Light beam will enter water at incident angle of 80°, before it enter a diamond crystal. What will be the speed of light, in x10⁶ m/s, inside the diamond crystal?
(nwater = 1.333, ndiamond = 2.419) (Express your answer in 4 decimal place/s, NO UNIT REQUIRED)s

The actual mechanical advantage (ama) of the given simple machine is 4.8

The mechanical advantage (MA) of a simple machine is defined as the ratio of the output force to the input force.

So, to find the MA of a simple machine that requires a 50 N input to produce a 240 N output, we can use the formula:

MA = output force / input force

Given that the input force is 50 N and the output force is 240 N, we can plug these values into the formula:

MA = 240 N / 50 N

MA = 4.8

Therefore, the mechanical advantage of this simple machine is 4.8.

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Answer:

a = 0.8 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration, in this way we come to the following equation:

∑F = m*a

where:

F = forces applied [N]

m = mass = 1000 [kg]

a = acceleration [m/s²]

Now using Newton's second law.

\(1200 - 400 = 1000*a\\800 = 1000 *a\\a=0.8[m/s^{2} ]\)

Answer

3m/s²

Explanation

u=o

t=25s

v=75m/s

from Newton's first law of motion,

v=u+at

75=0+a(25)

75=25a

a= 75/25

a=3m/s²

The acceleration of the airplane is 3m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Initial velocity of the airplane: u=o.

Time taken: t=25s.

Final velocity of the airplane: v=75m/s.

We have to find acceleration of the plane: a = ?

We know that for accelerating motion of the air plane; final velocity can be expressed as:

    v=u+at

⇒ 75=0+a(25)

⇒ 75=25a

⇒ a= 75/25

⇒ a= 3m/s².

hence, acceleration of the airplane is 3m/s².

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Answer:

Explanation:The Hertzsprung-Russell Diagram is a graphical tool that astronomers use to classify stars according to their luminosity, spectral type, color, temperature and evolutionary stage. Stars in the stable phase of hydrogen burning lie along the Main Sequence according to their mass.

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The copper wire with a diameter of 1.7 mm carries a current of 20 A, and the current density in the wire is approximately 8.81 x 10^6 A/m^2.

The diameter of the copper wire is given as 1.7 mm. To find the cross-sectional area of the wire, we can use the formula for the area of a circle, which is A = πr^2, where r is the radius of the wire. The radius can be calculated by dividing the diameter by 2, so in this case, the radius is 0.85 mm (or 0.00085 m).

Next, we need to calculate the cross-sectional area of the wire using the formula mentioned earlier. Substituting the value of the radius into the formula, we have A = π(0.00085)^2 = 2.27 x 10^-6 m^2.

Now, we know the current passing through the wire is 20 A.

The current density, denoted by J, is defined as the current passing through a conductor per unit cross-sectional area.

So, we can calculate the current density by dividing the current by the cross-sectional area: J = 20 A / 2.27 x 10^-6 m^2 = 8.81 x 10^6 A/m^2.

Therefore, the copper wire with a diameter of 1.7 mm carries a current of 20 A, and the current density in the wire is approximately 8.81 x 10^6 A/m^2.

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The power output of the Marine can be calculated by dividing the work done in climbing the rope by the time taken. The power output of the Marine is approximately 805.53 watts.

Power is defined as the rate at which work is done or energy is transferred. In this case, the work done by the Marine in climbing the rope can be calculated by multiplying the force applied (weight of the Marine) by the distance covered (height of the rope). The equation for work is given by W = Fd, where W is the work, F is the force, and d is the distance.

The weight of the Marine is given as 665 N, and the height of the rope is 11.5 m. Therefore, the work done is W = 665 N × 11.5 m = 7647.5 J (joules).

To calculate the power output, we divide the work done by the time taken. The equation for power is P = W/t, where P is the power, W is the work, and t is the time.

The time taken to climb the rope is given as 9.50 s. Therefore, the power output of the Marine is P = 7647.5 J / 9.50 s ≈ 805.53 watts (W).

Hence, the power output of the Marine is approximately 805.53 watts.

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During an extreme emergency, our body must be in fight or flight mode. There are three stages of stress response during an emergency. They are alarm, resistance, and fatigue.

Alarm is the first stage among the 3 stages in the stress response system. In alarm stage, the body and mind go on high alert. It is sometimes called the "fight or flight response". It prepares the body to either go for defending itself or to flee from a threat.

When you perceive a situation or event to be a threat, your body begins a stress response. The nervous system and the endocrine system are active during the body's response to stressors. This response is involuntary or automatic and happen in three stages.

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Answer:

30 mph

Explanation:

1800 divided by 60

When an object travels at a constant speed with zero acceleration it is known as uniform rectilinear motion. Then its velocity is given by:

v = d / t

Where d is distance and t is time. Evaluating:

v = 1800 m / 60 s

sensations of temperature, pain, and crude and light touch are carried by way of the "peripheral nervous system", specifically through different types of nerve fibers.

Temperature sensations are primarily carried by a type of nerve fiber called C fibers or unmyelinated C fibers. These fibers are responsible for transmitting slow pain signals, temperature changes, and other sensations related to temperature.

Pain sensations, also known as nociceptive sensations, are carried by two main types of nerve fibers: A-delta fibers and C fibers. A-delta fibers are myelinated and transmit fast pain signals, which are sharp and localized. C fibers, as mentioned earlier, are unmyelinated and transmit slow pain signals, which are dull and diffuse.

Crude and light touch sensations are carried by A-beta fibers, which are myelinated and responsible for transmitting various touch and pressure sensations. These fibers allow us to perceive sensations such as gentle touch, pressure, and vibration.

All these nerve fibers transmit signals from the peripheral receptors, such as sensory receptors in the skin, to the central nervous system, where the brain processes and interprets these sensations. The specific pathways involved in transmitting these signals can vary, but they generally involve a combination of ascending tracts within the spinal cord and relay centers in the brain.

It's important to note that while these different types of nerve fibers have specific roles in carrying specific sensations, they can also interact and contribute to the overall sensory experience. The sensation of touch, for example, may involve the integration of inputs from multiple types of nerve fibers to provide a comprehensive perception of the stimulus.

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Its closest distance from the Sun is about 4.44×10^12 meters, and its farthest distance is about 7.38×10^12 meters for Pluto's orbital period.

To calculate Pluto's orbital period in seconds, we will use Kepler's Third Law:

T^2 = (4 * π^2 * a^3) / (G * M)

Where:
- T is the orbital period in seconds
- a is the semi-major axis (5.91×10^12 m)
- G is the gravitational constant (6.674×10^-11 N(m/kg)^2)
- M is the mass of the Sun (1.989×10^30 kg)

1. Plug in the values: T^2 = (4 * π^2 * (5.91×10^12)^3) / (6.674×10^-11 * 1.989×10^30)
2. Solve for T: T ≈ 7.82×10^15 seconds

To convert this to Earth years, we can use the conversion factor of 1 year = 3.1536×10^7 seconds:

Pluto's orbital period in Earth years = (7.82×10^15 seconds) / (3.1536×10^7 seconds/year) ≈ 248 years

To find Pluto's closest and farthest distances from the Sun, we will use the formula:

d = a * (1 ± e)

Where:
- d is the distance from the Sun
- a is the semi-major axis (5.91×10^12 m)
- e is the eccentricity (0.249)

Closest distance (periapsis): d = 5.91×10^12 * (1 - 0.249) ≈ 4.44×10^12 meters
Farthest distance (apoapsis): d = 5.91×10^12 * (1 + 0.249) ≈ 7.38×10^12 meters

In summary, Pluto's orbital period is approximately 7.82×10^15 seconds or 248 Earth years. Its closest distance from the Sun is about 4.44×10^12 meters, and its farthest distance is about 7.38×10^12 meters.

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Given :

Force applied on book, F = 18 N.

Kinetic friction, \(K_f = 12\ N\).

Mass of book, M = 3 kg.

To Find :

The acceleration of book.

Solution :

Equation of force applied on book is :

\(F_{net} = F - K_f\\\\ma= 18 - 12 \\\\a=\dfrac{6}{3}\ m/s^2\\\\a = 2\ m/s^2\)

Therefore, acceleration of book is 2 m/s².

Hence, this is the required solution.

The speed at the highest point is approximately 7.13 m/s, and the maximum height it reaches is approximately 1.42 m.

To find the speed at the highest point and the maximum height of a 0.48 kg ball thrown with a speed of 8.8 m/s at an upward angle of 36 degrees,

1. Calculate the vertical component of the initial velocity (Voy):
Voy = V * sin(angle)
Voy = 8.8 * sin(36)
Voy ≈ 5.25 m/s

2. Calculate the time it takes to reach the highest point (t) using the vertical component of the velocity and the acceleration due to gravity (g = 9.81 m/s²):
Voy = gt
t = Voy / g
t = 5.25 / 9.81
t ≈ 0.54 s

3. Calculate the speed at the highest point (Vx):
Vx = V * cos(angle)
Vx = 8.8 * cos(36)
Vx ≈ 7.13 m/s

4. Calculate the maximum height (h) using the vertical component of the initial velocity, the time to reach the highest point, and the acceleration due to gravity:
h = Voy * t - (1/2) * g * t^2
h = 5.25 * 0.54 - (1/2) * 9.81 * 0.54^2
h ≈ 1.42 m

So, the speed at the highest point is approximately 7.13 m/s, and the maximum height it reaches is approximately 1.42 m.

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(a) The potential difference across the resistor is 10.287 V.
(b) The potential difference across each of the two sections of wire is equal to the potential difference across the resistor, 10.287 V.
(c) The rate at which energy is lost to thermal energy in the resistor is determined by the formula:
Power = Voltage x Current
Where P is power (in watts), V is voltage (in volts) and I is current (in amperes). The current is determined by the resistance of the resistor, and the voltage is the potential difference across the resistor, 10.287 V. So, the rate at which energy is lost to thermal energy in the resistor is 10.287 V x I, where I is determined by the resistance of the resistor.
(d) The rate at which energy is lost in each of the two sections of wire is determined by Ohm's Law:
V = I x R
Where V is voltage (in volts), I is current (in amperes) and R is resistance (in ohms). The current is determined by the resistance of the two sections of wire and the voltage is the potential difference across the two sections of wire, 10.287 V. So, the rate at which energy is lost in each of the two sections of wire is 10.287 V x I, where I is determined by the resistance of the two sections of wire.

In summary, the rate at which energy is lost to thermal energy in the resistor is determined by the potential difference across the resistor (10.287 V) and the resistance of the resistor, while the rate at which energy is lost in each of the two sections of wire is determined by the potential difference across the two sections of wire (10.287 V) and the resistance of the two sections of wire.

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The volume of one rubber ball and the cost of producing one ball and the profit will it make on each ball will be 20.58 cm³, $0.09261, and $0.40739 respectively.

It is concerned with the geometry, region, and density of various 2D and 3D shapes.

The given data in the problem is;

r is the Rubber balls = 1.7 cm

V is the volume

C is the cost of production

P is the profit

The volume of the rubber ball is  found as;

\(\rm v= \frac{4}{3} \pi r^3 \\\\ \rm v= \frac{4}{3} \times 3.14 (4.913)^3 \\\\ \rm v= 20.58 cm^3\)

If the price of the rubber required to make a ball is $0.0045/cm3, the ball's production cost will be $0.0045/cm3.

The cost of a ball is the multiplication of the cost of one ball and the selling price of the ball;

C = 0.0045 x 20.58

C = $0.09261

P is the profit gained and profit is the subtraction of the selling price and cost price.

P = S.P.-C.P.

P=0.5 - 0.09261

P = $0.40739

Hence the volume of one rubber ball and the cost of producing one ball and the profit will it make on each ball will be 20.58 cm³, $0.09261, and $0.40739 respectively.

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Answer:  

1: C

2: C

3: A

Explanation: just did it

A high jumper reaching the peak of their jump and A ball being tossed directly upward before reaching its highest point represents kinetic energy transforming into potential energy.

Kinetic energy (K.E.) can be described as the energy contained by a moving object due to its motion. The change in the kinetic energy of a moving body is equal to the work done.

The kinetic energy (K.E.)  of a moving object can be written as:

K.E = ½mv²  where ‘m’ is the mass, ‘v’ is the velocity of the object.

Potential Energy (P.E) can be defined as the energy that is stored by an object due to its position and is equal to P.E = mgh where ‘m’ is the mass, ‘g’ is the gravitational acceleration and ‘h’ is the height (in m).

The kinetic energy of the ball and the jumper is maximum at the ground and their kinetic energy changes into potential energy as they are moving toward the highest point.

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Answer:2 hours

Explanation:

The intensity of radiation emitted from a star decreases with increasing distance from the star. This can be explained by the inverse square law of radiation.

According to the inverse square law, the intensity of radiation is inversely proportional to the square of the distance from the source. Mathematically, this can be expressed as:

I ∝ 1/d^2

Where I is the intensity of radiation and d is the distance from the star.

As the distance from the star increases, the area over which the radiation is spread also increases. Since the same amount of radiation is distributed over a larger area, the intensity of radiation per unit area decreases.

This decrease in intensity with distance is due to the spreading out of radiation in three-dimensional space. The energy emitted by the star is spread over an increasingly larger sphere as the distance from the star increases.

Therefore, as an observer moves farther away from a star, the intensity of radiation they receive decreases, resulting in a dimmer appearance of the star.

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Answer:

B. Electron

Static charge is produced by electron transfer.

Explanation:

Answer A: The neutron does not possess a charge and is said to be neutral.

Answer D: Protons and neutrons never move from object to object.

Only negative charges can move freely from one object to another. The energy that comes from these charges particles is called electrical energy.

....

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The answer is an electron.

Answer:

r = 50.47 x 10³ m = 50.47 km

Explanation:

Using the formula for the acceleration due to gravity:

\(g = \frac{Gm}{r^2}\)

where,

g = acceleration due to gravity on the surface of asteroid = 0.0288 m/s²

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

m= mass of asteroid = 1.1 x 10¹⁸ kg

r = radius of asteroid = ?

Therefore,

\(0.0288\ m/s^2 = \frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^2)(1.1\ x\ 10^{18}\ kg)}{r^2} \\\\r = \sqrt{\frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^2)(1.1\ x\ 10^{18}\ kg)}{0.0288\ m/s^2}}\)

r = 50.47 x 10³ m = 50.47 km

Answer:

5.05x10^4

Explanation:

g=(GM)/r^2, so

.0288=(6.67x10^-11*1.10x10^18)/r^2, r=5.05x10^4.

This is correct on Acellus.

Only the resistor connected in series which is resistor A will have the least current passing through it.

In this problem, we have some resistors that are connected in series and some in parallel.

The formula of resistors connected in series is given as;

R(series = R1 + R2 + R3 + ....+ Rn

The formula for resistors connected in parallel are

R(parallel) = 1/ R1 + 1/R2 + 1 / R3 +...+ 1/Rn

In this case, we have to assume that the voltage passing through the circuit is uniform and let's assume is 2V

V = IR

I = V/R

From the equation above, we can see that only the series resistance will have a small current passing through it.

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At Z ... slowest speed

At Y ... fastest speed

At X ... medium speed

Wherever it is in its orbit, the line from the planet to the Sun smears over the same amount of area every second.

That's Kepler's second law of planetary motion.

The reason this happens is: That's how gravity works. (A better explanation is available, but first you have to be able to twirl calculus and solid geometry in the air on long sticks.)

Answer:

where is the diagram..........

It will need a force acceleration

Hello!

We can use the following equation for calculating power dissipated by a resistor:
\(P = i^2R\)

P = Power (? W)
i = Current through resistor (2.0 A)
R = Resistance of resistor (50Ω)

Plug in the known values and solve.

\(P = (2.0^2)(50) = \boxed{\text{ B. }200 W}\)

The two earth satellites are in parallel orbits of differing radii, so they will not always be 1 km apart. Therefore, the time it takes for them to be 1 km apart again will depend on their rate of revolution, which is determined by the time it takes for them to complete one orbit.

To answer Part A, we must calculate the orbital period of each satellite, which is calculated by dividing the circumference of the orbit by the speed of the satellite. Once we calculate the orbital period for each satellite, we can use this information to determine how long it will take for the two satellites to be 1 km apart again.

For Part B, we must calculate the thermal efficiency of the heat engine. This is done by dividing the amount of heat extracted from the hot reservoir (60 kJ) by the amount of heat exhausted (35 kJ). The thermal efficiency is the ratio of these two numbers, and can be expressed as a percentage.

Finally, we must calculate the work done per cycle, which is the difference between the heat extracted and the heat exhausted (60 kJ-35 kJ = 25 kJ). This amount can also be expressed to two significant figures, with the appropriate units.

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According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.

Things that are negatively charged and things that are positively charged pull on (attract) each other. This makes electrons and protons stick together to form atoms. Things that have the same charge push each other away (they repel each other). This is called the Law of Charges.

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