Mark ran for 15 minutes. How many seconds did Mark run? (1 minute = 60 seconds) seconds

The real distance between towns X and Y measuring 11.2 cm apart on a map with a scale 1: 100,000 is 11.2 km.

Given the scale = 1: 100,000, which means that 1 cm on the map represents 100,000. Thus, 11.2 cm on the map represents 11.2* 100,000 = 1,120,000cm.

We know that 1 km = 100,000cm

Therefore 1,120,000 cm = 1,120,000/100,000

= 11.2 km

Therefore, the real distance between towns X and Y is 11.2km.

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Answer:

slope: -3/4    y-intercept: 3   equation: y=(-3/4)x+3

Answer:

The answer is a = -15

Step-by-step explanation:

1/3a = -5

3 × 1/3a = 3 × (-5)

a = 3 × (-5)

a = -3 × 5

Answer is a = -15

Answer:

a = 15

Step-by-step explanation:

Just answer

Yes, the equations have different slopes, so the lines are not parallel, which mean that at some points the lines will intersect.

We know that Elena's car has a current mileage of 15,000 and she drives 23,000 miles more each year. Then the mileage in her car as a linear function of the number of years x is:

E = 15,000 + 23,000*x

While we know that has a current mileage of 46,000 and he drives 9,000 miles more each year. Then his function is:

M  = 46,000 + 9,000*x

We can see that the slopes are different in both equations, then the lines are not parallel, which means that at some point the lines will intersect, then the correct option is the third one.

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Answer:

It's D ...

hope it helps

Answer:

it is literally 0

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

thats simple..........

The average daily balance for the month was $84.21, and the finance charge for the month was $30.13.

Given that Sally's balance on her credit card is $75.00 on the first day of August, and she makes a payment of $18.00 on August 17 and a new purchase of $41.00 on August 29, and the annual interest rate is 21.25%, to determine what is Sally's average daily balance and finance charge for the month of August, the following calculation must be made:

Therefore, the average daily balance for the month was $84.21, and the finance charge for the month was $30.13.

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Answer:

Natalie Spent $59.54 on songs after 5 months at online music service.

Step-by-step explanation:

Total membership cost =$14.99

Number of songs purchased in each month = 9

Cost per song = $0.99

We need to find total amount she had spent after 5 months.

Solution:-

So First we will Number of songs purchased in 5 months.

1 month = 9 songs

So in 5 months = Songs purchased in 5 months.

By Using Unitary method we get;

Songs purchased in 5 months =  

Now Also Given:

1 song = $0.99

45 songs = Cost for 45 songs.

Again by using Unitary method we get;

Cost for 45 songs =  

No Total Amount Natalie spent after 5 months is equal to Total membership cost plus Cost of songs purchased in 5 months.

framing in equation form we get;

Total Amount Natalie spent =  

Hence Natalie Spent $59.54 on songs after 5 months at online music service.

Answer:

59.54 total spent

Step-by-step explanation:

each song cost .99 so .99×9=8.91 take that times the next 5 months 8.91×5= 44.55 then we add the fist payment of 14.99 44.55+14.99= 59.54

Answer:

56

Step-by-step explanation:

54 + 4(3/4 − 1/2)2

=> 54 + 4(1/4)2

=> 54 + (1)2

=> 54 + 2

=> 56

Therefore, 56 is our answer.

Hoped this helped.

Answer:

Question 1:

SAT average divided by budget per student and

SAT average divided by teachers per student

Question 2:

Yes. According to both definitions, school A has the higher SAT average relative to the resources invested per student.

There are 4,377 different ways to distribute the 96 children into groups, with each group having a minimum of 5 children and a maximum of 20 children. (By division)

To determine the number of ways to distribute the 96 children into groups, we need to find the number of divisors of 96 that are between 5 and 20.

First, let's find the divisors of 96. The divisors of 96 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96.

Next, we need to consider the divisors that fall within the range of 5 to 20. In this case, the divisors are 6, 8, 12, and 16.

Now, we can calculate the number of ways to distribute the children into groups using the divisors:

For each divisor, we divide the total number of children (96) by the divisor to determine the number of groups.

Number of ways = Number of groups = Total number of children / Divisor

For the divisor 6: Number of groups = 96 / 6 = 16 groups

For the divisor 8: Number of groups = 96 / 8 = 12 groups

For the divisor 12: Number of groups = 96 / 12 = 8 groups

For the divisor 16: Number of groups = 96 / 16 = 6 groups

Finally, we sum up the number of ways for each divisor:

Number of ways = Number of ways for divisor 6 + Number of ways for divisor 8 + Number of ways for divisor 12 + Number of ways for divisor 16

= 16 + 12 + 8 + 6

= 42

Therefore, there are 42 different ways to distribute the 96 children into groups, with each group having a minimum of 5 children and a maximum of 20 children.

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Answer:X=4

Step-by-step explanation: you add 12 to both sides which should get you 2x=68 and then divide both sides by 2 which should get you X=4

The five-number summary for the dataset are Minimum: 68, Q1: 69, Median: 78, Q3: 90 and Maximum: 94.

To create a box and whisker plot for the given dataset {69, 88, 94, 73, 78, 90, 68}, follow these steps:

Step 1: Arrange the data in ascending order:

68, 69, 73, 78, 88, 90, 94

Step 2: Find the five-number summary:

Minimum: The smallest value in the dataset, which is 68.

First quartile (Q1): The median of the lower half of the dataset. In this case, it's the median of {68, 69, 73}, which is 69.

Median (Q2): The middle value of the dataset. In this case, it's 78.

Third quartile (Q3): The median of the upper half of the dataset. In this case, it's the median of {88, 90, 94}, which is 90.

Maximum: The largest value in the dataset, which is 94.

Step 3: Create the box and whisker plot:

Draw a number line with a range from the minimum (68) to the maximum (94).

Mark the first quartile (Q1) at 69.

Mark the median (Q2) at 78.

Mark the third quartile (Q3) at 90.

Draw a box from Q1 to Q3.

Draw a vertical line (whisker) from the box to the minimum (68) and another vertical line from the box to the maximum (94).

The resulting box and whisker plot for the given dataset would look like this:

  |

 94|                 ▄

  |                ╱ ╲

 90|              ╱   ╲

  |             ╱     ╲

 88|            ▇       ▂

  |            ▇       ▂

 78|            ▇       ▂

  |            ▇       ▂

 73|          ╱         ╲

  |         ╱           ╲

 69|        ▃             ▃

  |       ╱               ╲

 68|      ╱                 ╲

  |_________________________________

    68     73     78     88     94

This plot represents the distribution of the given dataset, showing the minimum, maximum, first quartile (Q1), median (Q2), and third quartile (Q3).

The five-number summary for the dataset are Minimum: 68, Q1: 69, Median: 78, Q3: 90 and Maximum: 94.

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Answer:

0.2.5

Step-by-step explanation:

2.5 x 5 = 2

Answer: 16.61

Step-by-step explanation:

If we are talking about a 10x the original amount it would be 16.61

Answer:

Step-by-step explanation:

D think is your answer

If you save $2,015.82 every year at an interest rate of 8%, you can retire in 30 years and live another 25 years while still having enough money to spend $80,000 per year.

To calculate the amount you need to save per year for the next 30 years, we can use the future value of an ordinary annuity formula.

The future value of an ordinary annuity formula is:

\(FV = P \cdot \left(\frac{(1 + r)^n - 1}{r}\right)\)

Where:

FV = Future value of the annuity

P = Payment amount per period

r = Interest rate per period

n = Number of periods

In this case:

P = Amount you need to save per year

r = 8% = 0.08 (annual interest rate)

n = 30 (number of years)

We want the future value (FV) to be equal to the amount needed to spend per year during retirement, which is $80,000.

Using the formula, we can calculate the amount you need to save per year:

\(\$80,000 = P \cdot \left[\left(1 + 0.08\right)^{30} - 1\right] / 0.08\$\)

Simplifying the equation:

\($80000 = P \cdot [1.08^{30} - 1] / 0.08$\)

$80,000 * 0.08 = P * [1.08³⁰ - 1]

$6,400 = P * [1.08³⁰ - 1]

Dividing both sides by [1.08³⁰ - 1]:

\($P = \dfrac{\$6400}{1.08^{30} - 1}$\)

Calculating [1.08³⁰ - 1]:

[1.08³⁰ - 1] ≈ 3.172024

Dividing $6,400 by 3.172024:

P ≈ \($\frac{6,400}{3.172024} \approx$ $2,015.82\) (rounded to the nearest cent)

Therefore, you need to save approximately $2,015.82 per year into your investment account at the end of each year for the next 30 years.

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Answer:

Step-by-step explanation:

We'll get the coordinates of the points C and D first and find slope and y-intercept

As per the graph, the coordinates are:

Formula of the line

Slope is

So the line is

I’m backkkkkkkk

Arrange the tiles

Write a paragraph that explains

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What is the range of the function

Explain your answer

Research paper

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History

African American

Experiences

Justice

Identify

Social

Women

Which factors push cultures to change over time

Population

Distribution

Trade

Growth

Technology

Properties of algebra

Find the sum of

As a result, the app stοre's οwner prοjects that in its third year οf οperatiοn, there will be rοughly 2.197 milliοn app dοwnlοads.

A mathematical functiοn with the fοllοwing fοrmula is an expοnential functiοn: f(x) = \(a^x\) where x is the expοnent and an is a cοnstant knοwn as the base. Expοnential functiοns have a distinctive structure where the value οf the functiοn rapidly rises (οr falls) as the expοnent x value rises. The rate οf increase οr decline is determined by the expοnential functiοn's base. If a > 1, the functiοn will quickly increase as x rises, and if 0 a 1, the functiοn will quickly decrease as x rises.

We can use the fοrmula: tο create an expοnential grοwth functiοn f(x) that prοvides the number οf app dοwnlοads (in milliοns) in year x.

\(f(x) = f(0) * (1 + r)^x\)

where x is the number οf years since the app stοre first launched, r is the grοwth rate, and f(0) is the οriginal number οf dοwnlοads.

In this instance, there were 1 milliοn initial dοwnlοads, and the grοwth rate was 30%, οr 0.30. Thus, the fοllοwing is the expοnential grοwth equatiοn fοr the milliοns οf app dοwnlοads in year x:

\(f(x) = 1 * (1 + 0.30)^x\)

\(f(x) = 1.3^x\)

Therefοre, fοr instance, entering x=3 intο the functiοn will return the amοunt οf app dοwnlοads (in milliοns) fοr the third year.

\(f(3) = 1.3^3\)

\(f(3) = 2.197\)

As a result, the app stοre's οwner prοjects that in its third year οf οperatiοn, there will be rοughly 2.197 milliοn app dοwnlοads.

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The value of the composite function is found as 68/5.

The function is given as;

g(x) = 32/(x+3)

Write the function as 'y'

y = 32/(x+3)

Replace the value of x with y.

x = 32/(y+3)

Solve for y.

x(y + 3) = 32

xy = 32 - 3x

y = (32 - 3x)/x

Thus, g⁻¹ (x) = (32 - 3x)/x is the inverse of the function.

Now, find the value composite function;  (g⁻¹ o g) (5).

(g⁻¹ o g) (5) =  (32 - 3x)/x . 32/(x+3)

Put x = 5

(g⁻¹ o g) (5) =  (32 - 15)/5 . 32/(5+3)

(g⁻¹ o g) (5) = 17×4/5

(g⁻¹ o g) (5) = 68/5

Thus, the value of the composite function is found as 68/5.

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To develop the Branch and Bound (B&B) tree for the given problem, follow these steps:

1. Start with the initial B&B tree, where the root node represents the original problem.

2. Choose \($x_1$\) as the branching variable at node 0. Add two child nodes: one for

\($x_1 \leq \lfloor x_1 \rfloor$ \\(floor of $x_1$) and one for $x_1 \geq \lceil x_1 \rceil$ (ceiling of $x_1$).\)

3. At each node, perform the following steps:

  - Solve the relaxed linear programming (LP) problem for the node, ignoring the integer constraints.

  - If the LP solution is infeasible or the objective value is lower than the current best solution, prune the node and its subtree.

  - If the LP solution is integer, update the current best solution if the objective value is higher.

  - If the LP solution is non-integer, choose the fractional variable with the largest absolute difference from its rounded value as the branching variable.

4. Repeat steps 2 and 3 for each unpruned node until all nodes have been processed.

5. The node with the highest objective value among the integer feasible solutions is the optimal solution.

6. Optionally, backtrace through the tree to retrieve the optimal solution variables.

Note: The specific LP problem and its constraints are missing from the given question, so adapt the steps accordingly.

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Answer:

question 1:  23.111.etc question 2: 7

Step-by-step explanation:

208/9=23.11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111112

question 2: 21/7=3 answer:7

To find the minimum population of Lake Norman, we need to determine the lowest value of the function that models its population, which is given by pt = 3000 sin(30t) + 6100.

To find the minimum population, we need to analyze the behavior of the function pt = 3000 sin(30t) + 6100. The function represents a sinusoidal pattern due to the presence of the sine function. The general form of a sine function is y = A sin(Bx + C) + D, where A represents the amplitude, B represents the frequency, C represents the phase shift, and D represents the vertical shift.

In this case, the amplitude is 3000, indicating the maximum deviation from the average population. The frequency is 30, representing how quickly the population oscillates over time. The vertical shift is 6100, indicating a baseline population value. By analyzing the function, we can determine that the minimum population occurs when the sine function reaches its lowest point.

The sine function has a minimum value of -1, which occurs at certain values of t. To find the minimum population, we need to solve the equation -1 = sin(30t). By solving for t, we can determine the corresponding value of the population. It's important to note that the specific time and corresponding population value will depend on the given range or constraints for t, such as the time frame of interest. By evaluating the sine function at the specific t value, we can find the minimum population of Lake Norman based on the given model.

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Answer:

74 + 76 = 150

Step-by-step explanation:

Given it's Even integers,  150/2 =75. Take the preceding and following even numbers. They are consecutive even numbers.

14 ft to 21 ft = 2 ft to 3 ft

In September, Mrs. Segars sold a total of 552 cups of coffee and pastries at the Star books cafe, earning a total of $667. By setting up a system of equations, we can determine that she sold 404 cups of coffee and 148 pastries during this period.

Let's assume that Mrs. Segars sold x cups of coffee and y pastries in September. According to the given information, the total number of cups of coffee and pastries sold is 552: x + y = 552.

The price of each cup of coffee is $1, and the price of each pastry is $2. The total revenue earned is $667, so we can set up another equation: 1x + 2y = 667.

To solve these equations, we can use substitution or elimination. Let's solve them using the substitution method. From the first equation, we can express x in terms of y: x = 552 - y.

Substituting this value of x into the second equation, we get: 1(552 - y) + 2y = 667.

Simplifying the equation gives us: 552 - y + 2y = 667.

Combining like terms, we have: 552 + y = 667.

By rearranging the equation, we find: y = 667 - 552.

Solving this, we get: y = 115.

Substituting the value of y back into the first equation, we find: x + 115 = 552.

Simplifying, we get: x = 552 - 115.

Thus, x = 437.

Therefore, Mrs. Segars sold 437 cups of coffee and 115 pastries in September at the Starbooks cafe.

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Answer: 5x + 6y

Step-by-step explanation:

Answer:

1.753 g

Step-by-step explanation:

Half life of Einsteinium = 20.5 days

Time elapsed = 31 days

Initial quantity of the substance = 5g

The formula to apply is;

\(N( t )=N_o( \frac{1}{2} )^{\frac{t}{t0.5} }\)

Where

N(t)=quantity of a substance remaining

No =Initial quantity of the substance = 5g

t= time elapsed=31 days

t1/2 = half life of the substance= 20.5 days

N(t)=5 * {1/2} ^ {31/20.5}

N{t} = 5 * {0.5}^1.5

N{t} = 5*0.3506

N{t} =1.753 g

Answer: t=15

Step-by-step explanation:

ST=9. BC=3

ST/BC=

9/3=3 ==> with this information, we can conclude that triangle ABC needs to be stretched by a scale factor of 3 in order to become triangle RST.

t=RS

RS=AB*3

RS=5*3

RS=15

t=15