Lisa tosses a flying disc to her friend. The more force she uses to throw the disc, the greater the acceleration. Which of physics' laws of motion explains that the disc has a greater acceleration when it is thrown with a greater force ?

It's average velocity Is 96 km/h east and it's average speed is ​ 96 km/h.

To calculate the average velocity, we need to find the total displacement of the car and the total time taken.

The car moves at 120 km/h for 3 hours, so the total displacement during this time is:

displacement = velocity x time = 120 km/h x 3 h

                       = 360 km east

The car then moves at 60 km/h for 2 hours, so the total displacement during this time is:

displacement = velocity x time

                      = 60 km/h x 2 h

                       = 120 km east

The total displacement of the car is the sum of these displacements:

total displacement = 360 km + 120 km

                               = 480 km east

The total time taken by the car is:

total time = 3 h + 2 h

               = 5 h

Therefore, the average velocity is:

average velocity = total displacement / total time

                            = 480 km / 5 h

                              = 96 km/h east

To calculate the average speed, we need to find the total distance traveled by the car and the total time taken.

The car travels at 120 km/h for 3 hours, so the distance traveled during this time is:

distance = velocity x time

               = 120 km/h x 3 h

               = 360 km

The car then travels at 60 km/h for 2 hours, so the distance traveled during this time is:

distance = velocity x time

              = 60 km/h x 2 h

              = 120 km

The total distance traveled by the car is the sum of these distances:

total distance = 360 km + 120 km

                        = 480 km

Therefore, the average speed is:

average speed = total distance / total time

                         = 480 km / 5 h

                           = 96 km/h

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three plus four NERD

Answer:

True

Explanation:

The Gravitational potential energy is given by:

G = mgh

m = mass of body ; g = acceleration due to gravity ; h = height

G for a ball of mass 10kg ; height of 20 meters above the ground

G = 10kg * 9.8m/s² * 20m = 1960 kgm²/s²

G for a ball of mass 1000kg at height, 0 meters :

G = 1000 * 9.8 * 0 = 0

1960 > 0

Hence, Gravitational potential energy for 10kg ball at height 20m is greater Thammfor a 1000kg ball on the ground.

None of the above answer choices are correct. The total kinetic energy just before the collision is 25J.

We can use conservation of momentum and conservation of energy to solve this problem.

Let m be the mass of each particle, v1 be the velocity of the slower particle, and v2 be the velocity of the faster particle. We know that:

mv1 + mv2 = 0 (conservation of momentum)

and

(1/2)mv1^2 + (1/2)mv2^2 = 25 J + 100 J = 125 J (conservation of energy)

Simplifying the momentum equation, we get:

v2 = -2*v1

Substituting this into the energy equation and simplifying, we get:

5*v1^2 = 125 J

v1^2 = 25 J

v1 = ±5 m/s

Since the particles are moving towards each other, their relative velocity is the sum of their velocities, which is:

v_rel = v1 + v2 = v1 - 2*v1 = -v1

Therefore, the speed of the particles just before they collide is:

|v_rel| = |v1| = 5 m/s

The total kinetic energy just before the collision is:

(1/2)mv1^2 + (1/2)mv2^2 = (1/2)mv1^2 + (1/2)m(-2v1)^2 = 5/2m*v1^2 = 25J.

Therefore, the answer is 25J.

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Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process

Explanation:

To get the total number of iterations in a nested loop, add the number of iterations in the inner loop to the number in the outer loop is option b. false

A break statement in a nested loop only terminates the loop it is contained in. As a result, even if the inner loop is broken, the outer loop keeps going. The looping ends completely, though, if the break is positioned in the outer loop.

Therefore, the number of outer loop repetitions multiplied by the number of inner loop repetitions is the formula for determining how many times the inner loop executes. The nested for loops have an iteration count of N=N1N2.

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Answer:

The laws of liquid pressure are: ... The liquid pressure at a point inside the liquid is same in all directions. The liquid pressure at a point inside the liquid is directly proportional to the depth of that point from the free surface of liquid. The pressure of liquid at same depth is different for different liquids

Answer:

The laws of liquid pressure:

The pressure that is inside the liquid rises with the intensity from the surface of a liquid.

The term fluid:

Fluid is basically liquid and a substance that is known to have no certain shape. The opposite of the term fluid would be solid.

Answer:

4.7m

Explanation:

Given parameters:

Mass of the book  = 1kg

Gravitational potential energy  = 46J

Unknown:

Height of the shelf  = ?

Solution:

The potential energy is due to the position of a body above the ground.

        Gravitational potential energy  = mgh

m is the mass,

g is the acceleration due gravity  = 9.8m/s²

h is the height which is unknown

                       46  = 1 x 9.8 x h

                       h  = 4.7m

Answer:

a=6m/sec²

Explanation:

f=5 N

a1=8m/sec²

a2=24m/sec

m1=f/a1=5/8kg

m2=f/a2=5/24kg

New, f=(m1+m2)a

a=5/5/8+5/24=5/15+5/24=24*5/20

a=6m/sec²

Answer:

Sketch the situation.

b. Calculate the potential energy, the kinetic energy, and the total energy of the car as it leaves the cliff.

c. Make a graph displaying the kinetic, gravitational potential, and total energy of the car at each 10 m

increment of height as it drops

Explanation:

The potential energy of the car at that position is 10.6 x 10⁵ J.

Potential energy of an object is defined as the energy acquired by the object by virtue its position.

Here,

Mass of the car, m = 1200 kg

Speed of the car, v = 29 m/s

Height of the cliff, h = 90 m

Therefore,

Potential energy of the car, PE = mgh

PE = 1200 x 9.8 x 90

PE = 10.6 x 10⁵ J

Hence,

The potential energy of the car at that position is 10.6 x 10⁵ J.

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Answer:

The speed of molecules in an "ideal" gas is related to the temperature

Advanced work indicates that

1/2 m v^2 = 3/2 k T    where v^2 here is the mean square speed

This is true for H2, He, O2, Hg   etc. and m is the molecular mass and k the Boltzmann constant

The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.

To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.

Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.

Using the formula, we can calculate the distance traveled as follows:

d = rt

d = 130 mph × 2.5 hours

Multiplying the rate (130 mph) by the time (2.5 hours) gives us:

d = 325 miles

Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.

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Work does by a 55 kg person against gravity in walking up a trail that gains 720 m in elevation is 396,000 Joule = 396 kJ

Work calculated by multiplying the force with the distance of the end point of the object. In this case the object is a 55 kg person and the distance is 720 m in elevation. To determine the force of the object we can use this equation:

F = m x a

With,

F = force (N)

m = object mass (kg)

a = acceleration (\(m^{2}\)/s), in this case a = gravity = 10 \(m^{2}\)/s

F = 55 x 10

F = 550 N

After got the value of the force, we can calculate the work done by the person:

W = F x s

With,

W = work (J)

F = force (N)

s = distance (m)

W = 550 x 720

W = 396,000 J = 396kJ

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Answer:

There are also reasons not to, but usually it keeps you on the road.

Explanation:

If I keep my vehicle straight behind the one in front of me, as long as they are fine I’m fine.
Although, if they make a mistake it’s easy to be too focused on following them than to save yourself.

Using the taillights of the vehicle in front of you to guide you in snowy conditions can help improve your visibility, provide guidance on the road ahead, and keep you centered and safe while driving in challenging conditions.

In extremely snowy conditions, visibility can be severely reduced, making it difficult to see the road ahead and navigate safely. Using the taillights of the vehicle in front of you can help guide you for several reasons:

(1) Contrast: The taillights of a vehicle provide a contrasting light against the white background of the snow, making it easier to see and follow the vehicle in front of you.

(2) Visibility: The taillights are usually positioned higher up on the vehicle than the brake lights, making them more visible above the snow drifts or other obstacles on the road.

(3) Indicators: The taillights provide indicators of the vehicle in front's movements, such as when they are turning or slowing down. By paying attention to these indicators, you can anticipate the actions of the vehicle ahead and react accordingly.

(4) Centering: Following the taillights of the vehicle in front can help keep you centered on the road and prevent you from accidentally veering off course.

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A clay liner and a system of pipes is used in a sanitary landfill to

a) Prevent leakage

What is sanitary landfill ?

Sanitary landfill refers to the efficient use of engineering techniques to confine waste to the smallest practical area in order to cover it with a layer of soil to reduce its volume and minimize pollution. It is a land-based method of disposal without harming the environment and public health. of air.

A landfill is a place where waste is isolated from the environment until it is safe. It is believed to be completely biologically, chemically and physically degraded. High-income countries may have higher levels of isolation achieved.

A safe landfill has critical elements: a bottom liner, a leachate collection system, a cover, and a natural hydrogeological environment. The natural environment can be chosen to minimize the potential for waste to enter the groundwater below the landfill.

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The light travels at the slowest speed through flint glass and at the fastest speed through water .The speed of light in a medium is dependent on the refractive index of that medium.

c. Flint glass (highest refractive index)

a. Corn oil

b. Ethyl alcohol

d. Water (lowest refractive index)

The refractive index determines how much the light is slowed down or sped up as it passes through a material compared to its speed in a vacuum.

To rank the four media from the one through which the light travels at the slowest speed to the one through which the light travels at the fastest speed, we need to consider their refractive indices.

The refractive indices for the given media are as follows:

a. Corn oil: Refractive index ≈ 1.47

b. Ethyl alcohol: Refractive index ≈ 1.36

c. Flint glass: Refractive index ≈ 1.66

d. Water: Refractive index ≈ 1.33

The higher the refractive index, the slower light travels in that medium. Therefore, ranking the media from the slowest speed to the fastest speed, we have:

c. Flint glass (highest refractive index)

a. Corn oil

b. Ethyl alcohol

d. Water (lowest refractive index)

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The statements about limiting frictional force between two surfaces are given below(3) A and C is correct option.

The nature of surfaces in contact affects the limiting frictional force because the coefficient of friction depends on the properties of the surfaces in contact.

The area of surfaces in contact also affects the limiting frictional force because a larger surface area in contact results in a larger normal force, which increases the maximum frictional force that can be generated.

The normal reaction between the surfaces in contact is not directly related to the limiting frictional force, as it only affects the magnitude of the frictional force and not its limit. Therefore, statement B is not correct.

Thus the correct option is (3).

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The momentum of the system is always constant. Therefore, the example that best fits the criteria is "A freely falling metal ball, with the ball and Earth as the system." So, C is the correct option.

When considering the examples given, we can eliminate options (a) and (d) as they suggest that the momentum of the system is always constant.

The momentum of a system is the product of the mass and velocity of an object. When the metal ball is falling freely, the momentum of the ball and the Earth system changes continuously as the velocity of the ball changes due to the force of gravity. Therefore, the momentum of the system is not constant in this case.

So, the correct option is C.

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a) the critical length of the banner is 2251.67 m

b)The drag coefficient of the banner is 0.833

c)The drag force acting on the banner is 9526.18 N

d)The power required to overcome banner drag is 317531.85 W

Given:Altitude, z = 2000 mHorizontal velocity, V = 120 km/h = 33.33 m/s

Height of advertising banner, h = 3 mLength of advertising banner, l = 5 m

To find:The critical length, X_cr of the banner Drag coefficient of the banner Drag force acting on the banner The power required to overcome banner drag

Formula Used:The critical length is given by the formula,\(Xcr = 5.0 * l * Re^(1/2)\)

Where, l is the length of the plate.

Re is the Reynolds number of the fluid and is given by,

Re = ρVD/μ

Where,ρ is the density of the fluidD is the characteristic dimension (diameter or length)μ is the dynamic viscosity of the fluidThe drag coefficient of the banner can be calculated by the formula,

Cd = Fd/(1/2ρAV^2)

Where,Fd is the drag forceρ is the density of the fluid

A is the frontal area

V is the velocity of the fluid

The drag force acting on the banner can be calculated by the formula,

Fd = (1/2)ρAV^2Cd

Where,ρ is the density of the fluid

A is the frontal area

V is the velocity of the fluid

Cd is the drag coefficient

The power required to overcome the banner drag can be calculated by the formula,

P = FdV

Where,Fd is the drag force

V is the velocity of the fluid

Solving part

(a)Critical Length:Since the Reynolds number of the fluid is not given, we need to calculate it first.

Reynolds Number of the fluid:

Re = ρVD/μ The density of air is given in the table as 1.225 kg/m^3.

The kinematic viscosity of air is given in the table as 15.89 x 10^-6 m^2/s.

The characteristic dimension (length) of the plate is

l = 5m.

Re = ρVD/μ

Re = (1.225 kg/m^3)(33.33 m/s)(5 m)/(15.89 x 10^-6 m^2/s)

Re = 1.012 x 10^8

Xcr = 5.0 * l * Re^(1/2)Xcr = 5.0 * (5m) * (1.012 x 10^8)^(1/2)

Xcr = 2251.67 meters

Therefore, .Solving part (b)

Drag Coefficient of the Banner:

Cd = Fd/(1/2ρAV^2)

Since we don't have the frontal area of the banner, we need to calculate it first.

Frontal Area of the Banner:

A = hl = (3 m)(5 m)

= 15 m^2

Cd = Fd/(1/2ρAV^2)

Fd = (1/2)ρAV^2Cd

Cd = Fd/(1/2ρAV^2)

Cd = 2Fd/(ρAV^2)Fd

= (1/2)ρAV^2CdFd

= (1/2)(1.225 kg/m^3)(33.33 m/s)^2(15 m^2)Cd

Cd = 2{(1/2)(1.225 kg/m^3)(33.33 m/s)^2(15 m^2)}/[(1.225 kg/m^3)(33.33 m/s)^2]^2

Cd = 0.833.

Solving part (c)Drag Force acting on the Banner:

Fd = (1/2)ρAV^2CdA = hl = (3 m)(5 m) = 15 m^2

Fd = (1/2)(1.225 kg/m^3)(33.33 m/s)^2(15 m^2)(0.833)

Fd = 9526.18 N.

Solving part (d)Power required to overcome Banner Drag:

P = FdVP

= (9526.18 N)(33.33 m/s)

P = 317531.85 W.

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The critical length (Xcr) = 1.489 m,

Drag coefficient of the banner = 0.0184,

Drag force acting on the banner = 8.42 N, and

Power required to overcome banner drag = 280.95 W.

Altitude of airplane, z = 2000 m

Horizontal velocity of airplane, V = 120 km/h

= 33.33 m/s

Height of the advertising banner, h = 3 m

Length of the advertising banner, l = 5 m

The critical length (Xcr), Drag coefficient of the banner, Drag force acting on the banner, and Power required to overcome banner drag

To find critical length (Xcr)The critical length of an object is the length at which the transition from laminar to turbulent flow occurs.

The critical Reynolds number for a flat plate is given by:  Xcr = 5lReL = 5*5*33.33*2000/1.79*10^(-5)

Critical length, Xcr = 1.489 m2.

To find Drag coefficient of the banner

The drag coefficient of the banner depends on Reynolds number.

The Reynolds number of the banner can be found as follows:

Re = VL/v

= (33.33*5)/1.79*10^(-5)

= 930508.38

From the table A-11, the value of Cd for Re = 930508.38 is 0.0184

Therefore, Drag coefficient of the banner = 0.01843.

To find Drag force acting on the banner

The drag force acting on the banner can be found as follows:

Fd = Cd* (1/2)*ρ*V^2*A

where,

ρ = 1.79 * 10^(-5) kg/m³ (from table A-11)

A = l * h = 5 * 3 = 15 m²

Fd = 0.0184 * (1/2) * 1.79*10^(-5) * 33.33^2 * 15

Drag force acting on the banner = 8.42 N4.

To find Power required to overcome banner drag

Power required to overcome banner drag = Fd * V

Power required to overcome banner drag = 8.42 * 33.33 = 280.95 W

Therefore, the critical length (Xcr) = 1.489 m,

Drag coefficient of the banner = 0.0184,

Drag force acting on the banner = 8.42 N, and

Power required to overcome banner drag = 280.95 W.

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Answer:

a)

there r two types of motion, uniform and non-uniform

uniform means equal distance travelled at equal intervals of time

and non-uniform is exactly the opposite.

b)

quantities which can be represented by magnitude along r called scalar quantities such as speed.

quantities which need magnitude along with direction r called vector quantities such as velocity.

c)

velocity=10m/s

acceleration = u-v/s i.e initial final velocity - initial velocity upon time

acceleration= 0.2m/s sq

time= 30s

10 = displacement/time

10 = x/30

10 = 300

Answer is 300 meters - distance/displacement.

Answer:

He could use magnets to lift heavy things and also move things like a train

Explanation:

i had the same question

Answer:

The universe doesn't actually have an "end" in the conventional sense, according to current scientific theory.

Explanation:

The universe doesn't actually have an "end" in the conventional sense, according to current scientific theory. Instead, there doesn't seem to be a limit or edge that designates the "end" of the cosmos; rather, it appears to be endless in both space and time.

One of the key pieces of evidence for the infinite nature of the universe comes from observations of the cosmic microwave background radiation, which is a faint glow of radiation left over from the Big Bang. These observations show that the universe is very nearly the same in all directions, suggesting that it is homogeneous and isotropic on large scales and that there is no preferred direction or edge to the universe.

Observations of far-off galaxies provide additional proof, demonstrating that they are accelerating away from us at rates proportionate to their distance from us. Hubble's law, which asserts that the cosmos is expanding uniformly and without a center or edge, is well-known.

It is crucial to remember that our knowledge of the world is always changing and that fresh revelations may alter how we currently see the universe's structure and course of evolution.

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Earth would be an icy wasteland if greenhouse gases were not present. Greenhouse gases keep our planet livable by retaining some of the Earth's heat energy, preventing it from escaping into space. The greenhouse effect refers to the trapping of heat.

It takes the ball 3.06 seconds to reach its highest point

The time it takes for a ball to reach its highest point is given by the equation:

t = v / g

where

In this case, the initial velocity is 30.0 m/s and the acceleration due to gravity is \(9.8 m/s^2\). Therefore, the time it takes for the ball to reach its highest point is:

\(t = 30.0 m/s / 9.8 m/s^2 = 3.06 s\)

Therefore, it takes the ball 3.06 seconds to reach its highest point.

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You were approximately 5.72 meters away from the second baseman. The vertical drop or distance between point A and point B was approximately 0.4576 meters.

To determine the distance between you (the shortstop) and the second baseman, we can use the formula for horizontal distance (d) traveled by an object moving at a constant horizontal velocity:

d = v * t

where:

- d is the horizontal distance traveled,

- v is the horizontal velocity of the ball,

- t is the time taken.

Given that the horizontal velocity (v) is 13 m/s and the time (t) is 0.44 s, we can calculate the horizontal distance (d) as follows:

d = 13 m/s * 0.44 s = 5.72 meters

So, you were approximately 5.72 meters away from the second baseman.

To find the vertical drop or the distance between point A and point B, we need to calculate the vertical component of the ball's motion. Since the ball is thrown horizontally, it will experience a constant vertical acceleration due to gravity.

The formula to calculate the distance (d) traveled vertically in free fall is:

d = 1/2 * g * t²

where:

- d is the vertical distance traveled,

- g is the acceleration due to gravity (approximately 9.8 m/s²),

- t is the time taken.

Given that the time (t) is 0.44 s, we can calculate the vertical distance (d) as follows:

d = 1/2 * 9.8 m/s² * (0.44 s)² = 0.4576 meters

So, the vertical drop or the distance between point A and point B is approximately 0.4576 meters.

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Answer: 28n x 2m= 56n-m= 56 joules

Explanation:

Answer:

464.1 km

Explanation:

Using R = u²sin2Ф/g where R = range of projectile, u = muzzle speed = 2.20 km/s = 2.20 × 10³ m/s, Ф = angle of elevation or projection angle = 55° and g = acceleration du° to gravity = 9.8 m/s²

Substituting the values of the variables into the equation, we have

R = u²sin2Ф/g

R = (2.20 × 10³ m/s)²sin2(55°)/9.8 m/s²

R = 4.84 × 10⁶ m²/s²sin110°/9.8 m/s²

R = 4.84 × 10⁶ m²/s² × 0.9397/9.8 m/s²

R = 4.548 × 10⁶ m²/s²/9.8 m/s²

R = 0.4641 × 10⁶ m

R = 464.1 × 10³ m

R = 464.1 km