In his practice, dr. howard uses the idea that because actions are learned, they can also be unlearned through classical and operant conditioning. dr. howard is most likely a

No, a fraction is not a term. The distributive property can be applied to fractions because it is a general mathematical principle.

A fraction is not considered a term in the traditional sense. It is a mathematical expression that represents division. However, the distributive property can still be applied to fractions because the property itself is a fundamental rule of arithmetic that extends beyond specific types of expressions.

The distributive property states that for any real numbers a, b, and c:

a × (b + c) = (a × b) + (a × c).

When working with fractions, we can apply the distributive property as follows:

Let's consider the expression: a × (b/c).

We can rewrite this as: (a × b)/c.

Now, let's distribute the 'a' to 'b' and 'c':

(a × b)/c = (a/c) × b.

In this step, we applied the distributive property to the fraction (a/c) by treating it as a whole.

Although fractions represent division, we can still use the distributive property because it is a general mathematical principle that allows for manipulating expressions involving addition, subtraction, multiplication, and division.

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Answer:

\(f-g+(-2) = -9.705\)

Step-by-step explanation:

Given

\(f = -3.005\)

\(g=4.7\)

Required

Determine  \(f-g+(-2)\)

We have:

\(f-g+(-2)\)

Open brackets

\(f-g+(-2) = f-g-2\)

Substitute values for f and g

\(f-g+(-2) = -3.005-4.7-2\)

Solve

\(f-g+(-2) = -9.705\)

Answer:

the answer i got was

-9.705

Step-by-step explanation:

i did it on khan

Answer:

The answer is -58

To find the range, CDF, and PDF of the random variable W = max(X,Y), where X and Y are random variables with the given joint PDF, we can proceed as follows:

1. Range of W:

The maximum value of two variables X and Y can be at most the maximum of their individual values. Since both X and Y have a range from 0 to a, the range of W will also be from 0 to a.

2. CDF of W:

To find the CDF of W, we need to calculate the probability that W is less than or equal to a given value w, P(W ≤ w).

We have two cases to consider:

a) When 0 ≤ w ≤ a:

P(W ≤ w) = P(max(X,Y) ≤ w)

Since W is the maximum of X and Y, it means both X and Y must be less than or equal to w. Therefore, the joint probability of X and Y being less than or equal to w is given by:

P(X ≤ w, Y ≤ w) = P(X ≤ w) * P(Y ≤ w)

Using the joint PDF fx,y(x,y) =\(1/(a^2)\) for 0 < x,y ≤ a, and 0

otherwise, we can evaluate the probabilities:

P(X ≤ w) = P(Y ≤ w)

= ∫[0,w]∫[0,w] (1/(a^2)) dy dx

Integrating, we get:

P(X ≤ w) = P(Y ≤ w)

= \(w^2 / a^2\)

Therefore, the CDF of W for 0 ≤ w ≤ a is given by:

F(w) = P(W ≤ w)

= \((w / a)^2\)

b) When w > a:

For w > a, P(W ≤ w)

= P(X ≤ w, Y ≤ w)

= 1, as both X and Y are always less than or equal to a.

Therefore, the CDF of W for w > a is given by:

F(w) = P(W ≤ w) = 1

3. PDF of W:

To find the PDF of W, we differentiate the CDF with respect to w.

a) When 0 ≤ w ≤ a:

F(w) =\((w / a)^2\)

Differentiating both sides with respect to w, we get:

f(w) =\(d/dw [(w / a)^2\)]

    = \(2w / (a^2)\)

b) When w > a:

F(w) = 1

Since the CDF is constant, the PDF will be zero for w > a.

Therefore, the PDF of W is given by:

f(w) =\(2w / (a^2)\) for 0 ≤ w ≤ a

      0 otherwise

To summarize:

- The range of W is from 0 to a.

- The CDF of W is given by F(w) =\((w / a)^2\) for 0 ≤ w ≤ a,

and F(w) = 1 for w > a.

- The PDF of W is given by f(w) = \(2w / (a^2)\) for 0 ≤ w ≤ a,

and f(w) = 0 otherwise.

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The surface area of this sphere is equal to 21.2 cm².

In Mathematics and Geometry, the surface area of a sphere can be calculated by using the following mathematical equation (formula):

Surface area of a sphere, S = 4πr²

Where:

r represents the radius.

By substituting the given radius into the formula for the surface area of a sphere, we have the following;

Surface area of a sphere, S = 4πr²

Surface area of a sphere, S = 3.14 × 2.6²

Surface area of a sphere, S = 3.14 × 6.76

Surface area of a sphere, S = 21.2 cm²

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

After the distribution:

Aran has 1/2 of the fruit roll-up.

Jon has 2/3 of the fruit roll-up.

Kiona has 2/9 of the fruit roll-up.

Let's break down the distribution of the fruit roll-up:

Aran has the fruit roll-up initially.

He gives half of it to Jon.

Jon then gives 1/3 of his portion to Kiona.

To determine how much each person gets, we'll go step by step:

Aran gives half of the fruit roll-up to Jon.

Aran has 1/2 of the fruit roll-up remaining.

Jon receives 1/2 of the fruit roll-up.

Jon gives 1/3 of his portion to Kiona.

Jon has 2/3 of his original portion remaining (1 - 1/3 = 2/3).

Kiona receives 1/3 of Jon's portion, which is (1/3) * (2/3) = 2/9 of the fruit roll-up.

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Using the power-reducing formula, the simplified tangent expression is given as follows:

tan^4(3x) = [3 – 4 cos (6x) + cos (12x)] / [3 + 4 cos (6x) + cos (12x)]

Power-reducing formulas are formulas for which the nth power of a trigonometric expression can be written using only trigonometric expressions of power 1.

For the fourth order of the tangent of an angle, the expression is given as follows:

tan^4(u) = [3 – 4 cos (2u) + cos (4u)] / [3 + 4 cos (2u) + cos (4u)]

For this problem, the expression is:

tan^4(3x).

Hence comparing to the standard formula, we have that u = 3x, hence the equivalent expression is given as follows:

tan^4(3x) = [3 – 4 cos (6x) + cos (12x)] / [3 + 4 cos (6x) + cos (12x)]

We just replaced each instance of u in the formula by 3x.

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An unnormalized relation refers to a table in a relational database that contains more than one row. This means that there are duplicate rows in the table, which violates the rules of normalization.

Normalization is a process in database design that aims to eliminate data redundancy and ensure data integrity. It involves breaking down a database into multiple tables and defining relationships between them. By doing so, we can efficiently store and retrieve data while minimizing inconsistencies.

In an unnormalized relation, duplicate rows can lead to various problems. For example, it can result in data inconsistencies, as updating one instance of a row may not reflect changes in other duplicate rows. Additionally, it can cause unnecessary storage and maintenance overhead.

To normalize an unnormalized relation, we need to identify the functional dependencies in the table and create separate tables for related data. This helps organize the data and reduces redundancy.

In summary, an unnormalized relation is a table in a relational database that has duplicate rows. It is important to normalize such relations to ensure data integrity and efficiency.

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Answer:

-1.55, 3.55 to nearest hundredth.

Step-by-step explanation:

First write this in vertex form:

f(x) = a(x - b)^2 + c

f(x) = a(x - 1)^2 - 13       where a is some constant.

f(x) = -11 when x = 0     so we have:

-11 = a(0 - 1)^2 - 13

a = -11 + 13 = 2.

intercept form is

f(x) = 2(x - 1)^2 - 13

When f(x) = 0 we have thd x-intercepts:

2(x - 1)^2 - 13 = 0

(x - 1)^2 = 6.5

x = ±√6.5 + 1

= 2.550 + 1, -2.550 + 1

x intercepts = 3.55, -1.55.

a) P20 is the 20th percentile, which separates the lowest 20% of the data from the highest 80%. To find P20, you would need to put the data in numerical order and find the value at the 20th percentile.

b) P67 is the 67th percentile, which separates the lowest 67% of the data from the highest 33%. To find P67, you would need to put the data in numerical order and find the value at the 67th percentile.

c) 34 is the 34th percentile, which separates the lowest 34% of the data from the highest 66%. It is the value at the 34th percentile

d) A boxplot is a graphical representation of a dataset that shows the minimum, first quartile, median, third quartile, and maximum of the data. To create a boxplot, you would need to put the data in numerical order, then calculate the minimum, first quartile (Q1), median (Q2), third quartile (Q3), and maximum of the data. These values are then plotted on a graph, with the box representing the interquartile range (Q3 - Q1) and the whiskers representing the minimum and maximum values. The outliers(if any) will be plotted as dots

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Answer:

Madeline picks 6 pieces of fruit per hour

Step-by-step explanation:

divide total amount of fruit she picked on that day by the amount of hours she spent picking

12/2 = 6

42/7 = 6

Answer:

1 1/4 hours

Step-by-step explanation:

.75/.6=x/1

cross multiply

.75=.6x

divide by .6

x=1.25 hours

(I didn't write this awnser it was written by

Katieg3593 I just thought I would share the awnser).

Answer:

2.846

Step-by-step explanation:

Answer:

2.85

Step-by-step explanation:

Answer:

According to the graph it should be D  Have a good day thank you <.>

Step-by-step explanation:

Answer:

D i think

Step-by-step explanation:

if it started at 54º, and in each one hour it grows 8 degrees, then it is d

not b because in the first hour it only went up to 60º

pls mark brainliest unless someone alreay answered it

thank you have a great day! :D

The Integral ∫−10∫−10x−Ydxdy Is Equal To 1/2.

To evaluate the given integral ∫∫[-1,0] x - y dx dy, we need to integrate the expression x - y with respect to x first and then with respect to y over the given region.

Let's perform the integration step by step:

∫∫[-1,0] x - y dx dy

Integrating with respect to x, treating y as a constant:

∫[-1,0] (1/2)x^2 - xy |[-1,0] dy

Now, substitute the limits of integration and simplify:

∫[-1,0] [(1/2)(0)^2 - (0)(y)] - [(1/2)(-1)^2 - (-1)(y)] dy

Simplifying further:

∫[-1,0] [-y + (1/2)] dy

Integrating with respect to y:

[-(1/2)y^2 + (1/2)y] |[-1,0]

Substituting the limits of integration:

[-(1/2)(0)^2 + (1/2)(0)] - [-(1/2)(-1)^2 + (1/2)(-1)]

Simplifying the expression:

[0 + 0] - [-(1/2) + (-1/2)]

Combining like terms:

0 + 1/2

The result is: 1/2

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Answer:

check the explanation

Step-by-step explanation:

1. To find the sum of two integers with like signs simply add them and keep the sign same as integers

for example:

\(2 + 3 = 5 \\ - 2 + ( - 3) = - 5\)

2. To find the sum of the integers with unlike signs just subtract them and then keep the sign of the bigger integer.

For example:

\( - 3 + 5 = 2 \\ - 5 + 3 = - 2\)

There are 360 black counters and 306 white counter in 20:17 ratio.

Let's denote the number of black counters by B and the number of white counters by W. We know that the ratio of black to white counters is 20:17, which means that:

B/W = 20/17

We also know that there are 54 more black counters than white counters, which means that:

B = W + 54

We can use substitution to solve for B. Substituting the second equation into the first equation, we get:

(W + 54)/W = 20/17

Cross-multiplying, we get:

17(W + 54) = 20W

Expanding the left side, we get:

17W + 918 = 20W

Subtracting 17W from both sides, we get:

918 = 3W

Dividing both sides by 3, we get:

W = 306

Now we can use the second equation to find B:

B = W + 54 = 306 + 54 = 360

Therefore, there are 360 black counters in the bag.

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The absolute maximum value of \(\( f(x) \)\) over the domain \(\([0,8]\)\) is 0, which occurs at \(\( x = 0 \)\), and the absolute minimum value is -64, which occurs at \(\( x = 64 \)\).

To find the critical points, we need to find where the derivative of \(\( f(x) \)\) equals zero or is undefined. Taking the derivative of \(\( f(x) \)\) with respect to \(\( x \)\), we have \(\( f'(x) = \frac{2}{3}x^{-1/3} - 1 \)\). Setting this derivative equal to zero and solving for \(\( x \)\), we find \(\( x = 4^3 = 64 \)\).

Since the function is only defined over the interval \(\([0,8]\)\), we need to check the function's values at the critical points and endpoints. Evaluating \(\( f(x) \) at \( x = 0 \), \( x = 8 \)\), and \(\( x = 64 \)\), we have \(\( f(0) = 0 \)\), \(\( f(8) = 8^{2/3} - 8 = -4 \)\), and \(\( f(64) = 64^{2/3} - 64 = -64 \)\).

Therefore, the absolute maximum value of \(\( f(x) \)\) over the domain \(\([0,8]\)\) is 0, which occurs at \(\( x = 0 \)\), and the absolute minimum value is -64, which occurs at \(\( x = 64 \)\).

The linear approximation for \(\( f(x) = 1 \)\) can be obtained by finding the point on the graph of \(\( f(x) \)\) that is closest to the line \(\( y = 1 \)\). Since the graph of \(\( f(x) \)\) is concave up, the linear approximation will be the tangent line to the graph at a specific point.

To find this point, we need to solve the equation \(\( f(x) = 1 \)\). Rearranging the equation, we have \(\( x^{2/3} - x - 1 = 0 \)\). Unfortunately, this equation does not have a simple algebraic solution. However, numerical methods such as Newton's method or the bisection method can be used to approximate the solution.

Once we find the approximate solution \(\( x_0 \)\), we can find the slope of the tangent line by evaluating the derivative of \(\( f(x) \) at \( x_0 \)\), which is \(\( f'(x_0) \)\). Then, using the point-slope form of a line, the linear approximation can be expressed as \(\( y - f(x_0) = f'(x_0)(x - x_0) \)\).

Note that without an explicit value of \(\( x_0 \)\), it is not possible to provide a specific linear approximation in this case.

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When multiplying fractions, multiply the numerator (top number), then the denominator (bottom number), and finally reduce to the lowest term if necessary.

Fractions are subsets of wholes. They are made up of a numerator (the number on top) and a denominator (the number on the bottom). The numerator represents the number of parts, while the denominator represents the total number of available parts.

To multiply two fractions, follow these three simple steps:

Step 1: Multiply the numerators of each fraction by themselves (the numbers on top). The answer's numerator is the result.

Step 2: Add the denominators of each fraction together (the numbers on the bottom). The answer's denominator is the result.

Step 3: Simplify or reduce your response.

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(a)image averaging is a very effective method of reducing noise in images. Image averaging reduces noise by adding multiple images of the same scene together and then dividing by the number of images added.The conditions that must be fulfilled for the image averaging method are as follows:-

(i) The background of the image must not move between each image capture.- The noise present in the image must be random.- The source of the noise must be consistent.

(ii)The mathematical expression that characterizes the noise in the resultant image when K images are averaged, as K becomes large is given by;sigma_n^2/K

Where;sigma_n^2 is the variance of the noise and K is the number of images that have been averaged.

Therefore, as K increases, the variance of the noise in the resultant image reduces, and thus, the noise reduces.When either method can be used for noise reduction, the temporal image averaging method would be the preferred method to select.

(iii)This is because it uses a sequence of images that are taken at different times, usually at high speeds, to produce a single image that is free of noise. This method is best when dealing with fast-moving objects, and it can be used in situations where the camera cannot be stabilized and is experiencing unwanted vibration or shaking.

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$540 dollars bro yor welcome

\(7 - 4(2w + 1) = 9w - 49 + w \\ 7 - 8w - 4 = 10w - 49 \\ 10w + 8w = 7 - 4 + 49 \\ 18w = 52 \\ w = \frac{52}{18} \\ w= 2.88\)

I hope I helped you^_^

The quotient of the expression is 4x+1.

An expression is a set of terms combined using the operations +, – , x or ÷. An expression is a number, a variable, or a combination of numbers and variables and operation symbols. An expression is in simplest form when no terms can be combined

Given:

The expression is

\((4x^{2} - 7x - 2) / (x-2)\)

By long division method the following steps are :

Divide the tens column dividend by the divisor. Then Multiply the divisor by the quotient in the tens place column ,Subtract the product from the divisor then at last Bring down the dividend in the ones column and repeat.

We have to find the quotient of the expression.

According to given question we have

\((4x^{2} - 7x - 2) / (x-2)\\\\=(x-2)(4x+1)/(x-2)\\\\=4x+1\)

Therefore, the quotient of the expression is 4x+1.

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As we have solved above, the answer of (-2.48) + (-4.5) ÷ (0.25) is -20.48.

So, both Kevin and Jack are incorrect.

They did a mistake while solving the expression.

Thus, neither Kevin nor Jack has the correct answer.

Given the following expressions;a) 8 - 12.5b) 0.25Now, to solve the above expressions;

a) 8 - 12.5 = -4.5b) 0.25

Therefore, the expression (-2.48) + (-4.5) ÷ (0.25) can be simplified as follows:

By using BEDMAS, divide -4.5 by 0.25

first, and then add -2.48 to the quotient.

(-2.48) + (-4.5 ÷ 0.25)= -2.48 - 18= -20.48

Thus, the final answer is -20.48

Now, Kevin believes that (-2.48) + (-4.5) ÷ (0.25)

= -12.5. Jack believes that

(-2.48) + (-4.5) ÷ (0.25)

= 12.5.

Now, we need to identify who is correct and why:

As we have solved above, the answer of (-2.48) + (-4.5) ÷ (0.25) is -20.48.

So, both the Kevin and Jack are incorrect.

They did mistake while solving the expression.

Thus, neither Kevin nor Jack has the correct answer.

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Answer:

answer is:

Circum: 25.13274 cm^2

Area: 50.26548 cm^2

Step-by-step explanation for the CIRCUMFERNCE ONLY:

Original equation for the circumference of a circle:

C=2(pi)r

We will use 3.14 as pi

We know that the diameter of a circle is 2 times the radius, so in order to find the radius all we have to do is divide the diameter by 2.

8/2 = 4

So now we know what the radius is equal to.

4

So now just plug in your numbers to the original equation

2 X (3.14) X 4

25.13274

If we were to round up the answer would be

25.13

Hope this helps!

Comparing the means of the two samples, we find that the difference between the means is significant. Therefore, we can reject the claim and conclude that male and female high school students have different exam scores.

To perform the two-sample t-test, we first calculate the standard error of the difference between the means using the formula:

SE = sqrt((s1^2 / n1) + (s2^2 / n2))

Where s1 and s2 are the population standard deviations of the male and female students respectively, and n1 and n2 are the sample sizes. Plugging in the values, we have:

SE = sqrt((47^2 / 49) + (4.3^2 / 53))

Next, we calculate the t-statistic using the formula:

t = (x1 - x2) / SE

Where x1 and x2 are the sample means. Plugging in the values, we have:

t = (239 - 21.1) / SE

We can then compare the t-value to the critical t-value at α = 0.01 with degrees of freedom equal to the sum of the sample sizes minus 2. If the t-value exceeds the critical t-value, we reject the null hypothesis.

In this case, the t-value is calculated and compared to the critical t-value using the provided standard normal distribution table. Since the t-value exceeds the critical t-value, we can reject the claim that male and female high school students have equal exam scores.

Therefore, the correct answer is:

B. Male and female high school students have different exam scores.

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Answer:

Shawna needs a mix of 4 cups of yoghurt and 6 cups of blueberries

Step-by-step explanation:

Here, we want to know the number of cups of yoghurt and smoothies Shawna needs to make;

We have 2 parts yoghurt and 3 parts blueberry, so we can say we have a ratio of 2:3

The total number of cups to be made is 10

So the number of cups of yoghurt will be;

2/(2+3) * 10

= 2/5 * 10 = 4 cups

The number of cups of blueberry would be;

3/5 * 10 = 6 cups

So a mix of 4 cups of yoghurt and 6 cups of blueberries is needed by Shawna

Answer:

2x+4=52

2x+19=67

2x+13=61

(I gotta be honest I can’t fully remember how to name the angles but to not set you astray I just put the equation each angle goes to)

x=24

Step-by-step explanation:

the sum of all three angles is equal to 180 degrees

So we can add all of these angles and set it equal to 180 like this

(2x+19)+(2x+4)+(2x+13)=180

Simplify by adding common terms

6x+36=180

   -36.  -36

6x=144

/6.  /6

x=24

So now to find the angles we just fill in x with 24

2(24)+4

48+4

52

2(24)+19

48+19

67

2(24)+13

48+13

61

Hopes this helps please mark brainliest