Answer:
Zero work
Explanation:
Recall that work done on an object is defined as the product of the net force applied to an object times the distance it travels in the same direction as the force.
Since in this case Jim used a given force to push a rock, but it didn't move, then he did zero work (because the distance moved is zero).
The environment affects people, but people don't affect the environment.
TRUE OR FALSE
Answer: False
Explanation:
The statement that the environment affects people, but people don't affect the environment is incorrect. It should be noted that people also affect the environment.
Some of our impact on the environment include pollution, deforestation, overpopulation, burning of fossil fuels etc. Thus has resulted in changes such as erosion, climate change, etc.
Explain how a dial test Indicator (DTI) reading is adjusted when the gauge is not positioned at right angle to the contact surface
The difference between the surfaces of two things, along a circle, or between two or more separate objects.
What is a dial test Indicator?In mechanical and industrial applications, dial indicators are measuring devices. They are designed to measure in either vertical or horizontal positions and are commonly used to assure the correctness of machined parts by measuring clearances, tolerance, and variation in tolerance.
A dial test indictor is made up of the following components: a circular body, an indicating hand, a revolution counter, a graduated scale, and a spindle with a contact point.
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1. How long would the car in Sample Problem C take to come to a stop from its initial velocity of 20.0 m/s to the west? How far would the car move before stopping? Assume a constant acceleration. Aron1
The time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.
What is the distance?The length of the path traveled by the body is known as the distance covered by the body.
Distance is a 1-dimensional phenomenon. its unit is a meter(m). The distance can be found by the product of velocity and time.
The given data in the problem will be
u is the initial velocity =20m/sec
t is the time =?
d is the distance =?
From the Newtons second law;
\(\rm F \triangle t = \triangle P \\\\ \triangle t = \frac{\triangle P }{F} \\\\ \triangle t = \frac{m(v_f-v_i)}{F} \\\\ \ \triangle t = \frac{2240 (0-20))}{8410} \\\\ \triangle t = 5.3 \ sec \\\\)
The distance travelled before the car stop is,
\(\rm \triangle t = \frac{1}{2} (v_f+v_i)\traingle t \\\\ \traingle x = \frac{1}{2} (-20+0)5.3 \\\\\ \triangle x= -53.3 m \ west\)
Hence,the time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.
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a horse was at rest.what was the final velocity of the horse if it covered 200 meters in 16 seconds?
Answer:
12.5m/s
Explanation:
Simplify the proportion.
200/16 = 100/8 = 50/4 = 25/2 = 12.5
Suppose you ran 53 km in 67 min. With what speed did you run?
Answer:
47.46 kilometers an hour
Explanation:
hope this helped
0.8 km/h
speed = distance / time
When a skateboarder comes to a stop at the top of either side of a ramp, what happens to the potential and kinetic energy?
Answer:
potential is at maximum
kinetic energy is zero
Near the surface of Earth, an electric field points radially downward and has a magnitude of approximately 100 N/C. What charge (magnitude and sign) would have to be placed on a penny that has a mass of 3 g to cause it to rise into the air with an upward acceleration of 0.19 m/s2?
Answer:
q = 2.997*10^-4C
Explanation:
In order to find the required charge that the penny have to have, to acquire an upward acceleration, you take into account that the electric force on the penny must be higher than the weight of the penny.
You use the second Newton law to sum both electrical and gravitational forces:
\(F_e-W=ma\\\\qE-mg=ma\) (1)
Fe: electric force
W: weight of the penny
q: required charge = ?
m: mass of the penny = 3g = 0.003kg
E: magnitude of the electric field = 100N/C
g: gravitational acceleration = 9.8m/s^2
a: acceleration of the penny = 0.19m/s^2
You solve the equation (1) for q, and replace the values of the other parameters:
\(q=\frac{ma+mg}{E}=\frac{m(a+g)}{E}\\\\q=\frac{(0.003kg)(0.19m/s^2+9.8m/s^2)}{100N/C}\\\\q=2.997*10^{-4}C\)
It is necessary that the penny has a charge of 2.997*10^-4 C, in order to acquire an upward acceleration of 0.19m/s^2
If an ice skater pulls their hands towards their body, will their angular momentum and kinetic energy both increase?
Answer:
The angular momentum depends on both the angular velocity and the mass distribution of the object. You can change this angular momentum by exerting a torque (a twisting force)—but with no external torque, the angular momentum is conserved. Now getting back to the ice skater.
What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.
The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.
Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.
Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.
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An apple is thrown at an angle of 30° above the horizontal from the top of a building 20 m high. Its initial speed is 40 ms-1. Calculate
a)the time taken for the apple to strikes the ground
b) the distance from the foot of the building will it strikes the ground
c) the maximun height reached by the apple from the ground
Answer:
(a) 4.83 seconds
(b) 167.3m
(c) 40m
Explanation:
This is a two-dimensional motion. Therefore, the components of the initial velocity - \(u_X\) and \(u_Y\) - in the x and y directions are given as follows:
\(u_X\) = u cos θ --------------(*)
\(u_Y\) = u sin θ -------------(**)
Where
θ = angle of projection
(a) To calculate the time taken for the apple to strike the ground.
For simplicity, let's first calculate the maximum height H reached by the apple.
Using one of the equations of motion as follows, we can find H:
v² = u² + 2as ---------------(i)
Where;
v = velocity at maximum height = 0 [at maximum height, velocity is 0]
u = initial vertical velocity of the apple = \(u_Y\)
=> u = \(u_Y\) = u sin θ
=> \(u_Y\) = 40 sin 30°
=> \(u_Y\) = 40 x 0.5
=> \(u_Y\) = 20 m/s
a = acceleration due to gravity = -g [apple moves upwards against gravity]
a = -10m/s²
s = H = maximum height reached from the top of the building
Substitute these values into equation (i) above to have;
0² = \(u_Y\)² + 2aH
0² = (20)² + 2(-10)H
0 = 400 - 20H
20H = 400
H = 20m
The total time taken to strike the ground is the sum of the time taken to reach maximum height and the time taken to strike the ground from maximum height.
=>Calculate time t₁ to reach maximum height.
Using one of the equations of motion, we can calculate t₁ as follows;
v = \(u_Y\) + at ---------------(ii)
Where;
v = velocity at maximum height = 0
u = initial vertical velocity of the apple = \(u_Y\)
a = -g = -10m/s² [acceleration due to gravity is negative since the apple is thrown upwards to reach maximum height]
t = t₁ = time taken to reach maximum height.
Equation (ii) then becomes;
0 = 20 + (-10)t₁
10t₁ = 20
t₁ = 2 seconds
=>Calculate time t₂ to strike the ground from maximum height.
Now, using one of the equations of motion, we can calculate the time taken as follows;
Δy = \(u_Y\) t + \(\frac{1}{2}\)at ---------------(iii)
Where;
Δy = displacement from maximum height to the ground = maximum height from top of building + height of building = 20 + 20 = 40m
a = g = 10m/s² [acceleration due to gravity is positive since the apple is now coming downwards from maximum height]
t = t₂ [time taken to strike the ground from maximum height]
\(u_Y\) = initial vertical velocity from maximum height = 0
\(u_Y\) = 0
Equation (iii) then becomes
40 = 0t + \(\frac{1}{2}\)(10)t₂²
40 = 5t₂² [divide through by 5]
8 = t₂²
t₂ = ±\(\sqrt{8}\)
t₂ = ±\(2\sqrt{2}\)
t₂ = +2\(\sqrt{2}\) or -2\(\sqrt{2}\)
since time cannot be negative,
t₂ = 2\(\sqrt{2}\) = 2.83 seconds
Therefore, the time taken for the apple to strike the ground is;
t₁ + t₂ = 2 + 2.83 = 4.83 seconds
(b) The distance from the foot of the building where the apple will strike the ground
Since this is the horizontal distance, we use the horizontal version of equation (iii) as follows;
Δx = \(u_X\) t + \(\frac{1}{2}\)at -----------(v)
Where
Δx = distance from the foot of the building to where the apple strikes the ground.
\(u_X\) = initial horizontal velocity of the apple as expressed in equation (*)
\(u_X\) = 40 cos 30
\(u_X\) = 34.64 m/s
t = time taken for the motion of the apple = 4.83 seconds [calculated above]
a = acceleration due to gravity in the horizontal direction = 0. [For a projectile, there is no acceleration in the horizontal direction since velocity is constant]
Substitute these values into equation (v) as follows;
Δx = \(u_X\) t + \(\frac{1}{2}\)(0)t
Δx = 34.64 x 4.83
Δx = 167.3 m
Therefore, the distance from the foot of the building is 167.3m
(c) The maximum height reached by the apple from the ground
This is the sum of the height reached from the top of the building (20m which has been calculated in (a) above) and the height of the building.
= 20m + 20m = 40m
Fill in the magnitude of net force for each case. Including the solution plss
Net forces in all above cases will be
A) F net = 0
B) F net = 1 N
C) F net = 5 N
D) F net = 5N
E) F net = 5 N
F) F net = 5 N
G) F net = 9.9 N
H) F net = 9.9 N
A) net force = upward force - downward force
= 4 - 4 = 0
B) net force = rightward force - leftward force = 4 - 3 = 1 N
C) net force
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N
D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N
E) balancing horizontal forces
rightward force - leftward force = 5 - 2 = 3 N
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = 5 N
F) balancing vertical forces
-5 + 2 = -3 N
using Pythagoras theorem
\(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N
G) using Pythagoras theorem
F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
H ) balancing horizontal forces
10 - 3 = 7 N
\(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
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A student throws a baseball vertically upward and then catches it. What would that graph look like?
If an object accelerates at 40 m/s^2 in four minutes ("careful this is in minutes),
what will be the final velocity? (assume the object started from rest) *
Change in speed = (acceleration) x (time)
4 minutes = 240 seconds
Change in speed = (40 m/s²) x (240 seconds)
Change in speed = 9,600 m/s
What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.
The driver would definitely NOT get a speeding ticket, because nobody could catch him.
Also, his car would heat up and shoot flames from atmospheric friction.
(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)
Actually, I hope there's nobody in the car. His experience wouldn't be pretty.
A 20m long string has mass of 0.020kg .if 5.0m segment of the string is fixed at both ends and three loops are produced when a force of 10N is applied to the string .calculate the velocity and frequency of the standing wave of the string
Answer:
.
Explanation:
A body dropped over a fixed rough inclined plane of inclination 45 from height h. If after collision velocity of body becomes horizontal
then co-efficient of restitution if co-efficient of friction is 1/2
As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.
Identify the body's starting velocity:
We may use the equation of motion to get the body's initial velocity (u)
\(v^2 = u^2 + 2as\)
\(0 = u^2 + 2(-9.8)m/s^2 * h\)
\(u^2 = 19.6h\)
u = √(19.6h)
Determine the coefficient of restitution (e):The body's initial velocity (u) and initial relative velocity (u_rel) are the same.
The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).
\(e = v_{rel }/ u_{rel}\)
e = 0 / u_rel = 0 / u
Now, one can investigate the forces affecting the body: When a body is on an inclined plane.
There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).
The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).
Determine the conditions for the body to stop:
μ * N = m * g * sin(45°)
μ * (m * g * cos(45°)) = m * g * sin(45°)
μ * cos(45°) = sin(45°)
(1/2) * cos(45°) = sin(45°)
Simplifying further, we have:
√2 / 4 = √2 / 2
Thus, the body will come to rest following the collision if the equation is valid.
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The largest flowers in the world are the Rafflesia Arnoldii, found in Malaysia. A single flower is almost a meter across and has a mass up to 11.0 kg. Suppose you cut off a single flower and drag it along the flat ground. If the coefficient of kinetic friction between the flower and the ground is 0.39, what is the magnitude of the frictional force that must be overcome?
The magnitude of the frictional force that must be overcome is 42.04 N.
What is the magnitude of the frictional force?
The magnitude of the frictional force that must be overcome is calculated by applying Newton's second law of motion as follows;
Mathematically, the formula for the frictional force is given as;
F = μmg
where;
μ is the coefficient of frictionm is the mass of the flowerg is acceleration due to gravityThe magnitude of the frictional force that must be overcome is calculated as;
F = 0.39 x 11 kg x 9.8 m/s²
F = 42.04 N
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Spring constant, Say if we have KEi + PEi + WNC= KEf + PEf , where does the spring potential energy go, before or after?
The spring potential energy is included in the initial potential energy term in the equation KEi + PEi + WNC= KEf + PEf.
What is the formula for calculating the potential energy of a spring?The formula for calculating the potential energy of a spring is PE = (1/2)kx^2, where k is the spring constant and x is the displacement of the spring from its equilibrium position.
How does the spring constant affect the potential energy of a spring?The spring constant (k) determines the stiffness of the spring and how much force is required to stretch or compress it. The greater the spring constant, the more potential energy is stored in the spring for a given displacement from its equilibrium position. This means that a spring with a higher spring constant will have a greater potential energy than a spring with a lower spring constant when stretched or compressed by the same amount.
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35 milliseconds?! that is crazy fast. Another
way to write that is 0.035 seconds. If the
airbag has to inflate 1 meters. How fast does
this airbagtravel? (remember velocity =
distance/time)
Answer:
28 m/s
Explanation:
1m / 0,035 s
v = 28.57 m/s
if you want km/h, multiply witz 3,6
102,85 km/h = 28,57 m/s
Highschool Physics
1. The driver of a car traveling at 9.0m/s is honking their horn. The horn has a frequency of 625 Hz. If the car is moving toward a person waiting at the crosswalk, what frequency of the horn does the person hear?
2. As the same car from question#1 passes the person, what frequency of the horn does the person hear as the car moves away from them?
Using the formula for the Doppler effect:
f' = (v + vr) / (v + vs) * f
Given:
Source frequency (horn): f = 625 Hz
Speed of sound: v = 343 m/s (approximate value at room temperature)
The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.
The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.
Thus:
f' = (v + vr) / (v + vs) * f
= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.
(2)Using the same Doppler effect formula:
f' = (v - vr) / (v - vs) * f
In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.
The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.
Thus:
f' = (v - vr) / (v - vs) * f
= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.
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A pitcher throws a baseball from the pitcher's mound to home plate in 0.46 s. The
distance is 18.4 m. What was the average speed of the baseball?
a. 40 m/s
b. - 40 m/s
c. 0.03 m/s
d. 8.5 m/s
The average speed of the baseball is option a. 40 m/s .
To calculate the average speed of the baseball, we use the formula:
Average Speed = Distance / Time
Given:
Distance = 18.4 m
Time = 0.46 s
Plugging in the values, we have:
Average Speed = 18.4 m / 0.46 s = 40 m/s
Therefore, the average speed of the baseball is 40 m/s.
Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.
Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.
In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.
It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.
Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.
Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.
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A 25 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0.25, and the coefficient of static friction is 0.35. As the angle is increased, find the minimum angle at which the box starts to slip.
24.5°
18.5°
21.3°
19.3°
Up until the moment the box starts to slip, the static friction is maximized with magnitude f, so that by Newton's second law,
• the net force acting on the box parallel to the ramp is
∑ F = mg sin(α) - f = 0
where mg sin(α) is the magnitude of the parallel component of the box's weight; and
• the net force acting perpendicular to the ramp is
∑ F = n - mg cos(α) = 0
where n is the magnitude of the normal force and mg cos(α) is the magnitude of the perpendicular component of weight.
From the second equation we have
n = mg cos(α)
and f = µn = µmg cos(α), where µ is the coefficient of static friction. Substituting these into the first equation gives us
mg sin(α) = µmg cos(α) ==> µ = tan(α) ==> α = arctan(0.35) ≈ 19.3°
Somebody help me please!!!
Answer: Environmental factors are the abiotic factors that interact with and influence the biotic factors. The amount of carbon dioxide, and water clarity affects the sunlight reaching the aquatic organisms.
Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of what?
A) scientific hypothesis
B)technology
C)deductive reasoning
D) scientific method
A scale measures the weight of a light object to be 11.000lbs +- 0.034 lbs. What is the uncertainty if this same scale is used to measure an object that weighs 78.000 lbs? Assume that the percent uncertainty of the scale remains constant.
A)0.034 lbs
B)0.044 lbs
C)0.240 lbs
D)0.310 lbs
Answer: 1)Scientists seek to acquire: scientific hypothesis
2)A scale measures the weight of a light object: 0.240 lbs
3)What does the process of scientific inquiry: It starts with a problem to solve or a question to answer
4)A mouse in a maze scurries 41 cm south: 76 cm southwest
5)When might an object's average velocity be equal to its average speed in two dimensions:
If the object moves in a straight line in one direction represented as positive, then the magnitude of average velocity will be equal to the average speed.
6)Using the velocity versus time graph, calculate the acceleration of Object A: 3 m/s^2
7)What is the range of a bullet fired horizontally at a height of 1.5m: 66.4m
8)What two vertical forces act on a falling leaf: weight, friction
9)What is equal and opposite to the applied force: spring force
10)Using the free-body diagram, calculate the net force: 12N, right
11)How does the force of impact during a collision change: it increases
12)The threads of a screw used to fasten two pieces of wood: by increasing the normal force exerted by the wood on the screw thread
13)A 60 kg skier with an initial velocity of 12 m/s coasts up a hill: 2.5m
14)A 1,500 kg car’s speed changes from 30 m/s to 15 m/s: -506,250 (negative 506,250| NOT POSITIVE)
15)What is true about weather: The weather depends on so many conditions that it is not possible to account for them all in any model.
16)A student records the mass of objects A, B, C, and D: A
17)Newton’s cradle is a contraption where metal balls: friction force
18)In a closed system, an object with a mass of 10 kg: 12kgm/s
19)Given the data, what is the kinetic energy of the: 3J
20)A wedge is a simple machine that is essentially two: A length of 12 in. and a thickness of 2 in.
21)Object A and Object B are at equal distances on opposite: 3/4
22)A geosynchronous satellite has an orbital period of 24: 35,900 km
23)Calculate the eccentricity for the planet if the: 0.0167
24)A planet travels in its orbit close to apogee : the same amount of time
25)If astronomers discovered a new planet and found its: 22.3 AU
Explanation:
Hope this helps you guys!!! <3 (this is for 'A Semester Exam')
What type of bond is most likely to form between two gold (Au) atoms?
Answer:
I believe it would be a metallic bond.
Explanation:
A crane is oriented so that the end of the 25-m boom AO lies in the yz plane. At the instant shown, the tension in cable AB is 5.9 kN Determine the moment about each of the coordinate axes of the force exerted on A by cable AB.
Previous question
0Nm, 147.5 Nm and -147.5Nm are the moment about each of the coordinate axes of the force exerted on A by cable AB.
What is moment?A moment is indeed a mathematical term used in physics that involves the combination of a physical quantity and a distance. Seconds relate to physical quantities that are dispersed from either the reference point and are often described with regard to something like a fixed reference point.
The instant therefore explains the position or arrangement of the amount. For instance, the moment of force, also known as torque, is the result of the force acting on an object and the item's distance first from reference point.
Moment = force ×distance
M = f × d
Moment about the x axis:
M = 5.9 ×0
M = 0Nm
Moment about the y axis:
M =5.9 ×25 = 147.5 Nm
Moment about the z axis:
M = 5.9 × (-25)
M = -147.5Nm
Therefore, 0Nm, 147.5 Nm and -147.5Nm are the moment about each of the coordinate axes of the force exerted on A by cable AB.
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Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
1. Name three ways you were able to change the green sum of forces arrow.
Changing the green sum of forces arrow involves manipulating applied forces, frictional forces, and normal forces, allowing for adjustments in magnitude and direction through various means.
To change the green sum of forces arrow, you can employ the following three strategies:
Adjusting Applied Forces: By modifying the magnitude or direction of the applied forces, you can alter the green sum of forces arrow. If the applied forces are increased or directed in a different way, the green sum of forces arrow will change accordingly. For instance, increasing the magnitude of a pushing force will result in a larger green sum of forces arrow in that direction.
Modifying Frictional Forces: Frictional forces play a crucial role in determining the green sum of forces. By changing the coefficient of friction or applying lubricants, you can affect the magnitude of frictional forces acting on an object. Reducing friction will decrease the green sum of forces arrow, while increasing friction will have the opposite effect.
Varying Normal Forces: The green sum of forces arrow can be influenced by adjusting the normal forces acting on an object. Normal forces are perpendicular to the surface and counteract the weight of an object. By changing the angle or surface on which an object rests, you can modify the normal forces. This alteration will subsequently impact the green sum of forces arrow.
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types of polarization physics
Answer:
Linear polarization.
Circular polarization.
Elliptical polarization.
The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in the liquid *
Answer:
The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in the liquid *
Explanation: