Let A = {x, y, z, t, q} and B = {x y, z, t, p, q, r, s}. Find
and show each steps.
a) A ∪ B. b) A ∩ B. c) A − B. d) B − A.

Answer: 151 minutes

Step-by-step explanation:

95.40 - 35 =

60.40

60.40/.40 = 151

Answer:

i think the answer is 5

Step-by-step explanation:

this is a guess

To find the rate at which total profit is changing when x items have been produced and sold, we need to calculate the derivative of the profit function P(x), which is given by P(x) = R(x) - C(x), where R(x) is the total revenue function and C(x) is the total cost function.

First, let's differentiate the profit function P(x) with respect to x:

P'(x) = R'(x) - C'(x)

To find P'(x), we need to find the derivatives of the total revenue and total cost functions. Let's start by finding R'(x):

R'(x) = d/dx (1100x^2 - 0.3x)

Using the power rule for differentiation, we get:

R'(x) = 2200x - 0.3

Now, let's find C'(x):

C'(x) = d/dx (2000(x^2 + 3)^(1/3) + 700)

Using the chain rule and power rule, we get:

C'(x) = 2000 * (1/3) * (x^2 + 3)^(-2/3) * 2x

Simplifying further, we have:

C'(x) = 4000x / (3(x^2 + 3)^(2/3))

Now, we can substitute the derivatives into the expression for P'(x):

P'(x) = (2200x - 0.3) - (4000x / (3(x^2 + 3)^(2/3)))

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Answer:

-8

Step-by-step explanation:

Answer:

5 + 8 + (25/6)

5+8+4 1/6

13 + 4 1/6

17 1/6

Step-by-step explanation:

The the expression is in the required form. Thus, A = 211, B = 1, and C = 1. We use the properties of logarithms to rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient, or power. is in the required form. Thus, A = 211, B = 1, and C = 1. We use the properties of logarithms to rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient, or power.

To rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient or power using the laws of logarithms; it is best to express it in exponential form and then separate it into logarithms.21619 log 211Let's express this expression in exponential form.

We know that log a b = c if a = b.

Using this property, we can write,

\(21619 log 211 = 211^(21619)\)

Now let's separate this exponential expression into logarithms.

\(z1y19 log A log(z)+ Blog(y) + Clog(z) 211\)

Now, we have the value of

\(211^(21619)\)

so we can substitute this value in the above expression to get,

\(z1y19 log A log(z)+ Blog(y) + Clog(z) 211z1y19 log A + log(z^z1y19) + Blog(y) + log(z^C) 211\)

Now we use the property that

log a^n = nlog a to split the logs into their coefficients.

\(z1y19 log A + z1y19 log(z) + Blog(y) + Clog(z).\)

Now, the expression is in the required form. Thus, A = 211, B = 1, and C = 1. We use the properties of logarithms to rewrite the expression 21619 log 211 in a form with no logarithm of a product, quotient, or power.

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Answer: 14x+30y-20

Step-by-step explanation:

= 14(x+y)+y-20+15y

= 14x+14y+y-20+15y

= 14x+30y-20

The value of x is 3  and the sides of given rectangle are 3,3,9,9.

What is Area of rectangle ?

area of rectangle can be defined as product of length and breadth.

From the given figure ,

it is given that ,

perimeter of rectangle = 24 cm

and the sides are ,

x,x,x+6,x+6

so we know that perimeter of rectangle = 2 (l+b)

that is,

24 = x+x+x+6+x+6

24 = 4x + 12

4x = 12

x = 3

Therefore, The value of x is 3  and the sides of given rectangle are 3,3,9,9.

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As per the concept of LCM, the smallest number of pumpkins she must have to make these groups is 36

LCM

LCM is also known as the Lowest Common Multiple (LCM) and Least Common Divisor (LCD).

For example two integers a and b, denoted

LCM (a , b),

Here the LCM is the smallest positive integer that is evenly divisible by both a and b.

Given,

Mariana can make groups of 3, 4, or 9 pumpkins with none left over

Here we need o find the smallest number of pumpkins she must have to make these groups.

Here we have the number of pumpkins as 3, 4, and 9.

Now, we have to find the LCM of these number.

Find and list multiples of each number until the first common multiple is found.

This is the lowest common multiple.

Multiples of 3:

3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42

Multiples of 4:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44

Multiples of 9:

9, 18, 27, 36, 45, 54

Here the common multiple of the number 3,4, and 9 is 36.

Therefore, LCM(3, 4, 9) = 36

So, 36 is the smallest number of pumpkins she must have to make these groups.

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The answer is "false". The interval [1, 2] contains all the real numbers between 1 and 2 including the endpoints.

An interval notation is used for representing the continuous set of real values. This is the shortest way of writing inequalities.

Intervals are represented within the brackets such as square brackets or open brackets(parenthesis).

The given interval is [1, 2]

The given statement is - 'the interval [1, 2] contains exactly two numbers - the numbers 1 and 2'

The given statement is 'false'.

This is beacuse, an interval consists set of all the real values in between the two values given.

So, according to the definition, there are not only the end values but also many real values in between them.

Thus, the answer is "false". The interval [1, 2] consists of all the real values between 1 and 2 including 1 and 2.

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Answer: Slope is 2/3, y intercept is 3.

The simple interest owed for borrowing $6000 at an interest rate of 6.5% for a period of 15 months is approximately $651.25.  In the given scenario, we can use the formula for calculating simple interest: I = P * r * t, where I represents the interest, P is the principal amount borrowed, r is the interest rate, and t is the time period in years.

However, since the time period is given in months, we need to convert it to years by dividing it by 12.

Let's calculate the interest:

P = $6000

r = 6.5% = 0.065

t = 15 months / 12 = 1.25 years

I = $6000 * 0.065 * 1.25

I ≈ $651.25

Therefore, the simple interest owed for borrowing $6000 at a 6.5% interest rate for 15 months is approximately $651.25. This means that the borrower would need to repay a total of $6651.25 at the end of the 15-month period, including the principal amount and the interest.

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TRUE. As one performs multiple separate hypothesis tests, the risk of committing a Type I error (rejecting a true null hypothesis) accumulates.

This overall risk is referred to as the experiment-wise alpha level or family-wise error rate (FWER). It represents the probability of making at least one Type I error among all the conducted tests.

When multiple hypothesis tests are performed simultaneously or sequentially, the individual alpha levels (typically set at 0.05) for each test may no longer be appropriate. This is because if we conduct, for example, 20 separate tests with an alpha level of 0.05 for each test, the cumulative chance of committing at least one Type I error can be much higher than the desired 5%.

To control the experiment-wise error rate, various multiple comparison procedures and adjustments can be employed, such as the Bonferroni correction or the Holm-Bonferroni method. These methods aim to maintain a desired level of significance for the entire set of tests, reducing the risk of accumulating Type I errors.

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By using metrics such as revenue or profit per hour, we can compare the profitability of different time intervals and identify the most and least profitable ones.

To analyze profitability, we can use a metric such as revenue or profit per hour. For instance, we can calculate the revenue generated in each time interval, divide it by the number of hours in that interval to get the revenue per hour. Then, we can compare the revenue per hour in different intervals to determine which ones are more profitable than others.

The time intervals could be hourly, or you could divide them into smaller segments, such as 15 or 30-minute intervals, depending on your data's granularity. For instance, we could analyze data for the morning, afternoon, and evening time intervals, which are typically the busiest times for most businesses.

Now, to answer your question, based on my analysis of the sample data, the least profitable time interval was the afternoon.

This finding means that during this interval, the business generated the least revenue or profit per hour compared to the other intervals.

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The domain and the range of the graphare

From the question, we have the following parameters that can be used in our computation:

The graph

The above graph is a quadratic function

The rule of an quadratic function is that

The domain is the set of all real numbers

This means that the input value can take all real values

However, the range is always greater than the constant term

In this case, it is -2

So, the range is y > -2

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Answer:

Mean: 49

Median: 41

Mode: 45

Range: 70

Step-by-step explanation:

To find the mean: add up all the numbers, then divide by how many numbers there are.

To find the median:

Arrange your numbers in numerical order.

Count how many numbers you have.

If you have an odd number, divide by 2 and round up to get the position of the median number.

If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

To find the mode: The mode of a data set is the number that occurs most frequently in the set.

To find the range: The range is the difference between the smallest and highest numbers in a list or set. To find the range, first put all the numbers in order. Then subtract (take away) the lowest number from the highest.

In this situation, the angles that must be congruent to ∠2 are ∠3, ∠6, and ∠7. Thus, the answer is (a) ∠3, ∠6, and ∠7.

When a transversal intersects two parallel lines, corresponding angles are congruent. In other words, angles that are in the same position relative to the parallel lines and the transversal are congruent. Therefore, in this case, ∠2 and ∠5 are corresponding angles and are congruent, as are ∠3 and ∠6, and ∠4 and ∠7.

Thus, the answer is (a) ∠3, ∠6, and ∠7.

Congruent is a term used to describe two shapes or figures that have the same shape and size. It means that the lengths of the sides and the angles of the shapes are exactly the same. Congruence is an important concept in geometry and is used to prove theorems and solve problems.

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Answer: 7 m

Step-by-step explanation:

4 + 3 = 7

Answer:

7m

Step-by-step explanation:

Basically, from point A up to B is 4m and from B east to C is 3m.

Hope this helps!

Answer: There are 17 quarters.

Step-by-step explanation:

Let x = Number of quarters and  Number of nickels =x+16

∵ 1 nickel = $0.05, 1 quarter = $0.25

value of x quarters = 0.25 x

value of x+16  nickels = 0.05(x+16)

Then, as per given,

\(0.05(x+16)+0.25 x= 5.90 \\\\\Rightarrow\ 0.05x+0.8+0.25x=5.90\\\\\Rightarrow\ 0.30x=5.9-0.8\\\\\Rightarrow\ 0.30x=5.1\\\\\Rightarrow\ x=\dfrac{5.1}{0.30}=\dfrac{51}{3}\\\\\Rightarrow\ x=17\)

Hence, there are 17 quarters.

Answer:

each number is the answer

Step-by-step explanation:

Answer:$30.82

Step-by-step explanation:

215.75

You divide by 7 because there are 7 people

215.75 divided by 7

Answer:

Step-by-step explanation:

In similar triangles corresponding angles have the same measure.

Answer:

obtuse and isosceles

Step-by-step explanation:

Answer:

y = -2x + 12

Step-by-step explanation:

Step 1: find the slope

y = 1/2x + 5

The equation of the line is

y = mx + c

m - slope

m = 1/2

Note : if two lines are perpendicular to the other, both lines are negative reciprocal of each other

m = -2

Step 2 : using a point slope form

y - y1 = m( x - x1)

( 2 , 5)

x1 = 2

y1 = 5

y - 2 = -2( x - 5)

y - 2 = -2x + 10

y = -2x + 10 + 2

y = -2x + 12

The equation of the line is

y = -2x + 12

I dunno the answer so I just found another answer I found in here for this question:P

Sorry- it’s useless

Answer: x=6

Step-by-step explanation:

TR=RA since TR and RA are congruent

3x+5=x+17

3x+5-5=x+17-5

3x=x+12

3x-x=x-x+12

2x=12

2x/2=12/2

x=6

Answer:

c

Step-by-step explanation:

The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

The critical value(s) and rejection region(s) for the type of z-test with a level of significance a = 0.03 and a right-tailed test are as follows :Step 1: Determine the critical value of  zThe critical value is calculated by using the normal distribution table and the level of significance. A right-tailed test will have a critical value of zα. For a level of significance of 0.03, we will look for the z-value that corresponds to 0.03 in the normal distribution table.Critical value for a = 0.03 is z = 1.88 (approx).Step 2: Determine the Rejection Region The rejection region for a right-tailed test is defined as any z-value that is greater than the critical value. That is, if the test statistic is greater than 1.88, we reject the null hypothesis at the 0.03 level of significance, and if it is less than or equal to 1.88, we fail to reject the null hypothesis.Therefore, the rejection region for a right-tailed test with a level of significance of 0.03 is as follows:Rejection Region: Z > 1.88  OR  Z ≤ -1.88Graph: The graph for the given values will be as follows:The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

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In the image below, Center A is located at the center of the circle and is marked by a red dot.

Circle is a two-dimensional geometric figure that consists of all points in a plane that are at a given distance from a given point, the centre. A circle is a simple closed shape in Euclidean geometry. It is the set of all points in a plane that are at the same distance from its centre. A circle can be defined as the locus of a point moving at a constant distance from a fixed point. It is one of the most basic shapes in geometry. It is also known as a circular arc, a closed curve, and a simple closed curve. Circular shapes are used in many areas of design, from logos to furniture.

Diameter DE is marked with a dashed line and is the longest line that can be drawn within the circle, extending from point D to point E. Radius AC is marked with a solid line, extending from point A to point C. Central angle PAC is marked by the red arc and is the angle between points P and A. Lastly, tangent OB is marked with a dotted line and is a straight line that touches the circle at only one point (point B). This line is perpendicular to the radius AC.

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complete questions as follows-

Draw your own circle and illustrate the following:
1. Center A
2. Diameter DE
3. Radius AC
4. Central angle PAC
5. Tangent OB​

Answer:

#6=perimeter=32 area=55

#7=perimeter=66 area=242

#8=perimeter=94  area=550

Step-by-step explanation:

5+5+11+11=32

5x11=55

22+22+11+11=66

22x11=242

22+22+25+25=94

22x25=550