The exact location where the light ray will hit on the border will depend on the angles at which the light ray hits each mirror.
If the light ray hits the first mirror and continues to bounce off the other mirrors inside the box, the path of the light ray can be determined using the law of reflection.
The law of reflection states that the angle of incidence is equal to the angle of reflection. Here's how you can determine where the light ray will eventually hit on the border:
1. Start by drawing the first mirror and the incident ray (incoming light ray) hitting the mirror at a certain angle.
2. Use the law of reflection to determine the angle of reflection. This angle will be equal to the angle of incidence.
3. Draw the reflected ray off the first mirror, making sure to extend it in a straight line.
4. Repeat steps 1-3 for each subsequent mirror the light ray encounters.
5. Trace the path of the reflected rays until they eventually hit the border of the box.
6. The point where the last reflected ray hits the border will be the location where the light ray will eventually hit on the border.
It's important to note that the angles at which the light ray strikes each mirror will determine exactly where it will strike the boundary.
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Two trains emit 508-Hz whistles. One train is stationary. The conductor on the stationary train hears a 4.5-Hz beat frequency when the other train approaches. What is the speed of the moving train
The speed of the moving train can be determined using the formula for the Doppler effect. By considering the observed beat frequency and the frequency of the stationary train's whistle, we can calculate the speed of the moving train relative to the conductor.
The beat frequency observed by the conductor is caused by the difference in frequencies between the whistles of the stationary train and the moving train. The beat frequency (\(f_{beat}\)) can be calculated using the formula:
\(f_{beat}\) = | \(f_{source}\) - \(f_{observer}\) |
In this case, the frequency of the stationary train's whistle ( \(f_{source}\) ) is 508 Hz, and the beat frequency observed (\(f_{beat}\)) is 4.5 Hz.
By rearranging the formula, we can determine the frequency observed by the conductor (\(f_{observer}\)):
\(f_{observer}\) = \(f_{source}\) - \(f_{beat}\)
Substituting the given values, we find:
\(f_{observer}\) = 508 Hz - 4.5 Hz = 503.5 Hz
The observed frequency is lower than the frequency of the stationary train's whistle because the moving train is approaching the conductor. The Doppler effect causes a decrease in frequency when the source is moving toward the observer.
The Doppler effect formula for frequency is given by:
\(f_{observer}\) = \(f_{source}\) * (\(v_{sound}\) + \(v_{observer}\)) / (\(v_{sound}\) + \(v_{source}\) )
Assuming the speed of sound (\(v_{sound}\)) is constant, and the speed of the conductor ( \(v_{observer}\)) is negligible compared to the speed of the moving train, we can simplify the equation to:
\(f_{observer}\) = \(f_{source}\) * ( \(v_{sound}\) / ( \(v_{sound}\) + \(v_{source}\)))
Rearranging the equation to solve for the speed of the moving train (\(v_{source}\)), we get:
\(v_{source}\) = \(v_{sound}\) * (\(f_{source}\) / \(f_{observer}\) - 1)
Substituting the known values, with the speed of sound typically around 343 m/s, we can calculate the speed of the moving train.
Hence, the speed of the moving train can be determined by plugging the values into the equation: \(v_{source}\) = 343 m/s * (508 Hz / 503.5 Hz - 1).
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A common brick is about 1.8 times denser than water. what is the apparent weight of a 0.20 m3 block of bricks under water?
Answer:
Pressure of .2 m^3 of bricks:
Pb = ρ g H = 1.8 ρw * 9.80 m/s^2 * .20 m = 1800 * 9.8 * .2 = 3530 Pascals
ρb = 1.8 ρw = 1.8 since the density of bricks is 1.8 that of water
Pw = 1 * 9.8 * 1000 * .2 = 1960 Pascals
W = P * A pressure * Area = Force
Pnet = 1570 Pascals - pressure due to bricks under water
F = 1570 N/m^2 * .2m^2 = 63 N force on pile of bricks
help me plz Your starting fitness level is known as__________. (10 points) a starting point b beginning level c baseline d entry level
Answer:
Would it be starting point?
Explanation:
When you start a sport or something, you may not be good or bad at it. However, as time goes on you are going to improve.
Idk if this helps or not buh yeah
Mechanic pulley system
Help please
Answer:
M g - T = NB vertical force on box B
T - m g = NA vertical force on box A
T must be uniform (same) throughout length of string
(M - m) g = NB + NA = (M + m) a since F accelerates M and m
Note: one can enclose the entire system with no external forces
No net vertical force or horizontal force is present - the net vertical force is A + B + C - masses of these objects * g
One would write a = (M - m) * g / (M + m)
The masses and tensions influence the accelerations of the boxes while considering friction and normal forces on block C.
When box A and B are released, their accelerations can be calculated using Newton's second law, (F = ma), where (F) is the net force and (a) is the acceleration.
The net force is the difference between the gravitational force (mg) and the tension in the rope (T).
For box A:
Net force: \(\rm \(F_{\text{net,A}} = T - mg\)\)
Using \(\rm \(T = m \cdot a_A\)\), where \(\rm \(a_A\)\) is the acceleration of box A:
\(\rm \(ma_A = T - mg\)\\\rm \(a_A = \frac{T}{m} - g\)\)
For box B:
Net force: \(\rm \(F_{\text{net,B}} = mg - T\)\)
Using \(\rm \(T = M \cdot a_B\)\), where \(\rm \(a_B\)\) is the acceleration of box B:
\(\rm \(Ma_B = mg - T\)\\\rm \(a_B = g - \frac{T}{M}\)\)
Now, considering friction and the normal force between block C and the ground:
The friction force \(\rm (\(F_{\text{friction}}\))\) can be calculated using the equation \(\rm \(F_{\text{friction}} = \mu N\)\), where \(\rm \(\mu\)\) is the coefficient of friction and (N) is the normal force.
The normal force (N) is equal in magnitude to the weight of block C \((mg_{C})\) since it's not accelerating vertically:
\(\rm \(N = mg_C\)\)
To summarize:
Acceleration of box A: \(\rm \(a_A = \frac{T}{m} - g\)\)
Acceleration of box B: \(\rm \(a_B = g - \frac{T}{M}\)\)
Friction force on block C: \(\rm \(F_{\text{friction}} = \mu mg_C\)\)
Normal force on block C: \(\rm \(N = mg_C\)\)
The masses and tensions influence the accelerations of the boxes while considering friction and normal forces on block C.
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Is an electron cloud bigger than an atom?
Answer:
no
Explanation:
An electron is one of the components of an atom, so it cannot be larger than that.
Answer:
No, it's not.
Explanation:
The tightly packed nucleus is 100,000 times smaller than the electron cloud.
according to the kinetic-molecular theory, how does a gas expand?
According to the kinetic-molecular theory, a gas expands as the average distance between its particles increases.
According to the kinetic-molecular theory, the expansion of a gas can be understood through the behavior of its individual particles, such as molecules or atoms. The kinetic-molecular theory describes the motion and interactions of these particles and provides insights into the macroscopic properties of gases, including their expansion.
The kinetic-molecular theory states that gas particles are in constant random motion. They move in straight lines until they collide with each other or with the walls of their container. These collisions are elastic, meaning that no energy is lost during the collision. The theory also assumes that the volume occupied by the gas particles themselves is negligible compared to the volume of the container.
When a gas expands, it means that the volume it occupies increases. This expansion occurs due to the increase in the average distance between gas particles. As the gas is heated or if external pressure is reduced, the kinetic energy of the gas particles increases. This increase in kinetic energy leads to an increase in the speed of the gas particles and their frequency of collisions with each other and the container walls.
During the expansion, the gas particles collide with the walls of the container more frequently and with greater force. These collisions exert a pressure on the walls, known as the gas pressure. As the gas expands, the particles collide more frequently and exert a higher pressure on the walls, resulting in the expansion of the gas.
The kinetic-molecular theory helps explain the macroscopic behavior of gases, including their expansion, based on the microscopic motion and collisions of individual gas particles. It provides a theoretical framework for understanding how gases respond to changes in temperature, pressure, and volume.
In summary, according to the kinetic-molecular theory, a gas expands as the average distance between its particles increases. This expansion is a result of the increased speed and frequency of collisions among the gas particles, which exert higher pressure on the walls of the container. The kinetic-molecular theory provides a fundamental understanding of the behavior of gases and their expansion based on the motion and interactions of individual gas particles.
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suppose a clay model of a koala bear has a mass of 0.195 kg and slides on ice at a speed of 0.65 m/s. it runs into another clay model, which is initially motionless and has a mass of 0.36 kg. Both being soft clay, they naturally stick together. What is their final velocity?
Based on the provided information, the final velocity of the system is 0.228 ft/s.
Suppose a clay model of a koala bear has a mass of 0.195 kg and slides on ice at a speed of 0.65 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.36 kg. Both being soft clay, they naturally stick together.
In order to calculate the final velocity, first of all, we can find the initial momentum of the system using the following formula:
Pinitial = m1 * v1 + m2 * v2
Where Pinitial is the initial momentum of the system, m1 is the mass of the first object, v1 is the velocity of the first object, m2 is the mass of the second object, v2 is the velocity of the second object.
Let's substitute the values given in the question.
Pinitial = (0.195 kg) * (0.65 m/s) + (0.36 kg) * 0 (the second object is initially at rest)
Pinitial = 0.12675 kg·m/s
Next, we can find the final momentum of the system using the following formula:
Pfinal = (m1 + m2) * vf
Where Pfinal is the final momentum of the system, m1 is the mass of the first object, m2 is the mass of the second object, vf is the final velocity of the system.
Let's substitute the values given in the question.
Pfinal = (0.195 kg + 0.36 kg) * vf
Pfinal = 0.555 kg·m/s
We know that the total momentum of the system is conserved, so:
Pinitial = Pfinal
0.12675 kg·m/s = 0.555 kg·m/s * vf
vf = 0.12675 kg·m/s / 0.555 kg
vf ≈ 0.228 ft/s (final velocity of the system)
Therefore, the final velocity of the system is approximately 0.228 ft/s.
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How to test a sample of an element to see if it’s metal?
ANSWER and EXPLANATION
We want to identify how to test to see if a sample is a metal or not.
To do this, the malleability of the sample can be tested. This is done by striking the sample with a hammer/mallet.
Metals are malleable i.e. they deform under pressure, compared to non-metals that crack under pressure.
Hence, if after striking it, it can be flattened or deformed then, it is metal but if it cracks or turns to powder, then it is not a metal.
Exploring Newton's Second Law Using Simulations Background: Newton's second law states that when a force acts on an object, it will cause the object to accelerate. The greater the force, the greater the acceleration. The force-1d simulation allows you to explore the relationship between force, mass, and acceleration. The simulation allows you to select different objects (each with a different mass) to which a horizontal force can be applied (by a partner named Joe). Then different aspects of the motion of objects can be measured. Activity 1: Explore the simulation Screenshot of the simulation shown below. Free Body Diagram Show hozontal forces Show total force Fricton On O orO Choose Obect File Cabinet 2000 g Retgerstor (400.0 kg Tethook (10 0 kal Crate 000.0 ka) lerpy Dog (250 ka Ital Poson 0m O meters it006020 20 60 10.0 Aeplesf Graph Applied Force Less Cortols Oravity Nkg Graph Acceleration Graph Velocity Fa Clear Graph Position Mass Il Pass 44 n Helpl Spend 5 minutes exploring the simulator.
Discover the following:
1-How do you select an object? How do you change the mass of the object?
2-How is a push applied? How do you change the force of the push?
3-How do you determine the total force (net) that is applied to the object?
4-Can you turn on the free body diagram?
5-How can you find out about the movement of the object?
6-Can the acceleration of the object be quantified?
7-Can friction be deactivated?
8-How do you "reset" the simulator?
9-What other settings can you change? Should these be changed?
10-Can you record your experiments to be able to review what happened?
Here is a reorganized version of the instructions for better readability:
Object selection: Choose an object from the simulation, such as a file cabinet, refrigerator, tether hook, heavy dog, 250 g Italian sandwich, or crate. Adjust the object's mass using the slider located below its name in the upper left corner.Applying a push: Click and drag the arrow on the right side of the screen to apply a push. Modify the force of the push by using the slider above the arrow.Determining total force: Activate the free body diagram by checking the "Show forces" checkbox in the upper right corner. The free-body diagram displays all forces acting on the object. The total force is the sum of these forces.Free body diagram: The free body diagram can be enabled by clicking the "Show forces" checkbox in the upper right corner.Object's movement: Examine the graphs on the right side of the screen to gather information about the object's position, velocity, acceleration, applied force, and mass.Acceleration measurement: The acceleration graph provides quantitative information about the object's acceleration.Deactivating friction: If desired, uncheck the "Friction" checkbox in the upper right corner to disable friction.Resetting the simulator: Click the "Clear Graphs" button located below the graphs on the right side to reset the simulator.Additional settings: Other settings, such as applied force, gravity, and object position, can be adjusted, but they are notnecessary for exploring the relationship between force, mass, and acceleration.Recording experiments: Capture a screenshot of the simulation and save it to your computer to record your experiments.Learn more about Object selection
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an orthopedic drill uses circular motion to cut a hole in bone. this is an example of what type of energy?
Orthopedic drill is an example of a type of kinetic energy. It uses circular motion to cut a hole in bone.
Orthopedic drillOrthopedic drill is for traumatology cases, and hand-foot surgery, with a wide range of attachments for various applications (punching holes, saws, attaching screws, installing wires, and widening holes), and a powerful and reliable handpiece.
It uses circular motion by rotating on a circular axis due to a change in potential energy into kinetic energy which gives enough speed to make a rotation.
In an orthopedic drill, there is a change in electrical energy into motion energy (kinetic energy).
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four forces are acting on an object in static equilibrium: force 1 (f1) has a magnitude of 46.0 n and is acting at an angle of (45 a) degrees above the positive x-axis. force 2 (f2) has a magnitude of (15 b) n and is acting along the positive x-axis. force 3 (f3) has a magnitude of 34.5 n and is acting along the negative y-axis. find the magnitude of the last force, f4. give your answer in newtons (n) and with 3 significant figures.
When there is no net force operating on the body, equilibrium is achieved. or a closed polygon with four sides will result in a force of zero acting on an identical plane.
Which four sorts of forces are there?There are four basic forces of nature, which you may recall if you recall any of the topics in physics you learnt in school. Gravity, electromagnetic, the weak nuclear force, or the strong nuclear power are listed in no particular order.
Why are there four natural forces?Weak nuclear force, electrostatic field, nuclear force, and gravitational force are the four basic forces of nature. The strong and weak forces are dominant only on the level or subatomic particles and are only effective across very small distances. Magnetic and gravitational forces have a limitless range.
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I need help, what are the steps to solve this , I don’t understand
Which is the most reasonable slit spacing for a transmission diffraction grating?1) 0.001 nm2) 1000 nm3) 1 times 10^(–6) nm4) 1 times 10^6 nm
For the diffraction grating, the slits spacing should be comparable to the wavelength of length incident on the grating to observe the phenomenon of diffraction.
The wavelength of light considered for the for diffraction ranges from,
\(\begin{gathered} 100\text{ nm to 10 }\mu m \\ or \\ 100\times10^{-9}\text{ m to 10}\times10^{-6}\text{ m} \\ or\text{ } \\ 1\times10^{-7}\text{ m or 1}\times10^{-5}\text{ m} \end{gathered}\)By simplifying the given value in meters,
\(\begin{gathered} 1.\text{ 0.001 nm = 0.001}\times10^{-9}\text{ m = 1}\times10^{-12}\text{ m} \\ 2.\text{ 1000 nm = 1000}\times10^{-9}\text{ m} \\ =\text{ 1}\times10^{-6}\text{ m} \\ 3.\text{ 1}\times10^{-6}\text{ nm= 1}\times10^{-6}\times10^{-9}\text{ m} \\ =1\times10^{-15}\text{ m} \\ 4.\text{ 1}\times10^6\text{ nm= 1}\times10^6\times10^{-9}\text{ m} \\ =1\times10^{6-9}\text{ m} \\ =1\times10^{-3}\text{ m} \end{gathered}\)As the value of 1000 nm fall in this range and thus, considered as most reasonable slit spacing.
Hence, option 2 (1000 nm) is the correct answer.
Select the correct answer. Lisa’s doctor tells her that she needs to eat more foods that contain calcium to maintain her bone health. What could happen if Lisa doesn’t follow her doctor’s orders?
A. She could have trouble breathing.
B. She could have a higher risk of skeletal fractures.
C. She could have frequent headaches.
D. She could become more vulnerable to infections.
Answer:
B. She could have a higher risk of skeletal fractures
Explanation:
She needs to maintain her bone health and B is the only answer that involves a consequence with bones.
I hope this helps
he tangent plane to the surface z= 53−x 2
−2y 2
at the point (3,2,6).
To explain the tangent plane to the surface, `z = 53 − x² − 2y²` at the point `(3, 2, 6)`, let us first determine the partial derivatives of `z` with respect to `x` and `y`.
Partial derivative of `z` with respect to `x`, `∂z/∂x = -2x`Partial derivative of `z` with respect to `y`, `∂z/∂y = -4y`Now, let's find the gradient vector `grad z` at `(3, 2, 6)` and the value of `z` at `(3, 2)`.gradient vector `grad z = (-2x, -4y, 1)`gradient vector `grad z = (-6, -8, 1)` at `(3, 2, 6)`.Value of `z` at `(3, 2)` is given by `z = 53 - 3² - 2(2)² = 39`.
Therefore, the equation of the tangent plane to the surface `
z = 53 − x² − 2y²` at `(3, 2, 6)` is:
`z - 6 = -6(x - 3) - 8(y - 2)`
which can be written as:`6x + 8y + z = 50`Thus, the equation of the tangent plane to the surface `z = 53 − x² − 2y²` at the point `(3, 2, 6)` is `6x + 8y + z = 50`.
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A roller coaster car is traveling at a constant 3 m/s when it reaches a downward slope. On the slope, the car accelerates at a constant rate of 4.5 m/s 2 . The length of the slope is 45 meters. A) Find the velocity of the car at the bottom of the hill. B) Find the time of travel.
Answer:
Velocity of the car at the bottom of the slope: approximately \(20.3\; \rm m \cdot s^{-2}\).
It would take approximately \(3.9\; \rm s\) for the car to travel from the top of the slope to the bottom.
Explanation:
The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.
Let \(v\) denote the final velocity of the car. Let \(u\) denote the initial velocity of the car.Let \(a\) denote the acceleration of the car. Let \(x\) denote the distance that this car travelled.\(v^2 - u^2 = 2\, a\cdot x\).
Given:
\(u = 3\; \rm m \cdot s^{-1}\).\(a = 4.5\; \rm m \cdot s^{-2}\).\(x = 45\; \rm m\).Rearrange the equation \(v^2 - u^2 = 2\, a\cdot x\) and solve for \(v\):
\(\begin{aligned}v &= \sqrt{2\, a \cdot x + u^2} \\ &= \sqrt{2 \times 4.5\; \rm m \cdot s^{-2} \times 45\; \rm m + \left(3\; \rm m \cdot s^{-1}\right)^{2}} \\ &\approx 20.3\; \rm m \cdot s^{-1}\end{aligned}\).
Calculate the time required for reaching this speed from \(u = 3\; \rm m \cdot s^{-1}\) at \(a = 4.5\; \rm m \cdot s^{-2}\):
\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{20.3\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1}}{4.5\; \rm m \cdot s^{-2}} \approx 3.9\; \rm m \cdot s^{-1}\end{aligned}\).
Explain how each of the following will affect your photographs. a. Half of the lens on your camera is covered by a piece of paper. b. The negative is placed in the enlarger with half of it covered by a piece of tape on the inside. c. Half of the lens on the enlarger is covered by a piece of paper. d. The camera lens is replaced by a diverging lens with the same focal length.
Each scenario affects photographs by altering exposure, contrast, or focus, leading to partial or uneven exposure, decreased sharpness, or distorted images.
a. Half of the lens on your camera is covered by a piece of paper: This will cause uneven exposure, with one half of the image being darker due to the obstruction.
b. The negative is placed in the enlarger with half of it covered by a piece of tape on the inside: This will result in uneven contrast, with half of the image being less detailed and darker due to the blocked light.
c. Half of the lens on the enlarger is covered by a piece of paper: Similar to scenario (a), this will cause uneven exposure in the final print, with one half of the image being darker.
d. The camera lens is replaced by a diverging lens with the same focal length: This will lead to a distorted image, as the diverging lens causes light rays to spread out, resulting in decreased sharpness and focus.
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PLEASE HELP MAX POINTS AND BRAINLIEST!
Look at the graph below.
A graph is shown with Absolute magnitude shown on the y-axis and Surface temperature in degree Celsius shown on the x-axis. The Dwarf stars are shown along a slanting line from coordinates 30,000 and minus 3 to 10,000 and minus 4. The Main Sequence stars are shown along a slanting line from coordinates 20,000 and minus 2 to 2,000 and minus 6. The giants are shown along a line parallel to the x-axis from coordinates 5,000 and 2 to 2,000 and 3. The supergiants are shown along a line parallel to the x-axis from coordinates 7,500 and 4 to 2,500 and 4. Point A has coordinates 20,000 and minus 4. Point B has coordinates 2,500 and minus 4. Point C has coordinates 5,000 and 2. Point D has coordinates 7,000 and 4.
Which of the following stars is most likely to be red?
a. Star A
b. Star B
c. Star C
d. Star D
i believe it would be Star A since Point A is a dwarf star and dwarf stars are usually most likely to have red coloring
Answer:
Star A
Explanation:
Literally the question has provided the answer itself
Calculation not required.
See the wordings
First star is dwarf star .
Dwarf star is mostly reddish brown or red colored .
Hence star A is the answer
now assume that a strong, uniform magnetic field of size 0.55 t pointing straight down is applied. what is the size of the magnetic force on the wire due to this applied magnetic field? ignore the effect of the earth's magnetic field. express your answer in newtons to two significant figures.
The size of the magnetic force on the wire due to the applied magnetic field of 0.55 T pointing straight down is 0.55 N (to two significant figures).
The magnetic force on a current-carrying wire is given by the equation F = I * L * B * sinθ, where F is the magnetic force, I is current, L is the length of the wire, B is the magnetic field, and θ is the angle between the current and the magnetic field.
In this case, the wire is carrying a current of 12 A (as given in the previous question), the length of the wire is 0.5 m (also given in the previous question), and the magnetic field is 0.55 T (given in the current question). Since the wire is perpendicular to the magnetic field, sinθ is equal to 1.
Plugging in these values into the equation, we get F = 12 * 0.5 * 0.55 * 1 = 0.55 N, rounded to two significant figures. Therefore, the size of the magnetic force on the wire due to the applied magnetic field is 0.55 N.
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At what time was the car’s position 25.0 m east of the origin?
Answer:
4 seconds
Explanation:
A reconnaissance
plane flies 584 km away
from its base at 940 m/s, then flies back to its
base at 1410 m/s.
What is its average speed?
Answer in units of m/s.
The average speed of the plane is 1128m/s.
The entire distance covered by the object in a specific amount of time is its average speed. Average speed exists as a scalar quantity. The magnitude serves as its representation, and it lacks direction.
Given:
Distance one way = 584km
Speed from its base = 940m/s
Speed back to base = 1410m/s
To find:
Average speed, Avg = ?
Formula:
Avg = total distance / total time
Calculations:
Total distance = 584 + 584 = 1168km = 1168000m
Total time = (584000/940) + (584000/1410)
Avg = 1168000 / [(584000/940) + (584000/1410)]
Avg = (2 x 940 x 1410) / (1410 + 940)
Avg = 2650800 / 2350
Avg = 1128m/s
Result:
The average speed of the plane is found to be 1128m/s.
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2. Blood stored at 4°C lasts safely for about 3 weeks, whereas blood stored at −160°C lasts for 5 years. What is the temperature for the blood that keeps longer using the Kelvin scale? 100 K 143 K 113 K 120 K
The temperature for the blood that keeps longer is 120 K.
What is temperature?Temperature is a physical property of matter that quantitatively expresses the common notions of hot and cold. It is the measure of the thermal energy present in a system and is an intensive property, meaning that it is independent of the amount of material in the system. Temperature is measured in various scales, including Celsius, Fahrenheit, Kelvin and Rankine. At the molecular level, temperature is determined by the amount of thermal energy emitted from the particles in the system. In a solid, this thermal energy is transferred through the lattice structure, while in a gas, it is transferred through collisions between particles.
This is because -160°C on the Celsius scale is equivalent to 113 K on the Kelvin scale, and 4°C on the Celsius scale is equivalent to 277 K on the Kelvin scale. Therefore, the temperature of 120 K is the one that keeps the blood safe for the longest period of time.
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Consider the formula d=\dfrac{m}{V}d= V m d, equals, start fraction, m, divided by, V, end fraction, where ddd represents density, mmm represents mass and has units of kilograms \left( \text{kg}\right)(kg)left parenthesis, k, g, right parenthesis, and VVV represents volume and has units of cubic meters \text{(m}^3)(m 3 )left parenthesis, m, start superscript, 3, end superscript, right parenthesis. Select an appropriate measurement unit for density
Density is a physical property and is measured in a wide variety of units. However, the most suitable measurement unit for density is the kg/m³. The formula to measure the density of an object is given byd = m/VWhere d represents density, m represents mass, and V represents volume.
The units of density will depend on the units of mass and volume. For example, if the mass is measured in kilograms and the volume is measured in cubic meters, the density will be measured in kilograms per cubic meter (kg/m³). The kg/m³ measurement is the most suitable for density because it gives the mass of an object per unit of volume in a standardized form.
In general, density is expressed in terms of mass per unit volume and the SI units of mass and volume are kilograms and cubic meters, respectively. Therefore, the appropriate measurement unit for density is kg/m³.
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Light travels from water (n=1. 33) into an unknown medium. If the angles of incidence is 30 and the angle of refraction is 24 what is the index of the refraction of the unknown medium ?
Refraction is the bending that occurs as light passes through various substances.
The refractive index of a material is determined by the ratio of the sine of the incidence angles to the sine of the refraction angle. (The Snell Rule)
Given that freshwater has an index of refraction of 1.33 and that the degrees of incidence and refraction are 30° and 40,° correspondingly,
Next, refraction gives the refractive index of a materials that is unknown.
Although one of the frequently observed phenomena is light refraction, refraction can also happen with noise and water waves. Refraction of Light Laws. According to the laws of refraction, the incident ray, the refracted ray, and the parallel to the interface between the two materials all simultaneously lie within the same plane at the point of impact.
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Which statement describes an example of static electricity?
A. Negatively charged particles are repelled by other negatively
charged particles
B. An insulator prevents electric charge from moving through it.
C. Electric charge flows past a point in a circuit.
D. A battery provides electrical energy to power a phone.
Answer:it’s a
Explanation:
Static electricity refers to the buildup or imbalance of electric charges on the surface of objects. The correct answer is B. An insulator prevents electric charge from moving through it.
An insulator prevents electric charge from moving through it. This statement describes an example of static electricity because insulators, such as rubber or plastic, do not allow electric charges to flow freely. When an insulator is rubbed or comes into contact with another object, it can cause the transfer of electrons between the two surfaces, leading to a buildup of static charge.
The charges remain stationary on the surfaces of the objects, resulting in an electrical imbalance without the flow of charges through the insulator.
Therefore, the correct answer is B. An insulator prevents electric charge from moving through it.
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What wind direction and speed will take place at Buffalo 12 hours in the future?
The wind direction and speed in Buffalo, NY in 12 hours will be from the south at 5 to 8 mph. The wind will become west in the afternoon.
The temperature will be a high of 78 degrees Fahrenheit. The sky will be sunny. There is no chance of precipitation.
The wind direction and speed in Buffalo, NY in 12 hours will be from the south at 5 to 8 mph. This means that the wind will be blowing from the south towards the north. The wind speed will be between 5 and 8 miles per hour. The wind will become west in the afternoon. This means that the wind will start blowing from the west towards the east. The temperature will be a high of 78 degrees Fahrenheit. This means that the temperature will be warm and comfortable. The sky will be sunny. This means that there will be no clouds in the sky and the sun will be shining. There is no chance of precipitation. This means that it will not rain or snow.
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A football player threw a football with a velocity of (3.0 m/s x + 5.0m/s y). How far did it travel horizontally?
The horizontal distance travelled by the football is 3.1 m.
What is the angle of projection of the ball?
The angle of projection of the football is calculated as follows;
tan ( θ ) = Vy / Vx
where;
Vy is the velocity of the ball in the vertical directionVx is the velocity of the ball in the horizontal directiontan ( θ ) = 5 / 3
tan ( θ ) = 1.667
θ = arc tan (1.667)
θ = 59⁰
The resultant velocity of the ball is calculated as follows;
v = √ (Vx² + Vy²)
v = √ (3² + 5²)
v = 5.83 m/s
The horizontal distance travelled by the football is calculated as follows;
x = v² sin(2θ) /g
where;
v is the resultant velocityg is acceleration due to gravityθ is the angle of projection of the ballx = [ (5.83)² sin(2 x 59) /9.8 ]
x = 3.1 m
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Which of the following has the most kinetic energy?
A. stretching a rubber band
B. a jet flying through the air
C. throwing a paper airplane
D. pitching a baseball
regarding the oscilloscope and based on the information provided in the laboratory manual. what axis measures the voltage strength, the x-axis or the y-axis?
pertaining to the oscilloscope and in accordance with the details in the laboratory manual. what axis quantifies the voltage intensity? Voltage (on the vertical axis) versus time is plotted on the oscilloscope's graph (on the horizontal axis).
What is meant by a Oscilloscope?An oscilloscope is a class of electronic test equipment that graphically shows changing electrical voltages as a two-dimensional plot of one or more signals as a function of time.
The major goals are to show on the screen waveforms that are repeating or singular and would otherwise occur too quickly for the human eye to see. The waveform that is being presented can then be examined for characteristics like amplitude, frequency, rising time, time interval, distortion, and others.
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When the mass of the object decreases, explain the effect that change in mass has on the potential and kinetic energy of the object.
When the mass of the object decreases, the potential and kinetic energy of the object also decreases.
WHAT IS KINETIC AND POTENTIAL ENERGY?Kinetic energy is the energy due to the motion of an object while potential energy is the energy due to rest of an object.
The kinetic and potential energy are calculated as follows:
K.E = ½ × mass × velocity ²P.E = mass × acceleration due to gravity × heightTherefore, when the mass of the object decreases, the potential and kinetic energy needed to make it move or be at rest respectively also decreases.
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