Name Period 7. When wave reflection occurs, the incoming wave approaching the barrier is called what? a. Incident wave b. Transverse wove c. Reflected wave d. Refracted wave 8. Which wave interaction

Answer:

Heroin

Explanation:

it can be smoked or injected and causes feelings of "euphoria"

Answer:

Explanation:

i just submitted the assignment ill let you know how i do

Answer:

Explanation:

Added arrows and chlorophyll to the plant.

Burn victims have experienced reduced levels of pain thanks to the distraction of virtual reality games.

The use of virtual reality (VR) technology as a therapeutic tool has been shown to reduce pain and divert patients during procedures or as part of a pain management routine. This includes those who have suffered burns, who frequently require prolonged and uncomfortable therapies while they recuperate.

Burn patients might divert their focus from their suffering by submerging themselves in virtual reality games or simulations. Virtual reality's captivating and interactive features can successfully divert their attention and relieve their suffering.

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Answer:

The speed of the student just before she lands, v₂ is approximately 8.225 m/s

Explanation:

The given parameters are;

The mass of the physic student, m = 43.0 kg

The height at which the student is standing, h = 12.0 m

The radius of the wheel, r = 0.300 m

The moment of inertia of the wheel, I = 9.60 kg·m²

The initial potential energy of the female student, P.E.₁ = m·g·h₁

Where;

m = 43.0 kg

g = The acceleration due to gravity ≈ 9.81 m/s²

h = 12.0 h

∴ P.E.₁ = 43 kg × 9.81 m/s² × 12.0 m = 5061.96 J

The kinetic rotational energy of the wheel and kinetic energy of the student supporting herself from the rope she grabs and steps off the roof, K₁, is given as follows;

\(K_1 = \dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2\)

The initial kinetic energy, 1/2·m·v₁² and the initial kinetic rotational energy, 1/2·m·ω₁² are 0

∴ K₁ = 0 + 0 = 0

The final potential energy of the student when lands. P.E.₂ = m·g·h₂ = 0

Where;

h₂ = 0 m

The final kinetic energy, K₂, of the wheel and student is give as follows;

\(K_2 = \dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2\)

Where;

v₂ = The speed of the student just before she lands

ω₂ = The angular velocity of the wheel just before she lands

By the conservation of energy, we have;

P.E.₁ + K₁ = P.E.₂ + K₂

∴ m·g·h₁ + \(\dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2\) = m·g·h₂ + \(\dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2\)

Where;

ω₂ = v₂/r

∴ 5061.96 J + 0 = 0 + \(\dfrac{1}{2} \times 43.0 \, kg \times v_{2}^2+\dfrac{1}{2} \times 9.60 \, kg\cdot m^2 \cdot \left (\dfrac{v_2}{0.300 \, m} }\right ) ^2\)

5,061.96 J = 21.5 kg × v₂² + 53.\(\overline 3\) kg × v₂² = 21.5 kg × v₂² + 160/3 kg × v₂²

v₂² = 5,061.96 J/(21.5 kg + 160/3 kg) ≈ 67.643118 m²/s²

v₂ ≈ √(67.643118 m²/s²) ≈ 8.22454363 m/s

The speed of the student just before she lands, v₂ ≈ 8.225 m/s.

Answer:

the correct answer is D

Explanation:

The velocity of the second ball that was hit by a ball of mass 2.5 kg moving with an initial velocity of 5 m/s is 5 m/s.

Velocity can be defined as the rate of change of displacement.

To calculate the velocity of the second ball after collision, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for V

Hence, the velocity of the second ball is 5 m/s.

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From aliens perspective, Earth would be an  exoplanet in English language.

Any planet outside of our solar system is an exoplanet. The majority of exoplanets orbit other stars, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic centre.

The majority of the exoplanets found so far are in the Milky Way, which is a rather tiny area of our galaxy. The Kepler Space Telescope of NASA has revealed that the galaxy has more planets than stars.

We can determine the sizes (diameters) and weights (weights) of exoplanets and determine their compositions, which range from extremely stony (like Venus and Earth) to extremely gas-rich (like Jupiter and Saturn). Exoplanets contain elements that are comparable to those found in our solar system, but their compositions of those elements may vary.

If aliens arrived on earth. Earth would be considered an exoplanet in the language of them.

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The high power objective on a microscope is used to provide a higher level of magnification for the detailed examination of specimens.

The high-power objective is one of the multiple objective lenses found on a microscope. It typically has a higher magnification power, often ranging from 40x to 100x or more. When the high-power objective is selected, it brings the specimen into sharp focus at a closer distance. This allows for the observation of finer details and structures that may not be visible with lower magnification objectives. However, higher magnification also means a smaller field of view and reduced depth of field. To compensate for this, a fine adjustment knob is often used to precisely focus the image. The high-power objective is commonly used in advanced biological and medical research, as well as in educational settings where a more detailed examination of microscopic specimens is required.

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Answer:

here's the answer to your question

Answer:

Force.

Explanation:

SImple as that. think of Newtons Laws.

Answer:

number 2

Explanation:

the 2 one is right

There is no clear trend in the density with mass or distance in trend Jovian planet densities with mass or distance from the sun.

The substance's mass per unit of volume is its density (also known as specific mass or volumetric mass density). The Latin letter D can also be used to represent density, however the most common symbol is (the lower case Greek letter rho). Mass divided by volume is the mathematical definition of density.

The word "specific volume," which is infrequently used in thermodynamics, refers to the reciprocal of a substance's density. A substance's density is an intense attribute in that its mass grows rather than its density when its amount is increased where denotes density, m denotes mass, and V denotes volume. Density is occasionally roughly described as something's weight per unit

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The radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.

The radius of the event horizon of a black hole is known as the Schwarzschild radius and it is a function of the mass of the black hole. The Schwarzschild radius is given by the formula:

r = 2GM/c^2

where

r = radius of the event horizon (in meters)

G = gravitational constant (6.674 x 10^-11 N*(m/kg)^2)

M = mass of the black hole (in kg)

c = speed of light in a vacuum (2.998 x 10^8 m/s)

For a 10-Solar-mass black hole, we can use the mass conversion factor 1 Solar mass = 1.989 x 10^30 kg.

M = 10 x 1.989 x 10^30 kg

Now, we can substitute the values into the formula

r = 2 x 6.674 x 10^-11 x M/ (2.998 x 10^8)^2

r = 2GM/c^2 = 2 x 6.674 x 10^-11 x (10 x 1.989 x 10^30) / (2.998 x 10^8)^2

r = 2.95 x 10^3 m = 2950 kilometers

So, the radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.

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Answer: A.

Explanation:

took the test just now

A battery supplies electrical energy to a circuit Chemical reactions in a battery cause positively and negatively charged particles to separate and become concentrated at the battery terminals. The correct option is A.

A chemical reaction is a process in which one or more substances, also known as reactants are converted to one or more different substances, known as products. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products

Chemical reactions in a battery cause positively and negatively charged particles to separate and become concentrated at the battery terminals resulting in the transformation into electrical energy therefore the correct option is A.

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Answer:The answer is C: any fundamental force

Explanation:

A P E X

In this situation, both balls will exert electrostatic force on each other in the first example.

Part b)

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Complete question : Two identical metal balls are suspended by insulating threads. Both balls have the same net charge. In this problem, do not assume the balls are point charges. a. Draw a separate free-body diagram for each ball. Label the forces to indicate: - the object exerting the force, - the object on which the force is exerted, - the type of force (gravitational, normal, etc.), and - whether the force is a contact or a noncontact force. b. Suppose the charge on the second ball is reduced slightly, so that it is less than that on the first ball. Predict whether the angle that ball l makes with the vertical will be greater than, less than, or equal to the angle that ball 2 makes with the vertical. Explain. Sketch your answer above. Name Ball I Ball 2 Free-body diagram Free-body diagram for ball I for ball 2 - - Ball I Ball 2 How does the free-body diagram for each ball in this case compare to the corresponding freebody diagram that you drew in part a

Answer:

no way I had that question too :-O anyways here's the answer

Explanation:

willow ptarmigan and Walia ibex

Answer:

The answer is 3

Explanation:

An anechoic chamber (an-echoic meaning "non-reflective, non-echoing, echo-free") is a room designed to completely absorb reflections of either sound or electromagnetic waves.

An an-echoic room can absorb the sounds, or we can say that it prevents the sound from reflecting. Hence, option 3 is correct.

A space created to prevent the reflection of electromagnetic radiation or sound waves is known as an an-echoic chamber. Additionally, they are frequently shielded from outside energy intrusion.

With this configuration, a human or detector only hears primary sounds (no reflected sound), simulating outdoor free field conditions.

Leo Beranek, an American acoustics expert, developed the phrase "an-echoic chambers," which at first was only used to describe acoustic an-echoic chambers.

The name has since been expanded to include additional RF and Sonar acoustical chambers, which remove reflection and outside noise brought on by electromagnetic waves.

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The change in the internal (thermal) energy of the gas can be calculated using the first law of thermodynamics, which states that the change in the internal energy of a system is equal to the heat added to the system minus the work done by the system.

Since the compression is adiabatic, no heat is added to the system, so the change in internal energy is equal to the work done on the gas. Therefore, the change in the internal energy of the gas is 800 J. The answer is (A) 800 J. Thermodynamics is a branch of physics that deals with the relationships between heat, energy, and work. It is concerned with how energy is transferred between systems, and how energy transformations occur within systems. The main principles of thermodynamics are the first and second laws of thermodynamics. The first law of thermodynamics, also known as the law of conservation of energy, states that energy cannot be created or destroyed, only converted from one form to another.

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Answer:

3m

Explanation:

p=250w

m=25.5

t=3.0s

D=x

F=mxa   F= 25.5kg x 9.8m/s^2 =250N

D= 250wx3.0s/250w

3m

Answer:

Resonances occur at:

OC       OCOC         OCOCOC       OCOCOCOC      OCOCOCOCOCλ

λ/4          3λ/4               5λ/4                 7λ/4                    9λ/4

A resonance occrurs at λ/4

Thereafter, resonance occurs every λ/2

The fifth resonance will occur at λ/4 + 2λ = 9λ/4

If λ / 4 = 10 m         then       λ = 40 m

9 λ / 4 = 10 m    because the pipe is 10 m long

λ = 40 m / 9 = 4.44 m          the fifth resonance occcurs at a wavelength of 4.44 m

f λ = c = 340 m/sec

f = 340 m/sec / 4.44 m = 76.5 / sec

Note: the first resonance occurs at f = 340 / 40 = 8.5 /sec

Answer: 10 cm

Explanation:

\($$The focal length is: \\ \\ \begin{aligned}f &=\frac{R}{2} \\&=-\frac{46}{2} \\f &=-20 \mathrm{~cm}\end{aligned}$$\)

\($$ Since the image is virtual: \\ \\ :\begin{aligned}\frac{v}{u} &=m \\\Rightarrow & v=m u \\\Rightarrow &v=2 u\end{aligned}$$\)

\($$ Using: \\ \\ \begin{aligned}&\frac{1}{l}=\frac{1}{v}+\frac{1}{u} \\&\frac{1}{20}=-\frac{1}{2 u}+\frac{1}{u} \\&\frac{1}{2 u}=\frac{1}{-20} \\&\Rightarrow u=-10 \\&\therefore u=10 \mathrm{~cm}\end{aligned}$$\)

Therefore, you must be 10 cm away from the mirror so that your virtual image is twice the size of your actual face

The answer is B.1.1 × 10^1 N; oriented toward the equilibrium point.

The magnitude and direction of the elastic force Fel, if a spring is extended 15 cm from its equilibrium point and the spring constant k is 75 N/m can be calculated as follows;

Spring constant, k = 75 N/m

Displacement, x = 15 cm = 0.15 m

The magnitude of the elastic force Fel is given by;

F_el = kx

Where; F_el = elastic force

k = spring constant

x = displacement

Substituting the values of k and x in the above equation we get;

F_el = kx

F_el = 75 N/m × 0.15 m

F_el = 11.25 N

This is the magnitude of the elastic force.

The direction of the elastic force is always in the opposite direction to the displacement from the equilibrium point. Since the displacement is towards the right, the elastic force will be in the left direction,

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Answer:

(1) body composition, (2) flexibility, (3) muscular strength, (4) muscular endurance, and (5) cardiorespiratory endurance. 

The approximate change in internal energy of the water, when heated from 0°C to 100°C at a constant pressure of 1 atm, is 9400 cal. This value is obtained using the formula ΔU = m * c * ΔT, where ΔU represents the change in internal energy, m is the mass of the water (94 g), c is the specific heat of water (1 cal/g·°C), and ΔT is the change in temperature (100°C - 0°C = 100°C). By substituting the given values into the formula, we find that the change in internal energy of the water is 9400 cal.

To calculate the change in internal energy of the water, we can use the formula:

ΔU = m * c * ΔT

where:

ΔU is the change in internal energy,

m is the mass of the water (94 g),

c is the specific heat of water (1 cal/g·°C), and

ΔT is the change in temperature (100°C - 0°C = 100°C).

Substituting the values into the formula, we get:

ΔU = 94 g * 1 cal/g·°C * 100°C

   = 9400 cal

Therefore, the approximate change in internal energy of the water is 9400 cal.

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The acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.

It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.

As we know,

The acceleration can be found using the formula:

a = Δv/t

Here a is the acceleration

Δv is the change in linear velocity

t is the time

Δv = 29 - 33

Δv = -4 m/s

t = 10 seconds

a = -4/10

a = -0.4 m/s²

Thus, the acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.

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Einstein's analysis of the photoelectric effect was instrumental in establishing the concept of quantized energy and the existence of individual particles, known as photons.

Photons are fundamental particles of light and electromagnetic radiation. They are considered to be the carriers of electromagnetic force and exhibit properties of both particles and waves. Photons have zero rest mass, travel at the speed of light in a vacuum (c), and possess energy and momentum.

According to quantum theory, photons are quantized packets of electromagnetic energy. They are emitted and absorbed by charged particles when they transition between energy levels. The energy of a photon is directly proportional to its frequency, as described by the equation E = hf, where E is energy, h is Planck's constant, and f is the frequency. Photons can behave as waves, demonstrating interference and diffraction, and they can also exhibit particle-like behavior, such as momentum transfer during collisions. This duality is a fundamental aspect of quantum mechanics.

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Answer:

Select the crown at the bottom of an answer where the speech bubble icon is.

Answer:

ok

Explanation:

Have a nice day!

At the instant shown, the six scenarios can be ranked in terms of the magnitude of current in the light bulb as follows:

1) Scenario 1 - Here, the battery is directly connected to the light bulb without any other resistors in the circuit. Therefore, the current flowing through the bulb will be the maximum among all the scenarios.

2) Scenario 3 - In this case, the battery is connected to the light bulb through a resistor. However, the resistance is less compared to other scenarios, so the current will be higher than in other cases.

3) Scenario 4 - Here, the battery is connected to the light bulb through a higher resistance compared to scenario 3. This will result in a lesser current in the bulb.

4) Scenario 5 - In this scenario, the battery is connected to the light bulb through a much higher resistance than in the previous two scenarios. Therefore, the current flowing through the bulb will be lower.

5) Scenario 6 - Here, the battery is connected to the circuit in such a way that the current will bypass the light bulb. Therefore, the bulb will not light up and the current flowing through it will be zero.

6) Scenario 2 - This scenario is similar to scenario 6 where the switch is open, so the circuit is not complete, and hence there will be no current flowing through the light bulb.

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