- La siguiente tabla, expone cómo desciende la temperatura (T) del aire con la altitud(h): Temperatura (ºC) 15 13,5 12 10,5 9 Altitud (m) 0 250 500 750 1000 Dado que la relación entre altura y temperatura viene dada por la siguiente fórmula: T=k*h+To Representa gráficamente los datos de la tabla y calcula To, que es la temperatura inicial (a una altitud de 0), y el valor de la constante k (pista k<0).

The reaction between HCl and NaOH is a 1:1 reaction, the limiting reagent is NaOH. Therefore, all of the NaOH will react with HCl to form MgCl2 and water.

1) To calculate the total mass of the final solution, we first need to calculate the moles of HCl and NaOH used.
Moles of HCl = Volume of HCl (L) x Molarity of HCl
= 0.050 L x 2.199 mol/L
= 0.11 mol

Moles of NaOH = Volume of NaOH (L) x Molarity of NaOH
= 0.054 L x 2 mol/L
= 0.108 mol

Since the reaction between HCl and NaOH is a 1:1 reaction, the limiting reagent is NaOH. Therefore, all of the NaOH will react with HCl to form MgCl2 and water.

Moles of MgCl2 formed = Moles of NaOH used = 0.108 mol

To calculate the mass of the final solution, we need to add the masses of the initial HCl solution, water, and magnesium.

Mass of HCl solution = Volume of HCl x Density of 2M HCl
= 0.050 L x 1.03 g/mL
= 0.0515 g

Mass of water = Volume of NaOH x Density of water
= 0.054 L x 1 g/mL
= 0.054 g

Mass of magnesium = 0.02 g (given)

Total mass of final solution = Mass of HCl solution + Mass of water + Mass of magnesium
= 0.0515 g + 0.054 g + 0.02 g
= 0.1255 g

2) The heat required to raise the MgCl2 solution to the maximum temperature can be calculated using the formula:

Heat = Mass x Specific Heat Capacity x Change in Temperature

We know the mass of the final solution is 0.1255 g and the specific heat capacity of the solution is 3.97 J/gC. The change in temperature can be calculated by subtracting the initial temperature (23C) from the maximum temperature.

Assuming the maximum temperature is 30C,

Change in Temperature = 30C - 23C
= 7C

Heat required = 0.1255 g x 3.97 J/gC x 7C
= 3.51 J

3) The heat required to raise the calorimeter to the maximum temperature can be calculated using the same formula as in part 2. We know the mass of the calorimeter is not given, but we do know the heat capacity of the calorimeter is 6.26 J/C.

Assuming the maximum temperature is 30C,

Change in Temperature = 30C - 23C
= 7C

Heat required = Mass x Heat Capacity x Change in Temperature

We can solve for the mass of the calorimeter:

Mass = Heat required / (Heat Capacity x Change in Temperature)

Mass = 3.51 J / (6.26 J/C x 7C)
= 0.079 g

4) The total heat evolved by the reaction can be calculated by adding the heats required to raise both the solution and the calorimeter to the maximum temperature.

Total Heat Evolved = Heat required to raise MgCl2 solution + Heat required to raise calorimeter
= 3.51 J + (0.079 g x 6.26 J/C x 7C)
= 7.34 J

5) The heat evolved per mole of Mg can be calculated by dividing the total heat evolved by the moles of Mg used.

Heat evolved per mole of Mg = Total Heat Evolved / Moles of Mg
= 7.34 J / 0.108 mol
= 68 J/mol

6) The change in enthalpy for the reaction is the heat evolved per mole of Mg, but with the sign reversed. This is because the reaction is exothermic, meaning heat is released, so the change in enthalpy is negative.

Change in Enthalpy = -68 J/mol

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The slope of the graph mass versus volume for the data is the density of the material.

The slope of a line in mathematics is given as;

m = y2 - y1/x2 - x1.

In this case we have a graph in which the y axis is the mass of the substance and the x axis is the volume of the substance. We know that ratio of the mass to the volume of the substance is the density and that this value is a constant.

As such, the slope of the graph mass versus volume for the data is the density of the material.

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The characteristics and the type of molecular bond they describe:

1. Bonds found in Halite (between Na⁺ and Cl⁻): Ionic bond

2. Bonds found between Si and O in the Si-O tetrahedron: Covalent bond

3. Bonds inside the water molecule (between the H and O): Covalent bond

4. Bonds that exist between two water molecules: Hydrogen bond

5. Strongest bond type: Covalent bond

6. Weakest bond type: Van der Waals bond

7. Bonds that are used by water to dissolve salt: Ionic bond

The ionic bond is a type of molecular bond found in halite (between Na⁺ and Cl⁻). The Si-O tetrahedron is held together by a covalent bond. The bond inside the water molecule (between the H and O) is also a covalent bond. The hydrogen bond is the type of bond that exists between two water molecules. The covalent bond is the strongest bond type, while the van der Waals bond is the weakest bond type. Water uses the ionic bond to dissolve the salt.

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Answer:

15000N/m²

Explanation:

Given parameters:

Force exerted by the girl  = 450N

Area  = 300cm²

Unknown:

Pressure exerted by her feet  =?

Solution:

Pressure is the force per unit area on a body;

    Pressure  = \(\frac{force }{area}\)

We need to convert the given area to m²;

        10000cm²   =  1m²

        300cm²  = \(\frac{300}{10000}\)   = 0.03m²

Pressure = \(\frac{450}{0.03}\)   = 15000N/m²

Polar protic solvents are preferable for Sn1 reactions because they are capable of stabilizing the intermediate carbocation and the leaving group through hydrogen bonding and solvation, thus promoting the reaction's rate and efficiency.

Polar protic solvents are preferable for Sn1 reactions because they have the ability to stabilize the carbocation intermediate that is formed during the reaction. The polar protic solvent can do this by solvating the carbocation through hydrogen bonding. This stabilization helps to lower the activation energy required for the reaction to occur, making it more favorable.

Additionally, the polar nature of the solvent helps to increase the rate of the reaction by facilitating the dissociation of the leaving group. Overall, the use of a polar protic solvent in Sn1 reactions can lead to increased yields and faster reaction rates.
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Answer:

Option A. 1.02g of Fe.

Explanation:

Step 1:

The balanced equation for the reaction.

3Mg + Fe2(SO4)3 —> 3MgSO4 + 2Fe

Step 2:

Determination of the mass Fe2(SO4)3 that reacted and the mass of Fe produced from the balanced equation. This is illustrated below:

Molar Mass of of Fe2(SO4)3 = (2x56) + 3[32 + (16x4)] = 112 + 3[32 + 64] = 112 + 3[96] = 400g/mol

Mass of Fe2(SO4)3 from the balanced equation = 1 x 400 = 400g

Molar Mass of Fe = 56g/mol

Mass of Fe from the balanced equation = 2 x 56 = 112g

From the balanced equation above,

400g of Fe2(SO4)3 reacted to produce 112g Fe.

Step 3:

Determination of the mass of Fe produced by reacting 3.65g of Fe2(SO4)3.

This is illustrated below:

From the balanced equation above,

400g of Fe2(SO4)3 reacted to produce 112g Fe.

Therefore, 3.65g of Fe2(SO4)3 will react to produce = (3.65 x 112)/400 = 1.02g of Fe.

Therefore, 1.02g of Fe is produced from 3.65g of Fe2(SO4)3.

Therefore, we can write the balanced redox reaction as: Bio3- - 2+ + f -> f2 + 2O- + 2bi  

The redox reaction you provided is incomplete and does not specify the oxidation states of the reactants and products. In order to balance the reaction, we need to provide the oxidation states of all the atoms involved in the reaction.

Assuming that the reaction is:

Bio3- - f -> f2 + bi

To balance the reaction, we need to ensure that the number of atoms of each element on the reactant side of the equation is equal to the number of atoms of each element on the product side of the equation.

In this case, the oxidation state of the Fe in the reactant is +2, while the oxidation state of the Fe in the product is +3. Therefore, we need to add a 2+ ion on the reactant side of the equation to balance the number of Fe atoms.

We can do this by adding a 2+ ion on the reactant side of the equation, which corresponds to the oxidation state of the Fe in the reactant.

Therefore, the balanced redox reaction is:

Bio3- - 2+ + f -> f2 + 2bi

The blanks in the reactant side of the equation can be filled in with the oxidation states of the other elements in the reaction. For example, the oxidation state of the Fe in the reactant is +2, while the oxidation state of the O in the reactant is 0.

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A molecule (such as a repressor molecule) that can change shape, and therefore function, in its interactions with other marsupial Reconstruction that had federalism debate that had been an issue since the 1790s.

Reconstruction failed by most other measures: Radical Republican legislation ultimately failed to protect former slaves from white persecution and failed to engender fundamental changes to the social fabric of the South. When President molecule B. federalism debate that had been an issue since the 1790s almost mediately . Hayes removed federal troops from the South in 1877, former Confederate molecule and slave returned to With the support of a conservative Supreme Court, these newly empowered white southern politicians passed black codes, voter qualifications, and other anti-progressive legislation to reverse the rights that blacks had gained during Radical Reconstruction. The U.S. Supreme Court bolstered this federalism anti-progressive movement federalism  with decisions in the Slaughterhouse Cases, the Civil Rights Cases, and United States v.

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Answer:

becose of the dark in the atmosphere it covers the sun

Explanation:

il explain in comment if you brainly me

Answer:

a. True

b. True

c. True

d. False

Explanation:

At equilibrium condition, the amount of products must be equal to the amount of reactants means 50% of reactant is converted into product and 50% of product is converted into reactant. During equilibrium, the concentration of the products as well as reactant does not change. Yes, a collision between reactants is needed to initiate and complete the reaction. If the concentrations of the reactants are too large, the rate of the forward reaction will be faster than the reverse reaction, and some of the reactants will be converted into products until equilibrium is achieved.

prophase, prometaphase, metaphase, anaphase,  telophase and cytokinesis

Explanation:

Answer

crush the cubes of broth, add warm water and stir the container.

Explanation

The FASTEST way to make the chicken broth with the cubes you have will be to increase the surface area of the cubes broth by crushing and raise the temperature of the cubes broth by adding warm water and by stirring the container.

Hence, the correct answer to your question is:

crush the cubes of broth, add warm water and stir the container.

Density of the unknown metal is 4.82 g/mL

Given,

mass of block is 83 g

When the block was placed in a graduated cylinder containing water, the volume of the block was 17.2 mL.

we have to find density with the help of these two terms,

As we know,

Density = Mass/volume

therefore,

Density = 83 / 17.2

= 4.82 g/mL

thus, density of unknown metal block is 4.82g/mL

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The hydrogen can be produced from water using renewable energy sources, which makes it more sustainable.

If we based our energy on hydrogen, two major economic or global problems that could be alleviated are:

1. Climate change: This is a global issue that requires an immediate response. The world needs to move away from carbon-emitting fossil fuels. Burning hydrogen fuel emits only water and does not release greenhouse gases. If the world shifts to hydrogen fuel, it will reduce carbon emissions and help to slow down climate change.

2. Dependence on Oil: Most countries are dependent on oil. The price of oil is volatile, and the demand and supply fluctuate due to political, economic, and weather events. This dependence on oil is a major economic challenge for many countries. If we based our energy on hydrogen, we could reduce our dependence on oil and decrease oil imports, which could significantly improve the economy of countries that do not produce oil.

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Answer:

Krypton (Kr)

Explanation:

We'll begin by writing the electronic configuration of bromine. This is illustrated below:

Br (35) => [Ar]4s² 3d¹⁰ 4p⁵

Since the bromine atom gains an extra electron, the number of electrons in the bromide ion, Br¯ becomes 36. Hence the electronic configuration of the bromide ion, Br¯ can be written as follow:

Br¯ (36) => [Ar]4s² 3d¹⁰ 4p⁶

Now, comparing the number of electrons in the bromide ion, Br¯ with those in the periodic table, it is evident that the bromide ion, Br¯ has the same number of electrons with krypton, Kr. Hence, the bromide ion, Br¯ and the krypton, Kr has the same electronic configuration i.e

Br¯ (36) => [Ar]4s² 3d¹⁰ 4p⁶

Kr (36) => [Ar] 4s² 3d¹⁰ 4p⁶

Answer:

tom holland

Explanation:

Answer:

me

Explanation:

it is very clearly me obviously

Answer:

6

Explanation:

Answer:

6

Explanation:

C6

Carbon 6

Salt suitable for sprinkling on food at meals.

Answer:

I think above answer is fully correct. Mark it brainliest

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1 g

Mass of CO₂ = 3.14 g

Mass of H₂O = 1.29 g

Empirical formula =?

Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:

For Carbon, C:

Mass of CO₂ = 3.14 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Molar mass of C = 12 g/mol

Mass of C =?

Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂

Mass of C = 12/44 × 3.14

Mass of C = 0.86 g

For hydrogen, H:

Mass of C = 0.86 g

Mass of compound = 1 g

Mass of H =?

Mass of H = (Mass of compound) – (mass of C)

Mass of H = 1 – 0.86

Mass of H = 0.14 g

Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:

Mass of C = 0.86 g

Mass of H = 0.14 g

Divide by their molar mass

C = 0.86 / 12 = 0.07

H = 0.14 / 1 = 0.14

Divide by the smallest

C = 0.07 / 0.07 = 1

H = 0.14 / 0.07 = 2

Thus, the empirical formula of cyclopropane is CH₂

The mass of the cell wall, assuming the cell is spherical and the wall is a thin spherical shell, is approximately 0.91 milligrams.

To calculate the mass of the cell wall, we first need to determine the volume of the wall.

The given diameter of the cell is 0.00 μm, which means the radius (r) of the cell is half of that, so r = 0.00/2 = 0.00 μm = 0.00 nm.Now, we need to find the volume of the cell wall, which can be approximated as a thin spherical shell. The volume of a thin spherical shell can be calculated using the formula:

V = 4/3 * π * (r_outer^3 - r_inner^3)

Since the cell is spherical, the inner radius of the shell is the same as the radius of the cell (r), and the outer radius of the shell is the sum of the radius of the cell (r) and the thickness of the wall (60.0 nm). Thus, the outer radius (r_outer) of the shell is:

r_outer = r + thickness = 0.00 + 60.0 = 60.0 nm

Substituting the values into the formula, we have:

V = 4/3 * π * (60.0^3 - 0.00^3)

= 4/3 * π * (216,000 nm^3)

= 288,000 π nm^3

Next, we need to calculate the mass of the cell wall using the density of pure water. The density (ρ) is given as 1000 kg/m^3, which is equivalent to 1000 kg/1,000,000,000 nm^3 since 1 m = 1,000,000,000 nm. Thus, the mass (m) of the cell wall is:

m = ρ * V

= 1000 kg/1,000,000,000 nm^3 * 288,000 π nm^3

= 0.000288 π kg

Now, we can calculate the mass of the cell wall by substituting the value of π (pi) as 3.14159:

m = 0.000288 * 3.14159 kg

= 0.000905 kg

≈ 0.91 mg

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The attributes of the genetic code include all of the following except B. Each codon specifies more than one amino acid.

A. Each codon consists of 3 nucleotides: This is a correct attribute of the genetic code. Codons are made up of three consecutive nucleotides, which form the basic unit of the genetic code.

B. Each codon specifies more than one amino acid: This is incorrect. Each codon typically specifies only one amino acid. However, there are some exceptions called "ambiguous codons" where a single codon can code for more than one amino acid, but they are relatively rare.

C. Codons are non-overlapping: This is a correct attribute of the genetic code. Codons are read sequentially and are not overlapping. Each codon starts at a specific position in the DNA or mRNA sequence.

D. Most amino acids are specified by more than one codon: This is a correct attribute of the genetic code. With a few exceptions, most amino acids are encoded by multiple codons. This redundancy provides some level of error tolerance and allows for variations in the DNA sequence without affecting the encoded protein.

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The number of grams of tungsten (W), atomic number 74, found in 3.10 moles is approximately 662.4 grams.

To calculate the number of grams of tungsten in 3.10 moles, we need to use the molar mass of tungsten. The molar mass of tungsten is approximately 183.84 g/mol.

First, we can calculate the number of grams in one mole of tungsten:

1 mole of W = 183.84 grams

Then, we can use this conversion factor to determine the grams in 3.10 moles of tungsten:

3.10 moles of W × 183.84 grams/1 mole = 570.504 grams

Rounding to the appropriate number of significant figures, the result is approximately 662.4 grams.

Therefore, there are approximately 662.4 grams of tungsten in 3.10 moles.

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It is impossible to narrow down anything about the unknown.

Flame tests are common analytical techniques used to determine the composition of an unknown compound based on the color that it imparts to flame. Each metal ion imparts a specific color to flame which helps us to identify it.

In this case, two colors were visible in the flame and it will be difficult to determine which of the colors corresponds to the actual metal ion present.

Therefore, it is impossible to narrow down anything about the unknown.

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Answer:

398 mL

Explanation:

Using the equation for molarity,

C₁V₁ = C₂V₂ where C₁ = concentration before adding water = 8.61 mol/L and V₁ = volume before adding water, C₂ = concentration after adding water = 1.75 mol/L and V₂ = volume after adding water = 500 mL = 0.5 L

V₂ = V₁ + V' where V' = volume of water added.

So, From C₁V₁ = C₂V₂

V₁ =  C₂V₂/C₁

= 1.75 mol/L × 0.5 L ÷ 8.61 mol/L

= 0.875 mol/8.61 mol/L

= 0.102 L

So, V₂ = V₁ + V'

0.5 L = 0.102 L + V'

V' = 0.5 L - 0.102 L

= 0.398 L

= 398 mL

So, we need to add 398 mL of water to the nitric solution.

To calculate the enthalpy of fusion and percent error for each of your three trials. Here are the steps to calculate each value:

1. Heat needed to melt the ice (q): You've already mentioned that you have this value as 18* for all three trials. I'm assuming this is in joules (J).

2. Enthalpy of fusion (ΔHfus): To calculate this, you need the mass of the ice melted (m). You mentioned that you're not sure how to find the mass of the ice melted. Usually, this value is provided in the experiment or you can measure it using a scale. Once you have the mass, use the following formula:

ΔHfus = q / m

3. Percent error: To calculate the percent error, you need the accepted enthalpy of fusion of water, which is 334 J/g. Use the following formula:

Percent error = (|calculated ΔHfus - accepted ΔHfus| / accepted ΔHfus) × 100

Now, perform these calculations for each of your three trials. Note that you'll need to obtain or measure the mass of the ice melted (m) for each trial to calculate the enthalpy of fusion and percent error.

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Tiana is developing a chemical additive to be used in swimming pools.

Chemical additives are substances added to products to alter or improve their performance. They are used in a wide range of consumer products and industrial processes for a variety of purposes including improving shelf-life, enhancing flavor, or increasing the efficiency of a process. Common examples of chemical additives are preservatives, colorants, emulsifiers, antioxidants, stabilizers, and thickeners.

This additive is designed to help keep the pool clean and sanitary, by removing bacteria and other contaminants from the water. The additive is also designed to help balance the pH of the pool water, to ensure that it is safe for swimming and does not irritate swimmers' skin or eyes. The chemical additive must also be safe to use, and must not cause any adverse reactions in swimmers. Tiana's work involves testing different chemical compounds to find the most effective and safe additive for pool water.

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In the base-three numeration system, 100 represents one group of three, zero twos, and zero ones. In both cases, the numeral represents the same value or amount of objects, which is fourteen.

4. A set of measuring units for the base-three numeration system using the same BMU that was used in Fart 1 for the base-five numeration system can be constructed.

The chart below shows the place value chart that records the set of units.

\(\begin{array}{|r|r|} \hline \text{Place Value}&\text{Base-Three Value}\\ \hline 243&2\\ \hline 81&1\\ \hline 27&0\\ \hline 9&2\\ \hline 3&1\\ \hline 1&0\\ \hline \end{array}\)

5. The base-three numeral 121 can be built using the measuring units from problem #4. The number represents the quantity three hundred forty-two.

6. The quantity represented by the base-three numeral 100 is two hundred forty-one.

7. The value of 14 five is the same as the value of 100 three because in both cases the value of the numeral is fourteen. In the base-five numeration system, 14 represents one group of five and four ones.

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According to the IUPAC convention, alkyl group names should be located at the end  of the name of the main chain.

IUPAC is a system of chemistry in which the naming of the organic compound has to be done based on their structure by following some rules given by the IUPAC system. Alkanes, alkenes and alkynes are the three major functional groups of organic chemistry.

The full form of IUPAC is the international union of pure and applied chemistry.

Alkyl groups are same as alkenes just the end name of both are different but both of then specifies the single bond in structure and name has to be written in last.

Therefore, according to the IUPAC convention, alkyl group names should be located at the end  of the name of the main chain.

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