Minimize a firms total costs, C = 45X^2+90XY=90Y^2 When the firm has to meet a production quota equal to 2X+3Y=60 by
A. Finding the critical values

Answer: 2500

Step-by-step explanation: If you calculate out 5x6 that equals 30 and 5x5-5 equals 20, when you do 30+20 that equals 50 and 50 to the 2nd power is 50x50 and that would equal 2500

Answer:

0 < A < 90

0 < C < 90

Step-by-step explanation:

If B is the right angle of the triangle, then the sum of the other angles, A and C, must equate 90° since all angles in a triangle sum to 180°:

A + C = 90

A and C could both be anything between 0 and 90, but they must satisfy the equation above:

0 < A < 90

0 < C < 90

Answer:

(f ￮ g)(x) = x²

Step-by-step explanation:

to find (f ￮ g)(x) , substitute x = g(x) into f(x)

(f ￮ g)(x)

= f(g(x) )

= f(x² + 2)

= x² + 2 - 2

= x²

Answer:

1.2 (the 2 continuing on)

Step-by-step explanation:

Just divide the numerator by the denominator and you'll get your answer

Answer:

Step-by-step explanation:

As the slope between (1,0) and (2,2) is 2 and the slope between (2,2) and (4,4) is 1, we can tell that the parabola must be downward opening and have a vertex in the first quadrant

Possibly best to use the vertex form to make 3 equations with 3 unknowns

y = a(x - h)² + k

0 = a(1 - h)² + k  (i)

2 = a(2- h)² + k  (ii)

4 = a(4 - h)² + k  (iii)

subtract i from ii

2 = a((2 - h)² - (1 - h)²)

2 = a(4 - 4h + h² - (1 - 2h + h²))

2 = a(3 - 2h)

a = 2/(3 - 2h)

subtract i  from iii

4 = a((4 - h)² - (1 - h)²)

4 = a(16 - 8h + h² - (1 - 2h + h²))

4 = a(15 - 6h)

substitute for a

4 = (2/(3 - 2h))(15 - 6h)

4(3 - 2h) = 2(15 - 6h)

12 - 8h = 30 - 12h

4h = 18

h = 9/2

a = 2/(3 - 2(9/2))

a = - 1/3

0 = -1/3(1 - 9/2)² + k

k = 49/12

y = (-1/3)(x - 9/2)² + 49/12

expand to get y = ax² + bx + c form

y = (-1/3)(x² - 9x + 81/4) + 49/12

y = (-1/3)x² + 3x - 27/4) + 49/12

y = (-1/3)x² + 3x - 8/3

The slope, y-intercept and the equation of the following graph are as follows:

1(a)

slope : 1

y-intercept: 2

Equation: y = x + 2

(b)

slope : -  1 / 3

y-intercept: - 1

Equation: y = - 1 / 3x - 1

2.

(a)

slope : 3 / 4

y-intercept: 5 / 4

Equation: y = 3 / 4 x + 5 / 4

(b)

slope : - 3 / 2

y-intercept: 1 / 2

Equation: y = - 3 / 2 x + 1 / 2  

where

m = slope

b = y-intercept

Therefore lets find the slope, y-intercept and equation of the following graph.

1.

(a)

(0, 2)(1, 3)

m = 3 - 2 / 1 - 0 = 1

b = 2

y = x + 2

(b)

(0, -1)(-3, 0)

m = 0 + 1 / -3 - 0 = - 1 / 3

b = -1

y = - 1 / 3x - 1

2.

(a)

(1, 2)(-3, -1)

m = -1 - 2 / -3 - 1 = 3 / 4

2 = 3 / 4 (1) + b

b = 2 - 3 / 4  = 5 / 4

y = 3 / 4 x + 5 / 4

3.

(b)

(-3, 5)(1, -1)

m = - 1 - 5 / 1 + 3 = - 6 / 4 = - 3 / 2

-1 = - 3 /2 (1) + b

b = -1 + 3 / 2 = 1 /2

y = - 3 / 2 x + 1 / 2  

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Answer:

y + 5 = -1 (x - 1)

Step-by-step explanation:

y = -1

y + 5 = -1 (x - 1)

Answer:

b. (4×12)+(3×7)

48+21= 69

she spent $69

Answer:

well I can answer b the shape here is a 3D  Hexagonal pyramid

We have a phone service fee which can be divided in:

- A fixed fee of $19 per month.

- A variable fee of $0.04 per minute, so that the cost for m minutes is 0.04*m.

We can add the two fees to express the total cost in function of the minutes as:

For a month where the cost is C(m) = 70.28, we can calculate the minutes as:

Answer: if she pays at least $70.28, she has talked at least m = 1282 minutes per month.

(∀x)P(x) can be written as p ∧ q, (Ǝx)P(x) can be written as ¬p ∨ ¬q, and the universal and existential negation rules of predicate logic correspond to the DeMorgan's law of propositional logic, which states that ¬(p ∨ q) = ¬p ∧ ¬q.

a) The statement (∀x)P(x) states that P(x) is true for all x in the domain, which consists of just 0 and 1. So, if P(0) is true, represented by p, and P(1) is true, represented by q, then (∀x)P(x) is true. Therefore, (∀x)P(x) can be written as p ∧ q.

b) The statement (Ǝx)P(x) states that P(x) is true for at least one x in the domain, which consists of just 0 and 1. So, if either P(0) is true, represented by p, or P(1) is true, represented by q, then (Ǝx)P(x) is true. Therefore, (Ǝx)P(x) can be written as p ∨ q.

c) The negation of (∀x)P(x), represented as ¬(∀x)P(x), is equivalent to the negation of (∀x)P(x) in predicate logic, represented as (Ǝx)¬P(x). This corresponds to DeMorgan's law of propositional logic, which states that ¬(p ∧ q) = ¬p ∨ ¬q.

Similarly, the negation of (Ǝx)P(x), represented as ¬(Ǝx)P(x), is equivalent to the negation of (Ǝx)P(x) in predicate logic, represented as (∀x)¬P(x). This corresponds to DeMorgan's law of propositional logic, which states that ¬(p ∨ q) = ¬p ∧ ¬q.

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The average rate of change of the function over the interval is -6

From the question, we have the following parameters that can be used in our computation:

The graph

The interval is given as

From x = 2 to x = 4

The function is a quadratic function

This means that it does not have a constant average rate of change

So, we have

f(2) = -3

f(4) = -15

Next, we have

Rate = (-15 + 3)/(4 - 2)

Evaluate

Rate = -6

Hence, the rate is -6

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Thus, an equation to show the overall price y of renting shoes and bowling x equipment is: y=4x+b.

The task is to create an equation that use the total expense (y) and the total number of bowled games (x). Hence, the way that we will begin is by entering the knowing into the formula of slope intercept form:  y=mx+b.

Thus, we include them in the formula: y=4x+b.

14 = 4(3)+b

Find b

14 = 12+b

14 - 12=b

b = 2

Thus, an equation to show the overall price y of renting shoes and bowling x equipment is: y=4x+b.

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Complete question:

The total cost for bowling includes the fee for shoe rental plus a fee per game. The cost of the game increases the price by $4. After 3 games, the total cost with shoe rental is $14.

a.write an equation to represent the total cost y to rent shoes and bowl x games.

Answer:

x = 27 , ∠ EAF = 27°

Step-by-step explanation:

∠ GAF = 90° , then

∠ GAC + ∠ CAF = ∠ GAF , that is

x + 63 = 90 ( subtract 63 from both sides )

x = 27

∠ DAE = 90°

since CD is a straight angle of 180° , then

∠ CAE = 90° , so

∠ CAF + ∠ EAF = ∠ CAE , that is

63° + ∠ EAF = 90° ( subtract 63° from both sides )

∠ EAF = 27°

Answer:

Hence, 6 = 3 ans.

Step-by-step explanation:

hope it's help

Answer:To show that Lorenz curves are always concave up on the interval [0, 1], we can use the definition of a Lorenz curve, which is L(x) = xp. Taking the second derivative of L(x) with respect to x gives us L''(x) = p. Since p is always greater than 0, L''(x) is always greater than 0. This means that L(x) is always concave up on the interval [0, 1].

Table of Lorenz values for p = 1.2, 1.5, 2.1, 2.5, 3, and 5:

a. The value of p that corresponds to the most equitable distribution of wealth is 1, as this would mean that the proportion of wealth held by each portion of the population is equal.

b. The value of p that corresponds to the least equitable distribution of wealth is 5, as this would mean that a small portion of the population holds a large proportion of the wealth.

The Gini Index is a measure of income inequality, where a value of 0 represents perfect equality (everyone has the same income) and a value of 1 represents perfect inequality (one person has all the income). The Gini Index is calculated as the ratio of the area between the Lorenz curve and the line of equality to the total area beneath the line of equality.

To find A and B for the Gini index we can use the following integral:

A = ∫(L(x) - x) dx from 0 to 1

B = ∫(x - L(x)) dx from 0 to 1

We can then solve the integral for each specific function of L(x) = xp to find the specific value of A and B.

Step-by-step explanation:

Answer:....

Step-by-step explanation:

Number 1.

\(5^x=2\), first we will take the \(log\) of both of these numbers getting us,

\(x=\frac{log(2)}{log(5)}\), which then gives us that \(x=0.4306777777....\)

Number 2

\(e^x=10\), solve for our exponent, \(2.718282^x=10\), use the logarithmic formula, and we get,

\(x=\frac{log(10)}{log(2.718282)}\), which then we get that \(x=2.302585\)

Answer:

y'=|x-5|-1

Step-by-step explanation:

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Answer:

I don't know what you think about it is not going to be a great day of school and I don't know what you think about it is not going to be a great day of school

Answer:

i actually dont know im sorry

Answer:

\(BC=5.1\)

\(B=23^{\circ}\)

\(C=116^{\circ}\)

Step-by-step explanation:

The diagram shows triangle ABC, with two side measures and the included angle.

To find the measure of the third side, we can use the Law of Cosines.

\(\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines} \\\\$c^2=a^2+b^2-2ab \cos C$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}\)

In this case, A is the angle, and BC is the side opposite angle A, so:

\(BC^2=AB^2+AC^2-2(AB)(AC) \cos A\)

Substitute the given side lengths and angle in the formula, and solve for BC:

\(BC^2=7^2+3^2-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-42\cos 41^{\circ}\)

\(BC^2=58-42\cos 41^{\circ}\)

\(BC=\sqrt{58-42\cos 41^{\circ}}\)

\(BC=5.12856682...\)

\(BC=5.1\; \sf (nearest\;tenth)\)

Now we have the length of all three sides of the triangle and one of the interior angles, we can use the Law of Sines to find the measures of angles B and C.

\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c} $\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)

In this case, side BC is opposite angle A, side AC is opposite angle B, and side AB is opposite angle C. Therefore:

\(\dfrac{\sin A}{BC}=\dfrac{\sin B}{AC}=\dfrac{\sin C}{AB}\)

Substitute the values of the sides and angle A into the formula and solve for the remaining angles.

\(\dfrac{\sin 41^{\circ}}{5.12856682...}=\dfrac{\sin B}{3}=\dfrac{\sin C}{7}\)

Therefore:

\(\dfrac{\sin B}{3}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin B=\dfrac{3\sin 41^{\circ}}{5.12856682...}\)

\(B=\sin^{-1}\left(\dfrac{3\sin 41^{\circ}}{5.12856682...}\right)\)

\(B=22.5672442...^{\circ}\)

\(B=23^{\circ}\)

From the diagram, we can see that angle C is obtuse (it measures more than 90° but less than 180°). Therefore, we need to use sin(180° - C):

\(\dfrac{\sin (180^{\circ}-C)}{7}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin (180^{\circ}-C)=\dfrac{7\sin 41^{\circ}}{5.12856682...}\)

\(180^{\circ}-C=\sin^{-1}\left(\dfrac{7\sin 41^{\circ}}{5.12856682...}\right)\)

\(180^{\circ}-C=63.5672442...^{\circ}\)

\(C=180^{\circ}-63.5672442...^{\circ}\)

\(C=116.432755...^{\circ}\)

\(C=116^{\circ}\)

\(\hrulefill\)

Additional notes:

I have used the exact measure of side BC in my calculations for angles B and C. However, the results will be the same (when rounded to the nearest degree), if you use the rounded measure of BC in your angle calculations.

Answer:

m=-9+n

Step-by-step explanation:

you want to get m by itself so you subtract 9 on both sides. 9-9 crosses out and you get m by itself. Which leads you to m= -9+n

Answer:

B. 3/4

Step-by-step explanation:

6/8=0.75

Answer: B

Step-by-step explanation:

6 = 8

3 = 4

1.5 = 2

0.75 = 1

Hope this helps!

By using Pythagoras theorem we get the height of the roof of dog house is 21 inches.

The Pythagoras theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. 

This theorem is named after the Greek philosopher Pythagoras, who lived around 570 BC. born. 

According to the question:

Given, Hypotenuse(h) = 29 inches

           Base(b) = 40/2 = 20 inches

Using Pythagoras theorem, we get

h² = b² + p²

⇒ 29² = 20² + p²

⇒ p² = 29² - 20²

⇒ p² = 841 - 400

⇒ p² = 441

⇒ p = √441

⇒ p = 21

∴ The height of the roof of dog house is 21 inches.

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Answer:

the value of x that makes the equation true is x = 3.5.

Step-by-step explanation:

To find the value of x that makes the equation 18x + 5 - 3 = 65 true, we need to simplify the equation and solve for x.

Starting with the equation:

18x + 5 - 3 = 65

First, combine like terms:

18x + 2 = 65

Next, isolate the term with x by subtracting 2 from both sides:

18x = 65 - 2

18x = 63

Finally, divide both sides of the equation by 18 to solve for x:

x = 63 / 18

x = 3.5

Therefore, the value of x that makes the equation true is x = 3.5.

The answer is:

Steps & work :

First, I focus only on the left side.

Combine like terms:

\(\sf{18x+5-3=65}\)

\(\sf{18x+2=65}\)

Subtract 2 from each side:

\(\sf{18x=63}\)

Now, divide each side by 18:

\(\sf{x=\dfrac{63}{18}\)

Clearly, this fraction is not in its simplest terms, and we can divide the top and bottom by 9:

\(\sf{x=\dfrac{7}{2}}\)

\(\therefore\:\:\:\:\:\:\stackrel{\bf{answer}}{\boxed{\boxed{\tt{x=\frac{7}{2}}}}}}\)

Answer:

5643

Step-by-step explanation:

you add them together then you divide  

As a result, option two (3.50) is correct.

Step-by-step explanation:                                                    
                                   
The code chunk that allows you to filter the data frame for chocolate bars with at least 70% cocoa and a rating of at least 3.5 pounds is as follows

∴ filter(Cocoa, percent>='70%'&Rating>=3.5)


Therefore, the code you write is facet wrap(Cocoa. Percent). Facet wrap() is a function in this code chunk that allows you to wrap a variable's facets. All of the ingredients are derived from cocoa beans. Cacao solids (the "brown" part, which contains health benefits and the unmistakable chocolatey flavor) and cacao butter (the "white" part, which contains the chocolate's fatty component) are split in proportion.


As a result, 3.5 appears in row 1 of your Tibble.

Other options I (iii), and (iv) are incorrect because the question states that any rating greater than or equal to 3.5 points can be considered a
high rating, and the rating here should be 3.5, not 3.75, 4.25, or 4

So, option (ii) is correct.  


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Answer:

C

Step-by-step explanation:

FUNCTION A

21 : 7 = 3

FUNCTION B

8: 4 = 2

3 is greater than 2