Answers
Answer:
\(a=-1.5\ m/s^2\)
Explanation:
Given that,
Initial velocity, u = 30 m/s
Final velocity, v = 0
Time, t = 20 s
We need to find the acceleration of the car. The rate of change of velocity is equal to acceleration. So,
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{-30}{20}\\\\a=-1.5\ m/s^2\)
So, the magnitude of the acceleration of the car is \(1.5\ m/s^2\) and it is decelerating.
Related Questions
b. Density and relative density.
Answers
Explanation:
density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC
A cube, 1 m on each edge, is held 0.75 m below the surface of a pool of water by a rope. The mass of the cube is 700 kg, and the weight distribution is such that one face remains parallel to the surface of the water. a. Find the tension in the rope. b. Assuming the rope is cut, how far will the cube protrude from the water
Answers
Answer:
Explanation:
The mass of cube = 700 kg
volume = 1 m³
density = 700 kg / m²
Its density is less than that of water so it will try to float on the surface .
Tension in rope will be equal to net upward force
upthrust = volume x density of water x g
= 1 x 10³ x 9.8
= 9800 N
weight of cube = mass x g
= 700 x 9.8
= 6860 N .
Net upward force = 9800 - 6860
= 2940 N.
Tension in the rope = 2940 N.
Rope will hold the cube inside and not allow it to go outside water .
b )
If rope is cut , cube being lighter , will float on surface of water .
Part of cube inside water while floating
= 6860 / 9800
= .7
.7 m will remain inside water
part floating outside
= 1 - 0.7
= 0.3 m .
A student releases a marble from the top of a ramp. The marble increases
speed while on the ramp then continues across the floor. The marble
travels a total of 140cm in 4.10s.
What was the marble's final speed?
Help please
Answers
Answer:
Vf = 0.68 m/s
Explanation:
First we find acceleration of the marble by using 2nd equation of motion:
s = Vi t + (1/2)at²
where,
s = distance covered = 140 cm = 1.4 m
t = time taken = 4.1 s
Vi = initial Velocity = 0 m/s (since, the marble was initially at rest)
a = acceleration = ?
Therefore,
1.4 m = (0 m/s)(4.1 s) + (1/2)(a)(4.1 s)²
a = (1.4 m)(2)/(4.1 s)²
a = 0.17 m/s²
Now, we use 1st equation of motion for final velocity (Vf)
Vf = Vi + at
Therefore,
Vf = 0 m/s + (0.17 m/s²)(4.1 s)
Vf = 0.68 m/s
PLS HELP PLS 10. This graph represents the velocity of an object over time. What is the average acceleration of the
object during the first 4 seconds?
Answers
Answer:
8 M/S
Explanation:
This is because the points match from 4 seconds (X) and it matches up to 8 (Y), therefore it went up 8 M/S in 4 seconds.
Conceptual Example 14 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of 105 kg·m2. When one person is standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s. However, as this person moves inward to a point located 0.507 m from the center, the angular velocity increases to 0.795 rad/s. What is the person's mass?
Answers
For one person standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s, the person's mass is mathematically given as
m = 24.2 kg
What is the person's mass?Generally, the equation for the conservation angular momentum is mathematically given as
(I + m * r0^2) * w0 = (I + m * r^2) * w^2
Therefore
(105 + m * 1.78^2) * 0.517 = (105 + m * 0.524^2) * 0.841
m = 24.2 kg
In conclusion, the mass
m = 24.2 kg
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A car accelerates from rest at a rate of 8.1 m/s2. How much time does it take the car to travel a distance of 65 meters?
Answers
Answer:
ोोञककतकषगकषषमषघ
Explanation:
zzjjjfkgkzgkggkkkammmmmmatAllzy##pglCsg
How long does it take a photon to escape the sun?
Answers
Answer:
About 5000 years.
Explanation:
Answer:
Explanation:
it will take more than half a million years for the photon to escape the sun. If you think it's about a centimeter, then it will take about 5,000 years for the photon to get outside the su
Liz rushes down onto a subway platform to find her train already departing. She stops and watches the cars go by. Each car is 8.60 m long. The first moves past her in 1.80 s and the second in 1.61 s. Find the constant acceleration of the train.
Answers
The constant acceleration of the train is 0.33 m/s.
The average velocity can be calculated by using the formula:
velocity = distance/time
For the 1st car, the velocity is calculated as:
v₁ = 8.60 m / 1.80 s = 4.78 m / s
For the second car, velocity can be calculated as:
v₂ = 8.60 m / 1.66 s = 5.34 m / s
Now we can solve for the acceleration using the formula:
v₂² = v₁² + 2 a d
Rewriting in terms of a, we get
a = (v₂² – v₁²) / 2 d
a = (5.34)² – (4.78)² / (2 × 8.6)
a = 0.33 m/s
Therefore, the constant acceleration of the train is 0.33m/s.
what is acceleration explain?
acceleration, fee at which speed modifications with time, in terms of each pace and course. A factor or an object shifting in a directly line is improved if it hastens or slows down. motion on a circle is improved even if the velocity is steady, due to the fact the route is constantly converting
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1. A 20 Ohm resistor and a 5 Ohm lamp are connected in a single path, with a 50 amps.
What type of circuit is this:
What is the total resistance of the circuit?
What is the total voltage in this circuit?
What is the current?
Answers
The circuit given is a series resistance circuit.
1) The given circuit is a series resistance circuit.
2) Resistance, R₁ = 20 Ω
Resistance, R₂ = 5 Ω
The effective resistance of the circuit is given by,
Reff = R₁ + R₂
Reff = 20 + 5
Reff = 25 Ω
3) Total resistance of the circuit, R = 25 Ω
Current flowing through the circuit, I = 50 A
Therefore, the voltage across the circuit is,
V = IR
V = 50 x 25
V = 1250 V
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A baseball of mass m = 0.31 kg is spun vertically on a massless string of length L = 0.51m. The string can only support a tension of Tmax = 7.5 N before it will break. What isthe maximum possible speed of the ball at the top of the loop, in meters per second?
Answers
Given data:
* The mass of the baseball is 0.31 kg.
* The length of the string is 0.51 m.
* The maximum tension in the string is 7.5 N.
Solution:
The centripetal force acting on the ball at the top of the loop is,
\(\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}\)For the maximum velocity of the ball at the top of the vertical circular motion,
\(v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}\)Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.
Need help Physics Will make Brainliest
Answers
Force between q1 and q2
F= (8.99*10^9)(8*10^-6)(3.5*10^-6)
F= 25.2 N
Meaning 25.2 N to the right
Force between q2 and q3
F= (8.99*10^9)(3.5*10^-6)(-2.5*10^-6)
F= -3.5 N
Meaning 3.5 N to the left
Resultant force= 25.2-3.5
Resultant force on q2= 21.6 N to the right
Hope this helps :)
The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.
To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.
The force between two point charges can be calculated using Coulomb's law, which states that
F = k × q₁× q₂ / r²
where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.
The force between q₁ and q₂ is
F₁ = k × q₁ × q₂ / r₁²
where r₁ = 0.10 m.
Substituting the values, we get
F₁ = 9.0 x 10⁹ N m² / C² × 8.0 C × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N
The force between q₂ and q₃ is
F₂ = k × q₂ × q₃ / r₂²
where r₂ = 0.15 m.
Substituting the values, we get
F₂ = 9.0 x 10⁹ N m² / C² × 3.5 C × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N
Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.
The net force on q₂ is the vector sum of F₁ and F₂
\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N
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A particle of charge Q and mass m is accelerated from rest through a potentialdifference V, attaining a kinetic energy K. What is the kinetic energy of a partical of charge2Q and mass m/2 that is accelerated fromrest through the same potential difference?
a) K/4
b) K/2
c) K
d) 2K
e) 4K
Answers
Hi there!
Recall the equation for work given a potential difference and charge:
\(\large\boxed{W = qV}\)
W = Work (J)
q = charge (C)
V = Potential difference (V)
The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.
Thus:
\(W' = (2Q)(V) = 2W\)
This is equivalent to:
\(\large\boxed{2W = \text{ d) } 2K}}\)
What is the extension force (in lbf) of a 14 inch diameter cylinder with a 10 inch rod and pressure of 700psi?
Answers
The given problem can be exemplified in the following diagram:
To determine the extension force we will use the definition of pressure:
\(P=\frac{F}{A}\)Where "F" is the force, and "A" is the area. To determine the area we will use the following equation:
\(A=\frac{\pi D^2}{4}\)Where "D" is the diameter. The force acts over the area of the 10 inches diameter alone, therefore we don't need to have into account the area of the rod. Replacing the value of the diameter we get:
\(A=\frac{\pi(14in)^2}{4}\)Solving the operation:
\(A=153.94in^2\)Replacing in the formula for the pressure we get:
\(P=\frac{F}{153.94in^2}\)Since we are required to determine the force, we will multiply both sides by the area:
\(153.94in^2P=F\)Replacing the given value of the pressure we get:
\((153.94in^2)(700\frac{lbf_{}}{in^2})=F\)Solving the operations we get:
\(107756.62lb_f\)Therefore, the extension force is 107756.62 lbf.
The mass of the Earth is 81 times the mass of the Moon, and the radius of the Earth is 3.7 times of the Moon. If the acceleration of free fall on the Earth is 9.81 ms, without using the actual mass and radius of Earth and Moon, determine the acceleration on the Moon?
Answers
Answer:
Fe = m ge = G Me m / Re^2 force exerted on m by earth
ge = G Me / Re^2
gm = G Mm / Rm^2 same for measuring g on moon
ge / gm = (Me / Mm) * (Rm / Re)^2 ratio of g
ge / gm = 81 * (1 / 3.7)^2 = 81 / 13.7 = 5.92 acceleration of earth to moon
Relationship between SI unit for area and other units of area
Answers
The SI unit for area is the square meter (m²). It is a fundamental unit of measurement in the International System of Units (SI). Here are some common units of area and their relationships to the square meter:
Square kilometer (km²): 1 km² is equal to 1,000,000 square meters (1 km² = 1,000,000 m²). It is used for large-scale measurements, such as land area or geographical regions.
Hectare (ha): 1 hectare is equal to 10,000 square meters (1 ha = 10,000 m²).
Square centimeter (cm²): 1 cm² is equal to 0.0001 square meters (1 cm² = 0.0001 m²).
Square millimeter (mm²): 1 mm² is equal to 0.000001 square meters (1 mm² = 0.000001 m²).
Acre: 1 acre is equal to approximately 4046.86 square meters.
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Say an impulse is applied opposite the go-kart's direction of travel. What happens to
the go-kart if its momentum + impulse = 0?
The go kart stops comes to a stop.
The go kart slows down but keeps moving.
The go kart speeds up.
There is no change in the speed of the go kart.
Answers
If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.
Option A is correct.
What is meant by impulse?impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.
If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.
Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.
As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.
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If you are driving 80 km/h along a straight road and you look to the side for 1.7 s , how far do you travel during this inattentive period?
Express your answer using two significant figures.
Answers
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
How far did the driver travel during the inattentive period?Speed is simply referred to as distance traveled per unit time.
Mathematically, Speed = Distance ÷ time.
Given the data in the question;
Speed = 80 km/hTime = 1.7sDistance travelled = ?First, convert 1.7 seconds to hours.
Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs
Now, find the distance traveled during the inattentive period.
80 km/h = Distance ÷ 1.7/3600 hrs
Distance = 80 km/h × 1.7/3600 hrs
Distance = 136/3600 km
Distance = 0.037 km.
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
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Complete each statement by dragging the forms of energy into their appropriate boxes.
wind turbine
roller coaster going downhill
toaster
car
A
converts electrical energy into thermal energy.
A
converts rotational energy into electrical energy.
A
converts gravitational energy into mechanical energy.
A
converts rotational energy into mechanical energy.
Answers
Statements 1,2,3 and 4 match statements B, C, A, and D respectively.A wind turbine converts rotational energy into electrical energy.
What is the law of conservation of energy?According to the Law of conservation of energy. Energy can not be created nor be destroyed, it can transfer from one to another form.
1.A wind turbine converts rotational energy into electrical energy.
2.A roller coaster going downhill converts gravitational energy into mechanical energy
3. Toaster converts electrical energy into thermal energy
4.A car converts rotational energy into mechanical energy.
Hence,statements 1,2,3 and 4 match statements B, C, A, and D respectively.
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A rubber ball (1 kg) falls from a height of 10 m and collides elastically with the floor. What is the velocity of the ball as it rebounds from the floor?
Answers
This question involves the concepts of the equation of motion and elastic collision.
The velocity of the ball as it rebounds from the floor will be "14 m/s".
REBOUND VELOCITYThe elastic collision is the one during which the momentum and kinetic energy of a body remain conserved. Hence, the velocity of the body also remains constant. Therefore, the rebound velocity of the ball will be the same as the striking velocity of the ball. This can be calculated using the third equation of motion.
\(2gh=v_f^2-v_i^2\)
where,
h = height = 10 mg = 9.81 m/s²vf = striking velocity = rebound velocity = ?vi = initial velocity = 0 m/sTherefore,
\((2)(9.81\ m/s^2)(10\ m)=v_f^2-(0\ m/s)^2\\v_f=\sqrt{196.2\ m^2/s^2}\\\\v_f=14\ m/s\)
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What are the
benefits and limitations of scientific models
that can be used to represent data gathered
from experiments and investigations?
Answers
checlknthfd sissExplanation: 2+3 ls g g fg
Which statement places events during the Space Race in the correct order from the earliest to the most recent?
1.NASA was established, US satellite Explorer launched, first man walked on the moon, first man orbited the Earth
2.first man walked on the moon, first man orbited the Earth, NASA was established, US satellite Explorer launched
3.US satellite Explorer launched, NASA was established, first man orbited the Earth, first man walked on the moon
4. first man orbited the Earth, first man walked on the moon, US satellite Explorer launched, NASA was established
Answers
Answer:
3,1,4,2
Explanation:
Answer:C
Explanation:
EASY POINTS:Which element is magnetic? calcium chromium carbon cobalt
Answers
Answer:
D
Explaination:
I got it right on the quiz
Answer:
The answer is D. cobalt! :)
Which of the following statements best describes the situation in
which the "constant-acceleration model" appears to fail to describe
the motion of an object (say, a leaf falling from a tree).
In practice, no object's motion is actually very close to the constant acceleration model.
DIf the conditions required for the constant-acceleration model are not present, then the model
may not describe the motion very well.
Any difference between the observed motion and the motion predicted by the constant-
acceleration model must be the result of measurement error.
Answers
We want to see which statements describe the siutuations where "constant-acceleration motion" fails.
We will see that the correct option is the first one.
"In practice, no object's motion is actually very close to the constant acceleration model."
We need to analyze each statement.
1) In practice, no object's motion is actually very close to the constant acceleration model.
This is true, for example, if we return to the leaf example, we usually would say something that "a falling object is only affected due to gravitational acceleration" and we assume that the acceleration is constant, but this is actually false, as there are a lot of other forces like friction or air resistance that also contribute. These forces also depend on the shape of the falling object and the velocity at which it falls, so the contributions to the acceleration are not constants, thus the acceleration is not constant.
2) the conditions required for the constant-acceleration model are not present, then the model may not describe the motion very well.
The conditions are not stated and depend on the particular situation, so this does not fit really well.
3) Any difference between the observed motion and the motion predicted by the constant- acceleration model must be the result of measurement error.
This is false, while yes, obviously, if you have a measurement error the predictions will be wrong, but even in the case where your measures are flawless, the constant-acceleration model ignores some things that contribute to the motion (are kinda small contributions, this is why we ignore them) so a lot of differences will be due to these contributions that we are ignoring.
So the correct statement is the first one.
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mechanical energy defintion
Answers
Answer: Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.
(The energy acquired by the objects upon which work is done)
Two blocks with masses 2.00 kg and 4.00 kg are placed side-by-side on a frictionless horizontal surface. A horizontal force with a magnitude of 5.20 N is applied to the 2.00-kg block perpendicular to its surface. What is the magnitude of the force on the 4.00-kg block?
a. 2.60
b. 3.11
c. 3.47
d. 3.89
Answers
The magnitude of the force on the 4.00-kg block is 3.47 N.
The given parameters:
Mass of first block, m1 = 2 kgMass of second block, m2 = 4 kgHorizontal force, F = 5.2 NAcceleration of both blocks;The acceleration of both blocks is calculated by applying Newton's second law of motion.\(a = \frac{F}{m_1 + m_2} \\\\a = \frac{5.2}{2 + 4} \\\\a = \frac{5.2}{6} \\\\a = 0.867 \ m/s^2\)
The magnitude of the force on the 4.00-kg block is calculated as follows;
F = ma
F = 4 x 0.867
F = 3.47 N
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22. True or False? When holding the hockey stick properly, players keep two hands on it for control and the blade stays low to the floor for safety. O True O False
Answers
Answer:
true msjnsnaks nsnaufitskclyc86xoyc
Consider the Atwood Machine, assuming a massless pulley. Assume m1 > m2. Using N2, we found the acceleration of the system is: a = g(m1 − m2)/(m1 + m2) and the tension was equal. Now take into account the mass of the pulley:
a) Suppose m1 = 0.7 kg and m2 = 0.4 kg. What would the system acceleration be for the pulley?
b) What is the net torque acting on the pulley in terms of the tensions T1, T2, and the pulley radius R? What is the net force acting on each mass in terms of T and weight?
c) Use Newton's 2nd, Rotational N2, and assume the string doesn’t “slip” (at = αR) to find the acceleration of the system if the mass of the pulley is 5 kg.
Answers
The system acceleration for the pulley having masses m1 = 0.7 kg and m2 = 0.4 kg Is 35.93 \(m/s^2\).
What is Newton's Second Law?Newton's second law provides a detailed explanation of how a force can alter a body's motion. It is believed that a body's momentum varies over time at a rate equal to the force acting on it in both direction and amplitude. The combined effects of a body's mass and velocity determine its momentum.
Given:
The mass, m₁ = 0.7 kg,
m₂ = 0.4 kg,
Calculate the system acceleration by the following formula,
a = g(m1 − m2)/(m1 + m2)
Here a is the acceleration.
Substitute the values,
a = 9.8 * (0.7 - 0.4 ) / (0.7 + 0.4)
a = 35.93 \(m/s^2\)
Therefore, the system acceleration for the pulley is 35.93 \(m/s^2\).
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A plane flying at a steady speed of 100 m/s accelerates to 150 m/s in 10 seconds. What is the plane’s acceleration?
Answers
A plane flying initially at 100 m/s uses an acceleration of 5 m/s² to reach a velocity of 150 m/s in 10 seconds.
What is acceleration?Acceleration is the change in velocity over time.
A plane is flying initially at 100 m/s (u) and it accelerates to 150 m/s (v) in 10 s (t). We can calculate its acceleration using the following expression.
a = v - u / t = (150 m/s - 100 m/s) / 10 s = 5 m/s²
A plane flying initially at 100 m/s uses an acceleration of 5 m/s² to reach a velocity of 150 m/s in 10 seconds.
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Adding salt to water increases the water’s boiling point.
If you performed an experiment to test this hypothesis, which action would introduce confounding variables into your experiment?
Answers
Answer:
Explanation:
Adding other substances to the water besides salt, such as sugar or baking soda, would introduce confounding variables into the experiment. Other factors that could introduce confounding variables include using different volumes of water, using different amounts of salt, and heating the water at different rates. To minimize confounding variables, it is important to keep all variables constant except for the one being tested, which in this case is the effect of salt on the boiling point of water.
effort distance of a lever should be increased to lift the havier load give reason
Answers
The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.
The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.
In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.
By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.
By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.
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