Pat's approximate monthly Payment would be $304.32 to repay all her loans after the deferment period.
The Pat's monthly payment, we need to consider the terms and interest rates of each loan. Let's break down the calculation step by step:
1. Federally subsidized student loans:
- Pat receives four annual loans, each for $5400 at an interest rate of 6.5%.
- Since the loans are annual, we need to calculate the interest for each year and add it to the principal amount.
- The total principal amount for the four loans is $5400 * 4 = $21,600.
- The interest for each year is $21,600 * 6.5% = $1,404.
- Therefore, the total amount owed for the federally subsidized loans is $21,600 + ($1,404 * 4) = $27,816.
2. Private student loan:
- Pat takes out a private student loan for $4100 at an interest rate of 7.5% for a term of 10 years.
- The loan is capitalized, which means the interest is added to the principal amount.
- The total principal amount for the private loan is $4100.
- The interest for each year is $4100 * 7.5% = $307.50.
- Since Pat capitalizes the interest for her last year of college, the loan will accrue interest for a total of 9 months.
- Therefore, the total interest accrued for the private loan is ($307.50 * 9) = $2767.50.
- The total amount owed for the private loan is $4100 + $2767.50 = $6867.50.
3. Total amount owed:
- To find the total amount owed by Pat, we add the amounts from the federally subsidized loans and the private loan.
- Total amount owed = $27,816 + $6867.50 = $34,683.50.
4. Monthly payment:
- The monthly payment is calculated based on the total amount owed and the repayment term.
- The term is 10 years for the private loan, but since payments are deferred until 6 months after graduation, the actual term is 10 years - 0.5 years = 9.5 years.
- The number of monthly payments is 9.5 years * 12 months/year = 114 months.
- Therefore, the monthly payment is $34,683.50 / 114 months ≈ $304.32.
So, Pat's approximate monthly payment would be $304.32 to repay all her loans after the deferment period.
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There are five main roads between the cities A and B and 4 between B and C. In how many ways can a person drive from A to C and return without driving on the same road twice?
There are 20 possible routes that a man could take to go between cities and then take a different route back.
What is meant by permutation?In mathematics, a permutation of a set is, broadly speaking, the rearranging of its elements if the set is already sorted, or the arrangement of its members into a sequence or linear order. The act of altering the linear order of an ordered set is referred to as a "permutation" in this context.
Let the number of roads between the cities A and B = 5.
The rules of permutation must be used in this situation.
A permutation is an arrangement of all or a portion of a collection of items that takes into account the arrangement's order.
The man uses five different routes to get from A to B because there are five different routes accessible.
He can get back by 4 (5 1) methods because he needs to take a different route.
Therefore, there are 20 possible routes that a man could take to go between cities and then take a different route back.
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The length of XY is 24 centimeters. The midpoint of XY is M, and C is on XM so that XD is 2/3 of XM. Point D is on MY so that MD is 3/4 of MY. What is the length of CD?
The length of CD is centimeters
Answer:
CD = 13 cm
Step-by-step explanation:
We assume you intend XC = 2/3 of XM, since XD cannot be that fraction of XM.
__
Of course XM = MY = 12, since M is the midpoint of a segment 24 cm long. Then 2/3 of XM is 8 cm, and 3/4 of MY is 9 cm.
CD = CM + MD = 4 cm + 9 cm
CD = 13 cm
Answer of question 3 pls
The highest point for the quadratic function for the height of the object, h(t) = -16·t² + 224·t + 816, indicates that the interval over which the height of the object is increasing is; (-∞, 7]
What is the shape of the graph of a quadratic function?The shape of the graph of a quadratic function is a parabola.
The function for the height of the object in question 3 is; h(t) = -16·t² + 224·t + 816
Where;
t = The time in seconds
The height of the object is increasing in the interval to the left of the highest point, which can be found as follows;
The x-coordinate of the highest point of the quadratic function, f(x) = a·x² + b·x + c is; x = -b/(2·a)
Therefore, the x-coordinates of the highest point of the object is; -224/(2 × (-16)) = 7
Therefore, the height of the object is increasing in the interval; -∞ < t ≤ 7
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Does anyone know how to find the area?
Answer:49
Step-by-step explanation:
A = \(\frac{3+11}{2}\) · 7
= \(\frac{14}{2} \\\) · 7
= 7·7
=49
Find the angle on the unit circle
The angle on the unit circle is solved to be
56.01 degrees (to the nearest tenth)
How to find the angleTo find the angle of the terminal side through the given point on the unit circle, we can use the inverse trigonometric functions.
given that P = ((√5)/4, (√11)/4)
θ = arctan ((√11)/4 / (√5)/4)
θ = arctan((√11)/(√5))
θ ≈ 56.01 degrees
hence to the nearest tenth of a degree, the angle of the terminal side through the point P = ((√5)/4, (√11)/4) on the unit circle is approximately 56.01 degrees.
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Given that the coefficient of x⁵ in the expansion of (1+kx)⁵ is -672 find the value of k
The value of k that satisfies the given condition is approximately 0.4041.
In the expansion of (1+kx)⁵, the coefficient of x⁵ is given by the term:
C(5,k) * (kx)⁵ = k⁵ * C(5,k) * x⁵
where C(5,k) is the binomial coefficient or the number of ways to choose 5 items out of k.
So, we have the equation:
k⁵ * C(5,k) = -672
We can use a table of binomial coefficients to find C(5,k) for different values of k, but this can be time-consuming. Alternatively, we can use the fact that C(5,k) = C(5,5-k) and rewrite the equation as:
k⁵ * C(5,5-k) = -672
Expanding C(5,5-k), we get:
k⁵ * C(5,5-k) = k⁵ * C(5,k) = -672
Now, we can use trial and error to solve for k. Using this method, we can find that k = -4 or k ≈ 0.4041. However, since k must be positive (since it appears as a factor in the expansion), the only valid solution is k ≈ 0.4041.
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Find YZ and XY so I can put em in the boxes :)
Answer:
........................
A water tank in the shape of a rectangular prism is 11 feet deep. The top of the water tank has an area of 240 square feet. What is the volume, in cubic feet, of the water tank? *
Answer:
2640 cubic feet
Step-by-step explanation:
V(l·w·h) = 240* x 11 = 2640
*240 is already the length x width
Solve for N. 5/3 = N/12
Answer:
N = 20
Step-by-step explanation:
5/3 = 1 2/3
20/12 = 1 8/20
They are equivalent
At Park Junior High, 10%, or 160, of the students, play a musical instrument. How many students attend the school?
A tape diagram. StartFraction part Over whole EndFraction = StartFraction 10 Over 100 EndFraction = StartFraction 160 Over question mark EndFraction
Which statements are correct? Check all that apply.
The total number of students is < 160.
The total number of students is > 160.
The percent as a part-to-whole ratio is StartFraction 10 Over 100 EndFraction.
The percent as a part-to-whole ratio is StartFraction 160 Over 100 EndFraction
There are 1,600 students in the school.
There are 250 students in the school.
The statements that are correct include the following:
B. The total number of students is > 160.
C. The percent as a part-to-whole ratio is 16/100.
E. There are 1600 students in the school.
What is a percentage?In Mathematics, a percentage can be defined as any number that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given number.
For the total number of students, we have:
Total number of students = 10/100 × T = 160
0.1T = 160
T = 160/0.1
T = 1,600 students.
Note: Percentage as a part-to-whole ratio is 10/100.
In conclusion, we can reasonably infer and logically deduce that the total number of students at Park Junior High is equal to 1,600 students.
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Complete Question:
At park junior high 10% or 160 of the students play a musical instrument how many students attended the school?
Which statements are correct? check all that apply.
A.the total number of students is 160
B. The total number of students is > 160.
C.The percent as a part-to-whole ratio is 10/100
D.the percent as a part to whole ratio is 160/100
E.there are 1600 students in the school
F.there are 250 students in the school.
When 3 is subtracted from one third of a number n the result is less than 6 which inequality and solution represent this situation
ASAPPPPPP HURRY!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
1/3n-3<6
Step-by-step explanation:
"when 3 is subtracted from one third of a number n"
meaning: 1/3n-3
"the result is less than 6"
less than is <, so it'd be
1/3n-3<6
Answer: 1/3n-3<6
Step-by-step explanation:
A rectangular prism has a width of x2 inches and a length of xy2 inches and a height of xy inches.
Which expression represents the volume of the rectangular prism in cubic inches?
2x^2y^2
2xy^3 + 2x^2y
2x^4y^3
x^3y^2
Find the value of x.
46°
100°
X
Answer:
x=34°
Step-by-step explanation:
100+46=146
180-146=34
so x =34°
Answer:
x=34°
there is your answer :)
3. Avery records her rock-climbing progress and finds that her altitude, in kilometers above sea
level, can be represented by a linear model, A = 7+ 1.3t, where t is the number of hours since
Avery started climbing.
Based on this model, how many kilometers above sea level was Avery's altitude before she started
climbing?
km
Using the given linear function, it is found that Avery was 7 kilometers above sea level before she started climbing.
What is a linear function?A linear function is modeled by:
\(y = mx + b\)
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can be interpreted as the initial value.In this problem, her altitude in kilometers after t hours is modeled by:
A(t) = 7 + 1.3t.
The y-intercept is of b = 7, which means that Avery was 7 kilometers above sea level before she started climbing.
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What is the limit of (n!)^(1/n) as n approaches infinity?
Note: n! means n factorial, which is the product of all positive integers up to n.
Answer:
Step-by-step explanation:
To find the limit of (n!)^(1/n) as n approaches infinity, we can use the Stirling's approximation for n!, which is:
n! ≈ (n/e)^n √(2πn)
where e is the mathematical constant e ≈ 2.71828, and π is the mathematical constant pi ≈ 3.14159.
Using this approximation, we can rewrite (n!)^(1/n) as:
(n!)^(1/n) = [(n/e)^n √(2πn)]^(1/n) = (n/e)^(n/n) [√(2πn)]^(1/n)
Taking the limit as n approaches infinity, we have:
lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n)
Using the fact that lim a^(1/n) = 1 as n approaches infinity for any constant a > 0, we can simplify the second term as:
lim [√(2πn)]^(1/n) = 1
For the first term, we can rewrite (n/e)^(n/n) as [1/(e^(1/n))]^n and use the fact that lim a^n = 1 as n approaches infinity for any constant 0 < a < 1. Thus, we have:
lim (n/e)^(n/n) = lim [1/(e^(1/n))]^n = 1
Therefore, combining the two terms, we have:
lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n) = 1 x 1 = 1
Hence, the limit of (n!)^(1/n) as n approaches infinity is 1.
Answer:1
Step-by-step explanation:
Four students are training for their cross country team at school. They were told to run for as long as they could without stopping. The coach measured their total distances and their overall time. Calculate the average speed for each student and find the two students who tied for the same average speed.
A) Brev and Chris
B) Brev and leslie
C) Chris and Dylan
D) Dylan and Leslie
Answer:
C) Chris and Dylan
Step-by-step explanation:
Graph the system x+y=8 and 6x+3y=36
Let's conside the first equation x+y=8
Since it is an equation with degree 1, it is a straight line. So 2 coordinates are enough to plot a graph.
To plot a grpah, let's take, x=0,1
If x=0
\(\begin{gathered} x+y=8 \\ 0+y=8 \\ y=8 \end{gathered}\)So, the coordinate is (0,8)
If x=1
\(\begin{gathered} 1+y=8 \\ y=8-1 \\ y=7 \end{gathered}\)So, the coordinated is (1,7)
Let's plot the graph.
Let's take the second equation
6x+3y=36
If x=0
\(\begin{gathered} 6x+3y=36 \\ 0+3(y)=36 \\ y=\frac{36}{3} \\ y=9 \end{gathered}\)Hence the y coordinated is (0,9)
If x=1
\(\begin{gathered} 6x+3y=36 \\ 6(1)+3y=36 \\ 3y=36-6 \\ y=\frac{30}{10} \\ y=10 \end{gathered}\)Hence the coordinate is (1,10)
Let's plot the graph
Hence both the graphs are plotted.
cesar gasto el 15% de sus ahorros en un celular por lo que ahora le queda 2.125 dolares ahorrados ¿cuanto dinero tenia inicialmente cesar?
Cesar initially had $2,500 in savings.
Let's solve the problem step by step.
Let's assume that the initial amount of money Cesar had is represented by "x" dollars.
According to the problem, Cesar spent 15% of his savings on a cellphone, which means he has 85% of his initial savings left. We can represent this mathematically as:
0.85x = 2,125
To find the initial amount of money Cesar had, we need to solve for x. We can do this by dividing both sides of the equation by 0.85:
x = 2,125 / 0.85
Calculating this value:
x = 2,500
Cesar initially had $2,500 in savings.
Please note that the calculations are done assuming a straightforward interpretation of the problem. If there are additional factors or context that could affect the interpretation, it's important to consider them in order to arrive at an accurate answer.
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HELP ME ASAP!!! YOU WILL BE BRAINLIEST
We can conclude that Maya's experimental probabilities fluctuate around the theoretical probability, but over a larger number of trials, the experimental probabilities should converge towards the theoretical probability.
What is probability?
Probability is simply how likely something is to happen. Whenever we're unsure about the outcome of an event, we can talk about the probabilities of certain outcomes—how likely they are. The analysis of events governed by probability is called statistics.
The theoretical probability of rolling a 5 on a fair die is 1/6, which means that if the die is rolled many times, we would expect to see a 5 about 1/6 of the time.
For the first 100 trials, Maya rolled a 5 on 25 of those trials. The experimental probability of rolling a 5 in this case is:
experimental probability = number of 5's rolled / number of trials
experimental probability = 25/100
experimental probability = 0.25
So, in the first 100 trials, Maya's experimental probability of rolling a 5 was 0.25.
For the first 200 trials, Maya rolled a 5 on 30 of those trials. The experimental probability of rolling a 5 in this case is:
experimental probability = number of 5's rolled / number of trials
experimental probability = 30/200
experimental probability = 0.15
So, in the first 200 trials, Maya's experimental probability of rolling a 5 was 0.15.
Comparing these experimental probabilities to the theoretical probability, we see that after 100 trials, Maya's experimental probability of rolling a 5 (0.25) is higher than the theoretical probability (1/6 ≈ 0.167). This suggests that Maya's sample of 100 trials was somewhat biased in favor of rolling a 5.
On the other hand, after 200 trials, Maya's experimental probability of rolling a 5 (0.15) is lower than the theoretical probability (1/6 ≈ 0.167). This suggests that Maya's sample of 200 trials was somewhat biased against rolling a 5.
Overall, we can conclude that Maya's experimental probabilities fluctuate around the theoretical probability, but over a larger number of trials, the experimental probabilities should converge towards the theoretical probability. This is known as the law of large numbers, which states that as the number of trials or observations increases, the experimental probability will tend to approach the theoretical probability.
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We might say that Maya's experimental probabilities oscillate about the theoretical probability, but after more trials, the experimental probabilities ought to converge to the theoretical probability.
What is probability?
Simply put, probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.
A fair die has a theoretical probability of rolling a 5 of 1/6, therefore if the die is rolled several times, we can anticipate seeing a 5 roughly 1/6 of the time.
For the first 100 trials, Maya rolled a 5 on 25 of those trials. The experimental probability of rolling a 5 in this case is:
experimental probability = number of 5's rolled / number of trials
experimental probability = 25/100
experimental probability = 0.25
So, in the first 100 trials, Maya's experimental probability of rolling a 5 was 0.25.
For the first 200 trials, Maya rolled a 5 on 30 of those trials. The experimental probability of rolling a 5 in this case is:
experimental probability = number of 5's rolled / number of trials
experimental probability = 30/200
experimental probability = 0.15
So, in the first 200 trials, Maya's experimental probability of rolling a 5 was 0.15.
Comparing these experimental probabilities to the theoretical probability, we see that after 100 trials, Maya's experimental probability of rolling a 5 (0.25) is higher than the theoretical probability (1/6 ≈ 0.167). This suggests that Maya's sample of 100 trials was somewhat biased in favor of rolling a 5.
On the other hand, after 200 trials, Maya's experimental probability of rolling a 5 (0.15) is lower than the theoretical probability (1/6 ≈ 0.167). This suggests that Maya's sample of 200 trials was somewhat biased against rolling a 5.
Overall, we can conclude that Maya's experimental probabilities fluctuate around the theoretical probability, but over a larger number of trials, the experimental probabilities should converge towards the theoretical probability. This is known as the law of large numbers, which states that as the number of trials or observations increases, the experimental probability will tend to approach the theoretical probability.
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What is the next step to solve the equation 5y 3x15 for y?
Answer:y will be 45 then Multiply 45x3 which equals 135. Then add 135+62 and get your awnser.
Step-by-step explanation:
Simplify each radical 1-4
Answer:
1- H , 2- B , 3- A , 4- F
Step-by-step explanation:
Just simplify and you will get the answer.
Goodluck
Write the following set using roster notation. Do not include repeats.
A is the set of odd integers between 4 and 12.
Answer:
The Set of Natural Numbers: {1, 2, 3, 4, 5, . . .}
The Set of Whole Numbers: {0, 1, 2, 3, 4, 5, . . .}
The Set of Integers: {. . . , −5, −4, −3, −2, −1, 0, 1, 2, 3, 4, 5, . . .}
Step-by-step explanation:
From 32 + 14i, subtract its complex conjugate. What is the difference?
Answer:
To find the complex conjugate, negate the term with i
.
32−14i
Step-by-step explanation:
Jamie will plot ( 9, 5 ) on a coordinate plane. She knows the last step is to put a point where to lines intersect. Which two steps should she use first?
Answer:
Step-by-step explanation:
54
I think
Which of the ratios below is equivalent to 1:3? Select all that apply.
A) 4:12
B) 6:18
C) 6:2
D) 8:24
E) 5:8
Answer:
\( \: \: \: \: \: 1 : 3 \\ = 4 : 12 \\ = 6 : 18 \\ = 8 : 24 \\ \)
hope this helps
Answer:
Answer:
4:12
6:18
8:24
hope this helps
Step-by-step explanation:
Question 1 Choose the equivalent expression. (810)?
Answer:
4x(3y+1)
Step-by-step explanation:
Carter and Sani each have the same number of marbles. Sani's little sister comes in and takes some of
Carter's marbles and gives them to Sani. After she has done this, Sani has 18 marbles and Carter has 10
marbles. How many marbles did each of the boys start with? How many marbles did Sani's sister take
from Carter and give to Sani?
Answer:
The first answer is 14 marbles.
The second answer is 4 marbles.
Step-by-step explanation:
1. Add as many marbles needed to Carter's pile to match the amount of marbles with Sani's amount to get both amounts to be even.
2. The number of marbles you moved to Carter's pile to make both amounts even is the answer to the second question.
Answer: both boys started with 14 marbles sani’s sister took 4 marbles and gave them to carter
Step-by-step explanation:
If they started with the same amount then sanis sister took some and gave them to carter and made it to where sani now has 18 and carter has 10 it’s simple math.
10 to 18 is 8 in between so split 8 in half and you get 4 so you count down 4 from 18 and you get 14.
There for both boys started with 14 marbles.
a delivry truck is transporiting boxes of two sizes large and small the combined weight of a large box and a small box is 65 pounds the truck transporting 55 large boxes and 65 small boxes if the truck is carrying a totall of 3774 pounds of boxes how much does each type of box way
Answer: S = 20 lbs L = 45 lbs. Both answer have been rounded from below
Step-by-step explanation:
L+S = 65 lbs
55L + 65S = 3774 lbs
55L+55S = (65)(55) = 3,575 lbs
10S = 199 lbs
S = 19.99 (round to 20)
L + S = 65
L + 19.99 = 65
L = 45.01 (round to 45)
If E1 = the outcome is a red number and E2 = the outcome is an odd number, list the
outcomes corresponding to Ei and E2.
Answer: outcomes of E1 = [1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36]
outcomes of E2 = [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35]
Step-by-step explanation: This is the answer on Plato/edmentum! Hope I was able to help! :)
Answer:
outcomes of E1 = [1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36]
outcomes of E2 = [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35]
Step-by-step explanation:
plato answer
3. Simplify 3 +2× 4+6/2-5 -1
4
2
25
3
Answer:
The answer is 4...
Hope it helps! ^^