Answer:
83.5 degrees
Step-by-step explanation:
first, find x:
x+5x-13+4x=180
10x=193
x=19.3
Then, substitute that value for c:
5*19.3-13
=83.5 degrees
a post-test. H o:μ d=0H a:μ d=0You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain pre-test and post-test samples for n=8 subjects. The average difference (post pre) is d=53.9 with a standard deviation of the differences of s d=37.2. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the mean difference of post-test from pre-test is not equal to 0. There is not sufficient evidence to warrant rejection of the claim that the mean difference of posttest from pre-test is not equal to 0 . The sample data support the claim that the mean difference of post-test from pre-test is not equal, to 0 There is not sufficient sample evidence to support the ciaim that the mean difference of post-test from pre-test is not equal to 0 .
The appropriate option is: This test statistic leads to a decision to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean difference of post-test from pre-test is not equal to 0.
The given statistical hypothesis isH o:μ d = 0H a:μ d ≠ 0 The sample size n = 8 is very small. We will use the t-test statistic as the population standard deviation is unknown. The test statistic formula is:t = (d - μ) / (s / √n)t = (53.9 - 0) / (37.2 / √8)t = 4.69 (approx.)Thus, the test statistic for this sample is 4.69. The degrees of freedom is n - 1 = 7.The p-value for this sample is P (|t| > 4.69) = 0.0025 (approx.)
Thus, the p-value is less than α. This test statistic leads to a decision to reject the null hypothesis.As such, the final conclusion is that There is sufficient evidence to warrant rejection of the claim that the mean difference of post-test from pre-test is not equal to 0.
Therefore, the appropriate option is: This test statistic leads to a decision to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean difference of post-test from pre-test is not equal to 0.
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How do I find the value of the cone in terms of pi??
Answer:
\(V=\pi^{}mi^3\)Explanation:
Step 1. Let h be the height of the cone:
\(h=3mi\)and let d be the diameter of the circle:
\(d=2mi\)From the diameter we can find the radius of the circle:
\(\begin{gathered} r=\frac{d}{2} \\ \downarrow\downarrow \\ r=\frac{2mi}{2} \\ \downarrow\downarrow \\ r=1mi \end{gathered}\)Step 2. To find the volume of a cone we use the following formula:
\(V=\frac{\pi r^2h}{3}\)Step 3. Substituting the values of r and h into the formula:
\(V=\frac{\pi(1mi)^2(3mi)}{3}\)Solving the operations:
\(\begin{gathered} V=\frac{\pi(1mi^2)(3mi)}{3} \\ \downarrow\downarrow \\ V=\frac{3\pi^{}}{3}mi^3 \end{gathered}\)The result is:
\(V=\pi^{}mi^3\)The volume is pi cubic miles.
Answer:
\(V=\pi^{}mi^3\)HELP HELP HELP FFHFJFHDHDHDHD
Answer:
y ≈ 15.9 cm
Step-by-step explanation:
using the tangent ratio in the right triangle
tan53° = \(\frac{opposite}{adjacent}\) = \(\frac{y}{12}\) ( multiply both sides by 12 )
12 × tan53° = x , that is
x ≈ 15.9 (to 1 decimal place )
When can a correlation coefficient based on an observational study be used to support a claim of cause and effect?
Never
When the correlation coefficient is close to -1 or +1.
When the correlation coefficient is equal to -1 or +1.
When the scatterplot of the data has little vertical variation.
A correlation coefficient based on an observational study cannot be used to support a claim of cause and effect. The correct answer is A: never.
Correlation does not imply causation, and while a strong correlation between two variables may suggest that there is a relationship between them, it does not prove that one variable causes the other. Observational studies are particularly susceptible to confounding variables, which can make it difficult or impossible to determine whether a relationship between two variables is causal or not.
To establish causality between two variables, a randomized controlled experiment is required. In a randomized controlled experiment, the experimenter can manipulate the independent variable and observe the effect on the dependent variable, while controlling for other variables that might affect the outcome. By randomly assigning subjects to different treatment groups, the experimenter can ensure that any differences in the outcome between groups are due to the treatment, rather than some other factor.
Therefore, while a correlation coefficient can be a useful tool for describing the relationship between two variables, it cannot be used to establish causality.
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Factor the expression using the greatest common factor.
-12z+16z4 - 3z²
The expression's factored version, which employs the greatest common factor, is -z(12z-16z3 + 3z).
Factoring using the greatest common factorThe largest number that can be split into exactly two or more other numbers. It is the "best" thing for making fractions simpler!
Given the expression below
-12z+16z^4 - 3z²
We are to factor the expression using the greatest common factor
Find the factors of each terms
-12z = -12 * z
16z^4 = 16 * z * z^3
-3z^2 = -3 * z * z
Since -z is common to the factors, hence the factored form of the expression using the greatest common factor is -z(12z-16z^3 + 3z)
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What is the recursive rule for the sequence?
Answer:
2nd option
Step-by-step explanation:
the recursive rule is
\(a_{n}\) = \(a_{n-1}\) + d ( d is the common difference )
use the explicit rule to find a₁ and d
a₁ = 48 - 11(1) = 48 - 11 = 37
a₂ = 48 - 11(2) = 48 - 22 = 26
then
d = a₂ - a₁ = 26 - 37 = - 11
recursive rule is then
\(a_{n}\) = \(a_{n-1}\) - 11
a₁ = 37
Please help I will give brainliest
A jewelry company is considering two different packages for their new bracelet. Both options are constructed as a wooden box with a cardboard label that covers the lateral surfaces. Use the information to answer the questions.
1. What is the total surface area of the package in plan A? Plan B?
2. What is the lateral surface area of the package in plan A? Plan B?
3. If it costs $0.15 per square inch for the wood, then what is the cost for plan A? Plan B?
4. If it costs $0.05 per square inch for the cardboard label, then what is the cost for plan A? Plan B?
5. Which plan will be more cost effective? By how much?
(Sorry if this is a lot i just need help im giving 29 points thats all i have)
Answer:
evalues ton calcule A est correct
Solve the following problem applying the solution strategies
from problems.
. Wanda's house is worth $ 127,000, but
she still owes $ 68,422.00 on her mortgage. She has $ 25,236.00
in a savings account and you have debt on your credit card
$ 8,477.00 credit. Also, she has another debt in the
cooperative savings of $ 5,131.00 and calculates that the car from her and
other household items have a value of $ 18,000.00.
What is Wanda's net worth?
Answer:
58,578
Step-by-step explanation:
I need help please, I have no idea what to do, my brain's dead
Hope you could understand.
If you have any query, feel free to ask.
Answer:
width = 6 units
length = 18 units
Step-by-step explanation:
P=2(l+w)
P=2(3w+w)
48=6w+2w
8w=48
w=6
width is therefore 6units and length 3w = 18units
A continuous random variable has a probability density function of f(x) = 2x² for 0 < x≤ 2 and is equal to 0 for other values. Another continuous random variable has a probability density function of f(y) = 1/(2√y) for 0 ≤ y ≤ 1 and is equal to 0 for other values. Calculate var(X) and var(Y).
Answer:
The variance of Y is given by the expression (2/5) * y^(5/2) - y.
Step-by-step explanation:
To calculate the variance of a continuous random variable, we use the formula:
Var(X) = E[X²] - (E[X])²
Let's start with calculating var(X):
The probability density function (PDF) of X is given as:
f(x) = 2x² for 0 < x ≤ 2, and f(x) = 0 for other values.
To calculate the variance of X, we need to find the expected value E[X] and the expected value of the square E[X²].
First, let's calculate E[X]:
E[X] = ∫(x * f(x)) dx
For 0 < x ≤ 2, f(x) = 2x²:
E[X] = ∫(x * 2x²) dx
= ∫(2x³) dx
= [1/2 * x⁴] from 0 to 2
= 1/2 * (2⁴ - 0⁴)
= 8/2
= 4
Next, let's calculate E[X²]:
E[X²] = ∫(x² * f(x)) dx
For 0 < x ≤ 2, f(x) = 2x²:
E[X²] = ∫(x² * 2x²) dx
= ∫(2x⁴) dx
= [1/2 * x⁵] from 0 to 2
= 1/2 * (2⁵ - 0⁵)
= 16/2
= 8
Now, we can calculate var(X):
Var(X) = E[X²] - (E[X])²
= 8 - (4)²
= 8 - 16
= -8
However, variance cannot be negative, so the variance of X is not meaningful in this case.
Moving on to var(Y):
The probability density function (PDF) of Y is given as:
f(y) = 1/(2√y) for 0 ≤ y ≤ 1, and f(y) = 0 for other values.
To calculate the variance of Y, we again need to find the expected value E[Y] and the expected value of the square E[Y²].
First, let's calculate E[Y]:
E[Y] = ∫(y * f(y)) dy
For 0 ≤ y ≤ 1, f(y) = 1/(2√y):
E[Y] = ∫(y * 1/(2√y)) dy
= ∫(1/(2√y)) dy
= (1/2) ∫(1/√y) dy
= (1/2) * 2√y + C
= √y + C
Since E[Y] is the expected value, it should be a constant. Therefore, C must be 0.
E[Y] = √y
Next, let's calculate E[Y²]:
E[Y²] = ∫(y² * f(y)) dy
For 0 ≤ y ≤ 1, f(y) = 1/(2√y):
E[Y²] = ∫(y² * 1/(2√y)) dy
= ∫(y^(3/2)) dy
= (2/5) * y^(5/2) + C
= (2/5) * y^(5/2) + C
Again, since E[Y²] is the expected value, C must be 0.
E[Y²] = (2/5) * y^(5/2)
Now, we can calculate var(Y):
Var(Y) = E[Y²] - (E[Y])²
= (2/5) * y^(5/2) - (√y)²
= (2/5) * y^(5/2) - y
So, the variance of Y is given by the expression (2/5) * y^(5/2) - y.
Var(X) is approximately -17.07 and Var(Y) is approximately 0.1. Variance measures the spread of a dataset and shows how much individual data points differ from the mean. A higher variance means there is greater diversity among the data points.
To calculate the variance of a continuous random variable, we need to use the following formula:
Var(X) = \(\int[(x - E(X))^2 \times f(x)] dx\)
where E(X) is the expected value or mean of X.
For the first random variable X with the probability density function f(x) = 2x² for 0 < x ≤ 2, we first need to calculate the mean:
E(X) = \(\int [x \times f(x)] dx\)
= \(\int [x \times 2x^2] dx\)
= 2∫[x³] dx
= 2[x⁴/4] evaluated from 0 to 2
= 2(2⁴/4 - 0⁴/4)
= 2(16/4)
= 8
Now, we can calculate the variance:
Var(X) = \(\int [(x - 8)^2 \times 2x^2] dx\)
=\(2\int [(x - 8)^2 \times x^2] dx\)
=\(2\int [x^4 - 16x^3 + 64x^2] dx\)
= 2[x⁵/5 - 4x⁴ + 64x³/3] evaluated from 0 to 2
= 2[(2⁵/5 - 4(2⁴) + 64(2³)/3) - (0⁵/5 - 4(0⁴) + 64(0³)/3)]
= 2[(32/5 - 4(16) + 64(8)/3) - (0 - 0 + 0)]
= 2[(32/5 - 64 + 512/3) - 0]
= 2[-128/15]
= -256/15
≈ -17.07 (rounded to two decimal places)
For the second random variable Y with the probability density function f(y) = 1/(2√y) for 0 ≤ y ≤ 1, the mean is:
E(Y) = \(\int [y \times f(y)] dy\)
= \(\int [y \times 1/(2\sqrt{y})] dy\)
= \(\int [1/(2\sqrt{y} )] dy\)
=\(\int [y^{(-1/2)}/2] dy\)
=\((y^{(1/2)}/2)\) evaluated from 0 to 1
= (1/2 - 0/2)
= 1/2
= 0.5
Now, let's calculate the variance:
Var(Y) = \(\int [(y - 0.5)^2 \times (1/(2\sqrt{y} ))] dy\)
= \(\int [(y - 0.5)^2/(2\sqrt{y} )] dy\)
= \(\int [(y^2 - y + 0.25)/(2\sqrt{y} )] dy\)
= \((1/2)\int [(y^{(3/2)} - y^{(1/2)} + 0.25y^{(-1/2)})] dy\)
=\((1/2)[(2/5)y^{(5/2)} - (2/3)y^{(3/2)} + 0.5y^{(1/2)}]\) evaluated from 0 to 1
=\((1/2)[(2/5)(1^{(5/2)}) - (2/3)(1^{(3/2)}) + 0.5(1^{(1/2)})] - (0 - 0 + 0)\)
= (1/2)[(2/5) - (2/3) + 0.5]
= (1/2)[(6/15) - (10/15) + 0.5]
= (1/2)[-4/15 + 0.5]
= (1/2)[-4/15 + 7/15]
= (1/2)[3/15]
= 3/30
= 1/10
= 0.1
Therefore, Var(X) ≈ -17.07 and Var(Y) = 0.1. Variance provides insight into the variability and volatility of a set of values, with a higher variance indicating greater diversity among the data points.
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E15 gasoline contains 15% of alcohol calculate the volume in liters of alcohol in a full 20 gallon gas tank
Since, 1 gallon = 3.78541 liters
Therefore, 20 gallons = 75.7082 liters
That means amount of gasoline in the gas tank is 20 gallons or 75.7082 liters.
It's given in the question that E15 gasoline contains 15% of alcohol.
Therefore, amount of alcohol in the gas tank = 15% of 75.7082
= 11.35623
≈ 11.36 liters
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Amount of total Alcohol in liters is 11.355 liter.
Given:
Amount of total gas solution = 20 gallon
Amount of Alcohol in total gas = 15%
Find:
Amount of total Alcohol in liters
Computation:
1 Gallon = 3.785 liter (Approx.)
Amount of total gas solution in liter = 20 × 3.785
Amount of total gas solution in liter = 75.7 liter (Approx.)
Amount of total Alcohol in liters = Amount of total gas solution in liter × Amount of Alcohol in total gas
Amount of total Alcohol in liters = 75.7 × 15%
Amount of total Alcohol in liters = 75.7 × 0.15
Amount of total Alcohol in liters = 11.355 liter (Approx.)
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complete the following for the system of equations. 2x − 4y = 5 0.6x − 1.2y = 1.5 (a) use a graphing utility to graph the equations in the system
The system of equations can be graphed using a graphing utility to find their intersection point, which represents the solution to the system.
To graph the system of equations, we first need to rearrange them in slope-intercept form, which is y = mx + b. For the first equation, we can solve for y by subtracting 2x from both sides and then dividing by -4, which gives us y = -0.5x + (5/4). For the second equation, we can solve for y by dividing both sides by -1.2 and then simplifying, which gives us y = -0.5x + (5/8). We can then enter these equations into a graphing utility, such as Desmos or GeoGebra, to plot their graphs. The intersection point of the two graphs represents the solution to the system. In this case, the intersection point is (4.4, 1.3), which means that x = 4.4 and y = 1.3 is the solution to the system of equations.
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Write the expression in standard form a+bi: (8-i)/(2+i)
Answer:
The expression (8-i)/(2+i) in standard form is, 3 - 2i
Step-by-step explanation:
The expression is,
(8-i)/(2+i)
writing in standard form,
\((8-i)/(2+i)\\\)
Multiplying and dividing by 2+i,
\(((8-i)/(2+i))(2-i)/(2-i)\\(8-i)(2-i)/((2+i)(2-i))\\(16-8i-2i-1)/(4-2i+2i+1)\\(15-10i)/5\\5(3-2i)/5\\=3-2i\)
Hence we get, in standard form, 3 - 2i
The expression (8-i)/(2+i) in standard form a+bi is (15 - 10i) / (3 + 4i).
To write the expression (8-i)/(2+i) in standard form a+bi, we need to eliminate the imaginary denominator. We can do this by multiplying the numerator and denominator by the conjugate of the denominator.
The conjugate of 2+i is 2-i. So, we multiply the numerator and denominator by 2-i:
(8-i)/(2+i) * (2-i)/(2-i)
Using the distributive property, we can expand the numerator and denominator:
(8(2) + 8(-i) - i(2) - i(-i)) / (2(2) + 2(i) + i(2) + i(i))
Simplifying further:
(16 - 8i - 2i + i^2) / (4 + 2i + 2i + i^2)
Since i^2 is equal to -1, we can substitute -1 for i^2:
(16 - 8i - 2i + (-1)) / (4 + 2i + 2i + (-1))
Combining like terms:
(15 - 10i) / (3 + 4i)
Therefore, the expression (8-i)/(2+i) in standard form a+bi is (15 - 10i) / (3 + 4i).
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katrina is single with a taxable income for lastvyear of $74,431
a. Use the tax table to determine Katrina's tax.
b. Does Katrina get a refund? SelectYesNoltem 2
c. Find the difference between Katrina's tax and the amount withheld by her employer
Answer:
A. Use the tax table to determine Katrina's tax
The state of a spin 1/2 particle in Sx basis is defined as (Ψ) = c+l + x) + i/√7 l - x) a) Find the amplitude c+ assuming that it is a real number and the state vector is properly defined. b) Find the expectation value . c) Find the uncertainty △SX.
1) The amplitude c+ is c+l
2) The expectation value is 0
3) The uncertainty ΔSX is √(3/7) c+.
Now, we know that any wave function can be written as a linear combination of two spin states (up and down), which can be written as:
Ψ = c+ |+> + c- |->
where c+ and c- are complex constants, and |+> and |-> are the two orthogonal spin states such that Sx|+> = +1/2|+> and Sx|-> = -1/2|->.
Hence, we can write the given wave function as:Ψ = c+|+> + i/√7|->
Now, we know that the given wave function has been defined in Sx basis, and not in the basis of |+> and |->.
Therefore, we need to write |+> and |-> in terms of |l> and |r> (where |l> and |r> are two orthogonal spin states such that Sy|l> = i/2|l> and Sy|r> = -i/2|r>).
Now, |+> can be written as:|+> = 1/√2(|l> + |r>)
Similarly, |-> can be written as:|-> = 1/√2(|l> - |r>)
Therefore, the given wave function can be written as:Ψ = (c+/√2)(|l> + |r>) + i/(√7√2)(|l> - |r>)
Therefore, we can write:c+|l> + i/(√7)|r> = (c+/√2)|+> + i/(√7√2)|->
Comparing the coefficients of |+> and |-> on both sides of the above equation, we get:
c+/√2 = c+l/√2 + i/(√7√2)
Therefore, c+ = c+l
The amplitude c+ is a real number and is equal to c+l
The expectation value of the operator Sx is given by: = <Ψ|Sx|Ψ>
Now, Sx|l> = 1/2|r> and Sx|r> = -1/2|l>
Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= -i/√7(c+l*) + i/√7(c+l)= 2i/√7 Im(c+)
As c+ is a real number, Im(c+) = 0
Therefore, = 0
The uncertainty ΔSX in the state |Ψ> is given by:
ΔSX = √( - 2)
where = <Ψ|Sx2|Ψ>and2 = (<Ψ|Sx|Ψ>)2
Now, Sx2|l> = 1/4|l> and Sx2|r> = 1/4|r>
Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= 1/4(c+l* + c+l) + 1/4(c+l + c+l*) + i/(2√7)(c+l* - c+l) - i/(2√7)(c+l - c+l*)= = 1/4(c+l + c+l*)
Now,2 = (2i/√7)2= 4/7ΔSX = √( - 2)= √(1/4(c+l + c+l*) - 4/7)= √(3/14(c+l + c+l*))= √(3/14 * 2c+)= √(3/7) c+
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A woman buys 50 eggs for $6.60. Some cost 12 cents each and the rest 14 cents each.
How many of each kind of eggs has she bought?
Answer:
She bought 20 eggs that were 12 cents, and she bought 30 eggs that were 14 cents.
Step-by-step explanation:
Create a system of equations where x is the number of 12 cent eggs and y is the number of 14 cent eggs.
x + y = 50
0.12x + 0.14y = 6.6
Solve by elimination by multiplying the top equation by -0.12:
-0.12x - 0.12y = -6
0.12x + 0.14y = 6.6
Add these together and solve for y:
0.02y = 0.6
y = 30
So, she bought 30 eggs that were 14 cents. Plug in 30 as y into one of the equations, and solve for x:
x + y = 50
x + 30 = 50
x = 20
So, she bought 20 eggs that were 12 cents.
She bought 20 eggs that were 12 cents, and she bought 30 eggs that were 14 cents.
solved previously. for each integer $n$, let $f(n)$ be the sum of the elements of the $n$th row (i.e. the row with $n 1$ elements) of pascal's triangle minus the sum of all the elements from previous rows. for example,\[f(2)
By applying Pascal's triangle concept for the f(n) as per given condition the value f(2) is 1.
To find f(2), calculate the sum of the elements in the second row of Pascal's triangle
and subtract the sum of all the elements from the previous rows.
Pascal's triangle is formed by starting with a row containing only 1
and then each subsequent row is constructed by adding the two numbers above it.
The first row of Pascal's triangle is simply 1.
The second row of Pascal's triangle is 1 1.
To calculate f(2), sum the elements in the second row and subtract the sum of the elements in the previous rows.
Sum of elements in the second row = 1 + 1 = 2
Sum of elements in the first row = 1
This implies, f(2) = 2 - 1 = 1.
Therefore, using Pascal's triangle the value f(2) is equal to 1.
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50 points
Complete the inequality below to describe the domain of the graph shown.
Domain: es001-1.j pg 4
The domain will be as -4 is less than x which is less than or equal to 4
The range will be -2 is less than or equal to y which is less than 5
What are domain and range?The set of possible input values, and the range is the set of all possible output values of the graph
The completed inequality representing the set of the domain and range are presented as follows;
We have given that there is an open circle at the point (-4, 5), which represents that there is no value at the point.
However, at the other end of the graph, which is point (4, -2), we have a closed circle, that represents the graph has a value at the point (4, -2)
Part A;
The domain of a graph is the possible (x-values) of the graph, in inequality format, the domain of the attached graph is -4 < x ≤ 4
Therefore;
The inequality for the domain gives that;
Domain: -4 is less than x which is less than or equal to 4
Part B;
The range of a graph is the possible y-values of the graph, in inequality format, the domain of the graph is -2 ≤ y < 5
The Range: -2 is less than or equal to y which is less than 5
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Answer:
First answer -4
Second answer-2
Step-by-step explanation:
I got it right on edge
triangles ABE, ADE, and CBE are shown on the cordinate grid, and all the verticals have coordinates that are integers
Solve for f please and thank youuuuu!
Answer:
\(f= \frac{G + 3m^3}{n}\)
Step-by-step explanation:
\(Nf= G + 3m^3\)
divide by n
\(f= \frac{G + 3m^3}{n}\)
Given f(x) = -x + 1, find f(0).
Answer:
f(x)=1
Step-by-step explanation:
f(0)=-0+1
=1
Given <2 and <4 are the vertical angels. Prove <2≅ <4
Answer:
Angle 2 = Angle 4 ( vertically opposite angles)
as the number of degrees of freedom become large, the t distribution approaches the binomial distribution. group of answer choices true false
As the number of degrees of freedom become large, the t distribution actually approaches the normal distribution, not
the binomial distribution. The correct answer is false.
The t distribution is used when the sample size is small and the population standard deviation is unknown, while the
binomial distribution is used for discrete data where there are only two possible outcomes.
The binomial distribution is a discrete probability distribution that models the number of successes in a fixed number of
independent trials with a constant probability of success, whereas the t distribution is a continuous probability
distribution that models the variability of sample means from a normal population.
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the dietary guidelines for americans recommends limiting saturated fat intake to less than 10% of total calories. on the spreadsheet report, locate the columns for saturated fat (fat-s) and calories (cals). calculate the percentage of calories from saturated fat for each of the two days. how does the percentage of calories from saturated fat on day 1 (jenna's original menu) compared to day 2 (jenna's modified menu)?
On Day 1, Jenna's original menu had 11 percentage of calories from saturated fat, while on Day 2, Jenna's modified menu had only 4% of calories from saturated fat.
To calculate the percentage of calories from saturated fat for both days, first locate the columns for saturated fat (Fat-S) and calories (Cals) on the spreadsheet report. Add the total number of calories for both days, then add the total number of saturated fat calories for both days. To calculate the percentage of calories from saturated fat for each day, divide the total number of saturated fat calories for each day by the total number of calories for each day and multiply by 100. On Day 1, Jenna's original menu had a total of 2,826 calories, with 317 saturated fat calories, meaning 11% of calories from saturated fat. On Day 2, Jenna's modified menu had a total of 2,839 calories, with 115 saturated fat calories, meaning 4% of calories from saturated fat. Therefore, Day 2 had a much lower percentage of calories from saturated fat when compared to Day 1.
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Tim bought some cans of paint and 3/4 of a liter of special paint additive formulated to reduce mildew. Before painting his house, he used all of the additive to put 3/8 of a liter of additive in each can. How many cans of paint did Tim buy?
If Tim bought some cans of paint and 3/4 of a liter of special paint additive formulated to reduce mildew. Before painting his house, he used all of the additive to put 3/8 of a liter of additive in each can. The number of cans of paint that Tim buy is: 6 cans.
Number of can of paints boughtLet x represent the number of can
Quantity of addictive mixed in each liter=3/8
Total addictive mixed=3/4
Hence,
x(3/8)=3/4
Cross multiply
x=8(3/4)
x=6 cans of paint
Therefore If Tim bought some cans of paint and 3/4 of a liter of special paint additive formulated to reduce mildew. Before painting his house, he used all of the additive to put 3/8 of a liter of additive in each can. The number of cans of paint that Tim buy is: 6 cans.
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Write the equation of the line that passes through the points (3, -8) and(9, 9). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.
help help please!!!! thank youuu
Answer:
*Most of these, you just have to get the variable by itself. To check, put the answer in for the letter.*
1. b+8=14
Subtract 8 from both sides
b=6
Check: 6+8=14 ——— 14=14
2. 25-t=15
Subtract 25 from both sides
-t = -10 ––Divide both sides by -1
t=10
Check: 25-10=15 ——— 15=15
3. 9p=81
Divide both sides by 9 to get p alone
p=9
Check: 9(9)=81 ——— 81=81
4. y/7= 2
Multiply both sides by 7 to cancel out the fraction
y=14
Check: 14/7=2 ——— 2=2
5. y+6=10
Subtract 6 from both sides
y=4
Check: 4+6=10 ——— 10=10
6. f-4=9
Add 4 to both sides
f=13
Check: 13-4=9 ——— 9=9
7. 8d=48
Divide both sides by 8 to get d alone
d=6
Check: 8(6)=48 ——— 48=48
8. 10 = r/5
Multiply both sides by 5 to cancel out the fraction
50 = r
Check: 10=50/5 ——— 10=10
9. 15=x/3
Multiply by 3 to cancel out the fraction
45=x
Check: 15=45/3 ——— 15=15
Let S n
=∑ i=1
n
N i
where N i
s are i.i.d. geometric random variables with mean β. (a) (5 marks) By using the probability generating functions, show that S n
follows a negative binomial distribution. (b) (10 marks) With n=50 and β=2, find Pr[S n
<40] by (i) the exact distribution and by (ii) the normal approximation. 2. Suppose S=∑ j=1
N
X j
is compound negative binomial distributed. Specifically, the probability mass function of claim counts N is Pr[N=k]=( k+r−1
k
)β k
(1+β) −(r+k)
,k=0,1,2,… The first and second moments of the i.i.d. claim sizes X 1
,X 2
,… are denoted by μ X
= E[X] and μ X
′′
=E[X 2
], respectively. (a) (5 marks) Find the expressions for μ S
=E[S] and σ S
2
=Var[S] in terms of β,r,μ X
and μ X
′′
. (b) (10 marks) Prove the following central limit theorem: lim r→[infinity]
Pr[ σ S
S−μ S
≤x]=Φ(x), where Φ(⋅) is the standard normal CDF. (c) (10 marks) With r=100,β=0.2 and X∼N(μ X
=1000,σ X
2
=100). Use part (b) to (i) approximate Pr[S<25000]. (ii) calculate the value-at-risk at 95% confidence level, VaR 0.95
(S) s.t. Pr[S> VaR 0.95
(S)]=0.05. (iii) calculate the conditional tail expectation at 95% confidence level, CTE 0.95
(S):= E[S∣S>VaR 0.95
(S)]
The probability generating functions show that Sn follows a negative binomial distribution with parameters n and β. Expanding the generating function, we find that Gn(z) = E(z^Sn) = E(z^(N1+...+Nn)) = E(z^N1... z^Nn). The probability that Sn takes values less than 40 is approximately 0.0012. The probability that Sn is less than 40 is approximately 0.0012.
(a) By using the probability generating functions, show that Sn follows a negative binomial distribution.
Using probability generating functions, the generating function of Ni is given by:
G(z) = E(z^Ni) = Σ(z^ni * P(Ni=ni)),
where P(Ni=ni) = (1−β)^(ni−1) * β (for ni=1,2,3,...).
Therefore, the generating function of Sn is:
Gn(z) = E(z^Sn) = E(z^(N1+...+Nn)) = E(z^N1 ... z^Nn).
From independence, we have:
Gn(z) = G(z)^n = (β/(1−(1−β)z))^n.
Now we need to expand the generating function Gn(z) using the Binomial Theorem:
Gn(z) = (β/(1−(1−β)z))^n = β^n * (1−(1−β)z)^−n = Σ[k=0 to infinity] (β^n) * ((−1)^k) * binomial(−n,k) * (1−β)^k * z^k.
Therefore, Sn has a Negative Binomial distribution with parameters n and β.
(b) With n=50 and β=2, find Pr[Sn < 40] by (i) the exact distribution and by (ii) the normal approximation.
(i) Using the exact distribution:
The probability that Sn takes values less than 40 is:
Pr(S50<40) = Σ[k=0 to 39] (50+k−1 k) * (2/(2+1))^k * (1/3)^(50) ≈ 0.001340021.
(ii) Using the normal approximation:
The mean of Sn is μ = 50 * 2 = 100, and the variance of Sn is σ^2 = 50 * 2 * (1+2) = 300.
Therefore, Sn can be approximated by a Normal distribution with mean μ and variance σ^2:
Sn ~ N(100, 300).
We can standardize the value 40 using the normal distribution:
Z = (Sn − μ) / σ = (40 − 100) / √(300/50) = -3.08.
Using the standard normal distribution table, we find:
Pr(Sn<40) ≈ Pr(Z<−3.08) ≈ 0.0012.
So the probability that Sn is less than 40 is approximately 0.0012.
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On saturdays, cars arrive at sami schmitt's scrub and shine car wash at the rate of 6 cars per fifteen minute interval. Using the poisson distribution, the probability that five cars will arrive during the next five minute interval is.
The probability that five cars will arrive during the next thirty minute interval is 0.0361
What is probability?
Probability is a way of calculating how likely something is to happen. Numerous things are difficult to forecast with absolute confidence.
Main Body:
Let X = number of cars arriving at Sami Schmitt's Scrub and Shine Car Wash.
The average number of cars arriving in 15 minutes is 6.
The average number of cars arriving in 1 minute is = 6/15 = 2/5
The average number of cars arriving in 5 minutes is, (2/5)*5 = 2
The random variable X follows a Poisson distribution with parameter λ = 2.
The probability mass function of X is:
P(X=\(x\)) = \((e^{-2} 2^{x} )/x!\) , x = 0,1 ,2 ,3...
Compute the probability that 5 cars will arrive in 5 minutes as follows:
P(X=5) =\((e^{-2} 2^{5} )/5!\)
P (X= 5) = 0.0361
Hence probability is 0.0361
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A survey was done that asked people to indicate whether they preferred to ride a
street bike or a mountain bike. The results of the survey are shown in the two-way
table.
Amjed is making a relative frequency table from this data.
What operation should Amjed perform to determine the relative frequency of a
person over 30 years old who prefers to ride a mountain bike? 1) Subtract 25 from 462, then divide by 462. 2) Divide 25 by 462. 3) Add 180 to 462, then divide by 463. 4) Divide 180 by 462
The operation that Amjed should perform to determine the relative frequency of a person over 30 years old who prefers to ride a mountain bike is given as follows:
2) Divide 25 by 462.
How to calculate a probability?The parameters that are needed to calculate a probability are listed as follows:
Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.
The total number of people is given as follows:
58 + 164 + 215 + 25 = 462.
Out of these people, 25 prefer mountain bike, hence the relative frequency is given as follows:
25/462.
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