Lightning flashes and you hear a thunderclap 4 seconds later. The
velocity of sound is 340 m/s. How far away did the lightning strike?

Answers

Answer 1
1380 m

the distance traveled by the thunder is given as follows.s=vt; where, s is the distance traveled, v is the velocity of sound and t is the time taken. That is, 340 * 4 s = 1360 m.
distance the lightning occured is 1360 m.

Related Questions

The distance between a charge and the source of an electric field changes from 3 mm to 6 mm.

As a result of the change, the electric potential energy of the charge is ______.

A. divided by 6
B. divided by 2
C. multiplied by 2
D. multiplied by 6

Answers

Answer:

c

Explanation:

The electric potential energy of the charge is divided by 2.

To find the electric potential energy, the values given from the source of an electric field changes from 3 mm to 6 mm.

What is electric potential energy?

            The electric potential energy is the energy that is needed to move a charge against the electric field.

The energy can be calculated as Work and these energy can be calculated as a whole not only the charges.

Formula for electric potential energy,

         U = KQ²/r

where,

K is the constant, k =  9 × 10⁹

Substituting the values of q as the charges and then the distance can be,

U = KQ² / 3   and U = KQ² / 6

So that, the values can be divided by 2.

The unit of electric potential energy is Joule.

The distance can be from r to ∞.

Hence, Option B is the correct answer.

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With modulus of elasticity, MoE - 7,920 N/mm2 at 12% mo, what would be the expected MoE at 23% mc? Assume FSP = 30 % Give your answer in N/mm² to the nearest whole number.

Answers

to find the modulus of elasticity MoE at 23% of moisture content based on the already given modulus of elasticity of 12% moisture content we need to consider a shrinkage behavior of material. the expected MoE comes out to be approximately \(6,836 N/mm².\)

given information:

Modulus of elasticity at 12% moisture content =7,920 N/mm²

resultant shrinkage or final shrinkage percentage FSP = 30%

To calculate the expected MoE at 23% moisture content we have the following equation:

MoE-23% =   \(MoE-12%\) \((1 - FSP (23 - 12) / (100 - 12))\)

MoE-23% = \(7,920 N/mm² × (1 - 0.30 × (23 - 12) / (100 - 12))\)

MoE-23% =\(7,920 N/mm² × (1 - 0.30 × 11 / 88)\)

MoE-23% = \(7,920 N/mm² × (1 - 0.1364)\)

MoE-23% = \(7,920 N/mm² × 0.8636\)

MoE-23% =  \(6,836 N/mm²\)

therefore the expected modulus of elasticity at 23% moisture content comes out to be approx \(6,836 N/mm²\).

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which option exhibits the doppler effect in the electromagnetic radiation it emits? responses stationary objects stationary objects microwave towers microwave towers x rays x rays moving objects

Answers

The options that exhibit the doppler effect in their radiation are:

Moving objects. (Assuming that are sources)Microwave tower.

What is the doppler effect?

The Doppler effect is a change in the "perception" of a wave due a movement of the receptor with respect to the source of the wave.

So, any moving source will produce Doppler effect, but still sources (like microwave towers) also will produce the Doppler effect when the receiver of the wave moves (suppose that a car or a plane is moving and it is receiving the waves that come from the tower).

Then the correct options are:

Microwave tower.

Moving objects (motion is fundamental for the doppler effect, here I assume that the moving object is a source)

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What causes earthquakes?


Where do earthquakes begin?

Answers

Answer:

An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.

Explanation:

Tensions around rocks are increasing, and an earthquake begins at tectonic plates.

The majority of earthquakes begin at or close to tectonic plate borders, where stress and strain gradually build up due to interactions between the plates over time. An earthquake occurs when the amount of accumulated tension surpasses the capacity of the rocks, which causes an abrupt release of energy. When there is an earthquake, seismic waves are released, and we feel and sense shaking as a result.

But even beyond plate borders, within tectonic plates, earthquakes can still happen. These earthquakes, also known as intraplate earthquakes, are frequently connected to old faults or weak spots in the crust of the Earth. Despite being less frequent than those near plate borders, intraplate earthquakes can nevertheless be severe and cause damage in populated regions.

Hence, tensions around rocks are increasing, and an earthquake begins at tectonic plates.

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If we have a 2D physics simulation with a gravity acceleration of 10 ms-2 directly downwards and we bounce a ball off level ground so that its initial upwards velocity is 20 ms at ground level. How long will the ball fly upwards for and what is the maximum height above the ground it will reach before it falls back down again?Hint: Remember your s = ut + 1/2at2 distance traveled equation and v = at velocity equation and t = v/a Options to the answer:
a. ) The ball will reach its maximum height in 4 seconds which will be 10 meters above the ground.
b.) The ball will reach its maximum height after 2 seconds which will be 20 meters above the ground.
c.) The ball will reach its maximum height after 4 seconds which will be 80 meters above the ground.

Answers

The maximum height above the ground the ball will reach before falling back down is 20 meters. therefore, the correct option is B.

To find the time it takes for the ball to reach its maximum height, we can use the equation s = ut + 1/2at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time.
Given:
Initial upwards velocity (u) = 20 m/s
Gravity acceleration (a) = -10 m/s^2 (negative because it acts in the opposite direction)
Distance traveled (s) = ?
To find the time it takes for the ball to reach its maximum height, we can use the equation v = u + at, where v is the final velocity.
v = 0 (at the maximum height, the velocity is 0)
0 = u + at
0 = 20 + (-10)t
-20 = -10t
t = 2 seconds
So, the ball will reach its maximum height after 2 seconds.
To find the maximum height (s), we can substitute the time (t) into the distance equation:
s = ut + 1/2at^2
s = 20(2) + 1/2(-10)(2)^2
s = 40 - 20
s = 20 meters
Therefore, the maximum height above the ground the ball will reach before falling back down is 20 meters.
The correct option is b.) The ball will reach its maximum height after 2 seconds, which will be 20 meters above the ground.


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A 2 kg ball is dropped from a height of 60 m. Find its speed just before it hits the ground. Assume no friction. Answer​

Answers

Answer:

-34.3m/s

Explanation:

first lets find the time befor it hit the ground by using free fall equation and we know we use that in one condition which is a constant acceleration in this case its a gravitational acceleration which is -9.8

\(h = \frac{1}{2} g {t}^{2} \)

\(t = \sqrt{ \frac{2 \times 60}{9.8 } } = 3.5s\)

now we know that the initial velocity its zero :

so applu the another kinematic equation which is

\(v = u - gt\)

v is final velocity and u is the initial velocity and its equal zero.

v = - 9.8 × 3.5 = - 34.3

\(\huge\sf\red{A}\pink{N}\orange{S}\green{W}\blue{E}\gray{R}\)

Given,

mass of the ball, m=2 kg ;

height of the ball, h=60 m

The initial potential energy of the ball,

\({\boxed{\underline{\sf{E_{p}=m g h=(2)(10)(60)=1200 \mathrm{~J}}}}\)

When the ball reaches the ground, its potential energy becomes zero as it is entirely converted into its kinetic energy ( \({\sf{E_{K}\) ), i.e.,

\({\Rightarrow{\sf{E}_{\sf{k}}=1200 \mathrm{~J}}}\)

If v is the velocity attained by the ball just before reaching the ground,

\({\Rightarrow{\sf{E}_{\sf{k}}=\frac{1}{2}{mv}^{2}}}}\)

\({\sf\Rightarrow{v=\sqrt{\frac{2 \sf{E}_{\sf{k}}}{\sf{m}}}=\sqrt{\frac{2 \times 1200}{2}}}\)

\({\Large{\mid{\underline{\overline{\Rightarrow{\sf{34.64\:m/s}}}}\:{\mid}\)

matlab questions help
QUESTION 5 Which of the following methods is used to repeat the same sound clip, one after another? O Add the sound sample arrays O Multiply the sound sample arrays by a scalar value less than 1 O Con

Answers

To repeat the same sound clip one after another, the method used is to concatenate the sound sample arrays. By concatenating the sound sample arrays, you create a new array that contains multiple copies of the original sound clip, effectively repeating it one after another. Therefore the correct option is b. Multiply the sound sample arrays by a scalar value less than 1.

When you want to repeat the same sound clip, one after another, you can achieve this by concatenating the sound sample arrays. Here's a step-by-step explanation:

1. Load the sound clip into MATLAB and convert it into a sound sample array.

2. Determine the number of times you want to repeat the sound clip.

3. Use the concatenation operator `[ ]` to join the sound sample arrays together.

4. Repeat the sound sample array as many times as desired by appending it to itself using the concatenation operator. For example, if you want to repeat the sound clip three times, you would write `[soundClip, soundClip, soundClip]`.

5. Store the concatenated sound sample array in a new variable.

6. If needed, you can then play the repeated sound clip using the `sound()` function in MATLAB.

By concatenating the sound sample arrays, you create a new array that contains multiple copies of the original sound clip, effectively repeating it one after another.

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why does a bowling ball and a father fall at the same speed while in a vacuum?
PLZ NEED HELP

Answers

Answer:

there is no drag in a vacuum (why is father in a vaccum)

Explanation:

there is nothing to hit and slow the object other than gravity like dust or air

which construction classification require that all structural members are composed of non combustible or limited combustible materials with high fire-resistive rating
A) Type 1
B) Type 2
C) Type 3
D) Type 4
E) Type 5

Answers

Type 1 construction is defined as demanding that all structural members be made of noncombustible or minimally combustible materials with high fire-resistance ratings.

Construction of type 1 is also referred to as fire-resistant construction and is built to endure intense fire exposure. It primarily consists of noncombustible structural components consisting of concrete, steel, or masonry, which are commonly covered in fire-resistant materials like gypsum board, spray-on protective coatings, or fire-resistant insulation. The term combustible refers to any material that has the ability to burn or ignite when exposed to heat, flame, or other sources of ignition. Combustible materials include a wide range of substances, including wood, paper, plastics, gasoline, propane, and natural gas

High-rise constructions, hospitals, schools, as well as other facilities requiring a high level of fire protection frequently adopt type 1 construction.

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A radioactive chemical has a decay rate of approximately 5% per year. Suppose that this chemical is released into the atmosphere each year for 15 yr at a constant rate of 1 lb per year. How much of this chemical will remain in the atmosphere after 15 yr? The amount of chemical remaining in the atmosphere is lbs.

Answers

After 15 years, approximately 0.319 lb (or 0.319 pounds) of the radioactive chemical will remain in the atmosphere.

The decay rate of the chemical is approximately 5% per year, which means that each year, 95% of the chemical will remain after decay. This can be expressed as a decay factor of 0.95.

Since the chemical is released into the atmosphere at a constant rate of 1 lb per year for 15 years, we can calculate the amount remaining using the formula:

Remaining amount = Initial amount * Decay factor^Number of years

In this case, the initial amount is 1 lb, the decay factor is 0.95, and the number of years is 15. Plugging these values into the formula, we get:

Remaining amount = 1 lb * (0.95)^15

Calculating this expression, we find:

Remaining amount ≈ 0.319 lb

After 15 years, approximately 0.319 lb of the radioactive chemical will remain in the atmosphere. The decay rate of 5% per year gradually reduces the amount of chemical present, resulting in a relatively small fraction remaining after 15 years.

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Help someone :(((((((((((((((

Help someone :(((((((((((((((

Answers

The answer is B

I attached the image and explanation below.
Help someone :(((((((((((((((

Suppose you plot the distance traveled by an object at various times and you discover that the graph is not a straight line. What does this indicate about the objects acceleration?

Answers

The acceleration must be constant if the graph of distance travelled over time is not straight.

The acceleration of an object's means:

An object's acceleration is the rate at which its velocity changes over time.

The mathematical equation for an object's acceleration is as follows:

a = Δv / Δt

where;

V represents the object's change in velocity.

It is the shift in the speed of motion.

Acceleration is the slope of the velocity-time graph. This suggests that acceleration rises as an object's velocity rises.

Yet, it suggests that the velocity is not uniform if the graph of an object's distance travelled over time is straight.

For example, if an object is thrown vertically upwards, it will experience a constant acceleration due to gravity, but the acceleration will be in the opposite direction to the initial velocity. As the object moves upward, its velocity decreases until it reaches the maximum height, and then it starts to accelerate downward due to gravity. The graph of distance traveled vs. time will be a curve, indicating that the acceleration is not constant.

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A curved line going up indicates the object is

Answers

Explanation:

Both graphs show plotted points forming a curved line. Curved lines have changing slope; they may start with a very small slope and begin curving sharply (either upwards or downwards) towards a large slope. In either case, the curved line of changing slope is a sign of accelerated motion (i.e., changing velocity).

A solenoid is configured to produce a magnetic field of 0.027T at its center. it has radius 1.4 cm and length 40cm and the wire can carry a maximum length of 12.0A. What is the total length required​

Answers

The total length of the wire required is 63 m.

What is current?

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

Given is a solenoid is configured to produce a magnetic field of 0.027T at its center. it has radius 1.4 cm and length 40cm and the wire can carry a maximum current of 12.0 A.

Radius, r = 1.4cm = 0.014 m

Length l = 40 cm = 0.4 m

If the current is I, then the magnetic field in solenoid is given by

B =  μ₀ n I

By substituting the values, we get

0.027 = 4π x 10⁻⁷ x n x 0.4

n = 1792 turns/unit length

Total length of wire = circumference x Turns

L = 2πr x N

where N = nl

Plug the values, we get

L = 2π x 0.014 x1792 x 0.4

L = 63 m

Thus, the total length of the wire is 63 m.

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answer this question al six marks please my slays

answer this question al six marks please my slays

Answers

Answer:

the driver need to stop before he drive

Explanation:

if he keep driving he will hit a car

A squeeze bottle squeezes when pressed. It regains its shape when pressed .It regains its shape when the pressure from your hand is withdrawn. What may happen if the squeeze bottle is pressed to take the sauce out and then immediately corked tightly? Will it regain its shape? If not, Why?

Answers

Answer:

The squeeze will not regain its shape

Explanation:

The squeeze bottle will not regain its shape.

This is because the atmospheric pressure compresses the squeeze bottle. Since the pressure in the squeeze bottle is now not equal to the atmospheric pressure since it has been corked tightly, its internal pressure cannot balance out the atmospheric pressure and thus cancel its effect.

So, the squeeze bottle does not regain its shape due to this imbalance of pressure.


12. A conductor allows energy to easily pass by.
a) True
Conductors and Insulators | Print -
b) false

Answers

Answer:

A

Explanation:

A conductor works by allowing electrons to move through it with relative ease. In metals, this movement is facilitated by the structure of the material. Metals consist of a lattice of atoms in which the outermost electrons are not tightly bound to any particular atom. Instead, they are shared by all the atoms in the lattice and are free to move through the material. This allows electricity to flow freely through the metal, making it a good conductor.

A truck is moving along at 80.0 km/h when it hits a gravel patch, which causes it to accelerate at -5.0 km/h/s. How far will the truck travel before it slows to 20.0 km/h?

Answers

The truck's initial velocity is 80.0 km/h. When it hits the gravel patch, it experiences a negative acceleration of -5.0 km/h/s. This means that the truck's velocity will decrease by 5.0 km/h every second.

To find out how far the truck travels before slowing to 20.0 km/h, we need to use the equation:

v^2 = u^2 + 2as

Where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

First, we need to convert the units of the velocities and acceleration to m/s:

Initial velocity, u = 80.0 km/h = 22.22 m/s
Final velocity, v = 20.0 km/h = 5.56 m/s
Acceleration, a = -5.0 km/h/s = -1.39 m/s^2

Now we can plug these values into the equation:

(5.56)^2 = (22.22)^2 + 2(-1.39)s

Solving for s, we get:

s = (5.56)^2 - (22.22)^2 / 2(-1.39) = 346.8 m

Therefore, the truck will travel 346.8 meters before slowing down to 20.0 km/h.
Hi! I'd be happy to help you with this problem. We will use the following terms: truck, accelerate, and consider the scenario in less than 100 words.

1. Identify the given values:
Initial velocity (v0) = 80.0 km/h
Final velocity (vf) = 20.0 km/h
Acceleration (a) = -5.0 km/h/s

2. Use the formula vf² = v0² + 2*a*d to find the distance (d) traveled:
(20.0)² = (80.0)² + 2*(-5.0)*d

3. Solve for distance (d):
400 = 6400 - 10d
6000 = 10d
d = 600 km

The truck will travel 600 km before it slows to 20.0 km/h.

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a spherical mirror is to be used to form an image, six times as tall as an object, on a screen positioned 4.6 m from the mirror. (a) describe the type of mirror required. the mirror is a concave mirror and it has a focal length of 0.657 m. (b) where should the mirror be positioned relative to the object? the object should be 0.767 m in front of the mirror.

Answers

The type of mirror required will be a concave mirror with a focal length of 0.657 m.

The mirror is positioned relative to the object at 0.767m in front of the mirror.

(a) The type of mirror required to form an image that is six times as tall as the object is a concave mirror.

This is because a concave mirror is capable of producing both real and virtual images, depending on the position of the object relative to the focal point.

In this case, since the image is larger than the object, a concave mirror with a focal length of the appropriate value can produce the desired image.

(b) The distance between the mirror and the object can be calculated using the mirror formula:

1/f = 1/do + 1/di

where f is the focal length of the mirror, do is the distance between the object and the mirror, and di is the distance between the image and the mirror.

Given that the image is six times as tall as the object and the screen is 4.6 m from the mirror, we can determine the position of the image:

h/i = -di/do = -6/1

Thus, the image is 6 times as tall as the object, and since it is real and inverted, the value of di is negative. Substituting the known values into the mirror formula and solving for do, we get:

1/0.657 = 1/do - 1/4.6

Solving for do, we get do = 0.767 m. Therefore, the mirror should be positioned 0.767 m in front of the object.

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Which type of protist is animal AND plant like?

Answers

Answer:

Protists are called plant-like, fungus-like and animal-like because they share some of the characteristics of plants, fungi and animals, even though they belong in a different category: the kingdom Protista.

Explanation:

a fighter jet is launched from an aircraft carrier with the aid of its own engines and a steam-powered catapult. the thrust of its engines is 1.80 105 n. in being launched from rest it moves through a distance of 87 m and has a kinetic energy of 4.30 107 j at lift-off. what is the work done on the jet by the catapult?

Answers

A fighter jet being launched from such an aircraft carrier using a steam-powered catapult and its own engines. Its engines produce 2.3 x 105 N of thrust.

What speed is reached when a jet fighter aircraft is fired from a slingshot on an aircraft carrier?

42 m/s On an aircraft carrier, a catapult is used to launch a jet fighter. Just at end of the sling, it takes 2 seconds to achieve velocity of 42 m/s. What is the catapult's length if the acceleration is constant?

How strong is the aircraft carrier's catapult?

Catapults A 48,000-pound aeroplane was launched 300 feet and increased in speed from 0 to 165 miles an hour in two seconds by four steam-powered catapults. On every

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what is one standard kilogram​

Answers

The Kilogram was for many years the only one of the seven SI base standards that was not defined in terms of a fundamental attribute of nature.

It was specified as the weight of a platinum-iridium cylinder stored in a lab outside of Paris under inert conditions.

The problem with that is that it needs to be managed in order to use such a standard for calibrating exact copies. No matter how meticulously you do it, surface molecules must experience some minimal impact.

Therefore, efforts have continued to find a replacement standard that is not a tangible thing. With the suggestion for a new Standard Kilogram utilizing a gadget called the Kibble Balance, it now seems that the quest is over.

Answer:

one standard kilogram is the mass of cylinder made up of platinum-iridum alloy with equal diameter and base kept Ar international bureau of weight and measures near paris

the difference between the time an operation actually takes place and the time it would have taken under uncongested conditions without interference from other aircraft?

Answers

The difference between the actual time an operation takes place and the time it would have taken under uncongested conditions without interference from other aircraft is known as the operational delay.

Operational delay refers to the discrepancy between the actual time it takes for an operation to occur and the time it would have taken if there were no congestion or interference from other aircraft. In an ideal scenario with uncongested conditions, operations can proceed smoothly and efficiently, adhering to their scheduled timelines. However, in reality, various factors can contribute to delays in the aviation industry.

Operational delays can occur at different stages of an operation, including taxiing, takeoff, en route navigation, and landing. These delays are often caused by congestion in airspace or on the ground, traffic flow management issues, adverse weather conditions, or unexpected events such as equipment malfunctions or air traffic control restrictions. When these factors impede the normal flow of operations, the actual time it takes for an operation to be completed extends beyond what it would have taken under uncongested conditions.

Reducing operational delays is a significant focus for air traffic management systems and aviation stakeholders. Efforts are made to optimize airspace utilization, enhance communication and collaboration between aircraft and air traffic control, improve routing and navigation procedures, and implement advanced technologies to mitigate congestion and interference. By minimizing operational delays, the aviation industry can enhance efficiency, punctuality, and overall customer satisfaction.

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How can two stars with the same mass be different?

Answers

Two stars with the same mass number can be different in their luminosity, life time and distance with respect other stars and planets.

What are stars?

Stars are spatial objects with brightness and are made of gases and dust. The major part of stars are hydrogen and helium gases. There are trillions of stars for each galaxies in the universe.

The energy formed inside the stars is from  the nuclear fusion of hydrogen nuclei forming helium nuclei releases tones of heat and light energy. The light and heat energy produced from each stars differ.

The luminosity or brightness of stars with same mass will be different. The life time of each stars also differ from other stars.

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The momentum of a 3000 kg truck is 6.36 x 104 kg·m/s. At what speed is the truck traveling? m/s


472

19,080

2.1

21.2

19.6

24.5

Answers

Answer:

21.2m/s

Explanation

Given data

P=6.36 x 10⁴kg·m/s.

M=3000kg

From the momentum expression

P=mv

v=p/m

Substitute

v=63600/3000

v=21.2m/s

Hence the Velocity is 21.2m/s

The speed of the truck is 21.2 m /s

Momentum is the product of the mass of the object and the velocity of the object. Therefore,

p = mv

where

m  = mass

v = velocity

m = 3000 kg

p = 6.36 x 104 kg·m/s.

lets find the velocity

6.36 x 10⁴  = 3000 × v

v = 6.36 x 10⁴ / 3000

v = 21.2 m / s

The speed of the truck is 21.2 m /s

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The sound level produced by one singer is 76.7 dB. What would be the sound level produced by a chorus of 40 such singers (all singing at the same intensity at approximately the same distance as the original singer)

Answers

The sound level produced by a single singer at 76.7 dB can be quite loud,

but it may not be enough to fill a large space or be heard clearly over other background noises. When you have a chorus of 40 singers all singing at the same intensity,

you can expect the overall sound level to increase significantly. To calculate the sound level produced by the chorus of 40 singers, you can use a formula called the log rule for sound intensity.

This formula states that the sound intensity (I) of multiple sound sources can be calculated by adding the logarithms of their individual sound intensities (I1, I2, I3, etc.). In other words, I(total) = 10*log10(I1 + I2 + I3 + ...)



Using this formula, we can calculate the sound level produced by the chorus of 40 singers.

Assuming that each singer produces the same sound intensity as the original singer, we can use the fact that sound intensity is proportional to the square of the sound pressure level (SPL).



That means that if one singer produces a SPL of 76.7 dB, then the sound intensity of that singer is I1 = 10^(76.7/10) = 3.98 x 10^-5 W/m^2 , To calculate the total sound intensity produced by 40 such singers, we can multiply the individual sound intensity by 40.



I(total) = 40*I1 = 1.59 x 10^-3 W/m^2, Using the log rule formula, we can convert this sound intensity to a sound pressure level (SPL) in dB. SPL = 10*log10(I/(10^-12)), where 10^-12 W/m^2 is the reference sound intensity for the threshold of human hearing.



SPL = 10*log10(1.59 x 10^-3/(10^-12)) = 105.5 dB, Therefore, the sound level produced by a chorus of 40 singers singing at the same intensity as the original singer would be around 105.5 dB.

This is significantly louder than the original singer and can be quite powerful and impressive, but it is important to note that sustained exposure to sound levels above 85 dB can cause hearing damage.

So if you are planning on listening to a chorus of 40 singers, make sure to protect your ears with earplugs or other hearing protection.

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A 9 kg box is placed on a 6 m tall shelf. What will be the kinetic energy of the box right before it hits the ground? (use g = 10 m/s/s)

Answers

Answer:

540 J

Explanation:

U at top equals to K at bottom if it's an isolated system therefore U at top is equals to 540 J so we can assume that at 0m U=0 (mgh) therefore the box has gained some velocity due to the acceleration due to g and we can calculate it using 1/2mv²

what is the critical speed below which the rope woudl becom slack when the bucket reaches the highest point in the circle

Answers

The critical speed below which the rope would become slack when the bucket reaches the highest point in the circle is determined by the length of the rope and the radius of the circle.

When the bucket is at the highest point in the circle, it is momentarily at rest and the tension in the rope must be zero.

The formula for calculating the critical speed at which the rope becomes slack is:

v = √(gr)

where v is the critical speed, g is the acceleration due to gravity, and r is the radius of the circle.

For example, if the radius of the circle is 2 meters and the acceleration due to gravity is 9.8 m/s², the critical speed would be:

v = √(9.8 × 2) = 4.4 m/s

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(Figure 1) shows a standing wave that is oscillating at frequency 100 Hz Part A How many antinodes will there be if the frequency is doubled to 200 Hz? Express your answer as an integer. N= 8 Soome Previous Answers ✓ Correct Part B Figure 1 of 1 If the tension in the string is increased by a factor of 4, at what frequency will the string continue to oscillate figure? Express your answer with the appropriate units. IMA th ? 1 - 400 Hz V Submit Previous Are Rest Answer X Incorrect: Try Again: 5 attempts remaining

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If the frequency of a standing wave that is oscillating at 100 Hz is doubled to 200 Hz, the number of antinodes will also double.

The formula for the number of antinodes (n) in a standing wave is:
n = (L / λ) + 1
where L is the length of the medium and λ is the wavelength.

Since the frequency is doubled, the wavelength will be halved (assuming the medium remains the same). This is because the speed of sound in a medium is constant, so if the frequency is doubled, the wavelength must be halved to maintain the same speed.

So, if the original wavelength at 100 Hz was λ1, then the new wavelength at 200 Hz would be λ2 = λ1/2.

Substituting this into the formula for n, we get:
n2 = (L / λ2) + 1
  = (L / (λ1/2)) + 1
  = 2(L / λ1) + 1

So, the number of antinodes at 200 Hz (n2) will be twice the number of antinodes at 100 Hz (n1), plus one.

Therefore, if there are n1 antinodes at 100 Hz, there will be 2n1 + 1 antinodes at 200 Hz.

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Caculate the grvtonal force between a 4kg and a 6kg mass seperated by a distance of 3m

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The gravitational force between a 4kg and a 6kg mass separated by  a distance  of 3 m is  1.185 × 10^-9 N.

The gravitational force between  two masses can be calculated using the formula: F = G * (m1 * m2) / r^2, where F is the  gravitational force, G is the gravitational constant (6.67430 × 10^-11 N·m^2/kg^2), m1 and m2 are the masses of the objects and r is the distance between their centers of mass.

In this case, m1 =4kg, m2= 6 kg and r is the 3 m. plugging  these values into the formula  above mentioned we get:

F = (6.67430 × 10^-11 N·m^2/kg^2) * (4 kg * 6 kg) / (3 m)^2= 1.185 × 10^-9 N

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