PLEASE HELP ME ANSWER ASAP

A student with a z-score of 1.80 on a test with a mean score of 90 and a standard deviation of 15 would have a score of approximately 118.5 on the test.

1. A z-score measures how many standard deviations a particular value is away from the mean. In this case, the z-score of 1.80 indicates that the student's score is 1.80 standard deviations above the mean. To find the actual score on the test, we can use the formula:

z = (x - mean) / standard deviation

Rearranging the formula to solve for x (the score), we have:

x = (z * standard deviation) + mean

Substituting the given values into the formula, we get:

x = (1.80 * 15) + 90 = 118.5

Therefore, the student's score on the test would be approximately 118.5.

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I may or may not be lying >:^P

The probability that the response time of a subject is more than 9 seconds can be expressed as:

P(X > 9) = 1 - P(X ≤ 9)

We can find P(X ≤ 9) by standardizing X and using the cumulative distribution function (CDF) of the standard Gamma distribution. Specifically, we can compute:

Z = (X - μ) / σ = (9 - 12) / 6 = -0.5

Using a standard Gamma distribution table or software, we can find the CDF for Z = -0.5 to be approximately 0.3085.

Therefore:

P(X > 9) = 1 - P(X ≤ 9) ≈ 1 - 0.3085 ≈ 0.6915

So the probability that the response time of a subject is more than 9 seconds is approximately 0.6915 or 69.15%.

*IG:whis.sama_ent*

I may or may not be lying >:^P

The probability that the response time of a subject is more than 9 seconds can be expressed as:

P(X > 9) = 1 - P(X ≤ 9)

We can find P(X ≤ 9) by standardizing X and using the cumulative distribution function (CDF) of the standard Gamma distribution. Specifically, we can compute:

Z = (X - μ) / σ = (9 - 12) / 6 = -0.5

Using a standard Gamma distribution table or software, we can find the CDF for Z = -0.5 to be approximately 0.3085.

Therefore:

P(X > 9) = 1 - P(X ≤ 9) ≈ 1 - 0.3085 ≈ 0.6915

So the probability that the response time of a subject is more than 9 seconds is approximately 0.6915 or 69.15%.

*IG:whis.sama_ent*

The mean hourly snowfall is 10/3 cm/hour or 3.33 cm/hr.

What do you mean by snowfall?

Snowfall is the term for precipitation that takes the shape of snow-like solid particulates. Snowfall happens at mean sea level in high-latitude, temperate locations while it happens higher than the snowline height in equatorial areas.

Given,

At 4 P.M the total snowfall is 3 centimetres.

AT 7 P.M, the total snowfall is 13 centimetres.

Duration of time = (7-4) = 3 hours

Snowfall changes= (13-3)= 10 centimeters

We know that,

Mean hourly snowfall= Snowfall changes/ duration of time

= 10/3 cm/hour

≅3.33 cm/hr

The mean hourly snowfall is 10/3 cm/hour or 3.33 cm/hr

Hence the correct answer is 10/3 cm/hour or 3.33 cm/hr

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Answer:

y = -8x - 8

Step-by-step explanation:

Add -8x on both sides to get -y = 8x + 8 and flip the y sign on the left to get your slope function which is y = - 8x - 8.

To graph the function, you would need to put (0, -8) as your y-intercept, and each unit will go down 8 units when you add 1.

Answer:

y=8x+8

Step-by-step explanation:

Just rewrite the problem so it's in y=mx+b format then it's easy to graph

Remember the y intercept is 8 because when x=0  y=8 and the slope is 8 so go up 8 and right 1

The digit that occurs the least frequently in the numbers between 1 and 1,000 is 9, which appears only 271 times.

To answer this question, we need to analyze the numbers between 1 and 1,000 and determine which digit occurs the least frequently. We can start by looking at each individual digit (0-9) and counting how many times it appears in each of the numbers in this range.
For example, the digit 0 appears 192 times in this range, while the digit 1 appears 301 times. We can continue this process for all of the digits and find that the digit that occurs the least frequently is 9, which appears only 271 times.
We can also note that this is not surprising since 9 is the largest single-digit number, and thus, it is less likely to appear in numbers between 1 and 1,000. Additionally, we can observe that the digits 0-8 all appear relatively evenly throughout this range, with each digit appearing between 271-305 times.
In conclusion, the digit that occurs the least frequently in the numbers between 1 and 1,000 is 9, which appears only 271 times.

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Answer:

93.75 boxes

25/2 = 12.5 per hour

12.5*7.5 = 93.75

To determine whether there is enough evidence to reject the null hypothesis, we need to compare the computed test statistic to the critical value.

In this case, the computed test statistic is 2.50 and the critical value is 2.33. If the computed test statistic falls in the rejection region beyond the critical value, we can reject the null hypothesis. Conversely, if the computed test statistic falls within the non-rejection region, we fail to reject the null hypothesis.In this scenario, since the computed test statistic (2.50) is greater than the critical value (2.33), it falls in the rejection region. This means that the observed data is unlikely to occur if the null hypothesis were true.

Therefore, based on the given information, there is enough evidence for the emergency room nurse to reject the null hypothesis. This suggests that there is sufficient evidence to support the claim that the average number of cases of upper respiratory infections per day at the hospital is over 21 cases.

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There is enough evidence to reject the null hypothesis in this case because the computed test statistic (2.50) is higher than the critical value (2.33). This suggests the average number of daily respiratory infections exceeds 21, providing substantial evidence against the null hypothesis.

Yes, there is enough evidence for the emergency room nurse to reject the null hypothesis. The null hypothesis is typically a claim of no difference or no effect. In this case, the null hypothesis would be an average of 21 upper respiratory infections per day. The test statistic computed (2.50) exceeds the critical value (2.33). This suggests that the average daily cases indeed exceed 21, hence providing enough evidence to reject the null hypothesis.

It's crucial to understand that when the test statistic is larger than the critical value, we reject the null hypothesis because the observed sample is inconsistent with the null hypothesis. The statistical test indicated a significant difference, upheld by the test statistic value of 2.50. The significance level (alpha) of 0.05 is a commonly used threshold for significance in scientific studies. In this context, the finding suggests that the increase in respiratory infection cases is statistically significant, and the null hypothesis can be rejected.

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The functions g and h, have values for the inverse functions g⁻¹(9) = 1 and h⁻¹(-1) = -1. The composite function (h o h⁻¹)(-1) is equal to -1.

A function is said to have an inverse if it is both one-to-one and onto

for the function g using y = mx + c, when x = 1 and y = 9

m = 8/5 and c = 37/5

g(x) = (8/5)x + 37/5

g⁻¹(x) = (5x - 37)/8

g⁻¹(9) = [5(9) - 37]/8

g⁻¹(9) = (45 - 37)/8

g⁻¹(9) = 8/8

g⁻¹(9) = 1

for the function h(x) = -3x - 4, the inverse;

h⁻¹(x) = -(x + 4)/3

h⁻¹(-1) = -(-1 + 4)/3

h⁻¹(-1) = -3/3 = -1

(h o h⁻¹)(-1) = -[3(-1)] - 4

(h o h⁻¹)(-1) = -(-3) - 4

(h o h⁻¹)(-1) = 3 - 4

(h o h⁻¹)(-1) = -1.

Therefore, for the functions g and h, the values for the inverse functions g⁻¹(9) = 1 and h⁻¹(-1) = -1. The composite function (h o h⁻¹)(-1) is equal to -1.

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Answer:

\((3m + n) \div n - 1 \times n(n - 1) \div 5\)

\(3m + n \times n \div 5\)

\(3mn + n {}^{2} \div 5\)

final answer C

Answer:

Step-by-step explanation:

Answer:

4. 1/125

.______.

Answer:

35

Step-by-step explanation:yes

The numerical order of the used formula is almost second-order.

The numerical order of a formula refers to the rate at which the error in the approximation decreases as the step size decreases. A second-order formula has an error that decreases quadratically with the step size. In this case, we are given two approximations of \(f''(1)\) using different step sizes: 26.8943377 with \(h=0.1\) and 25.61341227 with \(h=0.05\).

To determine the numerical order, we can compare the error between these two approximations. The error can be estimated by taking the difference between the approximation and the exact value, which in this case is given as \(f''(1) = 24.46453646\).

For the approximation with \(h=0.1\), the error is \(26.8943377 - 24.46453646 = 2.42980124\), and for the approximation with \(h=0.05\), the error is \(25.61341227 - 24.46453646 = 1.14887581\).

Now, if we divide the error for the \(h=0.1\) approximation by the error for the \(h=0.05\) approximation, we get \(2.42980124/1.14887581 \approx 2.116\).

Since the ratio of the errors is close to 2, it suggests that the formula used to approximate \(f''(1)\) has a numerical order of almost second-order. Although it is not an exact match, the ratio being close to 2 indicates a pattern of quadratic convergence, which is a characteristic of second-order methods.

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(a) (65+5x)m², (b) 15+2+x+5+(15−x)+5+2=44m is the perimeter, (c) Rs.250(x+21) , (d) Rs.150(15−x) (e) 5x=35 ⇒x=7m

In an algebraic expression, variables are represented by letters or symbols, and constants are represented by numerical values. The variables can be used to represent unknown values that need to be solved for, while the constants provide fixed values.

Algebraic expressions are used extensively in algebra and other mathematical fields to represent relationships between variables and to solve equations.

(a)

length of bedroom =x m

Breadth of bedroom =5 m

And, length of kitchen =15−(x+2)=13−x m

Breadth of kitchen =5 m

So, Area of both kitchen and bedrooms =2× times of area of bedroom + area of kitchen

=2(5×x)+(13−x)×5

=10x+(65−5x)

=(65+5x)m²

(b)

From figure,

Perimeter of the living room

=15+2+x+5+(15−x)+5+2=44m

(c)

From figure,

Total area of both living the room and the bedrooms =(5×x)+(7×15)=(5x+105)m²

The cost of carpeting is Rs. 50/m²

Therefore, total cost of carpeting

=(5x+105)×50=Rs.250(x+21)

(d)

Total area, bathroom and kitchen

=(15−x)×5m²

The cost of tiling is Rs. 30/m²

Therefore, total cost of tilling

=(15−x)×5×30=Rs.150(15−x)

(e)

Given, Area of floor of each bedroom 35 m²

So, Area of one bedroom

=5xSq.m

∴5x=35

⇒x=7m

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B. No, because the Central Limit Theorem states that the sampling distribution of x is approximately normally distributed only if the sample size is large enough.

The Central Limit Theorem (CLT) is a fundamental concept in statistics that states that as the sample size increases, the sampling distribution of the sample means will approach a normal distribution. However, this is only true if certain conditions are met, one of which is having a large enough sample size.
The CLT states that the sampling distribution of x will be approximately normally distributed if the sample size is large enough (usually greater than 30). If the sample size is small, the sampling distribution may not be normally distributed. In such cases, other statistical techniques like the t-distribution should be used.
Furthermore, the CLT assumes that the population being sampled is not necessarily normally distributed, but it does require that the population has a finite variance. This means that even if the population is not normally distributed, the sampling distribution of x will still be approximately normal if the sample size is large enough.
In conclusion, the answer is B, as the Central Limit Theorem states that the sampling distribution of x is approximately normally distributed only if the sample size is large enough.

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Answer:

D is (-4, -4)

Step-by-step explanation:

M = (x1 + x2)/2

-3 = (-2 + x2)/2

-6 = -2 + x2

x2 = -4

M = (y1 + y2)/2

-7 = (-10 + y2)/2

-14 = -10 + y2

y = -4

Answer:

\(a_{n}\) = - 2 \((4)^{n-1}\)

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

r = - 8 ÷ - 2 = - 32 ÷ - 8 = - 128 ÷ - 32 = 4

This indicates the sequence is geometric with nth term

\(a_{n}\) = a₁ \((r)^{n-1}\)

where a₁ is the first term and r the common ratio

Here a₁ = - 2 and r = 4 , then explicit formula is

\(a_{n}\) = - 2 \((4)^{n-1}\)

Given, there are hotdogs and sodas as items. Each hotdog costs twice the cost of soda.

Let's assume the cost of soda is x dollars. Then, the cost of a hotdog would be 2x dollars. Then, h hotdogs cost 2xh dollars, and simultaneously, s sodas cost xs dollars.

Given, the vendor takes a total of d dollars, then

d = 2xh + xs

Therefore, if the price of a soda is x dollars, then

x = \(\frac{d}{2h + s}\) dollars

And also, since 1 dollar is 100 cents, therefore, 1 cent would be 0.01 dollars.

So finally, x, the price of a soda in cents would be

x = \(100(\frac{d}{2h+s})\) cents

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Answer:

- 6

Step-by-step explanation:

The rate of change of the values is the slope m

Calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 2, 32) and (x₂, y₂ ) = (0, 20) ← 2 ordered pairs from the table

m = \(\frac{20-32}{0+2}\) = \(\frac{-12}{2}\) = - 6 ← rate of change

Answer:

6

Step-by-step explanation:

Number of blueberries = 18

Number of strawberries = 3 times less than blueberries

Number of strawberries

Answer: 6 strawberries

Answer:

Daniel: y = 4x

Ryan: 3 boxes per hour

y = total number of boxes

--

h = hours

Ryan is able to pack 3 boxes in one hour. In multiple hours, the problem will be represented by the equation y = 3h.

--

So,

Ryan: y = 3h

Daniel: y = 4h

--

Based on our answers, we can conclude that when h increases, y also increases. Daniel's rate of packing boxes is higher than Ryan's, and therefore he has a greater rate of change, which means Daniel packs boxes faster in the same amount of time than Ryan.

Hope this helped :)

To find the equation of the line, we will use the formula below;

x₁=-6 y₁=6 x₂=4 y₂=6

substitute the values into the formula

y - 6 = 0

y = 6

The value of the linear correlation coefficient, r, as calculated using Microsoft excel is: 0.708,

The linear correlation coefficient, r, using Excel spreadsheet

Step1: Open Microsoft excel spreadsheet

Step2: Entre the cost of advertising on one column, and the number of products sold on another column.

Step3: Select a blank cell and input the formula: =CORREL(B3:B10, C3:C10)

Step4: Press "entre" to get the value of the linear correlation coefficient.

Therefore, the value of the linear correlation coefficient, r, as calculated using Microsoft excel is 0.708.

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The equations are H = 4x + 60 and P = 8x + 20. We need to rent 10 tables to ensure that the cost of the rental will be the same.

A system of equations in algebra consists of two or more equations and looks for common answers to the equations. "A set of equations satisfied by the same set of variables is called a system of linear equations."

Let us suppose tables as x.

Given that,

The happy party rents tables for $4 per table plus a delivery fee of 60. This is expressed as:

H = 4x + 60

Party Rental rents tables for $8 per table plus a $20 delivery fee.

P = 8x + 20

To get the same cost of the rent:

H = P

4x + 60 = 8x + 20

60 - 20 = 8x - 4x

40 = 4x

x = 10

Hence, we need to rent 10 tables to ensure that the cost of the rental will be the same.

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Answer: 40

Step-by-step explanation:

38+ 52=90

230-90=40

Answer:

8 1/3

Step-by-step explanation:

We want to find a number, x, that when divided by 10/3 equals 2.5.  We can write that as:

  x/(10/3) = 2.5

x = (2.5)*(10/3)    [MULTIPLY BOTH SIDES BY (10/3)

x = 25/3

x = 8 1/3             [

An inequality to describe the possible values for the total area, A, of the green section can be represented as A ≥ 0 square feet. This inequality indicates that the total area must be greater than or equal to zero.

The area of a section cannot be negative since it represents a physical space. Therefore, the total area, A, of the green section must be non-negative. By using the symbol "≥" (greater than or equal to), we indicate that the area can be equal to zero or any positive value greater than zero. The inequality A ≥ 0 ensures that the total area is within the acceptable range. If the area is zero, it means there is no green section present. Any positive value represents the actual area of the green section. This inequality allows for flexibility in the size of the green section, as long as it is non-zero and non-negative. The inequality A ≥ 0 describes the possible values for the total area, ensuring that it is greater than or equal to zero square feet.

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The value of N/10 is 372.

The characters can be chosen from the word "AIME" or the number "2007".

There are 7 different characters that can be picked, with 0 being the only number that can be repeated twice.

There are two possible cases.

The first case is given below :

If 0 appears 0 or 1 time in the sequence, the number of possible sequences is 7!/(7-5)!.

If 0 appears 0 or 1 time in the sequence, the number of possible sequences is 2520.

The second case is given below :

If 0 appears twice in the sequence, the number of places to fill 0 is 5C2.

If 0 appears twice in the sequence, the number of places to fill 0 is 10.

The number of ways to place the remaining three characters is 6!/(6-3)!.

The number of ways to place the remaining three characters is 120.

The total number of ways in the second case is 10*120 = 1200.

The total number of ways is 2520 + 1200.

The total number of ways is 3720.

N = 3720

We have to find the value of (N/10).

N/10 = 3720/10

N/10 = 372

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