On Earth, we experience lunar and solar eclipses. what types of eclipses (if any) would an inhabitant of the moon experience? Explain.

Answers

Answer 1

Answer:

However, those astronauts would experience a second spectacle: A solar eclipse caused by the Earth – the Sun disappearing behind the dark disc of the Earth. When Earth inhabitants witness a lunar eclipse, Moon inhabitants would, simultaneously be witnessing a solar eclipse.


Related Questions

On a warm summer day, a large mass of air (atmospheric pressure 1.01×105Pa) is heated by the ground to a temperature of 25.0 ∘C and then begins to rise through the cooler surrounding air. Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×104 Pa. Assume that air is an ideal gas, with γ=1.40. (This rate of cooling for dry, rising air, corresponding to roughly 1 ∘C per 100 m of altitude, is called the dry adiabatic lapse rate.)

Answers

The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.

Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:

(1.01×10⁵ Pa)×V = (nR/T1)×T1(8.70×10⁴ Pa)×V = (nR/T2)×T2

Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:

(T2/T1) = [(P2/P1)^(γ-1)/γ] = [(8.70×10⁴ Pa)/(1.01×10⁵ Pa)]^(1.4/1.4) = 0.813

Solving for T2, we get:

T2 = T1×(P2/P1)^(γ-1)/γ = (25+273) K×0.813 ≈ 287.3 K ≈ 14.3°C

Thus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

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People who do very detailed work close up, such as jewellers, often can see objects clearly at much closer distance than the normal 25 cm. Assume that the lens-to-retina distance is 2.00 cm.

(a) What is the power of the eyes of a woman who can see an object clearly at a distance of only 8.00 cm?

(b) What is the size of an image of a 1.00 mm object, such as lettering inside a ring, held at this distance?

(c) What would the size of the image be if the object were held at the normal 25.0 cm distance?

Answers

(a) The power of the eyes of a woman who can see an object clearly at a distance of only 8.00 cm is 0.5 diopters. (b) The size of an image of a 1.00 mm object, such as lettering inside a ring, held at this distance is -0.25 mm. (c) The size of the image if the object were held at the normal 25.0 cm distance is -0.08 mm.

The power of the eyes of a woman who can see an object clearly at a distance of only 8.00 cm can be calculated using the formula P = 1/f, where P is the power of the lens and f is the focal length of the lens. In this case, the focal length is the distance from the lens to the retina, which is 2.00 cm. Therefore, the power of the eyes is:

P = 1/2.00 cm = 0.5 diopters

The size of an image of a 1.00 mm object, such as lettering inside a ring, held at this distance can be calculated using the formula m = -di/do, where m is the magnification, di is the distance from the image to the lens, and do is the distance from the object to the lens. In this case, di is 2.00 cm and do is 8.00 cm. Therefore, the magnification is:

m = -2.00 cm/8.00 cm = -0.25

The size of the image is then:

size = m x object size = -0.25 x 1.00 mm = -0.25 mm

The size of the image if the object were held at the normal 25.0 cm distance can be calculated using the same formula, with do = 25.0 cm. Therefore, the magnification is:

m = -2.00 cm/25.0 cm = -0.08

The size of the image is then:

size = m x object size = -0.08 x 1.00 mm = -0.08 mm

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3500 as a power of 10​

Answers

Answer: 3.5 × 10^3

Explanation:

Two objects (48.0 and 25.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley hangs from the ceiling. Find (a) the acceleration of the objects and (b) the tension in the string.

Answers

Answer:

a. 3.09 m/s^2

b. 322.52 N

Explanation:

The computation of the acceleration of the object and the tension of the string is as follows:

The acceleration of the system is a

= (m1 - m2) × g ÷ (m1 + m2)

= (48 - 25) × 9.81 ÷ (48 + 25)

= 3.09 m/s^2

b. The tension in the string is T

= 2 × m1 × m2 × g÷   (m1+m2)

= (2  × 48  × 25  ×  9.81) ÷  (48 + 25)

= 322.52 N

Select the correct answer.
Which graph shows the correct relationship between kinetic energy and speed?

Select the correct answer.Which graph shows the correct relationship between kinetic energy and speed?

Answers

Answer:

c

Explanation:

It's c the last one u see

a shiny object reflects light. will a shiny object make a shadow when light shine on it? explain your answer​

Answers

Answer:

yes I think it is possible

Yes the shiny object will surely make a shadow if there is a source of light and there is a screen because when the path is obstruct by an opaque object a shadow is formed. The shiny object will reflect light but wont allow light to pass through it which makes it an opaque object and it produces a shadow.

Write the word conductor or insulator on each of the lines. Then infer which type of material is inside the holes in the outlet. Explain you answer.
( will mark brainliest if you help.)

Write the word conductor or insulator on each of the lines. Then infer which type of material is inside

Answers

Inside the "holes" are springy brass fingers which grip the plug prongs when you insert the wall plug, leading to connection with your home's electrical system.

The required choice is for both the lines are conductor and conductor.

What is conductor and insulator?

A conductor is something that easily allows current to flow through it. As an example, consider metal or any other metal. An insulator is something that does not allow current to travel through it. Polyurethane is an example.

Here,
Inside each socket are two pairs of metal strips that are engineered to bend and flex but return to their original shape when pressure is released. Each pair of strips is linked to one of your power lines (either hot or ground).


When you insert the wall plug, springy brass fingers hold the plug prongs, allowing you to connect to your home's electrical system.

Thus, the required choice is for both the lines to be conductor and conductor.

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Maria read on an internet blog that infrared light is dangerous to humans. According to the blog, infrared light exposure is responsivle for a number of detrimental effects in humans. Which of these can actually be caused by exposure to infrared light?
a-overheating
b-skin cancer
c-radiation sickness
d-memory less

Answers

Of the options listed, the only effect that can be caused by exposure to infrared light is overheating (option a).

Infrared light is a form of electromagnetic radiation that is invisible to the human eye but can be detected as heat. When exposed to high levels of infrared light, such as in close proximity to a powerful infrared source, it can lead to overheating of the body or objects. Skin cancer (option b) is not directly caused by infrared light. It is primarily associated with overexposure to ultraviolet (UV) radiation from the sun or artificial sources like tanning beds. UV radiation falls in the higher energy range of the electromagnetic spectrum, while infrared radiation has lower energy. Radiation sickness (option c) is caused by exposure to high-energy ionizing radiation, such as gamma rays or X-rays. Infrared light does not possess enough energy to cause ionization and is therefore not capable of inducing radiation sickness. Memory loss (option d) is not a known effect of exposure to infrared light. Memory loss can be attributed to various factors, such as neurological conditions, head injuries, or aging, but not specifically to infrared light exposure. In summary, while exposure to high levels of infrared light can lead to overheating, it does not cause skin cancer, radiation sickness, or memory loss.

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What unit of measure is used to measure temperature?
a. Joules
b. Fahrenheit
c. Meters
d. Liters

Answers

Answer:

B. Fahrenheit measures temperature!

The phase angle in a circuit is 45° what's the power factor of the circuit

Answers

Answer:the power factor of the circuit is 96% to 75%

Explanation:

How do we use energy transformation in our daily lives?

Answers

Answer:hat are some examples of energy transformation?

The Sun transforms nuclear energy into heat and light energy.

Our bodies convert chemical energy in our food into mechanical energy for us to move.

An electric fan transforms electrical energy into kinetic energy.

Explanation:

We pick up cups and place them in different places

A mass of M-kg rests on a frictionless ramp inclined at 30°. A string with a linear mass density of μ=0.025" kg/m" is attached to the M-kg mass. The string passes over a frictionless pulley of negligible mass and is attached to a hanging mass (m). The system is in static equilibrium. A wave is induced on the string and travels up the ramp.

(a) Show that the mass of M is equal to twice the mass of the hanging mass: M = 2m.
(b) and at what wave speed does the wave travel up the string, if m = 5 kg?

A mass of M-kg rests on a frictionless ramp inclined at 30. A string with a linear mass density of =0.025"

Answers

Answer:

44.3 m/s

Explanation:

a) Draw a free body diagram of the mass M.  There are three forces:

Weight force mg pulling down,

Normal force N pushing perpendicular to the ramp,

and tension force T pulling parallel up the ramp.

Sum of forces in the parallel direction:

∑F = ma

T − Mg sin 30° = 0

T = Mg sin 30°

T = Mg / 2

Draw a free body diagram of the hanging mass m.  There are two forces:

Weight force mg pulling down,

and tension force T pulling up.

Sum of forces in the vertical direction:

∑F = ma

T − mg = 0

T = mg

Substitute:

mg = Mg / 2

m = M / 2

M = 2m

b) Velocity of a standing wave in a string is:

v = √(T / μ)

T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N.  Therefore:

v = √(49 N / 0.025 kg/m)

v = 44.3 m/s

How has the expansion of the universe affected the cosmic microwave background radiation?
A. It has caused it to heat up.
B. It has caused it to cool.
C. It has caused it to blue shift.
D. It has caused it to red-shift.

Answers

Answer:

The expansion of the universe has caused cosmic microwave background radiation to cool. As the universe expands, the radiation is stretched out, causing its wavelength to increase and its temperature to decrease. This phenomenon is known as cosmic microwave background radiation redshift.

the answer is D. It has caused it to red-shift.

Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.

Answers

The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

How to find displacement ratio?

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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Please help me with this and if I have good answer u will be marked as brilliant !!!!

Please help me with this and if I have good answer u will be marked as brilliant !!!!

Answers

Number one- numbers of items sold. Number two- Thursday and Friday. Number three- 1,200. Number four-150

Describe the role of the teacher and the learner in a natural science and technology classroom​

Answers

Teacher -> teach the topic
Learner -> learn the topic
Is that what you’re asking?

Students are instructed in subject-specific classes by science professors. They develop lesson plans, assess student performance, and educate using lectures, technology.

What are the characteristics of a good teacher?

The teacher who gives their best in order to develop the skills in all student of their class. A good teacher has to be a great command of his/her subjects.

He/she has to put their effort to improve the weak student of the class as well must appreciate the effort of good students.

The role of the teacher and the learner in a natural science and technology classroom​ is;

Students are instructed in subject-specific classes by science professors. They develop lesson plans, assess student performance, and educate using lectures, technology,

They also serve as role models for anticipated conduct in order to develop and maintain an ordered, disciplined classroom.

They must also be analytical since they must analyze kids' development and modify lesson plans for special-needs children.

They may create and sustain interpersonal ties with students, parents, other staff members, and administrators.

Hence the role teacher is to instruct the student, maintain discipline and educate using technology.

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A 55kg skateboarder wants to just make it to the upper edge of a quarter pipe, a pipe that is one-quarter of a circle with a radius of 3.10m. What speed does he need at the bottom?

Answers

Answer:

Explanation:

A 52.0 kg skateboarder wants to just make it to the upper edge of a "quarter pipe," a track that is one-quarter of a circle with a radius of 2.60 m .

What speed does he need at the bottom

Let the lowest point of the circle = (0,0)

Center of circle = (0, 2.6)

The height of the circle = 2 * radius = 2 * 2.60 = 5.20 m

Highest point = (0, 5.2)

As the skateboarder moves around ¼ of a vertical circle, the skateboarder moves from the lowest position to a position that is ½ the way up to the highest position. This is the point that is 2.6 meters directly to the right of left of the center = (2.6, 2.6)

As the skateboarder has moved 2.6 m upward, the potential energy increase = m * g * ∆h = 52.0 * 9.8 * 2.6

During this same time, the kinetic energy decreased from the maximum to 0. The decrease of KE = the increase of PE

½ * m * ∆v^2 = m * g * ∆h

½ * 52 * ∆v^2 = 52.0 * 9.8 * 2.6

½ * ∆v^2 = 9.8 * 2.6

∆v = (2 * 9.8 * 2.6)^0.5 = 7.14 m/s

The velocity at highest point, (2.6,2.6) is 0 m/s

So the velocity at the lowest point must be 7.14 m/s

Let’s see if the skateboarder has enough KE to move upward 2.6 m.

KE at bottom = ½ * 52 * 7.14^2 = 1325.5

PE = 52 * 9.8 * h

52 * 9.8 * h = 1325.5

h = 2.6 m

The answer is OK

The speed needed by the skateboarder at the bottom is 7.8 m/s.

The given parameters;

mass of the skateboarder, m = 55 kgradius of the quarter pipe, r = 3.1 m

Apply the principle of conservation of mechanical energy to determine the sped of the skateboarder at the bottom;

\(P.E_{top} = K.E_{bottom}\\\\mgh = \frac{1}{2}mv^2\\\\gh = \frac{1}{2} v^2\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2\times 9.8 \times 3.1} \\\\v = 7.8 \ m/s\)

Thus, the speed needed by the skateboarder at the bottom is 7.8 m/s.

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You decide to do an experiment to investigate Newton's Third Law. Below are several
example experiments you might run to help investigate your questions. Which one of the
following examples below are not related to Newton’s Third Law?
A. You and a friend push on each other’s hands while wearing roller blades and
observe the force of the shove.
B. You set a ball on the ground and observe the force of gravity on the ball
C. You stand on the bathroom scale and then decide to jump off and observe the
change in the reading.
D. You drive a remote-controlled car and observe the force at work

Answers

Answer:

C

Explanation:

You stand on the bathroom scale and then decide to jump off and observe the

change in the reading.

WHAT IS THE MEAING OF- Grouping Data​

Answers

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis
ball moving 30 m/s to the left. After the collision, the tennis ball is moving 34
m/s to the right. What is the velocity of the basketball after the collision?
Assume an elastic collision occurred.
O A. 11.4 m/s to the left
O B. 11.4 m/s to the right
O C. 1.4 m/s to the right
O D. 1.4 m/s to the left

Answers

Answer:

1.4 m/s to the left

Explanation:

just took it c:

Ultraviolet light of wavelength 270 nm strikes a metal whose work function is 2.3 eV.What is the shortest de Broglie wavelength for the electrons that are produced as photoelectrons?

Answers

Answer:

The shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm

Explanation:

Given;

wavelength of ultraviolet light, λ = 270 nm

work function of the metal, φ = 2.3 eV = 2.3 x 1.602 x 10⁻¹⁹ J = 3.685 x 10⁻¹⁹ J

The energy of the ultraviolet light is given by;

\(E = \frac{hc}{\lambda}\\\\E = \frac{(6.626*10^{-34} )(3*10^{8}) }{270*10^{-9} }\\\\E = 7.362 * 10^{-19} \ J\)

The energy of the incident light is related to kinetic energy of the electron and work function of the metal by the following equation;

E = φ  + K.E

K.E = E - φ

K.E = (7.362 x 10⁻¹⁹ J) - (3.685 x 10⁻¹⁹ J )

K.E = 3.677 x 10⁻¹⁹ J

K.E = ¹/₂mv²

mv² = 2K.E

velocity of the electron is given by;

\(V = \sqrt{\frac{2K.E}{m} }\\\\V = \sqrt{\frac{2(3.677*10^{-19}) }{9.1*10^{-31} } }\\\\V = 8.99*10^{5} \ m/s\)

the shortest de Broglie wavelength for the electrons is given by;

\(\lambda = \frac{h}{mv}\\ \\\lambda = \frac{6.626*10^{-34} }{(9.1*10^{-31})( 8.99*10^{5} )}\\\\\lambda = 8.10*10^{-10} \ m\\\\\lambda = 0.81 \ nm\)

Therefore, the shortest de Broglie wavelength for the electrons that are produced as photoelectrons is 0.81 nm

A motorcycle travels, in one direction only, with an average speed of 916.66 m/min during the first 30 minutes of its travel and 900 m/min during the next 20 minutes.
Calculate (Units must be in units of the international system):
a. The total distance traveled.
b. The average speed.

Answers

Explanation:

a. To calculate the total distance traveled, we need to find the distance traveled during the first 30 minutes and the distance traveled during the next 20 minutes, and then add them up.

During the first 30 minutes:

distance = speed × time

distance = 916.66 m/min × 30 min

distance = 27,499.8 meters

During the next 20 minutes:

distance = speed × time

distance = 900 m/min × 20 min

distance = 18,000 meters

Total distance traveled:

distance = 27,499.8 meters + 18,000 meters

distance = 45,499.8 meters

Therefore, the total distance traveled is 45,499.8 meters.

b. To calculate the average speed, we need to divide the total distance traveled by the total time taken.

Total time taken:

time = 30 min + 20 min

time = 50 min

Average speed:

speed = distance ÷ time

speed = 45,499.8 meters ÷ 50 min

speed = 909.996 m/min

Therefore, the average speed is 909.996 m/min.

If you walk at an average speed of 5 km/h for 30 minutes. How far will you walk ?

Answers

2.5 km
an hour = 60 minutes
30 minutes = 1/2 of 60 minutes
therefore 5/2 = 2.5

The distance walked is 2500 m.

To find the distance, the given values are,

Average speed = 5 km /hr

Time = 30 minutes.

What is the distance?The distance covered by a body is equal to the sum of total path covered i.e., the total speed with respect to particular time. It is equal to the total path traveled by an object during its entire journey.This quantity is always positive. It can't be 0 or a negative number.It is defined as a scalar quantity. A scalar quantity represents only the magnitude and does not give any detail about the direction of the quantity. Distance can be measured in any length also in any direction (no specific direction)

Mathematically, it can be calculated as follows :

     Distance = speed × time

Substituting the given values are,

Distance = 5 km / hr × 30 minutes

               = 2500 m.

The distance walked is 2500 m.

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2. Which of the following items would be the WORST conductor of electricity?
A. A steel rod
B. A copper wire
C. An aluminum bat
D. A rubber band

Answers

Answer: a rubber band

Explanation: A rubber band has no conductivity and no electricity would be able to flow whereas steel and copper and aluminum would be able to allow electricity to flow due to how they are built

If
you push on a box but the box moves backward, you have done
work.
Answer here

Answers

No you have not done work, if you had done work the box would be moving forward not backwards. Hope this helped

A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?

Answers

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.

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what change occurs to the mass of an object when a unbalanced

Answers

Answer:

The mass decreases

Explanation:

Just smart

A flask is filled with 1.57 L (L: liter) of a liquid at 90.6 °C. When the liquid is cooled to 10.2 °C, its volume is only 1.38 L. however. Neglect the contraction of the flask. What is the coefficient of volume expansion of the liquid?

Answers

The coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

What is the coefficient of volume expansion of the liquid?

The amount of volume that a substance expands by per unit of its original volume for each degree that its temperature rises is known as the coefficient of volume expansion.

As we know, The coefficient of volume expansion of the liquid

= change in volume/(original volume × temperature difference)

= (V₂ - V₁)/[V₁ × (T₂ - T₁)]

Change in volume = (V₂ - V₁)

Here, V₂ ( final volume) = 1.31 L

V₁  (initial volume)= 1.55 L

T₂ (final temperature) = 14.7 degrees

T₁ (initial temperature) = 96 degrees

The coefficient of volume expansion of the liquid

= (1.31 - 1.55) / [1.5 × (14.7- 96)]

= 1.97 × 10⁻³ /⁰C

Thus, the coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

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1. Two point charges, q1 and q2, are located 5 cm apart. The magnitude of q1 is 3 μC and the magnitude of q2 is -5 μC. What is the force between these charges, according to Coulomb's law?

Answers

The force between these charges, according to Coulomb's law would be -54 N.

We can solve this problem applying "Coulomb's Law" which states-

\(\qquad\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ \)

\( \qquad\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

Where-

q₁ and q₂ are the two cahrges.r is the distance between the charges.\(\sf \epsilon_{0} \) is the permittivity of free space.K is the Coulomb's Constant.k = 9×10⁹ Nm²/C²

According to the given parameters -

Magnitude of q₁= 3 μCMagnitude of q₂= -5 μCDistance,r = 5cm

Now that required values are given, so we can plug the values into the formula and solve for Force -

\(\qquad\qquad \:\sf\underline{Force = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

\( \longrightarrow \sf Force = 9\times 10^9 \times \dfrac{ 3\times 10^{-6}\times -5 \times 10^{-6}}{\bigg(5\times 10^{-2}\bigg)^2}\\ \)

\( \longrightarrow \sf Force = -\dfrac{9\times 5\times 3\times 10^{9} \times 10^{-12}}{25\times 10^{-4}}\\ \)

\( \qquad\longrightarrow \sf Force =- \dfrac{135 \times 10^{9-12+4}}{25}\\ \)

\( \qquad\longrightarrow \sf Force = - \dfrac{\cancel{135}}{\cancel{25}}\times 10\\ \)

\( \qquad\longrightarrow \sf Force = -5.4 \times 10\\ \)

\( \qquad\qquad\longrightarrow \sf \underline{Force = \boxed{\sf{-54 N}}} \\ \)

Henceforth, The force between these charges, according to Coulomb's law would be -54 N.

A 12 N net force is applied to an object as it moves a distance of 3.0 m: Use the
Work-Kinetic Energy Theorem to determine the object's change in kinetic energy.
Enter your answer in Joules.

Answers

Answer:

4 joules

Explanation:

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