PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

expanded:

y = sin(4x)*sin(4x)*cos(3x)

need to use the product rule and chain rule

look at individual derivatives, use chain rule

d/dx sin(4x) = 4cos(4x)

d/dx cos(3x) = -3sin(3x)

put it together using product rule

dy/dx = 4cos(4x)*sin(4x)*cos(3x) + 4cos(4x)*sin(4x)*cos(3x) - 3sin(3x)*sin(4x)*sin(4x)

simplify

dy/dx = 8cos(4x)*sin(4x)*cos(3x) - 3sin(3x)*sin2(4x)

answer is A.

Hope it helps friend request me and I'll accept xx:)

Suppose Sipho has x marbles. According to the given information, Mark has 3 times more marbles than Sipho, so Mark has 3 times more marbles.

If Mark gives Sipho 17 marbles, Mark will be left with (3x - 17) marbles. And this will be twice as many Sipho particles, i.e. x.

Therefore, we can write the equation:

3x - 17 = 2x

To solve x, we subtract 2x on both sides of the equation:

3x - 2x - 17 = 0

Simplify the equation:

x - 17 = 0

Added 17 to both sides:

x = 17

So Sipho has 17 marbles. Since Mark has 3 times as many marbles as Sipho, Mark has 3 * 17 = 51 marbles.

So Sipho has 17 marbles and Mark has 51 marbles. 

Answer:

b,c,d,e

Step-by-step explanation:

A=false

B=true

C=true

D=true

E=true

F=false

Answer:

Step-by-step explanation:

A. All rectangle are squares.

B. All rectangle are parallelogram

C. All rhombuses are parallelogram

D. All squares are rectangle

E. All squares are rhombuses

F. All trapezoid are parallelograms​

Answer:

35000

Step-by-step explanation:

multiple the the cards per shipment by the number of shipments

7000x 5

=35000

Answer: Ok I have two ways for this

1. If you mean how many will there be for each shipment: 1,400

If you mean how many will there be for 5 shipments since there is 7,000 each shipment then 35,000

Step-by-step explanation:

1. 7,000 ÷ 5

2. 7,000 x 5

Answer:

22.

     log3(4) + log3(5x^2 + 1) = 2

<=> log3(4 x (5x^2 + 1)) = log3(9)

<=> 20x^2 + 4 = 9

<=> 20x^2 = 5

<=> x^2 = 1/4

<=> x = +/- (1/2)

23.

      log8(4x^2 + 1) - log8(2) = log8(5)

<=> log8((4x^2 + 1)/2) = log8(5)

<=> 2x^2 + 1/2 = 5

<=> 2x^2 = 9/2

<=> x^2 = 9/4

<=> x = +- (3/2)

24.

      log8(4x^2 - 9) - log8(5) = 1

<=> log8((4x^2 - 9)/5) = log8(8)

<=> (4x^2 - 9)/5 = 8

<=> 4x^2 - 9 = 40

<=> 4x^2 = 49

<=> x^2 = 49/4

<=> x = +/- (7/2)

Hope this helps!

:)

Answer:

3 < 5

Step-by-step explanation:

3 < 5

We can write this inequality, because three is less than five, and < means less than.

An inequality is a mathematical sentence which

states that two expressions are not equal.

The "<" symbol means less than.

Since 3 is less than 5, we can write this as 3 < 5.

Take a look below I have attached the same problem

and an additional one to show you.

If the map shows that the school is 3 inches from home , that means the Harper home is 4.47 yards away from the school .

In the question,

it is given that

the 34 inches in map is equal to 50 yards in real .

So , 34 inches = 50 yards

1 inches = 50/34 yards

So, 1 inch = 1.47 yards

given that the the distance is 3 inches in map , then in real it will be

3 inch = 3*1.47 yards

= 4.47 yards

Therefore , If the map shows that the school is 3 inches from home , that means the Harper home is 4.47 yards away from the school .

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Answer:

90

Step-by-step explanation:

First of all you have to know that when 2 lines are perpendicular to each other,they produce a 90° angle, therefore DP||TD. Then you should remember that the measure of an arc is the same as the measure of the angle. So angle DB is 90°.

Arithmetic average return of the company is 2.57%.Geometric average return of the company is 13%.Variance of the company is 56.Standard deviation of the company is 7.48%.

Given, Returns of the company for the last few years are 5%, 10%, -15%, 20%, -12%, 22%, 8%
Arithmetic Average return:
Arithmetic Average return = (sum of all returns) / (total number of returns)
Arithmetic Average return = (5 + 10 - 15 + 20 - 12 + 22 + 8) / 7= 18 / 7= 2.57
Therefore, the arithmetic average return of the company is 2.57%.
Geometric average return:
Geometric average return = [(1+R1) * (1+R2) * (1+R3) * …….. * (1+Rn)]1/n - 1
Geometric average return = [(1.05) * (1.1) * (0.85) * (1.2) * (0.88) * (1.22) * (1.08)]1/7 - 1= 0.13
Therefore, the geometric average return of the company is 13%.
Variance:
Variance = (sum of (return - mean return)2) / (total number of returns)
Mean return = (5 + 10 - 15 + 20 - 12 + 22 + 8) / 7= 18 / 7= 2.57
Variance = [(5-2.57)2 + (10-2.57)2 + (-15-2.57)2 + (20-2.57)2 + (-12-2.57)2 + (22-2.57)2 + (8-2.57)2] / 7= 392.12 / 7= 56
Therefore, the variance of the company is 56.
Standard Deviation:
Standard Deviation = Square root of Variance
Standard Deviation = √56= 7.48
Therefore, the standard deviation of the company is 7.48%.

Thus, Arithmetic average return of the company is 2.57%.Geometric average return of the company is 13%.Variance of the company is 56.Standard deviation of the company is 7.48%.

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ANSWER:

STEP-BY-STEP EXPLANATION:

We have the following expression:

Answer:

C = -D - B

Step-by-step explanation:

Step 1: Write out equation

B + C = -D

Step 2: Subtract B on both sides

C = -D - B

If the data of the research subjects are presented in a frequency distribution graph, a histogram-type graph should be used.

If the data are presented in a frequency distribution graph, then the type of graph that should be used is a histogram. A histogram is a type of bar graph that displays the distribution of a continuous variable by dividing the range of values into intervals, and bins, and counting the number of observations that fall within each bin.

If the academic majors were nominal a bar graph could also be used to display the frequency of each major. In a bar graph, each category would be plotted on the horizontal axis, and the frequency of students in each category would be plotted on the vertical axis.

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Answer:

Step-by-step explanation:

p:q = ⅔:3 = 2:9 = 6:27

p:r = ¾:½ = 3:2 = 6:4

p:q:r = 6:27:4

We want to lower the sampling error one way to accomplish it is by decreasing the standard deviation or increasing the sample size.

By increasing the sample size, you can reduce the incidence of sampling errors. As the sample size increases, the sample approaches the actual population, and the likelihood of deviation from the actual population decreases. Note that the mean of 10 samples is much different than the mean of 100 samples. You can also take steps to ensure that your sample is a fair representation of the entire population.

Researchers can reduce their sampling errors by repeating studies. This can be achieved by performing the same measurements repeatedly or by performing multiple studies using multiple subjects or multiple groups.

Random sampling is an additional method to minimize the occurrence of sampling errors. Random sampling establishes a systematic approach to sample selection. For example, rather than randomly selecting participants to be interviewed, a researcher could select the person whose name appears first, tenth, twentieth, thirtieth, forty, etc. on a list.

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The given information is as follows:A random sample of 150 teachers in an​ inner-city school district found that​ 72% of them had volunteered time to a local charitable cause within the past 12 months.

The formula for calculating the standard error of sample proportion is given as:$$Standard\(\ error=\frac{\sqrt{pq}}{n}$$\)where:p = proportion of success in the sampleq = proportion of failure in the samplen = sample sizeGiven:Sample proportion, p = 72% or 0.72Sample size, n = 150

The proportion of failure in the sample can be calculated as:q = 1 - p= 1 - 0.72= 0.28Substituting the known values in the above formula, we get:\($$Standard \ error=\frac{\sqrt{pq}}{n}$$$$=\frac{\sqrt{0.72(0.28)}}{150}$$$$=0.0372$$\)Rounding off to the nearest thousandth, we get the standard error of sample proportion as 0.037

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Answer:

%50

%-15

%40

%62.5

%27.5

%60

Step-by-step explanation:

The probability of having zero errors is approximately 0.711.

The probability distribution that can be used to calculate the probability that zero errors will be found in a 255-word bond transaction is the Poisson distribution.

The Poisson distribution is a discrete probability distribution that is used to model the number of events occurring within a fixed interval of time or space, given the average rate of occurrence of the events.

In this case, the average rate of occurrence of errors is 6 per hour, which can be converted to 0.1 errors per minute. Therefore, the expected number of errors in a 255-word bond transaction is (255/75)*0.1 = 0.34 errors.

Using the Poisson distribution, the probability of having zero errors in a 255-word bond transaction can be calculated as:

\(P(X = 0) = (e^{(-\lambda)} * \lambda^0) / 0! = e^{(-0.34)} * 0.34^0 / 1! \approx 0.711\)

where λ is the expected number of errors in the 255-word bond transaction.

Therefore, the probability distribution used to calculate the probability of having zero errors in a 255-word bond transaction is the Poisson distribution, and the probability of having zero errors is approximately 0.711.

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Answer:

5\(\sqrt[\\]{3} \\\) or about 8.66

Step-by-step explanation:

To find the distance of any line, you have to use distance formula.

\(\sqrt{(y-y_{1} )^{2} + (x-x_{1} )^{2}\)

So, we insert our points:

\(\sqrt{(5-9 )^{2} + (-3-4 )^{2}\)

Then you solve, and should end up with \(\sqrt{75}\). Either you can simplify it for an exact number, or you can round. It depends on what the directions ask for.

The point of intersection for the two equations is: (4, 360).

The point of intersection is the point where the two equations becomes equal to each other.

To find the point of intersection for, y = 100 + 65x and y = 40 + 80x, set both equations equal to each other and solve for both x and y.

Thus:

100 + 65x = 40 + 80x

100 - 40 = 80x - 65x

60 = 15x

4 = x

Substitute x = 4 into the first equation

y = 100 + 65(4)

y = 360

Therefore, the point of intersection for the two equations is: (4, 360).

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False. if you are given a graph with two shif table lines, the correct answer will always require you to move both lines.

In a graph with two shiftable lines, the correct answer may or may not require moving both lines. It depends on the specific scenario and the desired outcome or conditions that need to be met.

When working with shiftable lines, shifting refers to changing the position of the lines on the graph by adjusting their slope or intercept. The purpose of shifting the lines is often to satisfy certain criteria or align them with specific points or patterns on the graph.

In some cases, achieving the desired outcome may only require shifting one of the lines. This can happen when one line already aligns with the desired points or pattern, and the other line can remain fixed. Moving both lines may not be necessary or could result in an undesired configuration.

However, there are also situations where both lines need to be shifted to achieve the desired result. This can occur when the relationship between the lines or the positioning of the lines relative to the graph requires adjustments to both lines.

Ultimately, the key is to carefully analyze the graph, understand the relationship between the lines, and identify the specific criteria or conditions that need to be met. This analysis will guide the decision of whether one or both lines should be shifted to obtain the correct answer.

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The probability that between 35% and 40% of an SRS of 400 high school seniors have vaped in the past year is 0.2643 + 0.2823 = 0.5466, or 54.66%.e) If the sample size were 900 rather than 400,

a) The mean of the sampling distribution of p is equal to the true proportion p, which is 0.37.

b) The standard deviation of the sampling distribution of p is given by:σp=√(pq/n)where p = 0.37, q = 1 - p = 0.63 and n = 400.σp = √(0.37 × 0.63/400) = 0.032 or 0.032 rounded to the nearest thousandth.

c) The curve of the sampling distribution of p is a normal distribution that is approximately symmetric with a mean of 0.37 and a standard deviation of 0.032.

d) The probability that between 35% and 40% of an SRS of 400 high school seniors have vaped in the past year can be found using the normal distribution.

We standardize the values as follows:

z1 = (0.35 - 0.37)/0.032 = -0.625z2 = (0.4 - 0.37)/0.032 = 0.781Using a standard normal distribution table or calculator,

we find the probabilities that z lies between -0.625 and 0.781 to be 0.2643 and 0.2823, respectively.

the curve of the sampling distribution of p would be narrower and more peaked since the standard deviation of the sampling distribution is inversely proportional to the square root of the sample size. The mean of the sampling distribution would remain the same at 0.37.

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Answer: x= 6

Step-by-step explanation:

Since the shape is a parallelogram, the angles will either be equal to each other or add up to 180.  

You can see they do not look the same so they add up to equal 180

12x + 3 +105 = 180

12x + 108 = 180

12x = 72

x = 6

The cube root of 126.2 is approximately 0.016 larger than the cube root of 125.

Linear approximation is a strategy for approximating the values of complicated functions. When a graph is relatively straight, this approximation is quite effective. A linear approximation for a function is a straight line that represents a close approximation of the original function.

The formula to be used is given by

df/dx = (f(x+dx)-f(x))/dx

The first derivative of the cube root of x can be computed as follows:

f(x) = x^(1/3)

df/dx = (1/3)*x^(-2/3)

Using this formula, we can calculate the linear approximation of the cube root of 126.2. This can be done as follows:

f(x + dx) ≈ f(x) + df/dx * dx

In the given case, the f(x) = ∛125 ⇒ 5

Let dx = 126.2 - 125 ⇒ 1.2

Then the linear approximation of the cube root of 126.2 is given by

f(126.2) ≈ f(125) + df/dx * dx

⇒ f(126.2) ≈ 5 + (1/3)*125^(-2/3) * 1.2

⇒ f(126.2) ≈ 5 + 0.016

⇒ f(126.2) ≈ 5.016

Therefore, the cube root of 126.2 is roughly 0.016 greater than the cube root of 125.

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The region in the plane for points with polar coordinates 2 < r < 3 and 5π/3 ≤ θ ≤ 7π/3.


Identify the range of r and θ: In this case, 2 < r < 3 and 5π/3 ≤ θ ≤ 7π/3. Draw the polar coordinate plane (with an origin, labeled "O") and radial lines representing the angles θ.Mark the angle 5π/3 on the plane, which is located in the fourth quadrant (5π/3 = 300°). Draw a radial line from the origin to represent this angle.

Mark the angle 7π/3 on the plane, which is also located in the fourth quadrant (7π/3 = 420°, but since 360° brings us back to the origin, it is equivalent to 60°). Draw a radial line from the origin to represent this angle.Draw two concentric circles around the origin with radii 2 and 3. These represent the range of r values.

Shade the region in the plane that is bounded by the radial lines, as well as the circles with radii 2 and 3. This is the region consisting of points whose polar coordinates satisfy the given conditions.

Your sketch should now show the region in the plane for points with polar coordinates 2 < r < 3 and 5π/3 ≤ θ ≤ 7π/3.

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When measuring the effects of a new diuretic medication, hourly urine output represents the ratio level of measurement.

What is ratio level of measurement?

Ratio level of measurement is a type of measurement that features a true zero point, meaning that the value 0 represents the absence of the characteristic being measured.

Some examples of ratio level measurements include weight, height, length, distance, speed, and many others. In this case, the hourly urine output of subjects is measured to determine the effects of a new diuretic medication.

The hourly urine output is a ratio measurement because it has a true zero point, which is the absence of urine output. In other words, if there is no urine output, the value would be 0, which represents the absence of the characteristic being measured.

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Answer:

\( \frac{9 - 8}{12 } \\ = \frac{1}{12} \\ = 0.8333333...\)

Answer:

Part A) = D) 13.33 m/sec

Part B) = A) Deer wins by 2.08 seconds

Step-by-step explanation:

Part A)

From the question in Part A, we know that, the White-tailed deer can run at 48 kilometers per hour for short periods. We were asked in the question, How many meters per second does the deer run?

The question gave us this (Hint: remember that there are 1,000 meters in a kilometer, 60 seconds in a minute, and 60 minutes in an hour.)

1 km = 1000 meters

48 km = x meters

Cross Multiply

= 1km × x meters = 48km × 1000 meters

x meters = 48km × 1000 meters/1 km

= 48000 meters/ hour

The speed of the dear = 48000 meters/ hour

We have to convert this to meters/ seconds

60seconds = 1 minute

60 minutes = 1 hour

Therefore, the number of seconds in one hour = 60 × 60

= 3600 seconds

Hence 48000meters/hour to meter per Seconds

= 48000meters/3600 seconds

= 13.333333333 meters/seconds

= 13.33m/s

Part B

From Part B Question, we know that Usain Bolt set a world record of 9.58 seconds for the 100 meter dash.

White-tailed deer can run at 48 kilometers per hour for short periods.

If Mr. Bolt and a white-tailed deer run a 100 meter dash at these speeds, who would win, and by how much?

Using our answer in Part A,

We know that the deer runs

48,000 meters in 3600 seconds.

The first step would be to find how many seconds it can run in an 100 meter race

Hence,

48,000 meters = 3600 seconds

100 meters = y seconds

We cross Multiply

48,000 meters × y seconds = 3600 seconds × 100 meters

y seconds = 3600 seconds × 100 meters/ 48,000 meters

y second = 7.5 seconds

This means, the deer can run a 100 meter dash in 7.5 seconds.

From the question, we know that Usain Bolt set the record of 9.58 seconds for an 100 letter dash.

The difference between both times for the Usain Bolt and the Deer = 9.58seconds - 7.5 seconds

= 2.08 seconds

Therefore the winner is the Deer , because it finishes the race is a shorter time of 7.5 seconds and wins by 2.08 seconds. Therefore, Option A) Deer wins by 2.08 seconds is correct

Domain and Range of the given rational functions are:Given rational function f(x) = 3/(x-1)The denominator of f(x) cannot be zero.x ≠ 1 Therefore the domain of f(x) is {x | x ≠ 1}

The range of f(x) is all real numbers except zero.Given rational function f(x) = (2x)/(x-4)The denominator of f(x) cannot be zero.x ≠ 4 Therefore the domain of f(x) is {x | x ≠ 4}The range of f(x) is all real numbers except zero.Given rational function f(x) = (x+3)/(5x-5)The denominator of f(x) cannot be zero.5x - 5 ≠ 0x ≠ 1 Therefore the domain of f(x) is {x | x ≠ 1}The range of f(x) is all real numbers except 1/5.Given rational function f(x) = (2+x)/(2x)The denominator of f(x) cannot be zero.x ≠ 0 Therefore the domain of f(x) is {x | x ≠ 0}The range of f(x) is all real numbers except zero.Given rational function f(x) = (x^2+4x+3)/(x^2-9)For the denominator of f(x) to exist,x ≠ 3, -3

Therefore the domain of f(x) is {x | x ≠ 3, x ≠ -3}The range of f(x) is all real numbers except 1, -1. Function Domain Rangef(x) = 3/(x-1) {x | x ≠ 1} All real numbers except zerof(x) = (2x)/(x-4) {x | x ≠ 4} All real numbers except zerof(x) = (x+3)/(5x-5) {x | x ≠ 1} All real numbers except 1/5f(x) = (2+x)/(2x) {x | x ≠ 0} All real numbers except zerof(x) = (x^2+4x+3)/(x^2-9) {x | x ≠ 3, x ≠ -3} All real numbers except 1, -1

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