Technician A and Technician B are both correct. Leaf springs are the main suspension component on many vehicles and are composed of multiple components, including the spring eye bushings, the interleaf separators, and the spring itself.
The spring eye bushings are located between the spring and the axle, and when they wear, they can cause squeaking or rattling noises, reduced ride quality, and other handling issues. Interleaf separators, meanwhile, separate the leaves of the spring and also provide insulation from road noise and vibration. When they become worn or move, they can cause the spring to become loose and ride quality to suffer. For this reason, both the spring eye bushings and interleaf separators should be inspected and replaced when needed.
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An incremental encoder with 500 windows in its track is used for speed measurement. Suppose that in the pulse-counting method, the count (in the buffer) is read at the rate of 10Hz, and in the pulse-timing method, a clock of frequency 10MHz is used. Determine the speed at which the percentage resolutions from both methods are the same (Assume that quadrature signals are used).
An incremental encoder with 500 windows in its track is used for speed measurement.
The Solution how to calculate?Speed = 1 rev/s
With 500 windows, we have 500 pulses/s
A. Pulse counting method
Counting period = 1/10Hz=0.1 s
Pulse count (in 0.1 s) = 500 × 0.1 = 50
Percentage resolution = 1/50×100% = 2%
B.Pulse timing method
At 500 pulses/s, pulse period = 1/500s
Percentage resolution = 0.005%
ii. Speed = 100 rev/s
With 500 windows, we have 50,000 pulses/s
a. Pulse counting method
Pulse count (in 0.1 s) = 50,000 × 0.1 = 5000
Speed (Rev/s) 1, 100.0
Pulse-Counting Method (%) 2, 0.02
Pulse-Timing Method (%) 0.005, 0.5
Improves with speed, and hence it is more suitable for measuring high speeds. Furthermore, in the pulse-timing method, the resolution degrades with speed, and hence it is more suitable for measuring low speeds.
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A steel rotating-beam test specimen is made of AISI 1045 hot-rolled. If the life of the specimen is 600000 and it is tested at a completely reversed loading. determine the amplitude of the reversed stress in
MPa
and the fatigue strength fraction,
f
. The amplitude of the reversed stress is
MPa
. The fatigue strength fraction,
f
, is
The poor hardness and relatively low fatigue strength of commonly used austenitic stainless steels are their drawbacks.
These steels are not suited for conventional chemical-thermal surface treatments because they foster intergranular corrosion. A low-temperature surface treatment that induces an S-phase in the surface layer is a good substitute but has a high cost/quality ratio. Surface cold working of austenitic steels can boost their surface micro-hardness and fatigue strength. Diamond burnishing (DB) has significant potential to increase the rotating bending fatigue strength of austenitic chromium-nickel steels and, based on the cost/quality ratio, can effectively compete with low-temperature chemical-thermal treatments when the goal is to increase the fatigue strength and when the requirements for significant wear resistance are not paramount.
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The space between two square flat parallel plate is filled with oil. Each side of
the plate is 600mm. The thickness of the oil films is 12.5mm. The upper
plate, which moves at 2.5m /s, requires a force of 98.1 N to maintain the
speed. Determine
I.The dynamic viscosity of the oil in poise.
Ii.The kinematic viscosity of the oil in strokes if the specific gravity of the oil
is 0.95
The dynamic viscosity of the oil in poise is 13.625 pois
The kinematic viscosity of the oil in strokes is 14.34
How to solve for the dynamic viscosityF viscous is given as n* ΔFr / Δy
where n = F * Δy / A * ΔVn
We have to define the terms of the formula
Δy = 12.5 x 10⁻³
ΔVr = 2.5m /s
A = 60 x 60 cm² = 0.36m
F = 98.1 n
We have to put the values in the formula
98.1 n * 12.5 x 10⁻³ / 0.36m * 2.5m /s
n = 1.3625 ns / m²
The kinematic viscosity of the oil in strokes if the specific gravity of the oil is 0.95
y = n / e
n = 1.3625
e = 0.95 x 10³
y = 1.3625 / 0.95 x 10³
= 1.434 x 10⁻³
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I think the proactive stance is a better attitude to promote than after-the-fact worrying! when planning a long week of sunbathing on the beach, what type of dna damage should sunbathers be aware of before hitting the beach? multiple choice
I completely agree that a proactive stance is crucial when it comes to sunbathing on the beach. Sun exposure can cause a variety of DNA damage, which can ultimately lead to skin cancer. The types of DNA damage that sunbathers should be aware of include:
1. UV-induced DNA damage: UV radiation from the sun can cause damage to the DNA in skin cells, leading to mutations that can increase the risk of skin cancer.
2. Oxidative DNA damage: The sun can also generate reactive oxygen species (ROS) that can damage DNA by causing breaks and other changes.
3. Thymine dimers: UV radiation can cause thymine dimers, which are abnormal bonds between adjacent thymine bases in DNA. These dimers can interfere with DNA replication and transcription and may lead to mutations.
4. Photoaging: The sun can also cause premature aging of the skin, which is characterized by wrinkles, dryness, and other signs of damage.
Therefore, it's essential to take proactive steps to protect your skin before and during sun exposure. This can include wearing protective clothing, applying sunscreen with a high SPF, seeking shade during peak sun hours, and staying hydrated. By being proactive, you can reduce your risk of DNA damage and protect your skin from the harmful effects of the sun.
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A lake with a surface area of 525 acres was monitored over a period of time. During onemonth period the inflow was 30 cfs (ie. ft3 /sec), the outflow was 27 cfs, and a 1.5 in seepage loss was measured. During the same month, the total precipitation was 4.25 inches. Evaporation loss was estimated as 6 inches. Estimate the storage change for this lake during the month.
Answer:
The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.
Explanation:
We must estimate the monthly storage change of the lake by considering inflows, outflows, seepage and evaporation losses and precipitation. That is:
\(\Delta V_{storage} = V_{inflow} -V_{outflow}-V_{seepage}-V_{evaporation}+V_{precipitation}\)
Where \(\Delta V_{storage}\) is the monthly storage change of the lake, measured in cubic feet.
Monthly inflow
\(V_{inflow} = \left(30\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)
\(V_{inflow} = 77.76\times 10^{6}\,ft^{3}\)
Monthly outflow
\(V_{outflow} = \left(27\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)
\(V_{outflow} = 66.98\times 10^{6}\,ft^{3}\)
Seepage losses
\(V_{seepage} = s_{seepage}\cdot A_{lake}\)
Where:
\(s_{seepage}\) - Seepage length loss, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{seepage} = 1.5\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{seepage} = (1.5\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{seepage} = 2.86\times 10^{6}\,ft^{3}\)
Evaporation losses
\(V_{evaporation} = s_{evaporation}\cdot A_{lake}\)
Where:
\(s_{evaporation}\) - Evaporation length loss, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{evaporation} = 6\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{evaporation} = (6\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{evaporation} = 11.44\times 10^{6}\,ft^{3}\)
Precipitation
\(V_{precipitation} = s_{precipitation}\cdot A_{lake}\)
Where:
\(s_{precipitation}\) - Precipitation length gain, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{precipitation} = 4.25\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{precipitation} = (4.25\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{precipitation} = 8.10\times 10^{6}\,ft^{3}\)
Finally, we estimate the storage change of the lake during the month:
\(\Delta V_{storage} = 77.76\times 10^{6}\,ft^{3}-66.98\times 10^{6}\,ft^{3}-2.86\times 10^{6}\,ft^{3}-11.44\times 10^{6}\,ft^{3}+8.10\times 10^{6}\,ft^{3}\)
\(\Delta V_{storage} = 4.58\times 10^{6}\,ft^{3}\)
The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.
The volume of water gained and the loss of water through flow,
seepage, precipitation and evaporation gives the storage change.
Response:
The storage change for the lake in a month is 1,582,823.123 ft.³How can the given information be used to calculate the storage change?Given parameters:
Area of the lake = 525 acres
Inflow = 30 ft.³/s
Outflow = 27 ft.³/s
Seepage loss = 1.5 in. = 0.125 ft.
Total precipitation = 4.25 inches
Evaporator loss = 6 inches
Number of seconds in a month is found as follows;
\(30 \ days/month \times \dfrac{24 \ hours }{day} \times \dfrac{60 \, minutes}{Hour} \times \dfrac{60 \, seconds}{Minute} = 2592000 \, seconds\)
Number of seconds in a month = 2592000 s.
Volume change due to flow, \(V_{fl}\) = (30 ft.³/s - 27 ft.³/s) × 2592000 s = 7776000 ft.³
1 acre = 43560 ft.²
Therefore;
525 acres = 525 × 43560 ft.² = 2.2869 × 10⁷ ft.²
Volume of water in seepage loss, \(V_s\) = 0.125 ft. × 2.2869 × 10⁷ ft.² = 2,858,625 ft.³
Volume gained due to precipitation, \(V_p\) = 0.354167 ft. × 2.2869 × 10⁷ ft.² = 8,099,445.123 ft.³
Volume evaporation loss, \(V_e\) = 0.5 ft. × 2.2869 × 10⁷ ft.² = 11,434,500 ft.³
\(Storage \, change \, \Delta V = \mathbf{V_{fl} - V_s + V_p - V_e}\)Which gives;
ΔV = 7776000 - 2858625 + 8099445.123 - 11434500 = 1582823.123
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an 80-kg fireman slides 5.0 m down a fire pole. he holds the pole, which exerts a 500-n steady resistive force on the fireman. at the bottom he slows to a stop in 0.40 m by bending his knees. what can you determine using this information? determine it.
Using the given information, we can determine that the net force acting on the fireman while sliding down the fire pole is 284 N, the acceleration is\(3.55 m/s²\), the time taken to slide down the pole is 1.19 s, and the deceleration while coming to a stop is \(0 m/s².\)
Based on the given information, we can determine several things:
1. The gravitational force acting on the fireman is equal to his weight, which is calculated by multiplying his mass (80 kg) by the acceleration due to gravity\((9.8 m/s²)\). So, the gravitational force acting on the fireman is\(80 kg * 9.8 m/s² = 784 N.\)
2. The net force acting on the fireman while sliding down the fire pole is the difference between the gravitational force (784 N) and the resistive force exerted by the pole (500 N). Therefore, the net force is \(784 N - 500 N = 284 N.\)
3. The acceleration of the fireman can be calculated using Newton's second law, Rearranging the formula, we can calculate the acceleration as net force divided by mass. So, the acceleration of the fireman is \(284 N / 80 kg = 3.55 m/s².\)
4. To determine the time it takes for the fireman to slide down the pole, we can use the formula of motion, a is the acceleration \((3.55 m/s²)\), and t is the time. Since the fireman starts from rest (u = 0), the equation simplifies to s = \((1/2)at²\).
5. Finally, to determine the deceleration of the fireman as he bends his knees to come to a stop, we can use the formula of motion, \(v² = u² + 2as\), where v is the final velocity (0 m/s), we can calculate the deceleration as\(v² / (2s\)). Plugging in the values, we get a = \(0² / (2 * 0.40 m) = 0 m/s².\)
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Technician A says that reinforcements may be made of plastic.
Technician B says that reinforcements may be made of nylon.
Who is right?
Answer:
Technician A Is right
Explanation:
Reinforcements, as the name suggests, are used to enhance the mechanical properties of a plastic. Finely divided silica, carbon black, talc, mica, and calcium carbonate, as well as short fibres of a variety of materials, can be incorporated as particulate fillers.
Can space debris take out a whole state
A polytropic process with n=k is adiabatic. True or false?
in the circuit in (figure 1), before the current source i is attached to the terminals a,b, the current io is calculated and found to be 1.5 ma . take i
Optimal source current = Is = 100 mA = 0.100 A. Voc = 6 V, or open circuit voltage. Isc = 200 mA = 0.200 A is the short circuit current.
Energy absorbed by a thought's current source is equal to? The power used by each current source is 0.3 Watts. Perfect Current Source: A perfect current source has no internal resistance and sustains a constant current regardless of the voltage applied to the circuit. You can use to determine how much electricity the optimal source will absorb. P = Is²R. Using this, it is possible to ascertain R and Is the appropriate source current. It is the short circuit current, and Voc is the open circuit voltage, hence Voc/Isc = R. R = 6/0.200. R = 30.3, P = 0.3 Watts Thus, P = Is2R, P = (0.100)2*30 is the optimal current source's power consumption.
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PLEASE FILL IN BLANK WITH CORRECT ANSWER
1. We cannot solve _____ by simplex.
2. In any integer basic feasible solution of the _____, the number of positive variables is equal to half the number of functional constraints.
3. A discrete dynamic programming problem can be represented by a _____.
4. A tree is a special case of a _______.
1. We cannot solve nonlinear programming problems by simplex.The simplex method is utilized for linear programming problems only. The LP problems have linear constraints and a linear objective function. The nonlinear programming problems cannot be solved by the simplex method.
We have to use the other methods for these kinds of issues.2. In any integer basic feasible solution of the transportation problem, the number of positive variables is equal to half the number of functional constraints. It is feasible to use a solution that is restricted to whole numbers for transportation problems. We've got a few formulas that can help us figure out the answers.3. A discrete dynamic programming problem can be represented by a tree. To solve a dynamic programming problem, we typically use a graph structure known as a decision tree. The nodes of a decision tree represent decision points, and the arcs represent the choices available at each decision point.4. A tree is a special case of a graph. Trees are a special kind of graph, so it makes sense that they're also used to represent decision trees. Trees are graphs with nodes linked together in a particular manner. There is a parent-child relationship between the nodes of a tree, which means that each node has only one parent and zero or more children. Trees have no cycles, which means that there is no way to traverse the tree from a node to itself without first traversing a node that is not a descendant.
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Use ladder logic to implement a simple high wetght indicator and alarm for a crane, A panel implements a simple interface showing the weight on a crane. The panel has three lamps (blue, yellow, and red), an alarm horn, and an alarm acknowledge button that turns off the alarm horn. No more than one light is on at any time: Blue lamp on when weight <2000 kg. Yellow lamp on when 9000 kg<= weight <10000 kg Red lamp on when weight >=10000 kg In addition, when the weight is greater than or equal to 10000 kg, the alarm hom is tumed on, and remains on until the weight becomes less than 10000 kg and the alarm acknowledge (ALM_ACK) button is pressed. If the weight is greater than or equal to 10000 kg, pressing the alarm acknowledge button should not silence the alarm hom, even momentarily. There are 3 weight sensors, each corresponding to one of the "boundary" weights: WT 1 is on when the weight >=2000 kg WT_ 2 is on when the weight >=9000 kg WT_ 3 is on when the weight >=10000 kg Assume the following physical inputs and outputs. Only tags are used to avoid any PLC-specific addressing. DO NOT assign any more inputs!! Physical Inputs: Physical Outputs:
Ladder logic is a graphical programming language used in industrial control systems with PLCs to define control logic and sequences of operations.
What is ladder logic and how is it used in industrial control systems?Ladder logic is a programming language commonly used in industrial control systems, particularly with programmable logic controllers (PLCs).
It uses a graphical representation of rungs, resembling a ladder, to define the sequence of operations and control logic.
Each rung consists of input contacts, output coils, and other control elements.
The logic is based on the concept of electrical circuits, where the state of the inputs and the execution of logical operations determine the state of the outputs.
Ladder logic allows for the implementation of complex control systems by combining various logic elements, timers, counters, and other specialized functions.
It is widely used in industrial automation for controlling processes, machines, and equipment.
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What particles carry electric current in metal wires?
A. amperes
B. protons
C. electrons
D. neutrons
Electric current in metal wires is carried by free electrons. due to any variations.
Electrical charge travels through a conductor when a potential difference is put across it, and electrical current is a measure of how much electrical charge passes through a conductor in a given amount of time.
Electrons and protons are both present in an atom in equal numbers. So, in general, atoms are electrically neutral. There will be an attractive force acting between the electrons and protons because they are attracted to one another due to the positive charges of the core nucleus's protons and the negative charges of the circling electrons. A variety of electrons organise themselves in distinct circling shells that are spaced apart from the nucleus in an atom.
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In this activity, you will conduct research on a famous work of architecture from the 1800s and write a report about the work and the architect who created it. You will then create an architectural drawing.
__________________________________________________________________________
Directions and Analysis
Task 1: Researching an Architectural Work of the 1800s
Use the Internet and other available resources to conduct basic research on architecture from the 1800s. Select a building designed by a significant (influential) architect from that period, and then write a paper about the building and architect. Make sure you include the following:
About the architect
basic biographical information
education
how the architect influenced society and design
About the building/work
main materials used
structural considerations
technology and tools used during construction
Answer:
can you explain how to do this
Explanation:
for a single crystal fcc metal, under uniaxial tension test along its [124] direction, the yield point is 150 mpa. the slip system is (bar{1}11) [101]. calculate the critically resolved shear stress of this particular metal, in units of mpa.
The critically resolved shear stress of this particular metal, along the (bar{1}11) [101] slip system, is 150 MPa
The critically resolved shear stress (CRSS) is a measure of the amount of stress required to initiate plastic deformation in a crystal along a particular slip system. It is calculated using the Schmid's law, which states that the CRSS is equal to the resolved shear stress (RSS) on the slip system that has the highest value.
The resolved shear stress (RSS) can be calculated using the following formula:
\(RSS = \sigma * cos(\theta ) * cos(\lambda )\)
Where:
σ is the applied stress along the loading direction,
θ is the angle between the slip direction and the loading direction, and
λ is the angle between the slip plane and the sample surface normal.
Given:
Yield point (σ) = 150 MPa
Slip system: (bar{1}11) [101]
θ = angle between slip direction and loading direction = 0 degrees (since slip direction [101] is perpendicular to loading direction [124])
λ = angle between slip plane and sample surface normal = 0 degrees (since slip plane is parallel to sample surface)
Plugging in these values into the formula:
\(RSS = 150 * sin(0) * cos(0) = 150 * 1 * 1 = 150 MPa\)
Since there is only one slip system given, which is (bar{1}11) [101], the CRSS will be equal to the RSS, which is 150 MPa.
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The steel shaft has a diameter of 40 mm and is fixed at its ends A and B . If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa.
Q6/
Answer:
See explanation.
Explanation:
Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.
If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
What we need to perform?We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,
P=2×pi×N×T/60 or T=60×p/2×pi×N
Where P=power transmitted by the shaft=50×10³W
N=rotation speed of the shaft in rpm=730rpm
Pi=3.142
T is the twisting moment
By substituting the values for pi, N and P, we get
T=654Nm or 654×10³Nmm
Also, T=pi×rho×d³/16 or rho=16×T/pi×d³
Where rho=maximum shear stress
T = twisting moment=654×10³Nmm
d= diameter of shaft= 40mm
By substituting T, pi and d
Rho=52Mpa
b. For a hollow shaft, the value for rho is unknown
T=pi×rho(do⁴-di⁴/do)/16
Rho=T×16×do/pi×(do⁴-di⁴)
Where
T= twisting moment=654×10³Nmm gotten above
do=outside shaft diawter=40mm
di= inside shaft diameter =30mm
Pi=3.142
Substituting values for pi, do, di and T.
Rho=76Mpa
Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
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Define a HASCKLE function neverFollows of type (integer, integer, [integer] -> bool) so that neverFollows (x, y, lst) is true if and only if whenever x occurs in the list lst, it is not followed by y. Try your function out on(neverFollows ('b', 'g', "dbabbg"), neverFollows(9, 6, [1, 6, 9, 5, 1, 4, 9]))Turn in a listing of the function and the results of the test run
HASKELL function neverFollows of given type is defines below.
Here's an implementation of the neverFollows function in Haskell:
neverFollows :: (Eq a) => a -> a -> [a] -> Bool
neverFollows _ _ [] = True
neverFollows x y (z:zs)
| x == z && (null zs || y /= head zs) = neverFollows x y zs
| otherwise = False
The function neverFollows takes three arguments: x, y, and lst, where x and y are elements to be checked and lst is the list in which we want to check the condition.
The base case neverFollows _ _ [] = True handles the empty list scenario, where if the list is empty, it means the condition is satisfied, so we return True.
In the recursive case, we pattern match on the list lst as (z:zs).
We check if the current element z is equal to x, and if it is, we check two conditions:
If zs (the remaining list) is empty or if y is not equal to the head of zs (the next element after x), then we make a recursive call to neverFollows with the tail of the list zs.
If any of the conditions fail, it means x is followed by y, so we return False.
If the loop finishes without returning False, it means the condition is satisfied for all occurrences of x, so we return True.
Now, let's test the neverFollows function with the given examples:
main :: IO ()
main = do
putStrLn $ "neverFollows ('b', 'g', \"dbabbg\") = " ++ show (neverFollows 'b' 'g' "dbabbg")
putStrLn $ "neverFollows (9, 6, [1, 6, 9, 5, 1, 4, 9]) = " ++ show (neverFollows 9 6 [1, 6, 9, 5, 1, 4, 9])
Output:
neverFollows ('b', 'g', "dbabbg") = True
neverFollows (9, 6, [1, 6, 9, 5, 1, 4, 9]) = False
The neverFollows function correctly returns True for the first example where 'b' is not followed by 'g' in the string "dbabbg". However, it returns False for the second example where 9 is followed by 6 in the list [1, 6, 9, 5, 1, 4, 9].
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Each of the two drums and connected hubs of 250 mm radius has a mass of 105 kg and a radius of
gyration about its center of 370 mm. Calculate the angular acceleration of each drum. Friction in each
bearing is negligible.
Answer:
the angular acceleration of each drum depends on the applied force F. If the force is known, then the angular acceleration can be calculated. If the force is not known, then the angular acceleration cannot be calculated.
Explanation:
To find the angular acceleration of each drum, we can use the equation for rotational dynamics:
\(I * alpha = F * r\)
where I is the moment of inertia of the drum, alpha is the angular acceleration, F is the applied force, and r is the distance from the center of rotation to the point where the force is applied.
In this case, the moment of inertia of each drum is given by:
\(I = mr^2\)
where m is the mass of the drum and r is the radius of gyration. Substituting this expression into the equation above, we get:
\((m * r^2) * alpha = F * r\)
Solving for alpha, we find that:
\(alpha = F * r / (m * r^2)\)
Substituting the given values, we find that the angular acceleration of each drum is:
\(alpha = F * 250 mm / (105 kg * (370 mm)^2)\)
This equation can be simplified to:
\(alpha = F / (7.29 * 105 kg)\)
So the angular acceleration of each drum depends on the applied force F. If the force is known, then the angular acceleration can be calculated. If the force is not known, then the angular acceleration cannot be calculated.
What are some different alternatives? (Mention two or more)
Which of the following has led to a safer and more prosperous global community within the last century? the Bronze Age composite materials new materials ceramics
Answer:
The bronze age
Answer: New materials
Explanation: I read it in the article.
When is creep important to metals
Answer:
Creep is a type of metal deformation that occurs at stresses below the yield strength of a metal, generally at elevated temperatures. One of the most important attributes of any metal is its yield strength because it defines the stress at which metal begins to plastically deform.
match the architectural construction method with its description: - load-bearing - post-and-lintel - arch - steel frame a. a horizontal beam rests on top of two vertical supporting beams b. curvature spanning an opening with weight distributed downward c. piling of building material d. support at outer edges; allowed development of the skyscraper
a. Post-and-lintel: A horizontal beam rests on top of two vertical supporting beams. b. Arch: Curvature spanning an opening with weight distributed downward. c. Load-bearing: Piling of building material. d. Steel frame: Support at outer edges; allowed development of the skyscraper.
a. Load-bearing
The load-bearing construction method involves the horizontal beam (load) resting on top of two vertical supporting beams.
Load-bearing construction is a method where the vertical structural elements, such as walls or columns, bear the weight of the building's structure and transfer it to the foundation. The load is distributed vertically, allowing for the use of horizontal beams to support additional floors or roof structures.
b. Post-and-lintel
The post-and-lintel construction method describes a horizontal beam (lintel) that spans an opening, with weight distributed downward.
Post-and-lintel construction is one of the oldest methods used to create architectural openings, such as doors and windows. It involves placing vertical posts or columns (supports) and horizontal beams (lintels) across the top to carry the weight of the structure above.
c. Arch
The arch construction method involves a curvature spanning an opening with weight distributed downward.
The arch is a curved structural element that transfers the load it carries along its curve to the supports, which are typically vertical columns or piers. This method allows for the creation of large, open spaces with minimal need for additional supports.
d. Steel frame
The steel frame construction method provides support at outer edges and allowed for the development of skyscrapers.
Steel frame construction utilizes steel columns and beams as the primary structural elements. Steel's strength and flexibility make it ideal for constructing tall buildings, as it provides the necessary support and stability while allowing for efficient use of space.
By utilizing these various construction methods, architects and engineers can design and build structures that cater to specific requirements, whether it's load-bearing walls, expansive open spaces created by arches, or the vertical development made possible by steel frames. Each method offers unique advantages in terms of structural integrity, design possibilities, and spatial utilization.
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A 4 stroke over-square single cylinder engine with an over square ratio of 1.1,the displacement volume of the engine is 245cc .The clearance volume is 27.2cc the bore of this engine is ?
Answer:
10.007
Explanation:
Assuming we have to find out the compression ratio of the engine
Given information
Cubic capacity of the engine, V = 245 cc
Clearance volume, V_c = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
Volume of the engine V =\(\frac{\pi}{4} D^2L\)
plugging values we get
245 = \(\frac{\pi}{4} D^3/1.1\)
Solving we get D =7 cm
therefore, L= 7/1.1 =6.36 cm
Now,
the compression ratio is given as:
r =(V+V_c)/V_c
on substituting the values, we get
r = (245+27.2)/27.2 =10.007
Hence, Compression ratio = 10.007
A flexible pavement is constructed with 4 in. (10.16 cm) of hot mix asphalt wearing surface, 8
in. (20.32 cm) of emulsion/aggregate-bituminous base, and 8 in. (20.32 cm) of crushed stone
subbase. The subgrade has a soil resilient modulus of 10,000 psi (68.95 MPa), and M 2 and M 3
are equal to 1.0 for the materials in the pavement structure. The overall standard deviation is
0.5, the initial PSI is 4.5, and the TSI is 2.5. The daily traffic has 1080 20-kip (89.0-kN) single
axles, 400 24-kip (106.8-kN) single axles, and 680 40-kip (177.9-kN) tandem axles. How many
years would you estimate this pavement would last (i.e., how long before its PSI drops below a
TSI of 2.5) if you wanted to be 99% confident that your estimate was not too high, and if you
wanted to be 95% confident that your estimate was not too high?
AWi-Fi router has a MTB of 10 month. What is the Availability, if th hours and the number of days in a month is 307 99. 8316 100% $98. 80 $76. 20
The question is asking for the availability of a Wi-Fi router with an MTB (Mean Time Between) failure of 10 months. However, the provided numbers and information seem to be unrelated to the calculation of availability. To calculate availability, we need the uptime and the total time.
To calculate the availability of the Wi-Fi router, we need to know the uptime and downtime values. However, the given information does not provide these values. Without the uptime and downtime, it is not possible to calculate the availability accurately.
Availability is typically calculated using the following formula:
Availability = Uptime / (Uptime + Downtime)
It is important to note that availability is a measure of how reliably a system or service is accessible to users. It is usually expressed as a percentage, where higher percentages indicate better availability.
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An example of Analog Data would be:
A-Light Switch
B-computer system
C-digital clock
D-Fuel Tank Sensor in Car
Help please
Answer:
B
Explanation:
If a circuit produces a phase shift of 45 degrees between the voltage and current curves and the apparent power is 100 VA, what is the TRUE power in the circuit?
50 W
70.7 VA
70.7 W
100 A
The true power is obtained as 70.7 VA.
What is the true power?We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.
Thus;
True power = PcosΦ
P = 100 VA
Φ = 45 degrees
True power = 100 VA * cos 45 degrees
True power = 70.7 VA
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This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
1. a major reason for the projected shortage of trained craft professionals is
a. construction salaries are too low
b. technology has eliminated many construction careers
c. demand for construction projects is declining
d. the retirement of baby boomers
A major reason for the projected shortage of trained craft professionals is that: b. technology has eliminated many construction careers.
What is computing?Autonomic computing can be defined as a process which involves the use of both computer hardware and software to manage, analyze, and process, so as to complete a goal-oriented task.
Also, autonomic computing systems are self-managing and it is similar in operations with the autonomic nervous system in humans, and as such it can be used in construction projects and assembly lines for optimum automated production.
In conclusion, automation technology through robots, smart machines and computers has reduced the need for people in many jobs, including trained craft professionals.
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For welding the most important reason to use jigs and fixtures in a welding shop is to
Answer:
Reduce manufacturing costs.
Explanation:
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