is toothpaste suspension,colloid,solution?​

Not enough information man

above because its above

Answer: The final pressure inside the tank is 8.41 kPa.

Explanation: We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We are given P1 = 25.0 kPa, T1 = -50 C = 223 K, and V1 is unknown. We also know that the temperature decreases by a factor of three, so T2 = T1/3 = 223/3 K.

To find V2, we need to assume that the steel container is rigid and its volume remains constant. Therefore, V1 = V2, and we can cancel out the volume from the equation:

P1/T1 = P2/T2

Substituting the values, we get:

P2 = P1 * T2 / T1 = 25.0 * (223/3) / 223 = 8.41 kPa

Therefore, the final pressure inside the tank is 8.41 kPa.

Answer:

So if pressure of a gas is increased by 25%, the volume of a gas is decreased by 25%.

Explanation:

Every chemical has an equal amount of atoms on both the product and reactant sides, and the equation is considered to be balanced without any inequalities. Hence, C3H8 + 5O2 3CO2 + 4H2O is the balanced chemical equation.

In order to make a stoichiometry equal in both the reactants and the products, add equations whenever necessary prior to the symbols or formulations.

In science, if an element is still, we state it is balanced. An thing is in a thermodynamic equilibrium when it's fully balanced. Any forces acting on the item are counterbalanced by forces moving the other way. The average location of the gravitational pull on an item is known as the centre of gravity.

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Answer:

NaHCO3 + NaOH → Na2CO3 + H2O.

Explanation:

Answer: 1

Explanation: one

Chloric acid is a neutral compound and an oxoacid with strong oxidizing power. In the compound (chloric acid), chlorine has an oxidation number of +5. Thus, option c is correct.

The oxidation number is defined as electrons that are transferred by accepting and donating in a chemical bond formation. They denote the atoms that have gained and donated electrons by the positive and negative states.

As chloric acid is a neutral compound, the equivalent will be zero. The oxidation state of the hydrogen atom is generally taken as 1 and that of oxygen as -2 as it requires two more electrons in its valence shell.

The oxidation number will be estimated as,

HCIO₃ = 0

+1 + x + 3(-2) = 0

+1 + x - 6 = 0

x = + 6 - 1

x = + 5

Therefore, option c. chlorine has a +5 oxidation number in chloric acid.

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The new volume assuming that the pressure and temperature remain constant is 0.46 L and the correct option is option 1.

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as-

                        PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Initial volume = 1.5 L

Initial moles = 7.5 moles.

Moles remaining = 2.3 moles

\(\frac{n_{1} }{V_{1} } = \frac{n_{2} }{V_{2} }\)

\(\frac{7.5}{1.5 } = \frac{2.3}{V_{2} } }\)

V₂ = 0.46 L

Thus, the ideal selection is option 1.

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Answer:

0.60 moles of atoms of carbon

Explanation:

Step 1: Given data

Step 2: Calculate the number of carbon atoms in the given sample

According to the chemical formula of the compound, the molar ratio of C to O is 2:6, that is, there are 2 moles of atoms of C every 6 moles of atoms of O. The number of moles of atoms of C is:

1.8 mol O × 2 mol C / 6 mol O = 0.60 mol C

Eukaryotic and prokaryotic cells are similar in having ribosomes, cell membrane, and DNA, and have the same system of DNA replication.

Prokaryotic cells are primitive cells with no nucleus or membrane-bound organelles. The cells usually have cell walls whose content can vary depending on the organism. Their genetic materials lie freely within the cytoplasm.

Eukaryotic cells, on the other hand, are plant and animal cells with nuclei and membrane-bound organelles such as mitochondrion and chloroplast. Plant cells have cell walls while animal cells do not. The genetic materials of eukaryotic cells lie largely in the nuclei while organelles like mitochondrion and chloroplast have also been shown to contain some DNA.

While both cells are different in a lot of ways, they also have some similarities. These include:

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Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.

In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.

In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.

Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

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In 0.8291 moles of hexane (\(C_6H_1_4\)) there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

To determine the number of liters in 0.8291 moles of hexane (C6H14), we need to use the ideal gas law equation:

PV = nRT

where:

P = pressure (atm)

V = volume (L)

n = moles of gas

R = gas constant (0.0821 L*atm/mol*K)

T = temperature (K)

We need to rearrange this equation to solve for V:

V = nRT/P

First, we need to calculate the number of moles of hexane:

n = mass/molar mass

The molar mass of hexane (C6H14) is:

6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

n = 0.8291 moles

Next, we need to convert the temperature to Kelvin. Assuming room temperature (25°C or 298 K):

T = 298 K

Finally, we need to assume a pressure value. Let's assume atmospheric pressure (1 atm).

P = 1 atm

Now we can plug in the values and solve for V:

V = (0.8291 mol)(0.0821 L*atm/mol*K)(298 K)/(1 atm)

V = 20.8 L

Therefore, there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

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6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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931 g of nitric acid is required to react with 454 g of C₇H₈ in the reaction between them.

It refers to the relation between the amount of reactants and products. It is a quantitative study concerned with mainly numbers.It helps in utilizing the balanced chemical equations for calculating the quantity of reactants and products.

The reaction between nitric acid and C₇H₈ takes place as follows:

C₇H₈+3 HNO₃ \(\rightarrow\)C₇H₅N₃O₆+ 3 H₂O

1 mole of C₇H₈ reacts with 3 moles of nitric acid .454 g of C₇H₈ are converted to moles using molar mass and then it's related with moles of C₇H₈ and moles of nitric acid .Then, the moles of nitric acid are converted to grams

454 g C₇H₈×1 mole C₇H₈/92.14 g ×3 moles nitric acid/1 mole C₇H₈×63.01 g nitric acid/ 1 mole nitric acid=931 g

Thus, 931 g of nitric acid is required to react with 454 g C₇H₈.

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Answer:

0.394 atm

Explanation:

Mathematically, when we increase the pressure of a gas, we are increasing its concentration and when we decrease the pressure, we are decreasing its concentration.l at same temperature

What this means is that pressure and concentration are directly proportional.

Representing concentration by c and pressure by p, we have;

P1/C1 = P2/C2

From the question;

P1 = 0.719 atm

P2 = ?

C1 = 429.7 ppm

C2 = 235.3 ppm

Now, we can rewrite the equation to be;

P1C2/C1 = P2

Substituting the values we have;

0.719 * 235.3/429.7 = 0.394 atm

Answer:

The balanced equation is:

2AgNO3(aq) + H2SO4(aq) → Ag2SO4(s) + 2HNO3(aq)

From the balanced equation, 2 moles of AgNO3 react with 1 mole of H2SO4 to form 1 mole of Ag2SO4.

Given that 0.205 moles of AgNO3 react with 0.155 moles of H2SO4, we can calculate the limiting reagent as follows:

1 mole of H2SO4 reacts with (2 moles of AgNO3 / 1 mole of H2SO4) = 2 moles of AgNO3

Therefore, H2SO4 is the limiting reagent since there are only 0.155 moles of it, which is less than the required 0.205 moles of AgNO3.

Using the amount of H2SO4, we can calculate the amount of Ag2SO4 formed:

0.155 moles of H2SO4 × (1 mole of Ag2SO4 / 2 moles of AgNO3) × (2 × 107.87 g/mol) = 16.95 g

Therefore, the mass of Ag2SO4 that could be formed is 16.95 grams.

I Hope This Helps!

Answer:

The balanced equation for the reaction is:

2AgNO3(aq) + H2SO4(aq) → Ag2SO4(s) + 2HNO3(aq)

From the equation, we see that 2 moles of AgNO3 react with 1 mole of H2SO4 to produce 1 mole of Ag2SO4. Therefore, the limiting reagent is H2SO4, as it has the smaller number of moles.

The balanced equation shows that 1 mole of H2SO4 produces 1 mole of Ag2SO4, so 0.155 moles of H2SO4 will produce 0.155 moles of Ag2SO4.

The molar mass of Ag2SO4 is:

2(Ag) + S + 4(O) = 2(107.87 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 311.99 g/mol

Therefore, the mass of Ag2SO4 that could be formed is:

0.155 moles × 311.99 g/mol = 48.36 g

So, the mass in grams of Ag2SO4 that could be formed is 48.36 g.

Explanation:

determine the genotypes of the parent organisms.

write down your "cross" (mating)

draw a p-square.

4. " ...

determine the possible genotypes of the offspring by filling in the p-square.

summarize results (genotypes & phenotypes of offspring)

Answer:

Yes

Explanation:

It was Dmitri Mendeleev, a Russian chemist and teacher.

Answer:

No, it wasn't. On Feb.17 in 1869, a very intelligent Russian professor of chemistry, Dimitri Ivanovich Mendeleev created his first part of the periodic table. I hope that helps you.

Explanation:

Answer:

A) I think I might be wrong :^

The amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance. It is a physical property that determines the direction of heat flow between two objects or systems in contact with each other. Temperature is measured in degrees Celsius (°C) or Fahrenheit (°F), or in kelvin (K) in the International System of Units (SI).

The amount of heat (q) required to raise the temperature of a substance can be calculated using the formula:

q = m x c x ΔT

Where:

m = mass of the substance (in grams)

c = specific heat of the substance (in J/g oC)

ΔT = change in temperature (in oC)

Plugging in the values given:

m = 34.2 g

c = 0.9 J/g oC

ΔT = 34 oC

q = (34.2 g) x (0.9 J/g oC) x (34 oC)

q = 1043.52 J

Therefore, the amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

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Answer:

\([NO_2]=0.112M\)

Explanation:

Hello there!

In this case, since the second-order integrated law is given by the following equation:

\(\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt\)

Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:

\(\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}\)

\([NO_2]=\frac{1}{8.933M^{-1}} =0.112M\)

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The peroxide addition would yield a product that is different from the antiperoxide addition

Markovnikov's rule states that when a protic acid HX is added to an alkene, the acid hydrogen (H) forms a bond with the carbon atom that has the greatest number of hydrogen atoms, while the halide (X) group forms a bond with the carbon atom that has the fewest hydrogen atoms.

This can be summed up with the phrases "the rich get richer" and "the poor get poorer" in terms of hydrogen. This fundamental principle of alkene chemistry aids in predicting the results of addition reactions.

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Answer:

76.09 g/mole

Explanation:

So, the molar mass is 3(12.011)+8(1.00794)+2(15.9994), which is about 76.09 g/mole

Answer:

0.42 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of acid, HCl (nₐ) = 1

The mole ratio of base, NaOH (n₆) = 1

Finally, we shall determine the molarity of the base, NaOH. This can be obtained as follow:

Volume of acid, HCl (Vₐ) = 25 mL

Molarity of acid, HCl (Mₐ) = 0.25 M

Volume of base, NaOH (V₆) = 15 mL

Molarity of base, NaOH (M₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.25 × 25 / M₆ × 15 = 1

6.25 / M₆ × 15 = 1

Cross multiply

6.25 = M₆ × 15

Divide both side by 15

M₆ = 6.25 / 15

M₆ = 0.42 M

Therefore, the molarity of the base, NaOH is 0.42 M

This problem is providing us with the rate constant and initial mass for radon's decay. Thus, several questions regarding how much it is left over after specific times are proposed and solved along this.

In chemistry, radioactive decay is a process whereby an unstable atomic nucleus loses energy by radiation, and therefore its mass decreases as the time goes by.

In such a way, one can use the following equation for the required questions:

\(A=Ao*exp(-t*k)\)

Where A is how much is left over, Ao the initial amount, t the elapsed time and k the rate constant. Thus, we can proceed as follows:

(a) we just plug in the 2.96 days:

\(A=8.64g*exp(-2.96day*0.175day^{-1})\\\\A=5.15g\)

(b) we need to convert 46.4 hours to days:

\(A=8.64g*exp(-46.4hr*\frac{1day}{24hr} *0.175day^{-1})\\\\A=6.16g\)

(c) we assume this is a first-order reaction so we use its definition of half-life as:

\(t_{1/2}=\frac{ln(2)}{k} =\frac{ln(2)}{0.175day^{-1}}=3.96day\)

(d) if five half-lives have taken place, the radon which is left over turns out to be:

\(A=8.64g*(\frac{1}{2} )^5\\\\A=0.270g\)

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The mirror image of D-galactitol is L-galactitol. The main stereochemical relationship between  D-galactitol is L-galactitol is D-galactitiol is a meso compound whereas L-galactitol is not.

Stereochemistry is the branch of chemistry concerned with the three-dimensional arrangement of atoms and molecules and the effect of this on chemical reactions.

In stereochemistry, stereoisomerism, or spatial isomerism, is a form of isomerism in which molecules have the same molecular formula and sequence of bonded atoms (constitution), but differ in the three-dimensional orientations of their atoms in space.

Galactitol is an optically inactive hexitol having meso-configuration. It has a role as a metabolite, a human metabolite, an Escherichia coli metabolite and a mouse metabolite.

Therefore, The mirror image of D-galactitol is L-galactitol. The main stereochemical relationship between  D-galactitol is L-galactitol is D-galactitiol is a meso compound whereas L-galactitol is not.

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we can do soo by noticing any colour change, or by the formation of an insoluble precipitate or by the evolution of a gas.

In comparison to modern, highly accurate density meters or pycnometers, hydrometers are far less accurate and temperature.

Thus,  Although they require very large sample sizes, hydrometers are rather simple to operate. Usually, 300 to 500 ml per measurement are required. Hydrometers frequently require calibration off-site as well.

With measurements taken by eye, user error is a major issue, and temperature management is especially challenging. Inaccurately bringing and maintaining samples at temperature might take a long time, and once more, user perception of temperature levels is used to determine temperature levels.

Pycnometers and hydrometers have a further problem in that the findings of alcohol measurement are challenging to evaluate and record.

Thus, In comparison to modern, highly accurate density meters or pycnometers, hydrometers are far less accurate and temperature.

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Answer:

It converts The liquid into a gas at the same temperature.

Explanation:

Answer:

it converts the liquid into gas at the same temperature

Explanation:

when heat is added to a liquid at boiling temperature it converts the liquid into gas at that same boiling temperature

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

Elements are placed in order on the periodic table based on their atomic number, how many protons they have. In a neutral atom, the number of electrons will equal the number of protons, so we can easily determine electron number from atomic number.

Explanation:

Answer: Elements are placed in order on the periodic table based on their atomic number, how many protons they have. In a neutral atom, the number of electrons will equal the number of protons, so we can easily determine electron number from atomic number.

Explanation: