Identify the most and the least acidic compound in each of the following sets. Leave the remaining answer in each set blank. a) p-cyanobenzoic acid: benzoic acid: p-aminobenzoic acid: b) 3-fluoropropanoic acid:
fluoroacetic acid: iodoacetic acid: c) difluoroacetic acid: fluoroacetic acid: trifluoroacetic acid:

An enzyme converts 77 monomers into a linear polymer. In the process, 76 molecules of water are released.

When monomers are joined together to form a polymer, a water molecule is released for the formation of a bond between the monomers.

When another monomer is joined one more water molecule is removed. It means for three molecules of monomer two molecules of water are removed.

Since there are 77 monomers, there will be 76 bonds connecting them in a linear polymer, resulting in 76 water molecules being released.

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Answer:

= 10000000000000 Nanoliters

Explanation:

1.0 x (10^4) L =

10 000 L

10 000L converted into Nanoliters

= 10000000000000 Nanoliters

Hope this helps

The most likely reason for the observation by the student is the combined substances chemically reacted; the correct option is C.

Chemical reactions are reactions that involve changes in the chemical properties of the substance as well as changes in the chemical composition and structure of the substances involved.

There are several types of chemical reactions and they include:

In a precipitation reaction, an insoluble substance is obtained when two solutions are mixed together. The insoluble substance obtained is called a precipitate.

Precipitation reactions are also known as a double replacement or double displacement reactions.

The given reaction by a student who observed a decrease in temperature when two substances were combined and a milky substance formed and sank to the bottom of the flask is an example of a precipitation reaction.

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The emission properties of complexes can be influenced by temperature and the presence of oxygen (O2).

Here are the effects of temperature and O2 on the emission of complexes:

Temperature:

Thermal Deactivation: As temperature increases, the rate of non-radiative processes, such as vibrational relaxation and internal conversion, also increases. These processes compete with the radiative decay pathway, leading to decreased emission intensity and shorter emission lifetimes at higher temperatures.

Temperature-Dependent Emission Spectra: Some complexes exhibit temperature-dependent emission spectra. As the temperature changes, the energy levels involved in the emission process may shift, resulting in changes in the emission wavelength or color. This phenomenon is often observed in luminescent materials and can be utilized for temperature sensing or imaging applications.

Oxygen (O2):

Quenching of Excited State: Oxygen molecules, particularly molecular oxygen (O2), can act as quenchers of the excited state of complexes. When an excited complex encounters O2, an oxidative electron-transfer mechanism can occur, leading to the transfer of an electron from the excited state to O2. This process effectively deactivates the excited state, resulting in decreased emission intensity.

Formation of Excited Oxygen Species: In some cases, the interaction between the complex and O2 can lead to the formation of excited oxygen species, such as singlet oxygen (^1O2). These species can further react with other molecules, causing various chemical transformations and potentially affecting the emission properties of the complex.

The equation for the oxidative quenching of the excited state by O2 can be represented as follows:

[Complex]* + O2 → [Complex] + O2^-

In this reaction, the excited state of the complex ([Complex]*) transfers an electron to O2, resulting in the formation of the reduced complex ([Complex]) and the superoxide ion (O2^-).

In summary, temperature influences the thermal deactivation processes and can affect the emission spectra of complexes. O2 can quench the excited state through oxidative electron transfer, reducing the emission intensity. The interaction between complexes and O2 can have significant implications for the luminescent properties and applications of these complexes.

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A reaction occurs at the cathode is Option b. 2H₂O (l) + 2e⁻ → H₂ (g) + 2OH⁻ (aq)

At the cathode, reduction occurs, which involves the gain of electrons. In this case, water molecules (H₂O) are reduced to produce hydrogen gas (H₂) and hydroxide ions (OH⁻).

The half-reaction at the cathode can be understood as follows:

2H₂O (l) + 2e⁻ → H₂ (g) + 2OH⁻ (aq)

Here, two electrons (2e⁻) are gained by two water molecules, resulting in the formation of hydrogen gas (H₂) and hydroxide ions (OH⁻) in the aqueous solution. Therefore, the correct option for the reaction occurring at the cathode in the given electrolytic cell is 2H₂O (l) + 2e⁻ → H₂ (g) + 2OH⁻ (aq). Therefore, Option b is correct.

The question was incomplete. find the full content below:

A reaction in an electrolytic cell is as follows:

2NaCl(aq) + 2H₂O (1)→ Cl₂ (g) + H₂ (g) + 2NaOH(aq).

Which reaction occurs at the cathode?

a. Cl₂ (g) + 2e → 2Cl(aq)

b. 2H₂O (1) + 2e → H₂ (g) + 2OH(aq)

c. H₂(g) + 2OH(aq) → 2H₂O (1) + 2e¯

d. 2C1 (aq) → Cl2 (g) + 2e7

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Answer:

not enough information need more information to answer it

One mole of each element contains Avogadro's number of atoms, which is 6.022 x 10^23 atoms. Therefore, all three substances have the same number of atoms, which is 6.022 x 10^23 atoms.

The concentration of a solution expressed in moles of solute per 1 l of the solution is called Molarity.

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of a solution is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute

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A 0.150 M Na2SO4 solution is saturated with Ag2SO4. It has a [Ag+] equal to 9.7 × 10–3. The value of Ksp for Ag2SO4 is 1.4 × 10^-5.


The first step to solving this problem is to write the balanced chemical equation for the dissociation of Ag2SO4:
Ag2SO4(s) ⇌ 2Ag+(aq) + SO4 2-(aq)
The Ksp expression for this dissociation is:
Ksp = [Ag+]^2[SO4 2-]
We are given that the solution is saturated with Ag2SO4, which means that the concentration of Ag+ is equal to the solubility of Ag2SO4. Therefore, we can substitute the given [Ag+] value into the Ksp expression:
Ksp = (9.7 × 10^-3)^2 [SO4 2-]
To find the value of Ksp, we need to know the concentration of SO4 2-. This can be found using the stoichiometry of the balanced chemical equation:
1 mole of Ag2SO4 ⇌ 1 mole of SO4 2-
Since Ag2SO4 is a strong electrolyte, it completely dissociates into ions, so the initial concentration of Ag2SO4 is equal to the concentration of Ag+ (0.150 M). Therefore, the concentration of SO4 2- is also 0.150 M.
Substituting this value into the Ksp expression, we get:
Ksp = (9.7 × 10^-3)^2 (0.150) = 1.4 × 10^-5

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The molecular formula of the liquid​ : C₆H₁₂

Given

molar ratio C H = 1.2 : 0.12

0.12 g at STP gave 32 cm³(0.032 L)

Required

The molecular formula

Solution

At STP, 1 mol = 22.4 L, so for 0.032 L :

mol = 0.032 : 22.4

mol = 0.00143

Molar mass (M) of liquid :

M = mass : mol

M = 0.12 g : 0.00143 mol

M = 83.92≈84 g/mol

C : H = 1 : 2

(CH₂)n=84

(12+2.1)n=84

(14)n=84

n=6

(CH₂)₆=C₆H₁₂

Answer:

The large relative distances between particles in a gas means that there is considerable empty space between the particles.

The assumption that particles in a gas are relatively far apart explains gas compressibility.

Compressibility is a measure of how much the volume of matter decreases under pressure.

Energy is released by a gas when it is compressed

Explanation:

The kinetic molecular theory establishes that gases are composed of molecules. These molecules of gas are far apart from each other hence there is a considerable empty space between the gas molecules. As a result of these empty spaces between gas molecules, it is possible to compress a gas.

Compressibility is defined as a measure of how much the volume of matter decreases under pressure. When a gas is compressed, work is done on the gas and energy is evolved hence the gas heats up.

Answer:

It's cheap to make, and its recyclable

Answer:

the air will escape from the jar

Explanation:

Due to its low density air in the jar will be displaced and be replaced by water.

It would take 3905 joules of thermal energy to raise the temperature of 2 kilograms of water by 50 degrees Celsius.  

The temperature of 2 kilograms of water by 50 degrees Celsius, you would need to add enough thermal energy to raise the temperature of the water by 50 degrees Celsius.

The amount of thermal energy required to raise the temperature of a substance by a given amount can be calculated using the formula:

Q = m * c * ΔT

where Q is the amount of thermal energy in joules (J), m is the mass of the substance in kilograms (kg), c is the specific heat capacity of the substance in joules per kilogram per degree Celsius (J/kg°C), and ΔT is the change in temperature in degrees Celsius.

Using this formula, we can calculate the amount of thermal energy required to raise the temperature of 2 kilograms of water by 50 degrees Celsius as follows:

Q = 2 * 78.56 * 50

Q = 3905 J

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No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid.

The pH and the tartrate ion 1C4H4O6 2-2 concentration of a 0.250 M solution of tartaric acid can be calculated using the acid-dissociation constants and the Henderson-Hasselbalch equation. The acid-dissociation constants (Ka1 and Ka2) of tartaric acid are 1.14x10-2 and 5.01x10-5, respectively.

The pH of the solution can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([base]/[acid]) where [base] is the concentration of the conjugate base (the tartrate ion) and [acid] is the concentration of the acid (tartaric acid). Since the solution is 0.250 M in tartaric acid, [acid] = 0.250 M and [base] = 0.250 M - [tartrate ion], which can be calculated using the Ka1 and Ka2 values.

For Ka1, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 1.14x10-2 = 0.249 M. For Ka2, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 5.01x10-5 = 0.249 M.

Using the Henderson-Hasselbalch equation, the pH of the solution can be calculated as pH = pKa + log([base]/[acid]). The pKa values of tartaric acid are 3.92 and 5.63 respectively. Therefore, for Ka1, the pH of the solution can be calculated as pH = 3.92 + log(0.249/0.250) = 3.91, and for Ka2, the pH of the solution can be calculated as pH = 5.63 + log(0.249/0.250) = 5.63.

No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid, as the Henderson-Hasselbalch equation and the acid-dissociation constants of tartaric acid can be used.

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A weak acid as well as its corresponding base make up a buffered solution. The ions are represented by violet, grey, and green spheres, respectively.  The first system represents the buffer.

A buffer is indeed a solution that resists pH fluctuations and contains either one weak acid as well as its salt or even a weak base as well as its salt. To put it another way, a buffer is indeed an aqueous solution that includes a weak base as well as its conjugate acid, or a weak acid as well as its conjugate base.

A buffer may also be referred to as a buffer solution, hydrogen ion buffer, and pH buffer. A weak acid as well as its corresponding base make up a buffered solution. The ions are represented by violet, grey, and green spheres, respectively.  The first system represents the buffer.

Therefore, the first system represents the buffer.

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Answer:

V = l * w * h

V = 150.00 mm x 1cm/10 mm x 10.00 cm x 0.95 m x 100 cm/1 m = 1.4 x 104 cm3 D = M/V

M = D * V = 19.3 g/cm^3 * 1.4 * 104 cm^3 = 2.7 x 10^5 g = 270000 grams

2..5 grams of platinum will be there at the end of the reaction, because Platinum is the catalyst here.

Catalyst is a substance that can be added to a chemical reaction to increase the rate of reaction without getting itself consumed in the reaction. It just acts as a driving force for the reaction and it itself does not take part in the chemical reaction.

Catalysts basically speeds up a reaction by reducing the activation energy or also by changing the reaction mechanism. Enzymes are proteins that act as catalysts in the biological systems.

In the above given question if 2.5 grams of platinum is added to the reaction vessel then at the end of the reaction 2.5 grams of platinum itself will be remaining because it acts as a catalyst here.

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Answer:

oh no!! I can't do this ;(

Explanation:

oopsie "BrO" I can't do this pleaseee.

don't be selfish next time and maybe people will help you...

The correct answer is a) Henry's Law. This law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas in the overlying space.

This means that as the partial pressure of the gas increases, more gas molecules will dissolve in the liquid. Henry's Law is important in many areas of science, including chemistry, environmental science, and biology.

For example, it is used to understand the behavior of gases in the atmosphere and their impact on climate change, as well as the ability of aquatic organisms to obtain oxygen from water.

Henry's Law can also be applied to industrial processes such as gas purification and carbonation of beverages.

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1rst is D, second is A

Explanation:

Answer:

9.90

Explanation:

Given [H+] = 1.25 x 10^-10 M, we can calculate the pH using the formula:

pH = -log10([H+])

pH = -log10(1.25 x 10^-10)

Using logarithmic properties:

pH = -log10(1.25) - log10(10^-10)

Since log10(10^-10) is equal to -10:

pH = -log10(1.25) - (-10)

pH = -log10(1.25) + 10

Now, evaluating the logarithm using a calculator:

pH = -0.0969 + 10

pH = 9.9031

Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately 9.9031. Rounding it to two decimal places, the pH is approximately 9.90.

The reaction represents a decomposition reaction because XY is broken into its constituents.

A decomposition reaction is one in which the reactant is broken up into its constituents. In this case, the reactant is XY. The reactant is shown in the left hand side. The reactant is broken up to yield the products. X and Y.

Since the reactant was broken up into the one white and one gray circles labelled X and Y, then the reaction is a decomposition reaction.

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Answer:

C if your answers are different!

Explanation:

Answer:

Complex permanent tissue is defined as a collection of structurally dissimilar cells performing a common function or set of functions.

its functions are:

1.help in the transportation of organic material, water, and minerals up and down the plants.

2.it helps in transportation of food from leaves to other parts of plants.

have a great dayyyyyy

An argumentative, plausible view of the literary work being evaluated is the claim in a literary analysis.

The claim in a literary analysis, which is an interpretation of a literary work, is the author's argument or viewpoint regarding the relevance or meaning of the work.

The assertion needs to be clear, debatable and backed up by textual evidence.

The claim in literary analysis is the main viewpoint or argument that the author is advancing regarding the relevance or meaning of the literary work under consideration.

The assertion should be a reasonable, disputed opinion that can be backed up by textual evidence, and it should be sufficiently detailed to be convincing and understandable to the reader.

For instance, in an interpretation of William Shakespeare's play "Hamlet," a writer can contend that, rather than a lack of courage, Hamlet's hesitation to exact revenge on his father's murderer stems from his desire for justice and his battle with indecision.

This assertion is both plausible and problematic because different readers or critics may interpret Hamlet's actions differently.

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Arroyave, Penaranda, and Lewis in 2011 studied the role of organizational change in increasing colon, breast, and cervical cancer screening in primary care practices.

According to the study, changes to an organization may boost cancer screening in primary care practices.However, the study did not suggest the ideal structure of organizational change to enhance screening in primary care settings. Nonetheless, it is important to note that organizational change can improve the delivery of preventive care such as cancer screening in primary care practices.

A change in the organization can help improve the quality of care delivered to patients by focusing on preventive services that are necessary. A study by Solberg et al. (2012) suggested that a change in organizational structure can lead to the improvement of preventive care services and better outcomes.

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The fossil fuel which normally contains contains high carbon sources. When it burnt it'll produce a lot of carbon dioxide increasing in its concentration in the atmosphere. But the ratio of 14C to 12C is decreasing because the age of those fossil fuel are so high that the carbon's content is ruined.

These are Extracted by Humans through the method of Drilling and Mining.

Thus from the above conclusion we can say that, ratio of 14C to 12C is decreasing because the age of these fossil fuel are so high that the carbon's content is ruined.

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Explanation:

When an electromagnetic wave like light hits a material, the electrons gets emitted. The emission of electrons is called photoelectric effect. The emitted electrons are called photoelectrons. In this process the transfer of energy takes place from light to an electron.

Hence, the correct option regarding the photoelectric experiment is (A) " Light can cause electrons to be released from the surface of a  metal."