndex 3 StartRoot 16 x EndRoot) minus 3 (RootIndex 3 StartRoot 8 x EndRoot).
The simplified form of the given expression \(7\sqrt[3]{2x}-3\sqrt[3]{16x} -3\sqrt[3]{8x}\) is \(\sqrt[3]{2x} -6\sqrt[3]{x}\).
The given expression is,
\(7\sqrt[3]{2x}-3\sqrt[3]{16x} -3\sqrt[3]{8x}\)
It is required to solve the given expression.
How to simplify the given expression?Write all the terms in the form of power of primes and then take the cube root of that term.
Simplify the given expression as,
\(7\sqrt[3]{2x}-3\sqrt[3]{16x} -3\sqrt[3]{8x}=7\sqrt[3]{2x}-3\sqrt[3]{2^4x} -3\sqrt[3]{2^3x}\\ =7\sqrt[3]{2x}-6\sqrt[3]{2x} -6\sqrt[3]{x}\\ =\sqrt[3]{2x} -6\sqrt[3]{x}\)
Therefore, the simplified form of the given expression \(7\sqrt[3]{2x}-3\sqrt[3]{16x} -3\sqrt[3]{8x}\) is \(\sqrt[3]{2x} -6\sqrt[3]{x}\).
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Answer:
C
Step-by-step explanation:
apparenlty
the stony brook ams major has also been ranked for several years as one of the top five u.s. undergraduate programs in applied mathematics by college factual, as cited in usa today. the 2020 ranking is:
The Stony Brook University has been ranked as the third best university to pursue a degree in applied mathematic among all the other public and private universities.
Stony Brook University—SUNY is placed #77 in the Best Colleges rating for 2022–2023's National Universities category.
The tuition fees is $10,556 and $28,476 for in-state and out-of-state respectively. The Stony Brook University comes under the state University of New York along with the other 64 universities.
The Stony Brook AMS major has reportedly been listed by College Factual as one of the top five undergraduate applied mathematics degrees in the US for a number of years, according to USA Today. The top five schools for 2020 are CalTech, Stanford, Harvard, Brown, and Stony Brook.
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Given line is parrel to M
Prove 1 is supplementary to 2
S1: m || n
S2: m∠2 ≅ m ∠3
R3: Corresponding angles postulate
R5: Linear pair angles are also supplementary angles
S7: m∠1 + m∠2 =180°
What is linear pair?
An angle pair that is linear is produced when two lines intersect at a single point. The terms "linear" and "rectangular" are used to describe angles that follow the intersection of two lines in a straight line. Total angles of a linear pair are always equal to 180°.
Given that line m and line n are parallel to each other.
Statement 1: m || n
Reason 1: Given
Corresponding angles postulate: When a transversal divides two parallel lines, the resulting angles are congruent.
Statement 2: m∠2 ≅ m ∠3
R2: Corresponding angles postulate
S3: m∠2 ≅ m ∠3
R3: Corresponding angles postulate
Statement 5: ∠1 is supplementary to ∠2.
Reason 5: The linear pair angles are also supplementary angles.
Statement 7: m∠1 + m∠2 = 180°
Reason 7: Substitution property of equality
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show work / explain it
Answer:inequality form x ≤ -1
for 3x + 9 ≤ 6
Step-by-step explanation:isolate the variable by dividing eash side by factors that dont contain the variable
Answer:
Answer Varies
Step-by-step explanation:
For the 1st equation, there are a lot of numbers that could fit x, such as any negative number, such as -1,-2,-3, etc. For the 2nd equation, 9 and below would work. Please correct me if I am wrong because everybody makes mistakes.
Could someone please help me with this?
A regular child admission ticket to the San Diego Zoo is $52. If you have a special pass, you can get a 20% discount on the original ticket price. What is the discounted amount of the ticket when you use the discount?
Joan's Nursery specializes in custom-designed landscaping for residential areas. The estimated labor cost associated with a particular landscaping proposal is based on the number of plantings of trees, shrubs, and so on to be used for the project. For cost-estimating purposes, managers use two hours of labor time for the planting of a medium-sized tree. Actual times from a sample of 10 plantings during the past month follow (times in hours). 1.6 1.4 2.7 2.3 2.5 2.3 2.6 3.0 1.3 2.3 With a 0.05 level of significance, test to see whether the mean tree-planting time differs from two hours. (a) State the null and alternative hypotheses. H0: ???? = 2 Ha: ???? ≠ 2 H0: ???? < 2 Ha: ???? ≥ 2 H0: ???? ≤ 2 Ha: ???? > 2 H0: ???? ≥ 2 Ha: ???? < 2 H0: ???? > 2 Ha: ???? ≤ 2 (b) Compute the sample mean. (c) Compute the sample standard deviation. (Round your answer to three decimal places.) (d) What is the test statistic? (Round your answer to three decimal places.) What is the p-value? (Round your answer to four decimal places.) p-value = (e) What is your conclusion? Reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes.Do not reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes. Do not reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes.Reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes.
The null hypothesis for the sample data set is given by H₀ : μ = 2 and the alternate hypothesis for the data is H₁ : μ > 2 .
a)H₀ : μ = 2
H₁ : μ > 2
We cannot reject the null hypothesis and conclude that no significant evidence exists to confirm that the mean tree-planting time differs from two hours.
Given :
X = 23.71,17.79, 29.87,18.78,28.76
b)Sample mean, x = Σx / n = 22/10 = 2.2
c) Standard deviation, s = 0.516
H0 : μ = 2
H1 : μ > 2
Test statistic :
(x - μ) ÷ (s/√(n))
n = 10
d) Test statistic :
=(2.2 - 2) ÷ (0.516/√(10))
=0.2 / 0.1631735
Test statistic = 1.23
Using the P-value from T-score we get the degrees of freedom:
df
= n - 1
= 10 - 1
= 9
P-value (1.23, 9) = 0.1249
e) Since, P-value > α ; We fail to reject the null and conclude that no significant evidence exists to support that mean tree-planting time differs from two.
A hypothesis is thetheory put up to explain a phenomenon. If a hypothesis cannot be tested by the scientific method, it cannot be referred to as a scientific hypothesis.
Scientific theories frequently start with historical observations that can't be adequately explained by the body of knowledge at this time. A hypothesis is a tested assertion regarding the relationship between two or more variables in the scientific area or a theory put out to explain an observed phenomena.
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Name a 3 digit number divisible by 4,5,9
9514 1404 393
Answer:
180
Step-by-step explanation:
The smallest such number is 4·5·9 = 180. Any multiple of 180 will be divisible by 4, 5, and 9.
 evaluate each of the given expression if P = - 6 and q = 5
5p-q=
5pq=
Answer:
5p-q = 5. (-6) - 5 = -30 - 5 = -35
5pq= 5. (-6) . 5 = -30 . 5 = -150
Step-by-step explanation:
1. Suppose that the rats on the campus of Hypothetical U are found to be carriers of bubonic plague. Eradicating the rats has an estimated cost of $1,000,000 and is expected to reduce the probability a given student dies of the plague from 1/3,000 to zero. Suppose that there are 30,000 students on campus. Suppose further that the administration refuses to eradicate the rats due to the cost. From this information, we can estimate that the administration’s willingness to pay to save a student statistical life is no more than:
a) $50,000
b) $1,000,000
c) $100,000
d) $33,333
The administration's willingness to pay to save a student's statistics life is no more than option c) $100,000.
To estimate the administration's willingness to pay to save a student's statistical life, we need to calculate the cost per statistical life saved. Currently, the probability of a student dying from the plague is 1/3,000. If the rats are eradicated, this probability is reduced to zero. The cost of eradicating the rats is $1,000,000. To calculate the cost per statistical life saved, we divide the cost by the number of statistical lives saved.
The number of statistical lives saved is the product of the number of students on campus (30,000) and the reduction in probability (1/3,000).
Cost per statistical life saved = $1,000,000 / (30,000 * (1/3,000))
= $1,000,000 / (30,000 * 1/3,000)
= $1,000,000 / 10
= $100,000
Therefore, the correct answer is option c) $100,000.
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onsider the system Ax =b, where A = 1 4 3 1 -1
3 9 3 0 9
2 6 2 4 -2
1 3 1 2 -1 b1
b2
B= b3 b4 find all possible values of b so that rank(a) = rank[a| b]. (b) find all possible values of b so that the system ax = b is inconsistent.
The RREF of [a| b] obtained above does not have such a row, so the system is consistent for all values of b.
To find all possible values of b such that rank(a) = rank([a| b]), we need to consider the augmented matrix [a| b] and perform row operations to obtain its reduced row echelon form (RREF). If the RREF has the same number of nonzero rows as the RREF of a, then rank(a) = rank([a| b]).
Performing row operations on [a| b] gives:
1 4 3 1 -1 | b1
3 9 3 0 9 | b2
2 6 2 4 -2 | b3
1 3 1 2 -1 | b4
R2 - 3R1 -> R2:
1 4 3 1 -1 | b1
0 -3 -6 -3 12 | b2 - 3b1
2 6 2 4 -2 | b3
1 3 1 2 -1 | b4
R3 - 2R1 -> R3 and R4 - R1 -> R4:
1 4 3 1 -1 | b1
0 -3 -6 -3 12 | b2 - 3b1
0 -2 -4 2 0 | b3 - 2b1
0 -1 -2 1 0 | b4 - b1
R2/(-3) -> R2 and R3/(-2) -> R3 and R4/(-1) -> R4:
1 4 3 1 -1 | b1
0 1 2 1 -4 | (3b1 - b2)/3
0 1 2 -1 0 | (2b1 - b3)/2
0 1 2 -1 0 | b4 - b1
R3 - R2 -> R3 and R4 - R2 -> R4:
1 4 3 1 -1 | b1
0 1 2 1 -4 | (3b1 - b2)/3
0 0 0 -2 4 | (2b1 - b3)/2 - (3b1 - b2)/3
0 0 0 -2 4 | b4 - b1 - (3b1 - b2)/3
R3/(-2) -> R3 and R4/(-2) -> R4:
1 4 3 1 -1 | b1
0 1 2 1 -4 | (3b1 - b2)/3
0 0 0 1 -2 | (b2 - 2b1 + b3)/3
0 0 0 1 -2 | (b1 - b4 + (3b1 - b2)/3)/2
R2 - 2R4 -> R2 and R1 - 3R4 -> R1:
1 4 3 0 1 | (5b1 - b2 + 2b4)/6
0 1 2 0 -8/3 | (-4b1 + b2 + 2b4)/3
0 0 0 1 -2 | (b2 - 2b1 + b3)/3
0 0 0 0 0 | (5b1 - b2 - 3b4)/6
Since the last row of the RREF has all zeros except for the last entry, we can conclude that rank(a) = rank([a| b]) if and only if 5b1 - b2 - 3b4 = 0. Therefore, all possible values of b are given by b4 = (5b1 - b2)/3.
To find all possible values of b such that the system ax = b is inconsistent, we need to check if the RREF of [a| b] has a row of the form [0 0 ... 0 | c] with c ≠ 0. If such a row exists, then the system is inconsistent for all values of b corresponding to that row.
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A punch recipe uses
2 1/2cups of sherbet to make 24 cups of punch.
How many cups of sherbet will be needed to make 12 cups of punch?
Answer:
1 1/4 cups
Step-by-step explanation:
Make a proportion; 24/2.5 = 12/xDivide 2.5 by two, which is 1.25Answer:
1 1/4 cups of punch.
Step-by-step explanation:
Since 2 1/2 cups of sherbet are needed to make 24 cups, and we need to make 12 cups of punch, it's basically 24 divided by 2. So we need to divide 2 1/2 by 2, which would be 1 1/4 cups.
Evaluate the expression 2(8 - 4)^2 - 10 divide 2.
A) 11
B) 27
C) 56
D) 59
(9th-grade Algebra 1 )
PLSSSSS HELP MEEEEEE DUE TODAY!!!!!
Answer:
4/5 or .8
Step-by-step explanation:
Triangle ABC has angle measures as shown below. Using the information in the diagram, find the value of x. Be sure to write your answer down on a piece of paper - you will need it for Question 4.Find x and measure of Angle C
Solution:
Given the triangle ABC;
The sum of interior angles of a triangle is 180 degrees. Thus;
\(\angle A+\operatorname{\angle}B+\operatorname{\angle}C=180^o\)We have;
\(\begin{gathered} 35^o+52^o+3(x+2)^o=180^o \\ \\ 87^o+3x^+6^o=180^o \\ \\ 3x=180^o-93^o \\ \\ 3x=87^o \\ \\ x=\frac{87}{3} \\ \\ x=29 \end{gathered}\)Thus, the measure of angle C is;
\(\begin{gathered} m\angle C=3(x+2)^o \\ \\ m\angle C=3(29+2)^o \\ \\ m\angle C=3(31)^o \\ \\ m\angle C=93^o \end{gathered}\)if the allowable tensile and compressive stress for the beam are (σallow)t = 2.1 ksi and (σallow)c = 3.6 ksi , respectively
The minimum cross-sectional area is zero. As a result, the beam can support no load.
Beams are structural members that are used to bear loads and to transmit these loads to the supporting structure. They are characterized by their length and cross-section.
They're designed to bend and resist bending when loaded by gravity, snow, wind, and other loads. Beams are generally horizontal, but they may also be slanted or curved.
The allowable tensile stress (σallow)t is given as 2.1 ksi, and the allowable compressive stress (σallow)c is given as 3.6 ksi. Thus, the allowable axial load on the beam may be computed using the following equations:
For tension,Allowable tensile stress :σt= 2.1 ksi
Cross-sectional area of beam : A P = σt × A
Rearranging the above equation, A = P/ σt
:= P/2.1 ...(1)
For compression,Allowable compressive stress : σc= 3.6
ksi Cross-sectional area of beam :A P = σc × A
Rearranging the above equation, A = P/ σc
= P/3.6 ...(2)
In Equations 1 and 2, P is the allowable axial load on the beam. The smallest of these two equations determines the allowable axial load on the beam because it governs the beam's strength.
The minimum value for A can be found by combining the equations.
We can equate the two equations to obtain:
P/2.1 = P/3.6
Rearranging the equation, we get
3.6P = 2.1P
P = 0
Therefore, the minimum value for A can be obtained by substituting P = 0 into either equation. Since the load is zero, the beam is weightless and the smallest cross-sectional area that can support no load is zero.
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draw the straight line y=2x-3
Answer:
Look at the explanation.
Step-by-step explanation:
In 2001, 229 million cartons of apples were produced in the U.S. If 40% of the apples were eaten as fresh fruit, how many apples were used for fruit juice and other things?
26,862 divided by 407
Answer:
66
Step-by-step explanation:
it is 66
Consider a case where 400 fish are tagged and released during a first outing. During a second outing in the same area, 400 fish are again caught and released, of which half are already tagged. Estimate N, the total number of fish in the entire sampling area.
The total number of fish in the entire sampling area is 600
Sampling:
The process of selecting the group that you will actually collect data from in your research is called sampling.
Given,
Consider a case where 400 fish are tagged and released during a first outing. During a second outing in the same area, 400 fish are again caught and released, of which half are already tagged.
Here we need to find the total number of fish in the entire sampling area.
Let us consider N be the number of fish in the entire sampling area.
While looking through the given question,
We have identified the following,
Number of fish tagged = 400
Next time number of fish caught = 400
We know the half of them are tagged, so the untagged fishes are
=> 400/2
=> 200
Therefore, the total number of fishes is
=> 400 + 200
=> 600
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Suppose you have an outdoor vegetable garden with dimensions 2 mx2 m. A storm lasting 1 hr delivers 0.8 inches of rain. a. What is the storm rainfall flux? Express your answer using each of the following units: m 2
hr
kgliquid water m 2
hr
lb liquid water m 2
hr
liters liquid water m 2
hr
gallons liquid water b. How much liquid water fell on your garden? Express your answer using each of the following units:
The storm rainfall flux is 0.00127 m2/hr, 1.27 kg liquid water/m2hr, 2.8 lb liquid water/m2hr, 1.27 liters liquid water/m2hr, and 0.335 gallons liquid water/m2hr. The amount of liquid water fell on the garden is 80.6 L, 21.3 gallons.
Dimensions of outdoor vegetable garden = 2 m × 2 m
Storm rainfall = 0.8 inches of rain
Time of storm = 1 hr(
a) The rainfall flux is the amount of rainfall per unit area and unit time. It is given as:
Rainfall flux = (Amount of rainfall) / (Area × Time)
Given the area of the garden is 2 m × 2 m, and the time is 1 hr, the rainfall flux is:
Rainfall flux = (0.8 inches of rain) / (2 m × 2 m × 1 hr)
Converting inches to meters, we get:
1 inch = 0.0254 m
Therefore,
Rainfall flux = (0.8 × 0.0254 m) / (2 m × 2 m × 1 hr) = 0.00127 m/hr
Converting the rainfall flux to other units:
In kg/hr:
1 kg of water = 1000 g of water
Density of water = 1000 kg/m3
So, 1 m3 of water = 1000 kg of water
So, 1 m2 of water of depth 1 m = 1000 kg of water
Therefore, 1 m2 of water of depth 1 mm = 1 kg of water
Therefore, the rainfall flux in kg/hr = (0.00127 m/hr) × (1000 kg/m3) = 1.27 kg/m2hr
In lbs/hr:
1 lb of water = 453.592 g of water
So, the rainfall flux in lbs/hr = (0.00127 m/hr) × (1000 kg/m3) × (2.20462 lb/kg) = 2.8 lbs/m2hr
In liters/hr:
1 m3 of water = 1000 L of water
So, 1 m2 of water of depth 1 mm = 1 L of water
Therefore, the rainfall flux in L/hr = (0.00127 m/hr) × (1000 L/m3) = 1.27 L/m2hr
In gallons/hr:
1 gallon = 3.78541 L
So, the rainfall flux in gallons/hr = (0.00127 m/hr) × (1000 L/m3) × (1 gallon/3.78541 L) = 0.335 gallons/m2hr
(b) To calculate the amount of water that fell on the garden, we need to calculate the volume of water.
Volume = Area × Depth.
The area of the garden is 2 m × 2 m.
We need to convert the rainfall amount to meters.
1 inch = 0.0254 m
Therefore, 0.8 inches of rain = 0.8 × 0.0254 m = 0.02032 m
Volume of water = Area × Depth = (2 m × 2 m) × 0.02032 m = 0.0806 m3
Converting the volume to other units:
In liters:
1 m3 of water = 1000 L of water
Therefore, the volume of water in liters = 0.0806 m3 × 1000 L/m3 = 80.6 L
In gallons:
1 gallon = 3.78541 L
Therefore, the volume of water in gallons = 80.6 L / 3.78541 L/gallon = 21.3 gallons.
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let a and b be integers. prove that if ab = 4, then (a – b)3 – 9(a – b) = 0.
Let \(\(a\)\) and \(\(b\)\) be integers such that \(\(ab = 4\)\). We want to prove that \(\((a - b)^3 - 9(a - b) = 0\).\)
Starting with the left side of the equation, we have:
\(\((a - b)^3 - 9(a - b)\)\)
Using the identity \(\((x - y)^3 = x^3 - 3x^2y + 3xy^2 - y^3\)\), we can expand the cube of the binomial \((a - b)\):
\(\(a^3 - 3a^2b + 3ab^2 - b^3 - 9(a - b)\)\)
Rearranging the terms, we have:
\(\(a^3 - b^3 - 3a^2b + 3ab^2 - 9a + 9b\)\)
Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:
\(\(a^3 - b^3 - 3a^2(4) + 3a(4^2) - 9a + 9b\)\)
Simplifying further, we get:
\(\(a^3 - b^3 - 12a^2 + 48a - 9a + 9b\)\)
Now, notice that \(\(a^3 - b^3\)\) can be factored as \(\((a - b)(a^2 + ab + b^2)\):\)
\(\((a - b)(a^2 + ab + b^2) - 12a^2 + 48a - 9a + 9b\)\)
Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:
\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 48a - 9a + 9b\)\)
Simplifying further, we get:
\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\)
Now, we can observe that \(\(a^2 + 4 + b^2\)\) is always greater than or equal to \(\(0\)\) since it involves the sum of squares, which is non-negative.
Therefore, \(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\) will be equal to \(\(0\)\) if and only if \(\(a - b = 0\)\) since the expression \(\((a - b)(a^2 + 4 + b^2)\)\) will be equal to \(\(0\)\) only when \(\(a - b = 0\).\)
Hence, we have proved that if \(\(ab = 4\)\), then \(\((a - b)^3 - 9(a - b) = 0\).\)
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Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given point. x^2 + y^2 = 25, (4, 3) The point is on the curve because when is substituted for x and is substituted for y, the resulting statement is = 25, which is a statement. (Simplify your answers.)
The equation of the tangent would be y = -4x/3 - 25/3 and the equation of the normal would be y = 3x/4.
What is a parabola?
A parabola is a plane curve that is mirror-symmetrical and roughly U-shaped in mathematics. It fits several seemingly disparate mathematical descriptions, all of which can be shown to define the same curves. A point and a line are two ways to describe a parabola.
The given equation is x² + y² = 25 ; (4, 3)
Now when we put x = 4 and y = 3
then LHS = RHS.
Now find the slope:
2x + yy' = 0
⇒ y' = -x/y
Now at (4, 3) slope would be y' = -4/3.
The equation of the tangent would be
y - y1 = m(x - x1)
y - 3 = (-4/3)(x-4)
3y - 9 = -4x + 16
4x + 3y = 25
y = -4x/3 - 25/3
Now equation of the normal is:
y - y1 = (-1/m)(x - x1)
y - 3 = 3/4(x - 4)
y = 3x/4
Hence, the equation of the tangent would be y = -4x/3 - 25/3 and the equation of the normal would be y = 3x/4.
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Please ASAP :( can anyone help me with these questions 15-25 im really stressed out, i have to do a wgeo project after this, hopefully anyone can help me at least with my algebra questions
Answer:
Here are your answers! :)
Step-by-step explanation:
15) -21
16) -11
17) 26
18) 23
19) -32
20) -20
21) 65
22) 420
23) 16
24) -13
25) 20
(I hope this helps!!)
A number line going from 0 to 1. the line is shaded from 0 to startfraction 7 over 12 endfraction. randy walks his dog each morning. he walks startfraction 7 over 12 endfraction of a mile in 7 minutes. how many miles does he walk in 1 minute? startfraction 7 over 12 endfraction divided by 7 =
Answer:
1/12 mile
Step-by-step explanation:
He walks 7/12 mile in 7 minutes.
In 1 minute, he walks 1/7 of the distance.
1/7 of 7/12 mile = 1/12 mile