PE: A 75 kg runner, runs up the Art Museum's stairs to a height of 13 m. Find either the work done by the runner, or the change in potential energy as the runner ran up the stairs. Extra: If the runner took 8 s to run up, what was the power used in watts?Please help.

Explanation:

the answers are the first 3.

Answer:

4.6

Explanation:

Ans is 4.6 b coz the difference b/w 4.6 and the other values is comparitively the largest.

Answer:

Mass

Explanation:

In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015

Answer:

0.18 Nm

Explanation:

Note: Torque is independent of the mass of a body.

From the question,

T = F×d.......................Equation 1

Where T = Torque, F = force applied to the wrench, d = length of the wrench.

Given: F = 12 N, d = 15 cm = 0.015 m

Substitute into equation 1

T = 12(0.015)

T = 0.18 Nm.

Hence the torque applied is 0.18 Nm

Answer:

6 - iron

7 - by stringing many magnets together

Explanation:

6 - substances such as iron, cobalt, and nickel, most of the electrons spin in the same direction. This makes the atoms in these substances strongly magnetic—but they are not yet magnets. ... The piece of iron has become a magnet. Some substances can be magnetized by an electric current.

7 - it is that only

Answer:

20*365=7300

Explanation:

1 Year=365day

20years = x days

(a) The ball falls short of clearing the crossbar by 3.05 m (negative value indicates falling short).

(b) The ball approaches the crossbar while falling since it doesn't reach a height greater than the crossbar's height during its trajectory.

To solve this problem, we'll analyze the vertical motion of the ball.

(a) To find how much the ball clears or falls short of clearing the crossbar vertically, we need to calculate the maximum height reached by the ball.

The initial velocity (V0) of the ball is 23.2 m/s, and the launch angle (θ) is 52.0° above the horizontal.

The vertical component of velocity (Vy) at the highest point of the trajectory is zero since the ball momentarily stops before falling back down.

To find the time taken to reach the highest point, we can use the equation:

Vy = V0 * sin(θ)

0 = 23.2 m/s * sin(52.0°)

Solving for sin(52.0°), we find:

sin(52.0°) ≈ 0.7880

Dividing both sides by 23.2 m/s, we get:

0.7880 = sin(52.0°)

Taking the inverse sine, we find:

52.0° ≈ arcsin(0.7880)

Using a calculator, we find:

52.0° ≈ 56.43°

Now we can calculate the time (t) it takes to reach the highest point using the equation:

t = (2 * Vy) / g

Since Vy = 0, we have:

t = 0

This means that the ball reaches its maximum height instantaneously and starts falling immediately. Therefore, the ball does not clear the crossbar.

To find how much the ball falls short of clearing the crossbar vertically, we can calculate the height of the ball at a horizontal distance of 36.0 m.

Using the equation for vertical displacement, we have:

Δy = V0y * t + (1/2) * g * \(t^2\)

Plugging in the known values:

Δy = 0 * t + (1/2) * (-9.8 \(m/s^2\)) * (\(t^2\))

Since t = 0, the equation simplifies to:

Δy = 0

Therefore, the ball falls short of clearing the crossbar by 3.05 m vertically.

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Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

Answer:

389 J

Explanation:

m = 15.0 kg, v = 7.2 m/s

Kinetic energy = mv²/2 = 15.0 * 7.2²/2 = 389 J

a. 4000

This has 4-digits.

Answer:

in my opinion letter d.

Explanation:

Sana pi tama

Answer:

No because it could run out of gas quicker or get into a reck.

Explanation:

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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Both hammer and nail hit the ground at the same time because acceleration due to gravity is same for everything on Earth surface.

The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity.

M/s² is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on earth's surface is 9.8 m/s².

As acceleration due to gravity is same for everything on Earth surface, both hammer and nail hit the ground at the same time.

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Answer:

(Question)  Melissa is working on the roof of her house. She drops a hammer and a nail. Why do both objects hit the ground at the same time?

(Answer)  Earth’s gravity causes both objects to fall at the same rate.

(Question)  Which of the following statements about gravitational mass is true?

(Answer)  Gravitational acceleration is irrespective of mass.

(Question)  Two objects fall from an apartment window sill at the same time. Object 1 lands on the sidewalk in 3.6 seconds. Object 2 lands on the sidewalk in 3.3 seconds. What can be concluded about the objects?

(Answer)  Object 1 has more surface area than Object 2.

(Question)  A company uses drones to fly food to people in regions that have experienced natural disasters. The food is packed in boxes that are attached to parachutes. How can the company change the design of its parachute to reduce the number of boxes that are damaged when they hit the ground?

(Answer)  The company can design a parachute with more surface area.

(Question)  Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from the top of their school’s bleachers. They will time how long each object takes to reach the ground. How can they improve confidence in the experiment’s results?

(Answer)  Drop each object 10 times and use the average of each object’s fall times.

Explanation:

i just finished the quick check

Answer:

B

Explanation:

The iris controls the amount of light that enters the eye by opening and closing the pupil. The iris uses muscles to change the size of the pupil. These muscles can control the amount of light entering the eye by making the pupil larger (dilated) or smaller (constricted).

Answer:

D.

Explanation:

The iris has special muscles that are constantly contracting and expanding to adapt to the amount of light entering your eyes. That's why your iris dialates when you're in the dark, its becomes larger to adapt to the low lighting so you are able to see better

Energy is that which has the ability to cause change in matter.

Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.

So in simple definition we can say that energy is that which has the ability to cause change in matter.

Based on the given statements we can classify them as;

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Answer:

a positive form of stress having a beneficial effect on health, motivation, performance, and emotional well-being … during positive stress ("eustress"), such as a promotion or vacation, feel-good chemicals called endorphins are released

Explanation:

that is the answer

The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.

To find the capacitance value, we can use the formula:

C = Q / V

where Q is the charge stored in the capacitor and V is the voltage across the capacitor.

Substituting the given values, we get:

C = 9.40 x 10^-10 / 50.0

= 1.88 x 10^-11 F

Now we can use the formula for electric potential energy to find the energy stored in the capacitor:

U = (1/2) * 1.88 x 10^-11 * (50.0)^2

= 4.70 x 10^-8 J

Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

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The types of chemical reactions are as follows:

Chemical reactions are changes in which new substances are formed.

The types of chemical reactions are as follows:

In conclusion, chemical reactions produce new substances.

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Answer:

Explanation:

Coefficient of static friction μs = .830216

Coefficient of kinetic friction μk = .326245

a ) The angle at which the box starts sliding depends upon coefficient of static friction . If θ be the required angle

tanθ = μs

tanθ = .830216

θ = 39.7°

b )

When the box starts sliding , kinetic friction will be acting on it .

frictional force on the box = μk mg cos 39.7

net force on the box

= mg sin39.7 -  μk mg cos 39.7

Applying Newton's law of motion

mg sin39.7 -  μk mg cos 39.7  = m a

a = g sin39.7 -  μk g cos 39.7

= 9.8 x sin 39.7 - .326245 x 9.8 x cos 39.7

= 6.26 - 2.46

= 3.8 m /s² .

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Because Newton as Pressure = Thrust/Area, the answer will be 7.5.

The rotating equivalent of Newton's first law is this. When each child's weight exerts an equal amount of torque about the pivot in opposing directions, two kids can balance on a seesaw (clockwise and counter clockwise).

The idea of the seesaw You are probably aware that any two people, regardless of their weights, can balance each other while seated on opposite sides of a seesaw. All that is required is for each individual to contribute an equal moment, which is determined by multiplying the person's weight by the distance from the fulcrum.

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Answer:

Approximately \(53^{\circ}\), assuming that the upper and lower surfaces of the glass on this boat are parallel.

Explanation:

Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.

The following angles would be alternate interior angles between the two normals:

Since the two normals are parallel to each other, these two angles would have the same value. Let \(\theta_{\text{glass}}\) denote the value of both of these angles.

Let \(\theta_{\text{src}}\) denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let \(\theta_{\text{dst}}\) denote the angle at which this beam of light enters the new medium.

Let \(n_\text{src}\) and \(n_\text{dst}\) denote the refractive indices of the original and the new medium, respectively. By Snell's Law:

\(\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}\).

Let \(\theta_{\text{water}}\) denote the angle at which the beam of light in this question leaves the water. Let \(\theta_{\text{air}}\) denote the angle at which this beam of light enters the air. It is given that \(\theta_{\text{water}} = 37^{\circ}\), while \(\theta_{\text{air}}\) is the value that needs to be found.

Let \(n_{\text{air}}\), \(n_{\text{water}}\), and \(n_{\text{glass}}\) denote the refractive index of air, water, and glass, respectively. By Snell's Law:

\(\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}\).

\(\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}\).

Thus:

\(\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}\).

Since \(\theta_{\text{water}} = 37^{\circ}\):

\(\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}\).

Therefore:

\(\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}\).

In other words, this beam of light would leave the glass at approximately \(53^{\cic}\) from the normal.

d. 49.0 m/s

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Given data:

* The original length of the rope is L = 3.72 m.

* The area of cross-section of rope is,

* The Young's modulus of rope is,

* The mass of the load is,

Solution:

The weight of the load is,

Young's modulus of the rope in terms of the weight, area, and the original length of the rope is,

where l is the change in the length,

Substituting the known values,

By simplifying,

Thus, the increase in the length of the rope is 3.54 mm.

Answer:

The ball has a velocity upwards but the acceleration is downwards. Gravity is giving the ball a downwards acceleration from the moment the ball leaves the hands.

An example of a time a Christmas movie modeled acceleration on incline with friction (physics) is:

It is not uncommon for movies, including Christmas movies, to depict characters moving up or down inclines or hills. In such cases, the motion of the characters can be analyzed using the principles of physics, including acceleration and friction.

In continuation of the story above:

Therefore, By applying the laws of motion to these forces, we could calculate Buddy's acceleration as he runs up the hill.

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Answer: I feel like it is Charon