please help asap
Jordan's recipe for chocolate cake asks
for 2 с of flour, c of butter, and 1 c of
sugar, among other ingredients. How
much flour, butter, and sugar will she
need to make three cakes?
Answers
Answer:
what is the butter amount?
Step-by-step explanation:
x's everything by 3
2x3=6 c of flour
1x3=3 c of sugar
Related Questions
Kayla is going to invest in an account paying an interest rate of 2.9% compounded
monthly. How much would Kayla need to invest, to the nearest cent, for the value of
the account to reach $42,000 in 6 years?
Answers
Answer:
the answer is 48m^2!
Step-by-step explanation:
Answer:
The answer is 35299.88. Hope this helps
Which statement about a dilation with a scale factor of 3 is true?
Answers
Given : dilation with a scale factor of 3
To find : Which statement is true
Solution:
A dilation is a transformation that produces an image that is the same shape as the original, but is a different size
if Dilation factor N then image Size is multiplied by N
if Scale factor < 1 then image get reduced
if scale factor > 1 then image get enlarged
scale factor = 1 lead to Same size image
Here is given that Scale factor of 3
=> image will be enlarged to 3 times the original image
Hence correct option is :
C)Each side in the pre-image is multiplied by three to find the corresponding side length in the image
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a) y = 5x
What happens to the value of y if the value of x doubles?
Select your answer.
×2, ×5, ÷2, ÷5
A B C D
b)y=5/X
What happens to the value of y if the value of X triples?
Select your answer.
×2, ×3, ÷2, ÷3
A B C D
Answers
Answer:
1- it will ×2 (a),2- ÷3 (d)
An atom of rhodium (Rh) has a diameter of about 2.7×10−8cm. If the atom is assumed to be a sphere, what is the volume in m3 of a single Rh atom?
Answers
Therefore, the volume of a single Rh atom is approximately 1.011 × 10^(-29) m^3.
The diameter of a single Rh atom is given as 2.7 × 10^(-8) cm. The radius of the atom, which is half of the diameter, is therefore:
r = 2.7 × 10^(-8) cm / 2 = 1.35 × 10^(-8) cm
To find the volume of the sphere, we can use the formula:
V = (4/3)πr^3
where π is the constant pi.
Substituting the values, we get:
V = (4/3)π(1.35 × 10^(-8) cm)^3
= 1.011 × 10^(-23) cm^3
However, the answer is required in m^3, so we need to convert cm^3 to m^3. We know that:
1 cm = 0.01 m
Therefore:
(1 cm)^3 = (0.01 m)^3
1 cm^3 = 1 × 10^(-6) m^3
Substituting this conversion factor, we get:
V = 1.011 × 10^(-23) cm^3 × 1 × 10^(-6) m^3/cm^3
= 1.011 × 10^(-29) m^3
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A distributor receives a large shipment of components. The distributor would like to accept the shipment if 10% or fewer of the components are defective and to return it if more than 10% of the components are defective. She decides to sample 10 components, and to return the shipment if more than 1 of the 10 is defective. a. If the proportion of defectives in the batch is in fact 10%, what is the probability that she will return the shipment
Answers
Let p be the proportion of defectives in the shipment. Since p = 0.10 and we have a sample of n = 10 components drawn from the shipment, then from the binomial distribution we get:
Let p be the proportion of defectives in the shipment.
Thus, the probability that the distributor will return the shipment if the proportion of defectives in the batch is in fact 10% is 0.2639.
Summary:In summary, we are given that the proportion of defectives in the shipment is 10% and we are asked to find the probability that the distributor will return the shipment if 10 components are sampled and more than 1 of the 10 is defective. We can calculate this probability using the binomial distribution, which yields a probability of 0.2639.
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when comparing several population means, we cannot perform a bunch of two-sample t tests because
Answers
By utilizing the methods, we can make valid and meaningful comparisons between several population means while appropriately controlling for errors and maintaining statistical power.
When comparing several population means, it is not feasible or appropriate to perform a bunch of two-sample t-tests for several reasons.
Increased Type I Error Rate: When conducting multiple hypothesis tests, there is an increased chance of making a Type I error, which is rejecting a null hypothesis when it is actually true. The more tests we perform, the greater the likelihood of observing statistically significant results by chance alone. This phenomenon is known as multiple comparisons problem or familywise error rate inflation. Performing multiple t-tests without adjusting for multiple comparisons can lead to an inflated overall Type I error rate.
Increased Chance of False Positive Results: Conducting multiple t-tests without appropriate adjustments increases the chance of obtaining false positive results. With each additional test, the probability of incorrectly concluding a significant difference between means due to random variation alone increases. This can lead to spurious findings and misleading interpretations.
Lack of Control for Experiment-Wide Error: Conducting multiple t-tests does not provide a control for the overall experiment-wise error rate. When comparing several population means simultaneously, it is essential to control the overall Type I error rate to maintain the desired level of statistical significance.
Loss of Statistical Power: Conducting multiple tests without appropriate adjustments can lead to a loss of statistical power. Power refers to the ability to detect a true effect when it exists. When multiple t-tests are performed, the individual sample sizes for each comparison may become smaller, reducing the power to detect true differences between population means.
To address these issues and appropriately compare several population means, various statistical techniques are available. Some common approaches include:
Analysis of Variance (ANOVA): ANOVA allows for simultaneous comparison of means across multiple groups. It tests the null hypothesis that all means are equal and provides an overall F-test to determine if there are significant differences between the groups. ANOVA takes into account the variation within and between groups, providing a more comprehensive analysis compared to multiple t-tests.
Multiple Comparison Procedures: If ANOVA reveals a significant overall difference, multiple comparison procedures, such as Tukey's Honestly Significant Difference (HSD) test or the Bonferroni correction, can be used to identify specific pairwise differences between means while controlling for the experiment-wise error rate.
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Andrew and Thomas collected a total of 190 bugs
for a science project. Andrew collected 10 more
bugs than Thomas. Which number sentence shows
the number of bugs that Andrew collected, b?
Answers
Answer:
b + b - 10 = 190
⇒ 2b - 10 = 190
Step-by-step explanation:
Let b = number of bugs Andrew collected
⇒ b - 10 = number of bugs Thomas collected
Given total number of bugs = 190
b + b - 10 = 190
To solve:
b + b - 10 = 190
⇒ 2b - 10 = 190
⇒ 2b = 200
⇒ b = 100
Therefore, Andrew colleted 100 bugs and Thomas collected 90 bugs.
I’m not sure I need help
Answers
Answer:
D) \(1 < x\leq 4\)
Step-by-step explanation:
1 is not included, but 4 is included, so we can say \(1 < x\leq 4\)
Solve for v. (v−4) 2=2v 2−3v+20
Answers
The solutions for v of the equation are:
v = (-5 + √(41)) / 2
v = (-5 - √(41)) / 2
Here, we have,
To solve the equation (v-4)² = 2v² - 3v + 20,
we can expand the squared term and simplify the equation:
(v-4)(v-4) = 2v² - 3v + 20
(v² - 4v - 4v + 16) = 2v² - 3v + 20
v² - 8v + 16 = 2v² - 3v + 20
Rearranging the equation:
0 = 2v² - v² - 3v + 8v - 20 + 16
0 = v² + 5v - 4
Now, let's solve this quadratic equation.
We can either factor it or use the quadratic formula.
In this case, we'll use the quadratic formula:
v = (-b ± √(b² - 4ac)) / (2a)
For our equation v² + 5v - 4 = 0, we have a = 1, b = 5, and c = -4.
v = (-(5) ± √((5)^2 - 4(1)(-4))) / (2(1))
v = (-5 ± √(25 + 16)) / 2
v = (-5 ± √(41)) / 2
Therefore, the solutions for v are:
v = (-5 + √(41)) / 2
v = (-5 - √(41)) / 2
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Calculate the unit rate for Machine A and Machine B. Determine which is the greater rate.
I need help on this, asap‼️
Answers
Answer:
A: 2 1/2 ft^2/h
B: 3 1/3 ft^2/h
B has the greater rate
Step-by-step explanation:
The rate in square feet per hour is found by dividing square feet by hours.
Machine A:
(5/8 ft^2) ÷ (1/4 h) = (5/8)×(4/1) ft^2/h = 5/2 ft^2/h = 2 1/2 ft²/h
Machine B:
(2/3 ft^2) ÷ (1/5 h) = (2/3)×(5/1) ft^2/h = 10/3 ft²/h = 3 1/3 ft²/h
Machine B has the greater rate.
Using diagonals from a common vertex, how many triangles could be formed from a13-gon?
Answers
Using diagonals from a common vertex, 143 triangles could be formed from a13-gon. But there will be 47 distinct triangles in total.
If we choose a common vertex of an n-gon, we can form (n-2) triangles by drawing diagonals from that vertex to each of the other vertices of the polygon. This is because every vertex, except for the adjacent vertices, can be connected to the chosen vertex to form a triangle.
Therefore, for a 13-gon, we can choose any one of the 13 vertices as the common vertex and form (13-2) = 11 triangles using diagonals from that vertex. We can repeat this process for each of the 13 vertices to form a total of 13*11 = 143 triangles.
However, we need to be careful not to count the same triangle multiple times. In the process of forming triangles from a common vertex, we may end up forming some of the same triangles using different vertices. For example, the triangle formed by connecting vertices 1, 6, and 9 is the same as the triangle formed by connecting vertices 9, 6, and 1.
To avoid double-counting, we can divide the total number of triangles by 3, since each triangle is counted 3 times in the process of forming triangles from a common vertex. Therefore, the number of distinct triangles that can be formed using diagonals from a 13-gon is 143/3 = 47.
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Hello what is the answer to this and the domain
Answers
We are given the following functions:
\(\begin{gathered} f(x)=7\sqrt[]{x}+6 \\ g(x)=x+6 \end{gathered}\)We are asked to determine the composite function:
\((f\circ g)(x)\)The composition of functions is equivalent to:
\((f\circ g)(x)=f(g(x))\)Therefore, we replace the value of "x" in function "f" for the function "g", therefore, we get:
\((f\circ g)(x)=f(g(x))=7\sqrt[]{x+6}+6\)Since we can't simplify any further this is the composition.
Now we are asked to determine the domain of this function. Since we have a square root, the domain must be the values of "x" where the term inside the radical is greater or equal to zero, therefore, we have:
\(x+6\ge0\)Now we solve for "x" by subtracting 6 from both sides:
\(x\ge-6\)Therefore, the domain is:
\(\lbrack-6,\infty)\)Help me please help me on number 20 you will get Brainliest 10 POINTS
Answers
Answer:
12 peppermint cupcakes 16 white cupcakes 22 chocolate cupcakes
Step-by-step explanation:
x+(x+4)+(x+(x+4)-6)=50
4x+4+4-6=50
4x+4-2=50
4x+2=50
4x=48
x=48/4
x=12 peppermint cupcakes
12+4= 16 white cupcakes
12+12+4-6=
12+16-6=
12+10= 22 chocolate cupcakes
check:
12+16+22=50
28+22=50
50=50 ✓
What is the measure of ∠xbc? m∠xbc = m∠bac m∠bca 3p â€"" 6 = p 4 84 3p â€"" 6 = p 88 2p â€"" 6 = 88 2p = 94 m∠xbc = °
Answers
Answer:
m∠XBC = 135
Step-by-step explanation:
What is the measure of ∠XBC?
m∠XBC = m∠BAC + m∠BCA
3p – 6 = p + 4 + 84
3p – 6 = p + 88
2p – 6 = 88
2p = 94
From the simplified expression, we need to find the value of p first
From the last line we can see that;
2p =94
Divide both sides by 2:
2p/2 =94/2
p = 47
From the expression, m∠XBC =3p-6
m∠XBC = 3(47)-6
m∠XBC = 141 -6
m∠XBC = 135
Hence the measure of m∠XBC is 135
Jeremy rounded the weight of his fruit to the nearest whole. He said his bag of apples weighed 4 pounds. What could have been the actual weight of his bag of apples? Group of answer choices
Answers
Answer: 3.5 - 4.4 pounds
Step-by-step explanation:
You included no options so I answered with the range of the answer.
When rounding a number up to the nearest whole number, the number needs to have the first decimal being 0.5 and above all the way to 0.9.
When rounding a number down to the nearest whole number, the number needs to have its first decimal being 0.1 to 0.4 to be rounded down.
For instance, 3.5 to 3.9 would get rounded up to 4 pounds.
4.1 to 4.4 would be rounded down to 4 pounds.
Consider the function P(x)=x2, which is a parabola that opens upward, with a vertex at (0,0).
It undergoes four separate transformations as indicated by the graphs that follow.
P(x) represents the preimage and is placed correctly on all images. I(x) represents the image after the transformation.
Match each transformation indicated by I(x) to the correct graph.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
I(x)=P(x)−4
I(x)=P(x+4)
I(x)=P(x)+4
I(x)=P(x−4)
Answers
The equations and their graphs are:
Graph 4: I(x)=P(x)−4Graph 2: I(x)=P(x+4)Graph 1: I(x)=P(x)+4Graph 3: I(x)=P(x−4)How to match the equations and their graphs?The parent function is given as:
P(x) = x^2
As a general rule of function transformation, we have:
Vertical translation up: I(x) = P(x) + kVertical translation down: I(x) = P(x) - kHorizontal translation left: I(x) = P(x + k) Horizontal translation right : I(x) = P(x - k)Using the above rules and the assumption that k is 4;
We have:
Vertical translation up: I(x) = P(x) + 4Vertical translation down: I(x) = P(x) - 4Horizontal translation left: I(x) = P(x + 4) Horizontal translation right : I(x) = P(x - 4)Hence, the graphs of the equations are:
Graph 4: I(x)=P(x)−4Graph 2: I(x)=P(x+4)Graph 1: I(x)=P(x)+4Graph 3: I(x)=P(x−4)Read more about function transformation at:
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Use the given conditions to write an equation for the line in point-slope form and slope-intercept form. Slope =−3, passing through (−7,−5) Type the point-slope form of the line: (Simplify your answer. Use integers or fractions for any numbers in the equation.)
Answers
The point-slope form of a line is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line, and m is the slope of the line.
Substituting the values, we get:
y - (-5) = -3(x - (-7))
y + 5 = -3(x + 7)
Simplifying the equation, we get:
y + 5 = -3x - 21
y = -3x - 26
Therefore, the equation of the line in point-slope form is y + 5 = -3(x + 7), and in slope-intercept form is y = -3x - 26.
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If we invest $100,000 today in an account earning 7% per year,
how many years until we have $500,000? Round to two decimals.
Answers
It would take approximately 19.65 years for an investment of $100,000 at a 7% annual interest rate to grow to $500,000. Rounded to two decimal places, the answer is 19.65 years.
To determine the number of years it will take for an investment of $100,000 at a 7% annual interest rate to grow to $500,000, we can use the compound interest formula:
A = P(1 + r/n)^(nt)
Where:
A = the future value of the investment ($500,000)
P = the initial principal amount ($100,000)
r = the annual interest rate (7% or 0.07)
n = the number of times that interest is compounded per year (assuming annually, so n = 1)
t = the number of years
Plugging in the values we know, we get:
$500,000 = $100,000(1 + 0.07/1)^(1*t)
Dividing both sides of the equation by $100,000 and simplifying:
5 = (1.07)^t
To solve for t, we can take the logarithm of both sides:
log(5) = log[(1.07)^t]
Using logarithmic properties, we can bring down the exponent:
log(5) = t * log(1.07)
Finally, we can solve for t by dividing both sides by log(1.07):
t = log(5) / log(1.07)
Using a calculator, we find:
t ≈ 19.65
Therefore, it would take approximately 19.65 years for an investment of $100,000 at a 7% annual interest rate to grow to $500,000. Rounded to two decimal places, the answer is 19.65 years.
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Vern has just opened a flower shop. Because of the startup costs, for the next month his net earnings for each bouquet are -$6. On Tuesday during that month, he sold 14 bouquets. What are Verns net earnings for Tuesday?
-$8
-$84
$84
$20
Answers
Answer:
-$84
Step-by-step explanation:
$-6 x $14 = -$84
Tara, Inc. is authorized to issue 5,000,000 shares of $20 par common stock. 500,000 shares of stock were originally sold for $50 per share. The stock is currently selling for $40 per share and Tara has decided to repurchase 12,000 shares of stock. When Tara, Inc. repurchases their own stock, how much gain or loss will the company recognize on its income statement?
A. $120,000 gain B. $120,000 loss C. $360,000 gain D. $-0-
Answers
The closest option is D. $-0
To determine the gain or loss on the repurchase of stock, we need to compare the repurchase price with the original sale price.
Original sale price: 500,000 shares * $50 per share = $25,000,000
Repurchase price: 12,000 shares * $40 per share = $480,000
To calculate the gain or loss, we subtract the repurchase price from the original sale price:
Gain or Loss = Original Sale Price - Repurchase Price
= $25,000,000 - $480,000
= $24,520,000
Since the result is a positive value, it represents a gain. Therefore, the company will recognize a gain of $24,520,000 on its income statement.
The given options do not include this exact amount, so the closest option is D. $-0-. However, it is important to note that the gain is not zero but rather $24,520,000.
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cmon pls help i am trying to pass
Answers
Answer: 1/10
Step by step explanation:
3x-10=8 i need help with this
Answers
Answer:
x=6
Step-by-step explanation:
3x=18
x=6
Answer:
x=6
Step-by-step explanation:
2 step equations
SIMPLIFY
STEP BY STEP EXPLANATION
WILL MARK BRAINLIEST!!!!!!!!!!!!!
Answers
Answer:
3x+7
3
Step-by-step explanation:
(3x-7) × (3x+7) × ____2x+4_____
6 3x∧2-x-14
(3x-7) × (3x+7) × ____2(x+2)_____
6 3x∧2 × 6x-7x-14
(3x-7) × (3x+7) × _____x+2_______
3 3x × (x+2)-7(x+2)
(3x-7) × (3x+7) × _____ x+2_______
3 (x+2) × (3x-7)
3x+7
3
Hope this helps! :)
find the following marked angles in the picture
Answers
please write clear handwriting
Answer:
I hope the above image will be helpful
anyone know the answer?
Answers
Answer:
26.97
find side km using cos,after you find km you can then use tan to find the angle
hope this helps
Please provide an explanation for this problem, thank you!Car A (traveling north at 70 mph) and car B (traveling west at 50 mph) are heading toward the same intersection. Car A is 5 miles from the intersection while car B is 6 miles from the intersection. Find parametric equations that describe the motion of cars A and B.A) Car A: x = 0, y = 70t-5; Car B: x = 6 - 50 t, y = 0B) Car A: x = 0, y = 50t - 6; Car B: x = 70t - 5, y = 0C) Car A: x = -70t + 5, y = 0; Car B: x = 6 - 50t, y = 0D) Car A: x = 50t - 6, y = 0; Car B: x = 0, y = 50 - 70t
Answers
The correct parametric equations for the motion of Car A and Car B are: Car A: x = 70t, y = 5 + 70t; Car B: x = 6 - 50t, y = 50t. Option C is correct.
Car A is traveling north at a speed of 70 mph. Therefore, its velocity vector can be represented as <0, 70>.
Car B is traveling west at a speed of 50 mph. Therefore, its velocity vector can be represented as <-50, 0>.
Let's assume that at time t = 0, Car A is at position (0, -5) and Car B is at position (6, 0).
Then, the position vectors for Car A and Car B at any time t can be given as:
Position of Car A = <0, -5> + t<0, 70> = <0, 70t-5>
Position of Car B = <6, 0> + t<-50, 0> = <6-50t, 0>
Therefore, the parametric equations for the motion of Car A and Car B are:
Car A: x = 0, y = 70t-5
Car B: x = 6 - 50t, y = 0
So, option C is the correct answer.
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What is the expanded form of this number? (In fractions)
570.086
Answers
Answer:
570 86/1000
Step-by-step explanation:
decimal goes into thousandths place
570 is a whole number
simplified is 570 43/500
(5×100)+(7×10)+(8×.010)+(6×.001)
a hairdresser is making 6 hair bows. she needs 5 over 8 yards for each bow. if she has 8 and 1 over 2 yards of ribbon, how much will be left over after making the bows?
Answers
Total yards of ribbon left over making the bows is 4.75
According to the question, a hairdresser has 8 and 1 over 2 yards (8.5 yards) of ribbon.
She needs 5 over 8 yards \((\frac{5}{8} yards)\) for each bow.
If she is making 6 hair bows. total yards of ribbon required = \(6\) × \(\frac{5}{8}\)
= 3 × (5/4)
= 3.75
She required 3.75 yards of ribbon for making 6 hair bows.
Total yards of ribbon = Used yards of ribbon + left out yards of ribbon
8.5 = 3.75 + Total yards of ribbon left
⇒ Total yards of ribbon left = 8.5 - 3.75
⇒ Total yards of ribbon left = 4.75 yards of ribbon
She is left with 4.75 yards of ribbon.
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5 − (x + 5) > −2(x + 4)
1) x > −8
2) x −18
4) x < −18
Answers
Answer:
1) x>-8
Step-by-step explanation:
love your pfp and user btw :>>
at a certain university, 23% of students will graduate with a math degree, 31% will graduate with a computer science degree and 7% will graduate with a degree in both math and computer science what is the probability that a student will graduate with a math or a computer science segree? A) 7% B) 47% C) 54% D) 61%
Answers
Work Shown:
A = event that the person has math degree
B = event that the person has a computer science degree
P(A) = 0.23, since 23% of the people have a math degree
P(B) = 0.31, similar reasoning as above, just different number
P(A and B) = 0.07
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.23 + 0.31 - 0.07
P(A or B) = 0.47
The decimal value 0.47 then converts to 47% after moving the decimal 2 spots to the right.
There's a 47% chance that we pick someone who has a math degree or a computer science degree (or both).
It might help to set up a venn diagram to see why that formula above works.