The critical radius (r*) when ice homogeneously nucleates at -40°C is approximately 1.61 × 10^(-10) meters.
How to calculate the critical radius of an element?The critical radius (r*) is a parameter in the theory of nucleation that represents the size of the nucleus at which the transition from the liquid phase to the solid phase (e.g., ice formation) becomes thermodynamically favorable. It can be calculated using the following equation:
r* = - (2 * γ) / ΔH
Given values are:
(Latent Heat of Fusion) ΔH = -3.1 × 10^8 J/m^3
(Surface Free Energy) γ = 25 × 10^(-3) J/m^2
Now, let's substitute the given values into the formula:
r* = - (2 * 25 × 10^(-3) J/m^2) / (-3.1 × 10^8 J/m^3)
r* = (50 × 10^(-3) J/m^2) / (3.1 × 10^8 J/m^3)
r* ≈ 1.61 × 10^(-10) m
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what is the law of conversation of mass
Answer:
Law of conversation of mass
Explanation:
According to the law of conservation of mass, mass cannot be made or destroyed. The energy can only be transferred from one state of matter to another. When the mass is changed from one state of matter to another, the mass is rearranged and changed but is not destroyed. Thus it can be concluded that during a chemical reaction, the mass of the reactants and the products remain the same.
what kind of metal is bronze? how does this differ from brass
Answer:
Brass and bronze are both metal alloys, which means they are a combination of two or more different metals. Brass is composed of copper and zinc, whereas bronze is made up of copper and tin, sometimes with other elements such as phosphorus or aluminium added in.
Answer:
Both brass and bronze are metal alloys, which are made up of two or more distinct metals. Brass is comprised of copper and zinc, while bronze is formed of copper and tin, with the addition of phosphorous or aluminum.
Explanation:
Hope it helps;)
Suppose the interaction between two atoms by the Lennard-Jones potential: ULJ = B/r^12 - A / r^6 where the values of A and B are known to be A = 10^-77 J x m^6 and B = 10^-134 J x m^12.
What does the Lennard-Jones potential predict for the separation r=r eq
hen the energy is at the minimum (equilibrium) value, U min. What is the u min fot this interaction at T=298 K ? What is the ratio of U min to the purely attractive van der Waals component of the interaction potential at r eq.
What is the ratio of r eq to r 0 defined by u(r 0 )=0. 4. What is the ratio of r s to r 0 , where r s is the separation where the magnitude of the (attractive adhesion) force is maximum, F max . What is the value for F max between the two atoms?
a) The Lennard-Jones potential predicts the separation r_eq at the minimum energy U_min.
b) The U_min for this interaction at T=298 K is the value obtained from the Lennard-Jones potential equation when r=r_eq.
c) The ratio of U_min to the purely attractive van der Waals component of the interaction potential at r_eq can be calculated by comparing the attractive part (-A/r^6) to the total potential energy U_min.
d) The ratio of r_eq to r_0, where u(r_0)=0.4, can be determined by finding the value of r_eq where the potential energy is equal to 0.4 times the total potential energy at r=r_0.
e) The ratio of r_s to r_0, where r_s is the separation where the magnitude of the attractive adhesion force is maximum, can be determined by finding the value of r where the derivative of the potential energy with respect to r is equal to zero.
f) The value of F_max between the two atoms can be obtained by taking the negative derivative of the potential energy equation with respect to r and evaluating it at r=r_s.
a) The Lennard-Jones potential provides information about the relationship between energy and separation between two interacting atoms.
At the minimum energy (U_min), the potential predicts the separation r_eq, which corresponds to the equilibrium distance between the atoms. This is the distance at which the energy of the system is at its lowest point.
b) To determine the value of U_min at a given temperature (T=298 K), you can substitute the equilibrium separation r_eq into the Lennard-Jones potential equation and calculate the resulting energy value.
This will give you the U_min for the interaction.
c) The Lennard-Jones potential consists of two components: an attractive component (-A/r^6) and a repulsive component (B/r^12).
The ratio of U_min to the purely attractive van der Waals component of the interaction potential at r_eq can be calculated by comparing the magnitude of the attractive component to the total potential energy at the equilibrium separation.
This ratio provides insights into the relative contribution of the attractive force to the overall potential energy at equilibrium.
d) The ratio of r_eq to r_0 can be determined by finding the value of r_eq where the potential energy is equal to 0.4 times the total potential energy at r=r_0.
In other words, you need to solve the Lennard-Jones potential equation for r_eq when the potential energy is equal to 0.4 times the potential energy at r=r_0.
e) The ratio of r_s to r_0 is obtained by finding the value of r where the magnitude of the attractive adhesion force is maximum.
This can be determined by finding the separation r where the derivative of the potential energy equation with respect to r is equal to zero.
The value of r_s represents the separation at which the attractive force between the atoms is strongest.
f) The value of F_max between the two atoms can be obtained by taking the negative derivative of the Lennard-Jones potential energy equation with respect to r and evaluating it at r=r_s.
This will give you the magnitude of the maximum attractive adhesion force between the atoms.
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in descriptive scientific investigations scientis often make observations to understand the interacting parts of a complex
The answer is System.
When a scientific investigation is in progress, its used to perform and understand the natural phenomenon that goes on using the scientific method. Since this is a descriptive investigation, it provides a descriptive account of any system by looking at it without any prior knowledge to that subject. This method of investigation does not use a hypothesis. Thus, proves our answer correct.
Best of Luck!
Answer:
The answer is System.
Explanation:
When a scientific investigation is in progress, its used to perform and understand the natural phenomenon that goes on using the scientific method. Since this is a descriptive investigation, it provides a descriptive account of any system by looking at it without any prior knowledge to that subject. This method of investigation does not use a hypothesis. Thus, proves our answer correct.
Please the app isn’t working and I can’t find other questions that got answered
Given:
Sum of masses of two isotopes = 371.9087 u
Re-185 natural abudance = 37.40%
Re-187 natural abudance = 62.60%
Known:
atomic weight of Re = 186.207 u
Atomic mass of Re-185:
To find the atomic mass of Re-185, take the total mass given and subtract atomic weight.
abundance of Re-185 = 37.40% = 0.3740
(371.9087 - x) = atomic weight of Re-187 in u
To find mass of Re-187:
abundance of Re-187 = 62.60% = 0.6260
Solution:
Step 1. Multiply x times the abundance of Re-185 and multiply (371.9087 - x) times the abundance of Re-187.
Re-185: (0.3740)(x) = 0.3740x
Re-187: (0.6260)(371.9087 - x) = 232.8148462 - 0.6260x
Step 2. Add the results and set them equal to 186.207.
0.3740x + 232.8148462 - 0.6260x = 186.207
Step 3. Solve for x by subtracting 232.8148462 from both sides and then divide both sides by -0.2520.
0.3740x + 232.8148462 - 0.6260x - 232.8148462 = 186.207 -
232.8148462
0.3740x - 0.6260x = -46.6078462
-0.2520x = -46.6078462
-0.2520x/-0.2520x = -46.6078462/-0.2520
x = 184.9517706 u
Step 4. Atomic weights of Re-185 and Re-187.
x = 185.0 u = the atomic weight of Re-185
(371.9087 - 184.9517706) = 186.9569294 = 187.0 u = the atomic weight of Re-187
Therefore the atomic weight of Re-185 is 185.0 u, and the atomic weight of Re-187 is 187.0 u.
Calculate the volume in L of 11.6 moles of Neon at 120 K when it has a pressure of 25.9 atm
Answer:
The volume of the gas is approximately 4.41 liters
Explanation:
The details of the data of the Neon gas are;
The number of moles of Neon gas present, n = 11.6 moles
The temperature of the sample of Neon gas, T = 120 K
The pressure of the sample of the Neon gas, P = 25.6 atm
By the ideal gas equation, we have;
P·V = n·R·T
Where;
R = The universal gal constant = 0.08205 L·atm·mol⁻¹·K⁻¹
Therefore, we get;
V = n·R·T/P
Which gives;
V = 11.6 moles × 0.08205 L·atm·mol⁻¹·K⁻¹ × 120 K/(25.9 atm) ≈ 4.4097915 L
The volume of the gas, V ≈ 4.41 L.
Each cart below is pushed across a room with the same amount of force. Which cart will result in the greatest change in speed?
F.A 75 kg cart being pushed with a 200 N force
G.A 125 kg box being pushed with a 200 N force
H.A 350 kg box being pushed with a 200 N force
J.A 450 kg cart being pushed with a 200 N force
The cart with the greatest change in speed is the cart with a mass of 75 Kg
Acceleration is defined as the change in velocity of an object with time. Also, acceleration is related to the force and mass according to the following equation:
Acceleration (a) = Force (F) / mass (m)
a = F / mTo answer the question, we shall determine the acceleration of each cart.
For cart of mass 75 kgMass (m) = 75 KgForce (F) = 200 NAcceleration (a) =?a = F / m
a = 200 / 75
a = 2.67 m/s²For cart of mass 125 kgMass (m) = 125 KgForce (F) = 200 NAcceleration (a) =?a = F / m
a = 200 / 125
a = 1.6 m/s²For cart of mass 350 kgMass (m) = 350 KgForce (F) = 200 NAcceleration (a) =?a = F / m
a = 200 / 350
a = 0.57 m/s²For cart of mass 450 kgMass (m) = 450 KgForce (F) = 200 NAcceleration (a) =?a = F / m
a = 200 / 450
a = 0.44 m/s²From the above illustrations, we can see that the cart with a mass of 75 K has the greatest change in speed (i.e 2.67 m/s²)
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Answer:
D
Explanation:
F. 200-75=125
G. 20-125=75
H. 350-200=150
J. 450-200=250
250 is the biggest number so it has the biggest change
At what year will Sagittarius be visible from the earth’s North Pole?
minerals are classified by specifying the principal . choose one: a. anion or anion group b. crystal structure c. mineral habit d. cation or cation group
Minerals are classified by specifying the principal, anion or anion group. The correct option is option A among all the given options.
What is mineral?Because the anion and anion group does have the greatest impact on the characteristics of the mineral, minerals are arranged according with anion and anion group that they contain. An example of an anion is SO42-.
Probably the most prevalent group in the mantle and crust are silicates, which have the anion SiO44-. Minerals are classified by specifying the principal, anion or anion group.
Therefore, minerals are classified by specifying the principal, anion or anion group. The correct option is option A.
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what is a mixture of elements and compounds
The substance in the image above would be classified as a mixture of elements (option E).
What is a compound and mixture?A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.
On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.
According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.
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When you add salt to water it makes the solution boil
A. faster.
B. at a lower temperature.
C. at a higher temperature.
D. slower.
Answer:
A i believe
Explanation:
1.1. A wind farm has steady winds at 12 m/s. Determine the following: 1.1.1. Wind energy per unit mass. 1.1.2. Wind energy for a mass of 6 kg. 1.1.3. Wind energy for a flowrate of 1000 kg/s of air.
The main answer to the question can be summarized as follows:
1) The wind energy per unit mass can be calculated using the equation 1/2 * v^2, where v is the wind speed in meters per second. This equation represents the kinetic energy per unit mass of the wind.
2) To calculate the wind energy for a mass of 6 kg, we multiply the wind energy per unit mass (calculated in step 1) by the mass of 6 kg. This will give us the total wind energy for the given mass.
3) To find the wind energy for a flow rate of 1000 kg/s of air, we need to multiply the wind energy per unit mass (calculated in step 1) by the flow rate of 1000 kg/s. This will give us the total wind energy for the given flow rate.
Explanation:
To determine the wind energy per unit mass, we use the equation 1/2 * v^2, where v represents the wind speed. By substituting the given wind speed of 12 m/s into the equation, we can calculate the wind energy per unit mass.
To find the wind energy for a specific mass, such as 6 kg, we multiply the wind energy per unit mass (calculated in step 1) by the given mass. This will give us the total wind energy for the specified mass.
To calculate the wind energy for a given flow rate, such as 1000 kg/s of air, we multiply the wind energy per unit mass (calculated in step 1) by the flow rate. This will give us the total wind energy for the specified flow rate.
It is important to note that the units of wind speed, mass, and flow rate must be consistent (e.g., all in meters per second or all in kilograms) to ensure accurate calculations.
the concept of wind energy, the factors affecting wind power generation, and the importance of wind speed in harnessing wind energy.
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2 Calculate the volume occupied, at rtp, 12.5 moles of sulfur dioxide gas. (One mole of any gas occupies a
volume of 24 dm³ at rtp.)
Answer:
300 dm³
Explanation:
According to the information given in this problem, SO₂ is 24 dm³/mol at rtp.
We are trying to find the volume of 12.5 moles of SO₂, so we can do the following math to solve:
12.5 mol SO₂ × 24 dm³/mol ⇒ mol cancels out, leaving us with dm³
300 dm³
Therefore, the volume occupied is 300 dm³
he amount of radiation a substance will absorb is di- rectly proportional to its concentration as defined by ___________ law.
The law that defines the direct proportionality between the concentration of a substance and the amount of radiation it will absorb is known as the Beer-Lambert law.
This law states that the absorption of light or radiation by a substance is proportional to the concentration of the substance and the path length of the radiation through the substance. Mathematically, the Beer-Lambert law is expressed as A = εcl, where A is the absorbance of the substance, ε is the molar absorptivity or extinction coefficient, c is the concentration of the substance, and l is the path length of the radiation. This law is widely used in analytical chemistry and spectroscopy to determine the concentration of substances in solution or to study the interaction of radiation with matter. y = kx.
where k is the proportionality constant.
As a result, the point (x, kx) is the proportionality constant.
Generally speaking, this is the point:
(x, k * f (x))
f (x) is a function that is proportional to x where.
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The mechanism of glyceraldehyde-3-phosphate dehydrogenase does NOT involve. true or fasle?
The mechanism of glyceraldehyde 3-phosphate dehydrogenase in glycolysis does not include phosphorylation of the substrate using ATP. Hence, option a is false.
What is glyceraldehyde 3-phosphate dehydrogenase ?Glyceraldehyde 3-phosphate dehydrogenase, or GAPDH, is an enzyme with a molecular mass of approximately 37 kDa that catalyzes glycolysis' sixth stage, converting glucose into energy and carbon molecules.
Initially, the carbonyl group of GAP is attacked by a cysteine residue in the active site of GAPDH, resulting in the formation of a hemithioacetal intermediate (covalent intermediate).
At the active site of the enzyme, a histidine residue deprotonates the hemithioacetal . In the ensuing thioester intermediate, deprotonation promotes the reformation of the carbonyl group and the ejection of a hydride ion. Not any step include the use of ATP. Thus, option a is false.
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Your question is incomplete. But, your complete question probably was:
The mechanism of glyceraldehyde-3-phosphate dehydrogenase does NOT involve. true or false?
A phosphorylation of the substrate using ATP.
B oxidation and phosphorylation of the substrate.
C a covalent intermediate.
D an active site histidine to serve as a proton acceptor.
help me with this please
Answer:
Gap 1, S-Phase, Gap 2, Prophase, Metaphase, Anaphase, Telophase, Cytokinesis
Hope this helps.
Energy is the work that done by a force acting through a distance And involves motion
Answer:
true
Explanation:
energy is the energy to do things
and there is a force in our bodies wich is giving out energy through a distance
In dimensional analysis you should always have the same units adjacent to each other (top left to bottom right)
O True
O False
Answer:
False
Explanation:
Calculate the wavelength (in nm) of light with a frequency of 5.98 x 1014 s 1. What is the energy of a photon of light that has a frequency of 9.89 x 1013 Hz?
The wavelength of the light is approximately 500 nm. The energy of the photon of light is approximately 6.56 x 10-20 J.
Answer: Question 1:The formula relating wavelength, frequency, and the speed of light is given by:c = fλHere,λ = wavelength, f = frequency, c = speed of lightI. n the problem, frequency is given as 5.98 x 1014 s-1. Therefore, using the formula, the wavelength of light can be calculated as follows:λ = c/f= (3 x 108 m/s)/(5.98 x 1014 s-1)≈ 500 nm
Therefore, the wavelength of the light is approximately 500 nm.
Question 2:The formula relating energy and frequency of light is given by:E = hfwhereE = energy of photonh = Planck's constant = 6.626 x 10-34 J s (Joule seconds)f = frequency of lightIn the problem, the frequency of light is given as 9.89 x 1013 Hz. Therefore, using the formula, the energy of the photon of light can be calculated as follows:E = hf= (6.626 x 10-34 J s) x (9.89 x 1013 Hz)≈ 6.56 x 10-20 J
Therefore, the energy of the photon of light is approximately 6.56 x 10-20 J.
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classify the following into physical and chemical changes a) drying of a shirt in the sun b) rising of hot air over a radiator c)rusting of iron d)mixing of sand with sugar e) digestion f) milk turns to curd g) dissolution of salt in water
Answer:
A. physical change
b. physical change
c. chemical change
d. chemical change
can someone help me solve the questions below using the data table below please
DATA TABLE:
Mass of flask and vinegar solution- 25.17g
Mass of flask- 15.12g
Volume of vinegar solution (in mL)- 10.00ml
Initial volume of NaOH (in mL)-0.00ml
Final volume of NaOH (in mL)-39.00ml
CALCULATIONS:
Mass of vinegar solution- 10.0503g
Volume of NaOH used in titration (in mL)-39.00ml
The percent by mass of acetic acid in the vinegar is 2.33%.
Below are the steps to solve the given problem using the data table given below:
Step 1: Calculate the mass of the vinegar. Given,Mass of flask and vinegar solution- 25.17gMass of flask- 15.12gMass of vinegar solution = Mass of flask and vinegar solution - Mass of flask= 25.17 g - 15.12 g= 10.05 g
Step 2: Calculate the moles of NaOH used in the titration.Molarity of NaOH solution is 0.1 M.Moles of NaOH = Molarity × Volume of NaOH usedMoles of NaOH = 0.1 M × 39.00 mL (since the initial volume of NaOH is 0.00 mL)Moles of NaOH = 0.0039 moles
Step 3: Determine the moles of acetic acid used in the reaction.The balanced chemical equation for the reaction between NaOH and acetic acid (the main component of vinegar) is given below:CH3COOH + NaOH → CH3COONa + H2OMoles of NaOH = Moles of CH3COOH (since they react in a 1:1 ratio)Moles of CH3COOH = 0.0039 moles
Step 4: Calculate the mass of acetic acid used in the reaction.Molar mass of acetic acid is 60.05 g/mol.Mass of CH3COOH = Moles of CH3COOH × Molar mass of CH3COOH= 0.0039 moles × 60.05 g/mol= 0.234 gStep 5: Calculate the percent by mass of acetic acid in the vinegar.Percent by mass of acetic acid = (Mass of CH3COOH / Mass of vinegar solution) × 100%= (0.234 g / 10.05 g) × 100%= 2.33%.
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Neils Bohr's model of the hydrogen atom explains the observed lines in the hydrogen spectrum as a consequence of:
Niels Bohr's model of the hydrogen atom explains the observed lines in the hydrogen spectrum as a consequence of the electron's quantized energy levels.
According to Bohr's model, electrons can only occupy certain discrete energy levels around the nucleus. When an electron transitions between these energy levels, it emits or absorbs energy in the form of electromagnetic radiation, such as light.
The specific wavelengths of light emitted or absorbed correspond to the energy differences between the electron's initial and final energy levels. This accounts for the distinct lines observed in the hydrogen spectrum, known as the emission or absorption lines, which are characteristic of the transitions of electrons within the hydrogen atom.
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For 2 hours, Leah was driving east at one-half of her car's top speed. Her car can go at a maximum speed of 180 kilometers per hour. In this time, how far did Leah drive?
Answer:
180 kilometers in 2 hours.
Explanation:
To find the distance Leah drove, we need to first determine her average speed. Since Leah was driving east at one-half of her car's top speed, her average speed was 180/2 = 90 kilometers per hour.
Next, we can use this speed to determine the distance she traveled. Since Leah was driving for 2 hours at an average speed of 90 kilometers per hour, she traveled 2 * 90 = 180 kilometers.
Therefore, Leah drove 180 kilometers in 2 hours while driving east at one-half of her car's top speed.
(b)
A student filters a mixture.
Figure 1 shows the apparatus.
Beaker.
Mixture
Figure 1
F
Flask
Filter paper cone
Suggest one improvement to the apparatus.
(1)
One improvement to the filtration assembly is the presence of glass rod as glass rod helps in negation of adhesion between glassware and the supernatent.
What is filtration?Filtration is defined as a process by which solid particles which are present in liquid or gaseous medium are allowed to be removed using a filter medium which retains the particles but allows the liquid to pass through.
The requirements for filtration are a filter medium ,fluid containing particles , a mechanical device usually a filter and a driving force.The filter media is classified depending on the pore size of particles which are to be filtered.
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Calculate the minimum of oxygen required for the complete combustion of a mixture of 20cm³ of CO (Carbon Monoxide) and 20cm³ of H₂ (Hydrogen gas)
The minimum amount of oxygen required for the complete combustion of 20cm³ of CO and 20cm³ of H₂ would be 20.16 cm³ at STP.
Stoichiometric problemThe balanced chemical equation for the combustion of CO and H2 is:
CO + 1/2O2 → CO2
H2 + 1/2O2 → H2O
From the equation, we can see that one mole of CO requires 1/2 mole of O2, while one mole of H2 requires 1/2 mole of O2.
20 cm³ CO at STP = 20/24000 = 0.00083 moles CO20 cm³ H2 at STP = 20/24000 = 0.00083 moles H2From the balanced equation, we can see that each mole of CO requires 1/2 mole of O2, while each mole of H2 requires 1/2 mole of O2.
Therefore, we need 0.00083/2 = 0.00042 moles of O2 for the combustion of CO and the same amount for the combustion of H2.
The total amount of O2 required is the sum of the amounts needed for each reactant:
Total O2 required = 0.00042 + 0.00042 = 0.00084 moles0.00084 moles O2 × 24000 cm³/mol = 20.16 cm³ O2Therefore, the minimum amount of oxygen required for the complete combustion of 20 cm³ of CO and 20 cm³ of H2 is approximately 20.16 cm³ at STP.
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Select the correct answer. what makes metals, in particular, good conductors of electricity? a. the ability of electrons to flow throughout the metal b. the absence of charged particles c. the high temperatures required to break metallic bonds d. the presence of positive and negative ions
Answer:
I believe the answer is A. Not completely sure though. : )
What is the difference in the electron withdrawing groups in electrophilic aromatic substitution (ENS) and nucleophilic aromatic substitution (NAS)?
Electrophilic aromatic substitution (EAS) and nucleophilic aromatic substitution (NAS) are two types of reactions that involve substitution of a group on an aromatic ring.
In EAS, electron-withdrawing groups (EWGs) are used to increase the reactivity of the aromatic ring towards electrophiles, leading to substitution of a hydrogen atom. Common examples of EWGs used in EAS include nitro, carbonyl, and halogen groups. In contrast, in NAS, electron-donating groups (EDGs) are used to increase the reactivity of the aromatic ring towards nucleophiles, leading to substitution of a leaving group. Common examples of EDGs used in NAS include amino, alkoxyl, and thiol groups. The difference in the type of groups used reflects the different types of reactivity required for each type of substitution reaction.
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What is the morality of a solution that contains 80.0 G Al2 (SO4)3 (aluminum sulfate) in 625 g H2O?
Answers
Explanations
PLEASE HELP!!!! DUE SOON!!
Use the portion of the periodic table shown below to answer the questions.
A portion of the first three columns of the periodic table is shown. Column one from top to bottom reads 11 sodium 22.990, 19 potassium 39.098, and 37 rubidium 85.468. Column two reads 12 magnesium 24.305, 20 calcium 40.078, and 38 strontium 87.62. Column three reads 21 scandium 44.956 and 39 yttrium 88.906.
Part 1: Name two elements that have the same properties as magnesium (Mg). (4 points)
Part 2: Determine the number of protons, electrons, and neutrons present in an atom of potassium (K). Explain how you determined your answer using complete sentences. (6 points)
Answer:
Explanation:
Calcium and Beryllium are similar to Magnesium because all the three elements belong to the same group and have 2 valence electrons in their outer shell.
Potassium has 19 protons and - since the number of protons is the same as the number of electrons- also 19 electrons. To find out the number of neutrons you have to look at the atomic mass or weight of the element.
The heterosphere is the layer of the atmosphere in which the gases are ________ because of ________.
The heterosphere is the layer of the atmosphere in which the gases are
poorly mixed because of the gravity influence.
What is Heterosphere?This is a part of the atmosphere which is characterized by gases being
separated out as a result of diffusion. This is usually pronounced with
increasing altitude in the atmosphere.
The gases in the layer are poorly mixed as a result of gravity which causes
gases of different weight to separate into layers.
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