If you swing an object on the end of a string around a circle, the string pulls on the object to keep it moving in a circle. What is the name of this force?
A. inertial
B. centripetal
C. resistance
D. gravitational

Answers

Answer 1

Answer:

B

Explanation:

Answer 2

The centripetal force keeps an object moving in a circular path. Therefore option (B) is correct.

What is centripetal force?

A centripetal force can be described as a force that makes a body follow a curved path and its direction is orthogonal to the motion of the body. Gravity offers the centripetal force causing astronomical orbits.

The centripetal force is directed perpendicular to the direction of the displacement of an object. It always acts towards the center of the circle on an object moving in a circular path. For example, When spinning a ball on a string, the tension on the rope pulls the object toward the center.

The Centripetal Force can be described as the product of mass and velocity squared, divided by the radius.

F = mv²/r

Where F is the Centripetal force, m is the mass, r is the radius of the circle and v is the velocity of the object.

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Related Questions

A 78kg car traveling at 60m/s collides head on with 62 kg car traveling at 47 m/s causing them to stick together. They continue to move until they collide a 35-degree angle with a fire hydrant at causing the 2kg mass cap to fly off .05 seconds later at a 60-degree angle relative to the Y-axisWhat is the momentum of the cars before collision?What is the final velocity of the 62kg car?

A 78kg car traveling at 60m/s collides head on with 62 kg car traveling at 47 m/s causing them to stick

Answers

Answer:

a). 7594 kg m/s^2

Explanation:

The initial momentum of the cars before the collision is the sum of the individual momenta

The momentum of the first car is

\(p_1=m_1v_1=78\operatorname{kg}\cdot60m/s=4680\operatorname{kg}m/s\)

The momentum of the second car is

\(p_2=m_2v_2=62\operatorname{kg}\cdot47m/s=2914\operatorname{kg}\cdot m/s\)

Hence, the total momentum is

\(p_{\text{tot}}=p_1+p_2=4680+2914=\boxed{7594\operatorname{kg}\cdot m/s}\)

which is our answer!

When the cars collide, the conservation of momentum gives

\(p_1+p_2=(m_1+m_2)v_f\)

where vf is the final velocity of the stuck-together cars.

solving for vf gives

\(v_f=\frac{p_1+p_2}{m_1+m_2}\)

since p1 + p2 = 7594 and m1 = 78 kg and m2 = 62kg; therefore,

\(v_f=\frac{7594}{62+78}\)\(\boxed{v_f=54.24m/s}\)

part (ii).

A sketch of the situation is given below.

A 78kg car traveling at 60m/s collides head on with 62 kg car traveling at 47 m/s causing them to stick

Knowing that a ball traveled 16 feet in one second, how much will it travel in the first quarter second?

Answers

Answer:

4 Feet

Explanation:

Because A Quarter of 16 is 4

You really can't tell. You don't know if its speed was constant for the whole second, or whether it was accelerated, decelerated, intermittent, bouncing back and forth, etc. All you know is that after 1 second, it had moved 16 ft.

IF its speed was constant AND it moved in a straight line, THEN it moved 4 ft in the first quarter of that second.

If it rolled off of a roof and FELL 16 ft in the first second, then it fell 1 foot in the first quarter second.

Suppose you had 10 identical molecules enclosed by a box. At a given instant, one molecule has an energy of 100 Joules, and the others are all stationary. (A) What is the average kinetic energy of the 10 molecules

Answers

Answer:

the average kinetic energy of the 10 molecules is 10 J.

Explanation:

Given;

energy on one molecule in motion, E = 100 J

number of molecules, n = 10

(A) The average kinetic energy of the 10 molecules

since the remaining 9 molecules are at rest, their kinetic energy = 0

\(E_{Avg} = \frac{E_1 + E_9}{10} \\\\E_{Avg} = \frac{100J+ 0}{10} \\\\E_{Avg} = \frac{100J}{10} \\\\E_{Avg} = 10J\)

Therefore, the average kinetic energy of the 10 molecules is 10 J.

If the velocity of a particle is nonzero, can the particle’s acceleration be zero? Explain.

Answers

If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.

What is acceleration?

The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.

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The pendulum on a grandfather
clock is 0.993 m long, and swings
to a maximum 4.57° angle. At that
point, how high is it above the
lowest point in its swing?
(Unit = m)
Watch your sig figs!

Answers

Answer:

Explanation:

the answer is 35.6

lowest point in its swing is  12.478 cm/s.

briefly:-

Any pendulum, when positioned vertically, swings equally in both directions.

Assume that the swing's angle on either side is.

So, 2θ = 4.57°

Or, θ = 2.285°

Let v represent the pendulum's lowest point's linear speed.

The highest point of the pendulum is really h = l * (1 - cos ) vertical height above the lowest point of the swing when it reaches its maximum position.

h is therefore equal to (0.993 m) * (1 - cos 2.285°) (0.993 m) * (1 - 0.9992) = 0.0007944 m.

If m is the pendulum's mass, we can express the following using the rule of conservation of energy:

The highest point's potential energy is transformed into kinetic energy at the lowest location via height.

Therefore, m* g* h= (1 / 2)* m* (v2)

Or, v = √(2gh) (2gh)

v = ( 2 * 9.8 * 0.0007944) m/sec

v = 0.12478 m/sec

The correct answer is 12.478 cm/s.

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when a pure water is heated , it increases in volume​

Answers

As water freezes below 4°C, the volume of the liquid shrinks and water molecule motion slows. When the temperature rises over 4 °C, the water molecules spread out and take up more space, increasing the volume.

How does cooling water from 4 C to 0 C affect its volume?

Due to the peculiar property of water known as "Anomalous Expansion of Water," when 1 liter of water is cooled from 4°C to 0°C, the volume of the water starts to grow. Between 4°C and 0°C, water expands abnormally.

What happens to water's specific volume when it is heated from 0 degrees Celsius?

Water volume reduces as it is heated from 0°C to 4°C because the water's density will be maximum

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A circuit consists of a resistance R, and an inductance L in parallel connected, which is in series with a second resistance R2. This system is applied a voltage of angular frequency w. Find the total impedance.​

Answers

Answer:

The impedance of the inductor is ω L:

This is in parallel wth R giving a resistance of the parallel combination:

1 / Rp = 1 / ω L + 1 / R

Rp = (ω L * R) / (ω L + R)      for the impedance of the parallel combination

Total resistance (impedance) Rt = Rp + R2 = Z

One can use the term impedance to show that the resulting current is not in phase with the resulting voltage    

phase angle φ -    cos φ  = ω L / Rt

V = I Z        shows the relation of voltage and urrent

Which of these properties of light is a constant?
speed in a vacuum
amplitude
wavelength
frequency

Answers

Answer:

speed in vacuum

Explanation:

lets say we are in an empty universe and you are moving 10% the speed of light you wont slow down or speed up.

53-54, Image is attached!

53-54, Image is attached!

Answers

Answer:

2.29 s

Explanation:

This problem is a description of an elastic collision (the two objects collide and effectively become one object).  The equation for an elastic collision is

\(m_1v_1+m_2v_2=m_3v_3\), where:

\(m_1v_1\) = the mass of the child (55.0 kg) times the velocity of the child (2.5\(\frac{m}{s}\))

\(m_2v_2\) =  the mass of the sled (12.0 kg) times the velocity of the sled (0.0\(\frac{m}{s}\))

\(m_3v_3\) = the combined mass of the child and the sled (67.0 kg) times the combined velocity of the child and the sled (\(v_3\))

First, rearrange the problem to solve for \(v_3\):

\(\frac{m_1v_1+m_2v_2}{m_3}=v_3\)

So,

\(\frac{(55.0\ kg)(2.5\ \frac{m}{s})+(12.0\ kg)(0.0\ \frac{m}{s})}{67.0\ kg}=v_3\\\frac{137.5\frac{kg*m}{s}}{67.0\ kg}=v_3\\2.05\frac{m}{s}=v_3\)

The force of friction for this problem is given as 60 N.  To stop the child and the sled, the force of friction must be equal and opposite to the force of the child and sled.  According to Newton's first law, force equals mass times acceleration (F=ma).  So, an equation to solve this portion of the problem can be given as -60 N=ma, where m=67.0 kg.  So,

\(-60\ N=(67.0\ kg)a\\\frac{-60\ \frac{kg*m}{s^2}}{67.0\ kg}=a\\-0.90\frac{m}{s^2}\)

Acceleration can then be used in kinematic equation #1 (\(v_f=v_i+at\)) to solve for time.  Rearrange the equation and let

\(v_f=0.0\frac{m}{s}\\v_i=2.05\frac{m}{s}\\a=-0.90\frac{m}{s^2}\)

So,

\(\frac{v_f-v_i}{a}=t\\\frac{0.0\frac{m}{s}-2.05\frac{m}{s}}{-0.90\frac{m}{s^2}}=t\\\frac{-2.05\frac{m}{s}}{-0.90\frac{m}{s^2}}=t\\2.29\ s=t\)

A wire is formed into a circle having a diameter of 20.0 cm and placed in a uniform magnetic field of 2.50 mT. The wire carries a current of 5.00 A.
(a) Find the maximum torque on the wire.
_____ µN·m
(b) Find the range of potential energies of the wire-field system for different orientations of the circle.
minimum
_____µJ
maximum
_____ µJ

Answers

The maximum torque on the wire is 392.3 µN·m and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)

Torque: Torque is a measure of the force that can cause an object to rotate about an axis. It is a vector quantity.

Given that,

diameter D=20cm

Radius r =10cm

magnetic field B =2.5mT

current I=5A

Torque= n×B

           =nBsinФ

torque=nB= NIAB

                 = 1×5×π×\(10^{2}\)×\(10^{-4}\)×2.5×\(10^{-3}\)

                 = 39.23×\(10^{-5}\)

                 = 392.3µN·m

minimum potential energy= -nB= -392.3µN·m

maximum potential energy =+nB= +392.3µN·m

Therefore the maximum torque on the wire is 392.3 µN·m when is placed in an uniform magnetic field of 2.50mT and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)

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Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.

Answers

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

What is the  magnitude of the initial acceleration?

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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A boat sails for 24 km pointed in the direction [40° S of WI. A constant current moves the boat 8 km [30° W of N]. If the trip takes 3 hours, find the boats resultant velocity


Please brainliest, really need it!!!

Answers

The resultant velocity of the boat is 7.5 km/h.

What is the resultant displacement of the boat?

The resultant displacement of the boat is calculated as follows;

Sum of the vertical displacement of the boat is calculated as;

∑Fy = -24 km sin(50)  + 8 km sin(60)

∑Fy = -11.5 km

Sum of the horizontal displacement of the boat is calculated as;

∑Fx = -24 km cos(50)  - 8 km cos(60)

∑Fx = -19.4 km

The resultant displacement is calculated as follows;

d = √ (-11.5² + 19.4²)

d = 22.55 km

The resultant velocity of the boat is calculated as follows;

v = ( 22.55 km ) / ( 3 hrs )

v = 7.5 km/h

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The results for one patient show that the blood in the aorta begins at a speed of 0.10 m/s and undergoes constant acceleration for 38 ms, reaching a peak speed of 1.29 m/s. (a) What is the acceleration reflected in these data? (b) How far does the blood travel during this period?

Answers

Answer:

s ≈ 0.0603 meters

Explanation:

(a) To find the acceleration, we can use the equation of motion:

v = u + at

Where:

v = final velocity = 1.29 m/s

u = initial velocity = 0.10 m/s

a = acceleration (unknown)

t = time = 38 ms = 0.038 s

Rearranging the equation, we have:

a = (v - u) / t

Plugging in the values, we get:

a = (1.29 - 0.10) / 0.038

a = 1.19 / 0.038

a ≈ 31.32 m/s²

Therefore, the acceleration reflected in the data is approximately 31.32 m/s².

(b) To find the distance traveled, we can use the equation of motion:

s = ut + (1/2)at²

Where:

s = distance traveled (unknown)

u = initial velocity = 0.10 m/s

t = time = 38 ms = 0.038 s

a = acceleration = 31.32 m/s²

Plugging in the values, we get:

s = (0.10 × 0.038) + (0.5 × 31.32 × 0.038²)

s ≈ 0.0038 + 0.0565

s ≈ 0.0603 meters

Therefore, the blood travels approximately 0.0603 meters during this period.

Answer:

0.002 m

Explanation:

We can use the equations of motion to solve this problem.

(a) The initial velocity of the blood is u = 0.10 m/s, the final velocity is v = 1.29 m/s, the time taken is t = 38 ms = 0.038 s, and the acceleration is a (which is what we want to find). The equation that relates these quantities is:

v = u + at

Rearranging this equation, we get:

a = (v - u) / t = (1.29 - 0.10) / 0.038 = 33.68 m/s^2

Therefore, the acceleration of the blood is 33.68 m/s^2.

(b) To find the distance traveled by the blood during this period, we can use another equation of motion:

s = ut + (1/2)at^2

where s is the distance traveled. Substituting the values we have:

s = (0.10)(0.038) + (1/2)(33.68)(0.038)^2 = 0.002 m

Therefore, the blood travels a distance of 0.002 m during this period.

"Part B? Question
The total resistance in a circuit with two parallel resistors is 2 ohms and $R_1$ is 6 ohms. Using the equation for R₂, in terms of Rt and R₁, what is R₂ ?
R₂ is ohms."

"Part B? QuestionThe total resistance in a circuit with two parallel resistors is 2 ohms and $R_1$ is

Answers

The value of R₂, given that the total resistance in a circuit with two parallel resistor is 2 ohms, is 3 ohms

How do I determine the value of R₂?

The formula to obtain the total resistance in a parallel connection for two resistors is given as folllow:

Rₜ = (R₁ × R₂) / (R₁ + R₂)

With the above formula, we can obtain the value of R₂. Details below:

Total resistance (Rₜ) = 2 ohmsResistor 1 (R₁) = 6 ohms Resistor 2 (R₂) = ?

Rₜ = (R₁ × R₂) / (R₁ + R₂)

2 = (6 × R₂) / (6 + R₂)

2 = 6R₂ / (6 + R₂)

Cross multiply

2 × (6 + R₂) = 6R₂

Clear bracket

12 + 2R₂ = 6R₂

Collect like terms

12 = 6R₂ - 2R₂

12 = 4R₂

Divide both sides by 4

R₂ = 12 / 4

R₂ = 3 ohms

Thus, we can conclude that the value of R₂ is 3 ohms

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two identical eggs are dropped from the same height. The first eggs lands on a dish and breaks, while the second lands on a pillow and does not break. Which quantities are the same in both situations

Answers

Answer:

The height is the same

Explanation:

Because they were at the same height but they fell at different velocities

1. The kinetic energy of a car is 8  106 J as it travels along a horizontal road. How much work is required to stop the car in 10 s? (A) zero joules (B) 8  105 J (C) 8  107 J (D)8  104 J (E) 8  106 J​

Answers

The power to stop the car with kinetic energy of a car is  \(8*10^{6} J\) as it travels along a horizontal road is  \(8*10^{5} watt\), option B

What is Kinetic energy ?

Kinetic energy can be seen as one that is been recorded when an object is able to move from a place , in a broad term we can say this is the energy that can be attributed to that of someone leaving a place and go to another place hence we can see it as the one in the motion.

The definition of energy as the "power to accomplish work" refers to the capacity to apply a force that moves an object. Even if the word is vague, it is clear what energy actually means: it is the force that causes objects to move. The two types  can be attributed to the one we know which are kinetic and potential energy.

\(Power \frac{Energy}{time}\)

\(Energy = 8*10^{6} J\)

\(time = 10 s\)

\(Power = \frac{8*10^{6} J}{10}\)

\(power = 8*10^{5} watt\)

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proper question;

The kinetic energy of a car is 8 × 106 J as it travels along a horizontal road. How much power is required to stop the car in 10 s? (A) zero joules (B) 8  105 J (C) 8  107 J (D)8  104 J (E) 8  106 J​

i need help with these questions thank u

i need help with these questions thank u

Answers

Answer:

duvergentv boundaries

The energy transfer diagram represents the energy of a light bulb.How much electrical energy is involved in this transformation?60 J80 J100 J 120 J

Answers

Answer:

j120

Explanation:

qll energy for residential is 120 and that's what ruffly is always used for wiring

Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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Vocabulary Matching
The specialized equipment used to conduct research and repair
damaged equipment
Instruments
Space Station
Space Suit
Accomodations

Answers

Answer:

instruments

Explanation:

prevailing theories about galaxies predict that there should exist numerous around large galaxies (like our milky way). observations are confirming these predictions. question 5 options:

Answers

Prevailing theories about galaxies predict that there should exist numerous dwarf galaxies around large galaxies (like our Milky Way). Observations are confirming these predictions. The correct answer is option b.

The prevailing theories about galaxies suggest that large galaxies like our Milky Way should be surrounded by numerous dwarf galaxies.

These dwarf galaxies are much smaller than large galaxies and have a much lower mass. They are thought to form around larger galaxies due to gravitational interactions between the larger galaxies and smaller gas clouds.

The predictions made by these theories are being confirmed through observations. In recent years, astronomers have discovered many dwarf galaxies around large galaxies like our Milky Way. These discoveries have helped to improve our understanding of galaxy formation and evolution.

Therefore, option b is correct.

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The probable question may be:

prevailing theories about galaxies predict that there should exist numerous ____ around large galaxies (like our milky way). observations are confirming these predictions.

options:

a) elliptical galaxies

b) dwarf galaxies

c) giant elliptical galaxies

if the body is floating in a liquid then can we say that the rise in the level of the liquid is equal to the height of the body

Answers

Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

1. In the image below, the purple particles are protons and the white particles are neutrons. Which of the following equations matches the balanced reaction shown in
the diagram?

1. In the image below, the purple particles are protons and the white particles are neutrons. Which of

Answers

The balanced reaction that could lead to the image shown is; 2/1 H + 1/1H -----> 3/2He.

What is a nuclear equation?

A  nuclear equation is one which involves changes in the nucleus of atoms to yeild new isotopes of elements.

We know that a nuclear equation must be balanced. The balanced reaction that could lead to the image shown is; 2/1 H + 1/1H -----> 3/2He.

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An electron is accelerated through 2400 V from rest and then enters a region in which there is a uniform 1.70 T magnetic field. What are (a) the maximum and (b) the minimum magnitudes for the magnetic force this charge can experience

Answers

Answer:

Explanation:

Let v be the velocity acquired by electron in electric field

V q = 1/2 m v²

V is potential difference applied on charge q , m is mass of charge , v is velocity acquired

2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²

v² = 844 x 10¹²

v = 29.05 x 10⁶ m /s

Maximum force will be exerted on moving electron when it moves perpendicular to magnetic field .

Maximum force = Bqv , where B is magnetic field , q is charge on electron and v is velocity of electron

= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶

= 79.02 x 10⁻¹³ N .

Minimum force will be zero when electron moves along the direction of magnetic field .

(a) The maximum force on the  electron due to the magnetic field will be  F= 79.02 x 10⁻¹³ N .

(b) Minimum force will be zero when electron moves along the direction of magnetic field .

What is magnetic force?

Whenever a current is passes through a wire then the magnetic fields are generated around the wire and if any other charged particle comes under the influence of this magnetic field then the magnetic force is applied in the charge.

Let v be the velocity acquired by an electron in electric field

\(Vq=\dfrac{1}{2}mv^2\)

V is potential difference applied on charge q ,

m is mass of charge ,

v is velocity acquired

2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²

v² = 844 x 10¹²

v = 29.05 x 10⁶ m /s

Maximum force will be exerted on the moving electron when it moves perpendicular to the magnetic field .

Maximum force = Bqv , where B is magnetic field , q is charge on an electron and v is velocity of electron

F=Bqv

F= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶

F= 79.02 x 10⁻¹³ N .

Minimum force will be zero when electron moves along the direction of magnetic field .

Hence the maximum force on the  electron due to the magnetic field will be  F= 79.02 x 10⁻¹³ N and the Minimum force will be zero when electron moves along the direction of magnetic field .

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Use the sentence to answer the question.

Light is affected by gravity.

Which inference can be made based on this fact?

(1 point)

Light behaves differently in space than on Earth.
Light behaves differently in space than on Earth.

Gravity causes light to refract.
Gravity causes light to refract.

Light moves faster in space than on Earth.
Light moves faster in space than on Earth.

Stronger gravity causes an increase in light.

Answers

Answer:

Light behaves differently in space than on Earth.

Explanation:

Because the gravity field is greater near earth than in most of space. Not the areas near stars, black holes, pulsars, and such but in the vast emptyness between the clumpy spots.

A hot air balloon is rising upward with a constant speed of 3.80m/s. When the balloon is 4.25m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground

Answers

We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.

After that, it falls down to the ground with the acceleration due to gravity. Given that the balloon is rising upward with a constant speed of 3.80m/s. Hence, the velocity of the compass when it is dropped will be equal to the velocity of the balloon, which is 3.80m/s. The acceleration due to gravity is 9.81m/s². We can use the following kinematic equation of motion to calculate the time taken by the compass to hit the ground: `y = vi * t + 0.5 * a * t²`, where `y` is the height, `vi` is the initial velocity, `a` is the acceleration, and `t` is the time taken.We know that the initial height of the compass is 4.25m, the initial velocity is 3.80m/s, and the acceleration due to gravity is 9.81m/s². We need to find the time taken by the compass to hit the ground. Using the above kinematic equation, we get:`0 = 3.80t + 0.5 * 9.81 * t²`Simplifying the equation, we get:`4.905t² + 3.80t = 0`Factorizing the equation, we get:`t(4.905t + 3.80) = 0`Solving for `t`, we get:`t = 0` (since time cannot be negative)`t = -3.80/4.905 = -0.776s`We ignore the negative value of time since time cannot be negative. Hence, the time taken by the compass to hit the ground is `t = 0.776s`.Answer: `0.776s`

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If I wanted to measure the mass of an object rather than the weight, what should I use

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Answer:

the most common way to measure mass is using a balance.

How do I solve this problem

How do I solve this problem

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Answer:

it is light

Explanation:

the arrow that says light is on the glass it must be near from tungsten

Help with Physical Science question?

Help with Physical Science question?

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Answer: The answer is a because that's where it would be after it bounced

Need help solving this question.

Need help solving this question.

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(a) The magnitude of the angular momentum of the system is 5,252 kg m²/s.

(b) The rotational energy of the system is 2,826 J.

(c) The new moment of inertia is 31.25 Kgm².

(d) The new speed of each astronaut is 420.15 m/s.

(e) The new rotational energy of the system is 65.82 kJ.

(f) The work is done by the astronauts in shortening the rope -45,317,098 KJ.

(a) To calculate the magnitude of the angular momentum of the system, we can use the following equation:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Since we are treating the astronauts as particles, we can assume they are point masses and use the formula for the moment of inertia of a point mass:

I = mr²

where m is the mass of each astronaut and r is the distance between them. The angular velocity can be found from the linear velocity and the distance between the astronauts:

ω = v/r

Putting in the given values, we get:

r = 5.00 m

m = 90.5 kg

v = 5.80 m/s

I = 2(mr²) = 2(90.5 kg)(5.00 m)²

              = 4,525 kg m²

ω = v/r = 5.80 m/s / 5.00 m

           = 1.16 rad/s

L = Iω = (4,525 kg m²)(1.16 rad/s)

          = 5,252 kg m²/s

Therefore, the magnitude of the angular momentum of the system is 5,252 kg m²/s.

(b) To calculate the rotational energy of the system, we can use the following equation:

E = (1/2)Iω²

Putting in the values for I and ω that we found in part (a), we get:

E = (1/2)(4,525 kg m²)(1.16 rad/s)²

  = 2,826 J

Therefore, the rotational energy of the system is 2,826 J.

(c) When the distance between the astronauts is shortened to 5.00 m, the moment of inertia of the system changes. We can calculate the new moment of inertia using the parallel axis theorem:

I = Icm + md²

where Icm is the moment of inertia about the center of mass (which remains the same), m is the mass of each astronaut, and d is the distance between each astronaut and the center of mass (which is half the original distance, or 2.50 m).

The new moment of inertia is:

I = Icm + 2md²

 = 2(m(2.50 m)²)

 = 31.25 kg m²

Therefore the new moment of inertia is 31.25 Kgm².

(d) To find the new speeds of the astronauts, we can use the conservation of angular momentum:

L = Iω = L'

where L is the initial angular momentum (which we found in part (a)) and L' is the new angular momentum (which we can find using the new moment of inertia and the new distance between the astronauts, which is 5.00 m).

Solving for ω', we get:

ω' = L' / I = L / I'

Putting in the values, we get:

L' = L = 5,252 kg m²/s

I' = 31.25 kg m²

ω' = 5,252 kg m²/s / 31.25 kg m² = 168.06 rad/s

The new speed of each astronaut is the tangential velocity at a distance of 2.50 m from the center of mass, which can be found using the formula:

v = ω'r

where r is the distance from the center of mass. Putting in the values, we get:

v = 168.06 rad/s * 2.50 m = 420.15 m/s

Therefore, the new speed of each astronaut is 420.15 m/s.

(e) To find the new rotational energy of the system after the astronauts have shortened the rope to 5.00 m, we can use the conservation of angular momentum:

L = Iω

where L is the angular momentum of the system, I is the moment of inertia of the system, and ω is the angular speed of the system. Since the rope is assumed to have negligible mass, we can treat the system as two point masses moving in a circle around their center of mass. The moment of inertia of this system can be calculated as:

I = 2mr²/5

where m is the mass of each astronaut and r is the distance between them. Initially, the moment of inertia of the system is:

I = 2 * 90.5 kg * (10.0 m / 2)² / 5

= 3638 kg m²

The initial angular momentum of the system is:

L = Iω = 3638 kg m² * (5.80 m/s) / (10.0 m / 2)

          = 4213.6 kg m²/s

After the astronauts have shortened the rope to 5.00 m, the moment of inertia of the system is:

I' = 2 * 90.5 kg * (5.00 m / 2)² / 5

  = 1352.5 kg m²

Since the angular momentum of the system is conserved, the new angular speed of the system is:

ω' = L/I' = 4213.6 kg m²/s / 1352.5 kg m² = 3.115 rad/s

E' = (1/2)I'ω'² = (1/2) * 1352.5 kg m² * (3.115 rad/s)²

                    = 65,817.6 J

                    = 65.82 kJ

Therefore, the new rotational energy of the system is 65.82 kJ.

(f) The work done by the astronauts in shortening the rope is:

W = ∫F dl = (F' - F) ∫dl

   = (6,043,064.25 N - 630.56 N) * (-7.50 m)

   = -45,317,098 KJ

Therefore, the work is done by the astronauts in shortening the rope -45,317,098 KJ.

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