I'll give brainliest!!!! help!

A ball is thrown in the air from a platform that is 64 feet above ground level with an initial vertical velocity of 32 feet per second. The height of the ball, in feet, can be represented by the function shown where t is the time, in seconds, since the ball was thrown.

h(t) = -16t2 + 32t + 64

Which of the following equations shows the function rewritten in the form that would be best used to identify the maximum height of the ball?

A.
h(t) = -16(t – 1)2 + 80

B.
h(t) = -16(t – 2)2 + 128

C.
h(t) = -16(t – 2)2 + 112

D.
h(t) = -16(t – 1)2 + 96

Answer:

What you chose is correct.

Step-by-step explanation:

5+1=6

3+1=4

6 chicken sandwichea and 4 veggie sandwiches

The weight of the Avery's lunch box using given weights is equal to 0.92 pounds (rounded to two decimal places).

Total weight of the backpack= 2 2/3 pounds

                                                = 8/3 pounds

The weight of the each book =7/8 pounds.

Let x be the weight of the lunch box in pounds.

An equation that represents the total weight in Avery's backpack,

2(7/8) + x = 8/3

To solve for x, simplify and solve for x,

⇒14/8 + x = 8/3

Multiplying both sides by 24 the least common multiple of 8 and 3 to clear the fractions,

⇒42 + 24x = 64

Subtracting 42 from both sides,

⇒24x = 22

Dividing both sides by 24,

⇒x = 22/24

Simplifying the fraction,

⇒x = 11/12

     =  0.92 pounds (rounded to two decimal places).

Therefore, the  weight of the lunch box is equal to 0.92 pounds (rounded to two decimal places).

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The mapping of the function q[r(5)] is equal to -47 r[q(5)] is equal to -70

A function is a rule that defines a relationship between one variable. It is the mapping whose codomain is the set of real numbers.

By mapping the functions q and r defined as;

q : x » x + 1 and r : x » -2x² + 2

then;

r(5) = -2(5)² + 2 {substitute the value 5 for x in the function r}

r(5) = -2 × 25 + 2

r(5) = -50 + 2

r(5) = -48

q[r(5)] = -48 + 1 {substitute the value -48 for x in the function q}

q[r(5)] = -47

q(5) = 5 + 1 {substitute the value 5 for x in the function q}

q(5) = 6

r[q(5)] = -2(6)² + 2 {substitute the value 6 for x in the function r}

r[q(5)] = -2 × 36 + 2

r[q(5)] = -72 + 2

r[q(5)] = -70

Hence, with proper mapping of the defined functions of q and r, the correct value for q[r(5)] is -47 and r[q(5)] is -70

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The equation "ax2 = y," which has one solution unless a = 4, and none unless a = 4, has a solution. x = √(-4ay) / (2a) restricted by the condition that y be negative.

We may use the quadratic formula to determine the solutions to an equation for various values of an to construct a solution to the equation "ax² = y," which has no solution when a = 4 & just one solution in all other cases.

According to the quadratic formula, the answers to the problem "ax2 + bx + c = 0" are provided by

x = (-b +/- √(b² - 4ac)) / (2a)

In this formula, if we add "ax² = y," we obtain

x = (-0 +/- √(0² - 4ay)) / (2a)

which simplifies to

x = √(-4ay) / (2a)

If a = 4, the equation becomes

x = √(-16y) / 8

The equation has no solutions if y is positive because the value of (-16y) is fictitious. The value of (-16y) is real if y is negative, but the equation is still unsolvable since x cannot have a negative value. As a result, when a = 4, the problem has no solutions.

The equation has a single solution provided by any other value of a.

x = √(-4ay) / (2a)

For example, if a = 3, the equation becomes

x = √(-12y) / 6

Since √(-12y) is imaginary if y is positive, the problem has no solutions. If y is negative, √(-12y) has a real value, and there is only one solution to the problem.

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Note that this prompt is an exercise on Metric Units for distance. The names and corresponding speeds from least to the greatest in Miles/Hour are listed below:

The most frequent units of distance in the metric system are

Then you also have:

To solve the problem of graduation as regards the above listed names, we must convert all distances to miles.

A) Julie's Distance is 62 Miles/Hr (Given, hence no computation required)

B) Monalo's Distance is 311,520 Feet/Hr

Note that:

1 Foot = 0.000189394 miles

Thus, 311,520 Feet in miles =

311,520 x 0.000189394

= 59.00001888

Thus,

Monalo's Distance in Miles/Hr \(\approx\) 59 Miles/Hr

C) Leshawn 1,448 meters per minute

We must convert to Hour for sake of consistency.

Since there are 60 minutes in an hour, we have the distance in meters are:

1448 x 60

= 86,880 meters/Hr

Next, we must now convert meters to Miles. Recall that

1 Meter = 0.000621371 Miles

Thus,  86,880 meters/Hr in miles is

86,880 x 0.000621371

= 53.98471248/Hr

Therefore,

Leshawn's distance in Miles \(\approx\) 54 Miles/Hr

Given the above, the names and corresponding speeds from least to greatest in miles per hour is:

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Full Question:

List the names and corresponding speeds from least to greatest in miles per hour. Julie 62 miles per hour Manalo 311,520 feet per hour and Leshawn 1,448 meters per minute

The only two options with equations that are true for x = –2 and x = 2 are;

Option A: x² - 4 = 0

Option D: 4x² = 16

The domain of a function is the set of all input values  for which the function is possible.

Now, we are given the domain values as  x = –2 and x = 2.

a) x² - 4

f(-2) = (-2)² - 4

= 0

f(2) = (2)² - 2

= 0

b) x² = -4

f(-2) = (-2)²

= 4

f(2) = (2)²

= 4

c) 3x² + 12

f(-2) = 3(-2)²  + 12

= 24

f(-2) = 3(2)²  + 12

= 24

d) 4x²

f(-2) = 4(-2)²

= 16

f(2) = 4(2)²

= 16

e) 2(x - 2)²

f(-2) = 2(-2 - 2)²

= 32

f(2) = 2(2 - 2)²

= 0

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The expression 27/(27x + 18) can be rewritten as 3/(3x + 2).

What are common factors?

Common factors are factors that two or more numbers share. In other words, they are factors that divide into two or more numbers without leaving a remainder. For example, the common factors of 12 and 18 are 1, 2, 3, and 6. These are the numbers that divide evenly into both 12 and 18.

Finding common factors is useful in simplifying fractions and factoring expressions. When simplifying a fraction, you can divide both the numerator and denominator by a common factor to reduce the fraction to its simplest form. When factoring an expression, you can factor out a common factor to simplify the expression and make it easier to work with.

It's worth noting that the greatest common factor (GCF) is the largest common factor that two or more numbers share. For example, the GCF of 12 and 18 is 6, which is the largest number that divides evenly into both 12 and 18.

To rewrite the expression 27/(27x + 18), we can factor out the greatest common factor in the denominator, which is 9. This gives:

27 / (9 * (3x + 2))

We can simplify this expression further by dividing both the numerator and denominator by 9, which results in:

3 / (3x + 2)

Therefore, the expression 27/(27x + 18) can be rewritten as 3/(3x + 2).

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1. The Frenet apparatus of the curve is computed, yielding the curvature k, the tangent vector T, the normal vector N, and the binormal vector B.

2. It is shown that the given curve is a circle with a center and radius determined.

1. To compute the Frenet apparatus, we start by calculating the derivatives of the given curve:

  - First, we find the first derivative: a'(s) = (0, -3sin(8s), cos(s)).

  - Next, we compute the second derivative: a''(s) = (0, -3cos(8s), -sin(s)).

  - Then, we calculate the tangent vector: T = a'(s)/||a'(s)||.

  - The curvature is given by k = ||a''(s)||/||a'(s)||^2.

  - To determine the normal vector, we normalize the second derivative: N = a''(s)/||a''(s)||.

  - Finally, we find the binormal vector by taking the cross product of T and N: B = T × N.

2. To show that the curve is a circle, we examine its components:

  - The x-component of the curve, a_1(s), is given by (1 - cos(8s)).

  - The y-component, a_2(s), is (3 + cos(s)).

  - The z-component, a_3(s), is sin(s).

  - By analyzing these components, we can see that a_1(s) and a_3(s) describe a circle in the x-z plane, while a_2(s) remains constant.

  - Therefore, the curve lies on a circle in 3D space.

  The center and radius of the circle can be determined by observing that a_1(s) and a_3(s) correspond to the x and z coordinates of points on the circle, respectively.

  - The center of the circle is located at (1, 0, 0) since a_1(s) reaches its maximum value of 2 when s = 0.

  - The radius of the circle is 1, as a_1(s) ranges from 0 to 2.

In summary, the Frenet apparatus of the given curve is computed, providing the curvature, tangent vector, normal vector, and binormal vector. It is then shown that the curve is a circle with a center at (1, 0, 0) and a radius of 1.

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It is the fourth one because n could be any number on that red line because it’s is greater than -3

Answer:

The 4th option on the picture

Step-by-step explanation:

First, we can find -3 on the number line. Next, the inequality doesn't say n is greater than or equal to -3 (When you have a line under the greater sign, it means greater than or equal to), it says that n is greater than -3, so you don't fill in the dot. We know that to be greater than something, you point the line to the right side of the point (And we plot less than a point is to go left of the point), so we have all of the data to plot the line. The point is at -3 and isn't filled in and goes right of -3. Therefore, the answer is the 4th one.

Answer:

30 feet

Step-by-step explanation:

90/30*10=30

Answer:

The answer is 30 ft

Step-by-step explanation:

Answer:

(a) 60 cups

(b) 5 cookies, 8 muffins and 4 cupcakes in each container

Step-by-step explanation:

Given

Let:

\(C \to Cookies; M \to Muffins; K \to Cupcakes\)

So:

\(C : M : K = 300 : 480 : 240\)

Solving (a): The greatest number of containers to be used;

To do this, we first reduce the ratio to the lowest

C : M : K = 300 : 480 : 240

Divide by 60

\(C : M : K = 5 : 8 : 4\)

The ratio cannot be further reduced. Hence, he will use 60 cups

Solving (b): The number in each cup

In (a), we have:

\(C : M : K = 5 : 8 : 4\)

This means that;

\(C = 5\) --- Cookies

\(M = 8\) --- Muffins

\(K = 4\) -- - Cupcakes

A) The probability of selecting a tomato soup can on the first draw = 4/10

The probability of selecting another tomato soup can on the second draw (without replacement) = 3/9

The probability of selecting a pumpkin soup can on the first draw = 6/10

The probability of selecting another pumpkin soup can on the second draw (without replacement) = 5/9

B) Probability of selecting one tomato soup can and one pumpkin soup can = probability of (i) + probability of (ii)

= 2/15 + 1/3

= 1/3

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Answer:

B. c =14 v = 4 are a pair of solutions to the equation.

E. If 20 cars go, no vans are needed.

F. 8 vans and 8 cars are numbers that meet the constraints in this situation.

Step-by-step explanation:

Volunteer drivers are needed to bring 80 students to the championship baseball game. Drivers either have cars, which can seat 4 students, or vans, which can seat 6 students. The equation

4 c + 6 v = 80

We are to find what can transport exactly 80 students.

We compare the options till we get our correct answer.

A. If 2 cars go, then 2 vans are needed.

4 c + 6 v = 80

c = number of cars needed

v = number of vans needed

Hence,

4(2) + 6(2)

8 + 12 ≠ 80

20≠ 80

Option A is wrong

B. c =14 v = 4 are a pair of solutions to the equation.

4 c + 6 v = 80

c = number of cars needed

v = number of vans needed

Hence,

4(14) + 6(4) = 80

56 + 24 = 80

80 = 80

Option B is correct

C. If 6 cars go and 11 vans go, there will be extra space

4 c + 6 v = 80

c = number of cars needed

v = number of vans needed

Hence,

4(6) + 6(11)

24 + 66

110 > 80

Option C is wrong, there would be no space left

D. 10 cars and 8 vans isn't enough to transport all the students.

4 c + 6 v = 80

c = number of cars needed

v = number of vans needed

Hence,

4(10) + 6(8)

40 + 48

88 > 80

Option D is wrong

E. If 20 cars go, no vans are needed.

4 c + 6 v = 80

c = number of cars needed

v = number of vans needed

Hence,

4(20) + 6(0) = 80

80 + 0 = 80

80 = 80

Option E is correct

F. 8 vans and 8 cars are numbers that meet the constraints in this situation.

4 c + 6 v = 80

c = number of cars needed

v = number of vans needed

Hence,

4(8) + 6(8) = 80

32 + 48 = 80

80 = 80

Option F is correct

Therefore the statements in options B, E and F are the only correct statement for the equation 4 c + 6 v = 80

Answer:

Page 218

Step-by-step explanation:

Let x = the first page

Let x + 1 =  the second page

x + x+ 1 = 437 combine like terms

2x + 1 = 437   Subtract 1 from both sides

2x = 436  Divide both sides by 2

x = 218

Check:

218 + 219 = 437

437 = 437

Helping in the name of Jesus.

Answer:

M: (2,-2)

N: (1,2)

O: (2,-4)

P: (5, -2)

Step-by-step explanation:

What you would do is find out where the two lines intercross. The 2 right quadrants are positive. The two left are negative. Count the lines and figure out the ordered pair. X is left and right, y is up and down. For example, if you were given a ordered pair, (4,-2) you would go up four, and left 2.

Answer:

-6

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The decimal number 0.00897 written in scientific notation is 8.97 ×10^3 and it has significant figures

Answer:

8.97 * 10⁻³

Step-by-step explanation:

0.00897 = \(\frac{8.97}{1000}=8.97 * 10^{-3}\)

Place the decimal point after the first nonzero number.

Write the power of 10,

(i) If we move the decimal to the right, the power of 10 decrease by number of moves.

(ii) If we move the decimal to the left, the power of 10 increase by the number of moves

The given statement is true.

If a has n distinct prime factors and b has m distinct prime factors and n>m, then ab has at least n and at most n m distinct prime factors.

Prime factorization is a manner of expressing various as fabricated from its prime factors. A high number is a variety that has preciseness elements, 1 and the variety itself. As an example, if we take the number 30. We recognize that 30 = 5 × 6, however, 6 isn't always a prime factor.

To show whether more than a few is a top wide variety, first attempt dividing it by 2, and see if you get an entire variety. If you do, it can not be a prime number. In case you don't get an entire number, subsequent attempt dividing it through prime numbers: 3, 5, 7, 11 (nine is divisible via three) and so forth, constantly dividing by way of a top wide variety.

Every prime range can be written within the shape of 6n + 1 or 6n – 1 (except the multiples of high numbers, i.e. 2, 3, five, 7, eleven), where n is a herbal variety. To realize the prime number extra than 40, the below formulation may be used.

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The correct rule to describe the function g as a function of f and gives the correct rule is that g(x) = 3x³-6x²+21x-33.

This function is obtained by multiplying the function f(x) by a constant, which in this case is 3.

The correct rule to describe the function

g(x) = 3f(x)

in terms of the function f(x) = x³-2x²+7x-11 is that

g(x) = 3(x³-2x²+7x-11) and thus

g(x) = 3x³-6x²+21x-33.

In order to obtain the function g(x) from the given function f(x), it is necessary to multiply it by a constant, in this case 3.

Therefore, g(x) = 3f(x) means that g(x) is three times f(x).

Thus, we can obtain g(x) as follows:

g(x) = 3f(x) = 3(x³-2x²+7x-11) = 3x³-6x²+21x-33

Therefore, the correct rule to describe the function g as a function of f and gives the correct rule is that

g(x) = 3x³-6x²+21x-33.

This function is obtained by multiplying the function f(x) by a constant, which in this case is 3.

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The value of the probabilities are

a. P(X < 4) = 0

b. P(X > 3.5) ≈ 0.796875

c. P(4 < X < 5) ≈ 0.5625

d. P(X < 4.5) ≈ 0.703125

e. P(X < 3.5 or X > 4.5) = 0

a. P(X < 4):

To calculate P(X < 4), we need to find the area under the curve of the function f(x) = x/8 for values of x less than 4. However, the given function is only defined for the range 3 < x < 5. Therefore, we cannot directly calculate P(X < 4) using this function. The probability of X being less than 4 is zero since the function does not cover that range.

b. P(X > 3.5):

To calculate P(X > 3.5), we need to find the area under the curve of the function f(x) = x/8 for values of x greater than 3.5. Since the function is defined for 3 < x < 5, we can calculate this probability by integrating the function over the range 3.5 to 5.

Integrating f(x) from 3.5 to 5:

∫[3.5, 5] (x/8) dx = [x²/16] evaluated from 3.5 to 5

= [(5²/16) - (3.5²/16)]

= (25/16) - (12.25/16)

= 12.75/16

= 0.796875

Therefore, P(X > 3.5) ≈ 0.796875.

c. P(4 < X < 5):

To calculate P(4 < X < 5), we need to find the area under the curve of the function f(x) = x/8 for values of x between 4 and 5. We can calculate this probability by integrating the function over the range 4 to 5.

Integrating f(x) from 4 to 5:

∫[4, 5] (x/8) dx = [x²/16] evaluated from 4 to 5

= [(5²/16) - (4²/16)]

= (25/16) - (16/16)

= 9/16

= 0.5625

Therefore, P(4 < X < 5) ≈ 0.5625.

d. P(X < 4.5):

To calculate P(X < 4.5), we need to find the area under the curve of the function f(x) = x/8 for values of x less than 4.5. We can calculate this probability by integrating the function over the range 3 to 4.5.

Integrating f(x) from 3 to 4.5:

∫[3, 4.5] (x/8) dx = [x²/16] evaluated from 3 to 4.5

= [(4.5²/16) - (3²/16)]

= (20.25/16) - (9/16)

= 11.25/16

= 0.703125

Therefore, P(X < 4.5) ≈ 0.703125.

e. P(X < 3.5 or X > 4.5):

To calculate P(X < 3.5 or X > 4.5), we can calculate the sum of probabilities P(X < 3.5) and P(X > 4.5). However, as mentioned earlier, the function f(x) = x/8 is not defined for values less than 3 or greater than 5. Therefore, the probability of X being less than 3.5 or greater than 4.5 is zero.

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Answer:

90

Step-by-step explanation:

Similar means same shape different size, so it is the same angle on a smaller shape

Answer:

I believe the answers C

Step-by-step explanation:

I took the test... k12 hope this helps

the specific lock code for your refrigerator. However, I hope this explanation helps you understand the concept of lock codes and their purpose in securing devices and objects.

but I cannot provide the code to the lock on your refrigerator. As an AI helper on Brainly, I don't have access to specific lock codes for individual appliances.

However, if you are trying to understand the concept of lock codes, I can provide a general explanation. A lock code is a combination of numbers, letters, or symbols that is used to secure and restrict access to a device or object, such as a refrigerator. It acts as a password or key to prevent unauthorized individuals from opening the lock.

The lock code for a refrigerator is typically set by the owner or manufacturer and can be personalized for security purposes. It is important to keep the lock code confidential to ensure that only authorized individuals can access the refrigerator.

I cannot provide the specific lock code for your refrigerator. However, I hope this explanation helps you understand the concept of lock codes and their purpose in securing devices and objects.

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Assuming a constant growth factor, the population of Gotham City grew by approximately 4.287% each year.

This can be calculated using the formula for exponential growth, which is:
y = a * (1 + r)^t
Where: y = final value of the population
a = initial value of the population
r = annual growth rate expressed as a decimal
t = number of years

For this problem, let's assume that the initial population of Gotham City was 100,000 and that the population grew for 10 years.

Using these values, we can calculate the annual growth rate as follows:

100,000 * (1 + r)^10 = final population
r = (final population / 100,000)^(1/10) - 1

Plugging in a final population of 148,644 (which is a 48.644% increase from the initial population),

r = (148,644 / 100,000)^(1/10) - 1r = 0.04287 (rounded to 5 decimal places)

Therefore, the annual growth rate (or percentage increase) is approximately 4.287% (rounded to 3 decimal places).

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Answer:

12+27a

Step-by-step explanation:

3(4+9a)=3(4)+3(9a)=12+27a

Answer: 12 days

Step-by-step explanation:

Divide 48 by 3 to find out how many pages she reads on in one day.

She reads 16 pages a day

Multiply 16•12 to see if the number you get will be 192

She will need 12 more days to finish her book

Answer:

(-2, 0) and (0, 4)

Step-by-step explanation:

The solutions are the intersection points. The graphs intersect at points (-2, 0) and (0, 4)

2250 student actually enrolled to the large university.

Percentage, a relative value indicating hundredth parts of any quantity.

The number of students applied = 10000

A large university accepts 50​% of the students who apply.

50% of 10000

50/100×10000

0.5×10000

5000

45​% actually enroll.

45% of 5000

0.45×5000

2250

Hence 2250 student actually enrolled to the large university.

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