Answer: Please upload the image or PDF.
convert to radical form (3) 2/3
Answer:
The radical form of 3 2/3 is
\( \sqrt[3]{3 {}^{2} } \)
find the length of a rectangle whose breadth is 1.18cm and area is 6.12m
Answer: 5.19 cm.
Step-by-step explanation: Area= l*w so then that also means that l=area/width. So you can divide 6.12 by 1.18 to get 5.19cm.
How many times larger is (5.4×10^6)than (9×10^3)?
Answer:
600 times
Step-by-step explanation:
5400000 ÷ 9000 = 600
Shirley is decorating the gym for a party. She has 5 rolls of blue streamer and 9 rolls of green streamer.
Each roll of blue streamer is 98 feet long and each roll of green streamer is 82 feet long. How many total feet of streamer does Shirley have to decorate with?
Answer:
rolls of blue streamer: 5×98=49
rolls of green streamer: 9×82=738
total rolls: 49+738=787
When I have walked 20% of the way to school, I have 1200 metres more to walk than when I have 20% of the walk remaining.
How far, in metres, is it from my home to my school?
Given:
I have walked 20% of the way to school.
I have 1200 metres more to walk than when I have 20% of the walk remaining.
To find:
The distance from home to school.
Solution:
Let x be the distance from home to school.
I have already walked 20% of the way to school and i have 1200 metres more to walk than when I have 20% of the walk remaining.
It means 1200 is \(100\%-20\%-20\%=60\%\) of the total distance from home to school.
\(1200=\dfrac{60}{100}x\)
\(1200=0.6x\)
\(\dfrac{1200}{0.6}=x\)
\(2000=x\)
Therefore, the distance from home to school is 2000 metres.
How far, in metres, is it from my home to my school is 2,000 metres.
First step is to formulate
1200/(1-2×20%)
Second step is to find how far in metres
Distance=1200/(1-0.4)
Distance=1200/0.6
Distance=2,000
Inconclusion how far, in metres, is it from my home to my school is 2,000 metres.
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A book, a person and a box cost Rs 45 and Rs 54 respectively . Find the smallest sum of money with which the exact number of books , pens and boxes can be purchased.
Answer:
99
Step-by-step explanation:
If you like my answer than please mark me brainliest
Answer: 99
Step-by-step explanation:
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Use the diagram below to answer questions 8 to 12
We get that ∠5 can be written as ∠ HDC, ∠ 3 can be written as ∠ GDE and the vertex of ∠ 2 is D.
An angle is formed when two straight lines or rays meet at a common endpoint. The common point of contact is called the vertex of an angle. The word angle comes from a Latin word named 'angulus,' meaning “corner.”
We are given a diagram.
We need to name the angles.
∠5 can be written as ∠ HDC
∠ 3 can be written as ∠ GDE
Vertex of ∠ 2 is D
Therefore, we get that ∠5 can be written as ∠ HDC, ∠ 3 can be written as ∠ GDE and the vertex of ∠ 2 is D.
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For the Adjusted R Squared, which of the following is true: a. Is the same R 2
as in the simple linear regression b. Can decrease if the addition of another X regressor does not lower SSR enough relative to the impact of the increase of k by another X regessor. c. Is between 0 and 1 d. Measures the ratio of the sum of squared residuals compared to the total sum of squares
The correct statement is c. The Adjusted R-squared is a measure used in multiple regression analysis that is between 0 and 1. It is different from the R-squared value in simple linear regression.
The Adjusted R-squared can decrease if the addition of another X regressor does not sufficiently lower the sum of squared residuals (SSR) relative to the impact of increasing the number of predictors (k). It measures the proportion of the variance explained by the predictors, adjusted for the number of predictors and the sample size, rather than the ratio of the sum of squared residuals to the total sum of squares. It provides a measure of how well the regression model fits the data, and it ranges between 0 and 1. A value closer to 1 indicates that a higher proportion of the variance in the dependent variable is explained by the predictors.
Adding another X regressor to the multiple regression model can impact the Adjusted R-squared. If the additional regressor does not significantly contribute to reducing the sum of squared residuals (SSR) relative to the increase in the number of predictors (k), the Adjusted R-squared can decrease. This means that the added regressor does not improve the model's ability to explain the variance in the dependent variable adequately.
However, the Adjusted R-squared does not directly measure the ratio of the sum of squared residuals to the total sum of squares. Instead, it represents the proportion of the variance explained by the predictors, adjusted for the number of predictors and the sample size. It penalizes models with a large number of predictors that may overfit the data, thereby providing a more reliable measure of the model's goodness of fit.
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Suppose that the function f(x) = 5.32 + 0.08x represent the cost of malling an object that weight x pound. How much would it cost to mail an object that weight 36 pounds?
(Note: Express the answer in dollar.cent.)
PLEASE HELP...
The given function is f(x) = 5.32 + 0.08x. By substituting x=36 in this function, we will get the cost to mail an object that weighs 36 pounds. f(x) = 5.32 + 0.08 To find the cost of mailing an object that weighs 36 pounds, we need to substitute x=36 in equation (i).
f(36) = 5.32 + 0.08(36) We need to evaluate the above expression. f(36) = 5.32 + 2.88f(36) = 8.2Hence, it would cost $8.20 to mail an object that weighs 36 pounds. In the given problem, we are given that f(x) = 5.32 + 0.08x represents the cost of mailing an object that weighs x pounds. We are asked to find the cost to mail an object that weighs 36 pounds.
We know that the given function is in the form y = mx + b, where m represents the slope and b represents the y-intercept. Here, the y-intercept represents the fixed cost involved in mailing an object and the slope represents the variable cost involved in mailing an object. In the given function f(x) = 5.32 + 0.08x, the y-intercept is 5.32. This means that there is a fixed cost of $5.32 involved in mailing an object. The slope is 0.08. This means that the cost involved in mailing an object increases by $0.08 for every pound of weight of the object. Substituting x=36 in the function f(x), we get the cost to mail an object that weighs 36 pounds. f(36) = 5.32 + 0.08(36)f(36) = 5.32 + 2.88f(36) = 8.2Therefore, it would cost $8.20 to mail an object that weighs 36 pounds.
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can u explain how to solve this?
Answer: B.pi/2
ABCD is a square
=> Δ ABD is a isosceles right triangle at A
using pythago theorem, we have:
AB² + AD² = BD²
=> 2AD² = 4
⇔ AD² = 2
⇒ AD = √2
through O, draw EF parallel to AD and BC
=> EF is diameter
because EF//AD => EF = AD = √2 (because circle O is inscribed the square ABCD)
=> the area of the circle is \(S=\frac{(\sqrt{2})^{2} }{4}.\pi =\frac{\pi }{2}\)
Step-by-step explanation:
There are only red pins and white pins in a box. A pin is taken at random from the box.
The probability that the pin is red is 0.4
b) Find the probability that the pin is white.
The probability that the pin is red is 0.4. The probability that the pin is white is 0.6, or 60%.
To find the probability that the pin is white, we need to consider that there are only two possible outcomes: red or white. If the probability of the pin being red is 0.4, then the probability of the pin being white can be found by subtracting the probability of it being red from 1.
Let's denote the probability of the pin being white as P(white). We know that P(red) = 0.4. Since there are only two options (red or white), we have:
P(white) = 1 - P(red)
P(white) = 1 - 0.4
P(white) = 0.6
Therefore, the probability that the pin is white is 0.6, or 60%.
This means that out of all the pins in the box, there is a 60% chance that a randomly selected pin will be white. The probability is calculated based on the assumption that each pin has an equal chance of being selected and that the selection process is random.
It's important to note that the sum of the probabilities for all possible outcomes must always be equal to 1. In this case, P(red) + P(white) = 0.4 + 0.6 = 1, which confirms that our probabilities are valid.
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the pages of a book are numbered through . when the page numbers of the book were added, one of the page numbers was mistakenly added twice, resulting in an incorrect sum of . what was the number of the page that was added twice?
xm denotes the number of the page that was added twice. By solving the equation, we can find xm = (S' - S)/2, which is the number of the page that was added twice.
Let the page numbers be denoted by x1, x2, x3, ... , xn.
The sum of the page numbers is given by S = x1 + x2 + x3 + ... + xn.
The sum of the page numbers with the page number added twice is S' = x1 + x2 + x3 + ... + xn + xm + xm
Therefore, S' = S + 2xm
Since S' = S + 2xm, then 2xm = S' - S
Therefore, xm = (S' - S)/2
Therefore, the number of the page that was added twice is xm = (S' - S)/2.
Let x1, x2, x3, ... , xn denote the page numbers of a book. The sum of the page numbers is denoted by S. When the page numbers were added, one of the page numbers was mistakenly added twice, resulting in an incorrect sum of S'. Therefore, S' = S + 2xm, where xm denotes the number of the page that was added twice. By solving the equation, we can find xm = (S' - S)/2, which is the number of the page that was added twice.
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please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44)=87m+m 5. Solve for k: ck+5k=a
Answer:
d = 55.5
x = 1
c = 11
m = \(\frac{1}{122}\)
k = \(\frac{a}{(c + 5)}\)
Step-by-step explanation:
Sorry, the formatting is slightly hard to understand, but I think this is what you meant.
Q1.
\(\frac{1}{6}\)d - 8 = \(\frac{5}{8}\) x 2
Step 1. Simplify.
\(\frac{5}{8}\) x 2 = \(\frac{5}{8}\) x \(\frac{2}{1}\) = \(\frac{10}{8}\)
Step 2. Cancel out the negative 8.
\(\frac{1}{6}\)d - 8 = \(\frac{10}{8}\)
+ 8 to both sides (do the opposite: \(\frac{1}{6}\)d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)
\(\frac{1}{6}\)d = \(\frac{10}{8}\) + 8
Step 3. Simplify.
\(\frac{10}{8}\) + 8 = \(\frac{10}{8}\) + \(\frac{8}{1}\) = \(\frac{10}{8}\) + \(\frac{64}{8}\) = \(\frac{74}{8}\) = \(\frac{37}{4}\)
Step 4. Cancel out the \(\frac{1}{6}\).
\(\frac{1}{6}\)d = \(\frac{37}{4}\)
÷ \(\frac{1}{6}\) from both sides (do the opposite: d is multiplied by \(\frac{1}{6}\) right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)
÷ \(\frac{1}{6}\) = x 6
So....
x 6 to both sides
d = \(\frac{37}{4}\) x 6 = \(\frac{37}{4}\) x \(\frac{6}{1}\) = \(\frac{222}{4}\) = \(\frac{111}{2}\) = 55.5
Step 5. Write down your answer.
d = 55.5
Q2.
3x - 4 + 5x = 10 - 2x × 3
Step 1. Simplify
3x - 4 + 5x = 3x + 5x - 4 = 8x - 4
10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x
Step 2. Cancel out the negative 6x
8x - 4 = 10 - 6x
+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)
14x - 4 = 10
Step 3. Cancel out the negative 4
14x - 4 = 10
+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)
14x = 14
Step 4. Divide by 14
14x = 14
÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])
x = 1
Step 5. Write down your answer.
x = 1
Q3.
7(c - 3) = 14 × 4
Step 1. Expand the brackets
7(c - 3) = (7 x c) - (7 x 3) = 7c - 21
Step 2. Simplify
14 x 4 = 56
Step 3. Cancel out the negative 21
7c - 21 = 56
+ 21
7c = 56 + 21
7c = 77
Step 4. Cancel out the ×7
7c = 77
÷ 7
c = 77 ÷ 7
c = 11
Step 5. Write down your answer.
c = 11
Q4.
11(\(\frac{m}{22}\) + \(\frac{3}{44}\)) = 87m + m × 5
Step 1. Expand the brackets
11(\(\frac{m}{22}\) + \(\frac{3}{44}\)) = (11 x \(\frac{m}{22}\)) + (11 x \(\frac{3}{44}\)) = (\(\frac{11}{1}\) x \(\frac{m}{22}\)) + (\(\frac{11}{1}\) x \(\frac{3}{44}\)) = \(\frac{11m}{22}\) + \(\frac{33}{44}\) = \(\frac{m}{2}\) + \(\frac{3}{4}\)
Step 2. Simplify.
87m + m x 5 = 87m + 5m = 92m
Step 3. Cancel out the add \(\frac{3}{4}\)
\(\frac{m}{2}\) + \(\frac{3}{4}\) = 92m
- \(\frac{3}{4}\)
\(\frac{m}{2}\) = 92m - \(\frac{3}{4}\)
\(\frac{m}{2}\) = \(\frac{92m}{1}\) - \(\frac{3}{4}\)
\(\frac{m}{2}\) = \(\frac{368m}{4}\) - \(\frac{3}{4}\)
\(\frac{m}{2}\) = \(\frac{368m - 3}{4}\)
Step 4. Cancel out the ÷ 4
\(\frac{m}{2}\) = \(\frac{368m - 3}{4}\)
x 4
2m = 368m - 3
Step 5. Cancel out the 368m
2m = 368m - 3
- 368m
-366m = - 3
Step 6. Cancel out the × -366
-366m = -3
÷ -366
m = \(\frac{-3}{-366}\)
m = \(\frac{1}{122}\)
Step 7. Write down your answer.
m = \(\frac{1}{122}\)
Q5.
ck + 5k = a
Step 1. Factorise
ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)
Step 2. Cancel out the × (c + 5)
k(c + 5) = a
÷ (c + 5)
k = a ÷ (c + 5)
k = \(\frac{a}{(c + 5)}\)
A square has a side length of 13 meters. What is the area of the square?
If the dimensions of the square are doubled, what will be the area of the new square?
Answer:
Area of original = 169m^2
Area of new = 676m^2
Step-by-step explanation:
Area of a square = (length of side)^2
13^2 = 13 * 13 = 169
If the dimension is doubled:
(2*13)^2 = 26^2 = 676
Answer:
G00D LuCk
Step-by-step explanation:
Feel free to fail
In Cynthia's state the weekly unemployment compensation is 65% of the 26 week average if the two highest quarters for the that year. In quarter 1 they earned $9,100. In quarter 2 they earned $8,950. In quarter 3 they earned $9,350. In quarter 4 they earned $8,890. What is the 26 week average for these two quarters?
The 26-week average for the two highest quarters is $709.62.
What is quarter?A quarter is a unit of time equal to one-fourth (1/4) of a year or three months. In a standard calendar year, there are four quarters.
According to question:To find the 26-week average for the two highest quarters, we need to add up the earnings for those two quarters and divide by the number of weeks in half a year (26 weeks).
First, we need to identify the two highest quarters:
Q1: $9,100
Q2: $8,950
Q3: $9,350
Q4: $8,890
The two highest quarters are Q1 and Q3, with earnings of $9,100 and $9,350, respectively.
Next, we add up the earnings for these two quarters:
$9,100 + $9,350 = $18,450
Then, we divide by the number of weeks in half a year (26 weeks) to get the 26-week average:
$18,450 / 26 = $709.62 (rounded to the nearest cent)
Therefore, the 26-week average for the two highest quarters is $709.62.
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A sample is selected from a population with a mean of μ = 65 and a standard deviation of σ = 15. if the sample has n = 9 scores, what are the expected value of m and the standard error of m?
The Expected value of M is 65
The Standard error of M is 5
The mean of the distribution of sample means is called the expected value of M.The standard deviation of the distribution of sample means is called the standard error of M.Given,
The sample score, n = 9
The Standard deviation, σ = 15
Population mean, μ = 65
Then,
The Expected value of M = μ
∴ The Expected value of M = 65
The Standard error of M = σ/\(\sqrt{n}\)
\(=\frac{15}{\sqrt{9} } \\\\=\frac{15}{3} \\=5\)
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2.5(4+2/5)=-13 how do I solve this
Answer: You add 4+2/5 then multiply it times 2.5
Step-by-step explanation:
If you Evaluate it your answer will be: 11 = -13
To study the effect of naps on student grades, two experimental treatments are planned: an eight-hour school day with a one-hour nap for one group
versus and eight-hour school day with a 30-minute nap for another. Which of the following groups would serve best as a control for this study?
A third group that takes a one-hour nap or a 30-minute nap randomly each day
A third group that shortens the school day to six hours
A third group in which no naps occur
A third group that splits the day with a 30-minute nap in the morning and a 30-minute nap in the afternoon
A third group in which each student chooses either a 30-minute nap or a one-hour nap
Answer:
A third group in which no naps occur
Step-by-step explanation:
Control group: In a study or an experiment, the term "control group" is described as a specific group that doesn't receive or being provided any sort of treatment by the investigator or researcher ans therefore used as a particular benchmark or criteria to analyze or measure the way other tested participants do. It is generally used as a specific strategy that minimized the effects of different variable except independent variable.
Answer:
above is correect. i took the test.
Step-by-step explanation:
I WILL GIVE BRAINLIEST!! PLEASE DONT IGNORE!! NEED ANSWER ASAP!!
Answer:
i gotchu the first one is 3 the second one is 1
Step-by-step explanation:
Fill in the table using this function rule.
y=29-4x
Answer:
x.1 y.25
x.3 y.17
x.5 y.9
x.6 y.5
Step-by-step explanation:
Find the radius of the button.
28 mm
radius:
mm
Answer:
14 mm
Step-by-step explanation:
Just write down the answer.
Answer:
28mm
Step-by-step explanation:
is the right answer
a fair coin is tossed 27 times. in how many outcomes do at least 3 tails occur? a) 134,217,349 b) 134,214,424 c) 134,217,350 d) 2,925 e) 1 f) none of the above.
The number of outcomes if at least 3 tails occur for a fair coin tossed 27 times is 134217700.
Probability is the likelihood or chance that an event will occur.
The formula for calculating probability is expressed as:
Probability = Expected outcome/Total outcome
If a fair coin is tossed 27 times, the total number of outcomes will be expressed as:
2²⁷ = 134217728
If at least 3 tails occur, the expected outcome will be 27 times.
Pr(at least 3 tails occur) = 2²⁷ - 27 - 1
Pr(at least 3 tails occur) = 134217728 - 28 = 134217700
Hence the number of outcomes if at least 3 tails occur is 134217700.
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The complete question is mentioned below:
A fair coin is tossed 27 times. In how many outcomes do at least 2 tails occur? a) 134,217,700 b) 134,217,349 c) 134,217,701 d) 351 e) 1 f) None of the above.
What is the measure of /x?
Angles are not necessarily drawn to scale.
PLS HELP I REALLY NEED TO GET THIS RIGHT!!
Answer:
x = 66°
Step-by-step explanation:
First, you can use exterior angle theorem to say that
\(m<JIH = m<JDI + m<DJI\)
and you can substitute to get:
105° = 39° + m<DJI
m<DJI = 66°
m<DJI and m<AJF are vertical angles, so they equal each other:
m<DJI = m<AJF
m<AJF = x = 66°
8. Comparison between a linear–quadratic state estimator and
Particle Filter
A linear-quadratic state estimator and a particle filter are both estimation techniques used in control systems, but they differ in their underlying principles and application domains.
A linear-quadratic state estimator, often referred to as a Kalman filter, is a widely used optimal estimation algorithm for linear systems with Gaussian noise. It assumes linearity in the system dynamics and measurements. The Kalman filter combines the predictions from a mathematical model (state equation) and the available measurements to estimate the current state of the system. It provides a closed-form solution and is computationally efficient. However, it relies on linear assumptions and Gaussian noise, which may limit its effectiveness in nonlinear or non-Gaussian scenarios.
On the other hand, a particle filter, also known as a sequential Monte Carlo method, is a non-linear and non-Gaussian state estimation technique. It employs a set of particles (samples) to represent the posterior distribution of the system state. The particles are propagated through the system dynamics and updated using measurement information. The particle filter provides an approximation of the posterior distribution, allowing it to handle non-linearities and non-Gaussian noise. However, it is computationally more demanding than the Kalman filter due to the need for particle resampling and propagation.
The choice between a linear-quadratic state estimator and a particle filter depends on the characteristics of the system and the nature of the noise. The Kalman filter is suitable for linear and Gaussian systems, while the particle filter is more versatile and can handle non-linearities and non-Gaussian noise. However, the particle filter's computational complexity may be a limiting factor in real-time applications.
In summary, a linear-quadratic state estimator (Kalman filter) is a computationally efficient estimation technique suitable for linear and Gaussian systems. A particle filter, on the other hand, provides more flexibility by accommodating non-linearities and non-Gaussian noise but requires more computational resources. The choice between these methods depends on the specific system characteristics and the desired accuracy-performance trade-off.
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How many powers of 7 are contained in 10?
There is only 1 power of 7 contained in 10.
Students use powers of numbers to solve this problem and learn what is occurring to the numbers as a result.
Students also learn how to divide a seemingly vast and challenging equation into smaller, more accessible components. The pupils should understand that raising 7 to a power only produces a finite number of unit digits. Furthermore, as the power of 7 rises, these particular numbers "circle round." 7, 9, 3, and 1 make up this cycle.
The digit in the tens place is the same.
The total number of times we multiply a number is known as its exponent or power. For instance, 2 to the power 3 denotes a 3x3 multiplication of 2.
The largest power of 7 that is less than 10 is 7^1 = 7, therefore there is only 1 power of 7 contained in 10.
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There is only 1 power of 7 contained in 10.
Students use powers of numbers to solve this problem and learn what is occurring to the numbers as a result.
Students also learn how to divide a seemingly vast and challenging equation into smaller, more accessible components. The pupils should understand that raising 7 to a power only produces a finite number of unit digits. Furthermore, as the power of 7 rises, these particular numbers "circle round." 7, 9, 3, and 1 make up this cycle.
The digit in the tens place is the same.
The total number of times we multiply a number is known as its exponent or power. For instance, 2 to the power 3 denotes a 3x3 multiplication of 2.
The largest power of 7 that is less than 10 is 7^1 = 7, therefore there is only 1 power of 7 contained in 10.
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help plzzzzzz as soon as possible
Answer:
when x = -5 y is -48
when x is -1 y is -8
when x is 0 y is 2
when x is 1 y is 12
Step-by-step explanation:
This data is going to be plotted on a scatter graph.
Length(cm) 103 129 99 82 110
Mass(kg) 4.1 2.6 5.7 1.9 2.8
The length axis is shown below
Choose the best scale for this axis
What should the values of A and B be
The best scale for the length axis would be to have a range of 0 to 130, with A = 0 and B = 130. This scale is ideal because it displays the range of the data points without being too small or too large.
To calculate the values of A and B, the range of the data must first be determined. The range is 129 - 82 = 47. Since the range is 47, the scale should be 0 to 130 to account for the extra 3 cm. Therefore, A = 0 and B = 130.The scale of 0 to 130 is ideal because it allows for the data points to be seen easily without making the graph too small or too large. Without this scale, it would be difficult to see the data points because either the range would be too small, or the graph would be too large. Additionally, this scale ensures that all of the data points are visible on the graph.
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What is the domain? I need help on this problem
The domain of the function \(f(x) = \sqrt{\frac{1}{3}x + 2\) is (d) x ≥ -6
How to determine the domain of the functionFrom the question, we have the following parameters that can be used in our computation:
\(f(x) = \sqrt{\frac{1}{3}x + 2\)
Set the radicand greater than or equal to 0
So, we have
1/3x + 2 ≥ 0
Next, we have
1/3x ≥ -2
So, we have
x ≥ -6
Hence, the domain of the function is (d) x ≥ -6
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A pair of shorts cost $14. If they are on sale for 40% off, what is the sale price of the shorts?
Answer:8.4
Step-by-step explanation:
Ten percent of 14 is 1.4 so add 1.4 4 times or multiple 1.4 by 4 and you get 5.6, then subtract 14 by 5.6 and you get 8.4
You earn $44.55 in 9 hours. Your friend earns $51.00 in 12 hours. How much do you AND your friend earn in 20 hours? HINT- You need to calculate how much you both make in 1 hour first! 1 point
Answer:
I earn $99. my friend earns $85. We both earn $184
Step-by-step explanation:
Steps
Find the amount earned per hour for each friend multiply the value gotten by 20 hours Add the amountAmount i earn per hour = 44.55 / 9 = $4.95
Amount my friend earns = 51 /12 = $4.25
Amount earned in 20 hours
4.95 x 20 = 99
4.25 x 20 = 85