Answer:
\(\frac{F}{F_o}\) = 1.2 10⁻²
force of attraction of the sun decreases by a factor of 1.2 10⁻² times
Explanation:
The force of gravity is given by the universal law of attraction
F = G m Ms / r²
where m is the mass of the Earth, Ms the mass of the Sun and r the distance from the Earth to the Sun
for the initial orbit
F₀ = G m Ms / R₀²
for one orbit
R = 9R₀
F = \(G \frac{m M_s}{ ((9R_o)^2}\)
F = \(G \frac{m M_s}{81 \ R_o^2}\)
we substitute
F = F₀ / 81
\(\frac{F}{F_o}\) = 1.2 10⁻²
therefore the force of attraction of the sun decreases by a factor of 1.2 10⁻² times
here is an acceleration vs. time graph. what is the change in velocity between 2s and 4s?
Explanation:
From 2s, velocity increased gradually up to 4s
The Voltmeter reads 16 V. The ammeter reads 0.25 A. The resistance must be
Answer:
64 ohms =R
Explanation:
R is directly proportional to V
R is inversely proportional to I(Current
Is the force of gravity that attracts my body to the Earth related to the force of gravity between the planets and the Sun
Certainly gravity is a force that exists between the Earth and the objects that are near it. As you stand upon the Earth, you experience this force.
An electric kettle heater has two coils. When one coil is switched on it takes 15 minutes and other coil takes 30 minutes to boil certain mass of water. The ratio of time taken by them when connected in series and parallel to boil same mass of water respectively is
The ratio of time taken by them when connected in series and parallel to boil same mass of water respectively is 9:2.
What is an electric kettle heater?
Electric kettles are mainly used for boiling the water in a jiffy container. Unlike the traditional gas stove kettles, electric tea kettles are highly efficient containers and these come with several innovative features.
R₁ = 15 min
Heat R₁ is
H = (V²/ H)15 = 15K
V²/ H = K
Same R₂,
V²/ H = K
Resistance in series,
R₁ + R₂
H = (V²/ R₁ + R₂)t
t₁ = (R₁ + R₂/ V²)H
t₂ = (H × R₁R₂)/ (R₁ + R₂)V²
t₁/ t₂ = (R₁ + R₂)²/ R₁R₂ = (15K + 30K)²/ (15K×30K)
t₁/ t₂ = 9/2
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A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².
The distance from the axis of the force applied is 2.05 m.
What is the distance from the axis of the force applied?The distance from the axis of the force applied is calculated as follows;
The formula for torque;
τ = Fr
where;
F is the applied forcer is the distance from the axis of the force appliedAnother formula for torque is given as;
τ = Iα
where;
I is the moment of inertia of the doorα is the angular acceleration;τ = (mr²)α
τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)
τ = 39.36 Nm
The distance is calculated as;
r = τ/F
r = ( 39.36 Nm ) / (19.2 N)
r = 2.05 m
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calculate the velocity of an object moved around a circle with a radius of 1.65m and an acceleration of 3.5 m/s^2
Answer:
2.4m/s
Explanation:
Describe a situation in which you can accelerate even though your speed doesn’t change.
Acceleration is not the same as speeding up. It refers to any modification of motion's direction or speed. Accelerated motion is any movement that is not constant speed in a straight line.
What is meant by acceleration?In physics, acceleration refers to the rate at which an object's velocity over time changes. They are accelerations and vector quantities. The direction of an object's acceleration is determined by the direction of the net force acting on it.
Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign.
Acceleration is the measure of a change in velocity. Acceleration frequently, though not always, denotes a shift in speed. The direction of motion is changing, therefore an object moving at a constant speed in a circular path is still moving ahead.
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A man is holding an 8.00-kg vacuum cleaner at arm's length, a distance of 0.550 m from his shoulder. What is the torque on the shoulder joint if the arm is held at 30.0
The torque on the shoulder joint is 21.4 N·m.
torque = force x distance x sin(theta)
weight = mass x gravity
where mass is 8.00 kg and gravity is 9.81 m/s². So,
weight = 8.00 kg x 9.81 m/s² = 78.5 N
torque = 78.5 N x 0.550 m x sin(30.0 degrees)
torque = 21.4 N·m
Torque is a measure of the rotational force or moment that is applied to an object, causing it to rotate around a fixed axis or pivot point. It is commonly expressed in units of Newton meters (Nm) or pound-feet (lb-ft) and is calculated by multiplying the force applied to the object by the distance from the pivot point to the point where the force is applied.
In simpler terms, torque is the amount of twisting force that is applied to an object, like a wrench turning a bolt or a motor turning a shaft. The greater the torque applied to an object, the greater the rotational acceleration produced, and the faster the object will rotate. Conversely, objects that are difficult to rotate require a greater torque to overcome their resistance and achieve rotation.
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Dry steam at 100° is bubbled into 500g of water originally at 20° . what will be the temperature of water after 30g of steam has condensed .(Specific latent heat of steam=2.26×10^6Jkg,specific heat capacity of water =4200Jkgk)
The temperature of the water after 30g of steam has condensed will be approximately 52.14°C.
To solve this problem, we need to consider the energy transfer that occurs when steam condenses into water. The energy released by the condensing steam will be absorbed by the water, resulting in a temperature change.First, let's calculate the energy released when 30g of steam condenses. The specific latent heat of steam is given as 2.26 × 10^6 J/kg, so the energy released by 30g of steam can be calculated as:
Energy released = (30g) × (2.26 × 10^6 J/kg) = 6.78 × 10^7 J
Next, we need to calculate the energy required to raise the temperature of the water from 20°C to the final temperature. The specific heat capacity of water is given as 4200 J/kgK, and the mass of the water is 500g. Therefore, the energy required can be calculated as:
Energy required = (500g) × (4200 J/kgK) × (final temperature - 20°C)
Since the energy released by the steam is equal to the energy required by the water, we can set up the equation:
6.78 × 10^7 J = (500g) × (4200 J/kgK) × (final temperature - 20°C)
Now, we can solve for the final temperature:
(final temperature - 20°C) = (6.78 × 10^7 J) / ((500g) × (4200 J/kgK))
(final temperature - 20°C) = 32.14°C
final temperature = 32.14°C + 20°C
final temperature ≈ 52.14°C
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Levi decides to examine the effect of fertilizer on the growth of tomato plants. He chooses four plants for his experiment and applies varying amounts of fertilizer to the three of them. He does not apply fertilizer to one plant.
Over a 15-day period, the plants receive fertilizer on Days 1, 4, 7, 10, and 13. Levi measures the height of all of his plants with a meter stick on Days 3, 6, 9, 12, and 15. He also makes sure to hold all experimental factors constant except for the fertilizer.
Which statement describes what Levi did to prepare the control group in his experiment?
Levi applied different amounts of fertilizer to three of his plants.
Levi did not apply any fertilizer to one of his plants..
Levi held all experimental factors constant except for fertilizer., ,
Levi measured his plants on five separate days.
Answer:
Levi did not apply any fertilizer to one of his plants..
Explanation:
In an experiment, there are two major groups namely: control group and experimental group. Control group is the group in an experiment that does not receive the experimental treatment i.e. the group which the independent variable is not applied to.
In this case, Levi is trying to examine the effect of fertilizer on the growth of tomato plants where he used varying amounts of fertilizer on three of the four plants he used for the experiment. The fourth plant did not receive any amount of fertilizer, which is the independent variable (variable being manipulated or changed). This means that Levi prepared the control group in his experiment by NOT APPLYING ANY FERTILIZER TO ONE OF HIS PLANTS.
calculate the magnitude of the effort in the given
what are the effects/impacts of electromagnetism to our world??
Answer:
Electromagnetic radiation is one of the most important ways of the energy redistribution in the Universe within a very large energy spectrum of photons; from the microwave background radiation up to the very high energy photons emitted by the explosing stars. Low energy photons interact only with molecules and atoms while the highest energy photons are able to transform atomic nuclei and convert into particle antiparticle pairs.
Explanation:
An ambulance siren has a frequency of 650 Hz and is moving away from you at 35 m/s. What frequency will you perceive? Use 346 for the speed of sound.
590 Hz is the answer to the question
An ambulance siren has a frequency of 650 Hz and is moving away from you at 35 m/s. What frequency will you perceive? Use 346 for the speed of sound.
Answer:
59.71 Hz
Explanation:
Frequency: 650 Hz
Velocity: 35 m/s
Speed of sound: 346
f = f(v / v + speed of sound)
f = 650(35 / 35 + 346)
Evaluate and you would perceive a frequency of 59.71 Hz
The effort needed when a simple machine is used is best described by which of these statements?
Answer:
effort effort effort effort effort effort
How can a luminous object convert into a non-luminous object?
pls helppp...
Answer:
Explanation:
A luminous object is one that emits light, whereas a non-luminous object does not emit light on its own. The process of a luminous object becoming a non-luminous object can occur in several ways, including:
Running out of fuel: Many luminous objects, such as stars, emit light and heat as a result of nuclear fusion reactions that occur within them. However, these reactions require fuel to continue, and when the fuel runs out, the luminosity of the object will decrease until it is no longer emitting significant amounts of light.
Cooling down: Some luminous objects, such as incandescent light bulbs, emit light as a result of being heated to high temperatures. However, as they cool down, they emit less light and eventually become non-luminous.
Changing physical state: Some luminous objects, such as fire, emit light and heat as a result of a chemical reaction. When the fuel for the reaction is exhausted, the fire will extinguish and the object will no longer be luminous.
In summary, a luminous object can become non-luminous when it runs out of fuel, cools down, or undergoes a physical change that stops the process that was causing it to emit light.
Please HELP!!! I will give brainliest to whoever gives honest help!!! A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the radius of the circular orbit. Determine the speed of the satellite. Determine the period of the orbit.
Given that,
Mass of satellite = 500 kg
Gravitational force = 3000 N
We need to calculate the radius of the circular orbit
Using formula of gravitational force
\(F_{g}=\dfrac{GMm}{(R+h)^2}\)
Where, G = gravitational constant
R = radius of earth
h = radius of the circular orbit
M = mass of earth
m = mass of satellite
Put the value into the formula
\(3000=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}}{(6.4\times10^{6})^2+h^2}\)
\(h^2=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}\)
\(h=\sqrt{\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}}\)
\(h=5073460.35\ m\)
\(h=5.1\times10^{6}\ m\)
(II). We need to calculate the speed of the satellite
Using formula of velocity
\(v=\sqrt{\dfrac{GM}{r}}\)
Put the value into the formula
\(v=\sqrt{\dfrac{6.67\times10^{-11}\times6\times10^{24}}{5.1\times10^{6}}}\)
\(v=8858.36\ m/s\)
\(v=8.8\times10^{3}\ m/s\)
\(v=8.8\ km/s\)
(III). We need to calculate the period of the orbit
Using formula of time period
\(T=2\pi\sqrt{\dfrac{r^3}{GM}}\)
Put the value into the formula
\(T=2\pi\sqrt{\dfrac{(5.1\times10^{6})^3}{6.67\times10^{-11}\times6\times10^{24}}}\)
\(T=3617.40\ sec\)
\(T=1.00\ hr\)
Hence, (I). The radius of the circular orbit is \(5.1\times10^{6}\ m\)
(II). The speed of the satellite is 8.8 km/s.
(III). The period of the orbit is 1.00 hr.
The work done in lifting a brick of mass 2kg through a height of 5m above the ground will be
(A)2.5J
(B)10J
(C)50J
(D)100J
Answer:
D. 100 J
Explanation:
Given
Mass (m) = 2 kg
Height (h) = 5 m
Acceleration due to gravity (g) = 10 m/s²
Now
Work done(W)
= m * g * h
= 2 * 10 * 5
= 100 Joule
Hope it will help :)❤
The work done in uplifting a brick having a mass of 2kg along with a height of 5m above ground level would be:
D). 100 J
Given that,
Mass of the brick \(= 2Kg\)
Height of the brick \(= 5m\)
As we know,
Work Done (W) \(= mgh\)
where
m = Mass
g = Acceleration due to gravity
h = height
A.T.Q.
By substituting the given values, we get;
\(Work Done (W)\) \(= 2\) × \(10\) × \(5\) (taking \(g = 10 m/s^2\))
\(= 100 J\)
Thus, the work done is 100 J and hence, option D is the correct answer.
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Which combination of charged spheres and separation distance produces an electrostatic?
Electrostatics is the study of electric charges at rest. When there is no current, it refers to stationary charges. Electrostatic phenomena are due to the presence of one or more electric charges, the distribution of charges in a system, and their interactions. There are two types of charged particles: positive and negative.
Electrostatics occurs when two oppositely charged particles (such as electrons and protons) are separated by a distance. The combination of charged spheres and separation distance that produces an electrostatic is two oppositely charged spheres separated by a distance. Electrostatics is based on the law of attraction and repulsion between two opposite charges and like charges, respectively.
According to Coulomb's law, the force between two charges is proportional to their magnitudes and inversely proportional to the square of the distance between them.
The electrostatic force between two charges can be calculated using the following equation: F = kq1q2/r2, where F is the electrostatic force between two chargesq1 and q2 are the magnitudes of the charges, r is the distance between the charges, k is Coulomb's constant (9 x 109 Nm2/C2).
The combination of charged spheres and separation distance that produces an electrostatic is two oppositely charged spheres separated by a distance.
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The amount of friction depends on the weight of the objects pressing together.
Answer:
The amount of friction depends on the force pushing the surfaces together. If this force increases, the hills and valleys of the surfaces can come into closer contact. The close contact increases the friction between the surfaces. Objects that weigh less exert less downward force than objects that weigh more.
Explanation:
Friction depends partly on the smoothness of the contacting surfaces, a greater force being needed to move two surfaces past one another if they are rough than if they are smooth.
help me pls its for my science class i need to show my work
Answer:
P = 5880 J
Explanation:
Given that,
The mass of the block, m = 30 kg
The block is sitting at a height of 20 m.
The block will have gravitational potential energy. The formula for gravitational potential energy is given by :
\(P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J\)
So, the required potential energy is equal to 5880 J.
!!! i'll give brainliest to whoever can answer this for me !!!
you have to match the letters in the picture to the list of energy types
Answer:
you have to match the letters in the picture to the list of energy types
if the power of sound at the source outlet is 100 w, what is its intensity at 4 m away from the source?
The intensity of sound is inversely proportional to the square of the distance from the source. The intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).
The intensity of sound is defined as the power per unit area. According to the inverse square law for sound propagation, the intensity of sound is inversely proportional to the square of the distance from the source. Mathematically, it can be expressed as
\(I=P/(4\pi r^{2})\)
where I is the intensity, P is the power, and r is the distance from the source.
Given that the power of sound at the source outlet is 100 W and the distance from the source is 4 m, we can substitute these values into the formula. Thus, we have
\(I = 100 W / (4\pi (4 m)^2)\)
Simplifying this expression, we find that the intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).
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what is one limitation of using a saltwater aquarium to model the ocean?
A. It can show only a small part of the actual ocean.
B. It can show how different ocean animals interact with each other.
C. It can show how certain plants grow in the ocean.
D. It can show how light affects ocean organisms.
Using a saltwater aquarium to model the ocean has limitations, such as showing only a small part of the actual ocean and being unable to replicate the vastness and complexity of the ocean ecosystem.
Explanation:One limitation of using a saltwater aquarium to model the ocean is that it can only show a small part of the actual ocean. Since an aquarium is confined and limited in size, it cannot realistically replicate the vastness and complexity of the ocean ecosystem. For example, it may not have the space to accommodate large marine animals like whales or the turbulent currents that exist in the open ocean. Therefore, it is important to recognize that while a saltwater aquarium can provide some insights into the ocean, it cannot fully capture the dynamic nature and diverse interactions found within the entire ocean ecosystem.
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A solenoid of radius 4.5 cm has 740 turns and a length of 25 cm. (a) Find its inductance. mH (b) Find the rate at which current must change through it to produce an emf of 70 mV. (Enter the magnitude.) A/s
To find the inductance of the solenoid, we can use the formula for the inductance of a solenoid: L = \((μ₀ * N² * A) / l,\) Once we have the inductance, we can calculate the rate of change of current required to produce a emf.
To find the inductance of the solenoid, we can use the formula L = \((μ₀ * N² * A) / l,\)where μ₀ is the permeability of free space \((4π × 10^(-7) T·m/A)\), N is the number of turns (740), A is the cross-sectional area \((π * r²)\), and l is the length (25 cm). By substituting the given values, we can calculate the inductance in millihenries (mH).
To determine the rate at which the current must change through the solenoid to produce an emf of 70 mV, we can use the formula ε = \(-L * (dI/dt)\), where ε is the emf and L is the inductance. Rearranging the formula, we can solve for dI/dt by dividing both sides by -L. Substituting the given values of ε (70 mV) and L (in the units obtained in part a), we can calculate the rate of change of current in amperes per second (A/s) required to produce the given emf.
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The ____ is a line drawn at a right angle to a barrier. a. normal c. node b. ray d. wave front
Answer:
a. normal
Explanation:
In the field of physics the normal is a line drawn at a right angle to a barrier. In other words the normal line is the line that is drawn perpendicular (right angle, 90 degrees) to the reflective surface of a mirror, or the particular boundary in which refraction occurs at the point of incidence of a light ray. This can be seen in the picture attached below.
GIRL HELPP ME WHAT U WAITING FO JKJK TAKE UR TIME SHAWTY
the answer is convection
Inside a freely-falling elevator, there would be no A) gravitational force on you. B) apparent weight for you. C) both of these D) none of these.
Inside a freely-falling elevator, there would be no apparent weight for you.So option B is correct.
Inside a freely-falling elevator, there is still a gravitational force acting on you. However, since both you and the elevator are falling at the same rate, you would experience a sensation of weightlessness. Your apparent weight, which is the force exerted on a body due to gravity, would be zero. This is because there is no contact force between you and the elevator floor that would provide a normal force to counteract gravity. Therefore, the correct option is that there would be no apparent weight for you.
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A mass weighing 4 kg is attached to a spring whose constant is 2 kg/sec² Assuming that a damping force numerically equal to 2 times the instantaneous velocity acts on the system, determine the equation of motion if the mass is initially released from rest from a point 3 m below the equilibrium position. Find the equation of motion if the mass is driven by an external force to f(t) = 10cos3t
The equation of motion if the mass is driven by an external force to f(t) = 10cos3t is 4d²x/dt² + 2dx/dt + 2x = 10cos(3t)
To determine the equation of motion for the given system, we can apply Newton's second law of motion. Let's denote the displacement of the mass from the equilibrium position as x(t), and the instantaneous velocity as v(t).
When the mass is released from rest, the forces acting on it are the spring force and the damping force. The spring force is given by Hooke's law as F_spring = -kx, where k is the spring constant. In this case, k = 2 kg/sec². The damping force is numerically equal to 2 times the instantaneous velocity, so F_damping = -2v.
Applying Newton's second law, we have:
md²x/dt² = F_spring + F_damping
4d²x/dt² = -2x - 2v
Since v = dx/dt, we can rewrite the equation as:
4d²x/dt² = -2x - 2(dx/dt)
Simplifying further, we have:
4d²x/dt² + 2dx/dt + 2x = 0
This is the equation of motion for the given system when the mass is released from rest.
If the mass is driven by an external force f(t) = 10cos(3t), the equation of motion becomes:
4d²x/dt^2 + 2dx/dt + 2x = f(t)
Substituting f(t) = 10cos(3t), we have:
4d²x/dt² + 2dx/dt + 2x = 10cos(3t)
This equation describes the motion of the system when driven by the external force f(t) = 10cos(3t).
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Coherent light with wavelength 400 nm passes through two very narrow slits that are separated by 0.200 mm, and the interference pattern is observed on a screen 4.00 m from the slits. a. What is the width (in mm) of the central interference maximum? b. What is the width of the first-order bright fringe?
a. The width (in mm) of the central interference maximum is 8 mm
b. The width of the first-order bright fringe is 8mm
we are given the information that Coherent light with wavelength 400 nm passes through two very narrow slits that are separated by 0.200 mm, and the interference pattern is observed on a screen 4.00 m from the slits. Since we know that:
Sinθ≈θ=(m+1/2)λ/d, where d is the distance, λ is the wavelength and the vertical distance y(m) from the central maximum to the mth minima can be defined as
tanθ≈θ=y(m)/D
solving the above equation we get :
y(m)=(m+12)λD/dy(m), for the width of the central maximum for the distance between the m=0 and m=-1 minima:
y(0)−y(1)=(1/2)λD/d−(−1/2)λD/d
=λD/d
=(400×10−9m)(4m)/2×10−4m = 0.008m=8mm
Since y(0)−y(−1) is is independent of m. So, the distance between adjacent minima is always the same and the width of the first-order bright fringe will be :
y(1)−y(0)=8mm
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A pitcher throws an overhand fastball from an approximate height of 2.65 m and at an angle of 2.5° below horizontal. The catcher catches the ball high in the strike zone, at a height of 1.02 m above the ground. If the pitcher's mound and home plate are 18.5 m apart, what is the initial velocity of the pitch?
Answer:
The initial velocity of the pitch is approximately 36.5 m/s
Explanation:
The given parameters of the thrown fastball are;
The height at which the pitcher throws the fastball, h₁ = 2.65 m
The angle direction in which the ball is thrown, θ = 2.5° below the horizontal
The height above the ground the catcher catches the ball, h₂ = 1.02 m
The distance between the pitcher's mound and the home plate = 18.5 m
Let 'u' represent the initial velocity of the pitch
From h = \(u_y\)·t + 1/2·g·t², we have;
\(u_y\) = The vertical velocity = u·sin(θ) = u·sin(2.5°)
h = 2.65 m - 1.02 m = 1.63 m
uₓ·t = u·cos(θ) = u·cos(2.5°) × t = 18.5 m
∴ t = 18.5 m/(u·cos(2.5°))
∴ h = \(u_y\)·t + 1/2·g·t² = (u·sin(2.5°))×(18.5/(u·cos(2.5°))) + 1/2·g·t²
1.63 = 8.5·tan(2.5°) + 1/2 × 9.8 × t²
t² = (1.63 - 8.5·tan(2.5°))/(1/2 × 9.8) = 0.25691469087
t = √(0.25691469087) ≈ 0.50686752763
t ≈ 0.50686752763 seconds
u = 18.5 m/(t·cos(2.5°)) = 18.5 m/(0.50686752763 s × cos(2.5°)) = 36.5334603 m/s ≈ 36.5 m/s
The initial velocity of the pitch = u ≈ 36.5 m/s.