I need help with the solution

The choices copper magnesium chloride calcium is cellular repair.

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The specific heat capacity and molar heat capacity of the metal cannot be determined due to missing values.

However, the values can be obtained using the formula below:

The specific heat capacity and molar heat capacity of the metal are calculated using the formula below:

ΔH₁ + ΔHcalorimeter + ΔH₂ = 0

where:

ΔH₁ is the heat change of the water = m₁Cwater(Tfinal - T1)

ΔHcalorimeter is heat change of the = Ccalorimeter(Tfinal - T1)

ΔH₂  is the heat change of the metal = m₂c₂(Tfinal - T2)

ΔH₁ = 99.45 * 4.184 * (23.9 - 19.5)

ΔH₁ = 1830.83 J

ΔHcalorimeter = Ccalorimeter * 23.9 - 19.5

The heat capacity of the calorimeter is not given, therefor the specific heat capacity and molar heat capacity of the metal cannot be determined.

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At 25°C, combine 47.0 mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL of water (d = 1.00 g/mL) to create an antifreeze solution. The antifreeze solution's molarity is 0.0086 M if its density is 1.07 g/mL.

Antifreeze is an additive that reduces a water-based liquid's freezing point. To achieve freezing-point depression for cold conditions, an antifreeze combination is utilized. Common antifreezes also raise the liquid's boiling point, enabling a rise in coolant temperature. However, every typical antifreeze addition also has a lower heat capacity than water, which makes it less effective as a coolant when combined with water.

The combination of a solution's freezing and boiling temperatures depends on the amount of dissolved components present. Therefore, salts cause aqueous solutions' melting points to decrease. Although salts are widely used for de-icing, salt solutions should not be utilized in cooling systems as they cause metal corrosion. Because they typically have melting values that are lower than those of water, low molecular weight organic substances can be used as antifreeze. Alcoholic organic compound solutions, in particular, are useful. Since antifreezes were first made commercially available in the 1920s, they have all been composed primarily of alcohols such methanol, ethanol, ethylene glycol, and others.

Molarity = \(\frac{mole}{volume}\)

To calculate the moles of ethylene glycol.

The mass of ethylene glycol is 47.0 mL × 1.11 g/mL = 52.17 g.

Since molar mass of ethylene glycol is 62.07 g/mol, the moles of ethylene glycol is:

\(\frac{52.17}{62.07}\) = 0.84 mol

To calculate the total volume of the antifreeze solution. We know that the volumes of ethylene glycol and H₂O are 47.0 mL and 50.0 mL, respectively.

Therefore, the total volume of the antifreeze solution is 47.0 mL + 50.0 mL = 97.0 mL.

Finally, the molarity of the antifreeze solution can be calculated using the formula

Molarity = \(\frac{mole}{volume}\)

Therefore, the molarity of the antifreeze solution is:

\(\frac{0.84}{97.0}\) = 0.0086 M

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In a molecule or covalent bonding, elements having Octet electrons to obtain the stability with eight electrons.

One element that does not follow the octet rule is hydrogen. For stability only require stable electrons.

A molecule can present covalent bond but can be chemical.

Covalent bonding is a type of chemical bonding that occurs when two or more atoms share electrons in order to form a strong bond between them. This type of bond is formed when atoms share electrons in a way that gives each atom a full outer shell of electrons, known as the octet rule. This means that all atoms in the bond must have a total of eight electrons in their outermost shell. The atoms involved in a covalent bond form a molecule, which is held together by the shared electrons.

The octet rule is a guideline that states that atoms will bond in a way that allows them to have a full outer shell of electrons. This means that they must share electrons in order to reach a total of eight electrons in their outermost shell. The sharing of electrons creates a strong bond between the atoms that form a molecule. The sharing of electrons also results in the creation of a covalent bond.

However, not all elements follow the octet rule. For example, hydrogen only requires two electrons to reach a stable state, so it does not need to share electrons in order to reach the octet rule. Therefore, a hydrogen molecule will not have a covalent bond.

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Answer:

\(-675.053\ \text{kJ/mol}\)

Explanation:

\(\Delta G\) = Gibbs free energy = \(-775.41\ \text{kJ/mol}\)

\(\Delta S\) = Change in entropy = \(817.91\ \text{J/mol K}=0.81791\ \text{kJ/mol K}\)

\(T\) = Temperature = \(135.4^{\circ}\text{C}=408.55\ \text{K}\)

\(\Delta H\) = Change in enthalpy

Gibbs free energy is given by

\(\Delta G=\Delta H-T\Delta S\\\Rightarrow \Delta H=\Delta G+T\Delta S\\\Rightarrow \Delta H=-775.41+408.55\times 0.81791\\\Rightarrow \Delta H=-441.253\ \text{kJ/mol}\)

\(T=12.7^{\circ}\text{C}=285.85\ \text{K}\)

\(\Delta G=\Delta H-T\Delta S\\\Rightarrow \Delta G=-441.253-285.85\times 0.81791\\\Rightarrow \Delta G=-675.053\ \text{kJ/mol}\)

The required Gibbs free energy is \(-675.053\ \text{kJ/mol}\).

Answer:

when they have eight valence electrons.

Explanation:

When atoms do not have a full valence shell, the atoms are more likely to react with other and vice versa.

Answer:

When they have a full shell of electrons

Explanation:

and or eight valence electrons

Answer:

I believe that in H-C≡N, Nitrogen has 4 bonding electrons and 2 non-bonding electrons.

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Explanation:

To determine the maximum \(Fe_2(SO_4)_3\) produced, we find the limiting reactant (Fe), calculate theoretical yield (0.3383 mol), and obtain a percentage yield of 47.56%.

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Answer:

\(m_{Cd(OH)_2}=36.6 gCd(OH)_2\)

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

\(n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2} =0.75molCd(OH)_2\)

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

\(m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2\)

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The mass of  Cd(OH)₂ that would be formed is 36.6 g

From the question,

We are to determine the mass of Cd(OH)₂ that would be formed

The given balanced chemical equation for the reaction is  

2NaOH(aq) + Cd(NO₃)₂(aq) → Cd(OH)₂ (s) + 2NaNO₃(aq)

This means

2 moles of NaOH reacts with 1 mole of Cd(NO₃)₂ to produce 1 mole of Cd(OH)₂ and 2 moles of NaNO₃

Now, we will determine the number of moles of each reactant present

Mass = 20.0 g

Molar mass = 39.997 g/mol

From the formula

\(Number\ of\ moles = \frac{Mass}{Molar\ mass}\)

Number of moles of NaOH present = \(\frac{20.0}{39.997 }\)

Number of moles of NaOH present = 0.50 mole

Volume = 0.750 L

Concentration = 1.00 M

From the formula

Number of moles = Concentration × Volume

∴ Number of moles of Cd(NO₃)₂ present = 1.00 × 0.750

Number of moles of Cd(NO₃)₂ present = 0.750 mole

Since,

2 moles of NaOH reacts with 1 mole of Cd(NO₃)₂

Then,

0.5 mole of NaOH will react with 0.25 mole of Cd(NO₃)₂

∴ The number of moles of Cd(NO₃)₂ that reacted is 0.25 mole

Now,

From the balanced chemical reaction

2 moles of NaOH reacts with 1 mole of Cd(NO₃)₂ to produce 1 mole of Cd(OH)₂

Then,

0.5 mole of NaOH will react with 0.25 mole of Cd(NO₃)₂ to produce 0.25 mole of Cd(OH)₂

∴ Number of moles of Cd(OH)₂ formed is 0.25 mole

Now, for the mass of Cd(OH)₂ that would be formed

From the formula

Mass = Number of moles × Molar mass

Molar mass of Cd(OH)₂ = 146.43 g/mol

∴Mass of Cd(OH)₂ formed = 0.25 × 146.43

Mass of Cd(OH)₂ formed = 36.6075 g

Mass of Cd(OH)₂ formed≅ 36.6 g

Hence, the mass of  Cd(OH)₂ that would be formed is 36.6 g

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Answer:

Ernest Rutherford is known in his work of pioneering studies of radioactivity and the specifics in the atom. He discovered that there are two types of radiation, which are alpha and beta particles, coming from uranium. He found that the atom consists mostly of empty space, with its mass concentrated in a central positively charged nucleus.

Explanation:

hope this helps

Answer:

Divergent boundary plate

Explanation:

I hope this helps but this question has its answer at the top of google when you search it

Question:

A mid-ocean ridge occurs at what boundary?

1. Convergent Boundary Plate

2. Divergent  Boundary Plate

3. Transform Boundary Plate

Answer:

2. Divergent Boundary Plate

Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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Answer: the c thingy is where you be like burgundy sauce then be like racial slair is what it mean's so the name thingy

Explanation:

Given that the radius of a silver atom is 145 pm, it would take \(7.97 \times 10^{6}\) silver atoms laid side by side to span a distance of 2.31 mm.

The radius of a silver atom is 145 pm. Then, the diameter (twice the radius) is:

\(d = 2 \times 145 pm = 290 pm\)

We will convert 290 pm to millimeters. We will use the conversion factors:

\(290 pm \times \frac{1m}{10^{12}pm } \times \frac{10^{3}mm }{1m} = 2.90 \times 10^{-7} mm\)

If the diameter of 1 silver atom is 2.90 × 10⁻⁷ mm, the number of silver atoms required to span a distance of 2.31 mm is:

\(2.31 mm \times \frac{1Ag\ atom}{2.90 \times 10^{-7}mm } = 7.97 \times 10^{6} Ag\ atom\)

\(7.97 \times 10^{6}\) silver atoms span a distance of 2.31 mm.

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Answer:

About 7.0 × 10³ J or 7.0 kJ

Explanation:

We want to determine the amount of energy needed to raise the temperature of 67 grams of water from 20°C to 45°C.

We can use the heat equation:

\(\displaystyle q = mC\Delta T\)

Where C is the specific heat of water.

Substitute and evaluate:

\(\displaystyle \begin{aligned} q & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)\left(45^\circ \text{ C}- 20.^\circ\text{ C}\right) \\ \\ & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)(25^\circ \text{ C}) \\ \\ & = 7.0\times 10^3 \text{ J}\end{aligned}\)

Recall that there are 1000 J in a kJ. Hence:

\(\displaystyle \begin{aligned} q & = 7.0\times 10^3 \text{ J} \cdot \frac{1\text{ kJ}}{1000\text{ J}} \\ \\ & = 7.0 \text{ kJ}\end{aligned}\)

In conclusion, it will take about 7.0 × 10³ J or 7.0 kJ of energy to raise the temperature of 67 grams of water from 20 °C to 45 °C.

The pressure inside the tire is approximately 1.970796 newtons per square centimeter (N/cm²) when measured in those units.

To convert the pressure from pounds per square inch (psi) to newtons per square centimeter (N/cm²), we need to use the conversion factors between these units.

First, let's convert pounds to newtons:

1 pound = 0.45359237 kilograms

1 kilogram = 9.80665 newtons

Next, let's convert square inches to square centimeters:

1 square inch = 6.4516 square centimeters

Now, we can perform the conversion:

1 psi = (0.45359237 kg) × (9.80665 N/kg) / (6.4516 cm²)

≈ 0.070307 N/cm²

Therefore, the pressure inside the tire of 28.0 psi is approximately equal to 28.0 × 0.070307 N/cm², which is approximately 1.970796 N/cm².

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Answer:

The climate has been caused by many natural factors including changes in the sun emissions from volcanoes variations in Earth's orbit and levels of carbon dioxide. Global climate change has typically occured very slowly over thousands or millions of years .The three causes of the Earth's climate are

these are the causes of the Earth's climate.

Climate is a average weather in a given area for a long period of time is called a climate

maybe this might help ur question

Explanation: The concentration of a solution helps us to determine the collision speed between particles in a molecule or compound. Knowing the concentrations of components in solutions can help determine the health of the world.

An element's electronegativity determines whether it is ionic or non-ionic. Fluorine has the most electronegativity while iodine has the lowest, which means that the Cs I ionic bond's power of attraction is at its lowest, allowing for the largest possible distance between their molecules.

The attracting and repellent forces that develop between the molecules of a substance are referred to as intermolecular forces (IMF), which is sometimes shortened. These forces act as a bridge between the individual molecules of a substance. Intermolecular forces are primarily responsible for the physical and chemical properties of matter.

The following are the four main intermolecular forces: Van der Waals dipole-dipole interactions < Van der Waals dispersion forces <Ionic bonds <Hydrogen bonds .

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Answer:

0.834 M.

Explanation:

Hello!

In this case, since this is a first-order reaction, we can infer that the half-life and the rate constant are related via:

\(t_{1/2}=\frac{ln(2)}{k}\)

Thus, we are able to compute the rate constant:

\(k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{32s}\\\\k=0.0217s^{-1}\)

Next, since we have the resulting concentration of the reactant and we need the initial one, we proceed as shown below with the rate law:

\(A=A_0exp(-kt)\\\\A_0=\frac{A}{exp(-kt)} \\\\A_0=\frac{0.062M}{exp(-0.0217s^{-1}*2.0min*\frac{60s}{1min} )}\\\\A_0=0.834M\)

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The mass of the block in kg is 6.65 kg for a rectangular block of tungsten has a length of 7.90 cm, a width of 2.30 cm, and a height of 1.90 cm as the density of tungsten is 19.28.

Density is the mass of a substance present per unit volume and it is the ratio of mass and the volume of the substance given by gram per centimeter cube.

The mass of tungsten is density multiplied by volume,

                      volume = 7.90 cm × 2.30 cm × 1.90 cm

                        19.28 × 53.53 = 6.65 kg.

Therefore, the density of tungsten is 19.28, and the mass of the block in kg is 6.65 kg for a rectangular block of tungsten has a length of 7.90 cm, a width of 2.30 cm, and a height of 1.90 cm.

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Answer:

The waters' temp increased

Explanation:

The temperature of the water in the swimming pool has increased due to the heat from the Sun. As a result, the particles in the water are moving faster and have a higher kinetic energy than in the morning.

The pressure of oxygen in the vessel after the leak is repaired is 667.8 torr.

To solve this problem, we can use the ideal gas law:

PV = nRT

where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin.

First, let's find the number of moles of oxygen in the vessel before the leak: n = PV/RT = (741 torr)(10.0 L)/(0.082 L atm/mol K)(298 K) = 30.7 mol

Next, we can calculate the new number of moles of oxygen after the leak: n' = n - (mass of gas leaked/molar mass of oxygen) = 30.7 mol - (5.75 g)/(32.00 g/mol) = 28.9 mol

Using ideal gas law again to solve for the new pressure:

P' = n'RT/V = (28.9 mol)(0.082 L atm/mol K)(298 K)/(10.0 L) = 667.8 torr

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Answer:

The reaction rate decreases with a decrease in temperature. Catalysts can lower the activation energy and increase the reaction rate without being consumed in the reaction. Differences in the inherent structures of reactants can lead to differences in reaction rates.

Explanation:

The molecule must possess dipolar bonds, exhibit suitable vibrational frequencies, and be in a form that can be analyzed using IR spectroscopy in order to be studied in an IR spectrum.

To study a molecule in an infrared (IR) spectrum, several criteria need to be considered. Firstly, the molecule should have a dipole moment, meaning it must have a separation of positive and negative charges within the molecule.

This is because IR spectroscopy primarily detects vibrations of covalent bonds, which are associated with changes in dipole moment.Additionally, the molecule should have covalent bonds that can undergo vibrational modes within the range of the instrument. IR spectroscopy typically covers the frequency range of 4000 to 400 cm⁻¹, which corresponds to the energies of molecular vibrations.

The molecule should also be able to be vaporized or dissolved in a suitable solvent to generate a homogeneous sample for analysis. Gaseous or liquid samples are commonly used in IR spectroscopy.

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Answer:

0.67 cm³

Explanation:

We can solve this problem by using the definition of density:

We can rearrange the equation and isolate volume:

As we are given both the mass and the density, we can now calculate the volume:

Answer:

Orbiter

Explanation:

Space shuttles are made out of three main parts: rocket boosters, a fuel tank, and orbiter (the part that resembles an airplane

Answer:The reactions are as follows: a carbon-12 (12C) nucleus captures a hydrogen nucleus (1H, a proton) to form a nucleus of nitrogen-13 (13N); a gamma ray (γ) is emitted in the process. The nitrogen-13 nucleus emits a positive electron (positron, e+) and becomes carbon-13 (13C).