need an explanation

It takes 15 minutes for all of the sand to flow through a sand timer. The sand timer contains 475 grams of sand. Each millilitre of sand weighs 1.5 grams. How many millilitres of sand flow through the timer per minute?
​

Without explicitly solving for x, we can conclude that the solution to the equation 2^x - 2 = 8^4 is x = 12.

To solve the equation 2^x - 2 = 8^4 without explicitly solving for x, we can simplify the equation using exponent rules and observe the relationship between the numbers.

First, let's simplify the equation:

2^x - 2 = 8^4

We know that 8 can be expressed as 2^3, so we can rewrite the equation as:

2^x - 2 = (2^3)^4

Applying the exponent rule (a^m)^n = a^(mn), we can simplify further:

2^x - 2 = 2^(34)

Simplifying the right side of the equation:

2^x - 2 = 2^12

Now, we can observe that both sides of the equation have the same base, which is 2. In order for the equation to hold true, the exponents must be equal:

x = 12

Therefore, we may deduce that the answer to the equation 2x - 2 = 84 is x = 12 without having to explicitly solve for x.

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The time Jack left Santa Clara is 1 : 55 pm

A word problem in math is a math question written as one sentence or more. These statements are interpreted into mathematical equation or expression.

The time for Jack to walk to lose Altos is 25 min and he uses another 25mins to work to Palo alto.

Therefore, the total time he spent is

25mins + 25 mins = 50 mins

He arrived Palo at 2 :45 pm, therefore the time he left Santa Clare will be ;

2:45 pm = 14 :45

= 14:45 - 50mins

= 13:55

= 1 : 55pm

Therefore he left at 1:55 pm

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Answer:

He can make $ 168.75 per week.

Step-by-step explanation:

1hr =$ 12.50

For 13.5 hrs,

12.5*13.5

= 168.75

Problem

What linear equation represents the graph of a horizontal line, parallel to the Z-axis, that travels through the point (0,4)? Use the grid or a piece of paper if needed. ​

Solution

for this case the general equation of a plane is given by:

A(x-xo) + B(y-yo) + C(z-zo)=0

C=0 for this case

A(x-xo) + B(y-yo) =0

And for this case one possible answer would be:

y=4

Answer:

m ≤ 5

Step-by-step explanation:

I will begin by assuming m to be the number.

Then, the sum of m and 3 is: m + 3.

The symbol for "less than or equal to" is ≤.

So we form an inequality, like this :

m + 3 ≤ 8

To find m subtract 3 on each side:

m ≤ 5

Therefore, m ≤ 5.

The shower head follows a linear function

From the complete question, we understand that:

Each minute, 5 gallons of water are used

This mean that, the possible ordered pairs are:

\(\mathbf{(x,y)= \{(1,5),(2,10),(3,15).....\}}\)

When the shower head is used for 0 minutes we have:

\(\mathbf{(x,y)= \{(1-1,5-5)\}}\)

\(\mathbf{(x,y)= \{(0,0)\}}\)

The ordered pair when the shower head is used for 0 minutes is (0,0)

The location on the graph is called the y-intercept.

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1. Initial prediction for the data set with smaller Mean Absolute Deviation was Period A. Prediction was wrong.

2. The Mean Absolute Deviation for Period A is 1.8 and Period B, 1.1

This means that period B has a smaller Mean absolute deviation.

We start by finding the mean for each set;

Period A: Mean = (1×92 + 1×94 + 3×95 + 1×96 + 2×97 + 1×99 + 1×100)/10

= 960/10

= 96

Period B: Mean = (1×94 + 3×95 + 1×96 + 4×97 + 1×98)/10

= 961/10

= 96.1

Period A:

Mean Absolute Deviation = ((92-96) + (94-96) + 3(95-96) + (96-96) + 2(97-96) + (99-96) + (100-96))/10

Mean Absolute Deviation = (4 + 2 + 3 + 0 + 2 + 3 + 4)/10

Mean Absolute Deviation = 1.8

Period B:

Mean Absolute Deviation = ((94-96.1) + 3(95-96.1) + (96-96.1) + 4(97-96.1) + (98-96.1))/10

Mean Absolute Deviation = (2.1 + 3.3 + 0.1 + 3.6 + 1.9)/10

Mean Absolute Deviation = 1.1

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We are given two box plots of a variable, for two different towns. Recall that the structure of a box plot is

where Q1 is the 25th percentile (or quartile 1), Q2 is the median and Q3 is the 75th percentile (or Quartile 3). This type of graphs tells us how the data is distributed, and more specially it can tell us how the data is spread across the different values the variable could take. So the way to analyze the spread from the graph is by considering the inter quartile range (IQR). This amount can be calculated by simply finding the difference between Q3 and Q1. If this range is really small, this would mean that the data is less spread and if this range is big, then this would mean that the data is more spread.

Using the given box plots, we can determine the following:

Town A: Q3 = 40, Q1 = 20, IQR = 40-20=20

Town B: Q3 = 45, Q1=35, IQR = 45-35 = 10

So, this would lead to option D.

Answer:

Since the other dude is being inappropriate-

Here's your answer!

Answer: 60 mph

Step by Step Explanation

300+120+420=840

840/14=60

Answer:

3 and a half hours

Answer:3.5 hours

Step-by-step explanation:

6 acre= 1 hour

60 min ÷6= 10 min for 1 acre

10 ×21= 210

210÷60=3.5 hours

Answer:

Lower quartile= 4

Middle quartile= 6

Upper quartile=8

Answer:

there is no answer to that

Step-by-step explanation:

what do you mean by that.

Answer:

b. 44°

Step-by-step explanation:

Reference angle = x

Hypotenuse = 21

Adjacent = 15

Apply trigonometric function CAH:

\( Cos(x) = \frac{Adj}{Hyp} \)

\( Cos(x) = \frac{15}{21} \)

\( x = cos^{-1}(\frac{15}{21}) \)

x = 44.4153086° ≈ 44° (nearest degree)

Answer:

1

Step-by-step explanation:

Answer:

5

6

Step-by-step explanation:

To solve, collect like terms

x ≥ 2 + 21/2

x ≥ 4 1/2

the whole number that would be greater than 41/2 would be 5

2.  2.7 + 3.3  > x

6 > x

Answer:

7x+28

Step-by-step explanation:

7(x+4)

Use the distributive property to multiply 7 by x+4.

7x+28

Graph if needed:

The probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213 is approximately 0.9702.

To find the probability that a single randomly selected value is between 189.7 and 213, we can use the standard normal distribution.

Step 1: Calculate the z-scores for the given values using the formula:

  z = (x - μ) / σ

  For 189.7:

  z1 = (189.7 - 189.7) / 96.7 = 0

  For 213:

  z2 = (213 - 189.7) / 96.7 ≈ 0.2417

Step 2: Utilize a standard typical conveyance table or number cruncher to find the probabilities comparing to the z-scores.

  P(189.7 < X < 213) = P(0 < Z < 0.2417) ≈ 0.0939

Therefore, the probability that a single randomly selected value is between 189.7 and 213 is approximately 0.0939.

To find the probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213, we use the central limit theorem. Under specific circumstances, the testing dispersion of the example mean methodologies a typical conveyance

Step 1: Calculate the standard error of the mean (σ_m) using the formula:

  σ_m = σ / sqrt(n)

  σ_m = 96.7 / sqrt(62) ≈ 12.2878

Step 2: Convert the given qualities to z-scores utilizing the equation:

  z = (x - μ) / σ_m

  For 189.7:

  z1 = (189.7 - 189.7) / 12.2878 = 0

  For 213:

  z2 = (213 - 189.7) / 12.2878 ≈ 1.8967

Step 3: Utilize a standard typical conveyance table or mini-computer to find the probabilities relating to the z-scores.

  P(189.7 < M < 213) = P(0 < Z < 1.8967) ≈ 0.9702

Therefore, the probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213 is approximately 0.9702.

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Answer:

It would be 0.83.

Step-by-step explanation:

Ok, to start, this dice has 6 sides, 1, 2, 3, 4, 5, and 6. Each of these sides has a 1/6 chance of landing on it if you were to throw this dice.

Now, we are looking for chance that the dice does not land on 5. With this, the dice may only land on 1, 2, 3, 4, or 6 but not 5.

Therefore, since all of the sides have an equal chance, there are 6 total sides, and 5 of the sides can be landed on, 5 of the 6 sides can be landed.

This gives it a 5/6 chance that it will land on one of these sides.

Lastly, it needs to be in the form of a decimal, so by doing divison of 5/6, would would get:

0.83333...

By doing rounding to 2 decimal places, this will round down to 0.83.

Answer:800 students total

Step-by-step explanation: 88% of 800 is 704. 12% or 96 people didnt say red

9514 1404 393

Answer:

  (p, h) = (32, 11)

Step-by-step explanation:

We can write an expression for p using the first equation, then substitute that into the second equation.

  4.5(43-h) +12h = 276 . . . . substitute for p

  193.5 +7.5h = 276 . . . . . . eliminate parentheses

  7.5h = 82.5 . . . . . . . . . . . . subtract 193.5

  h = 82.5/7.5 = 11 . . . . . . . . divide by the coefficient of h

  p = 43 -11 = 32

The solution is (p, h) = (32, 11).

To find the fraction of pocket money left after spending on transport and fruit, we need to subtract the amount spent from the total pocket money and express it as a fraction.

The student spends 18 out of 35 of his pocket money, which means he has (35 - 18) = 17 units of his pocket money left.

Therefore, the fraction of pocket money left can be written as 17/35.

The expression that is always equivalent to sin x when 0° < x < 90° is (1) cos (90° - x). Option 1

To understand why, let's analyze the trigonometric functions involved. In a right triangle, the sine of an angle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. Since we are considering angles between 0° and 90°, we can guarantee that the side opposite the angle will always be the shortest side of the triangle, and the hypotenuse will be the longest side.

Now let's examine the expression cos (90° - x). The cosine of an angle is defined as the ratio of the length of the side adjacent to the angle to the length of the hypotenuse. In a right triangle, when we subtract an angle x from 90°, we are left with the complementary angle to x. This means that the remaining angle in the triangle is 90° - x.

Since the side adjacent to the angle 90° - x is the same as the side opposite the angle x, and the hypotenuse is the same, the ratio of the adjacent side to the hypotenuse remains the same. Therefore, cos (90° - x) is equivalent to sin x for angles between 0° and 90°.

On the other hand, options (2) cos (45° - x) and (3) cos (2x) do not always yield the same value as sin x for all angles between 0° and 90°. The expression cos x (option 4) is equivalent to sin (90° - x), not sin x.

Option 1 is correct.

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a. The object is momentarily at rest at t = 6.

b. It moves up in the interval (0, 6) and moves down in the interval (6, 12).

c. The object changes direction at t = 6.

d. It speeds up in the interval (0, 6) and slows down in the interval (6, 12).

e. The object does not have a maximum speed within the given interval, and it is moving slowest at t = 0 and t = 12.

f. The object is farthest from the axis origin at t = 6.

To solve the given problem, we start by finding the velocity and acceleration functions based on the position function provided:

Position function: \(s = f(t) = 192t - 16t^2\)

a. Velocity function: v(t) = ds/dt = f'(t)

Taking the derivative of the position function with respect to time, we have:

\(v(t) = d(192t - 16t^2)/dt = 192 - 32t\)

b. Acceleration function: \(a(t) = d^2s/dt^2 = f''(t)\)

Taking the second derivative of the position function with respect to time, we have:

a(t) = d(192 - 32t)/dt = -32

Now, let's answer the given questions:

a. The object is momentarily at rest when its velocity is equal to zero.

Setting v(t) = 0 and solving for t:

192 - 32t = 0

32t = 192

t = 6

b. The object moves up when the velocity is positive (v(t) > 0) and moves down when the velocity is negative (v(t) < 0).

Interval when the object moves up: (0, 6)

Interval when the object moves down: (6, 12)

c. The object changes direction when the velocity changes sign. In this case, it changes direction at t = 6.

d. The object speeds up when the acceleration and velocity have the same sign, and it slows down when the acceleration and velocity have opposite signs.

The object speeds up in the interval (0, 6) and slows down in the interval (6, 12).

e. The object is moving fastest when its velocity is maximum. The velocity function is v(t) = 192 - 32t, and it reaches its maximum when its derivative is equal to zero.

Setting v'(t) = 0 and solving for t:

v'(t) = -32 = 0

There is no solution for t since -32 is a constant.

The object is moving slowest when its velocity is minimum, which occurs at the endpoints of the given interval.

So, the object is moving slowest at t = 0 and t = 12.

f. To find when the object is farthest from the axis origin, we look for the maximum value of the position function.

The position function is \(s(t) = 192t - 16t^2,\) and it reaches its maximum value when its derivative is equal to zero.

Setting s'(t) = 0 and solving for t:

s'(t) = 192 - 32t = 0

32t = 192

t = 6

So, the object is farthest from the axis origin at t = 6.

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Answer:

Step-by-step explanation:

                                                   error

Answer:

x ≈ 75.2

Step-by-step explanation:

using the tangent ratio in the right triangle

tan62° = \(\frac{opposite}{adjacent}\) = \(\frac{x}{40}\) ( multiply both sides by 40 )

40 × tan62° = x , then

x ≈ 75.2 ( to the nearest tenth )

Answer:

X= 7

Step-by-step explanation:

First, multiply \(18*5 = 90\)

Then, divide \(90 / 6 = 15\)

Therefore, each group has 15 students.

Answer:

31°

Step-by-step explanation:

α = ß = 31°

Answer:

Step-by-step explanation: m=s-c/c

\(\huge\underline\mathtt\colorbox{cyan}{3-7}\)

Step-by-step explanation:

The correct interpretation of 3+(-7) is 3-7, simply

Answer:

The answer will be

3+(-7)

The sum of positive and negative is negative

So 3+(-7) is 3-7

= -4

Step-by-step explanation:

Hope it helps

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