PLEASE HELP!! ;) <3 how many degrees of a circle graph would represent carbon monoxide (CO) how many degrees would represent methane (CH4)

thanks

Statement that is true about chemical reaction that forms acid rain : b)The bonds that break are between N and O in HNO2and between O and H in HNO3.

Acid rain is a acid deposition, which refers to the many ways in which acidity can move from atmosphere to Earth's surface. Acid deposition includes acidic rain as well as other forms of acidic wet deposition such as snow, sleet, hail, and fog.

HNO2 is less stable thus dissociates easily to HNO3 + NO + H2O and HNO3 is a strong acid. Therefore, when they react with H2O, they form acid rain.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Which two statements are true about this chemical reaction that forms acid rain? 2NO2 + H2O--> HNO2 +HNO3

a) The bonds that form are between N and O in HNO2 between and between O and H in HNO3.

b)The bonds that break are between N and O in HNO2and between O and H in HNO3.

c)The bonds that break are between N and O in NO2 and between O and H in H2O.

d)The bonds that form are between N and O in NO2 and between O and H in H2O.

Answer:  The correct two answers are  :  

1.)  The BONDS that FORM are between N and O in HNO  2   and between O and H in HNO 3

2.)  The BONDS that BREAK are between N and O in NO2 and between H and O in H2O

Explanation:   I took the test.

Answer:

The correct option is;

D. The kinetic energy decreases by 3·m₀·v₀²

Explanation:

The given parameters are;

The mass of object X = m₀

The initial velocity of object X = v₀

The mass of object Y = 2·m₀

The initial velocity of object Y = -2·v₀

By conservation of linear momentum, we have;

The total initial momentum = The total final momentum

Therefore, we have;

The total initial momentum = m₀·v₀ - 2·m₀·2·v₀ = The total final momentum

∴ The total final momentum = -3·m₀·v₀

The total mass of the two object after sticking together = 2·m₀ + m₀ = 3·m₀

Therefore, the velocity of the two objects after collision = (The total final momentum)/(Total mass) = -3·m₀·v₀/(3·m₀) = -v₀

The kinetic energy = 1/2 × Mass × (Velocity)²

Therefore, the kinetic energy after collision = 1/2 × (3·m₀) × v₀² = 3·m₀·v₀²/2

The kinetic energy before collision = 1/2 × m₀ × v₀² + 1/2 × (2·m₀) × (2·v₀)² = (1/2 + 4) × (m₀·v₀²)

∴ The kinetic energy before collision =  9·(m₀·v₀²)/2

The change in kinetic energy = The kinetic energy after collision - The kinetic energy before collision = 3·m₀·v₀²/2 - 9·(m₀·v₀²)/2 = -3·m₀·v₀²

Therefore, the kinetic energy decreases by 3·m₀·v₀².

By using the orbital period equation we will find that the orbital radius is r = 4.29*10^11 m

This would be the time that a given body does a complete revolution in its orbit.

It can be written as:

\(T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\)

Where:

Rewriting the equation for the radius we get:

\(T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\\\\r = \sqrt[3]{ \frac{T^2*G*M}{4*\pi ^2} }\)

Where T = 7.5 years = 7.5*(3.154*10^7 s) = 2.3655*10^8 s

Replacing the values in the equation we get:

\(r = \sqrt[3]{ \frac{(2.3655*10^8 s)^2*(6.67*10^{-11} m^3/(kg*s^2))*(1.989*10^{30} kg)}{4*3.14 ^2} } = 4.29*10^{11 }m\)

So the orbital radius is 4.29*10^11 m

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By analyzing the velocity-time graph, we can determine the maximum speed at the end of the constant speed phase and the disability during the deceleration phase.

To sketch the velocity-time graph and determine the maximum speed and disability, let's break down the motion into three phases:

Phase 1: Acceleration

The object starts from rest and undergoes acceleration for 40 seconds at a constant speed. During this phase, the velocity increases linearly with time. The slope of the velocity-time graph will be a straight line with a positive gradient.

Phase 2: Constant Speed

After 40 seconds, the object continues to move at a constant speed for the next 100 seconds. During this phase, the velocity remains constant, resulting in a horizontal line on the velocity-time graph.

Phase 3: disability

After 140 seconds, the object is brought to rest with uniform disability over a duration of 20 seconds. The velocity decreases linearly with time during this phase. The slope of the velocity-time graph will be a straight line with a negative gradient.

To determine the maximum speed, we need to find the highest point on the velocity-time graph. In this case, it occurs at the end of phase 2 when the object is moving at a constant speed. The maximum speed is reached at this point.

To determine the disability, we need to find the slope of the line during phase 3. The negative gradient of the velocity-time graph during the deceleration phase represents the magnitude of the uniform disability.

Therefore, by analyzing the velocity-time graph, we can determine the maximum speed at the end of phase 2 and the disability during phase 3.

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Answer:the power source

Explanation:

Answer:

A. The power source

Explanation:

Just took the quiz

By using the blackbody radiation formula, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

To tackle this issue, we need to understand black body radiation. A black body object's energy emission is inversely proportional to its area and the temperature to the fourth power. It may be established that

P = A . e . σ . T⁴

where P (power), A (surface area), e (emissivity), ( 5.67 x 10¯⁸ W/m²K⁴), and T (temperature) are all variables.

From the question above, we know that

P1 = 10 watt

P2 = 100 watt

T1 = T1

By using the black body radiation formula, the ratio of temperature is

T1⁴ / T2⁴ = P1 / P2

Hence,

T1⁴ / T2⁴ = P1 / P2

T1⁴ / T2⁴ = 10 / 100

T1⁴ / T2⁴ = 1 / 10

T2⁴ = 10T1⁴

T2 = ⁴√(10T1⁴)

T2 = T1 x 10⁰'²⁵

Thus, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

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Answer:

Gravity

Explanation:

The answer is gravity because when the 3 masses were hung from the spring, gravity pulled the spring towards the ground.

1. The maximum height the object will attain is 8.6 m

2. The time spent by the object in the air is 2.65 s

3. The distance (i.e range) the object will land is 19.88 m

1. How to determine the maximum height

The maximum height reached by the eobject can be obtained as follow:

H = u²Sine²θ / 2g

H = [(15)² × (Sine 60)²] / (2 × 9.8)

H = 168.75 / 19.6

H = 8.6 m

2. How to determine the time of flight

The time spent by the object in the air can be obtained as follow:

T = 2uSineθ / g

T = [2 × 15 × Sine 60] / 9.8

T = 2.65 s

3. How to determin the distance (i.e range)

R = u²Sine(2θ) / g

R = (15)² × Sine (2×60) / 9.8

R = 19.88 m

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For a distance of 5.0 meters, an object moving at an initial speed of 4.0 meters per second accelerates uniformly at 2.0 meters per second2. What is the object's final speed? Vi=4m/s

The object's final speed after uniformly accelerating in the direction of its motion is 6 m/s.

We apply the third equation of motion to calculate the object's final speed. Where u is the starting velocity, an is the acceleration, and s is the distance traveled, v is the end speed or velocity, a.

20 m/s is the final velocity.

Initial speed is equal to 16 m/s.

Equation 1 can be solved for by substituting these numbers above.

20² = 16²+2×a×36\s36a = 400-256

36a = 144\sa = 144/36\sa = 4

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The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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The advantage of an interferometer is that it dramatically increases the resolution and light gathering power, making it the correct option (a). Additionally, it does not directly affect the focal length or address chromatic aberration, as mentioned in options (b) and (d), respectively.

An interferometer is an optical instrument that combines two or more light waves to create an interference pattern. This pattern contains information about the relative phases of the waves, which can be used to enhance the resolution of the instrument. By combining the waves, an interferometer effectively increases the effective aperture size, leading to higher resolution. This increase in resolution is particularly useful in fields such as astronomy and microscopy, where fine details need to be observed.

While an interferometer can improve resolution, it does not directly affect the focal length of an optical system. The focal length determines the convergence of light rays and is determined by the curvature of the lenses or mirrors used. Similarly, an interferometer does not specifically address chromatic aberration, which is an optical defect that causes different wavelengths of light to focus at different points. Chromatic aberration is typically mitigated through the use of corrective lenses or lens coatings designed to minimize this effect.

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The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Answer: \(-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}\)

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

\(2Br^.\rightarrow Br_2\)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

\(Rate=-\frac{d[Br^.]}{2dt}\)

or \(Rate=+\frac{d[Br_2]}{dt}\)

Thus \(-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}\)

Answer:

Las coordenadas del punto son \((x,y) = (6.582\,m, 3.8\,m)\).

Explanation:

La relación entre un vector en formato polar y uno con formato rectangular con respecto al mismo origen queda sintetizado por la siguiente expresión:

\((x, y) = r\cdot (\cos \theta, \sin \theta)\) (1)

Donde:

\(r\) - Magnitud de la distancia del punto con respecto al origen, medido en metros.

\(\theta\) - Dirección del punto con respecto del semieje +x, medido en grados sexagesimales.

\(x,y\) - Coordenadas rectangulares del punto con respecto al origen, medidas en metros.

Si sabemos que \(r = 7.6\,m\) y \(\theta = 30^{\circ}\), entonces las coordenadas rectangulares del punto con respecto al origen son:

\((x,y) = (7.6\,m)\cdot (\cos 30^{\circ}, \sin 30^{\circ})\)

\((x,y) = (6.582\,m, 3.8\,m)\)

Las coordenadas del punto son \((x,y) = (6.582\,m, 3.8\,m)\).

Answer:

0.10 g/cm3

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Answer:

\(e \: = \: \frac{kq}{{r}^{2} } \)

then q = e r² / k

then q = 100 * (50 ×10^-2)² / 9×10^9 = 2.777777778×10^-9 C

\(2.8\times 10^{-9}C\) is value of q

An electric property associated with each point in space when charge is present in any form.

The magnitude and direction of the electric field are expressed by the value of E, called electric field strength .

By definition,

The electric field of a point charge is given as follows:

\(E = k\dfrac{q}{r^2}\)

​Where q is the charge,

r = 50cm = 0.5mr=50cm=0.5m is the distance from the charge,

k =\(9\times 10^9N\cdot m^2/C^2\)

C is the Coulomb's constant.

Substituting E = 100N/C and expressing q,

obtain:

\(q = \dfrac{Er^2}{k} = \dfrac{100\cdot 0.5^2}{9\times 10^9} \approx 2.8\times 10^{-9}C\)

Therefore,

\(2.8\times 10^{-9}C\) is the value of q.

The complete question is given below:

If the electric field is 100N/C at a distance of 50 cm from a point charge , what is the value of q?

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The element that has 1 valence electron in its outer shell and will react with a group 17 element (also known as a halogen) in a 1:1 ratio is Potassium (K).

The correct answer is option B.

Potassium belongs to Group 1 of the periodic table, also known as the alkali metals. The alkali metals have one valence electron in their outermost shell, making them highly reactive. In the case of Potassium, it has an electron configuration of 2-8-8-1, with the valence electron being in the outermost shell.

Group 17 elements, on the other hand, are known as halogens and have seven valence electrons. They are highly reactive and tend to gain one electron to achieve a stable electron configuration of a noble gas. When reacting with alkali metals, halogens achieve a stable configuration by accepting the alkali metal's single valence electron, forming an ionic compound.

In the case of Potassium, it will react with a group 17 element in a 1:1 ratio. For example, it can react with Chlorine (Cl) to form Potassium Chloride (KCl). Potassium will lose its single valence electron to chlorine, which will gain the electron to form a stable chloride ion.

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Answer:

33 hours

Explanation:

7.5 + 6.5 = 13 + 1

14 + 10 = 24

9= 6+3

24 + 6 = 30

30+3= hours

The vertical velocity of the projectile increases but reaches zero at the maximum height and begins to decrease.

When we talk of the projectile, we are talking about the object that is moving along a parabolic path. Hence the object that is undergoing the projectile motion is going to have a curved path. Take an instance, when you kick a soccer ball, you have to notice that the ball would tend to curve as it moves up in the air and then begins to descend. That is a typical example of a projectile motion.

Now, we have to note that at the maximum height, the vertical velocity of the object would be zero. When I throw an object up, the vertical velocity of the object would continue to increase until the object reaches the maximum height where the vertical velocity is zero and then the vertical velocity of the object begins to decrease as shown in the image.

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Answer:

Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.

Answer:

What we see in the sky

Where are they in the general context of the overview of the Universe?

With the naked eye, the main astronomical objects we can see are the Sun, the Moon, the stars, and some of the planets

All of the stars we see are in the Milky Way galaxy, most of them relatively close to the Sun.

The stars we see in the sky come in a range of brightnesses, partly because stars come in different intrinsic brightnesses, and partly because some are closer than others.

When we look at an astronomical object ``by eye'', we can't tell just by looking how far away it is (because not all objects have the same intrinsic brightness). All we can see is what direction it is in.

As a result, when looking ``by eye'', the positions of stars on the sky are described by their direction only; you can imagine that the sky is a big sphere with astronomical objects located at different positions on it. This is called the celestial sphere

The positions of the stars can be described with a sort of astronomical longitude and latitude, called right ascension and declination.

Constellations are patterns of stars seen in the sky. However, although the stars in any constellation are all in the same general direction in the sky, the different stars in a constellation may be at very different distances from Earth, hence constellations may not be real associations of stars in space, just stars in the same general direction as seen from Earth.

Only the nearest galaxies are visible to the naked eye, as relatively faint smudges of light, although two of the very nearest galaxies, the Magellanic Clouds, are visible are moderately large clouds from the Southern hemisphere.

Motions in the sky

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Answer:

Approximately \(9.3\; {\rm m\cdot s^{-1}}\).

Explanation:

Apply unit conversion:

\(t = 45\; {\rm ms} = 45 \times 10^{-3}\; {\rm s}\).

At a velocity of \(v\), the momentum \(p\) of an object of mass \(m\) would be \(p = m\, v\).

Initial momentum of this ball:

\(\begin{aligned}p_{0} &= m\, v_{0} \\ &= 0.060\; {\rm kg} \times (-32\; {\rm m\cdot s^{-1}}) \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}\).

When a constant force \(F\) is exerted on an object for a duration of length \(t\), the impulse \(J\) applied to that object would be \(J = F\, t\).

Impulse that the ground applied to this ball:

\(\begin{aligned}J &= F\, t \\ &= 55\; {\rm N} \times (45 \times 10^{-3}\; {\rm s}) \\ &= 2.475\; {\rm N \cdot s}\end{aligned}\).

Note that \(1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}}\). Thus, the impulse applied to this ball would be equivalent to:

\(\begin{aligned}J &= 2.475\; {\rm (kg \cdot m \cdot s^{-2}) \cdot s} \\ &= 2.475\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

After this impulse was applied, the momentum of this ball would become:

\(\begin{aligned}p_{1} &= p_{0} + J \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}}) + 2.475\; {\rm kg \cdot m \cdot s^{-1}} \\ &= 0.555\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

The new velocity of this ball would be:

\(\begin{aligned}v_{1} &= \frac{p_{1}}{m} \\ &= \frac{0.555\; {\rm kg \cdot m \cdot s^{-1}}}{0.060\; {\rm kg}} \\ &\approx 9.3\; {\rm m\cdot s^{-1}}\end{aligned}\).

Answer:

(A)

Explanation:

I took the test

We need to use the formula for work done, which is :

W = F x D

P = W / T

In this case, the force (F) is equal to the weight of the mass, which is :

F = m x g

where m is the mass (100kg) and g is the acceleration due to gravity (9.81 m/s²).

F = 100kg x 9.81 m/s² = 981 N

The power (P) of the engine is 400 W, and the time (T) is 3 seconds.

P = W / T, therefore W = P x T = 400 W x 3 s = 1200 J

Now we can use the work formula to find the distance (D) that the engine can lift the mass :

D = W / F = 1200 J / 981 N = 1.22 m

Therefore, the 400W engine can lift a 100kg mass to a height of 1.22 meters in 3 seconds.

It would take her approximately 12.15 minutes to reach the cliff. To estimate the time required, the girl scout can use the speed of sound to calculate the distance between her and the cliff.

Since the echo returns after 2.3 seconds, the total time for the sound to travel to the cliff and back is 2.3 x 2 = 4.6 seconds.

Using the formula distance = speed x time, the distance between the girl scout and the cliff is 343 m/s x 4.6 s = 1577.8 meters or 1.5778 km.

If the girl scout can hike 1.00 km in 7.7 minutes, then to hike 1.5778 km, it would take her 7.7 x 1.5778 = 12.15 minutes. Therefore, it would take her approximately 12.15 minutes to reach the cliff.

In summary, the girl scout can estimate the time required to walk to the cliff by using the speed of sound to calculate the distance between her and the cliff, and then calculating the time it would take her to hike that distance based on her known hiking speed.

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If the distance between the spheres is reduced, the magnitude of the attractive force between them will increase according to the inverse square law.

The magnitude of the new attractive force between two conducting spheres that are separated by a distance d can be determined by using Coulomb's law. Coulomb's law states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. However, for conducting spheres, the charges are distributed uniformly on their surfaces.

Assuming that the spheres have charges of q₁ and q₂, the magnitude of the attractive force between them can be given by the following equation:

F = (1/4πε) (q₁ q₂ / d²)

Where ε is the permittivity of the medium between the spheres.

Therefore, if the distance between the spheres is reduced, the magnitude of the attractive force between them will increase according to the inverse square law. On the other hand, if the distance between the spheres is increased, the magnitude of the attractive force will decrease.

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Answer: Wave frequency can be measured by counting the number of crests (high points) of waves that pass the fixed point in 1 second or some other time period. The higher the number is, the greater the frequency of the waves. The SI unit for wave frequency is the hertz ( Hz ), where 1 hertz equals 1 wave passing a fixed point in 1 second.

Explanation:

To have the right foods for any health problem such as a food allergy, check the food package or label to know the right serving.

A food label is any piece of information contained in a food package that tells you how many calories and how much fat, protein, carbohydrates, and other nutrients are in one food serving.

Many packaged foods contain more than a single serving.

Thus, when you plan a meal you should try to have the right foods for any health problem such as a food allergy. For example the food package or label to know the right serving.

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A current i flows around a continuous path that consists of portions of two concentric circles of radii a and a/2, respectively. The point p is at the common center of the two circle segments, and the total field at p is μ₀i/2πa.

The expression for the magnetic field due to a current-carrying conductor is given by the Biot-Savart Law.

The Biot-Savart law is given by the formula:

B = (μ₀i/4π) × ∫dl × r/|r|³

where,

μ₀ is the magnetic constant or the permeability of free space,

i is the current,

dl is the length element along the conductor,

r is the position vector from the length element to the field point,

|r| is the distance between the length element and the field point

μ₀ is given as 4π × 10^-7 Tm/A

Since the two circular parts of the path have current flowing in opposite directions, the magnetic field at p due to these two segments will cancel each other out.

Thus, the net magnetic field at p is due to the two straight radial segments only.

Along the two straight radial segments, the magnetic field is perpendicular to the length element dl, and thus, the scalar product dl × r is the same as |dl||r|.

Since the two radial segments are of equal length and equidistant from p, the magnetic field contribution due to these two segments will be equal and opposite. Therefore, we only need to consider one of these segments.

Let's consider the inner segment (segment 2).

At point p, the direction of the magnetic field due to segment 2 is perpendicular to the page and is directed into the page. The direction of the field due to the outer segment is out of the page. Thus, we will choose the direction of the field due to the inner segment as negative and that due to the outer segment as positive.

Let's first calculate the magnetic field due to segment 2.

The length of this segment is a/2 and the position vector r at point p is also a/2 since p is at the center of the circle.

Thus, the magnetic field due to segment 2 is given by:

B2 = (μ₀i/4π) × ∫dl × r/|r|³

= (μ₀i/4π) × ∫a/2 × (1,0,0) × (a/2,0,0)/[(a/2)²]³

= (μ₀i/4π) × [(a/2)²/(a/2)³] × ∫a/2 × (1,0,0) dl

= μ₀i/4πa

Since the two radial segments contribute equal and opposite magnetic field, the total magnetic field at p is given by:

B = B1 - B2

where,

B1 is the magnetic field due to the outer segment

The length of this segment is a and the position vector r at point p is also a.

Thus, the magnetic field due to segment 1 is given by:

B1 = (μ₀i/4π) × ∫dl × r/|r|³

= (μ₀i/4π) × ∫a × (-1,0,0) × (a,0,0)/(a³)

= - μ₀i/4πa

Thus, the net magnetic field at p is given by:

B = B1 - B2

= - μ₀i/4πa - μ₀i/4πa

= -μ₀i/2πa

Therefore, the total field at p is -μ₀i/2πa.

Taking the modulus, the total field is |B| = μ₀i/2πa.

Therefore, the total field at p is μ₀i/2πa.

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Answer:

(i) How deep is the well (Height)

=> t = √(2H/g)

=> √2H = t × g

=> 2H = t² × g²

=> 2H = (2.60)² × (10)²

=> 2H = 6.76 × 100

=> 2H = 676

=> H = 676 ÷ 2

=> H = 338 m

(ii) speed of the stone:

=> v = √(2Hg)

=> v = √(2 × 338 × 10)

=> v = √6760

=> v = 26√10 m/s