if a stress (s1) greater than the yield point is applied to a metal in a tensile test, then that applied stress (s1) becomes:

A weak entity set can always be converted into a strong entity set by simply adding to its attributes the primary-key attributes of its identifying entity set. But doing so will result in the redundant storage of the primary key.

Although a weak entity set can be transformed into a strong entity set by adding appropriate primary-key attributes, but this strategy results in the redundant storage of the primary key. Since the primary key of the weak entity set can be deduced from its relationship with the strong entity set, if we add primary-key attributes to the weak entity set, then they will be present in both the relationship set and the entity set that need to be the same, resulting in the redundant storage of the primary key.

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Focus primarily on highly precise specifics of what Cornell offers and how it matches with your interests and values. You can regard this as a "Why us?" essay with some optional "Why major" spice.

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Answer:

Coiled tubing is often used to carry out operations similar to wire lining.

Answer:

sorry , for my point

Explanation:

The length of the surface for which the flow remains laminar can be determined by calculating the Reynolds number and comparing it to the critical Reynolds number for laminar flow. In this case, the critical Reynolds number is not provided, so we cannot determine the exact length.

To determine the length of the surface for which the flow remains laminar, we need to compare the Reynolds number (Re) to the critical Reynolds number (Rec) for laminar flow. The Reynolds number is calculated using the formula:

Re = (velocity * length) / kinematic viscosity

Given the velocity of 7 m/s and the length of the surface (4 m), we can calculate the Reynolds number. However, we also need to know the kinematic viscosity (ν) of air, which is given as 1.798 x 10^-5 m^2/s.

Re = (7 m/s * 4 m) / (1.798 x 10^-5 m^2/s) = 77,743\

To determine the length of the laminar flow, we need to compare the Reynolds number to the critical Reynolds number. However, the critical Reynolds number (Rec) for laminar flow is not provided in the given information. The critical Reynolds number depends on various factors, including the type of flow, surface roughness, and specific conditions of the flow.

Without the critical Reynolds number, we cannot determine the exact length for which the flow remains laminar. It is possible that laminar flow could be maintained over the entire 4 m length, or it could transition to turbulent flow at some point along the surface. To determine the length accurately, the critical Reynolds number specific to the flow conditions needs to be known or estimated.

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The center of gravity, also known as the balance point or point of rotation when an object is permitted to freely rotate, is the average location of an object's weight.

All objects with mass are attracted to one another by the gravitational attraction, which has a magnitude that is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another.

By means of gravity, a planet or other body pulls items toward its core. All the planets are maintained in their orbits around the sun by the force of gravity.

Any particle of matter in the universe will gravitate toward any other with a force that varies directly as the product of the masses and inversely as the square of the distance between them, according to Newton's law of gravity.

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Answer:

- Work done is 2.39 kJ

- heat transfer is 20.23 kJ/kg

Explanation:    

Given the data in the question;

First we obtain for specific volumes and specific enthalpy from "Table Properties Refrigerant 134a;

Specific Volume v₁ =  0.02547 m³/kg

Specific enthalpy u₁ = 243.78 kJ/kg

Specific Volume V₂ = 0.02846 m³/kg

Specific enthalpy u₂ = 261.62 kJ/kg

p = 8 bar = 800 kPa

Any changes in kinetic and potential energy are negligible.

So we determine the work done by using the equation at constant pressure

]Work done W = p( v₂ - v₁ )

we substitute

W = 800 kPa( 0.02846 m³/kg - 0.02547 m³/kg )

W = 800 kPa( 0.00299 m³/kg )

W = 2.39 kJ

Therefore, Work done is 2.39 kJ

Heat transfer;

using equation at constant pressure

Heat transfer Q = W + ( u₂ - u₁ )

so we substitute

Q = 2.392 kJ + ( 261.62 kJ/kg - 243.78 kJ/kg )

Q = 2.392 kJ +  17.84 kJ/kg )

Q = 20.23 kJ/kg

Therefore, heat transfer is 20.23 kJ/kg

The person that is correct based on the 2 statements from Tech A and Tech B is; Tech B

A mass flow sensor is defined as a sensor that is used to measure the mass flow rate of air entering a fuel-injected internal combustion engine and then sends a voltage that represents the airflow to the electronic control circuit.

However, for Tech A is incorrect and so the correct answer is that Tech B is right because his statement corresponds with the definition of mass flow sensor.

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Answer:

Tech B is correct.

Explanation:

A mass flow sensor is basically sensor that checks the mass flow rate (hence the name) and then produces an electrical signal that copies the airflow going to the electronic control circuit. Smart technology, eh?

You don't have to give me brainliest, but I would greatly appreciate it! Thanks mate!

To determine the factor of safety with respect to buckling for the W12 x 50 column, you will need to perform a buckling analysis to determine the critical buckling load of the column, and then compare it to the actual load that the column is subjected to.

Step-by-step Explanation:

To begin, you will need to determine the effective length of the column. For a pin-supported column with a length of 20 feet, the effective length is equal to the actual length, so the effective length of the column is 20 feet.

Next, you will need to determine the elastic critical buckling load of the column using a suitable buckling equation, such as the Euler buckling equation. The Euler buckling equation for a pin-supported column is given by:

P_cr = pi^2 * E * I / (K_L * L_e)^2

where:

You will need to obtain the values for E, I, and K_L for the W12 x 50 column, which you can find in a suitable reference such as a steel design manual.

Once you have determined the critical buckling load of the column, you can calculate the factor of safety with respect to buckling by dividing the critical buckling load by the actual load that the column is subjected to. In this case, the actual load is 150 kip, so the factor of safety is given by:

FOS = P_cr / P_actual

= (critical buckling load) / 150 kip

Plugging in the values and solving the equation will give you the factor of safety.

It is important to note that this is a simplified approach to determining the factor of safety with respect to buckling, and in practice there may be other factors that need to be taken into consideration, such as the effects of axial load and lateral loads, the influence of neighboring columns, and the influence of imperfections in the column.

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In part a) When setting the initial price of the product in Pakistan, Big Bird Foods could apply several methods. In part b) For the new product internationally, a suitable pricing strategy for Big Bird Foods could be market skimming.

Market-based pricing can be used by analyzing customer preferences, purchasing power, and competitors' prices. Value-based pricing can consider the unique benefits of the product and customers' willingness to pay. Additionally, they could employ penetration pricing to attract customers by setting a lower initial price. Ultimately, a combination of these methods, tailored to the Pakistani market, would help Big Bird Foods set a competitive and profitable price for their freeze-dried pasta.

Market skimming strategy involves setting an initially high price for the product to target early adopters and customers who value the premium quality and convenience of freeze-dried pasta. As the product gains recognition and market share, Big Bird Foods can gradually lower the price to appeal to a broader customer base. This approach capitalizes on the product's uniqueness and allows the company to maximize profits before facing increased competition or price pressure from rival products.

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The disadvantage of using a linear model is that; It is sensitive to outliers and prone to multicollinearity.

Linear regression is defined as a regression technique whereby the independent variable has a linear relationship with the dependent variable.

Now, there are some advantages of this model in statistics such as;

However, there are some disadvantages such as;

It is very sensitive to outliers.

It is prone to having multicollinearity.

It assumes linearity between dependent and independent variables.

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Solution :

1. PL \($= \frac{11.53 - 10.49}{10.49 - 4.5} \times 100$\)

       = 17.36 %

2. Liquid limit at 25 number of blows,

  \($LL = \frac{(26-25)\times 49.8 + (25 - 2.17) \times 47.5}{26-17}$\)

       \($= 47.75 $\) %

Since 84 % of the passes the number 200 sieve the soil is immediately fine grained and MI, OI or CI because LL = 47.75 % > 35%

Therefore, the Plasticity index, PI  \($=47.75 - 17.36 = 30.39$\) %

Equation of A-line \($= 0.73 \times [47.75 - 20]$\)

                             \($=20.25 $\) %

Thus the soil lies above the A-line, that is soil is medium compressible clay ---- CI

Answer:

0.39 nM

Explanation:

The critical crack tip radius from the equation

attached below

for fracture to occur the бm will have to reach the fracture strength of material

i.e.  бm =  E/10

from equation 2 attached below

St = ( 400 * a * бo^2 ) / E^2 ------ 3

Given : a = 2*10^-3 mm , бo = 275 MPa, E = 393 * 10^3 MPa ( gotten from table)

Input given values into equation 3

St = 3.9 * 10^-7 ≈ 0.39 nM

Answer:

Used to recall the direction a standard screw

The correct answer is option (C): 18862.5 J/kg

To determine the specific work done on the system, we can use Bernoulli's equation for steady, incompressible flow along a streamline. Neglecting the gravitational potential energy variation, Bernoulli's equation can be expressed as:

p/ρ + V²/2 = constant

Using Bernoulli's equation between the inlet and outlet ports of the control volume, the equation becomes:

p1/ρ + C1²/2 = p2/ρ + C2²/2 + L

Given the values of inlet pressure (P), inlet velocity (C), outlet pressure (Pout), outlet velocity (Cout), and viscous dissipations (L), we can substitute them into the equation and solve for L:

1/1000 + 5²/2 = 200/1000 + (-10)²/2 + L/1000

Simplifying the equation gives L = 1000 J/kg.

The specific work done on the system is calculated using the formula:

W = (Pout - P)/ρ + (Cout² - C²)/2 - L/ρ

Substituting the given values, we get:

W = (200 - 1)/1000 + ((-10)² - 5²)/2 - 1000/1000

Simplifying further, we find W = -3.5625 kJ/kg. Multiplying this by 1000, we obtain the specific work done on the system as 18862.5 J/kg.

Therefore, the correct option is (C) 18862.5 J/kg.

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Answer:

glue

Explanation:

Answer:

No.

Explanation:

\(P_r\) = Power rating = 1 W

R = Resistance = \(350\ \Omega\)

V = Voltage = \(24\ \text{V}\)

Power is given by

\(P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{24^2}{350}\\\Rightarrow P=1.65\ \text{W}\)

\(1.65\ \text{W}>1\ \text{W}\)

So

\(P>P_r\)

Hence, the resistor is not operating within its power rating.

Answer:

a. the rate of heat loss from the electronic device to the surrounding air

A total of 10 rectangular aluminum fins (k = 203 W/m·K) are placed on the outside flat surface of an electronic device. Each fin is 100 mm wide, 20 mm high and

4 mm thick. The fins are located parallel to each other at a center-to-center distance of 8 mm. The temperature at the outside surface of the electronic device is 72°C. The air is at 20°C, and the heat transfer coefficient is 80 W/m2·K. Determine (a) the rate of heat loss from the electronic device to the surrounding air and (b) the fin effectiveness.

Explanation:

Sorry if wrong, Hope I helped

~#Lilly

Answer

(a) upsilon(t)= 0.1[δ(t - 2) - δ(t - 4) - δ(t - 8) + δ(t - 10)] V

    p(t) = 0.02[δ(t - 2) - δ(t - 4) - δ(t - 8) + δ(t - 10)] W
    w(t) = 0.002 × [δ(t - 2) - δ(t - 4) - δ(t - 8) + δ(t - 10)] J

(b) upsilon(t) = 0.2e^-0.4t u(t) - 0.5δ(t) V

    p(t) = upsilon(t) × i2(t)
    w(t) = 0.5 × L × i2(t)^2

(c) upsilon(t) = 0.4e^-0.4t u(t) V

    p(t) = -1.6(1 - e^-0.4t) u(t) W
    w(t) = 0.05[4(1 - e^-0.4t) u(t)]^2 J

To obtain expressions and generate plots for upsilon(t), p(t), and w(t) for a 0.5-mH inductor, we first need to find the voltage across the inductor using the formula:

upsilon(t) = L(di(t)/dt)

where L is the inductance and di(t)/dt is the derivative of the current with respect to time.

(a) For i1(t) = 0.2r(t - 2) - 0.2r(t - 4) - 0.2r(t - 8) + 0.2r(t - 10) A, we can find the derivative of the current waveform as follows:

di1(t)/dt = 0.2[δ(t - 2) - δ(t - 4) - δ(t - 8) + δ(t - 10)]

where δ(t) is the Dirac delta function.

Then, we can find upsilon(t) as follows:

upsilon(t) = 0.5 × di1(t)/dt
          = 0.1[δ(t - 2) - δ(t - 4) - δ(t - 8) + δ(t - 10)] V

To find p(t) and w(t), we can use the formulas:

p(t) = upsilon(t) × i1(t)
w(t) = 0.5 × L × i1(t)^2

Substituting the values, we get:

p(t) = 0.02[δ(t - 2) - δ(t - 4) - δ(t - 8) + δ(t - 10)] W
w(t) = 0.002 × [δ(t - 2) - δ(t - 4) - δ(t - 8) + δ(t - 10)] J

(b) For i2(t) = 2u(-t) + 2e^-0.4t u(t) A, we can find the derivative of the current waveform as follows:

di2(t)/dt = 0.8e^-0.4t u(t) - 2δ(t)

Then, we can find upsilon(t) as follows:

upsilon(t) = 0.5 × 0.5 × di2(t)/dt
          = 0.2e^-0.4t u(t) - 0.5δ(t) V

To find p(t) and w(t), we can use the formulas:

p(t) = upsilon(t) × i2(t)
w(t) = 0.5 × L × i2(t)^2

Substituting the values, we get:

p(t) = 0.4e^-0.4t u(t) W
w(t) = 0.05[2u(-t) + 2e^-0.4t u(t)]^2 J

(c) For i3(t) = -4(1 - e^-0.4t) u(t) A, we can find the derivative of the current waveform as follows:

di3(t)/dt = 1.6e^-0.4t u(t)

Then, we can find upsilon(t) as follows:

upsilon(t) = 0.5 × 0.5 × di3(t)/dt
          = 0.4e^-0.4t u(t) V

To find p(t) and w(t), we can use the formulas:

p(t) = upsilon(t) × i3(t)
w(t) = 0.5 × L × i3(t)^2

Substituting the values, we get:

p(t) = -1.6(1 - e^-0.4t) u(t) W
w(t) = 0.05[4(1 - e^-0.4t) u(t)]^2 J

To generate plots for upsilon(t), p(t), and w(t), we can use software such as MATLAB or Python. The plots will depend on the values of the constants used and the time range specified.

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The amplitude of the response at a time of 4 natural periods after the motor is switched on is A(4T) = A x cos(4w₀T) = (√(m/M)/2) x cos(4√(M/mR) x T)

In this problem, we have a conveyor belt with a left wheel that is locked into position when the motor is accidentally switched on, exerting a harmonic torque M(t) = Msin(N2t) about the hub of the right wheel. The mass and radius of the flywheel are given as m and R, respectively, and no slipping occurs between the belt and wheels. The effective stiffness of each leg of the elastic belt can be represented as k/2.
To determine the response of the system at resonance, we need to find the natural frequency of the system. The natural frequency can be calculated as:
w₀ = √(k/m)
where k is the effective stiffness of each leg of the elastic belt and m is the mass of the flywheel.
At resonance, the frequency of the harmonic torque applied to the system will be equal to the natural frequency of the system. Therefore, we have:
N₂ = w₀
Solving for w₀, we get:
w₀ = √(N2) = √(M/mR)
Now, we can find the amplitude of the response at a time of 4 natural periods after the motor is switched on. The amplitude of the response can be calculated using the formula:
A = M/(2kRw₀)
Substituting the values of M, k, R, and w₀, we get:
A = M/(2kR√(M/mR)) = √(m/M)/2
Therefore, the amplitude of the response at a time of 4 natural periods after the motor is switched on is:
A(4T) = A x cos(4w₀T) = (√(m/M)/2) x cos(4√(M/mR) x T)

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The complete question is:

The left wheel of a conveyor belt is locked into position when the motor is accidentally switched on, exerting a harmonic torque M (t) = M₀ sinΩt, sint about the hub of the right wheel, as indicated in Figure P3.6. The mass and radius of the flywheel are m and R, respectively. If no slipping occurs between the belt and wheels the effective stiffness of each leg of the elastic belt may be represented as k/2, as shown. Deter- mine the response of the system at resonance. What is the amplitude of the response at a time of 4 natural periods after the motor is switched on?

The angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.

(b) The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .

Angular acceleration of the rod

The angular acceleration of the rod is calculated as follows;

Apply the principle of conservation of angular momentum;

τ = Iα

where;

τ is torque

I is moment of inertial of the rod

α is the angular acceleration

τ = Fr = mg(L/2) cosθ

I = mL²/3

mg(L/2) cosθ =  mL²/3(α)

g(1/2) cosθ =  L/3(α)

(³/₂)g cosθ  = L(α)

(³/₂ L)g cosθ  = α

1.5Lg cosθ  = α

1.5(2.1) cos (70.4) = α

1.06 rad/s² = α

Angular speed of the rod

ωf² = ω₁² + 2αθ

ωf² = 0 + 2(1.06)(70.4π/180)

ωf² = 2.605

ωf = √2.605

ωf = 1.61 rad/s

Thus, the angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.

The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .

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Answer:

it's not included

Explanation:

plz exact ur explain

Answer:

si amor

Explanation:

Hoiykñjdnlklbutrk

Answer: B) Rotating

Explanation: Osha 10 Career safe

Answer:

Top Final year projects for civil engineering students

• Geographic Information System using Q-GIS. ...

• Structural and Foundation Analysis. ...

• Construction Project Management & Building Information Modeling. ...

• Tall Building Design. ...

• Seismic Design using SAP2000 & ETABS.

Explanation:

Hope it's help

Answer: see attached files

❎❎❎❎❎❎❎ sorry but that didn't help me that much

sens organ is the eye example

Answer:

10

Explanation:

Answer:

D. Overrule any other laws and traffic control devices.

Explanation:

Laws and traffic control devices are undoubtedly compulsory to be followed at every point in time to control traffic and other related situations. However, there are cases when certain instructions overrule these laws and traffic control devices. For example, when a traffic police is giving instructions, and though the traffic control devices too (such as traffic lights) are displaying their own preset lights to control some traffic, the instructions from the traffic police take more priority. This is because at that point in time, the instructions from the traffic control devices might not be just applicable or sufficient.

Also, in the case of instructions given by construction flaggers, these instructions have priority over those from controlling devices. This is because during construction traffic controls are redirected from the norms. Therefore, the flaggers such be given more importance.

Answer:

D. Overrule any other laws and traffic control devices.

Explanation: