Next in sequence 6, 12, 15,60,65

Answer:

The answer is b

Step-by-step explanation:

I know this because a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression and since 9 is being multiplied by x that would mean 9 is a coefficient in this expression.

Given that sec(t) = -2.475 and angle t is in Quadrant III, the other five trigonometric ratios are as follows: cos(t) ≈ 0.404, sin(t) ≈ -0.916, tan(t) ≈ 2.268, csc(t) ≈ -1.092, and cot(t) ≈ 0.441.

We are given that sec(t) = -2.475, which represents the reciprocal of the cosine of angle t. Since sec(t) is negative and angle t is in Quadrant III, we can deduce that the cosine of t is negative. To find cos(t), we can use the identity sec(t) = 1/cos(t) and solve for cos(t), resulting in cos(t) ≈ 0.404.

Using the Pythagorean identity \(sin^2(t) + cos^2(t)\) = 1, we can find sin(t) as sin(t) = ±\(\sqrt(1 - cos^2(t))\). Since angle t is in Quadrant III, where sine is negative, we take the negative value. Thus, sin(t) ≈ -0.916.

By dividing sin(t) by cos(t), we obtain the tangent of t. Hence, tan(t) ≈ sin(t)/cos(t) ≈ -0.916/0.404 ≈ 2.268.

Cosecant (csc) is the reciprocal of sine, so csc(t) ≈ 1/sin(t) ≈ -1.092.

Similarly, cotangent (cot) is the reciprocal of tangent, so cot(t) ≈ 1/tan(t) ≈ 1/2.268 ≈ 0.441.

In conclusion, when sec(t) = -2.475 and angle t is in Quadrant III, the other five trigonometric ratios are approximately: cos(t) ≈ 0.404, sin(t) ≈ -0.916, tan(t) ≈ 2.268, csc(t) ≈ -1.092, and cot(t) ≈ 0.441.

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Answer:

5

Step-by-step explanation:

the angles need to add up to 180

60 + 40 =100

180 - 100 =80

80 - 5 =75

75/15 =5

To find the probability of getting 10 or more successes in a binomial experiment with p = 0.63 and n = 11 trials, we can use the cumulative probability function.

P(X ≥ 10) = 1 - P(X < 10)

Using a binomial probability formula, we can calculate the probability of getting exactly k successes:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

where C(n, k) represents the binomial coefficient.

Let's calculate the probability for each value from 0 to 9 and subtract it from 1 to get the probability of 10 or more successes:

P(X < 10) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 9)

P(X < 10) = Σ[C(11, k) * p^k * (1 - p)^(11 - k)] for k = 0 to 9

Using this formula, we can calculate the probability:

P(X < 10) ≈ 0.121

Therefore, the probability of getting 10 or more successes in the binomial experiment is:

P(X ≥ 10) ≈ 1 - P(X < 10) ≈ 1 - 0.121 ≈ 0.879

Rounding to three decimal places, the probability is approximately 0.879.

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Answer:

3x+15

Step-by-step explanation:

distribute by multiplying 3 to each term

3(x)+3(5)

3x+15

Hopes this helps please mark brainliest

Answer:

I believe it is B. 2

Step-by-step explanation:

Answer:

m = -6n-5 / 2

Step-by-step explanation:

2m = -6n - 5

/2        /2

---------------------

m = -6n-5 / 2

Answer:

m=-3n+-5/2

Step-by-step explanation:

Divide both sides by 2

The value of x is 1/2y+3/2

Answer:

y = 2x - 3

Step-by-step explanation:

8 + 2y - 5x + y = x - 1

3y = 6x - 9

y = 2x - 3

slope is 2, y-intercept is -3

Answer:

i think it's D. because 55% isn't enough, but very close, and 0.625% is waaaay too little, and the same for 1.60.

Step-by-step explanation:

estimation.

The percentage of Janet's money does Emma have is D. 62.5%.

Given that,

Based on the above information, the calculation is as follows:

\(= \$25 \div \$40\)

= 62.5%

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Step-by-step explanation:

if he buys 7 pounds, it will cost 7×5 = $35

he might buy more than that (and it will then also cost more than that) , but not less than that.

so,

c >= $35

Answer:

(i) The complement of the intersection of Sets A and B, denoted by (A∩B)', is the set of all elements that are not in the intersection of Sets A and B. It can be found by taking the union of the complements of Sets A and B, denoted by A' and B'. Hence, (AnB)' = A' U B'.

(ii) The complement of the union of Sets A and C, denoted by (A U C)', is the set of all elements that are not in the union of Sets A and C. It can be found by taking the intersection of the complements of Sets A and C. Hence, (A U C)' = A' ∩ C'.

(iii) The complement of the union of Sets A, B, and C, denoted by (A U B U C)', is the set of all elements that are not in the union of Sets A, B, and C. It can be found by taking the intersection of the complements of Sets A, B, and C. Hence, (A U B U C)' = A' ∩ B' ∩ C'.

Answer:

Step-by-step explanation:

8% supporting the visiting team, so:

92% is 2576, find the total number:

Answer:four right angles

Step-by-step explanation:

Because a rectangle had four right angles

The characteristic of the figure with vertices at coordinates A(1, 1), B(1, 2), C(2, 2), and D(2, 1) should be four right angles.

For a polygon, it shows the corners of the polygon or the point at which two sides of the polygon should be met out.

The Coordinates of a point with respect to the coordinate plane represent the  position of the point on the plane.

Also, the rectangle does contain four right angles so this should not be the characteristic.

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This value represents the present worth below which the probability is 0.5, indicating a negative present worth.

To estimate the probability that the present worth is negative using the NORM.INV function in Excel,

we need to calculate the present worth of the project and then determine the corresponding probability using the normal distribution.

The present worth of the project can be calculated by finding the sum of the present values of the annual receipts over the 10-year period, minus the initial investment. The present value of each annual receipt can be calculated by discounting it back to the present using the minimum attractive rate of return (MARR).

Using the given information, the present value of the initial investment is $10,000. The present value of each annual receipt is calculated by dividing the expected return of $1,800 by \((1+MARR)^t\),

where t is the year. We then sum up these present values for each year.

We can use the NORM.INV function in Excel to estimate the probability of a negative present worth. The function requires the probability value, mean, and standard deviation as inputs.

Since we have a mean and standard deviation for the present worth,

we can calculate the corresponding probability of a negative present worth using NORM.INV.

This value represents the present worth below which the probability is 0.5. By using the NORM.INV function,

we can estimate the probability that the present worth is negative based on the given data and assumptions.

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Answer:

3200000 I think

Step-by-step explanation:

I just multiplied them together.

The indicated coefficients are:

\(c_2 = -(-2) = 2\)

\(c_4 = 5/2\)

\(c_5 = -22\)

To find the power series solution of the differential equation about x = 0, we assume that the solution has the form:

y(x) = ∑(n=0 to infinity) \(c_n x^n\)

where \(c_n\) are the coefficients of the power series.

Differentiating y(x), we get:

y'(x) = ∑(n=1 to infinity) \(n c_n x^{(n-1)}\)

Next, we substitute y(x) and y'(x) into the differential equation:

(\(x^2\) - x + 1)y' - y + 8y = 0

(\(x^2\) - x + 1) ∑(n=1 to infinity)\(n c_n x^{(n-1)}\) - ∑(n=0 to infinity)\(c_n x^n\) + 8∑(n=0 to infinity)\(c_n x^n\) = 0

Simplifying this expression and grouping the terms with the same power of x, we get:

∑(n=1 to infinity) \(n c_n x^n (x^2 - x + 1)\)+ ∑(n=0 to infinity) \((8c_n - c_{(n+1)}) x^n\) = 0

Since this equation holds for all values of x, we must have:

\(n c_n (n+1) - (n+2) c_(n+2) + 8c_n - c_(n+1) = 0\)

for all n ≥ 0, where we have set \(c_{(-1){ = 0\)and \(c_{(-2)}\)= 0.

Using the initial conditions y(0) = 0 and y'(0) = 4, we have:

\(c_0 = 0\)

\(c_1 = y'(0) = 4\)

Substituting these values into the recurrence relation, we can recursively find the coefficients of the power series solution:

\(n = 0: 0 c_0 - 2 c_2 + 8 c_0 - c_1 = 0 = > c_2 = (4-8c_0+c_1)/(-2) = -2\)

\(n = 1: 1 c_1 - 3 c_3 + 8 c_1 - c_2 = 0 = > c_3 = (9c_1-c_2)/3 = 6\)

\(n = 2: 2 c_2 - 4 c_4 + 8 c_2 - c_3 = 0 = > c_4 = (10c_2-c_3)/(-4) = 5/2\)

\(n = 3: 3 c_3 - 5 c_5 + 8 c_3 - c_4 = 0 = > c_5 = (11c_3-c_4)/5 = -22/15\)

\(n = 4: 4 c_4 - 6 c_6 + 8 c_4 - c_5 = 0 = > c_6 = (9c_4-c_5)/(-6) = -64/45\)

Hence, the power series solution of the differential equation about x=0 is:

\(y(x) = 4x + 2x^2 - 4x^3 + 23x^4 - 44/9 x^5 + 24/5 x^6 - 326/315 x^7 + ...\)

Therefore, the indicated coefficients are:

\(c_2 = -(-2) = 2\)

\(c_4 = 5/2\)

\(c_5 = -22\)

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The warmup period changes with different initial conditions in an M/M/1 queue simulation. Deleting a specific number of customers when starting the system empty, with 4 customers initially, and with 8 customers initially affects the warmup period.

The warmup period in an M/M/1 queue simulation refers to the time it takes for the system to stabilize and reach a steady-state behavior after initialization. By conducting simulations with different initial conditions, specifically starting the system empty, with 4 customers initially, and with 8 customers initially, the warmup period can be analyzed.

When starting the system empty, there are no customers present, and the warmup period is generally longer compared to scenarios with initial customers. This is because the system needs time to receive incoming customers and build up a queue.

With 4 customers initially in the system, there is already some workload present. This reduces the warmup period compared to an empty system since there are customers in the queue and the system can start processing them immediately.

Similarly, when starting with 8 customers initially, the warmup period further decreases as there are even more customers in the system from the beginning. This allows for faster processing and a shorter time required to stabilize.

These findings suggest that initializing simulations with some initial customers can help reduce the warmup period. Having customers in the system from the start allows for more accurate representations of real-world scenarios and avoids extended periods of transient behavior.

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Using simple mathematical operations, we know that the positive difference between the mass of the fish and fisherman is 26.25.

An operation is a function in mathematics that transforms zero or more input values into a clearly defined output value.

The operation's arity is determined by the number of operands.

The addition, subtraction, multiplication, division, exponentiation, and modulus operations are carried out via the arithmetic operators.

So, we know that:

Fish: 75kg + 75/4

75 + 18.75

93.75

Fisherman: 100kg + 100/5

100 + 20

120

Positive difference: 120 - 93.75 = 26.25

Therefore, using simple mathematical operations, we know that the positive difference between the mass of the fish and fisherman is 26.25.

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Answer:

he has 10 type of each coin

Step-by-step explanation:

Total number of cents in possession is calculated as;

= 25 + 10 + 5

= 40 cent

Total amount in possession = $4

                                               = 400 cent

Since he has equal number of each cent, let this equal number be "y";

40cent (y) = 400cent

40y = 400

divide both sides by 40

\(\frac{40y}{40} = \frac{400}{40} \\\\y = 10\)

Therefore, he has 10 type of each coin

The Taylor series expansion by plugging in the values f(z) = f(z0) + f'(z0)(z - z0) + f''(z0)(z - z0)²/2,f(z) = (ln(sqrt(2)) + i (-π/4)) + (-1/2 - (1/2)i)(z - (-1 + i)) + (i/2)(z - (-1 + i))²/2

The principal value of the logarithm, denoted as Log z, is defined as follows:

Log z = ln |z| + i Arg(z)

The function Log z is analytic in the complex plane except for the branch cut along the negative real axis, which is the set of points of the form x + 0i where x ≤ 0. This branch cut is necessary to define a consistent argument (Arg) for the complex logarithm.

To expand the principal value of the logarithm in a Taylor series with centre z0 = -1 + i, the following formula for a complex function:

f(z) = f(z0) + f'(z0)(z - z0) + f''(z0)(z - z0)²/2! + f'''(z0)(z - z0)³/3! +

Let's start by finding the values of the function and its derivatives at z0 = -1 + i:

f(z0) = Log z0 = ln |-1 + i| + i Arg(-1 + i)

To find the modulus |z0|,use the distance formula in the complex plane:

|-1 + i| = sqrt((-1)² + 1²) = sqrt(2)

To find the argument Arg(-1 + i),use the inverse tangent function:

Arg(-1 + i) = atan(1/-1) = atan(-1) = -π/4

Therefore, f(z0) = ln(sqrt(2)) + i (-π/4).

Now, let's calculate the first derivative:

f'(z) = d/dz (ln |z| + i Arg(z))

= 1/z

At z = z0,

f'(z0) = 1/(-1 + i)

To simplify the expression, multiply the numerator and denominator by the conjugate of -1 + i:

f'(z0) = (1/(-1 + i)) × ((-1 - i)/(-1 - i))

= (-1 - i)/((-1)² - (i)²)

= (-1 - i)/(1 + 1)

= (-1 - i)/2

= -1/2 - (1/2)i

Now, let's calculate the second derivative:

f''(z) = d/dz (1/z)

= -1/z²

At z = z0,:

f''(z0) = -1/(-1 + i)²

To simplify the expression, square the denominator:

f''(z0) = -1/((-1 + i)²)

= -1/((-1 + i)(-1 + i))

= -1/(1 - 2i + i²)

= -1/(1 - 2i - 1)

= -1/(-2i)

= (1/2i)

= (1/2i) × (i/i)

= i/2

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Transformations that may have been used to construct A'B'C include a 90° upward rotation and a 3 unit up and 3 unit right shift.

Transformation in mathematics refers to the process of changing the position, size, or shape of a geometric object. The following are the most common types of transformations: Translation: It involves moving an object from one location to another without changing its size or orientation. Reflection: It involves flipping an object over a line of reflection, so that the object and its image are mirror images of each other. Rotation: It involves rotating an object around a fixed point, called the center of rotation. Dilation: It involves changing the size of an object, either making it larger or smaller, while preserving the shape of the object. Shear: It involves skewing an object in a given direction, causing its shape to be distorted. Similarity Transformation: It is a combination of transformations that preserve the shape of an object, but changes its size and orientation.

Here,

Triangle A’B’C’ is the image of triangle ABC. Transformations could have been used to create A’B’C,

Rotation of 90° upwards.

Shift of 3 units up and 3 units to the right.

Transformations could have been used to create A’B’C is Rotation of 90° upwards and Shift of 3 units up and 3 units to the right.

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Answer:

It stays open,because |−53.50| > 40

Step-by-step explanation:

His account has 53.50 dollars, so he can still pay it off. Don't get confused about the fact that he has 53.50 dollars, not owes.

Hope this helps!

Have a great day!

Answer:

use math- way for those and your other homework i promise it'll work!

Step-by-step explanation:

The number of degrees of freedom for the t-test statistics is: 58.

T tests can use t-distribution to assess statistical significance and are hypothesis tests again for mean.

Calculation for the degree of freedom;

The sample sizes drawn from two normal populations are 27 and 35.

n₁ = 27

n₂ = 35

Degree of freedom = n₁ + n₂ -1

                                = 27 + 35 - 1

Degree of freedom = 58

Therefore, the number of degrees of freedom for the t-test statistics is 58.

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Answer:

117 sweets

Step-by-step explanation:

Please see attached picture for full solution. (model method)

S, N and R represents the number of sweets Sarah, Natasha and Richard have respectively.

Alternatively,

Let the number of sweets Sarah have be 4x.

Number of sweets Natasha have= 2x

Number of sweets Richard have= 3x

Sarah gets 13 more sweets than Richard

4x= 3x +13

4x -3x= 13

x= 13

Total number of sweets

= 4x +2x +3x

= 9x (simplify)

= 9(13) (subst. x=13)

= 117 sweets

Answer:

Solution,

Given ratio= 4 : 2 : 3

Sarah has 4x sweets.

Natasha has 2x sweets.

Richard has 3x sweets.

Given,

\(3x + 13 = 4x \\ 3 x - 4 x= - 13 \\ - x = - 13 \\ x = 13\)

Now,

Total sweets:

\(4x + 2x + 3x \\ = 4 \times 13 + 2 \times 13 \times 3 \times 13 \\ = 52 + 26 + 39 \\ = 117 \: sweets\)

Hope this helps..

Good luck on your assignment...

Answer:

40

Step-by-step explanation:

The denominators are 4, 5, and 8.

Write the prime factorizations:

4 = 2²

5 = 5

8 = 2³

To find the least common denominator, multiply the prime numbers with the highest exponents.

2³ × 5 = 40

Answer:

LCD=40

EXPLANATION= To find the least common denominator first convert all integers and mixed numbers (mixed fractions) into fractions. Then find the lowest common multiple (LCM) of the denominators.

Answer:

Why might Washington have fought inequality privately instead of openly calling for an end to legal discrimination

Step-by-step explanation:

noono