Non-uniform Acceleration The acceleration of a vehicle can be expressed as: du/dt=3.6−0.06u If the vehicle speed, u, is 40ft/s at time T0 , determine the distance traveled when the vehicle has accelerated to 55ft/s. Please round your answer to the nearest foot (whole number).

Answer:

4.5m/s

Explanation:

Given parameters:

Mass of object  = 31kg

Net force  = 25N

radius  = 25m

Unknown:

Velocity  = ?

Solution:

To solve this problem, we must understand that the net force here is a centripetal force.

        F  = \(\frac{mv^{2} }{r}\)

F is the centripetal force

m is the mass

v is the velocity

m is the mass

               25  = \(\frac{31 x v^{2} }{25}\)  

               31v²   = 625

                 v²   = 20.2

                v  = 4.5m/s

Answer:The voltage V in volts (V) is equal to the current I in amps (A) times the resistance R in ohms (Ω): V (V) = I (A) × R (Ω) The power P in watts (W) is equal to the voltage V in volts (V) times the current I in amps (A): P (W) = V (V) × I (A) AC Ohm's law calculator.

Explanation:

40 ampere current passes through a 1 kW heater with 25 Voltage across it.

The difference in electric potential between two places is known as voltage, often referred to as electric pressure, electric tension, or potential difference. It relates to the amount of labor required to transfer a test charge between two places in a static electric field.

Given that power of the source is 1 kW and voltage is 25 V

current is given as,

Power = Voltage*Current

1kW = 25*Current

Current = 1000/25 = 40 ampere.

40 ampere current passes through a 1 kW heater with 25 Voltage across it.

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Answer:

-292 degrees F

Explanation:

C = 5/9( F -32)

-180 = 5/9 (F-32)

F =  -292 degrees

An object's mass rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force experienced by a body. The weight of a body can be different as it depends on where and under what conditions it is kept.

However mass is the measure of the amount of matter contained in a body and it is always constant.

Weight is defined as the amount of force exerted on a body by a moving gravitational field or any other field at the surface of the earth. It is measured in Newton (N)

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The mass density of a cube of a certain metal with 0.040 m sides and a mass of 0.48 kg is calculated by dividing the mass of the cube by the volume of the cube. The mass density is (e) 7500 kg/m³.

To find the mass density of the cube, we can use the formula:

mass density = mass / volume

Since the cube has equal sides of 0.040 m, its volume is given by:

volume = length × width × height = 0.040 m × 0.040 m × 0.040 m = 0.000064 m³

We know the mass of the cube is 0.48 kg, so we can now calculate the mass density:

mass density = 0.48 kg / 0.000064 m³ = 7500 kg/m³

Therefore, the mass density of the cube is 7500 kg/m³, and the correct answer is (e).

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The downtown is 5 miles far away, if the car travels at 10 miles / hour for 0.5 hours.

v = d / t

v = Velocity

d = Distance

t = Time

v = 10 mi / hr

t = 0.5 hr

d = v * t

d = 10 * 0.5

d = 5 mi

Velocity of the car is the rate of change of position of the car. In simple words it can be said as velocity is used to calculate the distance covered in a given amount of time.

Therefore, the downtown is 5 miles far.

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A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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Using the gravitational force, the mass of item 1 and object 2, and the Newton's law of gravity calculator, one may calculate the distance between two objects.

g = GM/r2, where M is the Earth's mass, r is its radius (or the distance from the Earth's center to where you are standing), and G is the gravitational constant. The gravitational constant is G (without the subscripts), while the speed of light is c.

By applying Newton's equation, we can accomplish this quite easily: forcegravity is defined as G M m2 separation. Suppose that you weigh 60 kilograms and your colleague weighs 70 kilograms. The center-to-centre distance, r, is 1 m, and the gravitational constant, G, is 6.67 10 -11 newtons square meter kilogram-2.

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Answer:

P V = N R T      Ideal gas equation

1 mole CO2 = 12 + 32 = 44 g

5 g = 5 / 44 = .114 moles

One definition of R is R = .08207 L-Atm / mole-deg K

P = .114 * .08207 * 298 / 10 = .279 Atmosphere

One needs to use care in using R in terms of other values given

Answer:

Doubling the large mass

Explanation:

Doubling the destance bewteen the masses will simply make the gravitational force weaker

same with every answer exce

Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Gravitational force is directly proportional to product of mass and inversely proportional to product of distance between them. So, on increasing heaver mass greatest increase in the gravitational force.

Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.

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This is the third harmonic of the standing wave on the guitar string.

In a standing wave, there are nodes (points where there is no vibration) and antinodes (points of maximum vibration). The number of antinodes in a standing wave on a guitar string is equal to the harmonic number. In this case, the guitar string is 64 cm long and has three antinodes. The distance between each antinode is equal to half a wavelength. Therefore, we can find the wavelength as: wavelength = (64 cm) / (3/2) = 42.67 cm The harmonic number is equal to the number of half-wavelengths that fit on the length of the string, which is given by:

harmonic number = 2 x length / wavelength

Substituting the given values, we get:

harmonic number = 2 x 64 cm / 42.67 cm = 2.99

Rounding to the nearest integer, we get the harmonic number as 3. Therefore, this is the third harmonic of the standing wave on the guitar string.

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When a positively charged particle moves north in a region where the magnetic field is to the east, the magnetic force on this particle is directed west.

The direction of the magnetic force can be found using the right-hand rule, which states that if the thumb of your right hand points in the direction of the particle's velocity, and your fingers curl in the direction of the magnetic field, then the direction in which your palm faces is the direction of the magnetic force.

In this scenario, the particle is moving north, so the thumb points north. The magnetic field is to the east, so the fingers curl to the east. This means that the palm of your hand faces west, which is the direction of the magnetic force on the positively charged particle.

The force acts perpendicular to both the velocity of the particle and the direction of the magnetic field.A positively charged particle moving in a magnetic field experiences a force perpendicular to both the direction of the magnetic field and the direction of its motion.

The magnitude of this force is given by the equation F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the magnetic field, and θ is the angle between the direction of the particle's velocity and the magnetic field.

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Answer:

\(\boxed {\boxed {\sf 4 \ meters}}\)

Explanation:

Gravitational potential energy can be found using the following formula:

\(E_P=m*g*h\)

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the tiger is 12.5 kilograms. The gravitational acceleration on Earth is 9.8 m/s².

\(m= 12.5 \ kg \\g= 9.8 \ m/s^2\\E_p= 490 \ kg*m^2/s^2\)

Substitute the values into the formula.

\(490 \ kg*m^2/s^2 = 12.5 \ kg * 9.8 \ m/s^2 *h\)

Multiply 12.5 kg and 9.8 m/s²

\(490 \ kg*m^2/s^2 = 122.5 \ kg *m/s^2 *h\)

Since we are trying to solve for h, we must isolate it. Since h is being multiplied by 122.5, we must divide both sides by that number because the inverse of division is the inverse of multiplication.

\(\frac{490 \ kg*m^2/s^2} { 122.5 \ kg *m/s^2}= \frac{ 122.5 \ kg *m/s^2 *h }{ 122.5 \ kg *m/s^2}\)

Note that when dividing, the kg*m/s² will cancel each other out, but a m (meter) will be left.

\(\frac{490 \ m }{122.5} =h\)

\(4 \ m =h\)

The tiger was 4 meters above the ground.

Answer:

6. Dolphins have two nasal passages

7. In a whale flipper there are:

Limbs: Cetacean flippers have the same bones as the forelimbs of other mammals. The humerus, radius, ulna, carpals, metacarpals and phalanges are all present. However, in cetaceans the radius and ulna (forearm) and humerus (upper arm) are fused.

Hope this helps! :D

Answer:

they have 2 nasal passages

In a penumbral lunar eclipse, "all parts of the moon are partly, not totally, shaded from the sun.

A penumbral lunar eclipse occurs when the Earth moves between the Sun and the Moon, but the three celestial bodies do not form a perfect line. This causes the Earth's outer shadow, called the penumbra, to fall on the Moon.

During a penumbral lunar eclipse, the Moon does not pass through the darkest part of the Earth's shadow (the umbra), so the Moon is only partly shaded from the sun, and the eclipse is usually not as noticeable as a total or partial lunar eclipse.

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According to the article, the Juno spacecraft has several observational capabilities. Juno's observational capabilities allow scientists to study Jupiter's atmosphere, magnetic field, and gravity field.

The Juno spacecraft has several observational capabilities that have been identified in various articles. Some of the observational capabilities of the Juno spacecraft are:

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Answer:

The moon does not have weather to erode the evidence of asteroid impacts.

Measurement of the distance traveled and the amount of time required to cover that distance are required in order to determine speed.

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Answer:

I do have the answer

Explanation:

The statement that rules of thumb are known as a non-traditional approach to setting standards is false. Rules of thumb are actually a traditional and informal method of making rough estimations or decisions.

Contrary to the statement, rules of thumb are not considered a non-traditional approach to setting standards. In fact, they have been used for centuries as a traditional and informal way to make rough estimations or decisions. Rules of thumb are practical guidelines or principles that are based on experience or common sense rather than precise measurements or formal procedures.

These rules are often used in various fields, such as engineering, construction, finance, and everyday life. They serve as quick and convenient methods to make approximate calculations or judgments when precise data or detailed analysis may not be available or necessary. For example, the "rule of thumb" that suggests spending around 30% of your income on housing expenses is a commonly used guideline in personal finance.

While rules of thumb can be helpful in certain situations, it's important to recognize their limitations. They are not meant to replace rigorous analysis or professional judgment. Depending solely on rules of thumb can lead to inaccuracies or oversimplifications. Therefore, they should be used with caution and in conjunction with more precise methods when necessary.

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Answer:

Explanation:

When a coil of wire is moved around a magnet, it induces electrons into the wire and creates electric current. Thus, the correct option is

moves through and cuts magnetic field lines

As the stapes bone vibrates against the oval window, it creates pressure waves that propagate through the fluid-filled cochlea of the inner ear.

These pressure waves are the initial stimulus for the process of hearing. The oval window is connected to the cochlea, which is a spiral-shaped structure responsible for converting sound waves into electrical signals that can be interpreted by the brain.

When the oval window moves in response to the vibrations of the stapes, it creates a pressure disturbance in the fluid within the cochlea. This disturbance travels through the cochlear fluid, causing the basilar membrane (a thin membrane running along the length of the cochlea) to vibrate. The basilar membrane has different mechanical properties along its length, so different regions of the membrane vibrate preferentially in response to specific frequencies of sound.

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The length of the pendulum on the moon is 26.66 times the acceleration due to gravity on the moon.

Let's assume the length of the pendulum on the moon to be Lm.Length of the pendulum on the Earth, Le = 4.44 m

Gravitational acceleration on the Earth, ge = g

Gravitational acceleration on the moon, gm = (1/6) * g

According to the given data, we can write:

T(moon) = T(earth)⇒ `2π * √(Lm/gm)` = `2π * √(Le/ge)`⇒ √(Lm/gm) = √(Le/ge)⇒ √(Lm/(1/6)g) = √(4.44/g)⇒ √(Lm/g) = √(4.44/(1/6))⇒ √(Lm/g) = √(4.44 * 6)⇒ √(Lm/g) = √(26.64)⇒ √(Lm/g) = 5.16⇒ Lm/g = 5.16² = 26.66⇒ Lm = 26.66g

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Answer:

The alkaline earth metals are the elements that correspond to group 2 of the modern periodic table. This group of elements includes beryllium, magnesium, calcium, strontium, barium, and radium. The elements of this group are quite similar in their physical and chemical properties.

Explanation:

An example where an object on Earth follows Newton's first law is a ball rolling on the ground.

Newton's first law of motion states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Examples of Newton's first law of motion;

Thus, an example where an object on Earth follows Newton's first law is a ball rolling on the ground.

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Answer:

The cumulative distance that the bird travel is 13.33 Km

Explanation:

Given that,

Velocity of runner = 3.4 km/hr

Distance = 8 km

Velocity of bird = 17 km/hr

Let x is the distance from the origin where the runner run into the bird

We need to calculate the value of x

Using time of runner and bird

\(t_{r}=t_{b}\)

\(\dfrac{d_{r}}{v_{r}}=\dfrac{d_{b}}{v_{b}}\)

Put the value into the formula

\(\dfrac{x}{3.4}=\dfrac{8+(8-x)}{17}\)

\(17x=3.4\times8+3.4(8-x)\)

\(17x=27.2+27.2-3.4x\)

\(17x+3.4x=54.4\)

\(x=\dfrac{54.4}{20.4}\)

\(x=2.67\)

We need to calculate the cumulative distance that the bird travel

Using distance of bird

\(d_{b}=16-x\)

Put the value into the formula

\(d_{b}=16-2.67\)

\(d_{b}=13.33\ km\)

Hence, The cumulative distance that the bird travel is 13.33 Km

You'll move more quickly and halt farther away thanks to gravity. To slow down to a safe speed and keep control of your car, you might need to downshift or gently apply the breaks.

Gravity aids you in stopping attempts and shortens the stopping distance when you are traveling uphill. When you are descending, gravity also works against you and lengthens your stopping distance. The next factor that can affect your braking distance is the friction between the road and your tires. The amount of time it takes to stop a moving object is related to the square of the starting speed of the vehicle and relies on how quickly it was moving before the brakes were applied. Hence, even little speed increases result in noticeably larger stopping distances. The distance covered while using the brakes is the braking distance. Speed and drag are two variables that influence it.

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The speed of flow of water at the lower level is 13.9 m/s.

The speed of flow of water at the lower level can be calculated using the equation of continuity, which states that the product of the cross-sectional area and the speed of flow of a fluid is constant in a closed system.
We can begin by using the given values for the initial speed of flow and the cross-sectional area to calculate the initial volume flow rate of water through the pipe.
Volume flow rate = speed x cross-sectional area
Volume flow rate = 27.8 m/s x 0.0004 m2
Volume flow rate = 0.01112 m3/s
Since the pipe's cross-sectional area increases by a factor of two, the cross-sectional area at the lower level is 8.0 cm2. We can use the equation of continuity to find the speed of flow at the lower level.
Volume flow rate = speed x cross-sectional area
0.01112 m3/s = speed x 0.0008 m2
speed = 13.9 m/s
Therefore, the speed of flow of water at the lower level is 13.9 m/s.

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The red wave has a greater amplitude because its height is greater than the height of the blue wave.

Both waves have the same wavelength because the distance between crests is the same.

They have the same frequency  because they are traveling at the same rate.

The amplitude of a periodic variable is described as a measure of its change in a single period.

The amplitude of a non-periodic signal is also its magnitude compared with a reference value.

We can say that the amplitude is half the distance between the maximum and minimum height.

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