Please answer my question ASAP...I give brianliest answer.

Answer:

the answer is 7!

Step-by-step explanation: hope this helped you out :)

Given :

The value of the surface area of the cylinder is equal to the value of the volume of the cylinder.

To Find :

The relation between height and radius.

Solution :

\(S.A=2\pi rh+2\pi r^2=2\pi r(h+r)\)

\(V=\pi r^2h\)

Now ,

\(S.A=V\\\\2\pi r(h+r)=\pi r^2h\\\\2(h+r)=rh\\\\2h+2r=rh\\\\h(2-r)=-2r\\\\h=\dfrac{2r}{r-2}\)

Hence, this is the required solution.

To find the time at which only 1 mg remains, we need to solve the equation \(\displaystyle\sf 1 = y(t) = 40(2-\frac{t}{30})\), where \(\displaystyle\sf t\) represents time.

Let's solve for \(\displaystyle\sf t\):

\(\displaystyle\sf 1 = 40(2-\frac{t}{30})\).

Dividing both sides of the equation by 40:

\(\displaystyle\sf \frac{1}{40} = 2-\frac{t}{30}\).

Subtracting 2 from both sides:

\(\displaystyle\sf -\frac{79}{40} = -\frac{t}{30}\).

Multiplying both sides by 30:

\(\displaystyle\sf -\frac{79}{40} \times 30 = -t\).

Simplifying:

\(\displaystyle\sf t = -30 \log 2\).

Therefore, the time at which only 1 mg remains is \(\displaystyle\sf t = -30 \log 2\).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

it is not clear whether the data is related to proportions or not. Therefore, the statement that "the Success/Failure Condition is satisfied for sample sizes of at least 75" may not be applicable in this context.

In statistics, the normal distribution or Gaussian distribution is a continuous probability distribution that is commonly used to approximate the distribution of many random variables. One of the main applications of the normal distribution is to model the sampling distribution of the sample mean. However, the accuracy of the normal approximation depends on the sample size.

To determine the smallest sample size that would be reasonable to use the normal model as an approximation for the sampling distribution, we need to look at the histograms of the data. If the histograms are approximately bell-shaped and symmetric, the normal model is likely to be a good approximation.

In this case, it is stated that the normal model would be reasonable to use for a sample size of at least 75. This means that if the sample size is 75 or larger and the histogram is approximately bell-shaped and symmetric, we can use the normal model to approximate the sampling distribution of the sample mean.

Regarding the Success/Failure Condition, it is a condition that applies when we are using the normal model to approximate the sampling distribution of a proportion. The condition states that if np and n(1-p) are both at least 10, where n is the sample size and p is the probability of success, then we can use the normal model to approximate the sampling distribution of the proportion.

However, in this case, it is not clear whether the data is related to proportions or not. Therefore, the statement that "the Success/Failure Condition is satisfied for sample sizes of at least 75" may not be applicable in this context.

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How does cellular respiration help maintain homeostasis in animals?

Answer: Cellular respiration helps animals maintain homeostasis by breaking down glucose to produce ATP, which is the energy currency of the cell. ATP is necessary for many cellular processes that help maintain homeostasis such as active transport and protein synthesis.

Explain why cells separate and expel waste.

Answer: Cells separate and expel waste to prevent the accumulation of toxic substances that can disrupt cellular function and lead to disease. The waste products are transported out of the cell and into the bloodstream where they are filtered and excreted by organs such as the kidneys.

Why do cells in organisms such as animals reproduce?

Answer: Cells in organisms such as animals reproduce to replace damaged or dying cells, and to enable growth and development. Reproduction ensures that the organism maintains the proper balance of cells and that there is enough tissue to perform necessary functions.

Explain how plant cells use photosynthesis to maintain homeostasis?

Answer: Plant cells use photosynthesis to maintain homeostasis by converting light energy into chemical energy in the form of glucose. This glucose is then used to produce ATP, which is necessary for cellular processes such as active transport and protein synthesis. Additionally, plants use photosynthesis to produce oxygen, which is necessary for respiration.

I hope this helps :)

Answer:

A'(-3,-2) B'(-1,-4) C'(-5,-3)

Step-by-step explanation:

im pretty sure that's right

hopes this helps

Answer:

\(A( - 2, \: 3) = > A'( 2, \: - 3) \\ B( - 4, \: 1) = > B'( 4, \: - 1) \\ C( - 3,\: 5) = > C'( 3, \: - 5)

\)

'

Answer:

It's 2

Step-by-step explanation:

2^x × 3^3 = 108

2^x = 108 / 27

2^x = 4

2^x = √4

x     = 2

The limit of (x + x²)/(2 − 3x²) as x approaches infinity is -1/3.

To find the limit of (x + x²)/(2 − 3x²) as x approaches infinity, we can use l'Hospital's Rule.

First, we need to check if the limit is in the indeterminate form 0/0 or ∞/∞. As x approaches infinity, both the numerator (x + x²) and the denominator (2 - 3x²) approach infinity.

Therefore, the limit is in the indeterminate form ∞/∞, and we can apply l'Hospital's Rule.

l'Hospital's Rule states that if the limit is in the indeterminate form 0/0 or ∞/∞, we can take the derivative of the numerator and denominator separately, and then find the limit of the ratio of their derivatives.

Numerator's derivative: d/dx(x + x²) = 1 + 2x Denominator's derivative: d/dx(2 - 3x²) = -6x

Now, we'll find the limit of the ratio of their derivatives as x approaches infinity: lim (1 + 2x)/(-6x) as x→∞

We can use l'Hospital's Rule again, as this limit is also in the indeterminate form ∞/∞. Numerator's second derivative: d/dx(1 + 2x) = 2

Denominator's second derivative: d/dx(-6x) = -6

Now, we'll find the limit of the ratio of their second derivatives as x approaches infinity: lim (2)/(-6) as x→∞ Since the limit involves constants only, it does not depend on x, and we can directly compute the limit: 2 / (-6) = -1/3

Therefore, the limit of (x + x²)/(2 − 3x²) as x approaches infinity is -1/3.

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Option C is the correct option.

The sampling distribution of proportion have center equal to population proportion.

As per the details share in the above question are as follow,

The details are as follow,

Only if: Is the proportion sampling distribution regularly distributed.

\(\mathrm{np} > 5 \text { and } \mathrm{n}(1-\mathrm{p}) > 5\)

The survey proportion's anticipated value is \(\mathrm{E}(\hat{\mathrm{p}})=\mathrm{p}\).

As a result, the center of the proportional sampling distribution is equal to the population percentage.

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Mu X is a statistical concept used to measure the difference between two means.

It is calculated by subtracting the mean of one group from the mean of another group. Mu X is often used to compare the means of two or more groups, or to compare the means of two subgroups within a group. It can also be used to measure the relative size of a group's mean compared to the grand mean or the size of a group's mean compared to the mean of another group. Mu X is a useful tool for distinguishing between true and false differences between two means. It is also useful for understanding the relative importance of different factors in a study. Mu X is sometimes referred to as the difference in means or the mean difference, and it is an important concept in inferential statistics.

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Answer:

3x + 5y = 15

Find gradient:

coordinates taken: (5, 0), (0, 3)

\(\rightarrow \sf \dfrac{y_2-y_1}{x_2-x_1}\)

\(\rightarrow \sf \dfrac{3-0}{0-5}\)

\(\rightarrow \sf -\dfrac{3}{5}\)

equation:

\(\sf \bold{ y = m(x) + b}\)

\(\rightarrow \sf y = -\dfrac{3}{5} x + 3\)

\(\rightarrow \sf y = -\dfrac{3}{5} x + \dfrac{15}{5}\)

\(\rightarrow \sf 5y =-3x+15\)

\(\rightarrow \sf 3x+5y =15\)

Take two points

So

equation of line in intercept form

\(\\ \rm\rightarrowtail \dfrac{x}{a}+\dfrac{y}{b}=1\)

\(\\ \rm\rightarrowtail \dfrac{x}{5}+\dfrac{y}{3}=1\)

\(\\ \rm\rightarrowtail 3x+5y=15\)

The probability distribution function of Y = |X| is given by:
P(Y ≤ y) = P(|X| ≤ y) = P(-y ≤ X ≤ y) = P(X ≤ y) - P(X < -y)

Since X ~ N(0, 2), we can use the standard normal distribution to find the probabilities:
P(X ≤ y) = Φ(y/√2)
P(X < -y) = Φ(-y/√2)

Therefore, the probability distribution function of Y is:
P(Y ≤ y) = Φ(y/√2) - Φ(-y/√2)

To find E(|X|) and Var(|X|), we can use the properties of the absolute value function:
E(|X|) = ∫_(-∞)^(∞) |x| f(x) dx = 2 ∫_(0)^(∞) x f(x) dx
Var(|X|) = E(|X|^2) - (E(|X|))^2 = 2 ∫_(0)^(∞) x^2 f(x) dx - (2 ∫_(0)^(∞) x f(x) dx)^2

Since f(x) is the probability density function of X, we can substitute it with the standard normal distribution:
f(x) = (1/√(2π)) e^(-(x^2)/4)

Therefore, E(|X|) and Var(|X|) can be found by evaluating the integrals:
E(|X|) = 2 ∫_(0)^(∞) x (1/√(2π)) e^(-(x^2)/4) dx = √(2/π)
Var(|X|) = 2 ∫_(0)^(∞) x^2 (1/√(2π)) e^(-(x^2)/4) dx - (√(2/π))^2 = 2 - (2/π)

So the final answers are:
1. E(|X|) = √(2/π)
2. Var(|X|) = 2 - (2/π)

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Answer:

-3/8

Step-by-step explanation:

I would use a table

x      y

-4     5

-12    8

from -4 to -12 you subtract -8

from 5 to 8 you add 3

so y/x  = 3/-8

The slope is - \(\frac{3}{8}\)

Hope this helped!

Answer:

10 cm

Step-by-step explanation:

Diameter= 2X radius

20/ 2 = radius

20/2 = 10 cm

The principal amount that must be invested at an interest rate of 9%, compounded continuously, so that $1,000,000 will be available for retirement in 20 years is $271,716.

The interest rate (r) is given as 9%, which means that for every year that passes, the investment will earn 9% of its value in interest. The time period (t) is given as 20 years, which means that the investment will be made for a period of 20 years before the retirement funds are needed.

The principal amount (P) is the amount of money that needs to be invested upfront in order to earn the desired amount of money at the end of the investment period. In this case, we want to end up with $1,000,000 after 20 years of continuous compounding at 9%.


So to determine the principal amount needed to reach our goal, we will need to use the formula:  \(A = Pe^(rt)\)
where A is the desired amount at the end of the investment (in this case, $1,000,000), e is the mathematical constant 2.71828..., r is the interest rate (0.09 in decimal form), and t is the time period (20 years).

Rearranging this formula to solve for P, we get:  \(P = A / e^(rt)\). Plugging in the given values, we get:  \(P = $1,000,000 / e^(0.09*20)\)  Using a calculator, we can find that P is approximately $271,716.

The principal amount that must be invested at an interest rate of 9%, compounded continuously, so that $1,000,000 will be available for retirement in 20 years is $271,716.

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Answer:

-12x+28

Step-by-step explanation:

if correct plz mark as brainliest

thank you

19NBoli

Answer:

-12x - 7.

Step-by-step explanation:

Hope this helps!

The correct option is B. The statement "The multiplicity of a root r of the characteristic equation of A is called the algebraic multiplicity of r as an eigenvalue of A." is true. The statement is the definition of the algebraic multiplicity of an eigenvalue of A.

A matrix is diagonalizable if and only if each eigenvalue of the matrix has an algebraic multiplicity that is equal to its geometric multiplicity. To get the characteristic equation of a matrix, the determinant of the matrix A   I is set to zero. The characteristic equation of an nn matrix A is given by AI = 0. The characteristic equation's roots are the matrix's eigenvalues.

The algebraic multiplicity of an eigenvalue is the number of times it appears as the root of the characteristic equation. The geometric multiplicity of an eigenvalue is the number of linearly independent eigenvectors corresponding to that eigenvalue. So, the correct option is B.

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Answer: 7.07 m/s

Step-by-step explanation:

I took the quiz and that was the correct answer 5 is wrong

The speed of the dog at half of its kinetic energy is 7.07 m/s. The correct option is (B).

When two quantities have some dependence in their values they can be said proportional to each other.

It can be of two types such as direct and indirect.

The direct proportionality means the values of both the quantities are increasing or decreasing at the same time while the indirect proportionality implies value of one quantity is increasing while the other is decreasing.

Given that,

The present speed of the dog is 10 m/s.

Suppose the mass of the dog be m kg.

Since, the kinetic energy of an object is given as K = 1/2mv².

As per the question, the following expression can be written,

Initial energy, K₁ = 1/2m × 10²

                           = 50m

Final energy, K₂ = K₁/2

                           = 50m/2

                           = 25m

Using the expression for kinetic energy,

1/2mv² = 25m

=> v² = 50

=> v = √50

       = 7.07

Hence, the speed of the dog when its kinetic energy is reduced to half is 7.07 m/s.

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The circumference of the ring is determined as 10.85 ft.

The circumference of the ring is calculated by applying the following formula for circumference of a circle

Circumference = π × diameter

The given parameter include;

The circumference of the ring is calculated as follows;

Circumference = 3.14 × 3.5 feet

Circumference = 10.85 ft

Thus, the circumference of the ring is equal to the circle of a circle with equal diameter of 3.5 feet, and the magnitude is determined as 10.85 ft.

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The extended ring R[a], obtained by adjoining an element a to a ring R, is indeed a ring isomorphic to R. This is demonstrated by showing that R[a] satisfies the properties of a ring and by constructing an isomorphism between R[a] and R.

To prove that adjoining an element a to a ring R gives a ring isomorphic to R, we need to show that the extended ring R[a] satisfies the definition of a ring and that there exists an isomorphism between R[a] and R.

First, let's define the extended ring R[a]. The elements of R[a] are represented as polynomials in a with coefficients from R. An element in R[a] can be written as:

R[a] = {r₀ + r₁a + r₂a² + ... + rₙaⁿ | r₀, r₁, r₂, ..., rₙ ∈ R}

where n is a non-negative integer and r₀, r₁, r₂, ..., rₙ are coefficients from R.

Now, let's prove the two main properties of a ring for R[a]:

Closure under addition and multiplication:

For any two elements (polynomials) p = r₀ + r₁a + r₂a² + ... + rₙaⁿ and q = s₀ + s₁a + s₂a² + ... + sₘaᵐ in R[a], the sum p + q and product p * q are also elements of R[a]. This can be proven by applying the distributive property and associativity of addition and multiplication.

Existence of additive and multiplicative identities:

The additive identity in R[a] is the polynomial 0, and the multiplicative identity is the polynomial 1. These identities satisfy the properties of an additive and multiplicative identity, respectively, when added or multiplied with any element in R[a].

Next, we need to show that there exists an isomorphism between R[a] and R, which means there is a bijective map that preserves the ring structure.

Consider the function φ: R[a] → R defined as φ(r₀ + r₁a + r₂a² + ... + rₙaⁿ) = r₀. This function maps each polynomial in R[a] to its constant term.

We can prove that φ is an isomorphism by verifying the following:

a) φ preserves addition: φ(p + q) = φ(p) + φ(q) for any p, q in R[a].

b) φ preserves multiplication: φ(p * q) = φ(p) * φ(q) for any p, q in R[a].

c) φ is bijective: φ is both injective and surjective.

The proofs for these properties involve applying the distributive property and associativity of addition and multiplication, and considering the coefficients of the polynomials.

Hence, we have shown that adjoining an element a to a ring R gives a ring isomorphic to R, denoted as R[a] ∼ R.

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The set in problem 8 was not a subspace because one of the subspace axioms requires that the zero vector, which is the additive identity element, is included in the set. In the given problem, the zero vector was not part of the set, so it failed to satisfy this axiom

a. The set F is a subset of the vector space of continuous functions on some interval, which we have studied this semester.

b. To prove whether F is a subspace of the vector space of continuous functions, we need to check if F satisfies the three subspace axioms: closure under addition, closure under scalar multiplication, and the zero vector property.

Let f and g be two functions in F, and let c be a scalar. To show closure under addition, we need to prove that f + g is also in F. Since both f and g have the property that f'(2) = 0 and g'(2) = 0, their sum (f + g) will also have the property that (f + g)'(2) = f'(2) + g'(2) = 0 + 0 = 0. Therefore, f + g is in F.

To show closure under scalar multiplication, we need to prove that cf is also in F. Again, since f has the property that f'(2) = 0, multiplying f by any scalar c will not change the derivative at 2. Therefore, (cf)'(2) = c × f'(2) = c × 0 = 0, and cf is in F.

Finally, the zero vector property states that the zero function, denoted as 0, must be in F. The zero function has the property that its derivative is always zero, including at 2. Therefore, 0'(2) = 0, and the zero function is in F.

Since F satisfies all three subspace axioms, we can conclude that F is a subspace of the vector space of continuous functions.

c. We can get away with not checking the other eight axioms (associativity, commutativity, distributivity, etc.) because F is a subset of a known vector space. By being a subset of a vector space, F inherits those axioms from the larger vector space. The other eight axioms are properties of vector spaces that hold true for all vectors in the larger vector space, including the vectors in F. Therefore, if F satisfies the subspace axioms, it automatically satisfies the other eight axioms by virtue of being a subset of a vector space.

d. It was not okay to only check the two subspace axioms on problem 8 from exam 2 because the set in that problem did not satisfy the zero vector property. One of the subspace axioms requires that the zero vector, which is the additive identity element, is included in the set. In the given problem, the zero vector was not part of the set, so it failed to satisfy this axiom. As a result, the set in problem 8 was not a subspace.

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Answer:

x=1/6

Step-by-step explanation:

since the base is the same, condense the equation

from log m base a=log n base n, m=n

Answer:

3.6

Step-by-step explanation:

Answer:

3.6

Step-by-step explanation:

see attached image

Answer:

160

Step-by-step explanation:

Give me brainliest PLz

I need it

Answer:

Q14    x = 3

Q15    No unique solution

Step-by-step explanation:

Q14

The value of x where the line crosses the x axis is the solution for x

Here we see the line crosses the x axis at x = 3 so solution is x =3

Mathematically,

2x - 3 = 3

2x = 3 + 3  adding 3 to both sides

2x = 6

x = 6/2 = 3

Q15

This is a horizontal line which crosses the y-axis at y = 1

Since this does not cross the x axis but is parallel to it, there is no unique solution for x

Mathematically,
-4x + 2 = -4x + 1

Adding 4x to both sides we get the absurdity that 2 = 1 and that indicates no unique solution for x. Alternatively we can say that x has an infinite number of solutions

The volume of Brody's display case is 270 cubic inches.

Brody's display case is shaped like a rectangular prism with a length of 15 inches, a width of 9 inches, and a height of 2 inches.

A rectangular prism is a three-dimensional shape that has six faces that are all rectangles. It is also sometimes called a rectangular cuboid.

The volume of a rectangular prism is the amount of space inside the prism and is given by the formula:

Volume = length x width x height

where "length" refers to the longest side of the prism, "width" refers to the second longest side of the prism, and "height" refers to the shortest side of the prism.

To find the volume of a rectangular prism, you simply need to multiply the length, width, and height of the prism together. The resulting value will have cubic units, such as cubic inches, cubic centimeters, or cubic feet, depending on the units used for the length, width, and height.

To find the volume of the display case, we simply need to multiply its length, width, and height together. Using the values you provided:

Volume = length x width x height

Volume = 15 inches x 9 inches x 2 inches

Volume = 270 cubic inches

Therefore, the volume of Brody's display case is 270 cubic inches.

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Answer:

False

Step-by-step explanation:

I looked it up and I also remember it from school. The earth is closer to the sun in the winter. When i looked it up, heres what came up (from the library of congress): Many people believe that the temperature changes because the Earth is closer to the sun in summer and farther from the sun in winter. In fact, the Earth is farthest from the sun in July and is closest to the sun in January!

I'm pretty certain this is right, let me know.

The ring Zp we have (a+b)^p =a^p + b^p for every a, b element of Zp. For Z6, the result is not true.

To show that (a+b)^p = a^p + b^p in the ring Zp, we can use the binomial theorem for a commutative ring.

For any integer n>=0 and elements a,b in a commutative ring, we have:

(a+b)^n = sum(k=0 to n) (n choose k) a^(n-k) b^k

where (n choose k) is the binomial coefficient.

Now, for p prime, the binomial coefficients (p choose k) are divisible by p for 0<k<p. This can be shown using the formula:

(p choose k) = p!/((p-k)! k!)

where p! is the factorial of p. Since p is prime, the denominator of (p choose k) contains no factors of p, but the numerator does, precisely p factors. Thus, (p choose k) is divisible by p for 0<k<p.

Using this fact, we can simplify the binomial expansion for (a+b)^p as follows:

(a+b)^p = sum(k=0 to p) (p choose k) a^(p-k) b^k

= a^p + b^p + pa^(p-1)b + pab^(p-1) + sum(k=2 to p-1) (p choose k) a^(p-k) b^k

Since (p choose k) is divisible by p for 0<k<p, we see that each of the terms in the sum is divisible by p, so we can conclude that:

(a+b)^p = a^p + b^p (mod p)

which means that (a+b)^p and a^p + b^p differ by a multiple of p, and hence they are equal in the ring Zp.

For Z6, the result is not true. For example, take a=2 and b=4. Then:

(a+b)^p = 6^p = 0 (mod 6)

but

a^p + b^p = 2^p + 4^p

can take different values modulo 6 depending on the value of p. For instance, when p=2 we have:

2^2 + 4^2 = 20 = 2 (mod 6)

but when p=3 we have:

2^3 + 4^3 = 72 = 0 (mod 6)

so in general a^p + b^p need not be equal to (a+b)^p in Z6.

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