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Answer:

2.26 is bigger than 2.25

Step-by-step explanation:

you can compare it like money

so for example , $2.26 > $2.25 because

in dollars 2.26 dollars is more.

Answer:

7.9 m

Step-by-step explanation:

Use the Pythagorean theorem: a²+b²=c²

This formula can be used to solve a side of any right (90°) triangle.

c² is the length of the hypotenuse (the diagonal side of the triangle, opposite to the 90° angle)

So, c = 32m.

Sides a and b are the legs of the triangle, but we only know one side. Plug numbers into the formula:

31² + b² = 32²

961 + b² = 1024 Subtract 961 from both sides to get b² by itself.

b² = 63

√b² = √63  Square root both sides to get b by itself.

b = 7.93725

Answer is 7.9 meters, rounded to tenths place

Answer:

8

Step-by-step explanation:

\(x^2-2x \\x=4\\(4)^2-2(4)\\16-8\\8\)

Answer:

\(6\sqrt{3}\)

Step-by-step explanation:

so we are going to create a factor tree which is the .The factor tree is any two numbers that equal to 108.

next we are going to pull out our pairs.so there are one pair of two's and one pair of threes

\(\sqrt[2]{108} =2*3\sqrt{3} =6\sqrt{3}\)

pls mark me brainliest

The value of m is 10cm and the value of n is 24cm

Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse.

a² = b² + c²

for the small rectangular face,

m² = 6² +8²

m² = 36 + 64

m² = 100

m = √100

m = 10cm

to find the value of n

n² = 24² + 8²

n² = 576 + 64

n² = 640

n = √ 640

n = 25.3 cm

Therefore the value of m and n is 10cm and 25.3 cm.

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The effective interest on £2000 at a 3% interest rate compounded quarterly over a period of 4 years is approximately £245.15.

To calculate the effective interest, we need to use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the future value of the investment (including interest)

P = the principal amount (initial investment)

r = the annual interest rate (as a decimal)

n = the number of compounding periods per year

t = the number of years

In this case, the principal amount (P) is £2000, the annual interest rate (r) is 3% (or 0.03 as a decimal), the compounding is done quarterly (n = 4), and the investment period (t) is 4 years.

Plugging the values into the formula:

A = £2000(1 + 0.03/4)^(4*4)

= £2000(1 + 0.0075)^16

= £2000(1.0075)^16

≈ £2000(1.126825)

Calculating the future value:

A ≈ £2253.65

To find the effective interest, we subtract the principal amount from the future value:

Effective Interest = £2253.65 - £2000

≈ £253.65

Therefore, the effective interest on £2000 at a 3% interest rate compounded quarterly after 4 years is approximately £253.65.

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Answer:

see attached for diagram

a) √13

b) √29

c) 4

Step-by-step explanation:

Equation of the circle:  \((x + 1)^2 + (y - 3)^2 = 16\)

⇒ center = (-1, 3)

⇒ radius = √16 = 4

Distance between 2 points formula:

\(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

a)  let (-1, 3) = \((x_1,y_1)\)

    let (2, 1) = \((x_2, y_2)\)

 \(\implies \sqrt{(2+1)^2+(1-3)^2} =\sqrt{13}\)

b)  let (-1, 3) = \((x_1,y_1)\)

    let (4, 1) = \((x_2, y_2)\)

\(\implies \sqrt{(4+1)^2+(1-3)^2} =\sqrt{29}\)

c)  let (-1, 3) = \((x_1,y_1)\)

    let (3, 3) = \((x_2, y_2)\)

\(\implies \sqrt{(3+1)^2+(3-3)^2} =4\)

Compare with (x-h)^2+(y-k)^2=r^2

Distance to (2,1)

Distance to (4,1)

Distance to (3,3)

The 7th term of the arithmetic sequence -3x+5, 2x+3, 7x+1, ... is: 27x-7.

To find the 7th term of the arithmetic sequence, we need to first determine the common difference between the terms. We can do this by subtracting the first term from the second term:

(2x+3) - (-3x+5) = 5x - 2

This means that the common difference between the terms is 5x - 2. Now, we can use the formula for the nth term of an arithmetic sequence:

aₙ = a₁ + (n - 1)d

Where an is the nth term, a₁ is the first term, n is the term number, and d is the common difference. Plugging in the values we have:

a₇ = (-3x+5) + (7 - 1)(5x - 2)

Simplifying the equation:

a₇ = -3x + 5 + 30x - 12

a₇ = 27x - 7

Therefore, the 7th term of the arithmetic sequence is 27x - 7.

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Answer:

1/8

Step-by-step explanation:

2⁻³ = 1 / 2³ = 1 / (2*2*2) = 1/8

so the minus sign in the exponent means you can put that factor in the denominator without the minus sign.

Answer:

72 ounces of bananas

Answer:

72

Step-by-step explanation:

4.5 ties 16 = 72

a) A department manager receiving an allocation of costs will care about management's methodology of overhead allocation because the overhead costs allocated to their department will have a direct impact on the department's profitability and cost efficiency.

b) The allocation base is the measure used to determine how much of the overhead costs should be allocated to a particular department or product, while the allocation rate is the amount of overhead costs allocated to each unit of the allocation base

c) Budgets are an important tool for cost planning, but their effectiveness depends on how well they are developed and implemented.

a) If the allocation method used by management is not accurate or fair, it could result in the department being burdened with more costs than they actually incur, which could affect their ability to meet their targets and objectives. It is, therefore, important for department managers to ensure that the allocation of costs is done fairly and accurately.

b) The allocation base and rate are important because they determine how the overhead costs are allocated to different departments or products.

Different allocation bases and rates can result in significantly different amounts of overhead costs being allocated to different departments or products, which can impact their profitability. While all of the overhead costs eventually make their way to the income statement, the allocation of these costs can have a significant impact on the accuracy of the income statement and the ability of the organization to make informed decisions.

c) Budgets can be helpful in providing a roadmap for achieving the organization's goals and objectives, but they need to be flexible enough to adapt to changing circumstances and priorities.

The budget(s) that are most important to the organization's success will depend on the nature of the organization and its objectives. However, typically the operating budget, capital budget, and cash budget are the most important budgets for most organizations.

The government's budget process is similar to the operating budgeting process described in the chapter in that it involves the development of a budget to allocate resources and achieve goals. However, the government's budget process is more complex and involves additional considerations such as political priorities and public opinion. Additionally, the government's budget process involves a more detailed review and approval process than the operating budgeting process.

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The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.

These are due to the Doppler effect, the equation of frequency detected by the observer as

\(f_o = f_s\sqrt{\frac{1-\beta }{1+\beta } }\) where \(\beta = \frac{v}{c}\), v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.

Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

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Histograms are used to demonstrate the distribution of a dataset. They provide a visual representation of the shape and spread of the data, showing how frequently different values occur in the dataset.

Histograms are especially useful when the data is continuous, meaning that it can take on any value within a certain range. They are created by dividing the range of the data into a set of intervals or "bins," and then counting the number of data points that fall within each bin.

The resulting bar chart shows the frequency of data points in each bin, with the height of each bar representing the number of data points in that bin.

Histograms can be used to reveal important features of the data, such as its central tendency, variability, and skewness. They can also be used to identify outliers or unusual patterns in the data. By showing the overall pattern of the data, histograms can provide insights that would be difficult to discern from a simple list of numbers or a table.

In a presentation, histograms can be used to help the audience understand the nature of the data and draw conclusions based on its distribution. They can also be used to compare the distributions of different datasets, to identify similarities or differences between them.

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Answer:

Hi! Nice to meet you!

Step-by-step explanation:

P.S Can I have brainliest?

The  equation of the tangent plane to the parametric surface is 3x + 2y + 6 root2z = 0.

A tangent to a curve was a line that just touched the curve at that point and was "parallel" to the curve at that point. A well-tangent plane to a surface is a plane that just touches the surface at that point and is "parallel" to the surface at that point.

The tangent plane to surface S at point P0 includes all tangents to curves in S that pass through P0. For a plane tangent to a surface to exist at a point on that surface, it is sufficient if the function defining the surface is differentiable at that point.

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Answer:

\((a+b)^{2}- \sqrt[3]{x . 3y}\)

Step-by-step explanation:

Subtract the cube root of the product of x and 3y from the square of the sum of a and b.  

A = The square of the sum of a and b is  \((a+b)^{2}\)

B = The cube root of the product of x and 3y is  \(\sqrt[3]{x . 3y}\)

They want us to subtract B from A so B - A, therefore the following.

\((a+b)^{2}- \sqrt[3]{x . 3y}\)  

The probability that the chosen integer is a perfect square or a perfect cube but not both is therefore 13/100.

When choosing an integer from 1 to 100, there are 10 perfect squares (1² to 10²) and 4 perfect cubes (1³ to 4³). However, the number 1 is both a perfect square and a perfect cube. To avoid counting it twice, we use the formula for the union of two sets: |A∪B| = |A| + |B| - |A∩B|. In this case, |A∪B| represents the number of integers that are either a perfect square or a perfect cube. Plugging in the values, we get |A∪B| = 10 + 4 - 1 = 13. The probability is therefore 13/100.

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Answer:

x = 25

Step-by-step explanation:

total interior angles in 360

4x - 20 + 100 = 180

4x = 100

x = 25

Answer:

sin= opposite leg/hypotenuse

Sin(a)=12/37

Step-by-step explanation:

Try this option:

a) 0.5; b) 0.91; c) 2.9; d) 0.72; e) 0.88; f) 0.47; g) 0.33; h) 0.71; i) 1.88; j) 0.42; k) 1; l) 0.87

Answer:

B) 14, 18, 5

Step-by-step explanation:

This is correct

The correct answer is C. The samples are dependent because there is a natural pairing between the two samples (before and after their first year of college).

In this case, the weight measurements of each student are paired based on their individual progress over time.

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Answer:

Combined area = 4\(x^{2}\) + 38x + 84

Step-by-step explanation:

The rectangle formed by the pool and walkway is 12 + 2x long and 7 + 2x wide.

Area of the rectangle = lw = (2x + 12)(2x + 7) = 4\(x^{2}\) + 38x + 84

Once we have categorized an object, our memory of the object increasingly resembles the category is B) prototype. This means that when we categorize an object, our memory of it begins to resemble the prototype or typical example of that category. For example, if we categorize a bird as a robin, our memory of the bird will increasingly resemble the characteristics of a typical robin.

This happens because our brain uses prototypes as a shortcut to process information and make sense of the world around us. We use prototypes to quickly identify objects and make assumptions about their characteristics based on their category.

our memory of an object after categorization is influenced by the prototype of the category. This helps us to quickly process and make sense of information, but it can also lead to errors and biases in our thinking.


A prototype is a mental image or best example of a category. When we categorize an object, our memory of the object increasingly resembles the prototype because we tend to recall the most representative or typical example of the category.

Once we categorize an object, our memory of the object becomes more like the prototype, which is the best example of the category. This is because we tend to remember the most representative or typical examples of a category.

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Null hypothesis (H0): The population mean amount spent by customers at the restaurant is equal to or greater than $32.

Alternative hypothesis (H1): The population mean amount spent by customers at the restaurant is less than $32.

The appropriate null and alternative hypotheses in this scenario can be stated as follows:

The null hypothesis is the default assumption, which states that there is no significant difference between the mean amount spent by customers last year and this year.

On the other hand, the alternative hypothesis is the claim that the mean amount spent by customers this year is less than the previous year, which the restaurant owner is trying to test.

By conducting appropriate statistical tests and analyzing the data, the restaurant owner can either reject the null hypothesis or fail to reject it, depending on the level of significance and the strength of the evidence gathered.

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Answer:

52 ounces

Step-by-step explanation:

The computation of the number of ounces buy is shown below:

Let us assume the number of guest be x

Now it is given  that

There is 6 ounces of dough and 4 ounces of sauce and  the total of them is 130

Now the equation is

6x + 4x = 130

10x = 130

x = 13

Now the number of ounces of sauce buy would be

= 13 (4)

= 52 ounces of sauce would be bought