Norma owns and operates an accounting business as a sole proprietor. She purchased several computers at a cost of $9,000 for use in her business. Her business produced $120,000 of net income. Assume that she purchased the computers (5-year property) and placed them into service on January 11th of the current year. What is the amount of the cost recovery deductions for the first 3 years under MACRS? [The MACRS Table is shown under Course Supplement Materials.] (Be sure to show your work). Calculate the cost recovery deduction for the first 3 years if Norma elects straight-line depreciation. (Show your work). What is the cost recovery deduction she can use for each year under Section 179?

You would expect to find the middle 98% of most averages for the lengths of pregnancies in the sample between approximately 264.0 days and 274.1 days.

To find the range in which you would expect to find the middle 98% of most pregnancies, you can use the concept of z-scores and the standard normal distribution.

For the given data:

Mean (μ) = 269 days

Standard deviation (σ) = 17 days

To find the range, we need to find the z-scores corresponding to the 1% and 99% percentiles. Since the normal distribution is symmetric, we can find the z-scores by subtracting and adding the respective values from the mean.

To find the z-score for the 1% percentile (lower bound):

z1 = Φ^(-1)(0.01)

Similarly, to find the z-score for the 99% percentile (upper bound):

z2 = Φ^(-1)(0.99)

Now, we can calculate the z-scores:

z1 = Φ^(-1)(0.01) ≈ -2.33

z2 = Φ^(-1)(0.99) ≈ 2.33

To find the corresponding values in terms of days, we multiply the z-scores by the standard deviation and add/subtract them from the mean:

lower bound = μ + (z1 * σ) = 269 + (-2.33 * 17) ≈ 229.4 days

upper bound = μ + (z2 * σ) = 269 + (2.33 * 17) ≈ 308.6 days

Therefore, you would expect to find the middle 98% of most pregnancies between approximately 229.4 days and 308.6 days.

Now, let's consider drawing samples of size 58 from this population. The mean and standard deviation of the sample means can be calculated as follows:

Mean of sample means (μ') = μ = 269 days

Standard deviation of sample means (σ') = σ / sqrt(n) = 17 / sqrt(58) ≈ 2.229

To find the range in which you would expect to find the middle 98% of most averages for the lengths of pregnancies in the sample, we repeat the previous steps using the mean of the sample means (μ') and the standard deviation of the sample means (σ').

Now, calculate the z-scores:

z1 = Φ^(-1)(0.01) ≈ -2.33

z2 = Φ^(-1)(0.99) ≈ 2.33

Multiply the z-scores by the standard deviation of the sample means and add/subtract them from the mean of the sample means:

lower bound = μ' + (z1 * σ') = 269 + (-2.33 * 2.229) ≈ 264.0 days

upper bound = μ' + (z2 * σ') = 269 + (2.33 * 2.229) ≈ 274.1 days

Therefore, you would expect to find the middle 98% of most averages for the lengths of pregnancies in the sample between approximately 264.0 days and 274.1 days.

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Answer:

?

Step-by-step explanation:

Answer:

On a full tank of gas, Tommy can drive a distance:

D = 22 x 16 = 352 miles

Hope this helps!

:)

Answer:352 miles

Step-by-step explanation:

1 gallons for 16 miles

22 gallons for ______

For 22 gallons 22x16=352 miles

Answer:

3

Step-by-step explanation:

given

3 + 11t - 9u

if t = 9, and u = 11, substitute these numbers into the equation:

3 + 11(9) - 9(11)

= 3 + 99 - 99

= 3

Answer: 3

Step-by-step explanation:

3+11t-9u=3+11(9)-9(11)

            =3+99-99

            =102-99

            =3

Therefore, both sequence A and sequence B can be used to map EFGH onto ABCD, so the answer is C) Both.

In mathematics, a transformation is a process of changing the position, size, or shape of a geometric figure. Transformations can be performed on two-dimensional or three-dimensional objects and include operations such as translation, rotation, reflection, scaling, and shearing. Translation involves moving an object in a straight line without rotating it. Rotation involves turning an object around a fixed point. Reflection involves flipping an object across a line or plane of symmetry. Scaling involves changing the size of an object, making it larger or smaller. Shearing involves distorting an object by pushing or pulling one of its sides. Transformations are often used in geometry and in other areas of mathematics and science to explore the properties of objects and to solve problems related to symmetry, similarity, and congruence. They are also used in computer graphics, animation, and other areas of computer science to create and manipulate images.

Here,

Both sequences of transformations can be used to map quadrilateral EFGH onto ABCD.

To see why, consider that a -90⁰ rotation about point H followed by a translation along HD will map H to A, E to D, F to C, and G to B. Similarly, a -90⁰ rotation about point F followed by a translation along FA will map F to A, G to D, H to C, and E to B.

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Answer:

  (A)  Only sequence A

Step-by-step explanation:

You want the sequence of transformations that maps parallelogram EFGH to ABCD.

We note that segment EF points to the right, and corresponding segment AB points down. The rotation required to change the direction in that way is a rotation of -90°, that is, 90° CW.

The translation that will work in this context is translation of the center of rotation to its corresponding point on the image. The given choices of center are ...

Point H corresponds to point D, so the translation vector would need to be HD after rotation about point H. This matches sequence A.

Point F corresponds to point B, so the translation vector would need to be FB after rotation about point F. Sequence B erroneously has the vector as FA.

Only sequence A maps EFGH to ABCD, choice A.

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Answer:

\(A= \frac{4}{3 + \sqrt{5} } - \frac{8}{1 + \sqrt{5} } + \frac{15}{ \sqrt{5} } \)

\( = \frac{4(3 - \sqrt{5)} }{4} - \frac{8(1 - \sqrt{5} }{ - 4} + \frac{15 \sqrt{5} }{5} = 3 - \sqrt{5 + 2 - 2 \sqrt{5 + 3 \sqrt{5 = 5} } } \)

Step-by-step explanation:

\(Cảm \: ơn!!!!\)

Angles and lines come in many distinct varieties in geometry.

Geometry has several different kinds of lines and angles. The six different types of angles include reflex angle, complete angle, straight angle, acute angle, and obtuse angle. The various sorts of lines are transverse, parallel, perpendicular, vertical, horizontal, and vertical lines.

There are three ways to name an angle: by the vertex, by the angle's three points (the middle point must be the vertex), or by a letter or number put inside the angle's aperture.

You can create your address block for letters, envelopes, and other mail merges using Label Lines, a collection of fields. Use Label Lines rather of Acknowledgement, Company, and Address lines to skip blank lines in your labels and address blocks.

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Derrick will receive total of $340 from all of his deductions

To create a histogram for these values using four classes, we must first determine the class width, which is determined as the data range divided by the number of classes. The data range is 151 - 58 = 93, which is the difference between the biggest and smallest numbers. The breadth of the class is 93/4 = 23.25. We'll round it up to 24 because we can't have a fractional class width.

Then, for each of the four classes, we'll start with the smallest number (58) and add the class width (24) again until we reach the maximum value (151). The lowest class boundaries for the four classes are as follows:

Class 1: 58

Class 2: 82

Class 3: 106

Class 4: 130

We'll determine the upper class limit for each lower class limit by adding the class width (24) - 1. The upper class restrictions are as follows:

Class 1: 81

Class 2: 105

Class 3: 129

Class 4: 153

Finally, we'll tally the amount of deductions made in each class and utilise that data to create the histogram. Each class has the following number of deductions:

Class 1: 1 (58)

Class 2: 3 (97, 98, 101)

Class 3: 3 (103, 127, 144)

Class 4: 3 (144, 151, 65)

We can compute the total amount Derrick will earn from all of his deductions now that we know the number of deductions in each class. He will earn $25 for each deduction of less than $130, and $45 for each deduction of $130 or more.

Derrick will receive the following total from all of his deductions:

$25 * 1 (for the single deduction of less than $130) + $45 * 7 (for the seven deductions of $130 or over) = $25 + $315 = $340

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On the vertical number line, negative numbers are to the bottom of 0. Therefore, -1/4 will go one unit down from 0.

On the horizontal number line, negative numbers are to the left of 0. Therefore, -1/4 will go to the left one unit.

Best of Luck!

Answer:

50 + 25 = 75

50 - 25 = 25

The numbers are 50 and 25

Step-by-step explanation:

The sum of two numbers is 25 and their difference is 75. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 25. In other words, x plus y equals 25 and can be written as equation A:  

x + y = 75

The difference between x and y is 75. In other words, x minus y equals 75 and can be written as equation B:

x - y = 75

Now solve equation B for x to get the revised equation B:  

x - y = 25

x = 25 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 75

25 + y + y = 75

25 + 2y = 75

2y = 50

y = 25

Now we know y is 25. Which means that we can substitute y for 25 in equation A and solve for x:

x + y = 75

x + 25 = 75

X = 50

Therefore,

Sum: 50 + 25 = 75

Difference: 50 - 25 = 25

Hope this helps! :D

Answer:

y=8/3x-4

Step-by-step explanation:

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Answer:

Step-by-step explanation:

8x-3y=12

-3y=12-8x

y=(12/-3)-8x/(-3)

y= -4+8/3x

slope= 8/3

y-int=-4

The algorithm justifies the answer of 3/5 as the fraction each person gets.

Representation of the fractions on the second row:

From what you described, two of the loaves were divided into thirds.

This means each person receives one third, and there is one third remaining. Then, this remaining third from the second loaf was further divided into fifths.

Therefore, each person receives one fifth from this remaining third.

So, the representation of the fractions on the second row would be:

Each person receives 1/3 (one third) from the two loaves.

Each person receives 1/5 (one fifth) from the remaining third.

Algorithm/Abstract strategy to justify the 3/5 found as the answer:

To find the final answer of 3/5, we can follow the steps you provided:

Divide two loaves into thirds, giving each person 1/3.

Divide the remaining third from the second loaf into fifths, giving each person 1/5.

Combining the fractions, each person has 1/3 + 1/5.

To add these fractions, we need to find a common denominator. In this case, the least common multiple (LCM) of 3 and 5 is 15. We can convert 1/3 and 1/5 to have a denominator of 15:

1/3 = 5/15 (multiplying numerator and denominator by 5)

1/5 = 3/15 (multiplying numerator and denominator by 3)

Now, we can add the fractions:

5/15 + 3/15 = 8/15

Therefore, each person receives 8/15 of a loaf.

Simplifying this fraction, we get 3/5.

Hence, the algorithm justifies the answer of 3/5 as the fraction each person gets.

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Answer:

\(528\ cm^2\)

Step-by-step explanation:

1. Approach

The surface area is the two-dimensional space around a three-dimensional object. In other words, if one was going to wrap an object with paper, the surface area is the amount of paper one would need. To find the surface area, one could find the area of each face of the prism and then add up all of the values.

2. Finding the surface area,

To find the area of each face of the prism, one must multiply the length of the face by the width of the face. After doing so, add up all of the resulting values.

10 * 20 = 200

8 * 20 = 160

6 * 20 = 120

\(\frac{1}{2}\) * 6 * 8 = 24

\(\frac{1}{2}\) * 6 * 8 = 24

Add up all of the values,

200 + 160 + 120 + 24 + 24

= 528

Answer:

Step-by-step explanation:

W=\(\sqrt{x-a/a}\)

squaring both sides

W^2=(\(\sqrt{x-a/a}\) )^2

W^2=x-a/a

wa=x-a

a=x-a/w

\( \boxed{\boxed{\huge{ \mathrm{  \underline{ Answer} \:  \:  ✓ }}}}\)

_____________________________

\(\mathrm{ ☠ \: TeeNForeveR \:☠ }\)

Peter left Town A around 10 a.m., traveling at an average speed of 84 km/h. William would reach Town B at 1:23 PM.

Firstly, we need to find the distance between Town A and Town B which can be calculated by calculating the distance travelled by Peter

Time taken by Peter = 2PM - 10AM

= 4 hrs

Speed of Peter = 84 km/h

Distance travelled by Peter = speed × time

= 84 × 4

= 336 km

So, the distance between Town A and Town B  = distance travelled by Peter = 336 km.

Now, we will calculate time taken by William.

Speed of William = 70 km / hr

Distance travelled by William = distance between Town A and town B = 336 km

Time taken by William = distance / speed

= 336 / 70 hr

= 4.8 hr

This can b converted into hrs and minutes

4.8 hr = 4 hr + 0.8 × 60

= 4 hr 48 mins

Time William took off = 10 AM - 1hr 25 mins

= 8:35 AM

Now, we will calculate the time William would reach town B.

Time = 8:35 + 4hr 48 mins

= 1:23 PM

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Answer:

594

Step-by-step explanation:

A=πrl+πr²

(22/7×9×12)+(22/7×9²)

=594

Answer:

mAngleY < mAngleZ < mAngleX

Answer:I think it Is the second

Step-by-step explanation:

Answer:

ITS 15 THANK ME LATER!!!!

Step-by-step explanation:

Answer:

M = 1/5

Step-by-step explanation:

Did you ever get the answer

The five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

Measures of statistical dispersion, or the spread of the data, include the interquartile range. In addition to the IQR, other names for it include the midspread, middle 50%, fourth spread, and H-spread.

To find the five-number summary and interquartile range for this data set, we first need to find the quartiles.

Step 1: Find the median (Q2)

When a data collection is sorted from least to largest, the median is the midway value. Since there are 12 values in this data set, the median is the average of the sixth and seventh values:

Median (Q2) = (41 + 46)/2 = 43.5

Step 2: Find the lower quartile (Q1)

The lower quartile is the median of the lower half of the data set. Since there are 6 values below the median, we take the median of those values:

Q1 = (32 + 32)/2 = 32

Step 3: Find the upper quartile (Q3)

The upper quartile is the median of the upper half of the data set. Since there are 6 values above the median, we take the median of those values:

Q3 = (50 + 51)/2 = 50.5

Now we have all the information we need to construct the five-number summary and interquartile range:

Minimum: 29

Lower quartile (Q1): 32

Median (Q2): 43.5

Upper quartile (Q3): 50.5

Maximum: 53

Interquartile range (IQR) = Q3 - Q1 = 50.5 - 32 = 18.5

the five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

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The most appropriate choice for area of rectangle will be given by -

Area of classroom = \(4\frac{27}{40}\) \(m^2\)

What is area of rectangle?

Rectangle is a four sided figure whose parallel sides are equal and whose every angle is 90°

The total space taken by the rectangle is called area of the rectangle.

If the length of the rectangle be l and the breadth of the rectangle be b, then area of the rectangle is given by

Area = \(l \times b\)

Here,

Length of classroom = \(6\frac{4}{5}\) m = \(\frac{34}{5}\) m

Width of classroom = \(1\frac{3}{8}\) m = \(\frac{11}{8}\) m

Area of classroom = \(\frac{34}{5} \times \frac{11}{8}\)

                               = \(\frac{187}{40}\)

                               = \(4\frac{27}{40}\) \(m^2\)

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Answer:

option C. is correct answer it is 2/5

Answer:

$237.75

Step-by-step explanation:

you add $305 & $250.25 together which is equal = $555.25,then subtract $317.50 from it = $237.75

The expression that is not rational is the first one:

\(f(x) = \frac{6x}{4}\)

A rational expression is something of the form:

\(f(x) = \frac{q(x)}{p(x)}\)

Such that q(x) can be any polynomial, and p(x) is a polynomial of at least degree 1.

This means that we need to have the variable "x" on the denominator.

Then is easy to recognize the expression that is not rational, is the one that does not have x on the denominator, which is the first one:

\(f(x) = \frac{6x}{4}\)

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Answer: B

Step-by-step explanation:

I took the test and this was the correct answer

La altura del cono es de 8 centimetros.

Sabemos que para un cono de radio R, altura H, y generatriz G se cumple la relación:

R^2 + H^2 = G^2

Resolviendo para la altura obtenemos:

H = √(G^2 - R^2)

En este caso sabemos que le diámetro es de 30 cm, entonces el radio será de:

R = 30cm/2 = 15cm

Y la generatriz es de 17cm, entonces G = 17cm

Reemplazando eso en la ecuación para la altura obtendremos:

H = √((17cm)^2 - (15cm)^2) = 8cm

Concluimos que la altura del cono es de 8 centimetros.

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The required probability of not getting all tails is  2037 / 2048.

Given that,
If you flip 11 coins, the probability of not getting all 11 tails is to be determined.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

The process in mathematics to operate and interpret the function to make function simple or more understandable called simplify and the process is called simplification.

Since each coin has 2 possible outcomes for a single toss i.e either head or tail.

Total number of sample spaces for the 11 coins to be tossed = 2^11 = 2048
The number of favorable outcomes for all tails = 11
Probability of not getting all 11 tails = 1 - probability of all are tails
                                                    = 1 - 11 / 2048
                                                    = 2037 / 2048

Thus, the required probability of not getting all tails is  2037 / 2048.

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There were 8 slices in the whole pizza.

An equation means the formula that expresses the equality of two expressions by connecting them with the equals sign =.  Let us assume the number of slices in the whole pizza is "x".

Since Jim ate two slices which is 25% of the pizza, we will set up the equation:

2 = 0.25x

To solve for "x":

2 / 0.25 = x

x = 8.

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