Please help asap!! Due today!

Answer:

LM = 85.5

Step-by-step explanation:

B1 + B2/2

46 + 125/2

LM = 85.5

Answer:

The answer is angle 7

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

It asks for the alternate exterior angle

1 is adjacent to 2

5 is interior

and 8 is not alternate to 2, so that leaves 7

Answer: 8250

Step-by-step explanation:

Multiply by 1.065 and subtract by 5000 to get  6.5% of 5000

1.065 * 5000 = 5325

5325-5000 = 325

6.5% of 5000 = 325

Multiply by 10 and add on value to 5000

325 *  10 = 3250

5000 + 3250 = 8250

Answer:

the kast option where g(-2) is greater than g(4)

Step-by-step explanation:

Answer:36

Step-by-step explanation:

Answer:

The x-coordinate is - 21986106

Step-by-step explanation:

Answer: More

Step-by-step explanation: 436x252 = 109872.

Answer:

more than 1000,000

Step-by-step example

well 436 times 252 is 109872 and 109872 minus 1000,000 is 890128 miles therefor a pilot flies more than 1000,000 miles from Boston to Philadelphia

Answer:

14/17

Step-by-step explanation:

14/17 as a fraction can't be simplified. 17 is a prime number, so it can't be divided by anything except 1.

If the question you're asking is 14-17, the answer would be -3...

I hope this helped you out!! Have an awesome day C:

Step-by-step explanation:

if you are subtracting it is -3

if you are dividing it is 0.823

if you are looking for an equivalent fraction it is 28/34

After reducing all the book prices by 50%, the new median price is determined to be $7.70 (B)

To find the new median price after reducing all the book prices by 50%, we first need to calculate the reduced prices. By reducing each given price by 50%, we get $6.375, $7.40, $9.995, $4.975, $8.00, and $8.975 respectively.

Next, we arrange these reduced prices in ascending order: $4.975, $6.375, $7.40, $8.00, $8.975, and $9.995. The median is the middle value in this ordered list. Since there are six prices, the middle two values are $7.40 and $8.00.

To find the median, we take the average of these two values, which gives us ($7.40 + $8.00) / 2 = $7.70.

Therefore, the new median price, after reducing all the book prices by 50%, is $7.70 (B). This means that the median price of the books, after the reduction, is $7.70.

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For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

217 oz

Step-by-step explanation:

You can easily eliminate 5 oz because 217 oz is larger already

Now all you have left is 13 lbs and 217 oz

217 oz is about 13.6 lbs

So 217 oz is the largest

The equation of the tangent line to the curve y = ln(x^2 - 5x + 1) at the point (5,0) is y = 0.

To find the equation of the tangent line to the curve y = ln(x^2 - 5x + 1) at the point (5,0), we need to find the slope of the tangent line at that point.

The derivative of y = ln(x^2 - 5x + 1) is:

y' = (2x - 5)/(x^2 - 5x + 1)

At the point (5,0), we have:

y' = (2(5) - 5)/(5^2 - 5(5) + 1) = 0

So the slope of the tangent line at (5,0) is 0.

The equation of the tangent line can be written as:

y - y1 = m(x - x1)

where (x1, y1) is the point of tangency and m is the slope.

Since the slope is 0, we have:

y - 0 = 0(x - 5)

which simplifies to:

y = 0

Therefore, the equation of the tangent line to the curve y = ln(x^2 - 5x + 1) at the point (5,0) is y = 0.

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The formula for logistic growth can be expressed as P(t) = K / (1 + A * e^(-rt)), where P(t) is the population at time t, K is the carrying capacity, r is the growth rate, A is the initial population.

Logistic growth is a type of population growth that considers a carrying capacity, which is the maximum population size that an environment can sustain. The formula for logistic growth takes into account the carrying capacity (K), the growth rate (r), and the initial population (A) to describe how the population changes over time.

In this case, the carrying capacity is given as 1500, and the growth rate is 0.25 per year. Let's denote the population at time t as P(t).

The formula for logistic growth can be written as:

P(t) = K / (1 + A * e^(-rt))

Plugging in the given values, we have:

P(t) = 1500 / (1 + A * e^(-0.25t))

The value of A is not explicitly given, so it represents the initial population. If the initial population is known, it can be substituted into the formula. If not, A can be left as a variable.

The term e^(-0.25t) represents the exponential decay component, which approaches 0 as t increases. It is multiplied by A, allowing the population to approach the carrying capacity over time.

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Answer:

i just realy need points

Step-by-step explanation:

Which of these values for x make the value of the expression (x-5)(x+7) the greatest? ​

This is a quadratic equation (vertical parabola) open upward

the vertex is a minimum

the greatest value of this expression is for the greater value of x in absolute value

we have

that -9 is the greater value in absolute value

therefore

the answer is -9

Answer:

C ≈ 25.13 ft

Step-by-step explanation:

the circumference (C) of a circle is calculated as

C = 2πr ( r is the radius ) , then

C = 2π × 4 = 8π ≈ 25.13 ft ( to 2 decimal places )

Answer:

QR = 15

Step-by-step explanation:

The product of the length of the secant segment and its external part equals the square of the length of the tangent segment.

(QR+5) *5 = 10^2

(QR+5) *5 = 100

Divide each side by 5.

(QR+5) *5/5 = 100/5

(QR+5)  = 20

Subtract 5 from each side.

QR = 20-5

QR = 15

The dollar was worth more than today in 1960 and 1880. In those years, inflation-adjusted values of the dollar were higher.

To determine when the dollar was worth more than it is today, we need to consider the historical context and inflation rates. Inflation erodes the purchasing power of a currency over time. Comparing the given years, 1960 and 1880, with today, we find that the dollar had higher purchasing power in both those periods.

In 1960, the dollar had a higher value due to lower inflation rates compared to today. Similarly, in 1880, the dollar's purchasing power was even higher due to significantly lower inflation rates during that time. Therefore, in both 1960 and 1880, the dollar was worth more than it is today, considering inflation-adjusted values.

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The approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches is 0.6

To find the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches, we will first calculate the surface area (SA) and volume (V) of the ball, and then divide the surface area by the volume.

Step 1: Calculate the surface area (SA) using the formula for the surface area of a sphere:

\(SA = 4 πr^2\)
\(SA = 4 π5^2\)
\(SA = 4 π(25)\)
\(SA=100π\)

Step 2: Calculate the volume (V) using the formula for the volume of a sphere:

\(V = \frac{4}{3} π (r)^{3}\)
\(V = \frac{4}{3} π (5)^{3}\)
\(V = \frac{4}{3} π (125)\)
V = 166.67 π cubic inches

Step 3: Calculate the surface-area-to-volume ratio (SA/V)
\(\frac{SA}{V} = \frac{100}{166.67}\)
\(\frac{SA}{V}=\frac{100}{166.67}\)

\(\frac{SA}{V}= 0.6\)

So the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches is 0.6. The best answer from the choices provided is A.

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Answer:

The total height of the climbing wall is 12 feet

Step-by-step explanation:

The given parameters are;

The star of the climbing wall = On the gym basement

The height of the gym's basement above the ground level = 9 feet

The height to which the wall extends above the ground level = 21 feet

The total height of climbing the wall = 21 - 9 = 12 feet

The start of the climbing wall is at the gym's basement level which is already 9 feet above the ground level, therefore, given the the height of the wall is 21 feet above ground level, with wall situated already at 9 feet above ground level which gives the total height of the climbing wall will be 21 - 9 feet or 12 feet.

Answer:

To find a power of a power, multiply the exponents.  This is an extension of the product of powers property . Suppose you have a number raised to a power, and you multiply the whole expression by itself over and over. This is the same as raising the expression to a power.

Answer:

Step-by-step explanation: When raising a power to a power in an exponential expression, you find the new power by multiplying the two powers together. For example, in the following expression, x to the power of 3 is being raised to the power of 6, and so you would multiply 3 and 6 to find the new power.

i hope this help

Answer:

4x=-16

x=-4 is your answer

Answer:A) x = -4

Additive inverse -3 to both sides 4x=-16

The divide both sides by 4, x=-4

Step-by-step explanation:

The probabilities of having 0, 1, 2, and 3 access lines in use are approximately 0.000048, 0.001636, 0.011072, and 0.047368, respectively. These probabilities are calculated using the Poisson distribution formula based on the given mean arrival rate of 34 calls per hour and a service rate of 18 calls per hour.

To determine the probabilities of having 0, 1, 2, and 3 access lines in use, we can use the Poisson distribution formula. Given a mean arrival rate of 34 calls per hour and a service rate of 18 calls per hour, we can calculate the probabilities as follows:

For 0 access lines in use, the probability can be calculated using the formula \(P(X = 0) = \frac {e^{-\lambda} * \lambda^0}{0!}\) where λ is the mean arrival rate. Substituting the values, we have \(P(X = 0) = e^{-34} * (34^0) / 0! = 0.000048\).

Similarly, for 1, 2, and 3 access lines in use, we can calculate the probabilities using the same formula. The probabilities are:

\(P(X = 1) = e^{-34} * (34^1) / 1! = 0.001636\)
\(P(X = 2) = e^{-34} * (34^2) / 2! = 0.011072\)
\(P(X = 3) = e^{-34} * (34^3) / 3! = 0.047368\)

Therefore, the probabilities of having 0, 1, 2, and 3 access lines in use are approximately 0.000048, 0.001636, 0.011072, and 0.047368, respectively.

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c i think

Step-by-step explanation:

Debbie can buy a maximum of 4 t-shirts with the remaining $38 after purchasing the $22 jeans.

To determine the greatest number of t-shirts Debbie can buy, we need to find out how much money she will have left after purchasing the pair of jeans. Debbie has $60 to spend and the jeans cost $22. Therefore, she will have $60 - $22 = $38 left to spend on t-shirts.

Each t-shirt costs $8, so we divide the remaining amount by the cost per t-shirt: $38 / $8 = 4.75.

Since Debbie cannot buy a fraction of a t-shirt, we round down the decimal value to the nearest whole number. Therefore, Debbie can buy a maximum of 4 t-shirts with the remaining $38.

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Answer:

7x-15/5

Step-by-step explanation:

Given :-

And , we need to solve for y in terms of x . So taking the given equation ,

\(:\implies\) 7x - 5y = 15

\(:\implies\) -5y = 15 - 7x

\(:\implies\) 5y = 7x - 15

\(:\implies\) y = ( 7x - 15)/5

The speed of Fred's snowmobile was 30 miles per hour.

This is calculated by dividing the distance traveled by the time taken for each journey, which gives a speed of 30 mph for both the outward and return journeys.

To find Fred's speed, we can use the formula speed = distance/time. We know that Fred traveled a distance of 360 miles in 12 hours on the outward journey, so his speed was 360/12 = 30 mph.

Similarly, on the return journey, he traveled the same distance of 360 miles, but it took him 15 hours, so his speed was again 360/15 = 24 mph.

However, we are asked to find his constant speed, so we take the average of the two speeds, which gives us (30 + 24)/2 = 27 mph. Therefore, Fred's snowmobile was traveling at a constant speed of 30 mph on both journeys.

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Answer:

50.24m

Step-by-step explanation:

3.14 x 16 = 50.24

Answer:

can i see the rest of the problem...

Step-by-step explanation:

Answer:

I mean, I think it varies by house and by location but a general range would be:

Min: 64 *F

Max: 74 *F