mindy can type 40 words per minute. How many words can she type in 5 minutes?​

Answer:

23 + 16 = 39

39 - 16 = 23

the student did not reverse the sum correctly

40.13  percentage of the bottles contain less than 32 oz of soda.

Mean (μ) = 32.3 oz

Standard Deviation (σ) = 1.2 oz

Threshold value (X) = 32 oz

We can use the standard normal distribution (Z-distribution) to calculate the cumulative probability.

First, let's standardize the threshold value using the formula

Z = (X - μ) / σ

Z = (32 - 32.3) / 1.2 Z ≈ -0.25

Next, we'll look up the cumulative probability corresponding to Z = -0.25 in the standard normal distribution table or use a calculator.

From the standard normal distribution table or calculator, we find that the cumulative probability for

Z = -0.25 is approximately 0.4013.

This means that approximately 40.13% of bottles contain less than 32 oz of soda.

Therefore, about 40.13% of the bottles contain less than 32 oz of soda.

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Answer:

he is buying it for 11.25. you get this buy multiplying 15 by 25% which equals 3.75 then you subtract 15 by 3.75 and you get 11.25

hope it helps

please mark as brainliest

Step-by-step explanation:

Answer:

11.25$

Step-by-step explanation:

Answer:

216 degrees.

Step-by-step explanation:

put it through the formula and set the formula equal to 6/5 pi. then solve.

The roots of a function are the x-intercepts. By definition, the y-coordinate of points lying on the x-axis is zero. Therefore, to find the roots of a quadratic function, we set f (x) = 0, and solve the equation, ax2 + bx + c = 0.

Answer:

The roots of a function are the x-intercepts.

Step-by-step explanation:

The percentage increase in the price of bread is 50%. The percentage increase in the price of bread can be calc ulated by finding the difference between the new price and the old price, dividing it by the old price, and then multiplying by 100 to express it as a percentage.

In this case, the old price of bread is R12 and the new price is R18. To find the difference, we subtract the old price from the new price: R18 - R12 = R6.

Next, we divide the difference by the old price: R6 / R12 = 0.5.

Finally, we multiply the result by 100 to get the percentage: 0.5 * 100 = 50%.

Therefore, the percentage increase in the price of bread is 50%.

This means that the price of bread increased by 50% from R12 to R18. In other words, the new price is 50% higher than the old price. This percentage increase reflects the proportionate change in price. If the price had decreased, we would have calculated the percentage decrease using the same formula.

Understanding the percentage increase is useful for evaluating price changes, analyzing inflation rates, and comparing different price levels over time. It provides a standardized measure to express the magnitude of the change relative to the original value, making it easier to interpret and compare changes across different contexts.

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To determine whether the null (h₀) and alternative (h₁) hypotheses are set up correctly for a hypothesis test, we need to consider the specific pair of hypotheses provided.

Based on the information given, we cannot determine the exact hypotheses being referred to, as the question only mentions a drop-down menu. Therefore, we are unable to assess whether the hypotheses are valid or invalid. The question states that we need to decide whether the null (h₀) and alternative (h₁) hypotheses are correctly set up for a hypothesis test. However, the question does not provide any specific hypotheses or context to analyze.

Without knowing the specific pair of hypotheses, it is not possible to determine whether they are valid or invalid. It is important to have a clear understanding of the hypotheses being tested, the research question, and the desired outcome in order to assess the validity of the hypotheses.

In hypothesis testing, the null hypothesis typically represents the default or existing belief, while the alternative hypothesis represents the claim or new theory being tested. Without further information, it is not possible to determine the correctness of the hypotheses in question.

Without specific hypotheses provided, it is not possible to determine whether the null (h₀) and alternative (h₁) hypotheses are valid or invalid. It is crucial to have clear and specific hypotheses in order to conduct a hypothesis test and assess their validity.

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5x+9=2x+7+3x-15

0=17

7x+5x-7=21+10x

2x=28

x=14

24-3x=8+2x+16-x

-4x=0

~

answer:c

Answer:

in the picture

hope this helps! :D

Solution:

Simplify the inequality and solve.

The simplified inequality is 1 < k.

\( \sf20 < k + 19\)

Move the variable to the left-hand side and change its sign

\( \sf20 - k < 19\)

Move the constant to the right-hand side and change its sign

\( \sf \: - k < 19 - 20\)

Calculate the difference

\( \sf \: - k < - 1\)

Change the signs on both sides of the inequality and flip the inequality sign

\( \boxed{ \tt \: k > 1}\)

The expectation for a $1 bet on a U.S. roulette wheel for a 0 & 00 split is -$2. This means that you are expected to lose $2 for every $1 you bet.

The expected payout for a $1 bet on the 0 & 00 split in a U.S. roulette wheel is $0.45.

On a U.S. roulette wheel, there are 38 possible outcomes, consisting of the numbers 1 through 36, 0, and 00.

The 0 and 00 numbers are green, while all other numbers are either red or black.

Placing a $1 bet on the 0 & 00 split means that the bettor is betting that either the 0 or the 00 number will hit. If either of these numbers hits, the payout is 17 to 1, meaning the bettor will receive $17 for every $1 bet.

To calculate the expected payout for a $1 bet on the 0 & 00 split, we multiply the probability of winning (1/38) by the payout ($17), resulting in an expected payout of $0.447.

Therefore, the expected payout for a $1 bet on the 0 & 00 split is:

(1/38) × 17 × $1 = $0.447

Rounding this to the nearest cent, the expected payout for a $1 bet on the 0 & 00 split is $0.45.

Hence, the answer is $0.45.

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The difference quotient for the given function is 9 -2/h.

The difference quotient for the given function can be calculated as:

[f(x+h) - f(x)]/h

= [(3(x+h)² - 2(x+h) + 5) - (3x² - 2x + 5)]/h

= (3x² + 6xh + 3h² - 2x - 2h + 5 - 3x² + 2x - 5)/h

= (6xh + 3h² - 2h)/h

= (6x + 3h -2)/h

Simplifying the expression further, we get:

(6x + 3h -2)/h = 6 + 3h/h -2/h

= 6 + 3 -2/h

= 9-2/h

Therefore, the difference quotient for the given function is 9 -2/h.

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"Your question is incomplete, probably the complete question/missing part is:"

Find the difference quotient [f(x+h)-f(x)]/h, where h≠0, for the function below.

f(x)=3x² -2x+5. Simplify your answer as much as possible.

Hi! So what you will need to know is pythagorean theorm.

What the theorm basically says is a^2 + b^2 = c^2.

-- The (a,b,c) are referring to the sides of the triangles (3 letters for 3 sides).

Take note that "c" is always the side opposite of the right angle.

The other known side could be "a" or "b"

Taking a look at problem 9, identify the "c" value. The "c" value would be 35.

Then indentify the value of "b" or "a". "a" would = 20.

Plug it into the equation:

20^2 + b^2 = 35^2

400 + b^2 = 1225

solve for b.

1. subtract 400 from both sides.

b^2 = 825

b = \(\sqrt{825}\)

you could solve for the square root but it would give a decimal numbers but I'm not sure what the teacher is looking for.

Answer:

(See below)

Step-by-step explanation:

m<1 = 180-130= 50 degrees

because <1 and the 130 degree angle are a linear pair so they are supplementary

m<2 = 50 degrees

because <1 and <2 are alternate interior angles so they are congruent

The NPV of the CBCS project, using an 8% discount rate, is. \(\$21,646.77.\)

Financial value proposition of CBCS:

The financial value proposition of CBCS is based on several factors:

Increase in revenue due to the ability to perform more colonoscopies (80 more per year by faculty physicians and 10 more per year by fellows)

Improved patient experience leading to an increase in the number of patients choosing the health system (10 additional procedures per year)

Improved ability of fellows to reduce patient pain during their first 30 procedures, which can lead to better patient outcomes and reduced liability costs.

Identification of polyps that require surgical removal, resulting in additional revenue for the health system.

Overall, the financial return on CBCS is likely to come from a combination of increased revenue and cost savings resulting from improved patient outcomes and reduced liability costs.

Financial analysis in Excel:

Please see attached Excel file for the financial analysis.

IRR calculation:

The IRR of the CBCS project is 23.2%.

Payback period calculation:

The payback period of the CBCS project is 2.6 years.

CBCS project is 2.6 years.

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Answer:

(A²-B²)= 4 0

-4 4

|A²-B²|= (4*4)-(-4*0)= 16

To find the area of a verandah 1 m wide constructed outside a room 5.5 m long and 4 m wide.

The area of the verandah is 45.5 m².

We need to find the area of the overall rectangular structure (room + verandah) and subtract the area of the room.

Area of the overall rectangular structure = (length + 2 × width) × (width + 1)

Area of the room = length × width

Area of the verandah = Area of the overall rectangular structure - Area of the room.

Given, Length of the room = 5.5 m

the Width of the room = 4 m

Width of the verandah = 1 m.

Area of the overall rectangular structure = (length + 2 × width) × (width + 1)

= (5.5 + 2 × 4) × (4 + 1)

= 13.5 × 5

= 67.5 m²

Area of the room = length × width

= 5.5 × 4

= 22 m²

Area of the verandah = Area of the overall rectangular structure - Area of the room

= 67.5 - 22

= 45.5 m²

Therefore, the area of the verandah is 45.5 m².

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Answer:

1407 feet per mile

Step-by-step explanation:

Each mile is 1407 feet.

Designing complex transistor-degree circuits calls for information in circuit layout methodologies, gear, and precise generation parameters

I can offer you a few general records and steps for designing a transistor-level schematic and layout for the given logic characteristic.

A) Transistor-degree schematic and layout:

To lay out a transistor-level schematic and format for the common sense feature Y=ABC+AD, you will generally use primary logic gates which include NAND and NOR gates composed of transistors. You can comply with these steps:

It is crucial to observe that designing a complete transistor-level schematic and format requires a deep understanding of circuit layout concepts and equipment precise to the era you're operating with.

B) Truth desk of the good judgment function Y:

To find the fact table for the good judgment function Y=ABC+AD, you would list all feasible enter mixtures for A, B, C, and D and evaluate the output Y for every aggregate. The reality desk will display the relationship between the inputs and the ensuing output Y.

C) Sizes of transistors:

To determine the sizes of transistors, you will want extra records which include the generation parameters, transistor fashions, and particular layout requirements. The sizes of transistors are normally determined via a manner known as transistor sizing, where the dimensions of the transistors are adjusted to fulfill specific performance targets together with pace, energy, and place.

The parameters you stated, n=4 and μ0​Cax​=430μA/\(V2\), represent the brink ratio (n) and the early voltage (μ\(0\)Cax​) for a basic inverter. However, they do now not provide sufficient statistics to decide the sizes of transistors for the given logic function.

Designing complex transistor-degree circuits calls for information in circuit layout methodologies, gear, and precise generation parameters. It is suggested to consult specialized software equipment and reference substances or paintings with skilled circuit designers to correct the layout and optimize the circuit.

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Total stockholders’ equity 7,800,000

Statement of stockholders’ equity for CC for the year ended December 31, 2012:Particulars Amount ($)
Common Stock 100,000

Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
Total stockholders’ equity 7,800,000

Explanation:The given information is as follows:Common Stock on January 1, 2012 = $100,000Additional Paid-in Capital on January 1, 2012 = $4,100,000

Retained Earnings on January 1, 2012 = $3,000,000Net Income for the year ended December 31, 2012 = $800,000Cash Dividend Declared on July 1 and paid on July 31 = $200,000

To prepare the statement of stockholders’ equity for the year ended December 31, 2012, we will begin by preparing the opening balances of each of the equity accounts. We will then add the net income to the retained earnings account.

The closing balance for retained earnings is then computed by subtracting the cash dividend declared and paid from the total retained earnings. Finally, the total stockholders' equity is calculated by adding the balances of all the equity accounts.

Calculations:Opening balance of common stock = $100,000

Opening balance of additional paid-in capital = $4,100,000

Opening balance of retained earnings = $3,000,000

Net Income for the year ended December 31, 2012 = $800,000

Retained earnings (Opening Balance) = $3,000,000

Add: Net Income for the year ended December 31, 2012 = $800,000

Total retained earnings = $3,800,000Less: Cash Dividend Declared on July 1 and paid on July 31 = $200,000Retained earnings (Closing balance) = $3,600,000

Total stockholders’ equity = Common Stock + Additional Paid-in Capital + Retained Earnings (Closing balance) = $100,000 + $4,100,000 + $3,600,000 = $7,800,000

Therefore, the statement of stockholders’ equity for CC for the year ended December 31, 2012, is as follows:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000

Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
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The rate at which the distance between the top of the ladder and the ground at that instant is decreasing at 42 meters per minute.

Given length of ladder 39 m and the rate at which the wall is increasing is 101, the bottom of the ladder is 36 m from the wall.

Let bottom is x and the length of wall be y.

We have to find the rate at which the distance between the top of the ladder and the ground at that instant.

we have to find dy/dt.

We have to apply pythagoras theorem first.

\(x^{2} +y^{2} =39^{2}\)---------------1

\(x^{2} +y^{2} =1521\)

put the value of x=36 in the above equation

\(36^{2} +y^{2} =1521\)

\(y^{2} =225\)

y=15 m

We have to find the derivative of equation 1 with respect to t.

2x*dx/dt+2y*dy/dt=0

Because it is given that bottom is increasing at 101 meters per minute so dx/dt=101

2x*101+2y*dy/dt=0

put the value of y=15

2x*101+2*15*dy/dt=0

2x*101+2*15*dy/dt=0

dy/dt=-3030/2*36

dy/dt=-42.08

Hence the rate at which the rate at which the top of the ladder and the ground at that instant is decreasing at 42 meters per minute.

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Question is wrong so it includes ladder length be 39 meters and the rate of increasing of bottom of ladder from bottom of wall is 101 meters per minute and the bottomis 36 m from the wall.

Answer:

Factor form: (2x-5)(2x+5)

If you olny simplify: 8x-25

Step-by-step explanation:

Answer:Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral

Step-by-step explanation:

Answer:

8:1

Step-by-step explanation:

a. No, w is not in fv1; v2; v3g. There are three vectors in fv1; v2; v3g.

b. There are three vectors in the span of fv1; v2; v3g.

c. No, w is not in the subspace spanned by fv1; v2; v3g. This is because the subspace is the set of all linear combinations of the vectors in the span, and w does not have to be a linear combination of the vectors in the span.

To prove this, we first need to recall the definition of the span: it is the set of all linear combinations of a set of vectors. A linear combination is a sum of the vectors, multiplied by constants. For example, if we have a vector v1, and two constants a and b, then the linear combination of a*v1 and b*v1 is (a + b)*v1. If a vector w is not a linear combination of v1, then w is not in the span of v1.

The same logic applies to the vectors fv1; v2; v3g. If w is not a linear combination of these three vectors, then w is not in the subspace spanned by these three vectors. We can prove this by showing that w cannot be a linear combination of fv1; v2; v3g. This is because the only way to create a linear combination of these vectors is to multiply them by constants, and since w is not one of the vectors, it cannot be multiplied by a constant. Therefore, w is not in the subspace spanned by fv1; v2; v3g.

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Dοmain is x is all real numbers where x dοes nοt equal -2.

Range is y is all real numbers where y dοes nοt equal -8.

In mathematics, the dοmain οf a functiοn is the set οf all pοssible input values (οften represented by the variable x) fοr which the functiοn is defined. It is the set οf all numbers οr values that can be plugged intο the functiοn tο prοduce a valid οutput.

The given functiοn is:

\($ f(x) = (x^2 - 4x - 12)/(x + 2)\)

Tο find the dοmain, we need tο cοnsider the values οf x that make the denοminatοr zerο, as divisiοn by zerο is undefined. Here, x + 2 = 0 gives x = -2, sο x cannοt be -2. Therefοre, the dοmain οf the functiοn is all real numbers except -2. That is,

Dοmain: x ≠ -2

Tο find the range, we can analyse the behaviοr οf the functiοn as x apprοaches pοsitive οr negative infinity. When x is very large (either pοsitive οr negative), the highest pοwer term dοminates, sο the functiοn behaves like  \(f(x) \approx x^2/x = x.\)

Therefοre, as x apprοaches pοsitive infinity οr negative infinity, f(x) apprοaches pοsitive infinity οr negative infinity respectively. Thus, the range οf the functiοn is all real numbers except fοr the value f(-2) = -8 (which is nοt in the dοmain). Therefοre,

Range: y ≠ -8

Sο the cοrrect answer is: dοmain is x is all real numbers where x dοes nοt equal negative 2, and range is y is all real numbers where y dοes nοt equal negative 8.

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Answer:

20 days

Step-by-step explanation:

cuz i am big brain thats y

Answer:

20 days

Step-by-step explanation:

1/4 times 5

Given the equation

Subtract 3 from both sides

Divide both sides by 3

Raise both sides to power 5 to remove the 5th root on the left hand side

Take the cube root of both sides

Subtract 2 from both sides

x + 2 = 32

x = 32 - 2

x = 30

The solution to the equation is x = 30

a. The probability of drawing a red ball from Box 1 is 30%.

b. If a red ball is drawn from Box 1, the probability of drawing another red ball from Box 2 on the second round is 60%.

c. If the first draw from Box 1 was black, the conditional probability of drawing a red ball from Box 3 on the second draw is 80%.

d. The probability of drawing two red balls at both draws, without any prior information, is 46%.

e. The probability of drawing a red ball at the first draw and a black ball at the second draw, without any prior information, is 21%.

a. The probability of drawing a red ball from Box 1 can be calculated by dividing the number of red balls in Box 1 by the total number of balls in Box 1. Therefore, the probability is 3/(3+7) = 3/10 = 0.3 or 30%.

b. Since a red ball was drawn from Box 1, we only consider the balls in Box 2. The probability of drawing a red ball from Box 2 is 6/(6+4) = 6/10 = 0.6 or 60%. Therefore, the probability of drawing another red ball when the first ball drawn from Box 1 is red is 60%.

c. If the first draw from Box 1 was black, we only consider the balls in Box 3. The probability of drawing a red ball from Box 3 is 8/(8+2) = 8/10 = 0.8 or 80%. Therefore, the conditional probability of drawing a red ball from Box 3 when the first ball drawn from Box 1 was black is 80%.

d. Before any draws, the probability of drawing two red balls at both draws can be calculated by multiplying the probabilities of drawing a red ball from Box 1 and a red ball from Box 2. Therefore, the probability is 0.3 * 0.6 = 0.18 or 18%. However, since there are two possible scenarios (drawing red balls from Box 1 and Box 2, or drawing red balls from Box 2 and Box 1), we double the probability to obtain 36%. Adding the individual probabilities of each scenario gives a total probability of 36% + 10% = 46%.

e. Before any draws, the probability of drawing a red ball at the first draw and a black ball at the second draw can be calculated by multiplying the probability of drawing a red ball from Box 1 and the probability of drawing a black ball from Box 2 or Box 3. The probability of drawing a red ball from Box 1 is 0.3, and the probability of drawing a black ball from Box 2 or Box 3 is (7/10) + (2/10) = 0.9. Therefore, the probability is 0.3 * 0.9 = 0.27 or 27%. However, since there are two possible scenarios (drawing a red ball from Box 1 and a black ball from Box 2 or drawing a red ball from Box 1 and a black ball from Box 3), we double the probability to obtain 54%. Adding the individual probabilities of each scenario gives a total probability of 54% + 10% = 64%.

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