Please helppp !!! each art movement inspires the next art movement. question 6 options: true false

Answer:

convection in the mantle.

Answer:

How long would it take a machine to do 13,000 joules of work if the power rating ... An object gains 15 joules of potential energy as it is lifted vertically 5.0 meters. ... As the time required to do a given quantity of work decreases, the power ... How much work is being done to the system by the person of the sled moves 10 m?

Answer:

i say amen to that brother a big amen

Answer:

The velocity of the mass after 10.0 seconds is 50.0 m/s.

Explanation:

Explanation: We can use the formula v = (F t)/m to calculate the velocity of the mass. Given that the force applied is 10.0 N, the mass is 2.00 kg, and the time elapsed is 10.0 s, we can substitute these values into the formula to get:

v = (10.0 N * 10.0 s) / 2.00 kg = 50.0 m/s

Therefore, the velocity of the mass after 10.0 seconds is 50.0 m/s.

Answer: 54 N

Explanation:

The impact force is 0.23 N.

An impact force is a force that causes a shock or a high impact in a short period of time. It happens when two things collide. This collision occurs when one object falls onto, or slams into, another object. This collision causes a shock because energy is transferred to the impacted entity (s).

v = m/s. The kinetic energy immediately preceding impact equals the gravitational potential energy at the height from which it was dropped: K.E. = J.

A car weighing 2000 kg travels at 60 km/h (16.7 m/s) before collapsing into a massive concrete wall. The front of the car makes a 0.5 m impact (the deformation distance). The force of the impact is 28 times that of gravity.

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Answer: c. The electric force increases

Explanation:

If the distance between two charged particles decreases, the electric force between them increases.

According to Coulomb's Law, the electric force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the equation can be represented as:

F = k * (q1 * q2) / r^2

Where:

F represents the electric force between the particles.

k is the electrostatic constant.

q1 and q2 are the charges of the particles.

r is the distance between the particles.

As the distance (r) between the particles decreases, the denominator of the equation (r^2) becomes smaller, causing the overall electric force (F) to increase. Conversely, if the distance between the charged particles increases, the electric force between them decreases. This inverse relationship between the distance and electric force is a fundamental characteristic of the electrostatic interaction between charged objects.

Answer:

420 L

Explanation:

Applying Boyle's Law,

PV = P'V'.................... Equation 1

Where P = Initial pressure, P' = Final pressure, V = Initial volume, V' = Final volume.

make V' the subject of the equation

V' = PV/P'.................... Equation 2

From the question,

Given: P = 720 mmHg, V = 350 L, P' = 600 mmHg

Substitute these values into equation 2

V' = (720×350)/600

V' = 252000/600

V' = 420 L

The magnitude of the impulse is defined as the product of the magnitude of the average force and the time interval of the force. Assuming that the force is constant, the magnitude of the impulse on the ball would be equal to the product of the constant force acting on the ball and the time interval for which it acts.

Impulse (j) = F avg ∆t Where, Impulse is the magnitude of the impulse F avg is the magnitude of the average force ∆t is the time interval of the force Therefore, if the force is constant, the magnitude of the impulse would simply be equal to the product of the force and the time interval for which it acts.

If you know the values of the constant force and the time interval, you can easily calculate the magnitude of the impulse. The magnitude of the impulse is measured in units of Newton-seconds (N·s).In conclusion, if a force is constant, the magnitude j of the impulse on the ball would be equal to the product of the constant force acting on the ball and the time interval for which it acts.

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The universe has four different types of galaxies: elliptical, spiral, barred spiral, and irregular. Although there are other sorts of galaxies besides these, which are the four primary categories, they are all categorized according to their shapes.

A galaxy's shape is a result of a combination of the gravitational pull of the gas clouds' internal gravity and the spinning gas cloud's centrifugal force. Because of the spinning gas cloud's centrifugal force, all galaxies were born with an elliptical form.

Due to the fact that galaxies rotate around a central axis and due to a phenomenon known as "density waves," astronomers think that galaxies have spiral arms. Galactic density waves are comparable to ocean waves. In a pond, the water doesn't actually move; instead, wave energy moves and changes the water as it passes.

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Answer:An object has balanced forces acting on it and constant velocity.

Explanation:

According to the statement, the vapor pressure of the NaCl solution is 22.63 torr.

To calculate the vapor pressure of the NaCl solution, we need to first calculate the mole fraction of water in the solution:

moles of water = mass of water / molar mass of water

moles of water = 150.0 g / 18.015 g/mol = 8.32 mol

moles of NaCl = mass of NaCl / molar mass of NaCl

moles of NaCl = 20.0 g / 58.44 g/mol = 0.342 mol

total moles = moles of water + moles of NaCl = 8.32 mol + 0.342 mol = 8.662 mol

X(water) = moles of water / total moles = 8.32 mol / 8.662 mol = 0.9603

Next, we can use Raoult's law to calculate the vapor pressure of the solution:

P = X(water) * P°(water)

Where P°(water) is the vapor pressure of pure water, which is given as 23.56 torr.

P = 0.9603 * 23.56 torr = 22.63 torr

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Answer:

Chemical bonds are forces that hold atoms together to make compounds or molecules. Chemical bonds include covalent, polar covalent, and ionic bonds. Atoms with relatively similar electronegativities share electrons between them and are connected by covalent bonds.

Explanation:

Answer:

a

Explanation:

a_c = v_t^2/r

a_c = (0.5)^2/0.03

a_c = 8.33 m/s^2

A three-phase full wave uncontrolled rectifier supplying an R-L-E load normally operates in the continuous conduction mode. In continuous conduction mode, the current through the rectifier diodes never falls to zero during each half-cycle of the input voltage waveform.

This means that the load current flows continuously through the diodes and the load. In this mode, the rectifier operates more efficiently and produces smoother output voltage and current waveforms. In a three-phase full wave rectifier, the input voltage is supplied by three-phase AC power, which means that there are six diodes involved in the rectification process. These diodes conduct in pairs to convert the AC input voltage into a pulsating DC output voltage.The R-L-E load refers to a load that consists of a resistance (R), an inductance (L), and possibly a capacitance (E). The continuous conduction mode is preferred for such loads as it provides a relatively stable and smooth output voltage, minimizing the effects of current and voltage ripples. The continuous conduction mode allows for efficient power transfer, reduced harmonic distortion, and improved power factor correction. It is commonly used in applications where a constant and regulated DC voltage is required, such as in power supplies, motor drives, and many other industrial and commercial applications.

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The total-distance travelled by toy-car is 198 meter, and average-speed of toy-car for entire trip is 9.43 ms⁻¹.

We break down the car's motion into three parts: the acceleration phase, the constant velocity phase, and the deceleration phase.

We use kinematic equations of motion to find distance traveled and average speed in each phase.

⇒ Acceleration phase:

The initial velocity (u) is = 0, the acceleration (a) is = 4.0 ms⁻², and time (t) is = 3.0 seconds. We use equation : s = ut + 1/2 at²,

s = 0 × (3.0) + 1/2 (4.0)(3.0)²,

s = 18.0 meters

So, The distance traveled during the acceleration phase is 18.0 meters.

⇒ Constant velocity phase:

The car maintains a constant velocity for 12.0 seconds, so we can use the equation : s = v × t,

where v is = constant velocity. Since, velocity is constant, we use final velocity (v) from acceleration phase:

v = u + at

v = 0 + (4.0)(3.0)

v = 12.0 ms⁻¹,

So, s = (12.0 ms⁻¹)(12.0 s)

s = 144.0 meters

The distance traveled during the constant velocity phase is 144.0 meters.

⇒ Deceleration phase:

The final velocity (v) is = 0, acceleration (a) is unknown, and time (t) is = 6.0 seconds. We can use the equation : v = u + at,

0 = 12.0 + a(6.0),

a = -2.0 ms⁻²,

The negative acceleration indicates that car is decelerating or slowing down. We use the same kinematic equation as before to find distance traveled : s = ut + 1/2 at²,

s = 12.0(6.0) + 1/2 (-2.0)(6.0)²,

s = 72.0 - 36.0

s = 36.0 meters

So, distance traveled during deceleration phase is 36.0 meters.

⇒ Total distance traveled can be found by adding the distances traveled in each phase:

total distance = 18.0 + 144.0 + 36.0

total distance = 198.0 meters

So, The total distance traveled is 198.0 meters.

⇒ Average speed:

We find the average speed of entire trip by dividing the total distance traveled by the total time taken:

total time = 3.0 + 12.0 + 6.0

total time = 21.0 seconds,

So, average speed = 198/21,

average speed = 9.43 ms⁻¹,

Therefore, the average-speed of entire-trip is 9.43 ms⁻¹.

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Answer:

Plural cerebrums cerebra The largest part of the vertebrate brain, filling most of the skull and consisting of two cerebral hemispheres divided by a deep groove and joined by the corpus callosum, a transverse band of nerve fibers. The cerebrum processes complex sensory information and controls voluntary muscle activity.

Explanation:

Answer:

268.22 m/s

Explanation:

An hour into the flight, you are 600 miles from San Francisco.

This sentence says that speed is 600 mi/h.

Now we need to convert it into m/s.

1 mi = 1609.34 m

1 h = 60 min = 60 min *60 s/1min = 3600 s

600 mi/h * 1609.34 m/1 mi * 1h/ 3600s= 600*1609.34/3600 m/s= =268.22 m/s

If you are flying 2586 miles from San Francisco to New York. An hour into the flight, you are 600 miles from San Francisco then your speed would have been 600 miles/hour.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem, If you are flying 2586 miles from San Francisco to New York. An hour into the flight, you are 600 miles from San Francisco then we have to find your speed,

Total distance traveled from  San Francisco to New York in one hor= 600 miles

speed of the flying plane = distance traveled in one hour time period

                                           = 600 miles/hour

Thus, your speed would have been 600 miles/hour.

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Answer:

GPEb=67.86% of initial GPE at point a

Explanation:

It depends on how massive the ball is, but I can still give an answer comparing original GPE at point A to new GPE at B

GPEa=m*9.8*140

GPEa=1372(m)

GPEb=m*9.8*95

GPEb=931(m)

GPEb=0.6786*GPEa

a) The work done on the person by gravity during the elevator ride is -20,790 J.

b) The amount of work the normal force of the floor did on the person is 20,790 J.

c) The average power of the force of gravity is -697 W.

The work done by gravity can be calculated using the formula:

Work = Force × Displacement × cos(θ)

In this case, the force of gravity is acting in the opposite direction to the displacement, so the angle θ is 180 degrees. The work done by gravity can be expressed as:

Work = mgh

where m is the mass of the person (70 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height (300 m).

Substituting the given values into the formula, we have:

Work = (70 kg) × (9.8 m/s²) × (300 m)

Work ≈ -20,790 J

Therefore, the work done on the person by gravity during the elevator ride is approximately -20,790 J. The negative sign indicates that the work is done in the opposite direction to the displacement.

The work done by the normal force of the floor can be calculated using the same formula as in part (a):

Work = Force × Displacement × cos(θ)

In this case, the normal force is acting in the same direction as the displacement, so the angle θ is 0 degrees. The work done by the normal force can be expressed as:

Work = mgh

Using the same values as in part (a):

Work = (70 kg) × (9.8 m/s²) × (300 m)

Work ≈ 20,790 J

Therefore, the amount of work the normal force of the floor did on the person is approximately 20,790 J.

The average power can be calculated using the formula:

Power = Work / Time

In this case, the work done by gravity is -20,790 J (as calculated in part a), and the time taken for the elevator ride is not given. Therefore, we cannot directly calculate the average power using the given information.

However, if the time taken for the elevator ride is known, the average power can be determined by dividing the work by the time.

For example, if the time taken is 30 seconds:

Power = -20,790 J / 30 s

Power ≈ -697 W

Therefore, the average power of the force of gravity would be approximately -697 W. The negative sign indicates that the power is being exerted in the opposite direction to the displacement.

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Answer:

B) 9.45 x 10^7 Newtons

Explanation:

The force of gravity between two objects can be calculated using the formula F = G * (m1 * m2)/(r^2), where F is the force of gravity, m1 and m2 are the masses of the objects, r is the distance between the objects, and G is the gravitational constant (G = 6.67 x 10^-11 N*(m^2)/(kg^2)). Plugging in the numbers, we get:

F = 6.67 x 10^-11 * (50 kg) * (6.39 x 10^23 kg) / (5.46 x 10^11 m)^2

F = 9.45 x 10^7 N

So the force on the 50 kg person due to Mars at their closest approach would be approximately 9.45 x 10^7 Newtons.

Answer:

all I know is C

are there more questions? anyone?

-KARL IS STOOPID

Explanation:

Answer:

First, remember that:

Acceleration = dV/dt

where V is velocity and t is time.

When you launch a projectile (θ between 0° and 90° means that you are not launching it into the ground) you are applying an initial velocity v0, that can be separated in components, where the vertical component will be:

v0*sin(v)

That initial vertical velocity is a constant, so it does not depend on time.

Then when we differentiate with respect to the time, that constant will vanish, and we will get:

rate of change of the vertical velocity = vertical acceleration.

And as you know, when we ignore the air resistance the only force acting on the vertical axis is the gravitational force, such that the vertical acceleration will be:

a(t) = -9.8m/s^2

Where the negative sign is because this force points down.

Then the rate of change of the vertical velocity will be exactly that, -9.8m/s^2.

And the vertical velocity equation, to see exactly how the vertical velocity depends on time, will be:

V(t) = (-9.8m/s^2)*t + v0*sin(θ)

Answer:

There are \(9.537\times 10^{-23}\) kilograms of radioactive material after 300 seconds.

Explanation:

From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:

\(\frac{dm}{dt} = -\lambda\cdot m\) (1)

Where:

\(\frac{dm}{dt}\) - Rate of change of the mass of the radioactive material, measured in kilograms per second.

\(m\) - Current mass of the radioactive material, measured in kilograms.

\(\lambda\) - Decay constant, measured in \(\frac{1}{s}\).

The solution of the differential equation is:

\(m(t) = m_{o}\cdot e^{-\lambda\cdot t}\) (2)

Where:

\(m_{o}\) - Initial mass of the radioactive material, measured in kilograms.

\(t\) - Time, measured in seconds.

If we know that \(m_{o} = 20\,kg\), \(\lambda = 0.179\,\frac{1}{s}\) and \(t = 300\,s\), then the initial mass of the radioactive material is:

\(m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}\)

\(m(t) \approx 9.537\times 10^{-23}\,kg\)

There are \(9.537\times 10^{-23}\) kilograms of radioactive material after 300 seconds.

When a volleyball is tossed over a net, starting from a height of 1.5 meters above the ground, where  after reaching the top of its trajectory it returns to its original height as it falls, the ball's speed is the same as when it was tossed, but its velocity is different.

As ball 1 gets to the top of its trajectory, its velocity becomes zero.

since not stated otherwise, we assume that both balls have the same properties

If ball 2 is released at this instance, then they both will travel down at the same time interval and have initial velocity as zero.

since vertical travel is downwards, then acceleration due to gravity g is positive for both balls.

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Answer:

The correct answer is Positive

Explanation:

Put the word POSITIVE

The force behind a river's flow is gravity. A river is a body of freshwater that flows downhill from its source, usually in mountains or hills, to a point where it meets a larger body of water like a lake or the ocean.

Rivers are long and constantly moving, and they are shaped by the surrounding landscape's features, like hills, valleys, and canyons. Gravity is the force that pulls everything towards the center of the earth, keeping everything in order. Every item, whether it's a person, a book, or a river, is pulled toward the ground by gravity. The force of gravity keeps the river moving downstream in the same direction. What is the relationship between gravity and a river's flow? The force behind a river's flow is gravity. The gravitational pull of the earth makes the water flow downhill, and it moves towards the sea because it follows the downhill path of least resistance. Gravity is what causes the river to move in the direction that it does, and it is also responsible for the energy that drives the movement. The steeper the slope of the land, the more the force of gravity acts on the water, and the faster it moves.

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You would be left with 1.25 g.

After 0.001 second, 10 grams decays to 5 grams.

After another 0.001 second, 5 g decays to 2.5 g. (Total time 0.002 s; two half-lives have passed)

After another 0.001 second, 2.5 g decays to 1.25 g. (Total time 0.003 s; 3 half-lives have passed)